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  • Android 2.1 address bar causes change in viewport dimensions

    - by davehumyo
    Hi, I have a page that has a 100% width and height div in it (all surrounding elements are sized accordingly so that it does actually achieve 100% width and height). Below that div I have a second div with a fixed height. In mobile safari and blackberry everything is fine, when the page loads the dimensions are applied correctly (the top div filling the viewport) and the user can scroll down to reveal the second div. Android 2.1 also applies the dimensions correctly, but with an added quirk; when the user scrolls down and removes the address bar from the page, the dimensions of the div are recalculated to fill the viewport, causing the content to jump. Ideally I would like the dimensions of the div to remain static when the page is scrolled, but remain 100% so that it will fill the viewport regardless of device size or orientation. Does anyone know of any way to disable this recalculation? Thanks for any help you can provide.

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  • ASP.NET web control with the same ID

    - by user370401
    On an ASP.NET page, if the ASP.NET elements like <asp:Texbox ID="Textbox1"> appears in more than one place, are they the same Textbox object or are they different objects with the same name "Textbox1"? If the same, "why won't it cause any conflicts?" E.G. runat="server" Text='<%# Bind("Name") %' runat="server" Text='<%# Bind("Name") %' '

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  • Format SQL Query Result into web menu

    - by highwingers
    I am trying to bhuild a drill down menu for my website, where user will click on a category and it will show the subcategories of that clicked category, there could be n-levels. I am able to write sql query which returns the output exactaly as I want, but the problem is...I dont want to show the whole menu to end user, I would like to open/expand only clicked category. my Query output is: 1 IPTV 2 Jadoo Tv 3 Shava Tv 4 Jalva Tv 5 Programming 6 Microsoft 7 Asp.Net 8 PHP so by default IPTV & Programming Should be displayed, since they are parent, and when I click on IPTV it should open the children of IPTV, like I said there could be n-levels. I was thinking, I can load the output of query to webpage and then control the menu navigation with css/javascript. do you guys have any ideas?

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  • Amazone API ItemSearch returns (400) Bad Request.

    - by BuzzBubba
    I'm using a simple example from Amazon documentation for ItemSearch and I get a strange error: "The remote server returned an unexpected response: (400) Bad Request." This is the code: public static void Main() { //Remember to create an instance of the amazon service, including you Access ID. AWSECommerceServicePortTypeClient service = new AWSECommerceServicePortTypeClient(new BasicHttpBinding(), new EndpointAddress( "http://webservices.amazon.com/onca/soap?Service=AWSECommerceService")); AWSECommerceServicePortTypeClient client = new AWSECommerceServicePortTypeClient( new BasicHttpBinding(), new EndpointAddress("http://webservices.amazon.com/onca/soap?Service=AWSECommerceService")); // prepare an ItemSearch request ItemSearchRequest request = new ItemSearchRequest(); request.SearchIndex = "Books"; request.Title = "Harry+Potter"; request.ResponseGroup = new string[] { "Small" }; ItemSearch itemSearch = new ItemSearch(); itemSearch.Request = new ItemSearchRequest[] { request }; itemSearch.AWSAccessKeyId = accessKeyId; // issue the ItemSearch request try { ItemSearchResponse response = client.ItemSearch(itemSearch); // write out the results foreach (var item in response.Items[0].Item) { Console.WriteLine(item.ItemAttributes.Title); } } catch(Exception e) { Console.ForegroundColor = ConsoleColor.Red; Console.WriteLine(e.Message); Console.ForegroundColor = ConsoleColor.White; Console.WriteLine("Press any key to quit..."); Clipboard.SetText(e.Message); } Console.ReadKey(); What is wrong?

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  • creating existing users on AWS when they don't have a group

    - by Jon Strayer
    It seems when chef creates a user with the id of "foobar" it also creates a group with the id of "foobar". AWS doesn't do that. So, when I run my create users script via Opsworks it blows up on the first user that already exists because the group doesn't. I thought there was a way to say create the user but not the group, but I can't find it. What's the best way to solve this problem? Can I: Tell chef to not create the user's group? Tell chef to create it if the user exists but the group doesn't? Write a script that finds the existing users and creates groups for them? Something else?

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  • Using Durable Services for saving wcf instances

    - by miker169
    I am currently creating a service which connects to a DAL and that can run a few stored procedures, one of the issues I am facing is that for certain times of the month, we can't update the database, (at the moment this is done manually. This is done via the user adding a note to their calendar) But I would like to automate this process, one of the possible solutions I can think of using is a durable service. When the date is lets say the 1st of the month, the Update/Insert/Delete instances can get saved to a database, and then ran after that date in a batch. Is this the intended use of durable services ? Is there a better route I could possibly take ?

