Search Results

Search found 90165 results on 3607 pages for 'exit code'.

Page 469/3607 | < Previous Page | 465 466 467 468 469 470 471 472 473 474 475 476  | Next Page >

  • Unable to execute stored Procedure using Java and JDBC on SQL server

    - by jwmajors81
    I have been trying to execute a MS SQL Server stored procedure via JDBC today and have been unsuccessful thus far. The stored procedure has 1 input and 1 output parameter. With every combination I use when setting up the stored procedure call in code I get an error stating that the stored procedure couldn't be found. I have provided the stored procedure I'm executing below (NOTE: this is vendor code, so I cannot change it). set ANSI_NULLS ON set QUOTED_IDENTIFIER ON GO ALTER PROC [dbo].[spWCoTaskIdGen] @OutIdentifier int OUTPUT AS BEGIN DECLARE @HoldPolicyId int DECLARE @PolicyId char(14) IF NOT EXISTS ( SELECT * FROM UniqueIdentifierGen (UPDLOCK) ) INSERT INTO UniqueIdentifierGen VALUES (0) UPDATE UniqueIdentifierGen SET CurIdentifier = CurIdentifier + 1 SELECT @OutIdentifier = (SELECT CurIdentifier FROM UniqueIdentifierGen) END The code looks like: CallableStatement statement = connection .prepareCall("{call dbo.spWCoTaskIdGen(?)}"); statement.setInt(1, 0); ResultSet result = statement.executeQuery(); I get the following error: SEVERE: Could not find stored procedure 'dbo.spWCoTaskIdGen'. I have also tried CallableStatement statement = connection .prepareCall("{? = call dbo.spWCoTaskIdGen(?)}"); statement.registerOutParameter(1, java.sql.Types.INTEGER); statement.registerOutParameter(2, java.sql.Types.INTEGER); statement.executeQuery(); The above results in: SEVERE: Could not find stored procedure 'dbo.spWCoTaskIdGen'. I have also tried: CallableStatement statement = connection .prepareCall("{? = call spWCoTaskIdGen(?)}"); statement.registerOutParameter(1, java.sql.Types.INTEGER); statement.registerOutParameter(2, java.sql.Types.INTEGER); statement.executeQuery(); The code above resulted in the following error: Could not find stored procedure 'spWCoTaskIdGen'. Finally, I should also point out the following: I have used the MS SQL Server Management Studio tool and have been able to successfully run the stored procedure. The sql generated to execute the stored procedure is provided below: GO DECLARE @return_value int, @OutIdentifier int EXEC @return_value = [dbo].[spWCoTaskIdGen] @OutIdentifier = @OutIdentifier OUTPUT SELECT @OutIdentifier as N'@OutIdentifier ' SELECT 'Return Value' = @return_value GO The code being executed runs with the same user id that was used in point #1 above. In the code that creates the Connection object I log which database I'm connecting to and the code is connecting to the correct database. Any ideas? Thank you very much in advance.

    Read the article

  • Make only one row show after search. flexgrid vb6

    - by Andeeh
    So i have flexgrid in my vb6 project I'm working on. It has names on each row, and I have a drop down so the user can select what name they want to see more info for, here is what I have. Dim target_name As String Dim r As Integer ' Get the name. target_name = Combo1 If Len(target_name) = 0 Then Exit Sub ' Search for the name, skipping the column heading row. target_name = LCase$(target_name) For r = 1 To MSFlexGrid1.Rows - 1 If LCase$(MSFlexGrid1.TextMatrix(r, 0)) = _ target_name Then ' We found the target. Select this row. MSFlexGrid1.Row = r MSFlexGrid1.RowSel = r MSFlexGrid1.Col = 0 MSFlexGrid1.ColSel = MSFlexGrid1.Cols - 1 ' Make the row visible. MSFlexGrid1.TopRow = r Exit Sub End If Next r That works well, but it shows everything below that name too, I would like it to single out only the name selected. Any help would be great.

    Read the article

  • How can I redirect the output of Perl's system() to a filehandle?

    - by syker
    With the open command in Perl, you can use a filehandle. However I have trouble getting back the exit code with the open command in Perl. With the system command in Perl, I can get back the exit code of the program I'm running. However I want to just redirect the STDOUT to some filehandle (no stderr). My stdout is going to be a line-by-line output of key-value pairs that I want to insert into a mao in perl. That is why I want to redirect only my stdout from my Java program in perl. Is that possible? Note: If I get errors, the errors get printed to stderr. One possibility is to check if anything gets printed to stderr so that I can quite the Perl script.

