Search Results

Search found 36773 results on 1471 pages for 'sql statement syntax'.

Page 458/1471 | < Previous Page | 454 455 456 457 458 459 460 461 462 463 464 465  | Next Page >

  • c, pass awk syntax as argument to execl

    - by Skuja
    I want to run following command in c to read systems cpu and memory usage: ps aux|awk 'NR > 0 { cpu +=$3; ram+=$4 }; END {print cpu,ram}' I am trying to pass it to execl command and after that read its output: execl("/bin/ps", "/bin/ps", "aux|awk", "'NR > 0 { cpu +=$3; ram+=$4 }; END {print cpu,ram}'",(char *) 0); but in terminal i am getting following error: ERROR: Unsupported option (BSD syntax) I would like to know how to properly pass awk as argument to execl?

    Read the article

  • A 'do' statement at the end of my perl script never runs

    - by Jeremy Petzold
    In my main script, I am doing some archive manipulation. Once I have completed that, I want to run a separate script to upload my archives to and FTP server. Separately, these scripts work well. I want to add the FTP script to the end of my archive script so I only need to worry about scheduling one script to run and I want to guarantee that the first script completes it work before the FTP script is called. After looking at all the different methods to call my FTP script, I settled on 'do', however, when my do statement is at the end of the script, it never runs. When I place it in my main foreach loop, it runs fine, but it runs multiple times which I want to avoid since the FTP script can handle having multiple archives to upload. Is there something I am missing? Why does it not run? Thanks

    Read the article

  • Why is this MySQL Join Statement not Working?

    - by Timmy
    Here is my code: $query2 = mysql_query("SELECT * FROM categories WHERE parent = $id JOIN SELECT * FROM posts WHERE main_nav_page = '$idTwo'"); while ($row2 = mysql_fetch_assoc($query2)) { $id = $row2['id']; $name = $row2['name']; $slug = $row2['slug']; $subMenuOrder = $row2['sub_menu_order']; echo "<tr>\n"; echo "<td>&nbsp; -- $name</td>\n"; echo "</tr>\n"; } Is my syntax wrong? EDIT: the error message is: Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/studentw/public_html/new_nav.php on line 30

    Read the article

  • does the condition after && always get evaluated

    - by brett
    I have this if statement that tests for the 2 conditions below. The second one is a function `goodToGo() so I want to call it unless the first condition is already true $value = 2239; if ($value < 2000 && goodToGo($value)){ //do stuff } function goodToGo($value){ $ret = //some processing of the value return $ret; } My question is about the 2 if conditions $value < 2000 && goodToGo($value). Do they both get evaluated or does the second one only get evaluated when the first one is true? In other words, are the following 2 blocks the same? if($value < 2000 && goodToGo($value)) { //stuff to do } if($value < 2000) { if (goodToGo($value)){ //stuff to do } }

    Read the article

  • Call a statement from resultMap->result iBatis

    - by Vinay
    Hi All, Please tell me is it correct configuration in given below. If there are mistake please reply. select * from PAYMENT where ORDER_ID = #ordId# and CUST_ID = #ordCustId# select * from PRODORDER where ord_id = #value# I am getting exceptions - com.ibatis.common.jdbc.exception.NestedSQLException: --- The error occurred in conf/sql-map.xml. --- The error occurred while applying a result map. --- Check the employee.orderResult. --- Check the result mapping for the 'payments' property. --- Cause: com.ibatis.sqlmap.client.SqlMapException: There is no statement named getOrderPayments in this SqlMap.

