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  • Binary serialization and deserialization without creating files (via strings)

    - by the_V
    Hi, I'm trying to create a class that will contain functions for serializing/deserializing objects to/from string. That's what it looks like now: public class BinarySerialization { public static string SerializeObject(object o) { string result = ""; if ((o.GetType().Attributes & TypeAttributes.Serializable) == TypeAttributes.Serializable) { BinaryFormatter f = new BinaryFormatter(); using (MemoryStream str = new MemoryStream()) { f.Serialize(str, o); str.Position = 0; StreamReader reader = new StreamReader(str); result = reader.ReadToEnd(); } } return result; } public static object DeserializeObject(string str) { object result = null; byte[] bytes = System.Text.Encoding.ASCII.GetBytes(str); using (MemoryStream stream = new MemoryStream(bytes)) { BinaryFormatter bf = new BinaryFormatter(); result = bf.Deserialize(stream); } return result; } } SerializeObject method works well, but DeserializeObject does not. I always get an exception with message "End of Stream encountered before parsing was completed". What may be wrong here?

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  • Listening Port Permanently. if file is on my stream, Get file. How to?

    - by Phsika
    i writed 2 client and server program. client dend file also server listen port and than get file.But i need My server App must listen on 51124 port permanently. if any file on my stream, show my message "there is a file on your stream" and than show me savefile dialog. But my server app in "Infinite loop". 1) listen 51124 port every time 2) do i have a file on my stream, show me a messagebox. private void Form1_Load(object sender, EventArgs e) { TcpListener Dinle = new TcpListener(51124); try { Dinle.Start(); Socket Baglanti = Dinle.AcceptSocket(); if (!Baglanti.Connected) { MessageBox.Show("No Connection!"); } else { while (true) { byte[] Dizi = new byte[250000]; Baglanti.Receive(Dizi, Dizi.Length, 0); string Yol; saveFileDialog1.Title = "Save File"; saveFileDialog1.ShowDialog(); Yol = saveFileDialog1.FileName; FileStream Dosya = new FileStream(Yol, FileMode.Create); Dosya.Write(Dizi, 0, Dizi.Length - 20); Dosya.Close(); listBox1.Items.Add("dosya indirildi"); listBox1.Items.Add("Dosya Boyutu=" + Dizi.Length.ToString()); listBox1.Items.Add("Indirilme Tarihi=" + DateTime.Now); listBox1.Items.Add("--------------------------------"); } } } catch (Exception) { throw; } } My Algorithm: if(AnyFileonStream()==true) { GetFile() //Also continue to listening 51124 port... } How can i do that?

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  • Consuming a WCF Service

    - by Lijo
    Hi I created a WCF service which is hosted in windows service. I created a proxy using svcutil “svcutil.exe http://localhost:8000/ServiceModelSamples/FreeServiceWorld?wsdl” It generated an output.config file and proxy class. The output.config has the following element <client> <endpoint address="http://localhost:8000/ServiceModelSamples/FreeServiceWorld" binding="wsHttpBinding" bindingConfiguration="WSHttpBinding_IWeather" contract="IWeather" name="WSHttpBinding_IWeather"> <identity> <servicePrincipalName value="host/D471DTRV.ustr.com" /> </identity> </endpoint> </client> I created a website (as client) and added a new C# file (MyFile.cs) into it. I copied the contents of the proxy class into MyFile.cs. [The output.config is not copied to the web site] In the code behnid of aspx, I am using the following code WeatherClient client= new WeatherClient("WSHttpBinding_IWeather"); It throws an exception as “Could not find endpoint element with name 'WSHttpBinding_IWeather' and contract 'IWeather' in the ServiceModel client configuration section.” Could you please help me to understand the missing link here? Thanks Lijo

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  • Android: sending xml as document object, POST method

    - by juro
    i am new at programming and i need some help with that please =/ web service is already written but not by me. so all i have to do is send xml as document object by post method through web service. my code: public class send extends application { @Override public void onCreate(Bundle icicle) { super.onCreate(icicle); HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://app.local/test/"); try { DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder(); Document document = documentBuilder.newDocument(); Element rootElement = document.createElement("packet"); rootElement.setAttribute("version", "1.2"); document.appendChild(rootElement); Element em = document.createElement("imei"); em.appendChild(document.createTextNode("000000000000000")); rootElement.appendChild(em); em = document.createElement("username"); em.appendChild(document.createTextNode("5555")); rootElement.appendChild(em); HttpResponse response = httpclient.execute(httppost); } catch (Exception e) { System.out.println("XML Pasing Excpetion = " + e); } } }

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  • guide for creating addins for Visual Studio 2010?

