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• Windows Service is not Working.

  - by prateeksaluja20

  I had made a windows service in visual studio 2008 in C#.inside the service i had written only single line code try { System.Diagnostics.Process.Start(@"E:\Users\Sk\Desktop\category.txt"); } catch { } then i add the project insatller & change the serviceProcessInstaller1 Account proerty as local system Also change the serviceInstaller1 start type proerty as Automatic. then i build the project.it was succesfull. after that i add another project that was setup project.i had added pprimary project output & i had added the custom action as "Primary output from DemoWindowsService (Active)".then buil the setup.setup was build sucessfully.then i install the setup & then went to services start the service.service stated properly butit was not performing the task. i had checked the path is correct & also i tried to do System.Diagnostics.Process.Start(@"E:\Windows\system32\notepad.exe") but still result is same.i tried alot but not getting the ans soleasse help me to solve this problem.

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• Good ACL implementation in Java

  - by yonconf

  Hi All. I'm implementing a web based document management system and I'd like to implement ACLs in my system. My formal requirements are hierarchal permissions (documents inherit permissions from their folders) user groups (users can dynamically create groups and associate users with groups). Such groups can have permissions on objects in the system. My code will query permission on objects in two cases: 1. Manipulating a single document 2. Listing all documents where a manipulation is possible The latter requirement seems the achilles heel for Spring Security ACLs (their method seems likely to incur multiple DB hits for each document I manage) Anyone know of another ACL implementation? Thanks!

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• What is the differance between those two Strings in Java

  - by user1816808

  why when we declare string in java we can't use == to compare this string and always will turn to false while if we initialize the string from the beginning it will be true . for example : import java.util.Scanner; public class MyString { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); String s = input.nextLine(); if(s=="Hello") system.out.println("Hello"); String d = "Hello"; if(d=="Hello") system.out.println("Hello"); } } I need an explanation please ??

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• Problem in populating a dictionary object using Enumerable.Range() (C#3.0)

  - by Newbie

  If I do for (int i = 0; i < appSettings.Count; i++) { string key = appSettings.Keys[i]; euFileDictionary.Add(key, appSettings[i]); } It is working fine. When I am trying the same thing using Enumerable.Range(0, appSettings.Count).Select(i => { string Key = appSettings.Keys[i]; string Value = appSettings[i]; euFileDictionary.Add(Key, Value); }).ToDictionary<string,string>(); I am getting a compile time error The type arguments for method 'System.Linq.Enumerable.Select(System.Collections.Generic.IEnumerable, System.Func)' cannot be inferred from the usage. Try specifying the type arguments explicitly. Any idea? Using C#3.0 Thanks

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• Xml schema, how to make sure one element exists with a specific attribute value

  - by pexxxy

  How do I enforce the existing of an element with a specific attribute value in the XML? For example: <events> <event type="system" desc="this is a system event"/> <event type="bla1" desc="this is bla1 event"/> <event type="bla2" desc="this is bla2 event"/> </events> I need a rule to make sure the event element with type attribute = 'system' exists (once). All other event elements are optional;

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• is it a good idea to change a recovery partition from primary to logical? [HP laptop]

  - by DiegoDD

  I have a new HP laptop, model dv6-6c85la, with 1TB hard drive, and it has 4 primary partitions, like this: |<- system [199 MB] -|<- c: [899.8 GB] -|<- d:(recovery) [27.5 GB] -|<- e:(hp_tools) [4 GB] -| I wanted to make another partition, splitting "C" which is the main partition, into TWO partitions, and leave the rest as it is. but it doesn't let me because they are already 4 primary partitions (the ones in the diagram). I read somewhere, that i could in fact split C into 2 partitions, but only if the adjacent partition (in this case d:(recovery) is converted into a "logical" partition. That way, the new unallocated part taken from C, and the recovery partition, would each be logical, "inside" an extended partition (right???) As i understand, the resulting partitions would be: primary (system, no letter), primary (c:), extended [ logical (x:) | logical(d:recovery) ], primary (e: hp_tools) "x" being the new one. am i correct? My question is, if i do convert the recovery partition to logical (and thus, it is inside an extended partition adjacent to the new "x:" one), would i have any problems when in case of a disaster i would like to restore the system using the now logical instead of primary RECOVERY partition? Or it is completely safe to change it to logical? My main concern is because i think i may need to be primary so the recovery can proceed in boot time? Or i am completely wrong? how does the recovery process happens? I also understand that i can simply create recovery media, in DVDs, and then even i would be able to delete that recovery partition completely, but as of now, i don't want to do that. I may create the disks, but i don't want to delete the partition, simply because it would be a lot faster and easier to recover from a hard drive than disks. Wrapping up: if i change a recovery partition from primary to logical, will the system still be capable of using it to recover? or it NEEDS to be primary to work? The whole point is that i want to split C:, but as things are, i cant directly, i'd need to change the recovery partition to logical. Or is there another way? thanks.

