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  • one to many jpa relationship

    - by user309944
    Hai I have created two table first table as student package com.crimson.rship; import javax.persistence.Basic; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.Id; import javax.persistence.OneToMany; @Entity(name="student") public class student { @Id private String stumailid; @Basic private String fathername; @Basic private String mothername; @Basic private String doa; @Basic private String dob; public student(String stumailid,String fathername,String mothername,String doa,String dob) { // TODO Auto-generated constructor stub this.stumailid=stumailid; this.fathername=fathername; this.mothername=mothername; this.doa=doa; this.dob=dob; } public void setStumailid(String stumailid) { this.stumailid = stumailid; } public String getStumailid() { return stumailid; } public void setFathername(String fathername) { this.fathername = fathername; } public String getFathername() { return fathername; } public void setMothername(String mothername) { this.mothername = mothername; } public String getMothername() { return mothername; } public void setDoa(String doa) { this.doa = doa; } public String getDoa() { return doa; } public void setDob(String dob) { this.dob = dob; } public String getDob() { return dob; } } Second table as mark package com.crimson.rship; import java.util.Collection; import javax.persistence.Basic; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.OneToMany; @Entity(name="mark") public class mark { @Id private String stumailid; @Basic private String fathername; @Basic private String mothername; @OneToMany(mappedBy="mark",targetEntity=student.class,fetch=FetchType.EAGER) private Collection orders; public mark(String stumailid,String fathername,String mothername) { // TODO Auto-generated constructor stub this.stumailid=stumailid; this.fathername=fathername; this.mothername=mothername; } public void setStumailid(String stumailid) { this.stumailid = stumailid; } public String getStumailid() { return stumailid; } public void setFathername(String fathername) { this.fathername = fathername; } public String getFathername() { return fathername; } public void setMothername(String mothername) { this.mothername = mothername; } public String getMothername() { return mothername; } public void setOrders(Collection orders) { this.orders = orders; } public Collection getOrders() { return orders; } } But this above coding working is not working correctly.can any one help me Thanks in advance

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  • data parsed to database Nokogiri rails

    - by Charlie Allombert
    So I'm just getting started with Nokogiri and Rails I have the following which returns the name of someone. TEST.rb: require 'nokogiri' require 'open-uri' url = "http://www.imdb.com/title/tt1439629/" doc = Nokogiri::HTML(open(url)) puts doc.css("div#wrapper [...too long...]")[0].text Now I created a table in my DB on rails and want to send the returned name to the actor table in the name column! How would I do that ? I can't seem to find atutorial on this... My goal would eventually be to have a rails form where I'd input an IMDB link which would return title and so on... (Also I'm new to ruby rails and programming so please provide easy info!)

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  • A question about indexes regarding to the gain of inserts & updates in database

    - by Mestika
    Hi, I’m having a question about the fine line between the gain of an index to a table there is growing steadily in size every month and the gain of queries with an index. The situation is, that I’ve two tables, Table1 and Table2. Each table grows slowly but regularly each month (with about 100 new rows for Table1 and a couple of rows for Table2). My concrete question is whether to have an index or to drop it. I’ve made some measurement that an covering index on Table2 improve my SELECT queries and some rather much but again, I’ve to consider the pros and cons but having a really hard time to decide. For Table1 it might not be necessary to have an index because the SELECT queries there is not that common. I would appreciate any suggestion, tips or just good advice to what is a good solution. By the way, I’m using IBM DB2 version 9.7 as my Database system Sincerely Mestika

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  • Hibernate: how to maintain insertion order

    - by jwaddell
    I have a list of entities where creation order is important, but they do not contain a timestamp to use for sorting. Entities are added to the end of the list as they are created so they will be ordered correctly in the list itself. After persisting the list using Hibernate the entities appear in the database table in the order that they were created. However when retrieving the list using a new Hibernate session the list is now in reverse order of insertion/creation. Is this expected behaviour? Is there any way to retrieve the list in the same order as it appears in the table? The primary key is a UUID, and the list of entities should always have been created on the same IP address and JVM. This mean sorting by UUID is a possibility but I'd rather not make assumptions. Another possibility is if the list is guaranteed to always come out in reverse order I could always just work through it backwards.

