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  • "Syntax error in INSERT INTO statement". Why?

    - by Kevin
    My code is below. I have a method where I pass in three parameters and they get written out to an MS Access database table. However, I keep getting a syntax error message. Can anyone tell me why? I got this example from the internet. private static void insertRecord(string day, int hour, int loadKW) { string connString = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\LoadForecastDB.accdb"; OleDbConnection conn = new OleDbConnection(connString); string ins = @"INSERT INTO Forecasts (Day, Hour, Load) VALUES (?,?,?)"; OleDbCommand cmd = new OleDbCommand(ins, conn); cmd.Parameters.Add("@day", OleDbType.VarChar).Value = day; cmd.Parameters.Add("@hour", OleDbType.Integer).Value = hour; cmd.Parameters.Add("@load", OleDbType.Integer).Value = loadKW; conn.Open(); try { int count = cmd.ExecuteNonQuery(); } catch (OleDbException ex) { Console.WriteLine(ex.Message); } finally { conn.Close(); } }

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  • Simple check for SELECT query empty result

    - by den-javamaniac
    Hi. Can anyone point out how to check if a select query returns non empty result set? For example I have next query: SELECT * FROM service s WHERE s.service_id = ?; Should I do something like next: ISNULL(SELECT * FROM service s WHERE s.service_id = ?) to test if result set is not empty?

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  • jquery script to retrieve select value on click: works in Firefox, does not in Internet Explorer

    - by vatshal
    hi vatshal here; I am using a jquery script in which I am getting the current value of a select box on mouse click; it works on Mozila Firefox but doesn't work in Internet Explorer onclick in IE shows previous value from the select box id <select> <option>value1</option> <option>value2</option> </select> if we are clicking on value2 then jquery gets the value of the first element, but it is working on mozila firefox only; jquery code is given below: <script type="text/javascript" src="jquery-1.4.2.js"></script> <script type="text/javascript"> $(function(){ $("#multiple").click(function(){ var a=$("#multiple").val(); $("#to").val(a); }); }); </script> Please help me

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  • JQuery setting the selected attribute on a select list

    - by Rupert
    I have the following html <select id="dropdown"> <option>A</option> <option>B</option> <option>C</option> </select> I have the string "B" so I want to set the selected attrribute on it so it will be: <select id="dropdown"> <option>A</option> <option selected="selected">B</option> <option>C</option> </select> How would I do this in JQuery?

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  • Oracle Reports SELECT INTO Not Selecting

    - by Kevin Cruz
    I'm working on a Report in Oracle Reports Builder, and having issues with my AFTERPFORM trigger. When viewing the report, it seems like the year is being processed properly, while the period and subperiod are using their initial values. I'm confused because they are the exact same select statement, but are not working as intended. Any help would be greatly appreciated! function AfterPForm return boolean is v_subpdenddt_user date; v_subpdenddt_max date; v_rowcount integer; begin select value into year from wos_report_param where parameter = 'year' and sequence_num = :sequencenum; select value into period from wos_report_param where parameter = 'period' and sequence_num = :sequencenum; select value into user_subpd from wos_report_param where parameter = 'subpd' and sequence_num = :sequencenum;

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  • [sqlalchemy] subquery in select statement

    - by webjunkie
    Hi guys, I have two tables (albums,pictures) in a one to many relationship and I want to display each albums details with one picture so I have the following query select albums.name,(select pictures.path from pictures where pictures.albumid=albums.id limit 1) as picture from albums where ... Now I'm struggling creating this on Pylons with sqlalchemy I tried to do the following picture = Session.query(model.Picture) sub_q = picture.filter_by(albumid = model.Album.id).limit(1).subquery() album_q = Session.query(model.Album, sub_q) result = album_q.all() but it creates the following statement displaying the incorrect picture beacuse the table albums is included in the subquery select albums.name,(select pictures.path from pictures,albums where pictures.albumid=albums.id) from albums where ... Am I doing it wrong?, is this even possible in sqlalchemy?.