    - by JMarsch
    Hello: 2 questions actuall: Is there a good comprensive guide out there for creating add-ins for Visual Studio? Here's a weird specific problem -- I'm trying to get my add-in to load. The code that the wizard stubs into the OnConnect method will add it to the toolbar, but only if it passes this "if" statement: if (connectMode == ext_ConnectMode.ext_cm_UISetup) The problem is that connectMode never seems to equal ext_cm_UISetup. It always seems to equal ext_cm_AfterStartup, and My AddIn never appears on the toolbar. I could cheat and short-circuit the if, but since Visual Studio put that code there, I bet it's right, and I have something else wrong. According to the docs, the value should only ever be ext_cm_UISetup once -- the first time VS encounters the addin. So I probably need to somehow make VS forget about the add-in, but I can't find anywhere to do that. And by the way, isn't that exceptionally delicate? The reason I'm in this pickle is because I happened to get an exception on the first try, so now I can never try again?? Can't be right.

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  • How to rename an private file of my application?

    - by Ungureanu Liviu
    Hi! I want to rename an context private file created with openFileOutput() but I don't know how... I tried that: File file = getFileStreamPath(optionsMenuView.getPlaylistName()); // this file already exists try { FileOutputStream outStream = openFileOutput(newPlaylistName, Context.MODE_WORLD_READABLE); // i create a new file with the new name outStream.close(); } catch (FileNotFoundException e) { Log.e(TAG, "file not found!"); e.printStackTrace(); } catch (IOException e) { Log.e(TAG, "IO exception"); e.printStackTrace(); } Log.e(TAG, "rename status: " + file.renameTo(getFileStreamPath(newPlaylistName))); //it return true This code throw FileNotFoundException but the documentation said "Open a private file associated with this Context's application package for writing. Creates the file if it doesn't already exist." so the new file should be created on disk. The problem: When I try to read from the new renamed file I got FileNotFoundException! Thank you!

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  • Ftp throws WebException only in .NET 4.0

    - by Trakhan
    I have following c# code. It runs just fine when compiled against .NET framework 3.5 or 2.0 (I did not test it against 3.0, but it will most likely work too). The problem is, that it fails when built against .NET framework 4.0. FtpWebRequest Ftp = (FtpWebRequest)FtpWebRequest.Create(Url_ + '/' + e.Name); Ftp.Method = WebRequestMethods.Ftp.UploadFile; Ftp.Credentials = new NetworkCredential(Login_, Password_); Ftp.UseBinary = true; Ftp.KeepAlive = false; Ftp.UsePassive = true; Stream S = Ftp.GetRequestStream(); byte[] Content = null; bool Continue = false; do { try { Continue = false; Content = File.ReadAllBytes(e.FullPath); } catch (Exception) { Continue = true; System.Threading.Thread.Sleep(500); } } while (Continue); S.Write(Content, 0, Content.Length); S.Close(); FtpWebResponse Resp = (FtpWebResponse)Ftp.GetResponse(); if (Resp.StatusCode != FtpStatusCode.CommandOK) Console.WriteLine(Resp.StatusDescription); The problem is in call Stream S = Ftp.GetRequestStream();, which throws an en instance of WebException with message “The remote server returned an error: (500) Syntax error, command unrecognized”. Does anybody know why it is so? PS. I communicate virtual ftp server in ECM Alfresco.

