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• C++ boost function overloaded template

  - by aaa

  I cannot figure out why this segment gives unresolved overloaded function error (gcc version 4.3.4 (Debian 4.3.4-6)): #include <algorithm> #include <boost/function.hpp> int main { typedef boost::function2<const int&, const int&, const int&> max; max m(static_cast<max>(&std::max<int>)); } can you help me, thanks

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• Call c++ function pointer from c#

  - by Sam

  Is it possible to call a c(++) static function pointer like this typedef int (*MyCppFunc)(void* SomeObject); from c#? void CallFromCSharp(MyCppFunc funcptr, IntPtr param) { funcptr(param); } I need to be able to callback from c# into some old c++ classes. C++ is managed, but the classes are not ref classes (yet). So far I got no idea how to call a c++ function pointer from c#, is it possible?

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• Arguments to JavaScript Anonymous Function

  - by Phonethics

  for (var i = 0; i < somearray.length; i++) { myclass.foo({'arg1':somearray[i][0]}, function() { console.log(somearray[i][0]); }); } How do I pass somearray or one of its indexes into the anonymous function ? somearray is already in the global scope, but I still get somearray[i] is undefined

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• c++ Function pointer inlining

  - by wb

  I know I can pass a function pointer as a template parameter and get a call to it inlined but I wondered if any compilers these days can inline an 'obvious' inline-able function like: inline static void Print() { std::cout << "Hello\n"; } .... void (*func)() = Print; func(); Under Visual Studio 2008 its clever enough to get it down to a direct call instruction so it seems a shame it can't take it a step further?

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• TSQL, Rename column of a returning table in user Function

  - by user1433660

  I have defined function which returns table with 2 columns. Can I rename these columns so that resulting table would be like: Press name | Sum of pages ? CREATE FUNCTION F_3 (@press nvarchar(255)) RETURNS @table TABLE ( Press nvarchar(255), PagesSum int ) AS BEGIN INSERT @table SELECT @press, SUM(Books.Pages) FROM Books, Press WHERE Press.Name = @press AND Books.Id_Press = Press.Id GROUP BY Press.Name RETURN END GO SELECT * FROM F_3('BHV') GO I've tried to do it like Press AS 'Press name' nvarchar(255) but that won't work.

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• Passing template into boost function

  - by Ockonal

  template <class EventType> class IEvent; class IEventable; typedef boost::function<void (IEventable&, IEvent&)> behaviorRef; What is the right way for passing template class IEvent into boost function? With this code I get: error: functional cast expression list treated as compound expression error: template argument 1 is invalid error: invalid type in declaration before ‘;’ token

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• function of random in perl

  - by stordi

  what is the function of random in perl . can you give me a example of this function . thanks

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• How To Run A Shell Script Again And Again Having X Interval Of Time?

  - by Muhammad Hassan

  I have a shell script in my Ubuntu Server 14.04 LTS at ./ShellScript.sh. I setup /etc/rc.local to run the shell script after boot but before login using below code. Run this: sudo nano /etc/rc.local then add following and save. #!/bin/sh -e # # rc.local # # This script is executed at the end of each multiuser runlevel. # Make sure that the script will "exit 0" on success or any other # value on error. # # In order to enable or disable this script just change the execution # bits. # # By default this script does nothing. #!/bin/bash ./ShellScript.sh exit 0 Now I want to run/execute this shell script again and again having 15min of time interval between every run after boot but before login. So Can I do it? Update 1:) When I run crontab -e then I got the following. Now What to do? no crontab for root - using an empty one Select an editor. To change later, run 'select-editor'. 1. /bin/ed 2. /bin/nano <---- easiest 3. /usr/bin/vim.basic 4. /usr/bin/vim.tiny Choose 1-4 [2]: After selecting 2, I got crontab: "/usr/bin/sensible-editor" exited with status 2 UPDATE 2:) Update ShellScript.sh like below... #!/bin/bash # Testing ShellScript... while true do echo "ShellScript Start Running..." ********************************** All My Shell Script Codes/Script/Commands ********************************** echo "ShellScript End Running..." exit 0 sleep 900 done Then Run this: sudo nano /etc/rc.local then add following and save. #!/bin/sh -e # # rc.local # # This script is executed at the end of each multiuser runlevel. # Make sure that the script will "exit 0" on success or any other # value on error. # # In order to enable or disable this script just change the execution # bits. # # By default this script does nothing. sh ./ShellScript.sh & exit 0

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• First 10 programs in a new scripting languge

  - by pro_metedor

  When a peron is learning a new scripting language like: bash python perl pike What kind of simple (yet practical) problem solutions to get through to make say that a person is comprehend with this scripting language enough to approach some complex yet still practical problems encountered in everyday job. In other words, which problems would you give that person to solve to make sure that he/she is familiar with the scripting language.

