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  • Number guessing game (3+- guessed result)

    - by Nick Waring
    I've been assigned a task to create a game that generates 4 digits and the user has to guess the digits one at a time to get the correct result. If the number is correct a Y is displayed and if not, a N. This was easy, now the next step was to implement another two responses. If the answer is too high, a H is displayed and too low, an N. Again, was easy - now the third is to use the same design as game 2 but if the number is 3 higher than a H is displayed and same if it's 3 lower than a L is displayed - otherwise an X is displayed. I can't figure out how to do this. Here's my test code for game 2 for just one of the digits - any help is appreciated. (5 was used just for a test.) def guess(): x = 5 g= int(input("Guess the number: ")) if g == x: print("Y") elif g < x: print("L") else: print("H")

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  • "IOError [Errno 13] Permisson denied" when copy a file on Windows

    - by wong2
    Hi, I wrote a program that will copy a file called a.exe to C:/Windows/, then I pack it to exe with PyInstaller, and rename the exe file to a.exe. When I run the exe file, it output IOError [Errno 13] Permisson denied: 'C:/Windows/a.exe', but the file a.exe was copied to the directory C:/Windows. Then I ran it as the Administrator, it happened again... At first, I copy the file with shututil.copy, then I wrote a function myself(open a.exe, create a.exe under C:/Windows, read a.exe 's content and write to C:/Windows/a.exe, close all), but it doesn't help...Any ideas?

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  • Praw (Redditt API) How to retrieve replies to a comment past 10 levels deep

    - by jpreed00
    Ok, so I've written some code that, for all intents and purposes, should work: def checkComments(comments): for comment in comments: print comment.body checkComments(comment.replies) def processSub(sub): sub.replace_more_comments(limit=None, threshold=0) checkComments(sub.comments) #login and subreddit init stuff here subs = mysubreddit.get_hot(limit=50) for sub in subs: processSub(sub) However, given a submission that has 50 nested replies like so: root comment -> 1st reply -> 2nd reply -> 3rd reply ... -> 50th reply The above code only prints: root comment 1st reply 2nd reply 3rd reply 4th reply 5th reply 6th reply 7th reply 8th reply 9th reply Any idea how I can get the remaining 41 levels of replies? Or is this a praw limitation?

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  • What is an alternative to eval in this situation?

    - by CppLearner
    Many of my view functions do similar things. For the most part, they reverse to a different views upon clicking a button / a text link. So I wrote a helper function render_reverse def render_reverse(f, args): # args are all string type return eval('reverse(' + f + ', ' + args + ')' ) eval is a bad practice, and is pretty slow. It takes 3 seconds to start redirecting, whereas calling reverse directly takes less than 1 second to start redirecting. What alternative do I have? By the way, the function above doesn't work properly. I was modelling after this line (which works) eval('reverse("homepage", args=["abcdefg"])') Thanks.

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  • Is this the right way of handling command line arguments?

    - by shadyabhi
    ask_username = True ask_password = True ask_message = True ask_number = True def Usage(): print '\t-h, --help: View help' print '\t-u, --username: Username' print '\t-p, --password: Password' print '\t-n, --number: numbber to send the sms' print '\t-m, --message: Message to send' sys.exit(1) opts, args = getopt(sys.argv[1:], 'u:p:m:n:h',["username=","password=","message=","number=","help"]) print opts, args for o,v in opts: if o in ("-h", "--help"): Usage() elif o in ("-u", "--username"): username = v ask_username = False elif o in ("-p", "--password"): passwd = v ask_password = False elif o in ("-m", "--message"): message = v ask_message = False elif o in ("-n", "--number"): number = v ask_number = False #Credentials taken here if ask_username: username = raw_input("Enter USERNAME: ") if ask_password: passwd = getpass() if ask_message: message = raw_input("Enter Message: ") if ask_number: number = raw_input("Enter Mobile number: ") I dont think it is, because I am using 4 objects just for checking if command line argument was provided... Guide me with the best way of doing it..

