Search Results

Search found 22501 results on 901 pages for 'form upload'.

Page 48/901 | < Previous Page | 44 45 46 47 48 49 50 51 52 53 54 55  | Next Page >

  • Access startup form locked GUI

    - by Brad
    I just had an interesting experience with a startup form in MS Access 2010. I designed a login form and when I thought I was done I set my startup form to be the login form I'd just created. I then closed Access and reopened it but my login form did not appear. Instead the whole GUI was locked. I cannot click on anything. My form was working during my tests before I set it as a startup form and reloaded Access. How can I either remove my form as a startup object or get the use of my GUI back?

    Read the article

  • ShowDialog and Hide form, when from is called from other object in VS2010

    - by Piotr Dabrowski
    Hallo, I have a modal Form, used for searching information in DB. This Form is used by a COM object, that waits for search result. Initialization of the form take a lot of time (because of building connection to DB). So, I initialize the Form (without showing it), and keep Form-object alive, as long as COM-object work. In this way I keep the state of the Form: public void Search() this.ShowDialog(); string result = this.ResultOfSearch; this.Hide() return result; And it doesn't work anymore on VS2010 (compiled for Framework 2.0). I search for alternative way to make a modal form (or a method to protect a form against Destroy() at the end of ShowDialog). Any ideas?

    Read the article

  • Select form children when multiple forms are present jQuery

    - by afreeland
    I am dealing with a webpage that has multiple forms..some basic HTML forms and some AJAX forms. I have a created validation for inputs, let me give an example...if an input has a class="required" whenever a submit button is pressed if any required classes are empty then the form doesnt submit. Which works great...until you have multiple forms with required fields that dont apply to the section your submitting. I am able to find the closest form $(this).closest("form") and it gets me the form element properly, I then need to be able to loop only through the children of that form. I have tried: .children(':input'), .find('input') and honestly to many to list. Here is the code for when a button is selected $('#formSubmit').click(function (e) { var submit = true; var form = $(this).closest("form"); var formID = $(form).attr("id"); e.preventDefault(); $(form).children(":input").each(function () { if ($('#ERROR').length > 0) { submit = false; alert("Please fix errors to continue"); } $('.required').each(function () { if ($(this).val() == "" || $(this).val() == undefined) { submit = false; $(this).css({ 'background-color': '#fef236' }); } }); }); if (submit == true) { this.form.submit(); } }); //End of #formSubmit Also of interest I have started creating forms with ids that are GUID's so they will be unique and allow me to target things without any issues, just wanted to throw that out there if it can help lead to a solution I appreciate any help =)

    Read the article

  • Iterate through all form fields within a specified DIV tag.