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  • how to show all added items into another activity, like: AddtoCart and ViewCart Functionality

    - by Stanley
    i am trying to make a shopping cart app, allowing user to choose category then select item to purchase, once user will click on any item to purchase, then showing that selected item into another activity with item image, name, cost, qty (to accept by user) and also providing add to cart functionality, now i want whenever user will click on Add to Cart button, then selected item need to show in ViewCart Activity, so here i am placing my AddtoCart Activity code, please tell me what i need to write to show added item(s) into ViewCart Category just like in shopping cart, In ViewCart activity i just want to show item title, cost and qty (entered by user):- public class AddtoCart extends Activity{ static final String KEY_TITLE = "title"; static final String KEY_COST = "cost"; static final String KEY_THUMB_URL = "imageUri"; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.single); Intent in = getIntent(); String title = in.getStringExtra(KEY_TITLE); String thumb_url = in.getStringExtra(KEY_THUMB_URL); String cost = in.getStringExtra(KEY_COST); ImageLoader imageLoader = new ImageLoader(getApplicationContext()); ImageView imgv = (ImageView) findViewById(R.id.single_thumb); TextView txttitle = (TextView) findViewById(R.id.single_title); TextView txtcost = (TextView) findViewById(R.id.single_cost); txttitle.setText(title); txtcost.setText(cost); imageLoader.DisplayImage(thumb_url, imgv); // Save a reference to the quantity edit text final EditText editTextQuantity = (EditText) findViewById(R.id.edit_qty); ImageButton addToCartButton = (ImageButton) findViewById(R.id.img_add); addToCartButton.setOnClickListener(new OnClickListener() { public void onClick(View v) { // Check to see that a valid quantity was entered int quantity = 0; try { quantity = Integer.parseInt(editTextQuantity.getText() .toString()); if (quantity <= 0) { Toast.makeText(getBaseContext(), "Please enter a quantity of 1 or higher", Toast.LENGTH_SHORT).show(); return; } } catch (Exception e) { Toast.makeText(getBaseContext(), "Please enter a numeric quantity", Toast.LENGTH_SHORT).show(); return; } // Close the activity finish(); } }); }}

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  • Data confusion - Selecting data in one DataGridView based on selection in another

    - by Logan Young
    This probably isn't the best way to do what I want, but I can't think of anything else to try... NB: I'm using Visual Basic.NET My form has 2 DataGridView controls. One of these is bound to a DataSet, the other isn't visible - at least not until the user selects a uniqueidentifier cell in the 1st grid. When the user makes this selection, the 2nd grid will become visible and display the row from another with the same id as the one selected in the 1st grid. So, basically, I want to dynamically display data in one grid based on user selection in another grid. My code looks like this so far... Private Sub RulesGrid_CellClick(ByVal sender As System.Object, ByVal e As System.Windows.Forms.DataGridViewCellEventArgs) Handles RulesGrid.CellClick Try FlagsGrid.Visible = True ''// MsgBox(RulesGrid.CurrentCell.Value.ToString()) Dim sql As String = "SELECT * FROM ctblMKA_Status_Flags " + _ "WHERE intStatusID = '" & RulesGrid.CurrentCell.Value & "'" DSFlags = GetDS(sql) DSFlags.DataSetName = "FlagsDataSet" FlagsGrid.DataSource = DSFlags ProgressBar.Visible = False Catch ex As Exception MsgBox(ex.ToString) End Try End Sub I feel like I'm missing something here... Any ideas anyone?

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  • Works on emulator but not on device