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• Java: Superclass to construct a subclass on certain conditions, possible?

  - by ramihope

  I have this condition public class A { public action() { System.out.println("Action done in A"); } } public class B extends A { public action() { System.out.println("Action done in B"); } } when I create an instance of B, the action will do just actions in B, as it overrides the action of the superclass. the problem is that in my project, the super class A is already used too many times, and I am looking for a way that under certain conditions, when i create an instance of A it makes a check and if it is true, replace itself with B. public class A { public A() { if ([condition]) { this = new B(); } } public action() { System.out.println("Action done in A"); } } A a = new A(); a.action(); // expect to see "Action done in B"... is this possible in some way?

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• Reference to fnc.

  - by atch

  Hi guys, Is there a way in java to do something like this: void fnc(void Reference_to_other_func()); What I'm trying is basically I have number of places where I need to display this same text to the user and the only difference is which method is invoked after this text. So for example instead of writing: System.out.println("Hello"); f1(); //in some other place System.out.println("Hello"); f2(); //etc I would like to define one function: public void f(void Reference_to_other_func()) { System.out.println("Hello"); Reference_to_other_func();//HERE I'M INVOKING } and then instead of repeating this whole code I could write something like this: f(f1); //in some other place f(f2) //etc. Thanks for answers

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• Reference and Value confusion

  - by rgamber

  Hi I read this question on Stack overflow, and tried to do an example. I had the below code: public static void main(String[] args){ int i = 5; Integer I = new Integer(5); increasePrimitive(i); increaseObject(I); System.out.println(i); //Prints 5 - correct System.out.println(I); //Still prints 5 System.out.println(increaseObject2(I)); //Still prints 5 } public static void increasePrimitive(int n){ n++; } public static void increaseObject(Integer n){ n++; } public static int increaseObject2(Integer n){ return n++; } Does the increaseObject print 5 because the value of reference is changing inside that function? Am I right? I am confused why the increasedObject2 prints 5 and not 6. Can anyone please explain?

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• Converting between square and rectangular pixel co-ordinates

  - by FlyboyUtah

  I'm new at using transforms and this type of math, and would appreciate some direction solving my coding problem. I'm writing in XCode for the iphone, and am working with CGraphics. Problem: In Xcode, I want to draw curves, lines and so on it's screen of of square pixels. Then convert those points, as close as possible, into non-square pixel sysem. For example if the original coordinate system is 500 x 500 pixels that are displayed on square screen of 10 by 10 inchs I draw a round circle with the circle formula. It looks round, and all is well. Now, I draw the same circle on a second 10 x 10 inch screen that is 850 pixels by 500 pixels. Without changing the coordinates, the same circle formual displays something that looks like an egg. How can I draw the circle on the second screen in a different coordinate system? And in addition, I need to access the set of points x,y system individually. s

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• Decoding MIME (HTML+Attachments)

  - by MH

  I'm planning to write an application that should handle incoming mails. Basically it will act more like a ticketing system than a webmail, so I'm only interested in receiving emails, and not sending them. I have made a simple prototype that downloads mails and displays the text with downloadable attachments in a web page, but handling mails from Outlook and others is more complicated. I have looked at some of the open source ticketing systems out there, but most of the code is tied to the system and is hard to separate. Is there a library that understands "rich" mail and makes this job simpler? Preferably in Python, Java, Ruby or Perl. I'm also open to suggestions for any command line mail clients that can be used for this, since the system will not receive large amounts of mail and can afford to launch external processes.

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• Need help with this question: Write Java code which reads numbers from the keyboard.....