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  • Isotope active class when using select menu

    - by Michael
    I am using Metafizzy's Isotope plugin and have it set up to filter using a select menu as seen here: http://jsfiddle.net/trewknowledge/jJZEN/ $(function() { var $container = $('#container'), $select = $('#filters select'); $container.isotope({ itemSelector: '.item' }); $select.change(function() { var filters = $(this).val(); ; $container.isotope({ filter: filters }); }); });? What I am trying to figure out is how I would add a highlight/active class to the selected elements when the filters variable is already being used.

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  • listbox select count not work dont work

    - by sadpcd
    I recently trying to make a form with multiple select box. When someone select the options the number of selected options will be display on another text. I'm a beginner in JavaScript. The function is called, but it doesn't count the number of the selected options. <select name="element_17_1[ ]" size="7" multiple="multiple" class="element select medium" id="element_17_1[ ]" onfocus="selectCount(this.form);" onClick="selectCount(this.form);" > <option value="Opt1">Opt1</option> <option value="Opt2">Opt2</option> <option value="Opt3">Opt3</option> <option value="Opt4">Opt4</option> <option value="Opt5">Opt5</option> <option value="Opt6">Opt6</option> <option value="Opt7">Opt7</option> </select> and this is the function I tried in the <head> function selectCount(f) { var selObj = myForm.elements['element_17_1[]']; var totalChecked = 0; for (i = 0; i < selObj.options.length; i++) { if (selObj.options[i].selected) { totalChecked++; } } f.element_9.value = totalChecked; }

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  • How to perform .select() on jQuery masked text input

    - by dllhell
    I'm using http://digitalbush.com/projects/masked-input-plugin/ plugin. There is an input text with defined mask: <input type="text" id="txtMyInput" class="FocusSense"/> and a script: $(document).ready(function () { jQuery(function ($) { $("#txtMyInput").mask("?9.99"); }); $(".FocusSense").focus(function () { this.select(); }); }) As you can see, I would like select all in txtMyInput on focus but but alas! On focus, mask appears and loose .select(). What should I do to preserve mask and .select()?

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  • <select> box not displaying on Android in PhoneGap

    - by Steve Nay
    I have some HTML code in a PhoneGap application that displays a <select> box to the user. When I tap on it, the usual Android selection screen doesn't pop up. I had a similar problem with this earlier on webOS (although at that time the drop-downs were working properly). The <select> is inside a <div> that gets hidden or shown at certain times during execution: <div id="submit"> <ul class="rounded"> <li><select id="item"></select></li> </ul> </div> The problem only occurs when the <div> has been hidden and then shown again (either directly through CSS or by using jQuery's hide() and show() methods. If I move the <select> box outside of that <div>, or if I make the <div> always visible, then the drop-down behaves as it should; no problems. Why is this?

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  • how to select a value from a listbox?

    - by udaya
    Hi I am having a list box like this ,the list box is populated from the database <td bgcolor="#FFFFCC"> <select name="listbox" id="FriendmailId" size="3" > <option value="0">Select User From List</option> <? foreach($searchfriend as $row) {?> <option value=""><?=$row['dEmailID'];?></option> <? } ?> </select> </td> The values are listed in the list box ....but the problem is when i select a item it is highted but not really selected why it is so

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  • Select text in edit window using DPAD

    - by rajankz
    I am using the DPAD controls to highlight text in android text-widget. I am wondering is there is any way that when i highlight the text, it selects it also. Right now when i highlight and try to bring the context menu, the first context menu I get is the one with options to select word, select all etc. and when i do select word, it selects the entire region highlighted(which is okay , but i wanted it to select while am highlighting) so that i could get the cut/copy and paste context menu directly. Any tips? Thanks a lot.

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  • SELECT Data from multiple tables?

    - by Kyle R
    I have 3 tables, with 3 fields all the same. I basically want to select information from each table For example: userid = 1 I want to select data from all 3 tables, where userid = 1 I am currently using: SELECT r.*, p.*, l.* FROM random r LEFT JOIN pandom p ON r.userid = p.userid LEFT JOIN landom l ON l.userid = r.userid WHERE r.userid = '1' LIMIT 0, 30 But it doesn't seem to work.

