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  • access a property via string with array in php?

    - by sprugman
    (This is in drupal, but I don't really think that matters.) I have a big list of properties that I need to map between two objects, and in one, the value that I need to map is buried inside an array. I'm hoping to avoid hard-coding the property names in the code. If I have a class like this: class Product { public $colors, $sizes; } I can access the properties like this: $props = array('colors', 'sizes'); foreach ($props as $p) { $this->$p = $other_object->$p; } As far as I can tell, if each of the properties on the left are an array, I can't do this: foreach ($props as $p) { $this->$p[0]['value'] = $other_object->$p; } Is that correct, or am I missing some clever way around this?

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  • Writing To The Response in Rails? (Like "echo" in PHP)

    - by Yar
    I know that I can do this in Rails: <%="hello" %> but is there any way to do this <% echo "hello" %> and get it to show up in the response? I have tried response.write which almost worked, but did not... Edit: print or puts do not do it, because I do not want to write to the console. I want to write to the browser/HTTP client. Edit: Here is an example: <% unless @research_activities.size == 0 concat(render(:partial => 'list')) end %> Why would I want to include two closing tags just to do that? It reads nicely in code, doesn't it?

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  • PHP "header (location)" isnide IFRAME, to load in _top location?

    - by Spoonk
    Hi Webmasters. I have a simple form which is inside IFRAME. When user click on SUBMIT, it redirects to a specific page on my server. The function I use for the redirect is header ('Location: mypage2.html'); exit (); But I want the new page to open in _top location, not inside the same IFRAME that I use. How can I tell the browser to open the new page in _top not inside the IFRAME? Thanks in advance.

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  • PHP SQL, SELECT corresponding data from 3 tables at once?

    - by user346325
    I have 3 tables, 'u' 'd' 's' 'u' has userid divid 'd' has divid divname 's' has sname primaryuserid secondaryuserid Now what I'd like to do is display a table with rows of the following format userid, divname, sname Plus figure out a way to decipher whether userid is a primary or secondary for this sname table. I'm able to show userid and divname using a left join, but I don't know how I would add a third table? To make it trickier, there can be more than 1 snames for each userid, up to ~20. Is there a way to display 0-20 snames depending on the userid, seperated with commas?

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  • PHP Passing Data to a Specific Class? (Data Encapsulation)

    - by Adam184
    I've learned that OOP is all about data encapsulation, but what about passing data between classes that have nothing to do with each other (would the below example be worthy of using extends)? class Dog { private $secretVar; public function getSecretVar() { $this->secretVar = 'psst... only for rainbow!'; return $this->secretVar; } } class Rainbow { public function __construct(Dog $Dog) { print_r($Dog->getSecretVar()); } } $Dog = new Dog(); $Rainbow = new Rainbow($Dog); // ... classes that don't need the $secretVar How would you encapsulate $secretVar for only classes Dog and Rainbow? As of now, anyone can call getSecretVar(), and I'm having a hard time allowing that to happen as it seems to defeat the whole point of encapsulation.

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  • How to get the value of an attribute from XML file in PHP?

    - by Matt
    Hi, Sorry if this seems like an easy question, but I've started pulling hair out on this... I have a XML file which looks like this... <VAR VarNum="90"> <option>1</option> </VAR> I'm trying to get the VarNum. So far I've been successful using the follow code to get the other information: $xml=simplexml_load_file($file); $option=$xml->option; I just can't get VarNum (the attribute value I think?) Thanks!

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  • SQL & PHP - Which is faster mysql_num_rows() or 'select count()'?

    - by Joel
    I'm just wondering which method is the most effective if I'm literally just wanting to get the number of rows in a table. $res = mysql_query("SELECT count(*) as `number` FROM `table1`"); $count = mysql_fetch_result($res,0,'number'); or $res = mysql_query("SELECT `ID` FROM `table1`"); $count = mysql_num_rows($res); Anyone done any decent testing on this?

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  • Desperate help using PHP's $_SERVER["DOCUMENT_ROOT"] on a web server?

    - by Nickersoft
    I've spent the past few months building a website on localhost. Throughout the site, instead of using relative paths, I used $_SERVER["DOCUMENT_ROOT"] to access the root of my server so I could reference files from there. However, I just decided to upload my site to 000webhost. As I soon found out, and for those of you who use them, you are probably aware, that their server root is different than your actual directory in which you upload your files. I believe it's virtual hosting... anyway, my $_SERVER["DOCUMENT_ROOT"] now throws errors along the lines of this on the site: Warning: include_once() [function.include-once]: open_basedir restriction in effect. File(/usr/local/apache/htdocs/mypath) is not within the allowed path(s) Every other site I looked at said that you should just replace $_SERVER["DOCUMENT_ROOT"] with the home directory provided to you by 000webhost. However, if I want to change hosting services in the future, I'm screwed. Is there any way to use $_SERVER to access a set virtual directory or use htaccess or something to make my code work? I tried using DocumentRoot in a htaccess file in my root directory, but it threw a 404 error when trying to access the page. I'm in desperate need... can anyone help me?

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  • Mac Text Editor (with function list)

    - by Meep3D
    So I've got a Mac in the post coming to me, and will probably be doing quite a bit of development on it so I am looking for a text editor (PHP + HTML mainly). I curently use Notepad++ on Windows and I simply cannot live without the function list plugin (It displays all functions in the current PHP file in a box on the right). Do any Mac text editors have this functionality? I am fairly sure that Notepad++ isn't available on an Apple. Thanks!

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