    Read the article

  • Unable to execute stored Procedure using Java and JDBC

    - by jwmajors81
    I have been trying to execute a MS SQL Server stored procedure via JDBC today and have been unsuccessful thus far. The stored procedure has 1 input and 1 output parameter. With every combination I use when setting up the stored procedure call in code I get an error stating that the stored procedure couldn't be found. I have provided the stored procedure I'm executing below (NOTE: this is vendor code, so I cannot change it). set ANSI_NULLS ON set QUOTED_IDENTIFIER ON GO ALTER PROC [dbo].[spWCoTaskIdGen] @OutIdentifier int OUTPUT AS BEGIN DECLARE @HoldPolicyId int DECLARE @PolicyId char(14) IF NOT EXISTS ( SELECT * FROM UniqueIdentifierGen (UPDLOCK) ) INSERT INTO UniqueIdentifierGen VALUES (0) UPDATE UniqueIdentifierGen SET CurIdentifier = CurIdentifier + 1 SELECT @OutIdentifier = (SELECT CurIdentifier FROM UniqueIdentifierGen) END The code looks like: CallableStatement statement = connection .prepareCall("{call dbo.spWCoTaskIdGen(?)}"); statement.setInt(1, 0); ResultSet result = statement.executeQuery(); I get the following error: SEVERE: Could not find stored procedure 'dbo.spWCoTaskIdGen'. I have also tried CallableStatement statement = connection .prepareCall("{? = call dbo.spWCoTaskIdGen(?)}"); statement.registerOutParameter(1, java.sql.Types.INTEGER); statement.registerOutParameter(2, java.sql.Types.INTEGER); statement.executeQuery(); The above results in: SEVERE: Could not find stored procedure 'dbo.spWCoTaskIdGen'. I have also tried: CallableStatement statement = connection .prepareCall("{? = call spWCoTaskIdGen(?)}"); statement.registerOutParameter(1, java.sql.Types.INTEGER); statement.registerOutParameter(2, java.sql.Types.INTEGER); statement.executeQuery(); The code above resulted in the following error: Could not find stored procedure 'spWCoTaskIdGen'. Finally, I should also point out the following: I have used the MS SQL Server Management Studio tool and have been able to successfully run the stored procedure. The sql generated to execute the stored procedure is provided below: GO DECLARE @return_value int, @OutIdentifier int EXEC @return_value = [dbo].[spWCoTaskIdGen] @OutIdentifier = @OutIdentifier OUTPUT SELECT @OutIdentifier as N'@OutIdentifier ' SELECT 'Return Value' = @return_value GO The code being executed runs with the same user id that was used in point #1 above. In the code that creates the Connection object I log which database I'm connecting to and the code is connecting to the correct database. Any ideas? Thank you very much in advance.

    Read the article

  • Error while creating a table style in excel

    - by Rashmi Pandit
    Hi, I am using the following function to create a TableStyle: Public Function CreateTableStyle() ActiveWorkbook.Unprotect Dim objTS As TableStyle On Error Resume Next Set objTS = ActiveWorkbook.TableStyles("MyTableStyle") On Error GoTo err_CreateTableStyle If Not objTS Is Nothing Then Exit Function End If Set objTS = ActiveWorkbook.TableStyles.Add("MyTableStyle") With ActiveWorkbook.TableStyles("MyTableStyle") .ShowAsAvailablePivotTableStyle = True .ShowAsAvailableTableStyle = False End With With ActiveWorkbook.TableStyles("MyTableStyle").TableStyleElements( _ xlHeaderRow).Font .FontStyle = "Bold" .TintAndShade = 0 .ThemeColor = xlThemeColorDark1 End With With ActiveWorkbook.TableStyles("MyTableStyle").TableStyleElements( _ xlHeaderRow).Interior .ThemeColor = xlThemeColorLight2 .TintAndShade = -0.249946592608417 End With With ActiveWorkbook.TableStyles("MyTableStyle").TableStyleElements( _ xlTotalRow).Font .FontStyle = "Bold" .TintAndShade = 0 .ThemeColor = xlThemeColorDark1 End With With ActiveWorkbook.TableStyles("MyTableStyle").TableStyleElements( _ xlTotalRow).Interior .ThemeColor = xlThemeColorLight2 .TintAndShade = -0.249946592608417 End With ActiveWorkbook.TableStyles("MyTableStyle").TableStyleElements( _ xlSubtotalRow1).Font.FontStyle = "Bold" With ActiveWorkbook.TableStyles("MyTableStyle").TableStyleElements( _ xlSubtotalRow1).Interior .Color = 16764828 .TintAndShade = 0 End With ActiveWorkbook.TableStyles("MyTableStyle").TableStyleElements( _ xlSubtotalRow2).Font.FontStyle = "Bold" With ActiveWorkbook.TableStyles("MyTableStyle").TableStyleElements( _ xlSubtotalRow2).Interior .Color = 16777164 .TintAndShade = 0 End With ActiveWorkbook.Protect Exit Function err_CreateTableStyle: Call Common.ErrRaise(Erl, "Common", "CreateTableStyle", "CreateTableStyle") End Function At the line below: With ActiveWorkbook.TableStyles("MyTableStyle").TableStyleElements( _ xlHeaderRow).Font .FontStyle = "Bold" I am getting an error: Run-time error '1004' Unable to set the FontStyle property of the Font class. Can someone please identify the issue? I am not able to figure why it is not letting me set the property.