  - by Chris

  Write Java code which reads numbers from the keyboard until zero is entered. Only the positive numbers entered are to be added to a variable-sized collection. This is what I have so far: import java.lang.*; import java.util.*; import java.io.*; import java.net.*; public class Demo1App extends Object { public static void main(String[] argStrings) throws Exception { ArrayList myArrayList = new ArrayList(); Scanner input = new Scanner(System.in); System.out.println ("NUMBERS:"); while (int input > 0) { myArrayList.add(input); } while (int input < 0) { System.out.println ("ENTER NUMBERS GREATER THAN 0!"); } } } This code doesn't work, I'm not sure why but any help with it would be appreciated.

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• Java/Swing: JTable.rowAtPoint doesn't work correctly for points outside the table?

  - by Jason S

  I have this code to get a row from a JTable that is generated by a DragEvent for a DropTarget in some component C which may or may not be the JTable: public int getRowFromDragEvent(DropTargetDragEvent event) { Point p = event.getLocation(); if (event.getSource() != this.table) { SwingUtilities.convertPointToScreen(p, event.getDropTargetContext().getComponent()); SwingUtilities.convertPointFromScreen(p, this.table); if (!this.table.contains(p)) { System.out.println("outside table, would be row "+this.table.rowAtPoint(p)); } } return this.table.rowAtPoint(p); } The System.out.println is just a hack right now. What I'm wondering, is why the System.out.println doesn't always print "row -1". When the table is empty it does, but if I drag something onto the table's header row, I get the println with "row 0". This seems like a bug... or am I not understanding how rowAtPoint() works?

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• What is wrong with the below statement(C#3.0 / Lambda)

  - by Newbie

  what is wrong in the below Enumerable.Range(0, objEntityCode.Count - 1).Select(i => { options.Attributes[i] = new EntityCodeKey { EntityCode = objEntityCode[i].EntityCodes , OrganizationCode = Constants.ORGANIZATION_CODE }; }) .ToArray(); Throwing error The type arguments for method 'System.Linq.Enumerable.Select(System.Collections.Generic.IEnumerable, System.Func)' cannot be inferred from the usage. Try specifying the type arguments explicitly. But this works Enumerable.Range(0, objEntityCode.Count - 1).ToList().ForEach(i => { options.Attributes[i] = new EntityCodeKey { EntityCode = objEntityCode[i].EntityCodes , OrganizationCode = Constants.ORGANIZATION_CODE }; } ); Using C#3.0. Purpose: I am learning LINQ / LAMBDA and trying to do the same program in different way. Thanks.

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• laptop automatically goes offline [closed]

  - by user20989

  i have windows 2003 domain server in office & two Network printers installed on server. i have installed both printers from server to my PC with windows XP. problem i am facing is: while i start my PC all printers works fine, and after some time my system goes to offline state and printers stop working, until i restart my system again. thanks

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• String comparison in Java

  - by Kliver Max

  I want to compare two strings using Java. First sting name i get from .mif file using GDAL in cp1251 encoding. Second kadname i get from jsp. To compare i do this: if (attrValue instanceof String) { String string3 = new String((attrValue.toString()).getBytes("ISO-8859-1"), "cp1251"); dbFeature.setAttribute(name, string3); System.out.println("Name=" + name); System.out.println("kadname=" + kadname); if (name.equalsIgnoreCase(kadname)) { kadnum = string3; System.out.println("string3" + string3); } } And in console i get this: Name = kadnumm kadname = kadnumm Whats wrong with this?

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• Migrating Split Access Database from one domain to another (not working, details in Q)

