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  • hidden form element not bound?

    - by csetzkorn
    Is it standard/intended behaviour that the value of a hidden form field is not bound to the view model (nor is a query string value)? Example: <%= Html.Hidden("test", "13" )%> if my poco view model contains a property test it should be bound shouldn't it?! i have to set it explicitely in the controller at the moment which kind of defeats the objective doesn't it? bla( formviewmodel m, string test) { m.test = test; } any feedback appreciated. thanks! christian

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  • How to Import data from Excel 2010 to SQL table

    - by user2950101
    I am using this , Insert into smst(id,mobile,day,month,year,time,model,imie1,imie2,FullMessage)select * FROM OPENROWSET('Microsoft.Ace.OLEDB.14.0','Excel 14.0;Database=L:\SMS.xlsx;HDR=YES', 'SELECT id,mobile,day,month,year,time,model,imie1,imie2,FullMessage FROM [Sheet2]') Could you please help and find the error? sql error : 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '('Microsoft.Ace.OLEDB.14.0','Excel 14.0;Database=L:\SMS.xlsx;HDR=YES', 'SELECT i' at line 1 i am using excel 2010.

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  • Getting the last User ID in Zend Framework

    - by Ryan Murphy
    Using MySQL query browser, I manually made a table called users and input some date in the fields. I set the primary key to id and set it to auto increment. There are 3 rows, the highest id is 3. I then made the following class in the method directory to call upon the data in the table etc. class Application_Model_DbTable_User extends Zend_Db_Table_Abstract { protected $_name = 'user'; public function getLatestUserId() { $id = $this->getAdapter()->lastInsertId(); return $id; } } In the controller I do the following which gets the value generated by the method and lets the view access it: $usersDbModel = new Application_Model_DbTable_User(); $lastUserId = $usersDbModel->getLatestUserId(); $this->view->lastUserId = $lastUserId; In the view I then echo it to display it to the user: echo $this->lastUserId; However, even though my last id in the users table is 3. It displays 0. I have also tried: public function getLatestUserId() { $sql = 'SELECT max(id) FROM user'; $query = $this->query($sql); $result = $query->fetchAll(); return $result; } But this just throws out a server error. What have I done wrong? Am I missing something? Is there another way of doing this?

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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): def hot(request): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created') for link in links: delta_in_hours = (int(datetime.now().strftime("%s")) - int(link.created.strftime("%s"))) / 3600 link.popularity = ((link.votes - 1) / (delta_in_hours + 2)**1.5) if request.user.is_authenticated(): try: link.voted = Vote.objects.get(link=link, user=request.user) except Vote.DoesNotExist: link.voted = None links = sorted(links, key=lambda x: x.popularity, reverse=True) links = paginate(request, links, 15) return direct_to_template( request, template = 'links/link_list.html', extra_context = { 'links': links, }) The above view actually accomplishes what I need but in what I believe to be a horribly inefficient way. This causes the dreaded n+1 queries, as it stands that's 33 queries for a page containing just 29 links while originally I got away with just 4 queries. I would really prefer to do this using Django's ORM or at least .extra(). Any advice?

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  • Does CakePHP treat all INT fields as ID's for join tables?