    Read the article

  • PERL script error.

    - by FRESHTER
    !/usr/bin/perl use WWW::Mechanize; use Compress::Zlib; my $mech = WWW::Mechanize-new(); my $username = "9703460016"; #fill in username here my $keyword = "1raja1"; #fill in password here my $mobile = $ARGV[0]; my $text = $ARGV[1]; $deb = 1; print length($text)."\n" if($deb); $text = $text."\n\n\n\n\n" if(length($text) < 135); $mech-get("http://wwwl.way2sms.com/content/index.html"); unless($mech-success()) { exit; } $dest = $mech-response-content; print "Fetching...\n" if($deb); if($mech-response-header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech-update_html($dest); } $dest =~ s/ $mech-update_html($dest); $mech-form_with_fields(("username","password")); $mech-field("username",$username); $mech-field("password",$keyword); print "Loggin...\n" if($deb); $mech-submit_form(); $dest= $mech-response-content; if($mech-response-header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech-update_html($dest); } $mech-get("http://wwwl.way2sms.com//jsp/InstantSMS.jsp?val=0"); $dest= $mech-response-content; if($mech-response-header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech-update_html($dest); } print "Sending ... \n" if($deb); $mech-form_with_fields(("MobNo","textArea")); $mech-field("MobNo",$mobile); $mech-field("textArea",$text); $mech-submit_form(); if($mech-success()) { print "Done \n" if($deb); } else { print "Failed \n" if($deb); exit; } $dest = $mech-response-content; if($mech-response-header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); #print $dest if($deb); } if($dest =~ m/successfully/sig) { print "Message sent successfully" if($deb); } exit; *In this code I face with an error saying There is no form with the requested fields at ./sms.pl line 65 Can't call method "value" on an undefined value at /usr/share/perl5/vendor_perl/WWW/Mechanize.pm line* 1348. Could any 1 guide me please

    Read the article

  • Illegal instruction in Assembly

    - by Natasha
    I really do not understand why this simple code works fine in the first attempt but when putting it in a procedure an error shows: NTVDM CPU has encountered an illegal instruction CS:db22 IP:4de4 OP:f0 ff ff ff ff The first code segment works just fine: .model small .stack 100h .code start: mov ax,@data mov ds,ax mov es,ax MOV AH,02H ;sets cursor up MOV BH,00H MOV DH,02 MOV DL,00 INT 10H EXIT: MOV AH,4CH INT 21H END However This generates an error: .model small .stack 100h .code start: mov ax,@data mov ds,ax mov es,ax call set_cursor PROC set_cursor near MOV AH,02H ;sets cursor up MOV BH,00H MOV DH,02 MOV DL,00 INT 10H RET set_cursor ENDP EXIT: MOV AH,4CH INT 21H END Note: Nothing is wrong with windows config. I have tried many sample codes that work fine Thanks

    Read the article

  • Handling Java stdout and stderr in Perl

    - by syker
    I am trying to run a Java program from my Perl script. I would like to avoid using System.exit(1) and System.exit(-1) commands in Java. I am however printing to STDOUT and STDERR from Java. In my Perl script, I am reading from Java's stdout and using that line by line output. How do I print stderr and fail if I ever see stderr? This is what I have so far: my $java_command = ...; open(DATA, ">$java_command"); while (<DATA>) { chomp($_); .... .... }

    Read the article

  • PyQt4: Why does Python crash on close when using QTreeWidgetItem?

    - by Rini
    I'm using Python 3.1.1 and PyQt4 (not sure how to get that version number?). Python is crashing whenever I exit my application. I've seen this before as a garbage collection issue, but this time I'm not sure how to correct the problem. This code crashes: import sys from PyQt4 import QtGui class MyWindow(QtGui.QMainWindow): def __init__(self, parent=None): QtGui.QMainWindow.__init__(self, parent) self.tree = QtGui.QTreeWidget(self) self.setCentralWidget(self.tree) QtGui.QTreeWidgetItem(self.tree) # This line is the problem self.show() app = QtGui.QApplication(sys.argv) mw = MyWindow() sys.exit(app.exec_()) If I remove the commented line, the code exits without a problem. If I remove the 'self.tree' parent from the initialization, the code exits without a problem. If I try to use self.tree.addTopLevelItem, the code crashes again. What could be the problem?

    Read the article

  • How can I interrupt a ServerSocket accept() method?

    - by lukeo05
    Hi, In my main thread I have a while(listening) loop which calls accept() on my ServerSocket object, then starts a new client thread and adds it to a Collection when a new client is accepted. I also have an Admin thread which I want to use to issue commands, like 'exit', which will cause all the client threads to be shut down, shut itself down, and shut down the main thread, by turning listening to false. However, the accept() call in the while(listening) loop blocks, and there doesn't seem to be any way to interrupt it, so the while condition cannot be checked again and the program cannot exit! Is there a better way to do this? Or some way to interrupt the blocking method? Thanks!