  - by Expo_Rob

  Some background: I'm a programmer, not a network administrator, who has been asked to migrate some accounting software (Integrated Office Accounting version 3.2) from an existing domain (OLD_NETWORK) to a new domain (NEW_NETWORK). No-body at the office knows how it works under the hood. It is a split Access 2000 database with the back-end shared and on a file server (which is also the DC) using mapped drives. The DC is NT Server 4 SP 6. The new server is server 2003. The two networks are running independently (ie: two computers on each desk). I have been able to get new computers set up on NEW_NETWORK and working with the IOA software just perfectly but for one problem: The company here uses other entirely separate databases which access the tables IOA maintains (specifically the 'customers' table) via links. To switch between these systems, you press F11 then File-Open the appropriate database and away you go (this is necessary to maintain the permissions that the IOA system uses to protect the customers table). The entire database is Access 2000, the links go to other Access databases, SQL-Server is not involved in any way, nor is a migration to SQL server likely. If I can't migrate anything over, everything will stay as it is, and the NEW_NETWORK computers will not be used. The problem: When I try and update these seperate databases (I shall call one "BANK_ACCOUNT", but the name does not matter), it says "this recordset cannot be updated". It also will sometimes not pull information out of the 'customers' table (ie: date_entered) when looking at a report of everyone who opened a bank account on a certain day (ie: today). I have tried: Giving 'everyone' full control via. shared directory permissions Giving 'everyone' full control on a file system level Checking the permissions within Access (everyone has full read/write on all tables) Copying the entire server contents from one file server to another (ie: xcopy everything) Copying the entire local client files from one computer to another, putting them in the exact same position in the file system, with the same permissons (or full control to 'everyone'). Running as an Administrator Taking one of the NEW_NETWORK computers, having it join OLD_NETWORK and run the software (direct copy from a working system with identical drive mappings), this did not work Weeping openly My Question: Is there anything else I can try? (sorry for this being so long)

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• Java application return codes

  - by doele

  I have a Java program that processes one file at a time. This Java program is called from a wrapper script which logs the return code from the Java program. There are 2 types of errors. Expected errors and unexpected errors. In both cases I just need to log them. My wrapper knows about 3 different states. 0-OK, 1-PROCESSING_FAILED, 2- ERROR. Is this a valid approach? Here is my approach: enum ReturnCodes {OK,PROCESSING_FAILED,ERROR}; public static void main(String[] args) { ... proc.processMyFile(); ... System.exit(ReturnCodes.OK.ordinal()); } catch (Throwable t) { ... System.exit(ReturnCodes.ERROR.ordinal()); } private void processMyFile() { try { ... }catch( ExpectedException e) { ... System.exit(ReturnCodes.PROCESSING_FAILED.ordinal()); } }

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• How can I determine if a given git hash exists on a given branch?

  - by pinko

  Background: I use an automated build system which takes a git hash as input, as well as the name of the branch on which that hash exists, and builds it. However, the build system uses the hash alone to check out the code and build it -- it simply stores the branch name, as given, in the build DB metadata. I'm worried about developers accidentally providing the wrong branch name when they kick off a build, causing confusion when people are looking through the build history. So how can I confirm, before passing along the hash and branch name to the build system, that the given hash does in fact come from the given branch?

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• Error message regarding IEnumerable.GetEnumerator().

  - by Bon_chan

  I get this error message and I can't figure out why! Error 1 'Exo5Chap12.ShortCollection<T>' does not implement interface member 'System.Collections.IEnumerable.GetEnumerator()'. 'Exo5Chap12.ShortCollection<T>.GetEnumerator()' cannot implement 'System.Collections.IEnumerable.GetEnumerator()' because it does not have the matching return type of 'System.Collections.IEnumerator'. E:\MyFolders\Dev\c#\Chapter12\Exo5Chap12\Exo5Chap12\exo5.cs 9 18 Exo5Chap12 Here is the code with an implementation of GetEnumerator(). What is wrong? public class ShortCollection<T> : IList<T> { protected Collection<T> innerCollection; protected int maxSize = 10; public IEnumerator<T> GetEnumerator() { return (innerCollection as IEnumerator<T>).GetEnumerator(); } }

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• Can Firewall or Specific Software Server Tools Blocked PHP [closed]

  - by Kaii

  im using php scritps to upload file from my pc to our developments server the problem is after a hours my scripts seems doesn`t work or something is blocking it to upload images file.. our office as a new firewalll system application that allows to block applications and others is this connected to what ive encountered now? because script even the previous system scripts for uploading image that i created failed to work .. They just uploading the image with 0kb.

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• Confusing calling method in Java

  - by vBx

  class Parent { private void method1() { System.out.println("Parent's method1()"); } public void method2() { System.out.println("Parent's method2()"); method1(); } } class Child extends Parent { public void method1() { System.out.println("Child's method1()"); } } class test { public static void main(String args[]) { Parent p = new Child(); p.method2(); } } I'm confuse why does in Parent::method2() when invoking method1() it will cal Parents method1() and not Childs method1 ? I see that this happens only when method1() is private? Can someone explain me why ? Thanks you.