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  • jQuery select last word after = (equal symbol)

    - by Jonathan
    I'm using $(this).attr("href"); to select the href attribute value of the clicked element, but I need to select only the part after the last '=' symbol. Example: href="index.php?con=123&id=123&sel=heyhey" I only need the last part of the href that is 'heyhey' How can I select this??

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  • select k th mimimum from array a[0..n-1]

    - by davit-datuashvili
    i have done folloing code from progrmming pearls here is code import java.util.*; public class select { public static int select1(int x[],int l,int u,int k){ //pre l<=k<=u //post x[l..k-1]<=x[k]<=x[k+1..u] Random r=new Random(); int t=r.nextInt(u-1-l)+l; if (l>=u) return -1 ; swap(l,t); int s=x[l]; int i=l; int j=u+1; while (true){ do { i++; }while (i<=u && x[i]<t); do { j--; }while (x[j]>t); if (i>j) break; int temp=x[i]; x[i]=x[j];x[j]=t; swap(l,j); if (j<k){ return select1(x,j+1,u,k); } } return select1(x,l,j-1,k); } public static void main(String[] args) { int x[]=new int[]{4,7,9,3,2,12,13,10,20}; select1(x,0,x.length-1,5); } public static void swap(int i,int j){ int c=i; i=j; j=c; } } but here is mistake Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: -1 at select.select1(select.java:21) at select.main(select.java:36) Java Result: 1 please help

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  • Static DataTable or DataSet in a class - bad idea?

    - by Superbest
    I have several instances of a class. Each instance stores data in a common database. So, I thought "I'll make the DataTable table field static, that way every instance can just add/modify rows to its own table field, but all the data will actually be in one place!" However, apparently it's a bad idea to do use static fields, especially if it's databases: Don't Use "Static" in C#? Is this a bad idea? Will I run into problems later on if I use it? This is a small project so I can accept no testing as a compromise if that is the only drawback. The benefit of using a static database is that there can be many objects of type MyClass, but only one table they all talk to, so a static field seems to be an implementation of exactly this, while keeping syntax concise. I don't see why I shouldn't use a static field (although I wouldn't really know) but if I had to, the best alternative I can think of is creating one DataTable, and passing a reference to it when creating each instance of MyClass, perhaps as a constructor parameter. But is this really an improvement? It seems less intuitive than a static field.

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  • How to make MVC 4 Razor Html.Raw work for assignment in HTML within script tags

    - by Yarune
    For a project I'm using jqote for templating in JavaScript and HTML generated by MVC 4 with Razor. Please have a look at the following code in HTML and Razor: <script id="testTemplate" type="text/html"> <p>Some html</p> @{string id = "<%=this.Id%>";} <!-- 1 --> @if(true) { @Html.Raw(@"<select id="""+id+@"""></select>") } <!-- 2 --> @if(true) { <select id="@Html.Raw(id)"></select> } <!-- 3 --> @Html.Raw(@"<select id="""+id+@"""></select>") <!-- 4 --> <select id="@Html.Raw(id)"></select> <!-- 5 --> <select id="<%=this.Id%>"></select> </script> The output is this: <script id="testTemplate" type="text/html"> <!-- 1 --> <select id="<%=this.Id%>"></select> <!--Good!--> <!-- 2 --> <select id="&lt;%=this.Id%&gt;"></select> <!--BAD!--> <!-- 3 --> <select id="<%=this.Id%>"></select> <!--Good!--> <!-- 4 --> <select id="<%=this.Id%>"></select> <!--Good!--> <!-- 5 --> <select id="<%=this.Id%>"></select> <!--Good!--> </script> Now, the problem is with the second select under <!-- 2 -->. One would expect the Html.Raw to kick in here but somehow it doesn't. Or Razor wants to HtmlEncode what's in there. The question is: Does anyone have an idea why? Is this a bug or by design? Without the script tags it works. But we need the script tags cause we need to template in JavaScript. Hardcoded it works, but we need to use a variable because this will not always be a template. Without the @if it works, but it's there, we need it. Workarounds These lines give similar good outputs: @if(true) { <select id= "@Html.Raw(id)"></select> } @if(true) { <select id ="@Html.Raw(id)"></select> } @if(true) { <select id @Html.Raw("=")"@Html.Raw(id)"></select> } We're planning to do this: <script id="testTemplate" type="text/html"> @{string id = @"id=""<%=this.Id%>""";} @if(true) { <select @Html.Raw(id)></select> } </script> ...to keep as to markup intact as much as possible.