    - by Klaus
    Hello Community, I have an inner handler class that calls the method sendMessage. sendMessige is outside the handler class, but inside the conatining Android java class. On the emulator (AVD 2.2) it works fine, but on my Android 2.2 device the method sendMessage is not called at all. Inner handler class: private Handler handler2 = new Handler() { public void handleMessage(Message msg) { if (GeoSetting.equals("s") && (inNumber.equals(definedNumber))) **SendService.this.sendMessage(definedNumber, DisplayLoc)**; if (GeoSetting.equals("a")) **SendService.this.sendMessage(inNumber, DisplayLoc)**; stopService(new Intent(getApplicationContext(), GeoService.class)); }; The method that should be called: private void sendMessage(String sendNumber, String sendText){ Toast.makeText(getApplicationContext(), "done!!!", Toast.LENGTH_LONG).show(); SmsManager sms = SmsManager.getDefault(); try { sms.sendTextMessage(sendNumber, null, sendText, null, null); if (Message == true) {Toast.makeText(getApplicationContext(), "Sending SMS to "+sendNumber+": "+sendText, Toast.LENGTH_LONG).show();} } catch (Exception exeption){ Toast.makeText(getApplicationContext(), "Something is wrong, could not send SMS!", Toast.LENGTH_LONG).show(); } Toast.makeText(getApplicationContext(), "method called!", Toast.LENGTH_LONG).show(); } Does anybody have an idea why sendMessage is not called on the real device? Thank you for the help!

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  • load data from grid row into (pop up) form for editing

    - by user1495457
    I read in Ext JS in Action ( by J. Garcia) that if we have an instance of Ext.data.Record, we can use the form's loadRecord method to set the form's values. However, he does not give a working example of this (in the example that he uses data is loaded into a form through a file called data.php). I have searched many forums and found the following entry helpful as it gave me an idea on how to solve my problem by using form's loadRecord method: load data from grid to form Now the code for my store and grid is as follows: var userstore = Ext.create('Ext.data.Store', { storeId: 'viewUsersStore', model: 'Configs', autoLoad: true, proxy: { type: 'ajax', url: '/user/getuserviewdata.castle', reader: { type: 'json', root: 'users' }, listeners: { exception: function (proxy, response, operation, eOpts) { Ext.MessageBox.alert("Error", "Session has timed-out. Please re-login and try again."); } } } }); var grid = Ext.create('Ext.grid.Panel', { id: 'viewUsersGrid', title: 'List of all users', store: Ext.data.StoreManager.lookup('viewUsersStore'), columns: [ { header: 'Username', dataIndex: 'username' }, { header: 'Full Name', dataIndex: 'fullName' }, { header: 'Company', dataIndex: 'companyName' }, { header: 'Latest Time Login', dataIndex: 'lastLogin' }, { header: 'Current Status', dataIndex: 'status' }, { header: 'Edit', menuDisabled: true, sortable: false, xtype: 'actioncolumn', width: 50, items: [{ icon: '../../../Content/ext/img/icons/fam/user_edit.png', tooltip: 'Edit user', handler: function (grid, rowIndex, colIndex) { var rec = userstore.getAt(rowIndex); alert("Edit " + rec.get('username')+ "?"); EditUser(rec.get('id')); } }] }, ] }); function EditUser(id) { //I think I need to have this code here - I don't think it's complete/correct though var formpanel = Ext.getCmp('CreateUserForm'); formpanel.getForm().loadRecord(rec); } 'CreateUserForm' is the ID of a form that already exists and which should appear when user clicks on Edit icon. That pop-up form should then automatically be populated with the correct data from the grid row. However my code is not working. I get an error at the line 'formpanel.getForm().loadRecord(rec)' - it says 'Microsoft JScript runtime error: 'undefined' is null or not an object'. Any tips on how to solve this?

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  • ArgumentOutOfRangeException was unhandled by user code - (ASP .net)

    - by ASr..
    I use a GridView to display the records from the database. Also i've attached a Hyperlink to the GridView using TemplateField. When I try to add "onclick" attribute to the HyperLink inside the RowDateBound event, I get the following error.. GridView1.DataKeys[e.Row.RowIndex].Value = 'GridView1.DataKeys[e.Row.RowIndex]' threw an exception of type 'System.ArgumentOutOfRangeException' Message = "Index was out of range. Must be non-negative and less than the size of the collection.\r\nParameter name: index" This is the coding inside the RowDataBound mentod.. protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e) { if (e.Row.RowType == DataControlRowType.DataRow) { HyperLink HyperLink1 = (HyperLink)e.Row.FindControl("HyperLink1"); //The following line makes the error HyperLink1.Attributes.Add("onclick", "ShowMyModalPopup('" + GridView1.DataKeys[e.Row.RowIndex].Value + "')"); } } This is "ShowMyModalPopup" function in javascript <script type="text/javascript"> function ShowMyModalPopup(userpk) { var modal = $find('ModalPopupExtender1'); modal.show(); WebService.FetchOneUser(userpk,DisplayResult); } </script> Can anyone please explain me why this error occurs.. Many thanks in advance..