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• How do I get long command lines to wrap to the next line?

  - by BrianH

  Edit It was my .bashrc file. I've copied the same profile from machine to machine, and I used special characters in my $PS1 that are somehow throwing it off. I'm now sticking with the standard bash variables for my $PS1. Thanks to @ændrük for the tip on the .bashrc! ...End Edit... Something I have noticed in Ubuntu for a long time that has been frustrating to me is when I am typing a command at the command line that gets longer (wider) than the terminal width, instead of wrapping to a new line, it goes back to column 1 on the same line and starts over-writing the beginning of my command line. (It doesn't actually overwrite the actual command, but visually, it is overwriting the text that was displayed). It's hard to explain without seeing it, but let's say my terminal was 20 characters wide (Mine is more like 120 characters - but for the sake of an example), and I want to echo the English alphabet. What I type is this: echo abcdefghijklmnopqrstuvwxyz But what my terminal looks like before I hit the key is: pqrstuvwxyzghijklmno When I hit enter, it echos abcdefghijklmnopqrstuvwxyz so I know the command was received properly. It just wrapped my typing after the "o" and started over on the same line. What I would expect to happen, if I typed this command in on a terminal that was only 20 characters wide would be this: echo abcdefghijklmno pqrstuvwxyz Background: I am using bash as my shell, and I have this line in my ~/.bashrc: set -o vi to be able to navigate the command line with VI commands. I am currently using Ubuntu 10.10 server, and connecting to the server with Putty. In any other environment I have worked in, if I type a long command line, it will add a new line underneath the line I am working on when my command gets longer than the terminal width and when I keep typing I can see my command on 2 different lines. But for as long as I can remember using Ubuntu, my long commands only occupy 1 line. This also happens when I am going back to previous commands in the history (I hit Esc, then 'K' to go back to previous commands) - when I get to a previous command that was longer than the terminal width, the command line gets mangled and I cannot tell where I am at in the command. The only work-around I have found to see the entire long command is to hit "Esc-V", which opens up the current command in a VI editor. I don't think I have anything odd in my .bashrc file. I commented out the "set -o vi" line, and I still had the problem. I downloaded a fresh copy of Putty and didn't make any changes to the configuration - I just typed in my host name to connect, and I still have the problem, so I don't think it's anything with Putty (unless I need to make some config changes) Has anyone else had this problem, and can anyone think of how to fix it? Thanks in advance! Brian

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• background process outputs to the console

  - by broiyan

  Suppose test.sh is a bash script that is empty or contains only exit 0. When the script is backgrounded, what is the significance of the 1 and 16320 printed to the console? b@sam:~/Documents/bashscripts$ ./test.sh & [1] 16320 b@sam:~/Documents/bashscripts$ [1]+ Done ./test.sh b@sam:~/Documents/bashscripts$ Then if user hits ENTER at the command prompt, as illustrated above, another line appears and it shows this [1]+ Done ./test.sh What is the significance of the 1 digit and the + symbol?

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• How to execute a script as super user first checking the user and getting pass from askpass if not super user

  - by pahnin

  thers a similar question out there How can I determine whether a shellscript runs as root or not? I have the same doubt with different result Is it possible to, within the BASH script prior to everything being run, check if the script is being run as superuser, and if not, print a message saying You must be superuser to use this script, then subsequently get pass from the user using askpass or something like tht then execute the saem script as superuser?

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• Function currying in Javascript

  - by kerry

  Do you catch yourself doing something like this often? 1: Ajax.request('/my/url', {'myParam': paramVal}, function() { myCallback(paramVal); }); Creating a function which calls another function asynchronously is a bad idea because the value of paramVal may change before it is called.  Enter the curry function: 1: Function.prototype.curry = function(scope) { 2: var args = []; 3: for (var i=1, len = arguments.length; i < len; ++i) { 4: args.push(arguments[i]); 5: } 6: var m = this; 7: return function() { 8: m.apply(scope, args); 9: }; 10: } This function creates a wrapper around the function and ‘locks in’ the method parameters.  The first parameter is the scope of the function call (usually this or window).  Any remaining parameters will be passed to the method call.  Using the curry method the above call changes to: 1: Ajax.request('/my/url', {'myParam': paramVal}, myCallback.curry(window,paramVal)); Remember when passing objects to the curry method that the objects members may still change.