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• what does "do" do here? (java)

  - by David

  I saw this bit of code on the interents somewhere. I'm wondering what thedo is for. public class LoopControl { public static void main(String[] args) { int count = 0; do { if(count % 2 == 0) { for(int j = 0; j < count; j++) { System.out.print(j+1); if(j < count-1) System.out.print(", "); } System.out.println(); } count++; } while(count <= 5); } }

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• Run Windows in Ubuntu with VMware Player

  - by Matthew Guay

  Are you an enthusiast who loves their Ubuntu Linux experience but still needs to use Windows programs?  Here’s how you can get the full Windows experience on Ubuntu with the free VMware Player. Linux has become increasingly consumer friendly, but still, the wide majority of commercial software is only available for Windows and Macs.  Dual-booting between Windows and Linux has been a popular option for years, but this is a frustrating solution since you have to reboot into the other operating system each time you want to run a specific application.  With virtualization, you’ll never have to make this tradeoff.  VMware Player makes it quick and easy to install any edition of Windows in a virtual machine.  With VMware’s great integration tools, you can copy and paste between your Linux and Windows programs and even run native Windows applications side-by-side with Linux ones. Getting Started Download the latest version of VMware Player for Linux, and select either the 32-bit or 64-bit version, depending on your system.  VMware Player is a free download, but requires registration.  Sign in with your VMware account, or create a new one if you don’t already have one. VMware Player is fairly easy to install on Linux, but you will need to start out the installation from the terminal.  First, enter the following to make sure the installer is marked as executable, substituting version/build_number for the version number on the end of the file you downloaded. chmod +x ./VMware-Player-version/build_number.bundle Then, enter the following to start the install, again substituting your version number: gksudo bash ./VMware-Player-version/build_number.bundle You may have to enter your administrator password to start the installation, and then the VMware Player graphical installer will open.  Choose whether you want to check for product updates and submit usage data to VMware, and then proceed with the install as normal. VMware Player installed in only a few minutes in our tests, and was immediately ready to run, no reboot required.  You can now launch it from your Ubuntu menu: click Applications \ System Tools \ VMware Player. You’ll need to accept the license agreement the first time you run it. Welcome to VMware Player!  Now you can create new virtual machines and run pre-built ones on your Ubuntu desktop. Install Windows in VMware Player on Ubuntu Now that you’ve got VMware setup, it’s time to put it to work.  Click the Create a New Virtual Machine as above to start making a Windows virtual machine. In the dialog that opens, select your installer disk or ISO image file that you want to install Windows from.  In this example, we’re select a Windows 7 ISO.  VMware will automatically detect the operating system on the disk or image.  Click Next to continue. Enter your Windows product key, select the edition of Windows to install, and enter your name and password. You can leave the product key field blank and enter it later.  VMware will ask if you want to continue without a product key, so just click Yes to continue. Now enter a name for your virtual machine and select where you want to save it.  Note: This will take up at least 15Gb of space on your hard drive during the install, so make sure to save it on a drive with sufficient storage space. You can choose how large you want your virtual hard drive to be; the default is 40Gb, but you can choose a different size if you wish.  The entire amount will not be used up on your hard drive initially, but the virtual drive will increase in size up to your maximum as you add files.  Additionally, you can choose if you want the virtual disk stored as a single file or as multiple files.  