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  • Permission to view, but not to change! - Django

    - by RadiantHex
    Hi folks, is it possible to give users the permission to view, but not to change or delete. currently in the only permissions I see are "add", "change" and "delete"... but there is no "read/view" in there. I really need this as some users will only be able to consult the admin panel, in order to see what has been added in. Help would be amazing!

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  • reuse generators

    - by wiso
    I need to check the central limit with dices. Rool D dices. Sum the results. Repeat the same thing for N times. Change D and repeat. There's no need to store random values so I want to use only generators. The problem is that generators are consuming, I can't resuging them more times. Now my code use explicit for and I don't like it. dice_numbers = (1, 2, 10, 100, 1000) repetitions = 10000 for dice_number in dice_numbers: # how many dice to sum sum_container = [] for r in range(repetitions): rool_sum = sum((random.randint(1,6) for _ in range(dice_number))) sum_container.append(rool_sum) plot_histogram(sum_container) I want to create something like for r in repetitions: rools_generator = (random.randint(1,6) for _ in range(dice_number) sum_generator = (sum(rools_generator) for _ in range(r)) but the second time I resuse rools_generator it is condumed. I need to construct generator class?

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  • How to append a tag after a link with BeaufitulSoup

    - by systempuntoout
    Starting from an Html input like this: <p> <a href="http://www.foo.com">this if foo</a> <a href="http://www.bar.com">this if bar</a> </p> using BeautifulSoup, i would like to change this Html in: <p> <a href="http://www.foo.com">this if foo</a><b>OK</b> <a href="http://www.bar.com">this if bar</a><b>OK</b> </p> Is it possible to do this using BeautifulSoup?

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  • Choosing randomly all the elements in the the list just once

    - by Dalek
    How is it possible to randomly choose a number from a list with n elements, n time without picking the same element of the list twice. I wrote a code to choose the sequence number of the elements in the list but it is slow: >>>redshift=np.array([0.92,0.17,0.51,1.33,....,0.41,0.82]) >>>redshift.shape (1225,) exclude=[] k=0 ng=1225 while (k < ng): flag1=0 sq=random.randint(0, ng) while (flag1<1): if sq in exclude: flag1=1 sq=random.randint(0, ng) else: print sq exclude.append(sq) flag1=0 z=redshift[sq] k+=1 It doesn't choose all the sequence number of elements in the list.

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  • Problems with sys.stdout.write() with time.sleep() in a function

    - by philipjkim
    What I wanted is printing out 5 dots that a dot printed per a second using time.sleep(), but the result was 5 dots were printed at once after 5 seconds delay. Tried both print and sys.stdout.write, same result. Thanks for any advices. import time import sys def wait_for(n): """Wait for {n} seconds. {n} should be an integer greater than 0.""" if not isinstance(n, int): print 'n in wait_for(n) should be an integer.' return elif n < 1: print 'n in wait_for(n) should be greater than 0.' return for i in range(0, n): sys.stdout.write('.') time.sleep(1) sys.stdout.write('\n') def main(): wait_for(5) # FIXME: doesn't work as expected if __name__ == '__main__': try: main() except KeyboardInterrupt: print '\nAborted.'

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  • Efficiently generate numpy array from list comprehension output?

    - by shootingstars
    Is there a more efficient way than using numpy.asarray() to generate an array from output in the form of a list? This appears to be copying everything in memory, which doesn't seem like it would be that efficient with very large arrays. (Updated) Example: import numpy as np a1 = np.array([1,2,3,4,5,6,7,8,9,10]) # pretend this has thousands of elements a2 = np.array([3,7,8]) results = np.asarray([np.amax(np.where(a1 > element)) for element in a2])

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  • Concatenate multi value into one record.