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• Git pull auto complete OSX

  - by vodkhang

  Follow some instruction on this site http://denis.tumblr.com/post/71390665/adding-bash-completion-for-git-on-mac-os-x-leopard . I can do git auto complete for MAC OS. However, when I type git pull origin ma (for master), and then tab it takes a long time for git to auto complete to become git pull origin master . I think it connect to the server to get the branch, but I am not sure, is there any way to make it faster and only get the branch on local machine cd /tmp git clone git://git.kernel.org/pub/scm/git/git.git cd git git checkout v`git --version | awk '{print $3}'` cp contrib/completion/git-completion.bash ~/.git-completion.bash cd ~ rm -rf /tmp/git echo -e "source ~/.git-completion.bash" >> .profile

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• Why does cd print when run in command substitution?

  - by reasgt

  If I use the 'cd' BASH built-in in a command substitution, it prints extra stuff to stdout, but only when piped to, eg., less. $ echo `cd .` # The output is a single newline, appended by echo. $ echo `cd .` | less # less displays: ESC]2;my.hostname.com - tmp/testenv^G (END) What's going on there? This behavior isn't documented in the bash man page for cd. Obviously, running just 'cd' in a command substitution is silly, but something like NEWDIR=`cd mypath; pwd` could be useful. I solved this by instead using NEWVAR=`cd mypath > /dev/null 2>&1; pwd` but I still want to know what's going on. Bash Version: GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu) Copyright (C) 2005 Free Software Foundation, Inc. Distro: Scientific Linux SL release 5.5 (Boron)

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• Cron Permission Denied

  - by worldthreat

  good day, I have a bash script in my home directory that works properly from the command line (file structure is default media temple DV. < noted for certain permission issues) but receive this error from cron: "/home/myFile.sh: line 2: /var/www/vhosts/domain.com/subdomains/techspatch/installation.sql: Permission denied" NOTICE: it's just line 2... it writes to the local server just fine. Below is the Bash File: #!/bin/bash mysqldump -uUSER -pPASSWORD -hHOST dbName> /var/www/vhosts/domain.com/subdomains/techspatch/installation.sql mysql -uadmin -pPASSWORD -hlocalhost dbName< /var/www/vhosts/domain.com/subdomains/techspatch/installation.sql can't chmod from bash (lol, yeah i tried). writing the file there and setting the permissions before the transfer is useless... i have googled the heck out of this situation and this one still seems unique.... any insight is appreciated

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• mac cron can't use the shell correctly

  - by carneades

  I've set up cron to run a simple hello world shell script, but it's giving me an error that Google isn't helping me resolve. I've got to be missing something really simple! Here's my crontab: [email protected] SHELL=/bin/bash 30 * * * * * $HOME/hello.sh Here's hello.sh: #!/bin/bash echo HELLO WORLD! I get this error email: /bin/bash: 555: command not found I have tried setting shell to /bin/sh but it makes no difference. I still get an analogous error message.

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• Compute if a function is pure

  - by Oni

  As per Wikipedia: In computer programming, a function may be described as pure if both these statements about the function hold: The function always evaluates the same result value given the same argument value(s). The function result value cannot depend on any hidden information or state that may change as program execution proceeds or between different executions of the program, nor can it depend on any external input from I/O devices. Evaluation of the result does not cause any semantically observable side effect or output, such as mutation of mutable objects or output to I/O devices. I am wondering if it is possible to write a function that compute if a function is pure or not. Example code in Javascript: function sum(a,b) { return a+b; } function say(x){ console.log(x); } isPure(sum) // True isPure(say) // False

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• How to automatically define functions and aliases on remote server after ssh login

  - by Ramon

  I want to define bash functions and aliases in my remote shell automatically on login. I can't put the definitions into .profile or similar because the users I log in as are often shared with others who use the same systems and I don't have control of this. What I'm trying to do is execute a few bash function definitions in the remote process and then continue as a login shell. I tried this but it did not work: cat ~/.profile - | ssh -tt user@host bash -l Any ideas?

