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  • Error compiling basic java code

    - by Michael Younani
    New to java. Practicing coding by following a book. Heres my code: class Motorcycle { //Three instance variables - make and color are strings. while a boolean refers to TRUE OR FLASE(in this case off or on) String make; String color; boolean engineState; void startEngine() { if (engineState == true) System.out.print("The engine is already on."); else { engineState = true; System.out.print("The engine is now on."); } void showAtts() { System.out.print("This motorcycle is a " + color + " " + make); if (engineState ==true) System.out.print("The engine is on."); else System.out.print("The engine is off."); } } } When I compile I get 2 errors: 1) illegal start of expression 2) ; expected I can't pin point the problem. If anyone can direct me or hint me please do.

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  • Output error in comparing characters from two strings

    - by Andrew Martin
    I'm stuck with my a piece of code I'm creating. My IDE is Eclipse and when I use its debugging feature, to trace what's happening on each line, it outputs perfectly. However, when I click the "run" project, it just outputs a blank screen: public static void compareInterests(Client[] clientDetails) { int interests = 0; for (int p = 0; p < numberOfClients; p++) { for (int q = 0; q < numberOfClients; q++) { String a = clientDetails[p].getClientInterests(); String b = clientDetails[q].getClientInterests(); int count = 0; while (count < a.length()) { if (a.charAt(count) == b.charAt(count)) interests++; count++; } if ((interests >= 3) && (clientDetails[p].getClientName() != clientDetails[q].getClientName())) System.out.print (clientDetails[p].getClientName() + " is compatible with " + clientDetails[q].getClientName()); interests = 0; } } } The code is designed to import an object array which contains information on a client's name and a client's interests. The client's interests are stored in the format "01010", where each 1 means they are interested in that activity, each 0 means they are not. My code compares each character of every client's string with every other client's string and outputs the results for all client's that don't have the same name and have three or more interests in common. When I run this code through Java's debugger, it outputs fine - but when I click run project or compile, I just get a blank screen. Any ideas?

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  • SQL/ASP connection error

    - by tm1
    Line 10: Line 11: <asp:SqlDataSource ID="ac210db6" runat="server" Line 12: ConnectionString="<%$ ConnectionStrings:ac210db6ConnectionString %>" Line 13: SelectCommand="SELECT [cid] FROM [customers]"></asp:SqlDataSource><br /> The connection name 'ac210db6ConnectionString' was not found in the applications configuration or the connection string is empty. Description: An unhandled exception occurred during the execution of the current web request. Exception Details: System.InvalidOperationException: The connection name 'ac210db6ConnectionString' was not found in the applications configuration or the connection string is empty. Any ideas?

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  • error in a c code while trying to remove whitespace

    - by mekasperasky
    this code is the base of lexer , and it does the basic operation of removing the whitespaces from a source file and rewrites it into another file with each word in separate lines . But i am not able to understand why the file lext.txt not getting updated? #include<stdio.h> /* this is a lexer which recognizes constants , variables ,symbols, identifiers , functions , comments and also header files . It stores the lexemes in 3 different files . One file contains all the headers and the comments . Another file will contain all the variables , another will contain all the symbols. */ int main() { int i; char a,b[20],c; FILE *fp1,*fp2; fp1=fopen("source.txt","r"); //the source file is opened in read only mode which will passed through the lexer fp2=fopen("lext.txt","w"); //now lets remove all the white spaces and store the rest of the words in a file if(fp1==NULL) { perror("failed to open source.txt"); //return EXIT_FAILURE; } i=0; while(!feof(fp1)) { a=fgetc(fp1); if(a!="") { b[i]=a; printf("hello"); } else { b[i]='\0'; fprintf(fp2, "%.20s\n", b); i=0; continue; } i=i+1; /*Switch(a) { case EOF :return eof; case '+':sym=sym+1; case '-':sym=sym+1; case '*':sym=sym+1; case '/':sym=sym+1; case '%':sym=sym+1; case ' */ } return 0; }

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  • How can I set up disk quotas on a remote server in a Samba environment?