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  • Simple image editor to select area of image as wallpaper

    - by Kevin
    I've spent way to many hours looking for software to do the following simple task, so now I'll ask. I need software that will open an image and put a 'crop box' on it. You can set the 'crop box' to standard screen resolutions (1024x768) or define a custom one. You can move the 'crop box' around on the image to select the area you want. You can re-size the 'crop box' (selecting a corner and dragging w/mouse) and it maintains the correct aspect ratio. You can save the area in the 'crop box' to use as the Windows background. (The software doesn't need to set it as the background, I can do that myself in Windows XP.) The free software sites (CNET.com, etc.) have lots of image editing software that do things much more complicated than this simple task. I've spent too many hours downloading them to see if they will do this particular task. The ones I've tried would require manual trial and error to get the part of an image that I want saved as an image, with the correct aspect ratio so Windows doesn't screw with it (stretch, tile, crop) when I select it as the wallpaper.

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  • Excel VBA: select every other cell in a row range to be copied and pasted vertically

    - by terry alexander
    i have a 2200+ page text file. It is delivered from a customer through a data exchange to us with astericks to separate values and tildes (~) to denote the end of a row. The file is sent to me as a text file in Word. Most rows are split in two (1 row covers a full line and part of a second line). i transfer segments (10 page chunks) of it at a time into Excel where, unfortunately, any zeroes that occur at the end of a row get discarded in the "text to columns" procedure. So, i eyeball every "long" row to insure that zeroes were not lost and manually re-enter any that were. Here is a small bit of sample data: SDQ EA 92 1551 378 1601 151 1603 157 1604 83 The "SDQ, EA, and 92" are irrelevant (artifacts of data transmission). i want to use Excel VBA to select 1551, 1601, 1603, and 1604 (these are store numbers) so that i can copy those values and transpose paste them vertically. i will then go back and copy 378, 151, 157, and 83 (sales values) so that i can transpose paste them next to the store numbers. The next two rows of data contain the same store numbers but give the corresponding dollar values. i will only need to copy the dollar values so they can be transpose pasted vertically next to unit values (e.g. 378, 151, 157, and 83). Just being able to put my cursor on the first cell of interest in the row and run a macro to copy every other cell would speed up my work tremendously. i have tried using activecell and offset references to select a range to copy but have not been successful. Does any have any suggestions for me? Thanks in advance for the help.

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  • Spring-mvc project can't select from a particular mysql table

    - by Dan Ray
    I'm building a Spring-mvc project (using JPA and Hibernate for DB access) that is running just great locally, on my dev box, with a local MySQL database. Now I'm trying to put a snapshot up on a staging server for my client to play with, and I'm having trouble. Tomcat (after some wrestling) deploys my war file without complaint, and I can get some response from the application over the browser. When I hit my main page, which is behind Spring Security authentication, it redirects me to the login page, which works perfectly. I have Security configured to query the database for user details, and that works fine. In fact, a change to a password in the database is reflected in the behavior of the login form, so I'm confident it IS reaching the database and querying the user table. Once authenticated, we go to the first "real" page of the app, and I get a "data access failure" error. The server's console log gets this line (redacted): ERROR org.hibernate.util.JDBCExceptionReporter - SELECT command denied to user 'myDbUser'@'localhost' for table 'asset' However, if I go to MySQL from the shell using exactly the same creds, I have no problem at all selecting from the asset table: [development@tomcat01stg]$ mysql -u myDbUser -pmyDbPwd dbName ... mysql> \s -------------- mysql Ver 14.12 Distrib 5.0.77, for redhat-linux-gnu (i686) using readline 5.1 Connection id: 199 Current database: dbName Current user: myDbUser@localhost ... UNIX socket: /var/lib/mysql/mysql.sock -------------- mysql> select count(*) from asset; +----------+ | count(*) | +----------+ | 19 | +----------+ 1 row in set (0.00 sec) I've broken down my MySQL access settings, cleaned out the user and re-run the grant commands, set up a version of the user from 'localhost' and another from '%', making sure to flush permissions.... Nothing is changing the behavior of this thing. What gives?