    - by Jonnie
    I am trying to save a User, their Profile, and some tags and my join table that links the profile and the tags keeps getting messed up. The profile model is called Instructor, the tag model is called Subject. The Instructor has a phone number and a zip code and for some reason CakePHP thinks these are the fields it should use when creating entries in my join table. My Join table always comes out as: id | instructor_id | subject_id | 1 | 90210 | 1 | // thinks that the zip code is an instructor_id 2 | 1112223333 | 1 | // thinks that the phone number is an instructor_id 3 | 1 | 1 | // thinks that user_id is an instructor_id 4 | 1 | 1 | // the actual instructor_id, this one's correct 5 | 90210 | 2 | 6 | 1112223333 | 2 | 3 | 1 | 2 | 4 | 1 | 2 | My Models: class Instructor extends AppModel { var $name = 'Instructor'; var $belongsTo = array('User', 'State'); var $hasAndBelongsToMany = array( 'Subject' = array( 'className' = 'Subject', 'joinTable' = 'instructors_subjects', 'foreignKey' = 'instructor_id', 'associationForeignKey' = 'subject_id', 'unique' = true, 'conditions' = '', 'fields' = '', 'order' = '', 'limit' = '', 'offset' = '', 'finderQuery' = '', 'deleteQuery' = '', 'insertQuery' = '' ) ); } class Subject extends AppModel { var $name = 'Subject'; var $hasAndBelongsToMany = array( 'Instructor' = array( 'className' = 'Instructor', 'joinTable' = 'instructors_subjects', 'foreignKey' = 'subject_id', 'associationForeignKey' = 'instructor_id', 'unique' = true, 'conditions' = '', 'fields' = '', 'order' = '', 'limit' = '', 'offset' = '', 'finderQuery' = '', 'deleteQuery' = '', 'insertQuery' = '' ) ); } My Model Associations: User hasOne Instructor Instructor belongsTo User Instructor hasAndBelongsToMany Subject Subject hasAndBelongsToMany Instructor My form data looks like: Array ( [User] = Array ( [username] = MrInstructor [password] = cddb06c93c72f34eb9408610529a34645c29c55d [group_id] = 2 ) [Instructor] = Array ( [name] = Jimmy Bob [email] = [email protected] [phone] = 1112223333 [city] = Beverly Hills [zip_code] = 90210 [states] = 5 [website] = www.jimmybobbaseballschool.com [description] = Jimmy Bob is an instructor. [user_id] = 1 [id] = 1 ) [Subject] = Array ( [name] = hitting, pitching ) ) My function for processing the form looks like: function instructor_register() { $this-set('groups', $this-User-Group-find('list')); $this-set('states', $this-User-Instructor-State-find('list')); if (!empty($this-data)) { // Set the group to Instructor $this-data['User']['group_id'] = 2; // Save the user data $user = $this-User-save($this-data, true, array( 'username', 'password', 'group_id' )); // If the user was saved, save the instructor's info if (!empty($user)) { $this-data['Instructor']['user_id'] = $this-User-id; $instructor = $this-User-Instructor-save($this-data, true, array( 'user_id', 'name', 'email', 'phone', 'city', 'zip_code', 'state_id', 'website', 'description' )); // If the instructor was saved, save the rest if(!empty($instructor)) { $instructorId = $this-User-Instructor-id; $this-data['Instructor']['id'] = $instructorId; // Save each subject seperately $subjects = explode(",", $this-data['Subject']['name']); foreach ($subjects as $_subject) { // Get the correct subject format $_subject = strtolower(trim($_subject)); $this-User-Instructor-Subject-create($this-data); $this-User-Instructor-Subject-set(array( 'name' = $_subject )); $this-User-Instructor-Subject-save(); echo ''; print_r($this-data); echo ''; } } } } }

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  • Is it possible to specify Jquery File Upload to post back only once (for multiple files)?

    - by JaJ
    When I upload multiple files (per bluimp jquery file upload) the [httppost] action is entered once per file. Is it possible to specify one and only one postback with an enumerated file container to iterate? View: <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script> <script src="@Url.Content("~/Scripts/jquery.ui.widget.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.iframe-transport.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.fileupload.js")" type="text/javascript"></script> <input id="fileupload" type="file" name="files" multiple="multiple"/> Controller: public ActionResult Index() { return View(); } [HttpPost] public ActionResult Index(IEnumerable<HttpPostedFileBase> files) { // This is posted back for every file that gets uploaded...I would prefer it only post back once // with a actual collection of files to iterate. foreach (var file in files) // There is only ever one file in files { var filename = Path.Combine(Server.MapPath("~/App_Data"), file.FileName); file.SaveAs(filename); } return View(); }

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  • Process for beginning a Ruby on Rails project

    - by Daniel Beardsley
    I'm about to begin a Ruby on Rails project and I'd love to hear how others go through the process of starting an application design. I have quite a bit of experience with RoR, but don't have that many starting from scratch with only a vision experiences and would appreciate the wisdom of others who've been there. I'm looking for an order of events, reasons for the order, and maybe why each part is important. I can think of a few starting points, but I'm not sure where it's best to begin Model design and relationships (entities, how they relate, and their attributes) Think of user use-cases (or story-boards) and implement the minimum to get these done Create Model unit-tests then create the necessary migrations and AR models to get the tests to pass Hack out the most basic version of the simplest part of your application and go from there Start with a template for a rails app (like http://github.com/thoughtbot/suspenders) Do the boring gruntwork first (User auth, session management, ...) ...

