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  • Cannot add or update a child row: a foreign key constraint fails

    - by Tom
    table 1 +----------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +----------+-------------+------+-----+---------+----------------+ | UserID | int(11) | NO | PRI | NULL | auto_increment | | Password | varchar(20) | NO | | | | | Username | varchar(25) | NO | | | | | Email | varchar(60) | NO | | | | +----------+-------------+------+-----+---------+----------------+ table2 +------------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+--------------+------+-----+---------+----------------+ | UserID | int(11) | NO | MUL | | | | PostID | int(11) | NO | PRI | NULL | auto_increment | | Title | varchar(50) | NO | | | | | Summary | varchar(500) | NO | | | | +------------------+--------------+------+-----+---------+----------------+ com.mysql.jdbc.exceptions.MySQLIntegrityConstraintViolationException: Cannot add or update a child row: a foreign key constraint fails (myapp/table2, CONSTRAINT table2_ibfk_1 FOREIGN KEY (UserID) REFERENCES table1 (UserID)) What have I done wrong? I read this: http://www.w3schools.com/Sql/sql_foreignkey.asp and i don't see whats wrong. :S

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  • PL/SQL exception and Java programs

    - by edwards
    Hi Business logic is coded in pl/sql packages procedures and functions. Java programs call pl/sql packages procedures and functions to do database work. pl/sql programs store exceptions into Oracle tables whenever an exception is raised. How would my java programs get the exceptions since the exception instead of being propagated from pl/sql to java is getting persisted to a oracle table and the procs/functions just return 1 or 0. Sorry folks i should have added this constraint much earlier and avoided this confusion. As with many legacy projects we don't have the freedom to modify the stored procedures.

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  • Need help in setting application name with JPA (EclipseLink)

    - by enrique
    hello everybody i am using JPA with EclipseLink and oracle as DB and i need to set the property v$session of jdbc4 it allows to set an identification name to the application for auditing purposes but i had no lucky setting it up....i have been trying through entitiyManager following the example in this page: http://wiki.eclipse.org/Configuring_a_EclipseLink_JPA_Application_(ELUG) it does not show any error but does not set the application name at all... when i see the audit in oracle it is not being audited with the name i set by code "Customers" but with OS_program_name=JDBC Thin Client it means that the property in the code is not being set properly and i have no idea where the issue is, the code i am using is the following : emProperties.put("v$session.program","Customers"); factory=Persistence.createEntityManagerFactory("clients",emProperties); em=factory.createEntityManager(emProperties); em.merge(clients); does anybody know how to do it or any idea.... thanks.-

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  • Find all html characters in drop-down option text and replace them via jQuery

    - by Jon Harding
    I have a dropdown menu that pulls in text from a database column. The database column can include HTML mark-up. In the drop-down I obviously don't need that in the text. I am working on some jquery and it partially accomplished what I'm looking for. However, it seems to only be replacing the first instance of each character $('select option').each(function() { this.text = this.text.replace('&nbsp;', ' '); this.text = this.text.replace('<div>', '' ); this.text = this.text.replace('</div>', '' ); }); Here is the HTML for the drop-down: <select name="ctl00$SubPageBody$ClassList" id="ctl00_SubPageBody_ClassList"> <option value="196">Four Week Series: July 19, 2012, 11:00am-12:00pm&<div>July 26, 2012, 11:00am-12:00pm&nbsp;</div><div>August 2, 2012, 11:00am-12:00pm</div><div>August 9, 2012, 11:00am-12:00pm</div></option> </select>

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  • How can you access two identically-named columns in a MySQL LEFT JOIN query?

    - by George Edison
    I have two tables. table_x: id INT(11) tag INT(11) table_tags: id INT(11) name VARCHAR(255) Then I use PHP to perform the following query: SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id The only problem is: how do I access table_x.id and table_tags.id in the results? Here is the PHP code: $query = "SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id"; $results = mysql_query($query); while($row = mysql_fetch_array($results)) { // how do I now access table_x.id and table_tags.id ??? }

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  • Two Instances of Sql Server (2005 and 2008)

    - by Felipe
    Hi All, I installed Visual Studio 2008 Professional in my machine and It had installed SQL Server Express 2005 database in machine, and I use it very fine! I installed SQL Managment Studio and works great. So, in this week I Installed Visual Studio 2010 Pro in machine and the setup installed the SQL Server express 2008 and it overwrite the instance of my SQL Server Express 2005. All right, Now, I'd like to know how can I have two instances of the SQL Server Express in my Machine, Express 2005 and Express 2008. I can not access the 2005 , only 2008 :( and my projects uses 2005.. Somebody Help me! thanks Bye