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  • modx revo snippet variable in query

    - by Meddie
    I noticed something weird when using a query in a snippet. When I have a query like this: $sql = 'SELECT * FROM table WHERE colomn = ' . $variable; And I echo $sql, the query reads: SELECT * FROM table WHERE colomn = <code class="php plain">2</code> .. wich will result in an error because the sql is no longer valid. So for now I use strip_tags to remove the code tag, but I find it not a very clean method. I couldnt find anything about this, so maybe someone can shed some light on this for me?

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  • How to cache queries in EJB and return result efficient (performance POV)

    - by Maxym
    I use JBoss EJB 3.0 implementation (JBoss 4.2.3 server) At the beginning I created native query all the time using construction like Query query = entityManager.createNativeQuery("select * from _table_"); Of couse it is not that efficient, I performed some tests and found out that it really takes a lot of time... Then I found a better way to deal with it, to use annotation to define native queries: @NamedNativeQuery( name = "fetchData", value = "select * from _table_", resultClass=Entity.class ) and then just use it Query query = entityManager.createNamedQuery("fetchData"); the performance of code line above is two times better than where I started from, but still not that good as I expected... then I found that I can switch to Hibernate annotation for NamedNativeQuery (anyway, JBoss's implementation of EJB is based on Hibernate), and add one more thing: @NamedNativeQuery( name = "fetchData2", value = "select * from _table_", resultClass=Entity.class, readOnly=true) readOnly - marks whether the results are fetched in read-only mode or not. It sounds good, because at least in this case of mine I don't need to update data, I wanna just fetch it for report. When I started server to measure performance I noticed that query without readOnly=true (by default it is false) returns result with each iteration better and better, and at the same time another one (fetchData2) works like "stable" and with time difference between them is shorter and shorter, and after 5 iterations speed of both was almost the same... The questions are: 1) is there any other way to speed query using up? Seems that named queries should be prepared once, but I can't say it... In fact if to create query once and then just use it it would be better from performance point of view, but it is problematic to cache this object, because after creating query I can set parameters (when I use ":variable" in query), and it changes query object (isn't it?). well, is here any way to cache them? Or named query is the best option I can use? 2) any other approaches how to make results retrieveng faster. I mean, for instance I don't need those Entities to be attached, I won't update them, all I need is just fetch collection of data. Maybe readOnly is the only available way, so I can't speed it up, but who knows :) P.S. I don't ask about DB performance, all I need now is how not to create query all the time, so use it efficient, and to "allow" EJB to do less job with the same result concerning data returning.

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  • Database Abstraction & Factory Methods

    - by pws5068
    I'm interested in learning more about design practices in PHP for Database Abstraction & Factory methods. For background, my site is a common-interest social networking community currently in beta mode. Currently, I've started moving my old code for object retrieval to factory methods. However, I do feel like I'm limiting myself by keeping a lot of SQL table names and structure separated in each function/method. Questions: Is there a reason to use PEAR (or similar) if I dont anticipate switching databases? Can PEAR interface with the MySqli prepared statements I currently use? Will it help me separate table names from each method? (If no, what other design patterns might I want to research?) Will it slow down my site once I have a significantly large member base?

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  • Can you explain this odd behavior with dragging items into nested sortables?

    - by RDL
    I have the following setup: A sortable list where one of the <li> has a table with lists in each cell. All of the lists are sortable with each other. Draggable items that can be added to any of the sortables Issue: When adding a draggable item ('drag 1', 'drag 2', 'drag 3') to one of the lists in the horizontal lists (table of lists) it duplicates the draggable when dropped. Sometimes it will create both copies in the same list or one in the item list and one in the column list. Here is a demo: http://jsfiddle.net/MQTgA/ Question: How do I prevent the second item being created when dropping the draggable?