    Read the article

  • Using Unix Process Controll Methods in Ruby

    - by John F. Miller
    Ryan Tomayko touched off quite a fire storm with this post about using Unix process control commands. We should be doing more of this. A lot more of this. I'm talking about fork(2), execve(2), pipe(2), socketpair(2), select(2), kill(2), sigaction(2), and so on and so forth. These are our friends. They want so badly just to help us. I have a bit of code (a delayed_job clone for DataMapper that I think would fit right in with this, but I'm not clear on how to take advantage of the listed commands. Any Ideas on how to improve this code? def start say "*** Starting job worker #{@name}" t = Thread.new do loop do delay = Update.work_off(self) break if $exit sleep delay break if $exit end clear_locks end trap('TERM') { terminate_with t } trap('INT') { terminate_with t } trap('USR1') do say "Wakeup Signal Caught" t.run end end

    Read the article

  • python optparse, how to include additional info in usage output?

    - by CarpeNoctem
    Using python's optparse module I would like to add extra example lines below the regular usage output. My current help_print() output looks like this: usage: check_dell.py [options] options: -h, --help show this help message and exit -s, --storage checks virtual and physical disks -c, --chassis checks specified chassis components I would like it to include usage examples for the less *nix literate users at my work. Something like this: usage: check_dell.py [options] options: -h, --help show this help message and exit -s, --storage checks virtual and physical disks -c, --chassis checks specified chassis components Examples: check_dell -c all check_dell -c fans memory voltage check_dell -s How would I accomplish this? What optparse options allow for such? Current code: import optparse def main(): parser = optparse.OptionParser() parser.add_option('-s', '--storage', action='store_true', default=False, help='checks virtual and physical disks') parser.add_option('-c', '--chassis', action='store_true', default=False, help='checks specified chassis components') (opts, args) = parser.parse_args()

    Read the article

  • Unix Piping using Fork and Dup

    - by Jacob
    Lets say within my program I want to execute two child processes, one to to execute a "ls -al" command and then pipe that into "wc" command and display the output on the terminal. How can I do this using pipe file descriptors so far the code I have written: An example would be greatly helpful int main(int argc, char *argv[]) { int pipefd[2] pipe(pipefd2); if ((fork()) == 0) { dup2(pipefd2[1],STDOUT_FILENO); close(pipefd2[0]); close(pipefd2[1]); execl("ls", "ls","-al", NULL); exit(EXIT_FAILURE); } if ((fork()) == 0){ dup2(pipefd2[0],STDIN_FILENO); close(pipefd2[0]); close(pipefd2[1]); execl("/usr/bin/wc","wc",NULL); exit(EXIT_FAILURE); } close(pipefd[0]); close(pipefd[1]); close(pipefd2[0]); close(pipefd2[1]); }

    Read the article

  • Can output from OutputDebugString be viewed in VisualStudio's output window

    - by wageoghe
    I am using C# and VS2010. When I use OutputDebugString to write debug information, should it show up in the output window? I can see the output from OutputDebugString in DebugView, but I thought I would see it in Visual Studio's Output window. I have looked under Tools-Options-Debugging-General and the output is NOT being redirected to the Immediate window. I have also looked under Tools-Options-Debugging-Output Window and all General Output Settings are set to "On". Finally, I have used the drop-down list in the Output window to specify that Debug messages should appear. If I change Tools-Options-Debugging-General to redirect the output to the Immediate window, the OutputDebugString messages do not appear in the immediate window. Here is my entire test program: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Runtime.InteropServices; using System.Diagnostics; namespace OutputDebugString { class Program { [DllImport("kernel32.dll", CharSet = CharSet.Auto)] public static extern void OutputDebugString(string message); static void Main(string[] args) { Console.WriteLine("Main - Enter - Console.WriteLine"); Debug.WriteLine("Main - Enter - Debug.WriteLine"); OutputDebugString("Main - Enter - OutputDebugString"); OutputDebugString("Main - Exit - OutputDebugString"); Debug.WriteLine("Main - Exit - Debug.WriteLine"); Console.WriteLine("Main - Exit - Console.WriteLine"); } } } If I run within the debugger, the Debug.WriteLine output does show up in the output window, but the OutputDebugString output does not. If I run from a console window, both Debug.WriteLine and OutputDebugString show up in DebugView. Why doesn't the OutputDebugString output ever show up in the output window? Ultimately, my intent is not to write a lot of debug output with OutputDebugString, rather I will use System.Diagnostics or NLog or something similar. I am just trying to find out, if I configure a logging platform to write to OutputDebugString, will the output be visible from within the debugger. Edit: I went back to my original program (not the simple test above) which uses TraceSources and TraceListeners configured via the app.config file. If I configure the trace sources to write to the System.Diagnostics.DefaultTraceListener (which is documented as writing to OutputDebugString), then the trace source output DOES go to the debug window. However, lines that write directly with OutputDebugString (such as in my simple example) DO NOT go to the debug window. Also, if I use a different TraceListener that writes to OutputDebugString (I got one from Ukadc.Diagnostics at codeplex), that output DOES NOT go to the debug window. Note that I have seen these questions but they did not provide a working solution: here and here

    Read the article

  • What is the full "for" loop syntax in C (and others in case they are compatible) ?

