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  • Getting a table's values into a tree

    - by Jason
    So, I have a table like such: id|root|kw1|kw2|kw3|kw4|kw5|name 1| A| B| C| D| E| F|fileA 2| A| B| | | | |fileB 3| B| C| D| E| | |fileC 4| A| B| | | | |fileD (several hundred rows...) And I need to get it into a tree like the following: *A *B -fileB -fileD *C *D *E *F -fileA *B *C *D *E -fileC I'm pretty sure the table is laid out poorly but it's what I have to live with. I've read a little about Adjacency List Model & Modified Preorder Tree Traversal but I don't think my data is laid out correctly. I think this requires a recursive function, but I'm not at all sure how to go about that. I'm open to any ideas of how to get this done even if it means extracting the data into a new table just to process this. Are there any good options available to me or any good ways to do this? (Examples are a bonus of course)

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  • SQL: How to order values inside group by

    - by Denis Yaremov
    Consider the following MS SQL Server table: ID | X | Y ------+-------+------- 1 | 1 | 1 2 | 1 | 2 3 | 1 | 3 4 | 2 | 40 5 | 2 | 500 6 | 3 | 1 7 | 3 | 100 8 | 3 | 10 I need to select the ID of the row that has the maximum value of Y grouped by x, i.e: ID | X | Y ------+-------+------- 3 | 1 | 3 5 | 2 | 500 7 | 3 | 100 The query will be nested several times so an optimal performance solution is required... Thank you!

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  • While loop in foreach loop not looping correctly

    - by tominated
    I'm trying to make a very basic php ORM as for a school project. I have got almost everything working, but I'm trying to map results to an array. Here's a snippet of code to hopefully assist my explanation. $results = array(); foreach($this->columns as $column){ $current = array(); while($row = mysql_fetch_array($this->results)){ $current[] = $row[$column]; print_r($current); echo '<br><br>'; } $results[$column] = $current; } print_r($results); return mysql_fetch_array($this->results); This works, but the while loop only works on the first column. The print_r($results); shows the following: Array ( [testID] => Array ( [0] => 1 [1] => 2 ) [testName] => Array ( ) [testData] => Array ( ) ) Can anybody shed some light? Thanks in advance!

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  • How to check with PHP does a SQL database already have

    - by Dan Horvat
    I've tried to find the answer to this question but none of the answers fit. I have two databases, one has 15.000.000 entries and I want to extract the necessary data and store it in a much smaller database with around 33.000 entries. Both databases are open at the same time. Or at least they should be. While having the big database open and extracting the entries from it, is it possible to check whether the value already exists in the smaller database? I just need some generic way which checks that.

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  • How to set a filter for an estimated maximum price

    - by David
    I cannot figure out how to set an estimated maximum price for a collection of records. What I want to avoid is to simply use SQL MAX, because maybe there are records with exorbitant prices. For example, in the "computers-hardware" category of OLX (http://www.olx.com/computers-hardware-cat-240) the filter for maximum price is estimately set to $1400, but sorting by price, the first items are above $10000 Maybe they calculated the average and then estimated some maximum price... what do you think? And what about the stepping? How would you calculate it?

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  • Hibernate deletion issue

    - by muffytyrone
    I'm trying to write a Java app that imports a data file. The process is as follows Create Transaction Delete all rows from datatable Load data file into datatable Commit OR Rollback if any errors were encountered. The data loaded in step 3 is mostly the same as the data deleted in step3. The deletion is performed using the following DetachedCriteria criteria = DetachedCriteria.forClass(myObject.class); List<myObject> myObjects = hibernateTemplate.findByCriteria(criteria); hibernateTemplate.deleteAll(myObjects); When I then load the datafile, i get the following exception nested exception is org.hibernate.NonUniqueObjectException: a different object with the same identifier value was already associated with the session: The whole process needs to take place in transaction. And I don't really want to have to compare the import file / data table and then perform an insert/update/delete to get them into sync. Any help would be appreciated.

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  • Trying to grab several random videos from database, but it just shows the same one all the time.

