Search Results

Search found 4320 results on 173 pages for 'vertex arrays'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 46/173 | < Previous Page | 42 43 44 45 46 47 48 49 50 51 52 53  | Next Page >

  • How to do an array of hashmaps?

    - by Joren
    This is what I tried to do, but it gives me a warning: HashMap<String, String>[] responseArray = new HashMap[games.size()]; "Type safety: The expression of type HashMap[] needs unchecked conversion to conform to HashMap[]"

    Read the article

  • Can I put some form of If..End blocks inside of a hash definition?

    - by Benjamin Manns
    I am creating a web application to integrate with Chargify. I want to return a hash with customer_id set if the user has a customer associated with the account, and customer_attributes if a customer has to be created. Is there any way that I could do this with an if..end block inside of the hash definition. For example, I would be wanting to do something like the following (does not work): def subscription_params(product_id) { :product_id => product_id, if customer_id.nil? :customer_attributes => customer_params, else :customer_id => customer_id, end :credit_card_attributes => credit_card_params } end

    Read the article

  • Easiest way to pass a javascript array or its values to a servlet and convert to a HashMap

    - by Ankur
    I have a Javascript array. I want to pass it's data to a servlet using the ajax() method of jQuery. What is the easiest way to do this. The index values i.e. the i in array[i] are not in order, they are numbers that have meaning themselves, hence I cannot simply loop through and create a GET queryString, or so I believe. Maybe I should be converting the JavaScript array to a JSON Object and sending that to the server ?? I am stumped on this one.

    Read the article

  • Copy one jagged array ontop of another.

    - by George Johnston
    How could I accomplish copying one jagged array to another? For instance, I have a 5x7 array of: 0, 0, 0, 0, 0, 0, 0 0, 0, 0, 0, 0, 0, 0 0, 0, 0, 0, 0, 0, 0 0, 0, 0, 0, 0, 0, 0 0, 0, 0, 0, 0, 0, 0 and a 4x3 array of: 0,1,1,0 1,1,1,1 0,1,1,0 I would like to be able to specify a specific start point such as (1,1) on my all zero array, and copy my second array ontop of it so I would have a result such as: 0, 0, 0, 0, 0, 0, 0 0, 0, 1, 1, 0, 0, 0 0, 1, 1, 1, 1, 0, 0 0, 0, 1, 1, 0, 0, 0 0, 0, 0, 0, 0, 0, 0 What would be the best way to do this?

    Read the article

  • PHP - How to modify multi-dimensional array item from within a function?

    - by Marc
    My problem is as follows. I have a multidimensional array. I declare my array. Then, I run some code that populates my array partially. Then i run a function, which among others is supposed to modify some item in my array from within the function. This is unfortunately not working. So my question is simple. Is it normal? And if yes, how can I overcome this. Thank you very much in advance for your replies. Cheers. Marc. $list = array([0]=> array( [name]=>'James' [group]=>'' ) ); my_function(); print_r($list); function my_function(){ //some code here $list[0]['group'] = 'groupA'; }

    Read the article

  • How to structurally display a multi-dimensional array in PHP?

    - by Jaime Cross
    How can I display the contents of an array as follows: Company Name - Username1 - Username2 Another Company Name - Username3 The array I have created is as follows: $array[1]['company_id'] = '12'; $array[1]['company_name'] = 'ABC Company'; $array[1]['company_type'] = 'default'; $array[1]['user_id'] = '23'; $array[1]['user_name'] = 'Andrew'; $array[2]['company_id'] = '12'; $array[2]['company_name'] = 'ABC Company'; $array[2]['company_type'] = 'default'; $array[2]['user_id'] = '27'; $array[2]['user_name'] = 'Jeffrey'; $array[3]['company_id'] = '1'; $array[3]['company_name'] = 'Some Company'; $array[3]['company_type'] = 'default'; $array[3]['user_id'] = '29'; $array[3]['user_name'] = 'William'; $array[4]['company_id'] = '51'; $array[4]['company_name'] = 'My Company'; $array[4]['company_type'] = 'default'; $array[4]['user_id'] = '20'; $array[4]['user_name'] = 'Jaime';

    Read the article

  • perl array of array of hashes sorting

    - by srk
    @aoaoh; $aoaoh[0][0]{21} = 31; $aoaoh[0][0]{22} = 31; $aoaoh[0][0]{23} = 17; for $k(0.. $#aoaoh) { for $i(0.. $#aoaoh) { for $val (keys %{$aoaoh[$i][$k]}) { print "$val=$aoaoh[$i][$k]{$val}"; print "\n"; }} } output is 22=31 21=31 23=17 but i expect it to be 21=31 22=31 23=17 Please tell me where is this wrong.. Also how do i sort the values so that i get the output as 23=17 22=31 21=31 (if 2 keys have same value then key with higher value come first)

    Read the article

  • Sorting By Multiple Conditions in Ruby

    - by viatropos
    I have a collection of Post objects and I want to be able to sort them based on these conditions: First, by category (news, events, labs, portfolio, etc.) Then by date, if date, or by position, if a specific index was set for it Some posts will have dates (news and events), others will have explicit positions (labs, and portfolio). I want to be able to call posts.sort!, so I've overridden <=>, but am looking for the most effective way of sorting by these conditions. Below is a pseudo method: def <=>(other) # first, everything is sorted into # smaller chunks by category self.category <=> other.category # then, per category, by date or position if self.date and other.date self.date <=> other.date else self.position <=> other.position end end It seems like I'd have to actually sort two separate times, rather than cramming everything into that one method. Something like sort_by_category, then sort!. What is the most ruby way to do this?