You will see the best performance by keeping the virtual disk as one file, but the virtual machine will be more portable if it is broken into smaller files, so choose the option that will work best for your needs. Finally, review your settings, and if everything looks good, click Finish to create the virtual machine. VMware will take over now, and install Windows without any further input using its Easy Install.  This is one of VMware’s best features, and is the main reason we find it the easiest desktop virtualization solution to use.   Installing VMware Tools VMware Player doesn’t include the VMware Tools by default; instead, it automatically downloads them for the operating system you’re installing.  Once you’ve downloaded them, it will use those tools anytime you install that OS.  If this is your first Windows virtual machine to install, you may be prompted to download and install them while Windows is installing.  Click Download and Install so your Easy Install will finish successfully. VMware will then download and install the tools.  You may need to enter your administrative password to complete the install. Other than this, you can leave your Windows install unattended; VMware will get everything installed and running on its own. Our test setup took about 30 minutes, and when it was done we were greeted with the Windows desktop ready to use, complete with drivers and the VMware tools.  The only thing missing was the Aero glass feature.  VMware Player is supposed to support the Aero glass effects in virtual machines, and although this works every time when we use VMware Player on Windows, we could not get it to work in Linux.  Other than that, Windows is fully ready to use.  You can copy and paste text, images, or files between Ubuntu and Windows, or simply drag-and-drop files between the two. Unity Mode Using Windows in a window is awkward, and makes your Windows programs feel out of place and hard to use.  This is where Unity mode comes in.  Click Virtual Machine in VMware’s menu, and select Enter Unity. Your Windows desktop will now disappear, and you’ll see a new Windows menu underneath your Ubuntu menu.  This works the same as your Windows Start Menu, and you can open your Windows applications and files directly from it. By default, programs from Windows will have a colored border and a VMware badge in the corner.  You can turn this off from the VMware settings pane.  Click Virtual Machine in VMware’s menu and select Virtual Machine Settings.  Select Unity under the Options tab, and uncheck the Show borders and Show badges boxes if you don’t want them. Unity makes your Windows programs feel at home in Ubuntu.  Here we have Word 2010 and IE8 open beside the Ubuntu Help application.  Notice that the Windows applications show up in the taskbar on the bottom just like the Linux programs.  If you’re using the Compiz graphics effects in Ubuntu, your Windows programs will use them too, including the popular wobbly windows effect. You can switch back to running Windows inside VMware Player’s window by clicking the Exit Unity button in the VMware window. Now, whenever you want to run Windows applications in Linux, you can quickly launch it from VMware Player. Conclusion VMware Player is a great way to run Windows on your Linux computer.  It makes it extremely easy to get Windows installed and running, lets you run your Windows programs seamlessly alongside your Linux ones.  VMware products work great in our experience, and VMware Player on Linux was no exception. If you’re a Windows user and you’d like to run Ubuntu on Windows, check out our article on how to Run Ubuntu in Windows with VMware Player. Link Download VMware Player 3 (Registration required) Download Windows 7 Enterprise 90-day trial Similar Articles Productive Geek Tips Enable Copy and Paste from Ubuntu VMware GuestInstall VMware Tools on Ubuntu Edgy EftRestart the Ubuntu Gnome User Interface QuicklyHow to Add a Program to the Ubuntu Startup List (After Login)How To Run Ubuntu in Windows 7 with VMware Player TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 Get a free copy of WinUtilities Pro 2010 World Cup Schedule Boot Snooze – Reboot and then Standby or Hibernate Customize Everything Related to Dates, Times, Currency and Measurement in Windows 7 Google Earth replacement Icon (Icons we like) Build Great Charts in Excel with Chart Advisor