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  • Incompatible classes when loading SWF

    - by Bart van Heukelom
    I have two ActionScript 3 projects, game(.swf) and minigame(.swf). At runtime the main game loads the minigame via Loader. I also have a shared library (SWC) of event classes, included by both, which minigame will need to dispatch and game will need to listen to. First: Is this possible this way? Second: What will happen if I compile the minigame, then change the event classes so they're incompatible, then compile the main game. Will Flash crash when trying to load the minigame SWF? (I hope so) Third: And what will happen if I change the event classes, but in a way that preserves interface-level compatibility?

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  • Hibernate multi column discriminator

    - by shikarishambu
    I have a single lookup table that manages all lookups - legacy and new lookup table structure is context,name, code, value context is either legacy or new name is the name of the lookup - state, status etc...for example code is the code and value is the value associated with the code Is there a way to specify multiple columns as discriminators so that I can get all legacy state code/values or all new status code/values. Is there a different way to do this if discriminators cannot do it? <class name="com.company.domain.Lookup"> <id name="Id" column="id" type="big_integer"> <generator class="org.hibernate.id.TableHiLoGenerator" /> </id> <discriminator column="context" insert="false" /> <property name="code" type="string"/> <property name="value" type="string"/> <property name="desc" type="string"/> <subclass name="com.company.domain.LegacyLookup" discriminator-value="legacy">

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  • Passing password value through URL

    - by Steven Wright
    OK I see a lot of people asking about passing other values, URLS, random stuff through a URL, but don't find anything about sending a password to a password field. Here is my situation: I have a ton of sites I use on a daily basis with my work and oh about 90% require logins. Obviously remembering 80 bajillion logins for each site is dumb, especially when there are more than one user name I use for each site. So to make life easier, I drew up a nifty JSP app that stores all of my logins in a DB table and creates a user interface for the specific page I want to visit. Each page has a button that sends a username, password into the id parameters of the html inputs. Problem: I can get the usernames and other info to show up just dandy, but when I try and send a password to a password field, it seems that nothing gets received by the page I'm trying to hit. Is there some ninja stuff I need to be doing here or is it just not easily possible? Basically this is what I do now: http://addresshere/support?loginname=steveoooo&loginpass=passwordhere and some of my html looks like this: <form name="userform" method="post" action="index.jsp" > <input type="hidden" name="submit_login" value="y"> <table width="100%"> <tr class="main"> <td width="100" nowrap>Username:</td> <td><input type="text" name="loginname" value="" size="30" maxlength="64"></td> </tr> <tr class="main"> <td>Password: </font></td> <td><input type="password" name="loginpass" value="" size="30" maxlength="64"></td> </tr> <tr class="main"> <td><center><input type="submit" name="submit" value="Login"></center></td> </tr> </table> </form> Any suggestions?

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  • Efficiently retrieve objects with one to many references in Grails using GORM

    - by bebeastie
    I'm trying to determine how to find/retrieve/load objects efficiently in terms of a.) minimizing calls to database and b.) keeping the code as elegant/simple as possible (i.e. not writing hql etc.). Assume you have two objects: public class Foo { Bar bar String badge } public class Bar { String name } Each Foo has a bar and a badge. Also assume that all badges are unique within a bar. So if a Foo has a badge "4565" there are no other Foos that have the same badge # AND the same bar. If I have a bar ID, how can I efficiently retrive the Foo w/o first selecting Bar? I know I can do this: Foo.findByBadgeAndBar("4565", Bar.findById("1")) But that seems to cause a select on the Bar table followed by a select on the Foo table. In other words, I need to produce the Grails/Hibernate/GORM equivalent of the following: select * from foo where badge="4565" and bar_id="1"

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  • Next and Previous MySQL row based on name

    - by NightMICU
    Hi everyone, I have a table with details on personnel. I would like to create a Next/Previous link based on the individual's last name. Since personnel were not added in alphabetical order, selecting the next or previous row based on its ID does not work. It is a hefty table - the pertinent fields are id, name_l, and name_f. I would like to order by name_l, the individuals' last name. How would I go about accomplishing this task? Thanks!