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  • How to exclude results with get_object_or_404?

    - by googletorp
    In Django you can use the exclude to create SQL similar to not equal. An example could be. Model.objects.exclude(status='deleted') Now this works great and exclude is very flexible. Since I'm a bit lazy, I would like to get that functionality when using get_object_or_404, but I haven't found a way to do this, since you cannot use exclude on get_object_or_404. What I want is to do something like this: model = get_object_or_404(pk=id, status__exclude='deleted') But unfortunately this doesn't work as there isn't an exclude query filter or similar. The best I've come up with so far is doing something like this: object = get_object_or_404(pk=id) if object.status == 'deleted': return HttpResponseNotfound('text') Doing something like that, really defeats the point of using get_object_or_404, since it no longer is a handy one-liner. Alternatively I could do: object = get_object_or_404(pk=id, status__in=['list', 'of', 'items']) But that wouldn't be very maintainable, as I would need to keep the list up to date. I'm wondering if I'm missing some trick or feature in django to use get_object_or_404 to get the desired result?

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  • NameError when using act_as_ferret

    - by manish nautiyal
    Hi all I am getting this error when I am using acts_as_ferret :fields =[:competitor], :remote = true NameError in PartController#index uninitialized constant PartController::Competitor My Model class Competitor < ActiveRecord::Base validates_presence_of :fee_earner_id, :notes belongs_to :fee_earner belongs_to :country belongs_to :state belongs_to :user acts_as_ferret :fields =[:competitor], :remote = true end My controller class PartController < ApplicationController def index @proscribeds = Competitor.paginate(:all, :order = sort , :page = params[:page], :per_page = 70 ) end end Its working fine in localhost but when I deploy it in the server than I get this error. act_as_ferret is working good with other models. I don't know why this is not working with only Competitor model.

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  • How to control table width in code ignator?

    - by riad
    Dear Exparts, In codeIgnator frame work the below is my code working properly.But i cannot control the table width. So,when a long value come into the table then table going to extra large width.But i need to wrap the outcomes data.So,How i can fixed the table width? Pls see my code below.. ///controller code/// $config['base_url'] = base_url().'Search_Controller/songSearchPage/'; $config['total_rows'] = $this->db->count_all('tbl_rbt'); $config['per_page'] = '5'; $config['full_tag_open'] = '<p>'; $config['full_tag_close'] = '</p>'; $this->pagination->initialize($config); //load the model and get results $data[]=array(); $data['extraHeadContent'] = '<script type="text/javascript" src="' . base_url() . 'js/song_search.js"></script>'; $data['results'] = $this->search_model->getSongResult($config['per_page'],$this->uri->segment(3)); // load the HTML Table Class $this->table->set_heading('Song Name','Album Name','Artist Name'); // load the view $this->load->view('song_search_page',$data); /////view code///// <div class="song_element_output"> <?php echo $this->table->generate($results); ?> <?php echo $this->pagination->create_links(); ?> </div> Could anybody can help me to control the table??? Thanks Riad

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  • jquery multiple select x rails edit action

    - by VP
    Hi, i'm using the JQUERY multiselectable plugin. Because it's get one select box and transform it in two, where you can move one selected option to another select box. The problem is that i'm facing some problems with the edit action. When i load the form, the selected values (that are saved in my model) are not being populated in the "selected" select box. There is anybody with a good idea about how to "automatically" move the selected values in my database from the "available to be selected" to "selected" options? For now i'm doing something like <%= select "product", :option_ids, options_for_select(Option.all.map { |opt| [opt.description, opt.id]}), {},{:multiple=> true,:class=>'multiselect'} %> Here i can see already the problem. I could just use as options_for_select just all options - the options that are already choosed in my model. The problem is how to update the select box with this information?

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  • MVVM and division of amongst multiple developers

    - by nlawalker
    Can anyone speak to the ease of dividing work amongst multiple developers when designing and building a medium- to large-complexity Silverlight or WPF application? My team is finding it difficult to cleanly split work when you've got, for example, a number of controls that provide different visualizations of a Model/ViewModel that's fairly complex and has a lot of properties and methods for interacting with data. It seems like a very big portion of the work ends up being the design and build of the Model/ViewModel, and much less inside each of the controls, which are naturally what are easy to ration out to multiple people.

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  • What is the best way to maintain an entity's original properties when they are not included in MVC binding from edit page?