    - by user344255
    I need to be able to iterate through all the form fields within a specified DIV tag. Basically, any given DIV tag can have multiple form fields (which is easy enough to parse through), but it can also any number of tables or even additional DIV tags (adding additional levels of hierarchical layering). I've written a basic function that goes through each of the direct descendants of the parent node (in this case, the DIV tag) and it clears out its value. This part works fine. The problem is getting it to parse children when children (grandchildren) of their own. It winds up getting caught up in an infinite loop. In this case, I need be able to find all the form fields within DIV tag "panSomePanel", which will include some direct children (txtTextField1), but also some grandchildren who are within nested TABLE objects and/or nested DIV tags (radRadioButton, DESC_txtTextArea). Here is a sample DIV and its contents: <DIV id="panSomePanel"> <INPUT name="txtTextField1" type="text" id="txtTextField1" size="10"/><BR><BR> <TABLE id="tblRadioButtons" border="0"> <TR> <TD> <INPUT id="radRadioButton_0" type="radio" name="radRadioButton" value="1" /><LABEL for="radRadioButton_0">Value 1</LABEL> </TD> <TD> <INPUT id="radRadioButton_5" type="radio" name="radRadioButton" value="23" /><LABEL for="radRadioButton_5">Value 23</LABEL> </TD> </TR> <TR> <TD> <INPUT id="radRadioButton_1" type="radio" name="radRadioButton" value="2" /><LABEL for="radRadioButton_1">Value 2</LABEL> </TD> <TD> <INPUT id="radRadioButton_6" type="radio" name="radRadioButton" value="24" /><LABEL for="radRadioButton_6">Value 24</LABEL> </TD> </TR> <TR> <TD> <INPUT id="radRadioButton_2" type="radio" name="radRadioButton" value="3" /><LABEL for="radRadioButton_2">Value 3</LABEL> </TD> <TD> <INPUT id="radRadioButton_7" type="radio" name="radRadioButton" value="25" /><LABEL for="radRadioButton_7">Value 25</LABEL> </TD> </TR> <TR> <TD> <INPUT id="radRadioButton_3" type="radio" name="radRadioButton" value="21" /><LABEL for="radRadioButton_3">Value 21</LABEL> </TD> <TD> <INPUT id="radRadioButton_8" type="radio" name="radRadioButton" value="4" /><LABEL for="radRadioButton_8">Value 4</LABEL> </TD> </TR> <TR> <TD> <INPUT id="radRadioButton_4" type="radio" name="radRadioButton" value="22" /><LABEL for="radRadioButton_4">Value 22</LABEL> </TD> </TR> </TABLE> <DIV id="panAnotherPanel"><BR> <TABLE cellpadding="0" cellspacing="0" border="0" style="display:inline;vertical-align:top;"> <TR> <TD valign="top"> <TEXTAREA name="DESC:txtTextArea" rows="3" cols="48" id="DESC_txtTextArea"></TEXTAREA>&nbsp; </TD> <TD valign="top"><SPAN id="DESC_lblCharCount" style="font-size:8pt;"></SPAN> </TD> </TR> </TABLE> </DIV> </DIV> Here is the function I've written: function clearChildren(node) { var child; if (node.childNodes.length > 0) { child= node.firstChild; } while(child) { if (child.type == "text") { alert(child.id); child.value = ""; } else if (child.type == "checkbox") { child.checked = false; } else if (child.type == "radio") { alert(child.id); child.checked = false; } else if (child.type == "textarea") { child.innerText = ""; } //alert(child.childNodes.length); if (child.childNodes.length > 0) { var grandchild = child.firstChild; while (grandchild) { clearChildren(grandchild); } grandchild = grandchild.nextSibling; } child = child.nextSibling; } }

    Read the article

  • Django, want to upload eather image (ImageField) or file (FileField)

    - by Serg
    I have a form in my html page, that prompts user to upload File or Image to the server. I want to be able to upload ether file or image. Let's say if user choose file, image should be null, and vice verso. Right now I can only upload both of them, without error. But If I choose to upload only one of them (let's say I choose image) I will get an error: "Key 'attachment' not found in <MultiValueDict: {u'image': [<InMemoryUploadedFile: police.jpg (image/jpeg)>]}>" models.py: #Description of the file class FileDescription(models.Model): TYPE_CHOICES = ( ('homework', 'Homework'), ('class', 'Class Papers'), ('random', 'Random Papers') ) subject = models.ForeignKey('Subjects', null=True, blank=True) subject_name = models.CharField(max_length=100, unique=False) category = models.CharField(max_length=100, unique=False, blank=True, null=True) file_type = models.CharField(max_length=100, choices=TYPE_CHOICES, unique=False) file_uploaded_by = models.CharField(max_length=100, unique=False) file_name = models.CharField(max_length=100, unique=False) file_description = models.TextField(unique=False, blank=True, null=True) file_creation_time = models.DateTimeField(editable=False) file_modified_time = models.DateTimeField() attachment = models.FileField(upload_to='files', blank=True, null=True, max_length=255) image = models.ImageField(upload_to='files', blank=True, null=True, max_length=255) def __unicode__(self): return u'%s' % (self.file_name) def get_fields(self): return [(field, field.value_to_string(self)) for field in FileDescription._meta.fields] def filename(self): return os.path.basename(self.image.name) def category_update(self): category = self.file_name return category def save(self, *args, **kwargs): if self.category is None: self.category = FileDescription.category_update(self) for field in self._meta.fields: if field.name == 'image' or field.name == 'attachment': field.upload_to = 'files/%s/%s/' % (self.file_uploaded_by, self.file_type) if not self.id: self.file_creation_time = datetime.now() self.file_modified_time = datetime.now() super(FileDescription, self).save(*args, **kwargs) forms.py class ContentForm(forms.ModelForm): file_name =forms.CharField(max_length=255, widget=forms.TextInput(attrs={'size':20})) file_description = forms.CharField(widget=forms.Textarea(attrs={'rows':4, 'cols':25})) class Meta: model = FileDescription exclude = ('subject', 'subject_name', 'file_uploaded_by', 'file_creation_time', 'file_modified_time', 'vote') def clean_file_name(self): name = self.cleaned_data['file_name'] # check the length of the file name if len(name) < 2: raise forms.ValidationError('File name is too short') # check if file with same name is already exists if FileDescription.objects.filter(file_name = name).exists(): raise forms.ValidationError('File with this name already exists') else: return name views.py if request.method == "POST": if "upload-b" in request.POST: form = ContentForm(request.POST, request.FILES, instance=subject_id) if form.is_valid(): # need to add some clean functions # handle_uploaded_file(request.FILES['attachment'], # request.user.username, # request.POST['file_type']) form.save() up_f = FileDescription.objects.get_or_create( subject=subject_id, subject_name=subject_name, category = request.POST['category'], file_type=request.POST['file_type'], file_uploaded_by = username, file_name=form.cleaned_data['file_name'], file_description=request.POST['file_description'], image = request.FILES['image'], attachment = request.FILES['attachment'], ) return HttpResponseRedirect(".")