    - by mikehjun
    I joined two tables together and what I like to do is concatenate multi vaule in one records without duplicated value. TAXLOT_ZONE TID ZONE 1 A 1 A 1 B 1 C 2 D 2 D 2 E 3 A 3 B 4 C 5 D Desirable Final table looks like; TID ZONE 1 A, B, C 2 D, E 3 A, B 4 C 5 D

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  • Why doesn't this work?

    - by Kyle W
    take = raw_input('Please enter the string of numbers that compose code\n\n\t') y = str(take) l = [] for i in xrange(0, len(y), 3):         l.append(str(y[i:i+3])) b = len(l) a = 0 while(a!=b):         c = l[a].replace('444', ' ')         c = l[a].replace('111', 'a')         c = l[a].replace('112', 'b')         c = l[a].replace('113', 'c')         c = l[a].replace('114', 'd')         c = l[a].replace('115', 'e')         etc...         a = a + 1 filename = 'decmes.txt' file = open(filename, 'w') file.write(c) file.close() I can enter anything, just 111 for example and it gives me back the same thing I put in. Maybe it's something dumb, but I can't figure it out.

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  • One-to-One relation classes

    - by SeyZ
    I want to have a class named ProjectDirectory and a class named MetaDirectory. Each project has a MetaDirectory which contains some meta data. Is it the good way to write the classes like this: class ProjectDirectory(object): def __init__(self, directory=None): self.directory = directory self.meta_directory = MetaDirectory(self) def __repr__(self): return self.directory class MetaDirectory(object): def __init__(self, project_directory=None): self.project_directory = project_directory self.directory = "%s/.meta/" % project_directory ProjectDirectory has a reference to MetaDirectory and MetaDirectory has a reference to ProjectDirectory. Is there an other solution or this solution is good ?

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  • communicate with a process in utf-8 on a cp1252 consoless

    - by Mapad
    I need to control a program by sending commands in utf-8 encoding to its standard input. For this I run the program using subprocess.Popen(): proc = Popen("myexecutable.exe", shell=True, stdin=PIPE, stdout=PIPE, stderr=PIPE) proc.stdin.write(u'ééé'.encode('utf_8')) If I run this from a cygwin utf-8 console, it works. If I run it from a windows console (encoding ='cp1252') this doesn't work. Is there a way to make this work without having to install a cygwin utf-8 console on each computer I want it to run from ? (NB: I don't need to output anything to console)

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  • Matplotlib Contour Clabel Location

    - by jotimaz
    I would like to control the location of matplotlib clabels on a contour plot, but without utilizing the manual=True flag in clabel. For example, I would like to specify an x-coordinate, and have labels created at the points that pass through this line. I see that you can get the location of the individual labels using get_position(), but I am stuck at that. Any help would be greatly appreciated. Thanks! EDIT: The above image is an example plot that I would like to apply this method to. The default label positions are inconvenient -- the flat areas between Day 2 and Day 4 would be more visually appealing.

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  • Returning binomal as a tuple

    - by Mike
    I want to save the results of my function binomal_aux to a tuple but I don't have an idea how to, here is my code I have right now. def binomal (n): i=0 for i in range(n): binomal_aux(n,i) #want this to be in a tuple so, binomal (2) = (1,2,1) return def binomal_aux (n,k): if (k==0): return 1 elif (n==k): return 1 else: return (binomal_aux(n-1,k) + binomal_aux(n-1,k-1))

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  • Python3k parse string re help

    - by dsaccount1
    "8,5,,1,4,7,,,,7,,1,9,3,6,,,8,6,3,9,,2,5,4,,,,,3,2,,,7,4,1,1,,4,,6,9,,5,,,,5,,,1,,6,3,,,6,5,,,,7,4,,1,7,6,,,,8,,5,,,7,1,,3,9," I'm doing a programming challenge where i need to parse this sequence into my sudoku script. Need to get the above sequence into 8,5,0,1,4,7,0,0,0,7,0,1,9,3,6,0,0,8......... I tried re but without success, help is appreciated, thanks.

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