Search Results

Search found 34274 results on 1371 pages for 'mysql table'.

Page 480/1371 | < Previous Page | 476 477 478 479 480 481 482 483 484 485 486 487  | Next Page >

  • Editing/Updating one of the results in a search query.

    - by eggman20
    Hi guys. I'm creating a page that searches for an item and then be able to edit/update it. I was able to do it when it returns just one result but when it gives me multiple results I could only edit the very last item. Below is my code: ....... $dj =$_POST[djnum]; $sql= "SELECT * From dj WHERE datajack LIKE '$dj%'"; $result = mysql_query($sql); //more code in here// while ($info =mysql_fetch_array($result)) { // display the result echo "<form action=\"dj_update.php\" method=\"POST\"><input type=\"hidden\" name=\"djnumber\" value=\"".$info['datajack']."\">"; echo "<tr><td>DJ ".$info['datajack']."</td>"; echo "<td>".$info['building']."&nbsp;</td>"; echo "<td>Rm ".$info['room']."&nbsp;</td>"; echo "<td>".$info['switch']."&nbsp;</td>"; echo "<td>".$info['port']."&nbsp;</td>"; echo "<td>".$info['notes']."&nbsp;</td>"; echo "<td style=\"text-align:center;\"><input type=\"Submit\" value=\"Edit\" ></td></tr>"; } // more code here // Then this is the screen shot of the result: The idea is the user should be able to click on "Edit" and be able to edit/update that particular item. But when I click any of the Edit button I could only edit the last item. What am I missing here? Is there an easier way to do this? Thanks guys and Happy new year!

    Read the article

  • Caption in longtable

    - by Tim
    Hi, I find that the caption in my longtable takes two lines but it seems that it can fit in one line. See the figure below: http://i42.tinypic.com/96dqms.jpg My code is: \begin{longtable}{|c|c|c|c||c|c|c|} \caption{Testing error for training size 100000 and 8000 random counts\label{tab:1}}\\ \hline \multicolumn{2}{|c|}{Concept} & \multicolumn{2}{c||}{Negative Class} & \multicolumn{2}{c|}{Positive Class} & Error rate \\ \hline ... \end{longtable} How to make the caption fit into a single line? Thanks and regards!

    Read the article

  • SQL Query Returning Duplicate Results

    - by Jesse Bunch
    Hi, I've been working out this query now for a while and I thought I had it where I wanted it, but apparently not. There are two records in the database (orders). The query should return two different rows, but instead returns two rows that have exactly the same values. I think it may be something to do with the GROUP BY or derived tables I'm using but my eyes are tired and not seeing the problem. Can any of you help? Thanks in advance. SELECT orders.billerID, orders.invoiceDate, orders.txnID, orders.bName, orders.bStreet1, orders.bStreet2, orders.bCity, orders.bState, orders.bZip, orders.bCountry, orders.sName, orders.sStreet1, orders.sStreet2, orders.sCity, orders.sState, orders.sZip, orders.sCountry, orders.paymentType, orders.invoiceNotes, orders.pFee, orders.shipping, orders.tax, orders.reasonCode, orders.txnType, orders.customerID, customers.firstName AS firstName, customers.lastName AS lastName, customers.businessName AS businessName, orderStatus.statusName AS orderStatus, IFNULL(orderItems.itemTotal, 0.00) + orders.shipping + orders.tax AS orderTotal, IFNULL(orderItems.itemTotal, 0.00) + orders.shipping + orders.tax - IFNULL(payments.totalPayments, 0.00) AS orderBalance FROM orders LEFT JOIN customers ON orders.customerID = customers.id LEFT JOIN orderStatus ON orders.orderStatus = orderStatus.id LEFT JOIN ( SELECT orderItems.orderID, SUM(orderItems.itemPrice * orderItems.itemQuantity) as itemTotal FROM orderItems GROUP BY orderItems.orderID ) orderItems ON orderItems.orderID = orders.id LEFT JOIN ( SELECT payments.orderID, SUM(payments.amount) as totalPayments FROM payments GROUP BY payments.orderID ) payments ON payments.orderID = orders.id

    Read the article

  • CSS3 transition on table row using height property

    - by Alexis Leclerc
    I have an HTML table displaying some information with a few rows. On each row, the user can click to reveal some additional rows that contains information related to the clicked row. Something like this: While the additional rows are being created with an AJAX request, a loading row is inserted right after the clicked row : Currently, everything works perfectly (drill down style), but I would like to add some animation to the loading row. I found a question ( this one ) that has a JSFiddle showing kind of what I want ( this fiddle ). I tried to implement something similar with CSS3 transitions, but I can't get it to work. Here's my simulated attempt ( fiddle only for deployment of the loading row ) using these transitions : -webkit-transition: height 0.1s ease-in-out; -moz-transition: height 0.1s ease-in-out; -ms-transition: height 0.1s ease-in-out; -o-transition: height 0.1s ease-in-out; transition: height 0.1s ease-in-out; Any thought on why my fiddle doesn't do any animation? Any other methods you would propose? Thanks!