    Read the article

  • File upload progress

    - by Cornelius
    I've been trying to track the progress of a file upload but keep on ending up at dead ends (uploading from a C# application not a webpage). I tried using the WebClient as such: class Program { static volatile bool busy = true; static void Main(string[] args) { WebClient client = new WebClient(); // Add some custom header information client.Credentials = new NetworkCredential("username", "password"); client.UploadProgressChanged += client_UploadProgressChanged; client.UploadFileCompleted += client_UploadFileCompleted; client.UploadFileAsync(new Uri("http://uploaduri/"), "filename"); while (busy) { Thread.Sleep(100); } Console.WriteLine("Done: press enter to exit"); Console.ReadLine(); } static void client_UploadFileCompleted(object sender, UploadFileCompletedEventArgs e) { busy = false; } static void client_UploadProgressChanged(object sender, UploadProgressChangedEventArgs e) { Console.WriteLine("Completed {0} of {1} bytes", e.BytesSent, e.TotalBytesToSend); } } The file does upload and progress is printed out but the progress is much faster than the actual upload and when uploading a large file the progress will reach the maximum within a few seconds but the actual upload takes a few minutes (it is not just waiting on a response, all the data have not yet arrived at the server). So I tried using HttpWebRequest to stream the data instead (I know this is not the exact equivalent of a file upload as it does not produce multipart/form-data content but it does serve to illustrate my problem). I set AllowWriteStreamBuffering to false and set the ContentLength as suggested by this question/answer: class Program { static void Main(string[] args) { FileInfo fileInfo = new FileInfo(args[0]); HttpWebRequest client = (HttpWebRequest)WebRequest.Create(new Uri("http://uploadUri/")); // Add some custom header info client.Credentials = new NetworkCredential("username", "password"); client.AllowWriteStreamBuffering = false; client.ContentLength = fileInfo.Length; client.Method = "POST"; long fileSize = fileInfo.Length; using (FileStream stream = fileInfo.OpenRead()) { using (Stream uploadStream = client.GetRequestStream()) { long totalWritten = 0; byte[] buffer = new byte[3000]; int bytesRead = 0; while ((bytesRead = stream.Read(buffer, 0, buffer.Length)) > 0) { uploadStream.Write(buffer, 0, bytesRead); uploadStream.Flush(); Console.WriteLine("{0} of {1} written", totalWritten += bytesRead, fileSize); } } } Console.WriteLine("Done: press enter to exit"); Console.ReadLine(); } } The request does not start until the entire file have been written to the stream and already shows full progress at the time it starts (I'm using fiddler to verify this). I also tried setting SendChunked to true (with and without setting the ContentLength as well). It seems like the data still gets cached before being sent over the network. Is there something wrong with one of these approaches or is there perhaps another way I can track the progress of file uploads from a windows application?