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• Azure Grid Computing - Worker Roles as HPC Compute Nodes

  - by JoshReuben

  Overview ·        With HPC 2008 R2 SP1 You can add Azure worker roles as compute nodes in a local Windows HPC Server cluster. ·        The subscription for Windows Azure like any other Azure Service - charged for the time that the role instances are available, as well as for the compute and storage services that are used on the nodes. ·        Win-Win ? - Azure charges the computer hour cost (according to vm size) amortized over a month – so you save on purchasing compute node hardware. Microsoft wins because you need to purchase HPC to have a local head node for managing this compute cluster grid distributed in the cloud. ·        Blob storage is used to hold input & output files of each job. I can see how Parametric Sweep HPC jobs can be supported (where the same job is run multiple times on each node against different input units), but not MPI.NET (where different HPC Job instances function as coordinated agents and conduct master-slave inter-process communication), unless Azure is somehow tunneling MPI communication through inter-WorkerRole Azure Queues. ·        this is not the end of the story for Azure Grid Computing. If MS requires you to purchase a local HPC license (and administrate it), what's to stop a 3rd party from doing this and encapsulating exposing HPC WCF Broker Service to you for managing compute nodes? If MS doesn’t  provide head node as a service, someone else will! Process ·        requires creation of a worker node template that specifies a connection to an existing subscription for Windows Azure + an availability policy for the worker nodes. ·        After worker nodes are added to the cluster, you can start them, which provisions the Windows Azure role instances, and then bring them online to run HPC cluster jobs. ·        A Windows Azure worker role instance runs a HPC compatible Azure guest operating system which runs on the VMs that host your service. The guest operating system is updated monthly. You can choose to upgrade the guest OS for your service automatically each time an update is released - All role instances defined by your service will run on the guest operating system version that you specify. see Windows Azure Guest OS Releases and SDK Compatibility Matrix (http://go.microsoft.com/fwlink/?LinkId=190549). ·        use the hpcpack command to upload file packages and install files to run on the worker nodes. see hpcpack (http://go.microsoft.com/fwlink/?LinkID=205514). Requirements ·        assuming you have an azure subscription account and the HPC head node installed and configured. ·        Install HPC Pack 2008 R2 SP 1 -  see Microsoft HPC Pack 2008 R2 Service Pack 1 Release Notes (http://go.microsoft.com/fwlink/?LinkID=202812). ·        Configure the head node to connect to the Internet - connectivity is provided by the connection of the head node to the enterprise network. You may need to configure a proxy client on the head node. Any cluster network topology (1-5) is supported). ·        Configure the firewall - allow outbound TCP traffic on the following ports: 80,       443, 5901, 5902, 7998, 7999 ·        Note: HPC Server  uses Admin Mode (Elevated Privileges) in Windows Azure to give the service administrator of the subscription the necessary privileges to initialize HPC cluster services on the worker nodes. ·        Obtain a Windows Azure subscription certificate - the Windows Azure subscription must be configured with a public subscription (API) certificate -a valid X.509 certificate with a key size of at least 2048 bits. Generate a self-sign certificate & upload a .cer file to the Windows Azure Portal Account page > Manage my API Certificates link. see Using the Windows Azure Service Management API (http://go.microsoft.com/fwlink/?LinkId=205526). ·        import the certificate with an associated private key on the HPC cluster head node - into the trusted root store of the local computer account. Obtain Windows Azure Connection Information for HPC Server ·        required for each worker node template ·        copy from azure portal - Get from: navigation pane > Hosted Services > Storage Accounts & CDN ·        Subscription ID - a 32-char hex string in the form xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx. In Properties pane. ·        Subscription certificate thumbprint - a 40-char hex string (you need to remove spaces). In Management Certificates > Properties pane. ·        Service name - the value of <ServiceName> configured in the public URL of the service (http://<ServiceName>.cloudapp.net). In Hosted Services > Properties pane. ·        Blob Storage account name - the value of <StorageAccountName> configured in the public URL of the account (http://<StorageAccountName>.blob.core.windows.net). In Storage Accounts > Properties pane. Import the Azure Subscription Certificate on the HPC Head Node ·        enable the services for Windows HPC Server  to authenticate properly with the Windows Azure subscription. ·        use the Certificates MMC snap-in to import the certificate to the Trusted Root Certification Authorities store of the local computer account. The certificate must be in PFX format (.pfx or .p12 file) with a private key that is protected by a password. ·        see Certificates (http://go.microsoft.com/fwlink/?LinkId=163918). ·        To open the certificates snapin: Run > mmc. File > Add/Remove Snap-in > certificates > Computer account > Local Computer ·        To import the certificate via wizard - Certificates > Trusted Root Certification Authorities > Certificates > All Tasks > Import ·        After the certificate is imported, it appears in the details pane in the Certificates snap-in. You can open the certificate to check its status. Configure a Proxy Client on the HPC Head Node ·        the following Windows HPC Server services must be able to communicate over the Internet (through the firewall) with the services for Windows Azure: HPCManagement, HPCScheduler, HPCBrokerWorker. ·        Create a Windows Azure Worker Node Template ·        Edit HPC node templates in HPC Node Template Editor. ·        Specify: 