    - by graf_ignotiev
    I've been working with an install of Ubuntu 8.04 and Samba. I'm trying to set up user disk space quotas for our shared drive. That is, each user will have their own folder on our Network Attached Storage (NAS) that has a size limit. I can successfully mount the shared drive, but I can't figure out how to set quotas on it (I think smbcquota might work, but I'm not sure). It's been suggested to me to give each user a share on the shared drive or to use NFS. Unfortunately, neither option works for my purposes. Does anyone know how I could give users a quota on my NAS?

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  • Missing Localized Screenshots Error on itunes

    - by Arvind
    I have selected Default Language as "Australian English" as Default language. When I am submitting the binary it showing as rejected"Red Icon" with status "Missing Localized Screenshots". The application is in only single language. I have added screen shots also the application is only for iphone. When I am looking binary information that is showing as: Localizations : ( "en-AU" ) Please suggest me where I am making mistake.

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  • C++ Template Iterator error

    - by gprime
    I am going over some code i wrote in 2006 as an undergrad. It's a simple genetic algorithm library written in C++ using templates. It use to work in 2006 when i coded it with visual studio, but now when i am trying to run it in xcode i get compile errors. This function is giving me errors: friend bool operator==(const TSPGenome<T> & t1, const TSPGenome<T> & t2) { // loop through each interator and check to see if the two genomes have the same values if(t1.genome_vec->size() != t2.genome_vec->size()) return false; else { // iterate through each vector<T>::iterator it_t1; vector<T>::iterator it_t2; it_t1 = t1.genome_vec->begin(); for(it_t2 = t2.genome_vec->begin(); it_t2 != t2.genome_vec->end(); ++it_t2, ++it_t1) { if(*it_t2 != *it_t1) return false; } } // everything seems good return true; } xcode complains about these two lines not having ; before it_t1 and it_t2. vector<T>::iterator it_t1; vector<T>::iterator it_t2; Is it because the vector type it T? I declared it in the class as follows: template <typename T> class TSPGenome : public Genome { Any help would be appreciated. Thanks!

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  • unset in Varnish - syntax error

    - by Dude
    I'm trying to hide the "Server" header returned by Apache on every request, from Varnish. Using in sub vcl_fetch: unset obj.http.Server; on Varnish start I get: Expected action, 'if' or '}' (/etc/varnish/default.vcl Line 43 Pos 9) unset obj.http.Server; --------#####----------------- Any ideas?

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  • Getting the error "Missing $ inserted" in LaTeX

    - by Espenhh
    Hey, I try to write the following in latex: \begin{itemize} \item \textbf{insert(element|text)} inserts the element or text passed at the start of the selection. \item \textbf{insert_after(element|text)} inserts the element or text passed at the end of the selection. \item \textbf{replace(element|text)} replaces the selection with the passed text/element. \item \textbf{delete()} deletes the selected text. \item \textbf{annotate(name,value)} annotates the selected text with the passed name and value-pair. This can either be a hidden meta-data about the selection, or can alter the visible appearance. \item \textbf{clear_annotation()} removes any annotation for this specific selection. \item \textbf{update_element(value)} performs an update of the element at the selection with the passed value. \end{itemize} For some reason, I get a bunch of errors. I think there is something with the use of the word "insert". I get errors like "Missing $ inserted", so it seems like the parses tries to fix some "errors" on my parts. Do I need to escape words like "insert", how do I do that?

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  • Mechanize Submit Form Error: Insufficient items with name '10427'

    - by maneh
    I'm trying to submit a form with Mechanize, I have tried different ways, but the problem persists. Can anyone help me on this. Thank you in advance! This is the form I want to submit: http://www.stpairways.st/ This is the code that I'm using: def stp_airways(url): import re import mechanize br = mechanize.Browser() br.open(url) print br.title() br.select_form(name = "frmbook") br.form['TypeTrajet'] = ["1"] br.form['id_depart'] = ["11967"] br.form['id_arrivee'] = ["10427"] br.form['txtDateAller'] = "5/7/2014" br.form['txtDateRetour'] = "12/7/2014" br.form['TypePassager1u1000r0b1'] = ["1"] br.form['TypePassager2u1000r0b1'] = ["0"] br.form['TypePassager3u1000r0b1'] = ["0"] br.form['CodeIsoDeviseClient'] = ["17,20,23,24,25,26,27,28,29,30,31,33,34,36,37,64,65,67,68,70,73,80,81,95,96,103,147,151,152,159,160,162,169,170TP1TPF"] br.form['CodeIsoDeviseClient'] = ["EUR"] # submit response1 = br.submit() print response1.read()

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  • Where is the error in my code?