    Read the article

  • .NET Impersonate and file upload issues

    - by Jagd
    I have a webpage that allows a user to upload a file to a network share. When I run the webpage locally (within VS 2008) and try to upload the file, it works! However, when I deploy the website to the webserver and try to upload the file through the webpage, it doesn't work! The error being returned to me on the webserver says "Access to the path '\05prd1\emp\test.txt' is denied. So, obviously, this is a permissions issue. The network share is configured to allow full access both to me (NT authentication) and to the NETWORK SERVICE (which is .NET's default account and what we have set in our IIS application pool as the default user for this website). I have tried this with and without impersonation upon the webserver and neither way works, yet both ways work on my local machine (in other words, with and without impersonation works on my local machine). The code that does the file upload is below. Please note that the code below includes impersonation, but like I said above, I've tried it with and without impersonation and it's made no difference. if (fuCourses.PostedFile != null && fuCourses.PostedFile.ContentLength > 0) { System.Security.Principal.WindowsImpersonationContext impCtx; impCtx = ((System.Security.Principal.WindowsIdentity)User.Identity).Impersonate(); try { lblMsg.Visible = true; // The courses file to be uploaded HttpPostedFile file = fuCourses.PostedFile; string fName = file.FileName; string uploadPath = "\\\\05prd1\\emp\\"; // Get the file name if (fName.Contains("\\")) { fName = fName.Substring( fName.LastIndexOf("\\") + 1); } // Delete the courses file if it is already on \\05prd1\emp FileInfo fi = new FileInfo(uploadPath + fName); if (fi != null && fi.Exists) { fi.Delete(); } // Open new file stream on \\05prd1\emp and read bytes into it from file upload FileStream fs = File.Create(uploadPath + fName, file.ContentLength); using (Stream stream = file.InputStream) { byte[] b = new byte[4096]; int read; while ((read = stream.Read(b, 0, b.Length)) > 0) { fs.Write(b, 0, read); } } fs.Close(); lblMsg.Text = "File Successfully Uploaded"; lblMsg.ForeColor = System.Drawing.Color.Green; } catch (Exception ex) { lblMsg.Text = ex.Message; lblMsg.ForeColor = System.Drawing.Color.Red; } finally { impCtx.Undo(); } } Any help on this would be very appreciated!

    Read the article

  • Why my json_encode get corrupted

    - by Cullen SUN
    $model = new XUploadForm; $model->file = CUploadedFile::getInstance( $model, 'file' ); //We check that the file was successfully uploaded if( $model->file !== null ) { //Grab some data $model->mime_type = $model->file->getType( ); $model->size = $model->file->getSize( ); $model->name = $model->file->getName( ); $file_extention = $model->file->getExtensionName( ); //(optional) Generate a random name for our file $file_tem_name = md5(Yii::app( )->user->id.microtime( ).$model->name); $file_thumb_name = $file_tem_name.'_thumb.'.$file_extention; $file_image_name = $file_tem_name.".".$file_extention; if( $model->validate( ) ) { //Move our file to our temporary dir $model->file->saveAs( $path.$file_image_name ); if(chmod($path.$file_image_name, 0777 )){ // Yii::import("ext.EPhpThumb.EPhpThumb"); // $thumb_=new EPhpThumb(); // $thumb_->init(); // $thumb_->create($path.$file_image_name) // ->resize(110,80) // ->save($path.$file_thumb_name); } //here you can also generate the image versions you need //using something like PHPThumb //Now we need to save this path to the user's session if( Yii::app( )->user->hasState( 'images' ) ) { $userImages = Yii::app( )->user->getState( 'images' ); } else { $userImages = array(); } $userImages[] = array( "filename" => $file_image_name, 'size' => $model->size, 'mime' => $model->mime_type, "path" => $path.$file_image_name, // "thumb" => $path.$file_thumb_name, ); Yii::app( )->user->setState('images', $userImages); //Now we need to tell our widget that the upload was succesfull //We do so, using the json structure defined in // https://github.com/blueimp/jQuery-File-Upload/wiki/Setup echo json_encode( array( array( "type" => $model->mime_type, "size" => $model->size, "url" => $publicPath.$file_image_name, //"thumbnail_url" => $publicPath.$file_thumb_name, //"thumbnail_url" => $publicPath."thumbs/$filename", "delete_url" => $this->createUrl( "upload", array( "_method" => "delete", "file" => $file_image_name ) ), "delete_type" => "POST" ) ) ); Above code give me correct response, [{"type":"image/jpeg","size":2266,"url":"/uploads/tmp/0b00cbaee07c6410241428c74aae1dca.jpeg","delete_url":"/api/imageUpload/upload?_method=delete&file=0b00cbaee07c6410241428c74aae1dca.jpeg","delete_type":"POST"}] but if I uncomment the following // Yii::import("ext.EPhpThumb.EPhpThumb"); // $thumb_=new EPhpThumb(); // $thumb_->init(); // $thumb_->create($path.$file_image_name) // ->resize(110,80) // ->save($path.$file_thumb_name); it gave me corrupted response: Mac OS X 2??ATTR?dA??Y?Ycom.apple.quarantine0001;50655994;Google\x20Chrome.app;2599ECF9-69C5-4386-B3D9-9F5CC7E0EE1D|com.google.ChromeThis resource fork intentionally left blank ??[{"type":"image/jpeg","size":1941,"url":"/uploads/tmp/409c5921c6d20944e1a81f32b12fc380.jpeg","delete_url":"/api/imageUpload/upload?_method=delete&file=409c5921c6d20944e1a81f32b12fc380.jpeg","delete_type":"POST"}]