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  • MySQL: filling empty fields with zeroes when using GROUP BY

    - by SaltLake
    I've got MySQL table CREATE TABLE cms_webstat ( ID int NOT NULL auto_increment PRIMARY KEY, TIMESTAMP_X timestamp DEFAULT CURRENT_TIMESTAMP, # ... some other fields ... ) which contains statistics about site visitors. For getting visits per hour I use SELECT hour(TIMESTAMP_X) as HOUR , count(*) AS HOUR_STAT FROM cms_webstat GROUP BY HOUR ORDER BY HOUR DESC which gives me | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 20 | 3 | | 18 | 2 | | 15 | 1 | | 12 | 3 | | 9 | 1 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | And I'd like to get following: | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 21 | 0 | | 20 | 3 | | 19 | 0 | | 18 | 2 | | 17 | 0 | | 16 | 0 | | 15 | 1 | | 14 | 0 | | 13 | 0 | | 12 | 3 | | 11 | 0 | | 10 | 0 | | 9 | 1 | | 8 | 0 | | 7 | 0 | | 6 | 0 | | 5 | 0 | | 4 | 0 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | How should I modify the query to get such result? Thanks.

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  • GridView styling (CSS classes) disappears

    - by ProfK
    I'm migrating a large number of stand-alone pages into content pages. Most of this involves little more than copying and pasting a GridView from one page into the new page. However, I find that styling disappears in the new project, i.e. the styles (as classes) are still present in the stylesheet, but these classes are no longer applied to GridView table elements. Example, in the old project, once a table is rendered by the GridView, its header row has a class of HeaderStyle, but in the new project this is lost, without any editing of the GridView. Is there some mysterious, built-in mechanism that automatically applies these attributes to GridView elements that I have somehow disabled?

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  • Can I create many tables according to the same entity?

    - by jacob
    What I want to do is that I want to make the many tables dinamically which are the same entity structures. And then I want to refer to the dinamically created tables according to the table name. What I understood from hibernate reference is that I can only create only one table and it should be matched exactly with entity. So I can't find any solution to my problem. If you know any relevent open source related to my problem or any tip or web site, let me know. Thanks allways

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  • Is it a good idea to use a computed column as part of a primary key ?

    - by Brann
    I've got a table defined as : OrderID bigint NOT NULL, IDA varchar(50) NULL, IDB bigint NULL, [ ... 50 other non relevant columns ...] The natural primary key for this table would be (OrderID,IDA,IDB), but this it not possible because IDA and IDB can be null (they can both be null, but they are never both defined at the same time). Right now I've got a unique constraint on those 3 columns. Now, the thing is I need a primary key to enable transactional replication, and I'm faced with two choices : Create an identity column and use it as a primary key Create a non-null computed column C containing either IDA or IDB or '' if both columns were null, and use (OrderID,C) as my primary key. The second alternative seams cleaner as my PK would be meaningful, and is feasible (see msdn link), but since I've never seen this done anywhere, I was wondering if they were some cons to this approach.

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  • JOIN two tables to show already purchased items

    - by Norbert
    I have a table where I keep all my templates: templates template_id template_name template_price These templates can be purchased by a registered user and then are inserted in the payments table: payments payment_id template_id user_id Is there a way to join these two tables and get not just a list of templates that have been purchased by a certain user, but all the templates? And then figure out from there which ones have already been purchased? I used this SELECT, but only the ones that the user bought showed up. I would like to have all the rows from templates, but empty in case the user_id doesn't match. SELECT * FROM templates LEFT JOIN payments ON templates.template_id = payments.template_id WHERE user_id = 2 GROUP BY templates.template_id

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  • displaying values from join query array

    - by THOmas
    I have used a join query for retrieving value from two tables one is blogquestion and userdetails I wrote this query $this->questions = Doctrine_Query::create() ->select('b.question_id,b.user_id,b.question_title,b.question_tags,b.created_at,u.id,u.name') ->from('BlogQuestion b') ->leftJoin('b.UserDetails u') ->execute(); In the template iam displaying the result using a foreach <?php foreach($questions as $quest):?> echo $quest->getQuestionTitle() echo $quest->getQuestionTags() echo $quest->getName() <?php endforeach?> title is getting from the blogquestion table and name is in usredetails table iam getting the eerror Unknown record property / related component "name" on "BlogQuestion"

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  • pitfalls with mixing storage engines in mysql with django?