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  • Organize array in PHP from mysql

    - by Matthew Carter
    Hi i have a social networking website. what i want it to do is pull out my friends status updates. basically what it does is i have a mysql query that pulls out all of my friends and in that while loop there is another mysql query that pulls out the status's from my friends. i want it to be in order of date but since its one while loop in another what it does is pull out all status's from friend 1 then 2 then 3 and not in order by date. i even tried ORDER BY DATE but that just ordered it by date within the friend.. my thought is that i could putt it all in an array and friends is one thing and the values is the stats. then just sort by values would this work and how could i do it. THANKS SO MUCH

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  • Creating a fixed background for a website

    - by ShiVik
    Hello all I am trying to implement a fixed background for a website like one over here. Searching around for it told me that I can use background: fixed or background-attachment properties for this. My problem is the image which will be used as background. I am thinking about following issues: What should be image size? how will it repeat when browser window size is very large? for big 27" monitors out there? Can somebody guide me on these points? Regards Vikram

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  • How to automate testing of a browser-based app?

    - by mawg
    If it were a windows program, I would use Auto it to automate testing. Is there something similar for browser-based apps? Nothing too complex, it should just allow scripting (preferable for me to macro-recording) to simulate human interaction with the browser, which means being able to identify fields of a form by name, inject text into some, simulate mouse-click on others, etc and then, after submitting a form, should be able to read text certain named controls, check the status of others (checked, radio group index, read-only, etc). While I do appreciate a full featured product, I don't appreciate a steep learning curve. so something as simple as the scripting of Auto It woudl be fine. I don't know if it makes a difference which browser is used, but I could live with MSIE 6 or higher (maybe 7 or higher at a push).

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  • Image_tag .blank? - paperclip - Ruby on rails

    - by bgadoci
    I have just installed paperclip into my ruby on rails blog application. Everything is working great...too great. I am trying to figure out how to tell paperclip not to output anything if there is no record in the table so that I don't have broken image links everywhere. How, and where, do I do this? Here is my code: class Post < ActiveRecord::Base has_attached_file :photo, :styles => { :small => "150x150"} validates_presence_of :body, :title has_many :comments, :dependent => :destroy has_many :tags, :dependent => :destroy has_many :ugtags, :dependent => :destroy has_many :votes, :dependent => :destroy belongs_to :user after_create :self_vote def self_vote # I am assuming you have a user_id field in `posts` and `votes` table. self.votes.create(:user => self.user) end cattr_reader :per_page @@per_page = 10 end View <% div_for post do %> <div id="post-wrapper"> <div id="post-photo"> <%= image_tag post.photo.url(:small) %> </div> <h2><%= link_to_unless_current h(post.title), post %></h2> <div class="light-color"> <i>Posted <%= time_ago_in_words(post.created_at) %></i> ago </div> <%= simple_format truncate(post.body, :length => 600) %> <div id="post-options"> <%= link_to "Read More >>", post %> | <%= link_to "Comments (#{post.comments.count})", post %> | <%= link_to "Strings (#{post.tags.count})", post %> | <%= link_to "Contributions (#{post.ugtags.count})", post %> | <%= link_to "Likes (#{post.votes.count})", post %> </div> </div> <% end %>

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  • general things developer must know having 2+ years of exp?

    - by Salil
    Hi All, I have 2 years of experience in Ruby on Rails. I have basic knowledge (Very Basic) of mysql such as data insertion, join, select from more than one table. But now i want to know more about it cause my friends are having trouble in interview when ask questions like 1] What is the trigger. 2] which trigger call when 3] what's views in mysql? etc....... are this questions for developers?is it basic database? Also what other things developer should know having experience of 2 years or more. I am in double mind as i have over two years of exp. in ruby and i am learning new thing everyday in ruby only. if someone ask me to rate yourself i can't give more than 5 out of 10 in ROR only. So my question is What are the general things developer must know having 2+ years of exp? Regards, Salil Gaikwad

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  • Adding search for a private website

    - by Vitor Py
    I have a login-protected website. It's an internal application and it's not avaiable to the general public hence it's not indexed by any search engine. My application is developed on the Google App Engine. I would like to add a search engine but obviously without the need to public index it. There's any solution avaiable from Google/Bing/Others for a situation like this? Have you done this before? What solution did you chose and what are yours results?

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  • Killing Mysql processes staying in sleep command.

    - by Shino88
    Hey I am connecting a MYSQL database through hibernate and i seem to have processes that are not being killed after they are finished in the session. I have called flush and close on each session but when i check the server the last processes are still there with a sleep command. This is a new problem which i am having and was not the case yesterday. Is there any way i can ensure the killng of theses processes when i am done with a session. Below is an example of one of my classes. public JSONObject check() { //creates a new session needed to add elements to a database Session session = null; //holds the result of the check in the database JSONObject check = new JSONObject(); try{ //creates a new session needed to add elements to a database SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); session = sessionFactory.openSession(); if (justusername){ //query created to select a username from user table String hquery = "Select username from User user Where username = ? "; //query created Query query = session.createQuery(hquery); //sets the username of the query the values JSONObject contents query.setString(0, username); // executes query and adds username string variable String user = (String) query.uniqueResult(); //checks to see if result is found (null if not found) if (user == null) { //adds false to Jobject if not found check.put("indatabase", "false"); } else { check.put("indatabase", "true"); } //adds check to Jobject to say just to check username check.put("justusername", true); } else { //query created to select a username and password from user table String hquery = "Select username from User user Where username = :user and password = :pass "; Query query = session.createQuery(hquery); query.setString("user", username); query.setString("pass", password); String user = (String) query.uniqueResult(); if(user ==null) { check.put("indatabase", false); } else { check.put("indatabase", true); } check.put("justusername", false); } }catch(Exception e){ System.out.println(e.getMessage()); //logg.log(Level.WARNING, " Exception", e.getMessage()); }finally{ // Actual contact insertion will happen at this step session.flush(); session.close(); } //returns Jobject return check; }

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  • How can I keep data that a user has entered in my jQuery/Ajax pop-up form?