    - by Birk
    Hi guys, I'm trying to grab several random videos from my database, and have them show on a page. However, it just keeps on grabbing the same video rather than several different ones. So I end up with 5 of the same video rather than 5 different ones. Here's the grab random PHP code file... and after it is the template output file. //===================================================== // Random | Previous | Next //===================================================== $show['random'] = $db->quick_fetch( "SELECT file_id, title, title_seo, category_id, thumb FROM files WHERE files.category_id = '".$show['main']['category_id']."' AND files.verified=1 ORDER BY RAND() LIMIT 0,1; "); Here's the template CSS html thingy code I have this pasted 5 times to show 5 random videos <td valign="top" width="53%"><? $sql="select * from files ORDER BY rand() limit 0,5"; $res=@mysql_query($sql); $data=@mysql_result($res,0,'filename'); $id=@mysql_result($res,0,'file_id'); $title=@mysql_result($res,0,'title'); $title2=str_replace(" ", "-",$title); $path="{$siteurl}/media/{$file.random.file_id}/{$file.random.title_seo}/"; $img="{$siteurl}/thumbs/{$file.random.thumb}"; echo " {$file.random.title}"

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  • Determining the popularity of a video with ratings and views

    - by user295825
    I am about to embark on a new project - a video website. Users will be able to register, and vote on videos by clicking "like" or "dislike", or something to that effect. In any event, it will be a 2-option voting system, not a 5-star system. Every X number of days, I will be generating a "chart" of the most popular videos. So my question is: how should I determine the popularity of a given video? If I went the route of tallying up the videos with the most views, this could have the effect of exceptionally bad videos making it to the of the charts (just because they're so bad). If I go the route of a scoring system based on the amount of "like" and "dislike" votes (eg. 100 like votes, and 50 dislike votes equals a score of 2), videos with few views could appear on the top of the charts. So, what I need to do is a combination of the two. Barring, of course, spammy views and votes. What's your guys' thoughts on the subject?

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  • alter mysqldump file before import

    - by julio
    Hi-- I have a mysqldump file created from an earlier version of a product that can't be imported into a new version of the product, since the db structure has changed slightly (mainly altering a column that was NOT NULL DEFAULT 0 to UNIQUE KEY DEFAULT NULL). If I just import the old dump file, it will error out since the column that has default values of 0 now breaks the UNIQUE constraint. It would be easy enough to either manually alter the mysqldump file, or import into a temp table and change it, then copy to the new table. However, is there a way to do this programatically, so it will be repeatable and not manual? (this will need to happen for many instances of this product). I'm thinking something like disabling key constraints for the import, then setting all values that = 0 to NULL, then re-enabling the key constraints? Is this possible? Any help appreciated.

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  • making sure "expiration_date - X" falls on a valid "date_of_price" (if not, use the next valid date_

    - by bobbyh
    I have two tables. The first table has two columns: ID and date_of_price. The date_of_price field skips weekend days and bank holidays when markets are closed. table: trading_dates ID date_of_price 1 8/7/2008 2 8/8/2008 3 8/11/2008 4 8/12/2008 The second table also has two columns: ID and expiration_date. The expiration_date field is the one day in each month when options expire. table: expiration_dates ID expiration_date 1 9/20/2008 2 10/18/2008 3 11/22/2008 I would like to do a query that subtracts a certain number of days from the expiration dates, with the caveat that the resulting date must be a valid date_of_price. If not, then the result should be the next valid date_of_price. For instance, say we are subtracting 41 days from the expiration_date. 41 days prior to 9/20/2008 is 8/10/2008. Since 8/10/2008 is not a valid date_of_price, we have to skip 8/10/2008. The query should return 8/11/2008, which is the next valid date_of_price. Any advice would be appreciated! :-)

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  • how to join 3 relational tables

    - by orioncabbar
    Hello there, how to join 3 relational tables with the structure: t1 | id t2 | id | rating t3 | source_id | relation t3 stores the data of a field which t1 and t2 uses both. so source_id field can be t1's id or t2's id. input : t1 id output : t2 rating an example: **t1** id | --------- 42 | **t2** id | rating ------------- 37 | 9.2 **t3** id | source_id -------------- 42 | 1 37 | 1 26 | 2 23 | 1 what i want is to get 9.2 output with 42 input. can you do that in one sql query?

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  • Selecting records with specific month and year in SQL Server 2005

    - by John
    I want to list records with a particular month and year. The table name is 'Arrival' and 'date' is the field that stores the date that the record was added. This is to be done from a C# application. For example, if the user selects month as 'April' and year as '2009' in the application, it will list all the records that were added on April,2009. (I only need the query, hope I can figure out the rest :) )

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  • sql UPDATE, a calculation is used multiple times, can it just be calculated once?