    Read the article

  • Ajax get throws a syntax error when ip is given instead of localhost

    - by Aruna
    Hi , i am working on cakephp. I have developed an application where i have used localhost in all ajax post and get.. like var ht = $.ajax({ type: "GET", url: "http://localhost/FormBuilder/index.php/forms/getInvitees/<?php echo $emailid;?>", async: false }).responseText; var myObject = eval('(' + ht + ')'); this thing works only when i put localhost . But when i change that to my Ip like http://111.11.11.11/FormBuilder/index.php/forms/getInvitees/", then i am getting a syntax error () in the line var myObject = eval('(' + ht + ')'); WHy it happens ?? Please give valuable suggestions in solving this.. Thank you

    Read the article

  • prefix and postfix increments while comparing variables

    - by miatech
    could someone explain why this code output is not equals not equals 2 in the first if statement it seems that a = 0 b/c is a postfix increment; therefore a will not increase untile next line; however, the two a's are not equal why? and in the second if when I run the debugger the value of a is 2, but the test is false, why? public static void main (String[] args) { int a = 0; if (a++ == a++) { System.out.println("equals"); } else { System.out.println("not equals"); } if (++a == 2) { System.out.println("equals 2"); } else { System.out.println("not equals 2"); } }

    Read the article

  • C++ refactor common code with one different statement

    - by user231536
    I have two methods f(vector<int>& x, ....) and g(DBConn& x, ....) where the (....) parameters are all identical. The code inside the two methods are completely identical except for one statement where we do different actions based on the type of x: in f(): we do x.push_back(i) in g(): we do x.DeleteRow(i) What is the simplest way to extract the common code into one method and yet have the two different statements? I am thinking of having a templated functor that overloads operator () (int a) but that seems overkill.

    Read the article

  • How to properly match the following message id format in a case statement

    - by hsatterwhite
    I'm trying to get this regex pattern working in a case statement to match a particular type of ID, which could be passed to the script. I need to match the exact number of alphanumeric characters with the dashes to differentiate this message id from anything else, which may be passed to this bash script. An example of the message id format: c7c3e910-c9d2-71e1-0999-0aec446b0000 #!/bin/bash until [ -z "$1" ] do case "$1" in "") echo "No value passed" ;; [a-z0-9]\{8\}-[a-z0-9]\{4\}-[a-z0-9]\{4\}-[a-z0-9]\{4\}-[a-z0-9]\{12\}) echo "Found message ID: $1" ;; *) echo "Server $1" ;; esac shift done

    Read the article

  • Catch Id (INT AUTO INCREMENT) of a Record after INSERT INTO Statement

    - by Johannes
    This is my first time I use MySQL as datastorage for my C# Application, as I've seen that there is no UNIQUEIDENTIFIER type as in SQL server I decieded to use INT with AUTO_INCREMENT, my problem is now if I execute a INSERT, how may I get the ID of the Record I just added. My quick and dirty solution has been to execute a SELECT MAX(ID) FROM table Statement. But this doesn't seem consistent. I belive there is a better solution something like mysql_insert_id() (PHP). Any Idea how to resolve this in C#?

    Read the article

  • simple putStrLn in Haskell/Yampa with arrows syntax

    - by sisif
    i'm using Haskell with the Yampa FRP library which uses the arrows language extension. how can i do a simple putStrLn in a SF? mySF = proc x -> do y <- identity -< x*x putStrLn "Hello World!" ++ show y returnA -< y the arrow syntax complains about the expression not bein an arrow (of course), but even with arrows i get no output output <- identity -< putStrLn "Hello World!"

    Read the article

  • How to write syntax highlighting? c++

    - by ML
    Hi All, I am embarking on some learning and I want to write my own syntax highlighting for files in C++. Can anyone give me ideas on how to go about doing this? To me it seems that when a file is opened: 1. it would need to be parsed and decided what type of source file it is. Trusting the extension might not be full-proof a way to know what keywords/commands apply to what language a way to decide what color each keyword/command gets I want to do this on OS X, C++ or Objective-C Can anyone provide pointers on how I might get started with this?

    Read the article

  • Bash: Continue script if only one instance is running.