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  • How to convert "0" and "1" to false and true

    - by Chris
    I have a method which is connecting to a database via Odbc. The stored procedure which I'm calling has a return value which from the database side is a 'Char'. Right now I'm grabbing that return value as a string and using it in a simple if statement. I really don't like the idea of comparing a string like this when only two values can come back from the database, 0 and 1. OdbcCommand fetchCommand = new OdbcCommand(storedProc, conn); fetchCommand.CommandType = CommandType.StoredProcedure; fetchCommand.Parameters.AddWithValue("@column ", myCustomParameter); fetchCommand.Parameters.Add("@myReturnValue", OdbcType.Char, 1). Direction = ParameterDirection.Output; fetchCommand.ExecuteNonQuery(); string returnValue = fetchCommand.Parameters["@myReturnValue"].Value.ToString(); if (returnValue == "1") { return true; } What would be the proper way to handle this situation. I've tried 'Convert.ToBoolean()' which seemed like the obvious answer but I ran into the 'String was not recognized as a valid Boolean. ' exception being thrown. Am I missing something here, or is there another way to make '1' and '0' act like true and false? Thanks!

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  • Iphone Core Data Internal Inconsistency

    - by kiyoshi
    This question has something to do with the question I posted here: http://stackoverflow.com/questions/1230858/iphone-core-data-crashing-on-save however the error is different so I am making a new question. Now I get this error when trying to insert new objects into my managedObjectContext: *** Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: '"MailMessage" is not a subclass of NSManagedObject.' But clearly it is: @interface MailMessage : NSManagedObject { .... And when I run this code: NSManagedObjectModel *managedObjectModel = [[self.managedObjectContext persistentStoreCoordinator] managedObjectModel]; NSEntityDescription *entity =[[managedObjectModel entitiesByName] objectForKey:@"MailMessage"]; NSManagedObject *newObject = [[NSManagedObject alloc] initWithEntity:entity insertIntoManagedObjectContext:self.managedObjectContext]; It runs fine when I do not present an MFMailComposeViewController, but if I run this code in the - (void)mailComposeController:(MFMailComposeViewController*)controller didFinishWithResult:(MFMailComposeResult)result error:(NSError*)error { method, it throws the above error when creating the newObject variable. The entity object when I use print object produces the following: (<NSEntityDescription: 0x1202e0>) name MailMessage, managedObjectClassName MailMessage, renamingIdentifier MailMessage, isAbstract 0, superentity name (null), properties { in both cases, so I don't think the managedObjectContext is completely invalid. I have no idea why it would say MailMessage is not a subclass of NSManagedObject at that point, and not at the other. Any help would be appreciated, thanks in advance.

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  • Trouble accessing fields of a serialized object in Java

    - by typoknig
    I have instantized a class that implements Serializable and I am trying to stream that object like this: try{ Socket socket = new Socket("localhost", 8000); ObjectOutputStream toServer = new ObjectOutputStream(socket.getOutputStream()); toServer.writeObject(myObject); } catch (IOException ex) { System.err.println(ex); } All good so far right? Then I am trying to read the fields of that object like this: //This is an inner class class HandleClient implements Runnable{ private ObjectInputStream fromClient; private Socket socket; // This socket was established earlier try { fromClient = new ObjectInputStream(socket.getInputStream()); GetField inputObjectFields = fromClient.readFields(); double myFristVariable = inputObjectFields.get("myFirstVariable", 0); int mySecondVariable = inputObjectFields.get("mySecondVariable", 0); //do stuff } catch (IOException ex) { System.err.println(ex); } catch (ClassNotFoundException ex) { System.err.println(ex); } finally { try { fromClient.close(); } catch (Exception ex) { ex.printStackTrace(); } } } But I always get the error: java.io.NotActiveException: not in call to readObject This is my first time streaming objects instead of primitive data types, what am I doing wrong? BONUS When I do get this working correctly, is the ENTIRE CLASS passed with the serialized object (i.e. will I have access to the methods of the object's class)? My reading suggests that the entire class is passed with the object, but I have been unable to use the objects methods thus far. How exactly do I call on the object's methods? In addition to my code above I also experimented with the readObject method, but I was probably using it wrong too because I couldn't get it to work. Please enlighten me.