    - by Dave Orr
    I'm running a django system over mysql in amazon's cloud, and the database default is innodb. But now I want to put a fulltext index on a couple of tables for searching, which evidently requires myisam. The obvious solution is to just tell mysql to ALTER TABLE to myisam, but are there going to be any issues with that? One that comes to mind is that I'll have to remember to do that any time I build a new version of the database, which should theoretically be rare, but there doesn't seem to be a way to tell django to please set the storage engine at the table level. I guess I could write a migration (we use south). Any other things I might be missing? What could possibly go wrong?

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  • problem adding a where clause to a T-sql LEFT OUTER JOIN query

    - by Nickson
    SELECT TOP (100) PERCENT dbo.EmployeeInfo.id, MIN(dbo.EmployeeInfo.EmpNo) AS EmpNo, SUM(dbo.LeaveApplications.DaysAuthorised) AS DaysTaken FROM dbo.EmployeeInfo LEFT OUTER JOIN dbo.LeaveApplications ON dbo.EmployeeInfo.id = dbo.LeaveApplications.EmployeeID WHERE (YEAR(dbo.LeaveApplications.ApplicationDate) = YEAR(GETDATE())) GROUP BY dbo.EmployeeInfo.id, dbo.EmployeeMaster.EmpNo ORDER BY DaysTaken DESC The basic functionality i want is to retrieve all records in table dbo.EmployeeInfo irrespective of whether a corresponding record exists in table dbo.LeaveApplications. If a row in EmployeeInfo has no related row in LeaveApplications, i want to return its SUM(dbo.LeaveApplications.DaysAuthorised) AS DaysTaken column as NULL or may be even put a 0. With the above query, if i remove the where condition, am able to achieve what i want, but problem is i also want to return related rows from LeaveApplication only if ApplicationDate is in the current year. Now with the where condition added, am only able to get rows from EmployeeInfo only if they have corresponding rows in LeaveApplications yet i just wanted rows all in EmployeeInfo

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  • PostgreSQL - select only when specific multiple apperance in column

    - by Horse SMith
    I'm using PostgreSQL. I have a table with 3 fields person, recipe and ingredient person = creator of the recipe recipe = the recipe ingredient = one of the ingredients in the recipe I want to create a query which results in every person who whenever has added carrot to a recipe, the person must also have added salt to the same recipe. More than one person can have created the recipe, in which case the person who added the ingredient will be credited for adding the ingredient. Sometimes the ingredient is used more than once, even by the same person. If this the table: person1, rec1, carrot person1, rec1, salt person1, rec1, salt person1, rec2, salt person1, rec2, pepper person2, rec1, carrot person2, rec1, salt person2, rec2, carrot person2, rec2, pepper person3, rec1, sugar person3, rec1, carrot Then I want this result: person1 Because this person is the only one who whenever has added carrot also have added salt.

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  • tinyMce reloading data with html tags

    - by Arunraj Chandran
    I'm having issue with TinyMCE. After saving the contents of the editor and redisplaying it all the HTML tags are visible. This is how I'm initializing the editor: // Tinymce Config tinyMCE.init({ // General options mode : "specific_textareas", editor_selector : "mceEditor", language : "<?php echo $tinyMceLang?>", setup : function(ed) { ed.onActivate.add(tinyOnEdit); }, theme : "advanced", plugins : "table", // Theme options theme_advanced_buttons1 : "bold,italic,underline,strikethrough,|,justifyleft,justifycenter,justifyright,justifyfull,fontsizeselect,|,forecolor,backcolor,|,table,row_before,row_after,delete_row,col_before,col_after,delete_col,code", theme_advanced_buttons2 : "", theme_advanced_buttons3 : "", theme_advanced_buttons4 : "", theme_advanced_toolbar_location : "top", theme_advanced_toolbar_align : "left", theme_advanced_statusbar_location : "bottom", theme_advanced_path : false, theme_advanced_resizing : true, convert_fonts_to_spans : true, //font_size_style_values : "0.7em,0.8em,1em,1.2em,1.5em,2em,3em", //font_size_style_values : "8pt,10pt,12pt,14pt,18pt,24pt,36pt", // content CSS (should be your site CSS) content_css : "/css/tiny_content.css" }); if i paste a content like this (With HTML tags): "testing tinymce contents" redisplayed as : "testing tinymce contents" but excepted result is : testing tinymce contents (Text with red color)(Not allowing html tags)

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  • Is it ok to hardcode dynamic links in a permanent view?