    - by Andrew
    Hello, now this is embarrassing. I'm writing quick script and I can't figure out why this statement don't work. if [ $(pidof -x test.sh | wc -w) -eq 1 ]; then echo Passed; fi I also tried using back-ticks instead of $() but it still wouldn't work. Can you see what is wrong with it? pidof -x test.sh | wc -w returns 1 if I run it inside of script, so I don't see any reason why basically if [ 1 -eq 1 ] wouldn't pass. Thanks a lot!

    Read the article

  • Correct syntax of a HTTP 100 Continue response

    - by PartlyCloudy
    For me, one of the weakest points of the HTTP 1.1 RFC and the various implementations around is how to deal with 100 Continue headers. I searched on the web for a while and had a look at different implementations. However, there is one thing I'm not sure of. what is the correct syntax of a 100 Continue message? Several sources claim, that this must be a single response line without any further header lines. However, I can't find that in the RFC 2616 reflected. So what is right? HTTP/1.1 100 Continue or HTTP/1.1 100 Continue [Additional Headers…] ?

    Read the article

  • Android - Array or for statement problem

    - by Normano
    I making on a app, but I have a problem with for or with a array. When I use this code case MotionEvent.ACTION_MOVE: for (int i = 0; i < Button.length; i++) { if (Y > Button[i].getTop()+25 && Y < Button[i].getBottom()+25 && X > Button[i].getLeft() && X < Button[i].getRight()){ LastButton = i; edittext.setText("id " + i); } } break; But the for statement skip the first button in the array and the second button get id 1. anyone know how I can fix it? Thanks

    Read the article

  • Safely dereferencing FirstOrDefault call in Linq c#

    - by samy
    For brevity's sake in my code, i'd like to be able to do the following: having a collection, find the first element matching a lambda expression; if it exists, return the value of a property or function. If it doesn't exist, return null. var stuff = {"I", "am", "many", "strings", "obviously"}; var UpperValueOfAString = stuff.FirstOrDefault(s => s.contains("bvi")).ToUpper(); // would return "OBVIOUSLY" var UpperValueOfAStringWannabe = stuff.FirstOrDefault(s => s.contains("unknown token")).ToUpper(); // would return null Is it possible with some linq-syntax-fu or do i have to check explicitly for the return value before proceeding?

    Read the article

  • Java - Syntax Question: What is <? super T>

    - by aloh
    I'm having trouble understanding the following syntax: public class SortedList< T extends Comparable< ? super T> > extends LinkedList< T > I see that class SortedList extends LinkedList. I just don't know what T extends Comparable< ? super T> means. My understanding of it so far is that type T must be a type that implements Comparable...but what is "< ? super T "?

    Read the article

  • Sqlite + Java: table not updating

    - by Ben L
    I'm using a Java wrapper for SQLite called SQLiteJDBC - this may have some bearing on any answers... I have a table which I've displayed in a GUI, within that UI I have a button for the fields for an individual row of that table. When I save my changes I do this... Statement stmt = connection.createStatement(); stmt.execute("update 'tableName' set 'fieldName'=1 where userid=1"); int updateCount = stmt.getUpdateCount(); My connection is valid, I get no exceptions thrown and getUpdateCount() returns '1' indicating that one row has been updated. However my table is not updated. I've spent the last few hours trying to work out what's going on but I'm not having any luck. Help!!

    Read the article

  • why am i getting an error SyntaxError : invalid syntax for this code

    - by eragon1189
    This is a code in python which calculates f (x) =? ((-1)*x)/(x*x+n*n) n from 1 to infinite.... correct to 0.0001, for the range 1 < x < 100 in steps of 0.1.But i am getting an syntax error,as i am new to programming in python... from scipy import * from matplotlib.pyplot import * x=arange(0.1,100,0.1) f=zeros(len(x)) s=-1 for n in range (1,10000): t=s*x/(x*x+n*n) f +=t s =-s if max(abs(t))< 1e-4 break for xx in c_[x,f]: print "%f %f" % (xx[0],xx[1])