    Read the article

  • upload form only works in Firefox when uploading ASCII .stl 3D files

    - by NathanPDX
    uploadform.html and upload_file.php (below) works fine in Firefox but fails in Chrome, IE, and Safari when uploading ASCII .stl 3D files. Error message is "Invalid file" and problem occurs with multiple computers and multiple .stl files. When I modify the code to support other file types like JPG and PDF it allows those file types in all three web browsers. Also, Firefox only allows the .stl upload if I include application/octet-stream in the mime types section. Why doesn't this work outside of Firefox? uploadform.html: <!doctype html> <html> <body> <form action="upload_file.php" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <br /> <input type="submit" name="submit" value="Submit" /> </form> </body> </html> upload_file.php: <!doctype html> <html> <body> <?php $allowedExts = array("stl"); $extension = end(explode(".", $_FILES["file"]["name"])); if ( ( ($_FILES["file"]["type"] == "application/sla") || ($_FILES["file"]["type"] == "application/octet-stream") || ($_FILES["file"]["type"] == "text/plain") || ($_FILES["file"]["type"] == "application/unknown") ) && ($_FILES["file"]["size"] < 2000000) && in_array($extension, $allowedExts) ) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] /1024) . " KB<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "successful upload"; } } } else { echo "Invalid file"; } ?> </body> </html>

    Read the article

  • How to Publish InfoPath (which is fulltrusted having codebehid code ) in sharePoint?

    - by JanardhanReddy
    Hi all, I created one InfoPath form which is having C# code and i gave security option is 'full trusted' to access infopath object model,and it should be open with Browser.finally i published the Infopath form to SharePoint(by using admin-approved) site. But when i'am trying to open, it is not opening and giving an error that is 'InfoPath can not create a new or blank form InfoPath can not open the form,To fix this problem,Contact your System administrator' and in error show details its giving following message. 'The form template is trying to access files and settings on your computer. InfoPath cannot grant access to these files and settings because the form template is not fully trusted. For a form to run with full trust, it must be installed or digitally signed with a certificate'. please give me a solution.

    Read the article

  • How to debug Infopath2010 using VS2010

    - by ybbest
    In InfoPath 2010 , you can only use VSTO to write code for your form. However , when you try to debug you will see no attach to process option in the VSTO Project. In order to debug your InfoPath form , you have to do the following steps and debug using Visual Studio 2010. However , if you are not using InfoPath form services with SharePoint2010 and only using InfoPath Filler , you can see how to debug here. 1. You need to go to VSTO Project properties >> Build >> Advanced option >> Set the debug info to Full. (As shown below.) 2.Republish your form,this will rebuild your VSTO Project using the new build configurations. 3. Deploy the infopath form from the central admin and activate your form template to a site collection. If you have already deployed the form before , you need to do some clean up steps :     a.Delete all the infopath forms from the form library where you use your infopath form template as a content type     b.Remove the contentType from this form library     c.Deactivate the contype feature from the site collection features.     d.Delete the infopath form template from the central admin     e.Upload the new form template from from the central admin , you need to uncheck Upgrade the form template if it already exists     f.Activate the form template to the site collection and asscociate the contentType with your form library again. If the Above steps does not work , you need to delete the site collection and create a new one. 4. Open the FormCode.cs file you would like to debug in Visual studio 2010(just the file not the whole project),attach the w3wp.exe processes and set a breakpoint in the FormEvents_Loading event. Now if you add a new form to the form liabrary , the breakpoint should be hit.(See screenshot below) As mentioned above , if it does not hit.You might need to delete the site collection and create a new one.Delete the form template and reupload it again remember to uncheck Upgrade the form template if it already exists .Then you should be able to debug your infopath form.I do not see why debugging in InfoPath2010 is so much harder,but here we go.Happy SharePointing and InfoPathing .