    - by fmsf
    I have seen some very weird for loops when reading other people's code. I have been trying to search for a full syntax explanation for the for loop in C but it is very hard because the word "for" appears in unrelated sentences making the search almost impossible to Google effectively. This question came to my mind after reading this thread which made me curious again. The for here: for(p=0;p+=(a&1)*b,a!=1;a>>=1,b<<=1); In the middle condition there is a comma separating the two pieces of code, what does this comma do? The comma on the right side I understand as it makes both a>>=1 and b<<=1. But within a loop exit condition, what happens? Does it exit when p==0, when a==1 or when both happen? It would be great if anyone could help me understand this and maybe point me in the direction of a full for loop syntax description.

    Read the article

  • fwrite to txt-file

    - by timkl
    I'm currently trying to write to a txt-file with PHP, I've found this small script: <?php $filename = 'testFile.txt'; $somecontent = "Add this to the file\n"; if (is_writable($filename)) { if (!$handle = fopen($filename, 'a')) { echo "Cannot open file ($filename)"; exit; } if (fwrite($handle, $somecontent) === FALSE) { echo "Cannot write to file ($filename)"; exit; } echo "Success, wrote ($somecontent) to file ($filename)"; fclose($handle); } else { echo "The file $filename is not writable"; } ?> I get a success-message, but nothing is written to the file. Even if I delete the txt-file I still get the success-message Does anybody know how to troubleshoot a situation like this?

    Read the article

  • realloc - converting int to char

    - by Mike
    I'm converting an array of integers into a char by iterating through the whole array, and then I'm adding the resulting string to ncurses's method new_item. For some reason I'm doing something wrong the way I reallocate memory, thus I get the the first column as: -4 Choice 1 0 Choice 1 4 Choice 2 1 Choice 1 4 Choice 3 - Instead of - 2 Choice 1 4 Choice 4 3 Choice 1 4 Exit 4 Choice 1 - #include <stdio.h> #include <stdlib.h> #include <curses.h> #include <menu.h> #define ARRAY_SIZE(a) (sizeof(a) / sizeof(a[0])) #define CTRLD 4 char *choices[] = { "Choice 1", "Choice 2", "Choice 3", "Choice 4", "Exit", }; int table[5]={0,1,2,3,4}; int main() { ITEM **my_items; int c; MENU *my_menu; int n_choices, i; ITEM *cur_item; initscr(); cbreak(); noecho(); keypad(stdscr, TRUE); n_choices = ARRAY_SIZE(choices); my_items = (ITEM **)calloc(n_choices + 1, sizeof(ITEM *)); // right here char *convert = NULL; for(i = 0; i < n_choices; ++i){ convert = (char *) realloc (convert, sizeof(char) * 4); sprintf(convert, "%i", table[i]); my_items[i] = new_item(convert, choices[i]); } my_items[n_choices] = (ITEM *)NULL; my_menu = new_menu((ITEM **)my_items); mvprintw(LINES - 2, 0, "F1 to Exit"); post_menu(my_menu); refresh(); while((c = getch()) != KEY_F(1)) { switch(c) { case KEY_DOWN: menu_driver(my_menu, REQ_DOWN_ITEM); break; case KEY_UP: menu_driver(my_menu, REQ_UP_ITEM); break; } } free(convert); unpost_menu(my_menu); free_item(my_items[0]); free_item(my_items[1]); free_item(my_items[2]); free_item(my_items[3]); free_item(my_items[4]); free_menu(my_menu); endwin(); }

    Read the article

  • Why Won't My ASP.NET Hyperlink Work in IE?