    - by Lulu Larson
    /** Yields: a String that contains each capital Letter (in 'A'..'Z') whose representation is prime */ public static String primeChars() { String s = ""; // inv: s contains each capital in "A'..c-1 whose representation is prime for (char c = 'A'; c <= 'Z'; c=(char)(c+1)) { if (Loops.isPrime((int)c) == true) { s= s+1; } } // s contains each capital in 'A' ..'Z' whose rep is a prime return s; }

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  • out of memory error , my app's fault?

    - by arnold
    hello all, i have a aplication on the android market , in wich exceptions and errors are catched and sent to me by acra. But i receive quite a lot out of memory errors.. In different kind of classes...some my app, some general java.. Does this always mean there is a problem in my app, or can it also be the phone ran out of memory due to a other process? Will users also get a fc dialog ? thnks

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  • SQL CREATE TABLE Error

    - by Adam M-W
    Hi, I've been stuck on this one simple(ish) thing for the last 1/2 hour so I thought I might try to get a quick answer here. What exactly is incorrect about my SQL syntax, assuming I'm using mysql 5.1 CREATE TABLE 'users' ( 'id' MEDIUMINT(8) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY, 'username' VARCHAR(20) NOT NULL, 'password' VARCHAR(40) NOT NULL, 'salt' VARCHAR(40) DEFAULT NULL, 'email' VARCHAR(80) NOT NULL, 'created_on' INT(11) UNSIGNED NOT NULL, 'last_login' INT(11) UNSIGNED DEFAULT NULL, 'active' TINYINT(1) UNSIGNED DEFAULT NULL, ) ENGINE InnoDB; Also, does anyone have any good tutorials about how to use Zend_Auth for complete noobs? Thanks.

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  • Analyze VS2010 C# projects and report files on disk not part of the projects?

    - by Lasse V. Karlsen
    I discovered earlier tonight that files and folders I have removed from my C# projects are apparently still on disk, even though my Visual Studio Mercurial plugin seems to do a good job of deleting them when I delete them in Visual Studio. It must have hickuped when it came to these files. So I wondered... Does anyone have a script or similar, or know of something, that will look at my .csproj files and report extra files and folders on my disk that isn't part of the project files? I just want to clean up my repository contents.

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  • Error in create back up in mysql through java program

    - by Arivu2020
    Runtime.getRuntime().exec("C:\mysql\bin\mysqldump -u root -pmypassword Databasename -r C:/backup.sql"); I am using this code to create back up from my sql. but It creates the empty file in the path.Because it is waiting in the command prompt to get the password. How can i give password to it Using command prompt directly when i press enter after typing, it asks password.After giving password,It creates the backup.Give me any solution for this Thanks in advance

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  • Mysql Connection Error from 1.1.1 to 1.2.1

    - by Chromag
    I upgraded from 1.1.1 to 1.2.1 and I seem to be getting the following exception when it attempts to connect to MySQL: The last packet sent successfully to the server was 0 milliseconds ago. The driver has not received any packets from the server. at com.mysql.jdbc.Util.handleNewInstance(Util.java:407) at com.mysql.jdbc.SQLError.createCommunicationsException(SQLError.java:1116) at com.mysql.jdbc.MysqlIO.<init>(MysqlIO.java:343) ... Caused by: java.net.ConnectException: Connection refused at java.net.PlainSocketImpl.socketConnect(Native Method) at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:333) at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:195) I've confirmed that MySQL is indeed running and seems to be working fine. The following is the line from my application.conf file (with user/pass/db replaced): db=mysql:username:password@databasename I also tried using the full JDBC configuration. Did I miss something? This worked just fine in 1.1.1. I'm running MySQL 5.1.41. Thanks.