    - by kingdango
    I have an ASP.NET MVC view for editing a model object. The edit page includes most of the properties of my object but not all of them -- specifically it does not include CreatedOn and CreatedBy fields since those are set upon creation (in my service layer) and shouldn't change in the future. Unless I include these properties as hidden fields they will not be picked up during Binding and are unavailable when I save the modified object in my EF 4 DB Context. In actuality, upon save the original values would be overwritten by nulls (or some type-specific default). I don't want to drop these in as hidden fields because it is a waste of bytes and I don't want those values exposed to potential manipulation. Is there a "first class" way to handle this situation? Is it possible to specify a EF Model property is to be ignored unless explicitly set?

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  • Why should I use an N-Tier Approach When using an SqlDatasource is ALOT EASIER ?

    - by The_AlienCoder
    When it comes to web development I have always tried to work SMART not HARD. So for along time My Aproach to interacting with databases in my AspNet projects has been this : 1) Create my stored procedures 2) Drag an SQLDatasource control on my aspx page 3) Bind a DataList Control to my SQLDatasource 4) Insert, Update & Delete by using my Datalist or programmatically using built in SQLDatasource methods e.g MySqlDataSource.InsertParameters["author"].DefaultValue = TextBox1.Text; MySqlDataSource.Insert(); Recently however I got a relatively easy web project. So I decided to employ a 3-tier Model...But I got exhausted halfway and just didnt seem worth it ! It seemed like I was working too HARD for a project that could have been easily accomplished by a couple of SqlDataSource Controls. So Why Is the N-Tier Model better than my Approach? Has it anything to do with performance? What are the advantages of the ObjectDataSource control over the SqlDataSource Control?

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  • MVC Html Layout C# code formatting

    - by Andrew Florko
    I insert into asp.net mvc views C# logic that manages layout like the following: <% if (Model.People.Count > 0 ) { %> <% foreach (var person in Model.People) { %> ... <% }} else { %> <span class="error">Sorry, no people</span> <%} %> I try to minimize <% % code placing "{" symbol on the same line as it's condition (java-style). Html layout looks more clear to me after that. Do you apply C# formatting rules to <% % html injections "}" should be on a new line or manage layout in different way? Thank you in advance!

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  • validate uniqueness amongst multiple subclasses with Single Table Inheritance

    - by irkenInvader
    I have a Card model that has many Sets and a Set model that has many Cards through a Membership model: class Card < ActiveRecord::Base has_many :memberships has_many :sets, :through => :memberships end class Membership < ActiveRecord::Base belongs_to :card belongs_to :set validates_uniqueness_of :card_id, :scope => :set_id end class Set < ActiveRecord::Base has_many :memberships has_many :cards, :through => :memberships validates_presence_of :cards end I also have some sub-classes of the above using Single Table Inheritance: class FooCard < Card end class BarCard < Card end and class Expansion < Set end class GameSet < Set validates_size_of :cards, :is => 10 end All of the above is working as I intend. What I'm trying to figure out is how to validate that a Card can only belong to a single Expansion. I want the following to be invalid: some_cards = FooCard.all( :limit => 25 ) first_expansion = Expansion.new second_expansion = Expansion.new first_expansion.cards = some_cards second_expansion.cards = some_cards first_expansion.save # Valid second_expansion.save # **Should be invalid** However, GameSets should allow this behavior: other_cards = FooCard.all( :limit => 10 ) first_set = GameSet.new second_set = GameSet.new first_set.cards = other_cards # Valid second_set.cards = other_cards # Also valid I'm guessing that a validates_uniqueness_of call is needed somewhere, but I'm not sure where to put it. Any suggestions? UPDATE 1 I modified the Expansion class as sugested: class Expansion < Set validate :validates_uniqueness_of_cards def validates_uniqueness_of_cards membership = Membership.find( :first, :include => :set, :conditions => [ "card_id IN (?) AND sets.type = ?", self.cards.map(&:id), "Expansion" ] ) errors.add_to_base("a Card can only belong to a single Expansion") unless membership.nil? end end This works when creating initial expansions to validate that no current expansions contain the cards. However, this (falsely) invalidates future updates to the expansion with new cards. In other words: old_exp = Expansion.find(1) old_exp.card_ids # returns [1,2,3,4,5] new_exp = Expansion.new new_exp.card_ids = [6,7,8,9,10] new_exp.save # returns true new_exp.card_ids << [11,12] # no other Expansion contains these cards new_exp.valid? # returns false ... SHOULD be true

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  • Can I access views when drawn in the drawRect method?