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  • MySQL: Combining multiple where conditions

    - by Karl
    I'm working on a menu system that takes a url and then queries the db to build the menu. My menu table is: +---------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | node_id | int(11) | YES | | NULL | | | parent | int(11) | YES | | NULL | | | weight | int(11) | YES | | NULL | | | title | varchar(250) | YES | | NULL | | | alias | varchar(250) | YES | | NULL | | | exclude | int(11) | YES | | NULL | | +---------+--------------+------+-----+---------+----------------+ The relevant columns for my question are alias, parent and node_id. So for a url like: http://example.com/folder1/folder2/filename Alias would potentially = "filename", "folder1", "folder2" Parent = the node_id of the parent folder. What I know is how to split the url up into an array and check the alias for a match to each part. What I don't know is how to have it then filter by parent whose alias matches "folder2" and whose parent alias matches "folder1". I'm imagining a query like so: select * from menu where alias='filename' and where parent = node_id where alias='folder2' and parent = node_id where alias='folder1' Except I know that the above is wrong. I'm hoping this can be done in a single query. Thanks for any help in advance!

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  • How do I add values from two separate queries in SQL

    - by fishhead
    Below is my attempt at adding two values from separate select statements...it's not working, and I can't see why. I'm looking for some direction. select (v1.Value + v2.Value) as total from ( (Select Max(Value) as [Value] from History WHERE Datetime>='Apr 11 2010 6:05AM' and Datetime<='Apr 11 2010 6:05PM' and Tagname ='RWQ272017DTD' ) as v1 (Select Max(Value) as [Value] from History WHERE Datetime>='Apr 11 2010 6:05AM' and Datetime<='Apr 11 2010 6:05PM' and Tagname ='RU282001DTD' ) as v2 ) EDIT: Boy do I feel foolish...I asked the same question a few days ago...now I can't delete this.

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  • Slow query. Wrong database structure?

    - by Tin
    I have a database with table that contains tasks. Tasks have a lifecycle. The status of the task's lifecycle can change. These state transitions are stored in a separate table tasktransitions. Now I wrote a query to find all open/reopened tasks and recently changed tasks but I already see with a rather small number of tasks (<1000) that execution time has becoming very long (0.5s). Tasks +-------------+---------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-------------+---------+------+-----+---------+----------------+ | taskid | int(11) | NO | PRI | NULL | auto_increment | | description | text | NO | | NULL | | +-------------+---------+------+-----+---------+----------------+ Tasktransitions +------------------+-----------+------+-----+-------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+-----------+------+-----+-------------------+----------------+ | tasktransitionid | int(11) | NO | PRI | NULL | auto_increment | | taskid | int(11) | NO | MUL | NULL | | | status | int(11) | NO | MUL | NULL | | | description | text | NO | | NULL | | | userid | int(11) | NO | | NULL | | | transitiondate | timestamp | NO | | CURRENT_TIMESTAMP | | +------------------+-----------+------+-----+-------------------+----------------+ Query SELECT tasks.taskid,tasks.description,tasklaststatus.status FROM tasks LEFT OUTER JOIN ( SELECT tasktransitions.taskid,tasktransitions.transitiondate,tasktransitions.status FROM tasktransitions INNER JOIN ( SELECT taskid,MAX(transitiondate) AS lasttransitiondate FROM tasktransitions GROUP BY taskid ) AS tasklasttransition ON tasklasttransition.lasttransitiondate=tasktransitions.transitiondate AND tasklasttransition.taskid=tasktransitions.taskid ) AS tasklaststatus ON tasklaststatus.taskid=tasks.taskid WHERE tasklaststatus.status IS NULL OR tasklaststatus.status=0 or tasklaststatus.transitiondate>'2013-09-01'; I'm wondering if the database structure is best choice performance wise. Could adding indexes help? I already tried to add some but I don't see great improvements. +-----------------+------------+----------------+--------------+------------------+-----------+-------------+----------+--------+------+------------+---------+---------------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | Index_comment | +-----------------+------------+----------------+--------------+------------------+-----------+-------------+----------+--------+------+------------+---------+---------------+ | tasktransitions | 0 | PRIMARY | 1 | tasktransitionid | A | 896 | NULL | NULL | | BTREE | | | | tasktransitions | 1 | taskid_date_ix | 1 | taskid | A | 896 | NULL | NULL | | BTREE | | | | tasktransitions | 1 | taskid_date_ix | 2 | transitiondate | A | 896 | NULL | NULL | | BTREE | | | | tasktransitions | 1 | status_ix | 1 | status | A | 3 | NULL | NULL | | BTREE | | | +-----------------+------------+----------------+--------------+------------------+-----------+-------------+----------+--------+------+------------+---------+---------------+ Any other suggestions?