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  • Sleep Function Error In C

    - by Arman
    I have a file of data Dump, in with different timestamped data available, I get the time from timestamp and sleep my c thread for that time. But the problem is that The actual time difference is 10 second and the data which I receive at the receiving end is almost 14, 15 second delay. I am using window OS. Kindly guide me. Sorry for my week English.

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  • Error in inserting data into database

    - by Matthew
    When I try to run this code it will not insert the data into the database? <?php class Database { private $dsn; function __construct($dbname, $host, $user, $password, $enckey) { $this->dsn = "mysql:dbname=" . $dbname . ';host=' . $host; $this->user = $user; $this->password = $password; } private function createDSN() { return $this->dsn; } public function createConnection() { try { $dbh = new PDO(self::createDSN(), $this->user, $this->password); } catch (PDOException $e) { echo 'Connection failed: ' . $e->getMessage(); } return $dbh; } } $db = new Database('mytest', 'localhost', 'root', 'hashedpassword', null); $dbh = $db->createConnection(); $sql = $dbh->prepare("INSERT INTO contacts (firstname, lastname) VALUES (?,?)"); $sql->execute(array("abc", "xyz")); ?>

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  • Error during data INSERT in php

    - by nectar
    here my code- $sql = "INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES "; for($i=0; $i0) { $sql .= ", "; } $sql .= "('$pin[$i]', '$ownerid', 'Free', '1')"; } $sql .= ";"; echo $sql; mysql_query($sql); if(mysql_affected_rows() 0) { echo "done"; } else { echo "Fail"; } output: ** INSERT INTO tblpin ('pinId', 'ownerId', 'usedby', 'status') VALUES ('13837927', 'admin', 'Free', '1'), ('59576082', 'admin', 'Free', '1'); Fail why it is not inserting values when $sql query is right?

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  • PHP: Need a double check on an error in this small code

    - by Josh K
    I have this simple Select box that is suppose to store the selected value in a hidden input, which can then be used for POST (I am doing it this way to use data from disabled drop down menus) <body> <?php $Z = $_POST[hdn]; ?> <form id="form1" name="form1" method="post" action="test.php"> <select name="whatever" id="whatever" onchange="document.getElementById('hdn').value = this.value"> <option value="1">1Value</option> <option value="2">2Value</option> <option value="3">3Value</option> <option value="4">4Value</option> </select> <input type="hidden" name ='hdn' id="hdn" /> <input type="submit" id='submit' /> <?php echo "<p>".$Z."</p>"; ?> </form> </body> The echo call works for the last 3 options (2,3,4) but if I select the first one it doesnt output anything, and even if i change first one it still doesnt output anything. Can someone explain to me whats going on, I think it might be a syntax issue.

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  • Testing variable types in Python

    - by Jasper
    Hello, I'm creating an initialising function for the class 'Room', and found that the program wouldn't accept the tests I was doing on the input variables. Why is this? def __init__(self, code, name, type, size, description, objects, exits): self.code = code self.name = name self.type = type self.size = size self.description = description self.objects = objects self.exits = exits #Check for input errors: if type(self.code) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 110' elif type(self.name) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 111' elif type(self.type) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 112' elif type(self.size) != type(int()): print 'Error found in module rooms.py!' print 'Error number: 113' elif type(self.description) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 114' elif type(self.objects) != type(list()): print 'Error found in module rooms.py!' print 'Error number: 115' elif type(self.exits) != type(tuple()): print 'Error found in module rooms.py!' print 'Error number: 116' When I run this I get this error: Traceback (most recent call last): File "/Users/Jasper/Development/Programming/MyProjects/Game Making Challenge/Europa I/rooms.py", line 148, in <module> myRoom = Room(101, 'myRoom', 'Basic Room', 5, '<insert description>', myObjects, myExits) File "/Users/Jasper/Development/Programming/MyProjects/Game Making Challenge/Europa I/rooms.py", line 29, in __init__ if type(self.code) != type(str()): TypeError: 'str' object is not callable

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