    Read the article

  • how to incorporate a function within a function

    - by bklynM
    I updated my code with string dates created with new Date and added back in the if statement. This isn't disabling the string or range though. I've added the datepicker code too. function unavailableDays(date) { function createDateRange(first, last) { var dates = []; for(var j = first; j < last; j.setDate(j.getDate() + 7)) { dates.push(new Date(j.getTime())); } var alwaysDisabled = [new Date("1963-3-10T00:00:00"), new Date("1963-3-17T00:00:00"), new Date("1963-3-24T00:00:00"), new Date("1963-3-31T00:00:00"), new Date("1965-9-18T00:00:00")]; return dates.concat(alwaysDisabled); } var disabledDays = createDateRange(new Date("1978-8-10T00:00:00"), new Date("1978-11-5T00:00:00")); var yy = date.getFullYear(), mm = date.getMonth(), dd = date.getDate(); for (i = 0; i < disabledDays.length; i++) { if($.inArray(yy + '-' + (mm+1) + '-' + dd,disabledDays) != -1 || new Date() < date) { return [false]; } } return [true]; } $(document).ready(function (){ $('.selector').datepicker({ inline: true, dateFormat: 'yy-mm-dd', constrainInput: true, changeYear: true, changeMonth: true, minDate: new Date(1940, 1-1, 1), maxDate: new Date(2011, 10-1, 24), beforeShowDay: unavailableDays, onSelect: function(dateText, inst) { $("#img").attr("src", "http://www.example.com" + dateText + ".jpg"); var chosenDates = $.datepicker.parseDate('yy-mm-dd', dateText); var backToString = $.datepicker.formatDate('MM dd' + ',' + ' yy', chosenDates); $('.info').html('You are viewing:' + '<br />' + backToString).addClass('background'); } }); });

    Read the article

  • Understanding an interesting array update/replace function

    - by dave
    I'm a PHP amateur. This array function is an adaption of a function I noticed while reading this article. I thought this was an interesting type of array function, but I have a question about the way it works. my_func( array( 'sky' => 'blue' ) ); function my_func( array $settings = array() ) { $settings = $settings + array( 'grass'=>'green','sky'=>'dark' ); print_r( $settings ) ; // outputs: Array ( [sky] => blue [grass] => green ) } but..................... my_func( array( 'sky' => 'blue' ) ); function my_func( array $settings = array() ) { $settings = array( 'clock'=>'time' ) ; $settings = $settings + array( 'grass'=>'green','sky'=>'dark' ); print_r( $settings ) ; // outputs: Array ( [clock] => time [grass] => green [sky] => dark ) } Why does [sky] not equal 'blue' in the second instance? Thanks.

    Read the article

  • Check if an array item is set in JS

    - by Gusepo
    Hi, I've got an array var assoc_pagine = new Array(); assoc_pagine["home"]=0; assoc_pagine["about"]=1; assoc_pagine["work"]=2; I tried if (assoc_pagine[var] != "undefined") { but it doesn't seem to work I'm using jquery, I don't know if it can help Thanks

    Read the article

  • Array.BinarySearch where a certain condition is met

    - by codymanix
    I have an array of a certain type. Now I want to find an entry where a certain condition is met. What is the preferred way to do this with the restriction that I don't want to create a temporary object to find, but instead I only want to give a search condition. MyClass[] myArray; // fill and sort array.. MyClass item = Array.BinarySearch(myArray, x=>x.Name=="Joe"); // is this possible? Maybe is it possible to use LINQ to solve it?

    Read the article

  • addmultioption array problem in Zend

    - by davykiash
    Am trying to add options in my Zend_Form_Element_Select element $monthvalues = new Zend_Form_Element_Select('month_values'); $table = new Model_DbTable_Options(); $monthvalues->addMultiOptions($table->Months()) In my Model_DbTable_Options model I have public function Months() { $array = array( '01' => 'Jan', '02' => 'Feb', '03' => 'Mar', '04' => 'Apr', '05' => 'May', '06' => 'Jun', '07' => 'Jul', '08' => 'Aug', '09' => 'Sep', '10' => 'Oct', '11' => 'Nov', '12' => 'Dec', ); return $array; } It aint giving me the desired outcome. Whats missing?

    Read the article

  • What is a custom collection?