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  • Timer in java ,time difference problem

    - by javatechi
    I want to create a timer for my app. The sample code is shown below. When the method datetwo() is called the same time in milliseconds is shown as there in the main method. Please help me out with this import java.util.Date; import java.util.Timer; public class TimerChe { Timer timer; static Date date = new Date(); static Date date2 = new Date(); public static void timerMethod(){ new Thread() { public void run() { try { while (true) { sleep(10000); datetwo(); } } catch (InterruptedException ex) { } } }.start(); } public static void datetwo() { System.out.println ("OK, It's time to do something!") ; System.out.println("The Time is " + date2.getTime() + " milliseconds since 1970/01/01"); } public static void main(String args[]) throws Exception { System.out.println("The Time is " + date.getTime() + " milliseconds since 1970/01/01" ); System.out.println ("Schedule something to do in the mean time.") ; timerMethod(); } }

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  • Using linq2xml to query a single item deep within

    - by BrettRobi
    I'm wondering if there is a robust and graceful way using linq2xml to query an item deep within an xml hierarchy. For example: <?xml version="1.0" encoding="utf-8" ?> <data> <core id="01234"> <field1>some data</field1> <field2>more data</field2> <metadata> <response> <status code="0">Success</status> <content> <job>f1b5c3f8-e6b1-4ae4-905a-a7c5de3f13c6</job> <id>id of the content</id> </content> </response> </metadata> </core> </data> With this xml how do I query the value of without using something like this: var doc = XElement.Load("file.xml"); string id = (string)doc.Element("core") .Element("metadata") .Element("response") .Element("content") .Element("id"); I don't like the above approach because it is error prone (throws exception if any tag is missing in the hierarchy) and honestly ugly. Is there a more robust and graceful approach, perhaps using the sql-like syntax of linq?

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  • Get parent attribute within new child form?

    - by dannymcc
    I have a simple Rails 3 application and I am trying to create a new record that belongs to it's owner. It's working by passing the id to a hidden field in the new form of the child record. This works well and once the new child form submitted it correctly gets associated in the child/parent relationship. What I am trying to do, is lookup values form the parent within the new child form. The problem is that the child relationship is not yet created. Is there anyway I can use a .where lookup in the view? Or, is there a better way of doing this? At the moment I am passing the animal_id though to the new Claim form and it's inserted into a hidden field labelled animal_id. What I am trying to do: <%= @animal.where(:animal_id => params[:animal_id]).id %> The above would ideally get the animal ID from the soon-to-be-associated animal. Is there any sort of before_filter or anything that could take the passed params from the URL and temporarily create the relationship just for the new form view and then permanently create the relationship once the form is submitted? I've tried adding the following to my Claims controller and then called @animal.AnimalName in the view but I get NoMethodError: before_filter :find_animal protected def find_animal if params[:animal_id] Animal.find(params[:animal_id]) end end The URL of the new claim is correctly showing the animal ID so I'm not sure why it's not finding it: http://localhost:3000/claims/new?animal_id=1 The model relations are as follows: animal has_many claims animal has_one exclusion claim has_one animal exception has_one animal

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  • Java Applet 411 Content Length