    - by Giffyguy
    I'm making a very simple ad button system using ASP.NET 2.0 The advertisment is a 150x150px square that is displayed on "the r house." (Scroll down a little and you'll see the bright green "Angry Octopus" on the right side of the screen.) Now, I am not the administrator of "the r house." Instead, I am the administrator of angryoctopus.net Therefore, I don't have the ability to change the ad display code on a whim. So I gave "the r house" this snippet of code to display our ad nicely, while still allowing me to customize the back-end code on my end: <iframe src="http://www.angryoctopus.net/Content/Ad/150x150.aspx" frameborder="0" width="150" height="150" scrolling="no" style="padding: 0; margin: 0;"></iframe> You'll find this snippet in the page source to "the r house." On my side, the code looks like this: <asp:HyperLink runat="server" NavigateUrl="http://www.angryoctopus.net/" Target="_top"> <asp:Panel ID="pnlMain" runat="server" BackColor="#D1E231" style="padding: 0; margin: 0" Width="150" Height="150"> <asp:Image runat="server" ImageUrl="http://www.angryoctopus.net/Content/Ad/150x150.png" BorderStyle="None" style="padding: 0; margin: 0" /> </asp:Panel> </asp:HyperLink> ... and there's some insignificant back-end C# code for hit-counting. This looks all well and good from the code standpoint, as far as I can tell. Everything works in Firefox and Chrome. Also, everything appears to work in IE8 in all of my tests. I haven't tested IE7. But when you view "the r house" in IE(8) the hyperlink doesn't do anything, and the cursor doesn't indicate that the hyperlink is even there. Although you can see the target URL in the status bar. I've considered the fact that "the r house" uses XHTML 1.0 Strict could be causing problems, but that would probably effect Firefox and Chrome right? (My aspx pages use XHTML 1.0 Transitional) My only other theory is that some random CSS class could be applying a weird attribute to my iframe, but again I would expect that would effect Firefox and Chrome. Is this a security issue with IE? Does anyone know what part of the r house's website could be blocking the hyperlink in IE? And how can I get around this without having to hard code anything on the r house's website? Is there an alternative to iframe that would do the same job without requiring complicated scripting?

    Read the article

  • Is it a oop good design ?

    - by remi bourgarel
    Hi all, I'd like to know what you think about this part of our program is realized : We have in our database a list of campsite. Partners call us to get all the campsites near a GPS location or all the campsites which provide a bar (we call it a service). So how I realized it ? Here is our database : Campsite - ID - NAME - GPS_latitude - GPS_longitude CampsiteServices -Campsite_ID -Services_ID So my code (c# but it's not relevant, let say it's an OO language) looks like this public class SqlCodeCampsiteFilter{ public string SqlCode; public Dictionary<string, object> Parameters; } interface ISQLCampsiteFilter{ SqlCodeEngineCore CreateSQLCode(); } public class GpsLocationFilter : ISQLCampsiteFilter{ public float? GpsLatitude; public float? GpsLongitude; public SqlCodeEngineCore CreateSQLCode() { --return an sql code to filter on the gps location like dbo.getDistance(@gpsLat,@gpsLong,campsite.GPS_latitude,campsite.GPS_longitude) with the parameters } } public class ServiceFilter : : ISQLCampsiteFilter{ public int[] RequiredServicesID; public SqlCodeEngineCore CreateSQLCode() { --return an sql code to filter on the services "where ID IN (select CampsiteServices.Service_ID FROm CampsiteServices WHERE Service_ID in ...) } } So in my webservice code : List<ISQLFilterEngineCore> filters = new List<ISQLFilterEngineCore>(); if(gps_latitude.hasvalue && gps_longitude.hasvalue){ filters.Add (new GpsLocationFilter (gps_latitude.value,gps_longitude.value)); } if(required_services_id != null){ filters.Add (new ServiceFilter (required_services_id )); } string sql = "SELECT ID,NAME FROM campsite where 1=1" foreach(ISQLFilterEngineCore aFilter in filters){ SqlCodeCampsiteFilter code = aFilter.CreateSQLCode(); sql += code.SqlCode; mySqlCommand.AddParameters(code.Parameters);//add all the parameters to the sql command } return mySqlCommand.GetResults(); 1/ I don't use ORM for the simple reason that the system exists since 10 years and the only dev who is here since the beginning is starting to learn about difference between public and private. 2/ I don't like SP because : we can do override, and t-sql is not so funny to use :) So what do you think ? Is it clear ? Do you have any pattern that I should have a look to ? If something is not clear please ask

    Read the article

  • How do I test if a variable is a number in bash?

    - by Flávio Amieiro
    I just can't figure out how do I make sure an argument passed to my script is a number or not. All I want to do is something like this: test *isnumber* $1 && VAR=$1 || echo "need a number" Any help? UPDATE: I managed (whit Charles' help) to do it, but I'm not yet sure it's the best way to do that (even though it worked on my tests). This is how it ended up: [[ $1 =~ "^[0-9]+$" ]] && echo "numero" && exit 0 || echo "nao numero" && exit 1