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  • How do I use Perl to parse the output of the sqlplus command?

    - by benjamin button
    I have an SQL file which will give me an output like below: 10|1 10|2 10|3 11|2 11|4 . . . I am using this in a Perl script like below: my @tmp_cycledef = `sqlplus -s $connstr \@DLCycleState.sql`; after this above statement, since @tmp_cycledef has all the output of the SQL query, I want to show the output as: 10 1,2,3 11 2,4 How could I do this using Perl?

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  • Query to sum duplicated fields

    - by g0sha
    Here is mysql data id usr good quant delayed cart_ts ------------------------------------------------------ 14 4 1 1 0 20100601235348 13 4 11 1 0 20100601235345 12 4 4 1 0 20100601235335 11 4 1 1 0 20100601235051 10 4 11 1 0 20100601235051 9 4 4 1 0 20100601235051 15 4 2 1 0 20100601235350 16 4 7 1 0 20100602000537 17 4 3 1 0 20100602000610 18 4 3 1 0 20100602000616 19 4 8 1 0 20100602000802 20 4 8 1 0 20100602000806 21 4 8 1 0 20100602000828 22 4 8 1 0 20100602000828 23 4 8 1 0 20100602000828 24 4 8 1 0 20100602000828 25 4 8 1 0 20100602000828 26 4 8 1 0 20100602000829 27 4 8 1 0 20100602000829 28 4 9 1 0 20100602001045 29 4 10 1 0 20100602001046 I need to group fields in witch usr & good has duplicated values with summing quant field for getting smth like this: id usr good quant delayed cart_ts ------------------------------------------------------ 14 4 1 2 0 20100601235348 13 4 11 2 0 20100601235345 12 4 4 2 0 20100601235335 15 4 2 1 0 20100601235350 16 4 7 1 0 20100602000537 17 4 3 2 0 20100602000610 19 4 8 9 0 20100602000802 28 4 9 1 0 20100602001045 29 4 10 1 0 20100602001046 Which MySQL query I need to do to have this effect?

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  • How to display multiple categories and products underneath each category?

    - by shin
    Generally there is a category menu and each link to a category page where shows all the items under that category. Now I need to show all the categories and products underneath with PHP/MySQL in the same page. So it will be like this. Category 1 description of category 1 item 1 item 2 .. Category 2 description of category 2 item 5 item 6 .. Category 3 description of category 3 item 8 item 9 ... ... I have category and product table in my database. But I am not sure how to proceed. CREATE TABLE IF NOT EXISTS `omc_product` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `shortdesc` varchar(255) NOT NULL, `longdesc` text NOT NULL, `thumbnail` varchar(255) NOT NULL, `image` varchar(255) NOT NULL, `product_order` int(11) DEFAULT NULL, `class` varchar(255) DEFAULT NULL, `grouping` varchar(16) DEFAULT NULL, `status` enum('active','inactive') NOT NULL, `category_id` int(11) NOT NULL, `featured` enum('none','front','webshop') NOT NULL, `other_feature` enum('none','most sold','new product') NOT NULL, `price` float(7,2) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; CREATE TABLE IF NOT EXISTS `omc_category` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `shortdesc` varchar(255) NOT NULL, `longdesc` text NOT NULL, `status` enum('active','inactive') NOT NULL, `parentid` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; I will appreciate your help. Thanks in advance.

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  • How to have partial incremental synchronizations based on a GUID?

    - by Gonçalo Veiga
    I need to synchronize an SQL Server database to Oracle through an Oracle Transparent Gateway. The synchronization is performed in batches, so I need to get the next set of data from the point where I left off. The problem I'm having is that the only field I have in the source, to help me, is a GUID. If it were a number I could just order by it, keep the last one processed and restart the process by getting the records which are my recorded number. This won't work with a GUID. Any ideas?