    - by meder
    Let's say I wanted to showcase 2-3 clickable buttons on my homepage which will be there permanently. These are links to the css, html, and javascript tag listing pages. Is it fine to just hardcode href=/tags/css and href=/tags/html right in my django templates/view? I won't change them for at least a year or so, meaning I don't think I need to add a column to the tags table to distinguish them - is this common or should I try to make it somewhat dynamic? These tags are in a table but so are 1000 other tags.

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  • Select latest group by in nhibernate

    - by Kendrick
    I have Canine and CanineHandler objects in my application. The CanineHandler object has a PersonID (which references a completely different database), an EffectiveDate (which specifies when a handler started with the canine), and a FK reference to the Canine (CanineID). Given a specific PersonID, I want to find all canines they're currently responsible for. The (simplified) query I'd use in SQL would be: Select Canine.* from Canine inner join CanineHandler on(CanineHandler.CanineID=Canine.CanineID) inner join (select CanineID,Max(EffectiveDate) MaxEffectiveDate from caninehandler group by CanineID) as CurrentHandler on(CurrentHandler.CanineID=CanineHandler.CanineID and CurrentHandler.MaxEffectiveDate=CanineHandler.EffectiveDate) where CanineHandler.HandlerPersonID=@PersonID Edit: Added mapping files below: <class name="CanineHandler" table="CanineHandler" schema="dbo"> <id name="CanineHandlerID" type="Int32"> <generator class="identity" /> </id> <property name="EffectiveDate" type="DateTime" precision="16" not-null="true" /> <property name="HandlerPersonID" type="Int64" precision="19" not-null="true" /> <many-to-one name="Canine" class="Canine" column="CanineID" not-null="true" access="field.camelcase-underscore" /> </class> <class name="Canine" table="Canine"> <id name="CanineID" type="Int32"> <generator class="identity" /> </id> <property name="Name" type="String" length="64" not-null="true" /> ... <set name="CanineHandlers" table="CanineHandler" inverse="true" order-by="EffectiveDate desc" cascade="save-update" access="field.camelcase-underscore"> <key column="CanineID" /> <one-to-many class="CanineHandler" /> </set> <property name="IsDeleted" type="Boolean" not-null="true" /> </class> I haven't tried yet, but I'm guessing I could do this in HQL. I haven't had to write anything in HQL yet, so I'll have to tackle that eventually anyway, but my question is whether/how I can do this sub-query with the criterion/subqueries objects. I got as far as creating the following detached criteria: DetachedCriteria effectiveHandlers = DetachedCriteria.For<Canine>() .SetProjection(Projections.ProjectionList() .Add(Projections.Max("EffectiveDate"),"MaxEffectiveDate") .Add(Projections.GroupProperty("CanineID"),"handledCanineID") ); but I can't figure out how to do the inner join. If I do this: Session.CreateCriteria<Canine>() .CreateCriteria("CanineHandler", "handler", NHibernate.SqlCommand.JoinType.InnerJoin) .List<Canine>(); I get an error "could not resolve property: CanineHandler of: OPS.CanineApp.Model.Canine". Obviously I'm missing something(s) but from the documentation I got the impression that should return a list of Canines that have handlers (possibly with duplicates). Until I can make this work, adding the subquery isn't going to work... I've found similar questions, such as http://stackoverflow.com/questions/747382/only-get-latest-results-using-nhibernate but none of the answers really seem to apply with the kind of direct result I'm looking for. Any help or suggestion is greatly appreciated.

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