    - by Zachery Delafosse
    UPDATE `play` SET `counter1` = `counter1` + LEAST(`maxchange`, FLOOR(`x` / `y`) ), `counter2` = `counter2` - LEAST(`maxchange`, FLOOR(`x` / `y`) ), `x` = MOD(`x`, `y`) WHERE `x` `y` AND `maxchange` 0 As you can see, " LEAST(`maxchange`, FLOOR(`x` / `y`) ) " is used multiple times, but it should always have the same value. Is there a way to optimize this, to only calculate once? I'm coding this in PHP, for the record.

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  • Best way to construct this query?

    - by Andrew
    I have two tables set up similar to this (simplified for the quest): actions- id - user_id - action - time users - id - name I want to output the latest action for each user. I have no idea how to go about it. I'm not great with SQL, but from what I've looked up, it should look something like the following. not sure though. SELECT `users`.`name`, * FROM users, actions JOIN < not sure what to put here > ORDER BY `actions`.`time` DESC < only one per user_id > Any help would be appreciated.

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  • Get the first and last posts in a thread

    - by Grampa
    I am trying to code a forum website and I want to display a list of threads. Each thread should be accompanied by info about the first post (the "head" of the thread) as well as the last. My current database structure is the following: threads table: id - int, PK, not NULL, auto-increment name - varchar(255) posts table: id - int, PK, not NULL, auto-increment thread_id - FK for threads The tables have other fields as well, but they are not relevant for the query. I am interested in querying threads and somehow JOINing with posts so that I obtain both the first and last post for each thread in a single query (with no subqueries). So far I am able to do it using multiple queries, and I have defined the first post as being: SELECT * FROM threads t LEFT JOIN posts p ON t.id = p.thread_id ORDER BY p.id LIMIT 0, 1 The last post is pretty much the same except for ORDER BY id DESC. Now, I could select multiple threads with their first or last posts, by doing: SELECT * FROM threads t LEFT JOIN posts p ON t.id = p.thread_id ORDER BY p.id GROUP BY t.id But of course I can't get both at once, since I would need to sort both ASC and DESC at the same time. What is the solution here? Is it even possible to use a single query? Is there any way I could change the structure of my tables to facilitate this? If this is not doable, then what tips could you give me to improve the query performance in this particular situation?

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  • problem in creating a php tree menu

    - by Mac Taylor
    hi mates im writing a tree menu for my categories in php and i wonder how can i code it correctly ! this is my table in database " |----topicid------topicname--------parent | |---- 1 ------ News -------- 0 | |---- 2 ------ sport -------- 1 | |---- 3 ------ games -------- 1 | |---- 4 ------ PES -------- 3 | so now for showing it like a tree i did try but not worked : $result = mysql_query("SELECT * FROM Topics ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; if ($parent==0) { $menu_item .= "<li><span class='folder'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li>"; }else { $result = mysql_query("SELECT * FROM ".$prefix."_Topics where parent='$id' ORDER BY topicid"); while ($row = mysql_fetchrow($result)) { $id = intval($row['topicid']); $title = filter($row['topicname'], "nohtml"); $parent = $row['parent'] ; $menu_item .= " <ul><li><span class='file'><a title = \"$alt\" href=\"modules.php?name=News&amp;new_topic=$id\">$title</a></span></li></ul>"; } } i dont know how to solve this

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  • HOw Do I update from table-2 to table-1

    - by mathew
    HI what is the wrong in this code?? i have set it 24 hours to update the value in the table.but the problem is if $row is empty then it inserts value from table-2 but after 24 hours it wont update the value. what I want is it must delete the existing value and insert new one(random value) or it must update the same $row with new value what ever... if ($row == 0){ mysql_query("INSERT INTO table-1 (regtime,person,location,address,rank,ip,geocode) SELECT NOW(),person,location,address,rank,ip,geocode FROM table-2 ORDER BY RAND() LIMIT 1");}else{ mysql_query("UPDATE table-1 SELECT regtime=NOW(), person=person, location=location, address=address, rank=rank, ip=ip, geocode=geocode FROM table-2 ORDER BY RAND() LIMIT 1");}

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  • Retrieve data from an ASP.Net application using ADO.Net 2.0 connected model

    - by nikolaosk
    I have been teaching Entity Framework,LINQ to SQL,LINQ to objects,LINQ to XML for some time now. I am huge fan of LINQ to Entities and I am using Entity Framework as my main data access technology. Entity framework is in the second version right now and I can accomplish most of the things I need. I am sure the guys in the ADO.Net team will implement many more features in the future. I am a strong believer that you cannot really understand the benefits of LINQ to SQL or LINQ to Entities unless you...(read more)

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  • Can a binary tree or tree be always represented in a Database table as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person under him can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Slow query. Wrong database structure?