    - by GianPac
    When creating the content view of a tableViewCell, I used the drawInRect:withFont, drawAtPoint... and others, inside drawRect: since all I needed was to lay some text. Turns out, part of the text drawn need to be clickable URLs. So I decided to create a UIWebView and insert it into my drawRect. Everything seems to be laid out fine, the problem is that interaction with the UIWebView is not happening. I tried enabling the interaction, did not work. I want to know, since with drawRect: I am drawing to the current graphics context, there is anything I can do to have my subviews interact with the user? here is some of my code I use inside the UITableViewCell class. -(void) drawRect:(CGRect)rect{ NSString *comment = @"something"; [comment drawAtPoint:point forWidth:195 withFont:someFont lineBreakMode:UILineBreakModeMiddleTruncation]; NSString *anotherCommentWithURL = @"this comment has a URL http://twtr.us"; UIWebView *webView = [[UIWebView alloc] initWithFrame:someFrame]; webView.delegate = self; webView.text = anotherCommentWithURL; [self addSubView:webView]; [webView release]; } As I said, the view draws fine, but there is no interaction with the webView from the outside. the URL gets embedded into HTML and should be clickable. It is not. I got it working on another view, but on that one I lay the views. Any ideas?

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  • Database Design for One to One relationships

    - by Greelmo
    I'm trying to finalize my design of the data model for my project, and am having difficulty figuring out which way to go with it. I have a table of users, and an undetermined number of attributes that apply to that user. The attributes are in almost every case optional, so null values are allowed. Each of these attributes are one to one for the user. Should I put them on the same table, and keep adding columns when attributes are added (making the user table quite wide), or should I put each attribute on a separate table with a foreign key to the user table. I have decided against using the EAV model. Thanks!

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  • testing the controller in asp.net mvc

    - by csetzkorn
    Hi, I would like to test the validation of submitted DTO. This is the bare bone of a controller create action: [AcceptVerbs(HttpVerbs.Post)] public RedirectToRouteResult Create(SomeDTO SomeDTO) { SomeObject SomeObject = null; try { SomeObject = this.RepositoryService.getSomeObjectRepository().Create(SomeDTO, this.RepositoryService); } catch (BrokenRulesException ex) { ex.AddModelStateErrors(ModelState, "Model"); } catch (Exception e) { ModelState.AddModelError("Exception", e.Message); } TempData["ViewData"] = ViewData; TempData["SomeDTO "] = SomeDTO; return ModelState.IsValid ? RedirectToAction("SomeObjectDetail", new { Id = SomeObject.Id }) : RedirectToAction("Form"); } The mechanics , although not relevant, is as follows: I have a strongly typed view = form which submits a dto to this action which either returns the form or the details page of the created object. I would like to unit test whether the Model contains certain key/errorMessage combinations given some invalid dto. Did someone do similar stuff? Any pointers would be very much appreciated. Thanks. Best wishes, Christian

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  • Should I use parameters in template scripting to control the output, or a separate specialized template?

    - by asawyer
    Would it be considered best practice to use a single template that changes it's output based on script values, or have multiple templates, and use the view to pick the correct one instead? For example, in this underscope template: <script type="text/template" id="SkillsetTemplate"> <div class='RegularMode <%= (skillset.get('InEditMode')===false)?'show':'hide' %>'> </div> <div class='EditMode <%= (skillset.get('InEditMode')===true)?'show':'hide' %>'> </div> </script> I use a backbone model to bind against, and use the InEditMode attribute to pick which content to render. Should I instead have a normal mode, and an edit mode template, and use the attribute on the model to pick the template ? For background purposes, I am using backbone.js with underscore templates and an MVC3 backend.