    - by Win Coder
    A Group of objects. However i am having confusion in the following case. A sample class Class A { public string; } Class A_list { public A[] list; public A_list(A[] _list) { list = new A[_list.length]; for (int i = 0; i < _list.Length; i++) { list[i] = _list[i]; } } } static void Main(String[] args) { A[] names = new A[3] { new A("some"), new A("another"), new A("one"), }; A_list just_an_object = new A_list(names); } Which of the above is a custom collection the array or the object that holds array as a field or are both custom collections.

    Read the article

  • SQL Server: collect values in an aggregation temporarily and reuse in the same query

    - by Erwin Brandstetter
    How do I accumulate values in t-SQL? AFAIK there is no ARRAY type. I want to reuse the values like demonstrated in this PostgreSQL example using array_agg(). SELECT a[1] || a[i] AS foo ,a[2] || a[5] AS bar -- assuming we have >= 5 rows for simplicity FROM ( SELECT array_agg(text_col ORDER BY text_col) AS a ,count(*)::int4 AS i FROM tbl WHERE id between 10 AND 100 ) x How would I best solve this with t-SQL? Best I could come up with are two CTE and subselects: ;WITH x AS ( SELECT row_number() OVER (ORDER BY name) AS rn ,name AS a FROM #t WHERE id between 10 AND 100 ), i AS ( SELECT count(*) AS i FROM x ) SELECT (SELECT a FROM x WHERE rn = 1) + (SELECT a FROM x WHERE rn = i) AS foo ,(SELECT a FROM x WHERE rn = 2) + (SELECT a FROM x WHERE rn = 5) AS bar FROM i Test setup: CREATE TABLE #t( id INT PRIMARY KEY ,name NVARCHAR(100)) INSERT INTO #t VALUES (3 , 'John') ,(5 , 'Mary') ,(8 , 'Michael') ,(13, 'Steve') ,(21, 'Jack') ,(34, 'Pete') ,(57, 'Ami') ,(88, 'Bob') Is there a simpler way?

    Read the article

  • Array pointer arithmetic question

    - by Konrad
    Is there a way to figure out where in an array a pointer is? Lets say we have done this: int nNums[10] = {'11','51','23', ... }; // Some random sequence int* pInt = nNums[4]; // Some index in the sequence. ... pInt++; // Assuming we have lost track of the index by this stage. ... Is there a way to determine what element index in the array pInt is 'pointing' to without walking the array again?

    Read the article

  • Inserting only unique values into an array

    - by karl
    I have a set of values that I'm pushing into an array in the order they occur $valsArray = array(); //I process each value from a file (code removed for simplicity) //and then add into the array $valsArray[] = $val; How do I turn this into an associative array instead where the value gets inserted (as $key of associative array) only if it doesn't exist. If it does exist increment its count ($value of associative array) by 1. I'm trying to find a more efficient way of handling those values compared to what I'm doing now.

    Read the article

  • vectorized approach to binning with numpy/scipy in Python

    - by user248237
    I am binning a 2d array (x by y) in Python into the bins of its x value (given in "bins"), using np.digitize: elements_to_bins = digitize(vals, bins) where "vals" is a 2d array, i.e.: vals = array([[1, v1], [2, v2], ...]). elements_to_bins just says what bin each element falls into. What I then want to do is get a list whose length is the number of bins in "bins", and each element returns the y-dimension of "vals" that falls into that bin. I do it this way right now: points_by_bins = [] for curr_bin in range(min(elements_to_bins), max(elements_to_bins) + 1): curr_indx = where(elements_to_bins == curr_bin)[0] curr_bin_vals = vals[:, curr_indx] points_by_bins.append(curr_bin_vals) is there a more elegant/simpler way to do this? All I need is a list of of lists of the y-values that fall into each bin. thanks.

    Read the article

  • Convert array to nested HTML list

    - by Frank
    I have a 2 dimensional array. And each value contains a depth. What I want is that the the array is converted to a (unordered) HTML list. I already found a solution in PHP DOMDocument, but I can't really use it since I have to add a lot of classes and content to the HTML. I' have tried to make something myself, but it didn't workout. Here's the array: array ( 0 => array ( 'name' => 'ELECTRONICS', 'depth' => '0', ), 1 => array ( 'name' => 'TELEVISIONS', 'depth' => '1', ), 2 => array ( 'name' => 'TUBE', 'depth' => '2', ), 3 => array ( 'name' => 'LCD', 'depth' => '2', ), 4 => array ( 'name' => 'PLASMA', 'depth' => '2', ), 5 => array ( 'name' => 'PORTABLE ELECTRONICS', 'depth' => '1', ), 6 => array ( 'name' => 'MP3 PLAYERS', 'depth' => '2', ), 7 => array ( 'name' => 'FLASH', 'depth' => '3', ), 8 => array ( 'name' => 'CD PLAYERS', 'depth' => '2', ), 9 => array ( 'name' => '2 WAY RADIOS', 'depth' => '2', ), ) The array has to be converted to a list like this: ELECTRONICS TELEVISIONS TUBE LCD PLASMA PORTABLE ELECTRONICS MP3 PLAYERS FLASH CD PLAYERS 2 WAY RADIOS Thanks in advance, Frank

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 42 43 44 45 46 47 48 49 50 51 52 53  | Next Page >