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• Why to say, my function is of IFly type rather than saying it's Airplane type

  - by Vishwas Gagrani

  Say, I have two classes: Airplane and Bird, both of them fly. Both implement the interface IFly. IFly declares a function StartFlying(). Thus both Airplane and Bird have to define the function, and use it as per their requirement. Now when I make a manual for class reference, what should I write for the function StartFlying? 1) StartFlying is a function of type IFly . 2) StartFlying is a function of type Airplane 3) StartFlying is a function of type Bird. My opinion is 2 and 3 are more informative. But what i see is that class references use the 1st one. They say what interface the function is declared in. Problem is, I really don't get any usable information from knowing StartFlying is IFly type. However, knowing that StartFlying is a function inside Airplane and Bird, is more informative, as I can decide which instance (Airplane or Bird ) to use. Any lights on this: how saying StartFlying is a function of type IFly, can help a programmer understanding how to use the function?

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• Colored PS1 string

  - by Will Vousden

  Clarification: I want __foo to be executed each time the PS1 string is presented in the terminal, not when the PS1 string is constructed (hence its being in quotes). __foo contains logic that examines the current directory, so its execution must be deferred. I'm trying to use different colours in my Bash PS1 string from within a Bash function: LIGHTRED="\033[1;31m" LIGHTGREEN="\033[1;32m" RESET="\033[m" __foo () { # Do some stuff and genereate a string to echo in different colours: echo -n '\['$1'\]firstcolour \['$2'\]secondcolour' } PS1='$(__foo '$LIGHTRED' '$LIGHTGREEN')\['$RESET'\] \$' Essentially I want __foo to generate part of the PS1 in a bunch of different colours. My attempt doesn't seem to work, though; it produces the following output: -bash: 31m: command not found -bash: 32m: command not found \[]firstcolour \[\]secondcolour $ What gives, and how can I fix it?

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• Shell script for replacing string in all PHP-files, for each user

  - by Mads Skjern

  Each user has some php-files using a shared database commondb. I want to iterate over all users (in users.csv), and in their home folder (e.g. /home/joe) find all php files recursively, and replace each occurrence of "commondb" with their own databasename, e.g. "joedb" for "joe". I have tried the following: #!/bin/bash # Execute like this: # bash localize.bash users.csv OLDIFS=$IFS IFS="," while read name dummy do echo $name find /home/${name} -name '*.php' -exec sed -i '' 's/commondb/${name}db/g' "{}" \; done < $1 IFS=$OLDIFS for users.csv joe, Joe J george, George G It does not fail, but the files are unchanged. I am quite weak in bash, and I can't figure out how to debug it :/ Can my script be fixed to work?

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• Cronjob terminates early

  - by TheBigO

  In my crontab file I execute a script like so (I edit the crontab using sudo crontab -e): 01 * * * * bash /etc/m/start.sh The script runs some other scripts like so: sudo bash -c "/etc/m/abc.sh --option=1" & sleep 2 sudo bash -c "/etc/m/abc.sh --option=2" & When cron runs the script start.sh, I do ps aux | grep abc.sh and I see the abc.sh script running. After a couple of seconds, the script is no longer running, even though abc.sh should take hours to finish. If I do sudo bash /etc/m/start.sh & from the command line, everything works fine (the abc.sh scripts run for hours in the background until they complete). How do I debug this? Is there something I'm doing that is preventing these scripts from running in the background until they are done?

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• Chrooted user does not start in his home directory and does not load his bash_profiles

  - by Stuffy

  If the users logs in, he starts in / of the chroot (Which is /var/jail on the real machine). I would like him to start in his home-dir. Also, he seems not to load any of his profile-files (.bash.rc etc). I followed this tutorial to create the chroot environment. This is what my /etc/passwd looks like: test:x:1004:1008:,,,:/var/jail/home/test:/bin/bash this is what my /var/jail/etc/passwd file looks like: test:x:1004:1008:,,,:/home/test:/bin/bash I also found out that, if I remove Match User test ChrootDirectory /var/jail AllowTCPForwarding no X11Forwarding no from my /etc/ssh/sshd_config, the user starts in his correct home-folder and with his bash-settings loaded. However, he is able to leave the chroot-environment if I remove that part. This question I asked before is somewhat related, since I think the wrong look of the commandline is caused from the not loaded profile-files. So any ideas how to fix this?

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• Bash Associative Arrays

  <b>Linux Journal:</b> "There's nothing too surprising about associative arrays in bash, they are as you probably expect:"

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