    Read the article

  • Solr; "rookie" question

    - by Camran
    I have a SolrPhpClient on my classifieds website, and whenever users wants to add/remove classified the index in Solr gets updated via Php code. So I wonder, does this mean that my Solr index is open for anybody to alter with? Same Q applies to the Solr Admin page. If I set a password for the admin page, does this mean that my classifieds website wont have access to updating/removing documents from the Solr index? Thanks

    Read the article

  • SQL to CodeIgniter Array Missing Data Issue

    - by SamD
    $query = $this->db->query("SELECT t1.numberofbets, t1.profit, t2.seven_profit, t3.28profit, user.user_id, username, password, email, balance, user.date_added, activation_code, activated FROM user LEFT JOIN (SELECT user_id, SUM(amount_won) AS profit, count(tip_id) AS numberofbets FROM tip GROUP BY user_id) as t1 ON user.user_id = t1.user_id LEFT JOIN (SELECT user_id, SUM(amount_won) AS seven_profit FROM tip WHERE date_settled > '$seven_daystime' GROUP BY user_id) as t2 ON user.user_id = t2.user_id LEFT JOIN (SELECT user_id, SUM(amount_won) AS 28profit FROM tip WHERE date_settled > '$twoeight_daystime' GROUP BY user_id) as t3 ON user.user_id = t3.user_id where activated = 1 GROUP BY user.user_id ORDER BY user.date_added DESC"); return $query->result_array(); The query works fine running it in phpMyAdmin and returns complete results (in image attached). However, printing the array in CodeIgniter, it has no value for one field ,seven_profit, where it is there in the SQL query ran in phpMyAdmin, just the discrepancy in this one field, from sql to php array... I just can’t see why, when printing the array, that one field, which should have value of 26, contains nothing? Any ideas? I changed the field name from starting with a number in attempt to fix it, but no difference. I know this is complex and looks horrible, any help or just people coming across something similar would be great to know about, thanks. Sam

    Read the article

  • PHP function returns ZERO.

    - by hypnocode
    Hi guys, I'm having trouble with this PHP function. It keeps returning zero, but I know the SQL statement works because I've queried it myself. Any ideas what I'm doing wrong? The last line makes no sense to me...I'm editing this code that someone else wrote. This function should return a number in the hundreds, assuming the date is in March. Thanks! function getCountBetweenDays($day1,$day2,$service) { global $conn; if ($service==1){ $query = "SELECT COUNT(*) as NUM FROM `items` WHERE `modified` BETWEEN '$day1 00:00:00' AND '$day2 23:59:59';";} elseif($service==2){ $query = "SELECT COUNT(*) as NUM FROM `items` WHERE `modified` BETWEEN '$day1 00:00:00' AND '$day2 23:59:59';";} elseif($service==3){ $query = "SELECT COUNT(*) as NUM FROM `items` WHERE `modified` BETWEEN '$day1 00:00:00' AND '$day2 23:59:59';";} $result = mysql_query($query,$conn); $num = mysql_fetch_array ($result); return $num['NUM']; }

    Read the article

  • PHP pagination class

    - by Lizard
    I am looking for a php pagination class, I have used a rather simple one in the past and it is no longer supported. I was wondering if anyone had any recommendations ? It seems pointless to build my own when there are probably so many good ones out there. Thanks in advnace!

    Read the article

  • Active User Tracking, PHP Sessions

    - by Nik
    Alright, I'm trying to work on a function for active user counting in an AJAX based application. I want to express the below SQL Query in correct syntax but I'm not sure how to write it. The desired SQL Query is below: SELECT count(*) FROM active WHERE timestamp > time() - 1800 AND nick=(a string that doesn't contain [AFK]) Now, I do understand that time() - 1800 can be assigned to a variable, but how is timestamp > variable and nick that doesn't contain a string written in SQL?

    Read the article

  • Joomla - Joomfish Error Blank index.php

    - by Ivan Slaughter
    I have joomla error since installing multilanguage with joomfish. I'm using Joomla 1.5.11 and Joomfish 2.0.4. Resulting a blank page. How to trace error? since using joomla default error reporting doesn't work. still blank page with nothing. Please help, cause i can't figure out the error?

    Read the article

  • (My)SQL performance: updating one field vs many unneccesary fields

    - by changokun
    i'm processing a form that has a lot of fields for a user who is editing an existing record. the user may have only changed one field, and i would typically do an update query that sets the values of all the fields, even though most of them don't change. i could do some sort of tracking to see which fields have actually changed, and only update the few that did. is there a performance difference between updating all fields in a record vs only the one that changed? are there other reasons to go with either method? the shotgun method is pretty easy...

    Read the article

  • Cloud Database Service Latency/Performance

    - by Gcoop
    Hi All, I am running a heavy traffic site and our server is beginning to get to its limits, at the moment the entire LAMP stack is on one box (not ideal). I would like to move the database onto it's own box or onto a cloud service, but from my previous experience moving the database off the same box as the webserver increases the latency of reads quite dramatically slowing down the site. Is using a cloud service for this going to overcome this problem, because as far as I can tell its essentially the same situation (as moving it onto a separate box in my control)? In which case why is there so much popularity around cloud based database services at the moment? Are cloud based database services so quick that the latency of reads is so low that its almost like having it on the same box in the same datacentre?

