[ebp + 6] instead of +8 in a JIT compiler
- by David Titarenco
I'm implementing a simplistic JIT compiler in a VM I'm writing for fun (mostly to learn more about language design) and I'm getting some weird behavior, maybe someone can tell me why.
First I define a JIT "prototype" both for C and C++:
#ifdef __cplusplus
typedef void* (*_JIT_METHOD) (...);
#else
typedef (*_JIT_METHOD) ();
#endif
I have a compile() function that will compile stuff into ASM and stick it somewhere in memory:
void* compile (void* something)
{
// grab some memory
unsigned char* buffer = (unsigned char*) malloc (1024);
// xor eax, eax
// inc eax
// inc eax
// inc eax
// ret -> eax should be 3
/* WORKS!
buffer[0] = 0x67;
buffer[1] = 0x31;
buffer[2] = 0xC0;
buffer[3] = 0x67;
buffer[4] = 0x40;
buffer[5] = 0x67;
buffer[6] = 0x40;
buffer[7] = 0x67;
buffer[8] = 0x40;
buffer[9] = 0xC3; */
// xor eax, eax
// mov eax, 9
// ret 4 -> eax should be 9
/* WORKS!
buffer[0] = 0x67;
buffer[1] = 0x31;
buffer[2] = 0xC0;
buffer[3] = 0x67;
buffer[4] = 0xB8;
buffer[5] = 0x09;
buffer[6] = 0x00;
buffer[7] = 0x00;
buffer[8] = 0x00;
buffer[9] = 0xC3; */
// push ebp
// mov ebp, esp
// mov eax, [ebp + 6] ; wtf? shouldn't this be [ebp + 8]!?
// mov esp, ebp
// pop ebp
// ret -> eax should be the first value sent to the function
/* WORKS! */
buffer[0] = 0x66;
buffer[1] = 0x55;
buffer[2] = 0x66;
buffer[3] = 0x89;
buffer[4] = 0xE5;
buffer[5] = 0x66;
buffer[6] = 0x66;
buffer[7] = 0x8B;
buffer[8] = 0x45;
buffer[9] = 0x06;
buffer[10] = 0x66;
buffer[11] = 0x89;
buffer[12] = 0xEC;
buffer[13] = 0x66;
buffer[14] = 0x5D;
buffer[15] = 0xC3;
// mov eax, 5
// add eax, ecx
// ret -> eax should be 50
/* WORKS!
buffer[0] = 0x67;
buffer[1] = 0xB8;
buffer[2] = 0x05;
buffer[3] = 0x00;
buffer[4] = 0x00;
buffer[5] = 0x00;
buffer[6] = 0x66;
buffer[7] = 0x01;
buffer[8] = 0xC8;
buffer[9] = 0xC3; */
return buffer;
}
And finally I have the main chunk of the program:
void main (int argc, char **args)
{
DWORD oldProtect = (DWORD) NULL;
int i = 667, j = 1, k = 5, l = 0;
// generate some arbitrary function
_JIT_METHOD someFunc = (_JIT_METHOD) compile(NULL);
// windows only
#if defined _WIN64 || defined _WIN32
// set memory permissions and flush CPU code cache
VirtualProtect(someFunc,1024,PAGE_EXECUTE_READWRITE, &oldProtect);
FlushInstructionCache(GetCurrentProcess(), someFunc, 1024);
#endif
// this asm just for some debugging/testing purposes
__asm mov ecx, i
// run compiled function (from wherever *someFunc is pointing to)
l = (int)someFunc(i, k);
// did it work?
printf("result: %d", l);
free (someFunc);
_getch();
}
As you can see, the compile() function has a couple of tests I ran to make sure I get expected results, and pretty much everything works but I have a question...
On most tutorials or documentation resources, to get the first value of a function passed (in the case of ints) you do [ebp+8], the second [ebp+12] and so forth. For some reason, I have to do [ebp+6] then [ebp+10] and so forth. Could anyone tell me why?