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  • MySQL select query result set changes based on column order

    - by user197191
    I have a drupal 7 site using the Views module to back-end site content search results. The same query with the same dataset returns different results from MySQL 5.5.28 to MySQL 5.6.14. The results from 5.5.28 are the correct, expected results. The results from 5.6.14 are not. If, however, I simply move a column in the select statement, the query returns the correct results. Here is the code-generated query in question (modified for readability). I apologize for the length; I couldn't find a way to reproduce it without the whole query: SELECT DISTINCT node_node_revision.nid AS node_node_revision_nid, node_revision.title AS node_revision_title, node_field_revision_field_position_institution_ref.nid AS node_field_revision_field_position_institution_ref_nid, node_revision.vid AS vid, node_revision.nid AS node_revision_nid, node_node_revision.title AS node_node_revision_title, SUM(search_index.score * search_total.count) AS score, 'node' AS field_data_field_system_inst_name_node_entity_type, 'node' AS field_revision_field_position_college_division_node_entity_t, 'node' AS field_revision_field_position_department_node_entity_type, 'node' AS field_revision_field_search_lvl_degree_lvls_node_entity_type, 'node' AS field_revision_field_position_app_deadline_node_entity_type, 'node' AS field_revision_field_position_start_date_node_entity_type, 'node' AS field_revision_body_node_entity_type FROM node_revision node_revision LEFT JOIN node node_node_revision ON node_revision.nid = node_node_revision.nid LEFT JOIN field_revision_field_position_institution_ref field_revision_field_position_institution_ref ON node_revision.vid = field_revision_field_position_institution_ref.revision_id AND (field_revision_field_position_institution_ref.entity_type = 'node' AND field_revision_field_position_institution_ref.deleted = '0') LEFT JOIN node node_field_revision_field_position_institution_ref ON field_revision_field_position_institution_ref.field_position_institution_ref_target_id = node_field_revision_field_position_institution_ref.nid LEFT JOIN field_revision_field_position_cip_code field_revision_field_position_cip_code ON node_revision.vid = field_revision_field_position_cip_code.revision_id AND (field_revision_field_position_cip_code.entity_type = 'node' AND field_revision_field_position_cip_code.deleted = '0') LEFT JOIN node node_field_revision_field_position_cip_code ON field_revision_field_position_cip_code.field_position_cip_code_target_id = node_field_revision_field_position_cip_code.nid LEFT JOIN node node_node_revision_1 ON node_revision.nid = node_node_revision_1.nid LEFT JOIN field_revision_field_position_vacancy_status field_revision_field_position_vacancy_status ON node_revision.vid = field_revision_field_position_vacancy_status.revision_id AND (field_revision_field_position_vacancy_status.entity_type = 'node' AND field_revision_field_position_vacancy_status.deleted = '0') LEFT JOIN search_index search_index ON node_revision.nid = search_index.sid LEFT JOIN search_total search_total ON search_index.word = search_total.word WHERE ( ( (node_node_revision.status = '1') AND (node_node_revision.type IN ('position')) AND (field_revision_field_position_vacancy_status.field_position_vacancy_status_target_id IN ('38')) AND( (search_index.type = 'node') AND( (search_index.word = 'accountant') ) ) AND ( (node_revision.vid=node_node_revision.vid AND node_node_revision.status=1) ) ) ) GROUP BY search_index.sid, vid, score, field_data_field_system_inst_name_node_entity_type, field_revision_field_position_college_division_node_entity_t, field_revision_field_position_department_node_entity_type, field_revision_field_search_lvl_degree_lvls_node_entity_type, field_revision_field_position_app_deadline_node_entity_type, field_revision_field_position_start_date_node_entity_type, field_revision_body_node_entity_type HAVING ( ( (COUNT(*) >= '1') ) ) ORDER BY node_node_revision_title ASC LIMIT 20 OFFSET 0; Again, this query returns different sets of results from MySQL 5.5.28 (correct) to 5.6.14 (incorrect). If I move the column named "score" (the SUM() column) to the end of the column list, the query returns the correct set of results in both versions of MySQL. My question is: Is this expected behavior (and why), or is this a bug? I'm on the verge of reverting my entire environment back to 5.5 because of this.