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  • How to turn this simple 10 digit hex number back into 8 digits?

    - by Babil
    The algorithm to convert input 8 digit hex number into 10 digit are following: Given that the 8 digit number is: '12 34 56 78' x1 = 1 * 16^8 * 2^3 x2 = 2 * 16^7 * 2^2 x3 = 3 * 16^6 * 2^1 x4 = 4 * 16^4 * 2^4 x5 = 5 * 16^3 * 2^3 x6 = 6 * 16^2 * 2^2 x7 = 7 * 16^1 * 2^1 x8 = 8 * 16^0 * 2^0 Final 10 digit hex is: = x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = '08 86 42 98 E8' The problem is - how to go back to 8 digit hex from a given 10 digit hex (for example: 08 86 42 98 E8 to 12 34 56 78) Some sample input and output are following: input output 11 11 11 11 08 42 10 84 21 22 22 33 33 10 84 21 8C 63 AB CD 12 34 52 D8 D0 88 64 45 78 96 32 21 4E 84 98 62 FF FF FF FF 7B DE F7 BD EF

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  • Why this query is so slow?

    - by Silver Light
    This query appears in mysql slow query log: it takes 11 seconds. INSERT INTO record_visits ( record_id, visit_day ) VALUES ( '567', NOW() ); The table has 501043 records and it's structure looks like this: CREATE TABLE IF NOT EXISTS `record_visits` ( `id` int(11) NOT NULL AUTO_INCREMENT, `record_id` int(11) DEFAULT NULL, `visit_day` date DEFAULT NULL, `visit_cnt` bigint(20) DEFAULT '1', PRIMARY KEY (`id`), UNIQUE KEY `record_id_visit_day` (`record_id`,`visit_day`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 ; What could be wrong? Why this INSERT takes so long?

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  • Query on Triggers..

    - by RBA
    Created One Trigger in Oracle.. SQL> CREATE OR REPLACE TRIGGER student_after_insert 2 AFTER INSERT 3 ON student 4 FOR EACH ROW 5 BEGIN 6 @hello.pl 9 END student_after_insert; 10 / Contents of hello.pl are:- BEGIN DBMS_OUTPUT.PUT_LINE('hello world'); END; And.. the result is pretty good, as the content of hello.pl is displayed on screen while inserting a record.. Now, the query is -- When i change the content of the hello.pl file, after exiting from oracle, and then logging again, It doesn't shows the updated contents, instead it shows the previous content.. I noticed that, if i drop the trigger and create it again, then it is working fine.. Why is it happening so.. And what is the solution to this problem..

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  • Significance of date 02/31/2157?

    - by dpatchery
    I work in a large scale IT support environment. Twice now we have seen an invalid date of 02/31/2157 being inserted in an Oracle DATE column. So far I have not been able to reproduce this problem, but it appears to be happening occasionally when a user attempts to save '00/00/0000' into the column. I believe the value is originating from a PowerBuilder DataWindow update. The application uses myriad libraries for all sorts of technologies, so this question may be a bit vague, but... Has anyone seen the date 02/31/2157 in some established library that Oracle could be defaulting to when some other invalid date is entered? Perhaps an end-of-time concept analogous to the beginning-of-time date of 1/1/1970?

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  • Selecting a sequence NEXTVAL for multiple rows

    - by stringpoet
    I am building a SQL Server job to pull data from SQL Server into an Oracle database through a linked server. The table I need to populate has a sequence for the name ID, which is my primary key. I'm having trouble figuring out a way to do this simply, without some lengthy code. Here's what I have so far for the SELECT portion (some actual names obfuscated): SELECT (SELECT NEXTVAL FROM OPENQUERY(MYSERVER, 'SELECT ORCL.NAME_SEQNO.NEXTVAL FROM DUAL')), psn.BirthDate, psn.FirstName, psn.MiddleName, psn.LastName, c.REGION_CODE FROM Person psn LEFT JOIN MYSERVER..ORCL.COUNTRY c ON c.COUNTRY_CODE = psn.Country MYSERVER is the linked Oracle server, ORCL is obviously the schema. Person is a local table on the SQL Server database where the query is being executed. When I run this query, I get the same exact value for all records for the NEXTVAL. What I need is for it to generate a new value for each returned record. I found this similar question, with its answers, but am unsure how to apply it to my case (if even possible): Query several NEXTVAL from sequence in one satement