    Read the article

  • Pushing updates to live server... FTP isn't cutting it... a better method?

    - by Jenkz
    I'm the lead developer in a team of 2. My partner has only just joined the project and despite using GIT for version control etc, we are still stuck in the dark ages when it comes to code deployment. Currently I make all site updates via FTP (this way I have control / responsibility over everything that goes live), using Filezilla. I've done this for years, but we now have some large PHP classes (300KB), and a lot of traffic. So in short, every time I upload a key class "general" for example, the site goes down until the file finishes uploading. This is only 5/6 seconds at a time, but this is increasingly unacceptable. I realise I can upload the file under a different name and then rename both files... but really there must be a better way? I've heard about rsyncing code across from another server, but I don't see how this prevents switching to the new file whilst uploading. We only have one server (for DB and Apache) but also use some cloud servers (for openx as an example).

    Read the article

  • Problem IIS 7.0 Locking files durring upload

    - by viscious
    I am running a server 2008 with iis7 and the ftp addon on to iis 7.0 I have the ftp site configured and mostly working Except that about 70% of the time when transferring a file the upload will hang forever. If I disconnect the ftp client and reconnect and try to upload the same file I will get an error on the client saying the file is locked. I have to restart the ftp service to clear the lock. I fired up process explorer and did a search on the file in question and sure enough the ftp service has a lock on the file and it takes around 20 minutes to release the lock on its own (and sometimes longer). This lock stays around even after I disconnect the client. Like I said this only happens about 70% of the time, the other 30% of the time it goes through just fine. Things i have verified. -Not a firewall issue. Server is using passive port range 8000-9000 which is allowed on the firewall. -Not a nat issue, server has a globally rout-able ip address -all recommended/required updates installed I have 5 other servers in a very similar configuration and this is the only one i have problems with.

    Read the article

  • Using psftp to upload and download files

    - by macha
    Hello I am trying to upload and download files from my desktop to my server. Now after some search I did download psftp. I used to use filezilla earlier, but I cannot install it on my desktop due to a few reasons. Since psftp (similar to putty) is just an executable for file transfer. So now after going through this link http://www.math.tamu.edu/~mpilant/math696/psftp.html. I understood that put and get are two commands I would use to download and upload files. Now when I logon to the server and say get filename, it actually is throwing back an error "local: unable to open filename". I tried that with other files too, and I end up getting the same error. The psftp.exe file is on my desktop. The process that I am using is I double click the .exe file open "servrname" cd /path/where/files/are get "filename" And I get this error "local: unable to open filename". Am I making a mistake or is it a problem with this executable?

    Read the article

  • Anonymous FTP upload on CentOS 5.2

    - by Craig
    I need to allow users to upload files to an FTP server anonymously. They should not be able to see any other files, or download files. It is a CentOS 5.2 server. I have a separate partition for the the upload area (mounted at /ftp). I have tried to set up vsftpd, followed all the instructions/advice I could find. But, when a user logs in and tries to transfer a file it throws a "553 could not create file." error. If I do a 'pwd' it shows the directory as "/" rather than the anon_root of "/ftp/anonymous". Any attempt to change the remote directory ends with "550 Failed to change directory.". I have a subdirectory "/ftp/anonymous/incoming" that is writable for the uploads SELinux is in permissive mode. I am running version 2.0.5 release 16.el5 of vsftpd. Here is the vsftpd.conf file: anonymous_enable=YES local_enable=YES write_enable=YES local_umask=002 anon_umask=007 file_open_mode=0666 anon_upload_enable=YES anon_mkdir_write_enable=NO dirmessage_enable=YES xferlog_enable=YES connect_from_port_20=YES chown_uploads=YES chown_username=inftpadm xferlog_std_format=YES nopriv_user=nobody listen=YES pam_service_name=vsftpd userlist_enable=YES tcp_wrappers=YES ftp_username=inftpadm anon_root=/ftp/anonymous anon_other_write_enable=NO anon_mkdir_write_enable=NO anon_world_readable_only=NO dirlist_enable=YES Can anyone help?