1) Windows Azure subscription connection info (unique service name) for adding a set of worker nodes to the cluster + 2)worker node availability policy – rules for deploying / removing worker role instances in Windows Azure o   HPC Cluster Manager > Configuration > Navigation Pane > Node Templates > Actions pane > New à Create Node Template Wizard or Edit à Node Template Editor o   Choose Node Template Type page - Windows Azure worker node template o   Specify Template Name page – template name & description o   Provide Connection Information page – Azure Subscription ID (text) & Subscription certificate (browse) o   Provide Service Information page - Azure service name + blob storage account name (optionally click Retrieve Connection Information to get list of available from azure – possible LRT). o   Configure Azure Availability Policy page - how Windows Azure worker nodes start / stop (online / offline the worker role instance -  add / remove) – manual / automatic o   for automatic - In the Configure Windows Azure Worker Availability Policy dialog -select days and hours for worker nodes to start / stop. ·        To validate the Windows Azure connection information, on the template's Connection Information tab > Validate connection information. ·        You can upload a file package to the storage account that is specified in the template - eg upload application or service files that will run on the worker nodes. see hpcpack (http://go.microsoft.com/fwlink/?LinkID=205514). Add Azure Worker Nodes to the HPC Cluster ·        Use the Add Node Wizard – specify: 1) the worker node template, 2) The number of worker nodes   (within the quota of role instances in the azure subscription), and 3)           The VM size of the worker nodes : ExtraSmall, Small, Medium, Large, or ExtraLarge.  ·        to add worker nodes of different sizes, must run the Add Node Wizard separately for each size. ·        All worker nodes that are added to the cluster by using a specific worker node template define a set of worker nodes that will be deployed and managed together in Windows Azure when you start the nodes. This includes worker nodes that you add later by using the worker node template and, if you choose, worker nodes of different sizes. You cannot start, stop, or delete individual worker nodes. ·        To add Windows Azure worker nodes o   In HPC Cluster Manager: Node Management > Actions pane > Add Node à Add Node Wizard o   Select Deployment Method page - Add Azure Worker nodes o   Specify New Nodes page - select a worker node template, specify the number and size of the worker nodes ·        After you add worker nodes to the cluster, they are in the Not-Deployed state, and they have a health state of Unapproved. Before you can use the worker nodes to run jobs, you must start them and then bring them online. ·        Worker nodes are numbered consecutively in a naming series that begins with the root name AzureCN – this is non-configurable. Deploying Windows Azure Worker Nodes ·        To deploy the role instances in Windows Azure - start the worker nodes added to the HPC cluster and bring the nodes online so that they are available to run cluster jobs. This can be configured in the HPC Azure Worker Node Template – Azure Availability Policy -  to be automatic or manual. ·        The Start, Stop, and Delete actions take place on the set of worker nodes that are configured by a specific worker node template. You cannot perform one of these actions on a single worker node in a set. You also cannot perform a single action on two sets of worker nodes (specified by two different worker node templates). ·        ·          Starting a set of worker nodes deploys a set of worker role instances in Windows Azure, which can take some time to complete, depending on the number of worker nodes and the performance of Windows Azure. ·        To start worker nodes manually and bring them online o   In HPC Node Management > Navigation Pane > Nodes > List / Heat Map view - select one or more worker nodes. o   Actions pane > Start – in the Start Azure Worker Nodes dialog, select a node template. o   the state of the worker nodes changes from Not Deployed to track the provisioning progress – worker node Details Pane > Provisioning Log tab. o   If there were errors during the provisioning of one or more worker nodes, the state of those nodes is set to Unknown and the node health is set to Unapproved. To determine the reason for the failure, review the provisioning logs for the nodes. o   After a worker node starts successfully, the node state changes to Offline. To bring the nodes online, select the nodes that are in the Offline state > Bring Online. ·        Troubleshooting o   check node template. o   use telnet to test connectivity: telnet <ServiceName>.cloudapp.net 7999 o   check node status - Deployment status information appears in the service account information in the Windows Azure Portal - HPC queries this -  see  node status information for any failed nodes in HPC Node Management. ·        When role instances are deployed, file packages that were previously uploaded to the storage account using the hpcpack command are automatically installed. You can also upload file packages to storage after the worker nodes are started, and then manually install them on the worker nodes. see hpcpack (http://go.microsoft.com/fwlink/?LinkID=205514). ·        to remove a set of role instances in Windows Azure - stop the nodes by using HPC Cluster Manager (apply the Stop action). This deletes the role instances from the service and changes the state of the worker nodes in the HPC cluster to Not Deployed. ·        Each time that you start a set of worker nodes, two proxy role instances (size Small) are configured in Windows Azure to facilitate communication between HPC Cluster Manager and the worker nodes. The proxy role instances are not listed in HPC Cluster Manager after the worker nodes are added. However, the instances appear in the Windows Azure Portal. The proxy role instances incur charges in Windows Azure along with the worker node instances, and they count toward the quota of role instances in the subscription.

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