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  • Perfectly reproducable select statement default ordering issue....

    - by Dave
    Hi, I've recently been chasing an issue with a client's db... solution found, but impossible to recreate. Essentially, we're doing a Select * from mytable where ArbitraryColumn = 75 Where MyTable has an Identity column, called 'MyIndentityColumn' - incremented by one in each insert. Naturally, and normally I would assume that the order returned would be the order in which they are inserted (bad assumption, but one which was forced onto me, through an inherited application - which has been patched). Essentially, I would like suggestions as to why the database, when restored to my local machine (same OS, same SQL server version - 200 sp3) same collation, and same backup instance restored on it, as a test DB on the client site. When I perform the above select, I get them in order of insert (i.e. identity column ordered ascending). On the client, it seems random (but the same 'random' order each time)... A few other points: I have the same collation on my test server as client Same DB backup restored to a test only I can access Same SQL server version and service pack Same OS Test DB is a new DB - new log and MDF... I have the problem 'solved' by adding an explicit order by clause but I want to undertand the cause of the issue, given the exact nature of my attempts to recreate it beuing futile, and perfectly recreatable on the client server... Thanks in advance, Dave

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  • Strange Photoshop Problem: Can not select, zoom, paint, option button 'locked'

    - by nikcub
    I have a very strange problem with Photoshop. I can not use any of the tools, since the cursor appears 'locked'. If I select v on my keyboard, it goes to the zoom tool, but the cursor does not change. If I select the paintbrush tool, I can only paint if I hold down the option key. This is what the cursor look like (I had to paint it since I couldn't capture it). It is a rectangle with two lines through it. I am running Photoshop CS4 on a Macbook Pro with Mac OS X 10.6.6. Using both the trackpad and an external Logitech MX5000 mouse I see the same issue. This started when I fired up Photoshop today for the first time in a while. I can't remember changing any options or doing anything that could cause this. Is it possible that the option key is somehow locked in place, or there is some equivalent of num lock on? Very strange problem, I would appreciate any help anybody can offer. Edit: To add, the icon remains the same within all the menu options - it never goes back to being just a normal mouse cursor. Also, right click works fine, and if I hold down option, the cursor goes back to normal and I can paint with it. I can't use Marquee, Lasso, Crop, Type etc. even with option held down. When I go into Bridge, it is the same icon.

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  • IsNumeric() Broken? Only up to a point.