    Read the article

  • Setting the default permissions for files uploaded via FTP to a directory

    - by Kerri
    Disclaimer: I'm just a web designer/coder, and server admin stuff is my weakest point of them all. So be easy on me (and very specific). I'm using a simple CMS (Unify) on a site, where part of the functionality is that the client can upload files to a specified directory (using FTP). The permissions for the upload directory are set to 755. But when files are uploaded through the interface, they are uploaded with permissions set to 640 (instead of 644), so site visitors cannot acces the files. When I emailed the CMS's support about this, they told me that it was a server setting, and I need to make sure that files uploaded through FTP are set to 644. Makes perfect sense, but I have no idea how to do this. Any help would be greatly appreciated. This site is a shared site hosted by Network Solutions (Unix), so my access options are limited. I can edit .htaccess files, and php.ini, but that's about all I have access to. It appears I can't even log on via shell. ETA: 11/11/2010 Thanks all. I was able to work around this problem by setting up the CMS's settings in a different way. I'd be interested in following up on Nick O'Niel's suggestions, because I think he's on the right track, but unfortunately I can't access the necessary files on this particular server. So, anyway, I'm leaving this open, since the original questions isn't exactly resolved. Unfortunately, I probably can't put a correct answer to the test, since the shared server in question has nearly all of its config files tightly locked down.

    Read the article

  • Rails 3 Form For Custom Action

    - by Andrew
    I'm having trouble routing a form to a custom action in Rails 3. Here are my routes: resources :photos do resources :comments collection do get 'update_states' end member do put 'upload' end end Here's the form_for: form_for @photo, :remote => true, :url => { :action => upload_photo_path(@photo) }, :html => { :multipart => :true, :method => 'put' } do |f| And here's the error message: No route matches {:action=>"/photos/42/upload", :controller=>"photos"} ... this is especially frustrating because "photos/:id/upload" is exactly the correct action for this form. What am I missing? EDITS - Here are the original Photo-related routes: photo_comments GET /photos/:photo_id/comments(.:format) {:action=>"index", :controller=>"comments"} POST /photos/:photo_id/comments(.:format) {:action=>"create", :controller=>"comments"} new_photo_comment GET /photos/:photo_id/comments/new(.:format) {:action=>"new", :controller=>"comments"} edit_photo_comment GET /photos/:photo_id/comments/:id/edit(.:format) {:action=>"edit", :controller=>"comments"} photo_comment GET /photos/:photo_id/comments/:id(.:format) {:action=>"show", :controller=>"comments"} PUT /photos/:photo_id/comments/:id(.:format) {:action=>"update", :controller=>"comments"} DELETE /photos/:photo_id/comments/:id(.:format) {:action=>"destroy", :controller=>"comments"} update_states_photos GET /photos/update_states(.:format) {:action=>"update_states", :controller=>"photos"} upload_photo PUT /photos/:id/upload(.:format) {:action=>"upload", :controller=>"photos"} photos GET /photos(.:format) {:action=>"index", :controller=>"photos"} POST /photos(.:format) {:action=>"create", :controller=>"photos"} new_photo GET /photos/new(.:format) {:action=>"new", :controller=>"photos"} edit_photo GET /photos/:id/edit(.:format) {:action=>"edit", :controller=>"photos"} photo GET /photos/:id(.:format) {:action=>"show", :controller=>"photos"} PUT /photos/:id(.:format) {:action=>"update", :controller=>"photos"} DELETE /photos/:id(.:format) {:action=>"destroy", :controller=>"photos"} Here are the relevant routes when I changed the route to match 'upload': photo_comments GET /photos/:photo_id/comments(.:format) {:action=>"index", :controller=>"comments"} POST /photos/:photo_id/comments(.:format) {:action=>"create", :controller=>"comments"} } new_photo_comment GET /photos/:photo_id/comments/new(.:format) {:action=>"new", :controller=>"comments"} edit_photo_comment GET /photos/:photo_id/comments/:id/edit(.:format) {:action=>"edit", :controller=>"comments"} photo_comment GET /photos/:photo_id/comments/:id(.:format) {:action=>"show", :controller=>"comments"} PUT /photos/:photo_id/comments/:id(.:format) {:action=>"update", :controller=>"comments"} DELETE /photos/:photo_id/comments/:id(.:format) {:action=>"destroy", :controller=>"comments"} update_states_photos GET /photos/update_states(.:format) {:action=>"update_states", :controller=>"photos"} upload_photo /photos/:id/upload(.:format) {:action=>"upload", :controller=>"photos"} photos GET /photos(.:format) {:action=>"index", :controller=>"photos"} POST /photos(.:format) {:action=>"create", :controller=>"photos"} new_photo GET /photos/new(.:format) {:action=>"new", :controller=>"photos"} edit_photo GET /photos/:id/edit(.:format) {:action=>"edit", :controller=>"photos"} photo GET /photos/:id(.:format) {:action=>"show", :controller=>"photos"} PUT /photos/:id(.:format) {:action=>"update", :controller=>"photos"} DELETE /photos/:id(.:format) {:action=>"destroy", :controller=>"photos"} Unfortunately 'match' didn't work any better... -- EDIT -- Just to confirm another scenario here... with this in the routes: resources :photos do resources :comments collection do get 'update_states' end member do match 'upload' end end and this in the view: form_for @photo, :remote => true, :url => { :action => 'upload' }, :html => { :multipart => :true, :id => 'photo_upload' } do |f| I still get: No route matches {:action=>"upload", :controller=>"photos"}