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  • PL/SQL embedded insert into table that may not exist

    - by Richard
    Hi, I much prefer using this 'embedded' style inserts in a pl/sql block (opposed to the execute immediate style dynamic sql - where you have to delimit quotes etc). -- a contrived example PROCEDURE CreateReport( customer IN VARCHAR2, reportdate IN DATE ) BEGIN -- drop table, create table with explicit column list CreateReportTableForCustomer; INSERT INTO TEMP_TABLE VALUES ( customer, reportdate ); END; / The problem here is that oracle checks if 'temp_table' exists and that it has the correct number of colunms and throws a compile error if it doesn't exist. So I was wondering if theres any way round that?! Essentially I want to use a placeholder for the table name to trick oracle into not checking if the table exists.

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  • A hard Question ?

    - by the-ifl
    Hi Guys , I try To find a solution to a question .... we have a number , example : 20 ... and we have 6 number :{ a ,b , c , d , e , f} < 20 , t try to find all values of these numbers , but only if we can combinate (whit + or -) whit 2 of this numbers and getting all the value below to 20 : for example we choose 31 : a = 22 b = 21 c = 14 d = 11 e = 9 f = 5 we have : 22 - 21 = 1 ; 11 - 9 = 2 ; 14 - 11 = 3 ; 9 - 5 = 4 ; f = 5 ; 11 - 5 = 6 ; 21 - 14 = 7 ; .... .... .... .... .... 21 + 9 = 30 ; 9 + 22 = 31 ;

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  • Tunneling through SSH for 1521 port access?

    - by A T
    I am developing locally on my computer, using my own Apache server with PHP configured. My database however is remotely located on an Oracle 11g Database Server. We were also given a separate remote server for hosting our .html and .php files, however only FTP access has been provided there. Development is far too slow waiting for the FTP connection to push. So I decided to develop locally, but still use the remote DB server. Unfortunately that gives me an error. Not sure how—or where—to integrate tunnelling. Do I add something to the oci_connect HOST in my PHP file, or do I encapsulate my whole environment over SSH?

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  • Algorithm: Find smallest subset containing K 0's

    - by Vishal
    I have array of 1's and 0's only. Now I want to find contiguous subset/subarray which contains at least K 0's. Example Array is 1 1 0 1 1 0 1 1 0 0 0 0 1 0 1 1 0 0 0 1 1 0 0 1 0 0 0 and K(6) should be 0 0 1 0 1 1 0 0 0 or 0 0 0 0 1 0 1 1 0.... My Solution Array: 1 1 0 1 1 0 1 1 0 0 0 0 1 0 1 1 0 0 0 1 1 0 0 Index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 Sum: 1 2 2 3 4 4 5 6 6 6 6 6 7 7 8 9 9 9 9 10 11 11 11 Diff(I-S): 0 0 1 1 1 2 2 2 3 4 5 6 6 7 7 7 8 9 10 10 10 11 12 For K(6) Start with 9-15 = Store difference in diff. Next increase difference 8-15(Difference in index) 8-14(Compare Difference in index) So on keep moving to find element with least elements... I am looking for better algorithm for this solution.

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  • How can I read a continuously updating log file in Perl?

    - by Octopus
    I have a application generating logs in every 5 sec. The logs are in below format. 11:13:49.250,interface,0,RX,0 11:13:49.250,interface,0,TX,0 11:13:49.250,interface,1,close,0 11:13:49.250,interface,4,error,593 11:13:49.250,interface,4,idle,2994215 and so on for other interfaces... I am working to convert these into below CSV format: Time,interface.RX,interface.TX,interface.close.... 11:13:49,0,0,0,.... Simple as of now but the problem is, I have to get the data in CSV format online, i.e as soon the log file updated the CSV should also be updated. What I have tried to read the output and make the header is: #!/usr/bin/perl -w use strict; use File::Tail; my $head=["Time"]; my $pos={}; my $last_pos=0; my $current_event=[]; my $events=[]; my $file = shift; $file = File::Tail->new($file); while(defined($_=$file->read)) { next if $_ =~ some filters; my ($time,$interface,$count,$eve,$value) = split /[,\n]/, $_; my $key = $interface.".".$eve; if (not defined $pos->{$eve_key}) { $last_pos+=1; $pos->{$eve_key}=$last_pos; push @$head,$eve; } print join(",", @$head) . "\n"; } Is there any way to do this using Perl?

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