    Read the article

  • Only assignment, call, increment, decrement, and new object expressions can be used as a statement : Messagebox

    - by Nuru Salihu
    This what i am trying to achieved if(this.BeginInvoke((Action)(() => MessageBox.Show("Test", MessageBoxButtons.YesNo) == DialogResult.No))) The above gives error. I try seperating the delegate to an outside method like delegate void test(string text); private void SetTest(string text) { if(MessageBox.Show(text,"", MessageBoxButtons.YesNo) == DialogResult.No) } But it breach the very reason why i need the delegate. I found out the first works for me but i don't know how to put it in an if/else statement. Pls any help in a better way i can achieve some thing like below would be appreciated. if(this.BeginInvoke((Action)(() => MessageBox.Show("Test", MessageBoxButtons.YesNo) == DialogResult.No)))

    Read the article

  • PDO Prepare statement not processing parameters

    - by Danten
    I've exhausted all efforts at what appears to be a trivial problem, but gotten nowhere. There is a simple Prepare statement: $qry = $core->db->prepare("SELECT * FROM users WHERE email = '?'"); $qry->execute(array('[email protected]')); However, no rows are returned. Running the query with the parameters hardcoded into the query results in a successful selection of one row. I've tryed many different methods of doing the prepare, but even it this most simple form it isn't working. The PDO object is stored in a singleton called Core. PDO is using the mysql driver.

    Read the article

  • Call methods on native Javascript types without wrapping with ()

    - by Anurag
    In Javascript, we can call methods on string literals directly without enclosing it within round brackets. But not for other types such as numbers, or functions. It is a syntax error, but is there a reason as to why the Javascript lexer needs these other types to be enclosed in round brackets? For example, if we extend Number, String, and Function with an alert method and try calling this method on the literals, it's a SyntaxError for Number and Function, while it works for a String. function alertValue() { alert(this); } Number.prototype.alert = alertValue; String.prototype.alert = alertValue; Function.prototype.alert = alertValue; We can call alert directly on a string object: "someStringLiteral".alert() // alerts someStringLiteral but it's a SyntaxError on numbers, and functions. 7.alert(); function() {}.alert(); To work with these types, we have to enclose it within brackets: (7).alert(); // alerts "7" (function() {}).alert(); // alerts "function() {}"

    Read the article

  • In mySQL, Is it possible to SELECT from two tables and merge the columns?

    - by Travis
    If I have two tables in mysql that have similar columns... TABLEA id name somefield1 TABLEB id name somefield1 somefield2 How do I structure a SELECT statement so that I can SELECT from both tables simultaneously, and have the result sets merged for the columns that are the same? So for example, I am hoping to do something like... SELECT name, somefield1 FROM TABLEA, TABLEB WHERE name="mooseburgers"; ...and have the name, and somefield1 columns from both tables merged together in the result set. Thank-you for your help!

    Read the article

  • Access outer class from inner class: Why is it done this way?

    - by Vuntic
    So most of us know how to access an outer class from an inner class. Searches with those words give oodles of answered questions on that topic. But what I want to know is why the syntax is the way it is. Example: public class A { private class B { public void c() {A.this.d();} } public void d() {System.out.println("You've called d()! Go, you!");} } Why is it A.this.d()? It looks like this is a static field of class A, but... * am confused * Forgive me if this is a repeat; like I said, searches with those words give how-answers.

    Read the article

  • C++ -- return x,y; The point?

    - by Earlz
    Hello, I have been programming in C and C++ for a few years and now I'm taking a college course in it and our book had a function like this int foo(){ int x=0; int y=20; return x,y; //y is always returned } I have never seen such syntax. In fact, I never see the , operator used outside of parameter lists. If y is always returned though, then what is the point? Is there a case where a return statement would need to be created like this? (Also, I tagged C as well because it applies to both, though my book specifically is C++)

    Read the article

< Previous Page | 454 455 456 457 458 459 460 461 462 463 464 465  | Next Page >