    Read the article

  • Is there a W3C valid way to disable autocomplete in a HTML form?

    - by matt b
    When using the xhtml1-transitional.dtd doctype, collecting a credit card number with the following HTML <input type="text" id="cardNumber" name="cardNumber" autocomplete='off'/> will flag a warning on the W3C validator: there is no attribute "autocomplete". Is there a W3C / standards way to disable browser auto-complete on sensitive fields in a form?

    Read the article

  • how find out the form is submit in JSP?

    - by user261002
    I am trying to create a an online exam with JSP. I want to get the questions one by one and show them on the screen, and create a "Next" button then user is able to to see the next question, but the problem is that I dont know how to find out that the user has clicked on the "Next" button, I know how to do it in PHP : if($_SERVER['REQUEST_METHOD']=='GET') if($_GET['action']=='Next') but I dont know how to do it in JSP. Please help me this is piece of my code: String result = ""; if (database.DatabaseManager.getInstance().connectionOK()) { database.SQLSelectStatement sqlselect = new database.SQLSelectStatement("question", "question", "0"); ResultSet _userExist = sqlselect.executeWithNoCondition(); ResultSetMetaData rsm = _userExist.getMetaData(); result+="<form method='post'>"; result += "<table border=2>"; for (int i = 0; i < rsm.getColumnCount(); i++) { result += "<th>" + rsm.getColumnName(i + 1) + "</th>"; } if (_userExist.next()) { result += "<tr>"; result += "<td>" + _userExist.getInt(1) + "</td>"; result += "<td>" + _userExist.getString(2) + "</td>"; result += "</tr>"; result += "<tr>"; result += "<tr> <td colspan='2'>asdas</td></tr>"; result += "</tr>"; } result += "</table>"; result+="<input type='submit' value='next' name='next'/></form>"; }

    Read the article

  • Javascript form validation on client side without server side - is it safe?

    - by Vitali Ponomar
    Supose I have some form with javascript client side validation and no server side validation. If user disable javascript in his browser there will no be submit button so he can not send me any data without js enabled. But I do not know is there any way to change my validation instructions from client browser so he could send me untrusted data and make some damage to my database. Thanks in advance and sorry for my (possibly) obvious question!!!

    Read the article

< Previous Page | 44 45 46 47 48 49 50 51 52 53 54 55  | Next Page >