    - by Tin
    I have a database with table that contains tasks. Tasks have a lifecycle. The status of the task's lifecycle can change. These state transitions are stored in a separate table tasktransitions. Now I wrote a query to find all open/reopened tasks and recently changed tasks but I already see with a rather small number of tasks (<1000) that execution time has becoming very long (0.5s). Tasks +-------------+---------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-------------+---------+------+-----+---------+----------------+ | taskid | int(11) | NO | PRI | NULL | auto_increment | | description | text | NO | | NULL | | +-------------+---------+------+-----+---------+----------------+ Tasktransitions +------------------+-----------+------+-----+-------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------------+-----------+------+-----+-------------------+----------------+ | tasktransitionid | int(11) | NO | PRI | NULL | auto_increment | | taskid | int(11) | NO | MUL | NULL | | | status | int(11) | NO | MUL | NULL | | | description | text | NO | | NULL | | | userid | int(11) | NO | | NULL | | | transitiondate | timestamp | NO | | CURRENT_TIMESTAMP | | +------------------+-----------+------+-----+-------------------+----------------+ Query SELECT tasks.taskid,tasks.description,tasklaststatus.status FROM tasks LEFT OUTER JOIN ( SELECT tasktransitions.taskid,tasktransitions.transitiondate,tasktransitions.status FROM tasktransitions INNER JOIN ( SELECT taskid,MAX(transitiondate) AS lasttransitiondate FROM tasktransitions GROUP BY taskid ) AS tasklasttransition ON tasklasttransition.lasttransitiondate=tasktransitions.transitiondate AND tasklasttransition.taskid=tasktransitions.taskid ) AS tasklaststatus ON tasklaststatus.taskid=tasks.taskid WHERE tasklaststatus.status IS NULL OR tasklaststatus.status=0 or tasklaststatus.transitiondate>'2013-09-01'; I'm wondering if the database structure is best choice performance wise. Could adding indexes help? I already tried to add some but I don't see great improvements. +-----------------+------------+----------------+--------------+------------------+-----------+-------------+----------+--------+------+------------+---------+---------------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | Index_comment | +-----------------+------------+----------------+--------------+------------------+-----------+-------------+----------+--------+------+------------+---------+---------------+ | tasktransitions | 0 | PRIMARY | 1 | tasktransitionid | A | 896 | NULL | NULL | | BTREE | | | | tasktransitions | 1 | taskid_date_ix | 1 | taskid | A | 896 | NULL | NULL | | BTREE | | | | tasktransitions | 1 | taskid_date_ix | 2 | transitiondate | A | 896 | NULL | NULL | | BTREE | | | | tasktransitions | 1 | status_ix | 1 | status | A | 3 | NULL | NULL | | BTREE | | | +-----------------+------------+----------------+--------------+------------------+-----------+-------------+----------+--------+------+------------+---------+---------------+ Any other suggestions?

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  • PHP form validation submit problem

    - by TaG
    Every time I try to submit the form and I have not entered nothing in the year field I get Incorrect year! how can I still submit the form without having to enter a year. In other words leaving the year field blank and not getting a warning? Here is the PHP code. if(preg_match('/^\d{4,}$/', $_POST['year'])) { $year = mysqli_real_escape_string($mysqli, $_POST['year']); } else { $year = NULL; } if($year == NULL) { echo '<p class="error">Incorrect year!</p>'; } else { //do something }

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  • SELECT(IF(IN query.

    - by Harold
    There are 3 tables. Products, Options and Prod_Opts_relations. The latter holds product_id and option_id so i should be able to figure out which options are selected for any given product. Now i want to retrieve all options from the options table where the value of an extra alias field should hold checked or unchecked depending on the existance of a mathing record in the relations table for a give product id. Thus far i came up with this: SELECT IF(IN(SELECT id_option FROM prod_opt_relations WHERE id_product='18'),'y','n') AS booh ,optionstable.id AS parent_id ,optionstable.name_en AS parent_english ,optionstable.name_es AS parent_spanish FROM product_options AS optionstable WHERE 1 resulting in syntax errors. Alas i just cannot figure out where things go wrong here

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  • How to make an add friend/defriend function in PHP?

    - by user300371
    I have created a site where people can create a profile. But I am trying to figure out how to start on making an add friend button so users can have friends. In my user table, i have user_id, first_name, last_name, email, etc. Should I somehow relate the user_id of the user and the friend in a friend table? I am a novice to programming, so these things are still new to me. Thanks!

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