    Read the article

  • Syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in PHP

    - by pmms
    mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $result=mysql_query("select * from jos_users INTO OUTFILE 'users.csv' FIELDS ESCAPED BY '""' TERMINATED BY ',' ENCLOSED BY '"' LINES TERMINATED BY '\n' "); header("Content-type: text/plain"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Content-Transfer-Encoding: binary"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; in the above code in query string i.e string in side mysql_quey we are getting following error Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in C:\wamp\www\samples\mysql_excel\exel_outfile.php on line 8 in query string '\n' charter is not identifying as string thats why above error getting

    Read the article

  • social networking website database management

    - by Anup Prakash
    This could be very basic type of question for you! But for me it is very important. 1) How these(orkut, facebook or other) website store the images in server? Options: a) Keeping all the images in database by converting into bytecode/binary. b) Making a new folder for each user and saving photographs according to their library name. c) Or something else which i(Anup) didn't guess yet. Please reply me. Sayiing thanx to see my question and any many many thanx for answering my question.

    Read the article

  • SQL How to join multiplue columns with same name to one column

    - by Choi Shun Chi
    There is a super class account {User, TYPE} and subclasses saving{User, ID, balance,TYPE,interest,curency_TYPE} time{User,ID,balance,TYPE,interest,curency_TYPE,start_date,due_date,period} fore{User,ID,balance,interest,curency_TYPE} User and TYPE is the primary key of account and foreign key of three subclasses ID is primary key of three subclasses how to make a list of showing all IDs in one column?Also the same as balance and TYPE meet the problem I considered a.ID as saving, b.ID as time but it showing them separately

    Read the article

  • Frame of viewForHeaderInSection is always the same size

    - by gabac
    - (UIView *)tableView:(UITableView *)tableView viewForHeaderInSection:(NSInteger)section { if(section != 0) { UIView *view = [[UIView alloc] initWithFrame:CGRectMake(10, 10, 100, 30)]; view.backgroundColor = [UIColor redColor]; return view; [view release]; } else { return tableView.tableHeaderView; } } This is my implementation of viewForHeaderInSection but whatever frame I make it's always showing me the same red frame. Do you see any problem with my code? Can't post the picture because of my rep but here is the link ;-) http://img638.imageshack.us/img638/3350/bildschirmfoto20100315uq.png

    Read the article

  • LINQ for Java tool

    - by Milhous
    Would a LINQ for java be a useful tool? I have been working on a tool that will allow a Java object to map to a row in a database. Would this be useful for Java programmers? What features would be useful?

    Read the article

  • please help me in this query

    - by testkhan
    I have three tables (user, friends, posts) and two users (user1 and user2). When user1 adds user2 as friend then user1 can see the posts of user2 just like on Facebook. But only the posts after the date when user1 added user2 as friend. My query is like this: $sql = mysql_query("SELECT * FROM posts p JOIN friends f ON p.currentuserid = f.friendid AND p.time >= f.friend_since OR p.currentuserid='user1id' WHERE f.myid='user1id' ORDER BY p.postid DESC LIMIT 20"); it is working all the way fine but with a little problem.....!! it displays user2, user3 (all the users as friends of user1) posts for single time but shows user1 posts multiple.......i.e user2. hi user1. userssfsfsfsfsdf user1. userssfsfsfsfsdf user3. dddddddd user1. sdfsdsdfsdsfsf user1. sdfsdsdfsdsfsf but i in database it is single entry/post why it is happening........!! How can I fix it?

    Read the article

  • LINQ expression precedence with Skip(), Take() and OrderBy()

    - by Robert Koritnik
    I'm using LINQ to Entities and display paged results. But I'm having issues with the combination of Skip(), Take() and OrderBy() calls. Everything works fine, except that OrderBy() is assigned too late. It's executed after result set has been cut down by Skip() and Take(). So each page of results has items in order. But ordering is done on a page handful of data instead of ordering of the whole set and then limiting those records with Skip() and Take(). How do I set precedence with these statements? My example (simplified) var query = ctx.EntitySet.Where(/* filter */).OrderBy(/* expression */); int total = query.Count(); var result = query.Skip(n).Take(x).ToList();

    Read the article

  • Why does this query only select a single row?

    - by Joe
    SELECT * FROM tbl_houses WHERE (SELECT HousesList FROM tbl_lists WHERE tbl_lists.ID = '123') LIKE CONCAT('% ', tbl_houses.ID, '#') It only selects the row from tbl_houses of the last occuring tbl_houses.ID inside tbl_lists.HousesList I need it to select all the rows where any ID from tbl_houses exists within tbl_lists.HousesList

    Read the article

  • Reset ID autoincrement ? phpmyadmin

    - by Marcelo
    Hi, I was testing some data in my tables of my database, to see if there was any error, now I cleaned all the testing data, but my id (auto increment) does not start from 1 anymore, can (how do) I reset it ? Sorry for any mistake in English, and thanks for the attention.

    Read the article

< Previous Page | 476 477 478 479 480 481 482 483 484 485 486 487  | Next Page >