    Read the article

  • pthread and recursively calling execvp in C

    - by eduke
    To begin I'm sorry for my english :) I looking for a way to create a thread each time my program finds a directory, in order to call the program itself but with a new argv[2] argument (which is the current dir). I did it successfully with fork() but with pthread I've some difficulties. I don't know if I can do something like that : #include <unistd.h> #include <stdlib.h> #include <stdio.h> #include <string.h> #include <sys/types.h> #include <sys/stat.h> #include <sys/wait.h> #include <dirent.h> int main(int argc, char **argv) { pthread_t threadID[10] = {0}; DIR * dir; struct dirent * entry; struct stat status; pthread_attr_t attr; pthread_attr_init(&attr); int i = 0; char *res; char *tmp; char *file; if(argc != 3) { printf("Usage : %s <file> <dir>\n", argv[0]); exit(EXIT_FAILURE); } if(stat(argv[2],&status) == 0) { dir = opendir(argv[2]); file = argv[1]; } else exit(EXIT_FAILURE); while ((entry = readdir(dir))) { if (strcmp(entry->d_name, ".") && strcmp(entry->d_name, "..")) { tmp = malloc(strlen(argv[2]) + strlen(entry->d_name) + 2); strcpy(tmp, argv[2]); strcat(tmp, "/"); strcat(tmp, entry->d_name); stat(tmp, &status); if (S_ISDIR(status.st_mode)) { argv[2] = tmp; pthread_create( &threadID[i], &attr, execvp(argv[0], argv), NULL); printf("New thread created : %d", i); i++; } else if (!strcmp(entry->d_name, file)) { printf(" %s was found - Thread number = %d\n",tmp, i); break; } free(tmp); } } pthread_join( threadID[i] , &res ); exit(EXIT_SUCCESS); } Actually it doesn't works : pthread_create( &threadID[i], &attr, execvp(argv[0], argv), NULL); I have no runtime error, but when the file to find is in another directory, the thread is not created and so execvp(argv[0], argv) is not called... Thank you for you help, Simon

    Read the article

  • best practice on precedence of variable declaration and error handling in C

    - by guest
    is there an advantage in one of the following two approaches over the other? here it is first tested, whether fopen succeeds at all and then all the variable declarations take place, to ensure they are not carried out, since they mustn't have had to void func(void) { FILE *fd; if ((fd = fopen("blafoo", "+r")) == NULL ) { fprintf(stderr, "fopen() failed\n"); exit(EXIT_FAILURE); } int a, b, c; float d, e, f; /* variable declarations */ /* remaining code */ } this is just the opposite. all variable declarations take place, even if fopen fails void func(void) { FILE *fd; int a, b, c; float d, e, f; /* variable declarations */ if ((fd = fopen("blafoo", "+r")) == NULL ) { fprintf(stderr, "fopen() failed\n"); exit(EXIT_FAILURE); } /* remaining code */ } does the second approach produce any additional cost, when fopen fails? would love to hear your thoughts!

    Read the article

  • Why can't Perl's WWW::Machanize find the form by field names?

    - by FRESHTER
    #!/usr/bin/perl use WWW::Mechanize; use Compress::Zlib; my $mech = WWW::Mechanize->new(); my $username = ""; #fill in username here my $keyword = ""; #fill in password here my $mobile = $ARGV[0]; my $text = $ARGV[1]; $deb = 1; print length($text)."\n" if($deb); $text = $text."\n\n\n\n\n" if(length($text) < 135); $mech->get("http://wwwl.way2sms.com/content/index.html"); unless($mech->success()) { exit; } $dest = $mech->response->content; print "Fetching...\n" if($deb); if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech->update_html($dest); } $dest =~ s/<form name="loginForm"/<form action='..\/auth.cl' name="loginForm"/g; $mech->update_html($dest); $mech->form_with_fields(("username","password")); $mech->field("username",$username); $mech->field("password",$keyword); print "Loggin...\n" if($deb); $mech->submit_form(); $dest= $mech->response->content; if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech->update_html($dest); } $mech->get("http://wwwl.way2sms.com//jsp/InstantSMS.jsp?val=0"); $dest= $mech->response->content; if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech->update_html($dest); } print "Sending ... \n" if($deb); $mech->form_with_fields(("MobNo","textArea")); $mech->field("MobNo",$mobile); $mech->field("textArea",$text); $mech->submit_form(); if($mech->success()) { print "Done \n" if($deb); } else { print "Failed \n" if($deb); exit; } $dest = $mech->response->content; if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); #print $dest if($deb); } if($dest =~ m/successfully/sig) { print "Message sent successfully" if($deb); } exit; When run this code halts with an error saying: There is no form with the requested fields at ./sms.pl line 65 Can't call method "value" on an undefined value at /usr/share/perl5/vendor_perl/WWW/Mechanize.pm line 1348.