    - by user1903006
    I am new to Java. I wrote an applet with a gui that sends results (int w and int p) to a server, and I get the "411 Length Required" error. What am I doing wrong? How do you set a Content-Length? This is the method that communicates with the server: public void sendPoints1(int w, int p){ try { String url = "http://somename.com:309/api/Results"; String charset = "UTF-8"; String query = String.format("?key=%s&value=%s", URLEncoder.encode(String.valueOf(w), charset), URLEncoder.encode(String.valueOf(p), charset)); String length = String.valueOf((url + query).getBytes("UTF-8").length); HttpURLConnection connection = (HttpURLConnection) new URL(url + query).openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Content-Length", length); connection.connect(); System.out.println("Responce Code: " + connection.getResponseCode()); System.out.println("Responce Message: " + connection.getResponseMessage()); } catch (Exception e) { System.err.println(e.getMessage()); } }

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  • Performance of stored proc when updating columns selectively based on parameters?

    - by kprobst
    I'm trying to figure out if this is relatively well-performing T-SQL (this is SQL Server 2008). I need to create a stored procedure that updates a table. The proc accepts as many parameters as there are columns in the table, and with the exception of the PK column, they all default to NULL. The body of the procedure looks like this: CREATE PROCEDURE proc_repo_update @object_id bigint ,@object_name varchar(50) = NULL ,@object_type char(2) = NULL ,@object_weight int = NULL ,@owner_id int = NULL -- ...etc AS BEGIN update object_repo set object_name = ISNULL(@object_name, object_name) ,object_type = ISNULL(@object_type, object_type) ,object_weight = ISNULL(@object_weight, object_weight) ,owner_id = ISNULL(@owner_id, owner_id) -- ...etc where object_id = @object_id return @@ROWCOUNT END So basically: Update a column only if its corresponding parameter was provided, and leave the rest alone. This works well enough, but as the ISNULL call will return the value of the column if the received parameter was null, will SQL Server optimize this somehow? This might be a performance bottleneck on the application where the table might be updated heavily (insertion will be uncommon so the performance there is not a problem). So I'm trying to figure out what's the best way to do this. Is there a way to condition the column expressions with something like CASE WHEN or something? The table will be indexed up the wazoo as well for read performance. Is this the best approach? My alternative at this point is to create the UPDATE expression in code (e.g. inline SQL) and execute it against the server. This would solve my doubts about performance, but I'd rather leave this in a stored proc if possible.

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  • how to add data in Table of Jasper Report using Java

    - by Areeb Gillani
    i am here to ask you just a simple question that i am trying to pass data to a jasper report using java but i dont know how to to, because the table data is very dynamic thats y cannot pass sql query. any idea for this. i have a 2D array of object type, where i have all the data... so how can i pass that... Thanx in advance...!:) ConnectionManager con = new ConnectionManager(); con.establishConnection(); String fileName = "Pmc_Bill.jrxml"; String outFileName = "OutputReport.pdf"; HashMap params = new HashMap(); params.put("PName", pname); params.put("PSerial", psrl); params.put("PGender",pgen); params.put("PPhone",pph); params.put("PAge",page); params.put("PRefer",pref); params.put("PDateR",dateNow); try { JasperReport jasperReport = JasperCompileManager.compileReport(fileName); if(jasperReport != null ) System.out.println("so far so good "); // Fill the report using an empty data source JasperPrint jasperPrint = JasperFillManager.fillReport(jasperReport, params, new JRTableModelDataSource(tbl.getModel()));//con.connection); try{ JasperExportManager.exportReportToPdfFile(jasperPrint, outFileName); System.out.printf("File exported sucessfully"); }catch(Exception e){ e.printStackTrace(); } JasperViewer.viewReport(jasperPrint); } catch (JRException e) { JOptionPane.showMessageDialog(null, e); e.printStackTrace(); System.exit(1); }

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  • How would I authenticate against a local windows user on another machine in an ASP.NET application?