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  • How to enable/create elements on the fly

    - by Simon S
    Hi all I am using a combination of PHP, jQuery and Spry to serve a series of listboxes in which a user will select first the type of vehicle, then the make, then the model and finally the specific model. All my listboxes (SELECT) are working fine, and they update properly using the Spry elements. Each listbox is populated from a different Spry XML Dataset, and this is my problem. If I present all four listboxes to the user, the script has to go and fetch all four lots of XML to populate all four listboxes, taking several seconds. What I want to do is to create/enable the listboxes in order, so at the user selects from the first listbox, the second is created/enabled, when they select from the second, the third is created/enabled... and so on. Setting the disabled attribute is no good because the script has already fetched the XML before this is processed. Any ideas?? Si

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  • Dynamically changing validations in Rails

    - by user94154
    I have a model with a validation. At runtime, I'd like to change a value of the validation. For example: in the model bid.rb: class Bid ActiveRecord::Base @foo = Foo.find(1) validates_inclusion_of :amt, :in => [email protected], :message => "must be between 1 and #{@foo.bar}" end and in the application_controller (pseudocode): if today == 'wednesday' Foo.update(1, :bar => 10) else Foo.update(1, :bar => 5) end However, this setup isn't working. The "foo" attribute never updates. It seems that the validation code is set only when the dev server starts and then doesn't change.

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  • How to use Messageboxes in MVVM?

    - by BigTiger
    It seems that the XAML in MVVM pattern has difficulty to pop-up a Messageboxes. My client insists that the validation labels and colors are not good for them. They still want a messagebox. How can do it? I know I can pop-up messageboxes in the view-model, but it violates the whole purpose for the view-model. I can also raise a error, and pop-up a messagebox in some exception handlers, but the messagebox is not an exception. It is part of the normal program flow. Is there a good way to do it in XAML? My client likes messageboxes. She does not care about the MVVM pattern, she never had any quality problem before using MVVM and unit test. But now, she can not even get her messageboxes, so she is not very happy. Your help is definitely appreciated ... I need to make her happy.

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  • Dynamically creating subviews of similar type

    - by Akki
    My code for above view is: -(void)viewWillAppear:(BOOL)animated{ float yh = 0; while (yh<200) { //UIView CGRect myFrame = CGRectMake(0, yh, 320, 30); UIView *myFirstView = [[UIView alloc] initWithFrame:myFrame]; myFirstView.backgroundColor = [UIColor orangeColor]; //IUILabel in UIView CGRect mylblFrame = CGRectMake(5, yh, 60, 15); UILabel *lblsize = [[UILabel alloc] initWithFrame:mylblFrame]; lblsize.text = @"Hello"; [myFirstView addSubview:lblsize]; CGRect mylbl_hi = CGRectMake(80, yh, 60, 15); UILabel *lbl_hi = [[UILabel alloc] initWithFrame:mylbl_hi]; lbl_hi.text = @"Hii"; [myFirstView addSubview:lbl_hi]; [self.view addSubview:myFirstView]; [lbl_hi release]; [lblsize release]; [myFirstView release]; yh=yh+40; } [super viewWillAppear:YES]; } I can't understand reason of it being like this...i wanted labels to be attached with my subviews of orange color...this may be odd day for me to understand what's wrong with my code...if any of you can tell me where i ma doing wrong would be great to me. This is my first time creating view programmatically..so please excuse me if all this is silly question

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  • Getting batch_action functionality in Symfony 1.0

    - by Alex Ciminian
    I'm currently working on a web app written in Symfony. I'm supposed to add an "export to CSV" feature in the backend/administration part of the app for some modules. In the list view, there should be an "Export" button which should provide the user with a csv file of the elements that are displayed (considering filtering criteria). I've created a method in the actions class of the module that takes a comma separated list of ids and generates the CSV, but I'm not really sure how to add the link to it in the view. The problem is that the view doesn't exist anywhere, it's generated on the fly from the data in the generator.yml configuration file. I've posted the relevant part of the file below. I'm new to Symfony, so any help would be appreciated :). Thanks, Alex Update list: display: [id, =name, indemn, _status, _participants, _approved_, created_at] title: Lista actiuni object_actions: _edit: ~ _delete: ~ actions: _create: ~ export_csv: name: Export to CSV action: CSVExport params: id=csvActionSubmit filters: [name, county_id, _status_filter, activity_id] fields: id: name: Nr. crt. ... Thanks to your advice, I've managed to add a button that is linked to my action. The problem is that I also need to send some parameters to the action, because I may not want all the elements - filters may have been used. Unfortunately, the project is using Symfony 1.0, which doesn't support batch_actions. Currently, I'm working around this with Javascript (I parse the DOM to get the numeric ids (from the display table) and then build the link for the button. I really think there could be a better way for this.

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