    Read the article

  • Magento set Store Id - customer login - but still logged out

    - by user3564050
    I've got an overridden AccountController in which i set the current store to an other as currently running (example: Customer is in website default and store default, going to login page, click login, my loginPostAction sets the store to id "2" (on website 2) and then executes the parent code loginPostAction. The store is set, of course, but after the login and the redirect to home, the customer is not logged in anymore... Customer-sendlogindata-myaccountcontroller sets store-original account controller logs in without errors (cause $session customer is set)-redirect to home-customer is not logged in anymore... i set the store with Mage::app()-setCurrentStore($id); . And in index.php i've got an extra where the store is set to the right id (2) too and this works... but the customer is not logged in anymore.. is that an issue with the session cause different websites ? I don't want to globally share customer.. each website has his own customers, but every customer has to be able to login on default store. AccountController.php overridden: public $Website_Ids = array( array("code" => "gerstore", "id" => "3", "website" => "ger"), array("code" => "ukstore", "id" => "2", "website" => "uk"), array("code" => "esstore", "id" => "4", "website" => "es"), array("code" => "frstore", "id" => "5", "website" => "fr") ); public function loginPostAction() { $login = $this->getRequest()->get('login'); if(isset($login['username'])) { $found = null; foreach($this->Website_Ids as $WebsiteId) { $customer = Mage::getModel('customer/customer'); $customer->setWebsiteId($WebsiteId['id']); $customer->loadByEmail($login['username']); if(count($customer->getData()) > 0) { $found = $WebsiteId; } } if($found != null && Mage::app()->getStore()->getId() != $found['id']) { /* found, so set currentstore to id */ Mage::app()->setCurrentStore($found['id']); $_SESSION['current_store_b2b'] = $found; } /* not found, doesn't matter cause mage login exception handling */ } parent::loginPostAction(); } Index.php : session_start(); $session = $_SESSION['current_store_b2b']; if($session != null || $session != "") { Mage::app()->setCurrentStore($session['id']); Mage::run($session['code'], 'store'); } else { /* Store or website code */ $mageRunCode = isset($_SERVER['MAGE_RUN_CODE']) ? $_SERVER['MAGE_RUN_CODE'] : ''; /* Run store or run website */ $mageRunType = isset($_SERVER['MAGE_RUN_TYPE']) ? $_SERVER['MAGE_RUN_TYPE'] : 'store'; Mage::run($mageRunCode, $mageRunType); } Whats the matter ? Thanks.

    Read the article

  • Disable button after submit

    - by Chris Philpotts
    I'm trying to disable a button when a user submits a payment form and the code to post the form is causing a double post in firefox. This problem does not occur when the code is removed, and does not occur in any browser other than firefox. Any idea how to prevent the double post here? System.Text.StringBuilder sb = new StringBuilder(); sb.Append("if (typeof(Page_ClientValidate) == 'function') { "); sb.Append("if (Page_ClientValidate() == false) { return false; }} "); sb.Append("this.value = 'Please wait...';"); sb.Append("this.disabled = true;"); sb.Append(Page.GetPostBackEventReference(btnSubmit )); sb.Append(";"); btnSubmit.Attributes.Add("onclick", sb.ToString()); it's the sb.Append(Page.GetPostBackEventReference(btnSubmit )) line that's causing the issue Thanks EDIT: Here's the c# of the button: <asp:Button ID="cmdSubmit" runat="server" Text="Submit" /> here's the html This code posts twice (and disables the submit button and verifies input): <input type="submit" name="ctl00$MainContent$cmdSubmit" value="Submit" onclick="if (typeof(Page_ClientValidate) == 'function') { if (Page_ClientValidate() == false) { return false; }} this.value = 'Please wait...';this.disabled = true;document.getElementById('ctl00_MainContent_cmdBack').disabled = true;__doPostBack('ctl00$MainContent$cmdSubmit','');" id="ctl00_MainContent_cmdSubmit" /> This code posts twice (but doesn’t disable the submit button): <input type="submit" name="ctl00$MainContent$cmdSubmit" value="Submit" onclick="__doPostBack('ctl00$MainContent$cmdSubmit','');" id="ctl00_MainContent_cmdSubmit" /> This code posts once (but doesn’t verify the user input and doesn’t disable the submit button): <input type="submit" name="ctl00$MainContent$cmdSubmit" value="Submit" id="ctl00_MainContent_cmdSubmit" /> This code posts once (but doesn’t disable submit button): <input type="submit" name="ctl00$MainContent$cmdSubmit" value="Submit" onclick="javascript:WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions(&quot;ctl00$MainContent$cmdSubmit&quot;, &quot;&quot;, true, &quot;&quot;, &quot;&quot;, false, false))" id="ctl00_MainContent_cmdSubmit" /> This code doesn’t post at all: <input type="submit" name="ctl00$MainContent$cmdSubmit" value="Submit" onclick="this.disabled = true;WebForm_DoPostBackWithOptions(new WebForm_PostBackOptions(&quot;ctl00$MainContent$cmdSubmit&quot;, &quot;&quot;, true, &quot;&quot;, &quot;&quot;, false, false))" id="ctl00_MainContent_cmdSubmit" /> Obviously it’s the disabling of the submit button that’s posing the problem. Do you have any ideas how we can disable the submit to avoid multiple clicking?

    Read the article

< Previous Page | 465 466 467 468 469 470 471 472 473 474 475 476  | Next Page >