    - by Phil Factor
    In SQL Server, probably the best-known 'broken' function is poor ISNUMERIC() . The documentation says 'ISNUMERIC returns 1 when the input expression evaluates to a valid numeric data type; otherwise it returns 0. ISNUMERIC returns 1 for some characters that are not numbers, such as plus (+), minus (-), and valid currency symbols such as the dollar sign ($).'Although it will take numeric data types (No, I don't understand why either), its main use is supposed to be to test strings to make sure that you can convert them to whatever numeric datatype you are using (int, numeric, bigint, money, smallint, smallmoney, tinyint, float, decimal, or real). It wouldn't actually be of much use anyway, since each datatype has different rules. You actually need a RegEx to do a reasonably safe check. The other snag is that the IsNumeric() function  is a bit broken. SELECT ISNUMERIC(',')This cheerfully returns 1, since it believes that a comma is a currency symbol (not a thousands-separator) and you meant to say 0, in this strange currency.  However, SELECT ISNUMERIC(N'£')isn't recognized as currency.  '+' and  '-' is seen to be numeric, which is stretching it a bit. You'll see that what it allows isn't really broken except that it doesn't recognize Unicode currency symbols: It just tells you that one numeric type is likely to accept the string if you do an explicit conversion to it using the string. Both these work fine, so poor IsNumeric has to follow suit. SELECT  CAST('0E0' AS FLOAT)SELECT  CAST (',' AS MONEY) but it is harder to predict which data type will accept a '+' sign. SELECT  CAST ('+' AS money) --0.00SELECT  CAST ('+' AS INT)   --0SELECT  CAST ('+' AS numeric)/* Msg 8115, Level 16, State 6, Line 4 Arithmetic overflow error converting varchar to data type numeric.*/SELECT  CAST ('+' AS FLOAT)/*Msg 8114, Level 16, State 5, Line 5Error converting data type varchar to float.*/> So we can begin to say that the maybe IsNumeric isn't really broken, but is answering a silly question 'Is there some numeric datatype to which i can convert this string? Almost, but not quite. The bug is that it doesn't understand Unicode currency characters such as the euro or franc which are actually valid when used in the CAST function. (perhaps they're delaying fixing the euro bug just in case it isn't necessary).SELECT ISNUMERIC (N'?23.67') --0SELECT  CAST (N'?23.67' AS money) --23.67SELECT ISNUMERIC (N'£100.20') --1SELECT  CAST (N'£100.20' AS money) --100.20 Also the CAST function itself is quirky in that it cannot convert perfectly reasonable string-representations of integers into integersSELECT ISNUMERIC('200,000')       --1SELECT  CAST ('200,000' AS INT)   --0/*Msg 245, Level 16, State 1, Line 2Conversion failed when converting the varchar value '200,000' to data type int.*/  A more sensible question is 'Is this an integer or decimal number'. This cuts out a lot of the apparent quirkiness. We do this by the '+E0' trick. If we want to include floats in the check, we'll need to make it a bit more complicated. Here is a small test-rig. SELECT  PossibleNumber,         ISNUMERIC(CAST(PossibleNumber AS NVARCHAR(20)) + 'E+00') AS Hack,        ISNUMERIC (PossibleNumber + CASE WHEN PossibleNumber LIKE '%E%'                                          THEN '' ELSE 'E+00' END) AS Hackier,        ISNUMERIC(PossibleNumber) AS RawIsNumericFROM    (SELECT CAST(',' AS NVARCHAR(10)) AS PossibleNumber          UNION SELECT '£' UNION SELECT '.'         UNION SELECT '56' UNION SELECT '456.67890'         UNION SELECT '0E0' UNION SELECT '-'         UNION SELECT '-' UNION SELECT '.'         UNION  SELECT N'?' UNION SELECT N'¢'        UNION  SELECT N'?' UNION SELECT N'?34.56'         UNION SELECT '-345' UNION SELECT '3.332228E+09') AS examples Which gives the result ... PossibleNumber Hack Hackier RawIsNumeric-------------- ----------- ----------- ------------? 0 0 0- 0 0 1, 0 0 1. 0 0 1¢ 0 0 1£ 0 0 1? 0 0 0?34.56 0 0 00E0 0 1 13.332228E+09 0 1 1-345 1 1 1456.67890 1 1 156 1 1 1 I suspect that this is as far as you'll get before you abandon IsNumeric in favour of a regex. You can only get part of the way with the LIKE wildcards, because you cannot specify quantifiers. You'll need full-blown Regex strings like these ..[-+]?\b[0-9]+(\.[0-9]+)?\b #INT or REAL[-+]?\b[0-9]{1,3}\b #TINYINT[-+]?\b[0-9]{1,5}\b #SMALLINT.. but you'll get even these to fail to catch numbers out of range.So is IsNumeric() an out and out rogue function? Not really, I'd say, but then it would need a damned good lawyer.

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