    - by Daniel Chambers
    In my ASP.NET application, I need to be able to authenticate/authorise against local Windows users/groups (ie. not Active Directory) on a different machine, as well as be able to change the passwords of said remote local Windows accounts. Yes, I know Active Directory is built for this sort of thing, but unfortunately the higher ups have decreed it needs to be done this way (so authentication against users in a database is out as well). I've tried using DirectoryEntry and WinNT like so: DirectoryEntry user = new DirectoryEntry(String.Format("WinNT://{0}/{1},User", serverName, username), username, password, AuthenticationTypes.Secure) but this results in an exception when you try to log in more than one user: Multiple connections to a server or shared resource by the same user, using more than one user name, are not allowed. Disconnect all previous connections to the server or shared resource and try again. I've tried making sure my DirectoryEntries are used inside a using block, so they're disposed properly, but this doesn't seem to fix the issue. Plus, even if that did work it is possible that two users could hit that line of code concurrently and therefore try to create multiple connections, so it would be fragile anyway. Is there a better way to authenticate against local Windows accounts on a remote machine, authorise against their groups, and change their passwords? Thanks for your help in advance.

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  • Play playlist with MediaPlayer

    - by Kaloer
    Hi, I'm trying to play a playlist I get using the MediaStore provider. However, when I try playing a playlist nothing happens. Can a MediaPlayer play a playlist (m3u file) and do I need to set the first track to play ? This is my test code in the onCreate() method: Uri uri = MediaStore.Audio.Playlists.EXTERNAL_CONTENT_URI; if(uri == null) { Log.e("Uri = null"); } String[] projection = new String[] { MediaStore.Audio.Playlists._ID, MediaStore.Audio.Playlists.NAME, MediaStore.Audio.Playlists.DATA }; Cursor c = managedQuery(uri, projection, null, null, null); if(c == null) { Toast.makeText(getApplicationContext(), R.string.alarm_tone_picker_error, Toast.LENGTH_LONG).show(); return; } if(!c.moveToFirst()) { c.close(); Toast.makeText(getApplicationContext(), R.string.alarm_tone_picker_no_music, Toast.LENGTH_LONG).show(); return; } c.moveToFirst(); try { MediaPlayer player = new MediaPlayer(); player.setDataSource(c.getString(2)); player.start(); } catch(Exception e) { e.printStackTrace(); } I have turned on every volume stream. Thanks you, Kaloer

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  • Unable to write to a text file

    - by chrissygormley
    Hello, I am running some tests and need to write to a file. When I run the test's the open = (file, 'r+') does not write to the file. The test script is below: class GetDetailsIP(TestGet): def runTest(self): self.category = ['PTZ'] try: # This run's and return's a value result = self.client.service.Get(self.category) mylogfile = open("test.txt", "r+") print >>mylogfile, result result = ("".join(mylogfile.readlines()[2])) result = str(result.split(':')[1].lstrip("//").split("/")[0]) mylogfile.close() except suds.WebFault, e: assert False except Exception, e: pass finally: if 'result' in locals(): self.assertEquals(result, self.camera_ip) else: assert False When this test run's, no value has been entered into the text file and a value is returned in the variable result. I havw also tried mylogfile.write(result). If the file does not exist is claim's the file does not exist and doesn't create one. Could this be a permission problem where python is not allowed to create a file? I have made sure that all other read's to this file are closed so I the file should not be locked. Can anyone offer any suggestion why this is happening? Thanks

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  • Cannot connect to MySQL server using JSP

    - by Dibya
    I just set foot on JSP. I started writing simple programs to display dates, system info. Then I tried to connect a MySQL database I have a free hosting account, but I am not able to connect to MySQL database. Here is my code: <%@ page import="java.sql.*" %> <%@ page import="java.io.*" %>  <html> <head> <title>Connection with mysql database</title> </head> <body> <h1>Connection status</h1> <% try { String connectionURL = "jdbc:mysql://mysql2.000webhost.com/a3932573_product"; Connection connection = null; Class.forName("com.mysql.jdbc.Driver").newInstance(); connection = DriverManager.getConnection(connectionURL, "a3932573_dibya", "******"); if(!connection.isClosed()) out.println("Successfully connected to " + "MySQL server using TCP/IP..."); connection.close(); }catch(Exception ex){ out.println("Unable to connect to database."); } %> </font> </body> </html> I am getting Message as Connection Status unable to connect to database. I have tested this connection using PHP using the same username, password and database name. Where am I making mistake?

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