    - by Lucas McCoy
    I have a form on a website I'm working (you can see it here) on that allows my users to give feedback. It's an jQuery/Ajax popup form: $('.contact_us').click(function(){ var boxy_content; boxy_content += "<div style=\"width:300px; height:300px \"><form id=\"feedbacked\">"; boxy_content += "<p>Subject<br /><input type=\"text\" name=\"subject\" id=\"subject\" size=\"33\" /></p><p>Your E-Mail Address:<br /><input type=\"text\" name=\"your_email\" size=\"33\" /></p><p>Comment:<br /><textarea name=\"comment\" id=\"comment\" cols=\"33\" rows=\"5\"></textarea></p><br /><input type=\"submit\" name=\"submit\" value=\"Send >>\" />"; boxy_content += "</form></div>"; // Other code here... Is there anyway I can save what the user has entered (in case they see our error message when they try to submit)?

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  • get cookie after set cookie

    - by user1432779
    I've set my cookie using set-cookie as follows on the server's cgi scripts print """Content-type: text/html\r\n""", print """Set-Cookie: name=value\r\n\r\n""", but when I reload the page I can't get the cookie as it doesn't appear on document.cookie How do I get the cookies? and was Set-cookie : name=value supposed to appear on document.cookie after I refresh the page? Overall I want the client side to recognize the cookie if exists and act accordingly Thanks

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  • How web apps ask location of mobile device?

    - by kikkoman90
    Hello, Many modern mobile phones (google nexus one etc.) have some kind of built in location service. when i go to a some website (eg. google.com) that website asks if I'm willing to share my location with that site. How do you actually ask for mobile device to give out it's location to the site? And in what format is that location given? I've got no clue and didn't find any answers from google, neither.

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  • Dynamically Adding ASP.NET Web Forms Controls Loses State on Page Refresh

    - by Geetha
    I am creating dynamic label and textbox based on the number of values from the database for the selected item of the dropdownlist. Then the dynamic labels will have the names and the text box with the values. To retain the values of these controls im using Page_init event. So im using cache to hold the selectteditem from the dropdownlist. Problem: The process is going fine. But if i try to refresh the page no items are selected in the dropdown list but the cache is not getting clear so using this cache value dynamic control are creating.

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  • how to scrawl file hosting website with scrapy in python?

    - by Veryel Hua
    Can anyone help me to figure out how to scrawl file hosting website like filefactory.com? I don't want to download all the file hosted but just to index all available files with scrapy. I have read the tutorial and docs with respect to spider class for scrapy. If I only give the website main page as the begining url I wouldn't not scrawl the whole site, because the scrawling depends on links but the begining page seems not point to any file pages. That's the problem I am thinking and any help would be appreciated!

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  • PHP registration script: verifying and telling the user what went wrong

    - by Maxime
    Hi, I'm building a registration script and I want to insert the user's input (username, mail) ONLY if it's not already in the database. What I usually do in such cases is a request to see if something's already there, something like: "SELECT * FROM things WHERE thing_name = '$treated_user_input'". I have two fields that need to be unique this time though. Is there a way to do only one SELECT request and still be able to tell the user exactly what field went wrong? Or do I have to do one request per unique field? Thanks for your answers.

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  • Grab remaining text after last "/" in a php string.

    - by Roeland
    So, lets say I have a $somestring thats holds the value "main/physician/physician_view". I want to grab just "physician_view". I want it to also work if the passed string was "main/physician_view" or "site/main/physician/physician_view". Hopefully my question makes sense. Any help would be appreciated!

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  • a query is inserted from PHPMYAdmin but not from PHP

    - by iyad al aqel
    i'm writing a php code to insert form values in a forum values $dbServer = mysql_connect("localhost" , "root", "") ; if(!$dbServer) die ("Unable to connect"); mysql_select_db("kfumWonder"); $name= $_POST['name'] ; $password= md5($_POST['password']); $email= $_POST['email'] ; $major= $_POST['major'] ; $dateOfBirth=$_POST['dateOfBirth'] ; $webSite = $_POST['website']; $joinDate= date("Y m d") ; $query = "INSERT INTO user (name, password, email, major, dob, website, join_date) Values ('$name', '$password', '$email', '$major', '$dateOfBirth', '$webSite' , '$joinDate')" ; //echo $query ; $result = mysql_query($query) ; if (! $result ) echo " no results " ; this works perfectly fine when i took the printed query and run it in PHPMyAdmin but when i run this code nothing happens , any ideas !?

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