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  • Problem logging in and changing permissions in Facebook

    - by kujawk
    Hi everybody, I've got a piece of code that logs into Facebook, gets a session, sets status_update and offline_access permission if they are not set, and gets a new session with the newly set permissions. This code used to work fine but now I'm getting error 100 "One of the parameters specified was missing or invalid" as a response to the second call to get session and I can't figure out why. Here's the sequence in detail: CREATE TOKEN restserver.php?method=auth.createToken&api_key=[our key]&v=1.0&format=JSON&sig=[sig created with our secret] response: new token LOGIN m.facebook.com/login.php?api_key=[our key]&v=1.0&auth_token=[token created above] login screen loads and user successfully logs in with their username/password. GET SESSION restserver.php?method=auth.getSession&api_key=[our key]&v=1.0&format=JSON&auth_token=token created above&sig=[sig created with our secret] response: session key with expiration date and a secret CHECK/AUTHORIZE PERMISSIONS restserver.php?method=users.hasAppPermission&api_key=[our key]&v=1.0&format=JSON&ext_perm=status_update&call_id=[proper id]&session_key=[key returned above]&sig=[sig created with secret returned for get session] response: 0 m.facebook.com/authorize.php?api_key=[our key]&v=1.0&ext_perm=status_update authorization screen loads and user authorizes Same steps for status_update CREATE NEW TOKEN Same steps as done to create the first token LOGIN m.facebook.com/login.php?api_key=[our key]&v=1.0&auth_token=[new token] user is already logged in, redirected to their homepage GET NEW SESSION restserver.php?method=auth.getSession&api_key=[our key]&format=JSON&auth_token=[new token]&sig=[sig created with our secret] response: error 100 - missing or invalid parameter. Of course it doesn't tell me which one. Anybody have any ideas what I'm doing wrong here? I tried skipping the second login and going right to creating the new session and that didn't work. The only thing that seems to work is logging out the user after they've authorized the permissions and having them log back in again. I'd like to avoid this if possible. Can you have two outstanding sessions at one time? This code used to work but I'm thinking maybe something changed on Facebook's end that I'm not aware of. Thanks, kris

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  • UDP server doesnt accept calls from outside.

    - by rayman
    Hi, ive implement simple udp server on my Android device.(sdk 1.5) it works fine when i am runnning a local client on the phone sends through it trigger to my server. but when i try to get udp call from an outside server to my phone, it doesnt work. already make sure the outside server isnt blocked by firewall and it's sending the udp trigger to the right port, which my phone is listening to. i used natstat on the phone and checked that the phone is realy listening to the it's local ip and the port ive setted it to. here is my code of the server:(on the device) // server will listen to one client try { Thread udpServerThread = new Thread() { @Override public void run() { try { // Retrieve the ServerName InetAddress serverAddr = InetAddress .getByName("localhost"); Log.d("UDP", "S: Connecting..."); // Create new UDP-Socket socket = new DatagramSocket(SERVERPORT,serverAddr); byte[] buf = new byte[17]; // * Prepare a UDP-Packet that can contain the data we // * want to receive DatagramPacket packet = new DatagramPacket(buf, buf.length); Log.d("UDP", "S: Receiving..."); // wait to Receive the UDP-Packet socket.receive(packet); Log.d("UDP", "S: Received: '" + new String(packet.getData()) + "'"); acceptedMsg=new String(packet.getData()); notifyService(acceptedMsg); Log.d("UDP", "S: Done."); } catch (Exception e) { Log.e("UDP", "S: Error", e); } } }; udpServerThread.start(); } catch (Exception E) { Log.e("r",E.getMessage()) ; } so as i said, when i try it with local client(seperate thread) which sends udp trigger it works fine, but when i take this client implementation and put it on an outside real server, after UDP being sent, the phone doesnt respond to it. any idea? thanks, ray.

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  • Blackberry app development - Drawing graphics on top of rendered text/buttons etc

    - by paullb
    Based off the one of the demos I have the following code. Currently what displays in the simulator is just hte contents of the paint function, however the ObjectChoiceField is still selectable if one happens to click in the right location. I would like both the text contents and the paint function contents to appear. Is this possible? public CityInfoScreen() { //invoke the MainScreen constructor super(); //add a screen title LabelField title = new LabelField("City Information Kiosk", LabelField.ELLIPSIS | LabelField.USE_ALL_WIDTH); setTitle(title); //add a text label add(new RichTextField("Major U.S. Cities")); //add a drop-down list with three choices: //Los Angeles, Chicago, or New York //... String choices[] = {"Los Angeles","Chicago","New York"}; choiceField = new ObjectChoiceField("select a city", choices); add(choiceField); Manager man = this.getMainManager(); } ... public void paint(Graphics g){ super.paint(g); // g.drawRect(0,left,500,500+left); g.setGlobalAlpha(0); g.drawRect(100-left,100-top,200,200); String text = new Integer(left).toString(); String text2 = new Integer(top).toString(); g.drawText(text + " " + text2,120-left,120-top); }

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  • send email to list of users with different timezones?

    - by ylazez
    i use the following method to send email to list of users i want the (To) in each email to be for just the user only not all users i.e appears to the users that the email is sent to only him my guess is to loop on: message.addRecipients(Message.RecipientType.TO, address); then send the message right? , but this is a heavy process sending an email many times any ideas ? suppose that i have the timezone for each user and i want to send each user the message in his timzone, the same issue i guess setting sent date for each user in his timezone then sending the message, right ? the method is: try { Properties props = System.getProperties(); props.put("mail.smtp.host", "localhost"); // Get a mail session Session session = Session.getDefaultInstance(props, null); // Define a new mail message Message message = new MimeMessage(session); InternetAddress ia = new InternetAddress(); ia.setPersonal("MySite"); ia.setAddress(from); message.setFrom(ia); Address[] address = new Address[recievers.size()]; for (int i = 0; i < recievers.size(); i++) { address[i] = new InternetAddress(recievers.get(i)); } message.addRecipients(Message.RecipientType.TO, address); message.setSubject(subject); // Create a message part to represent the body text BodyPart messageBodyPart = new MimeBodyPart(); messageBodyPart.setContent(body, "text/html"); // use a MimeMultipart as we need to handle the file attachments Multipart multipart = new MimeMultipart(); // add the message body to the mime message multipart.addBodyPart(messageBodyPart); // Put all message parts in the message message.setContent(multipart); message.setSentDate(getCurrentDate()); // Send the message Transport.send(message); } catch (Exception ex) {}

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  • Blackberry (Java) - Drawing graphics on top of rendered text/buttons etc

    - by paullb
    Based off the one of the demos I have the following code. Currently what displays in the simulator is just hte contents of the paint function, however the ObjectChoiceField is still selectable if one happens to click in the right location. I would like both the text contents and the paint function contents to appear. Is this possible? public CityInfoScreen() { //invoke the MainScreen constructor super(); //add a screen title LabelField title = new LabelField("City Information Kiosk", LabelField.ELLIPSIS | LabelField.USE_ALL_WIDTH); setTitle(title); //add a text label add(new RichTextField("Major U.S. Cities")); //add a drop-down list with three choices: //Los Angeles, Chicago, or New York //... String choices[] = {"Los Angeles","Chicago","New York"}; choiceField = new ObjectChoiceField("select a city", choices); add(choiceField); Manager man = this.getMainManager(); } ... public void paint(Graphics g){ super.paint(g); // g.drawRect(0,left,500,500+left); g.setGlobalAlpha(0); g.drawRect(100-left,100-top,200,200); String text = new Integer(left).toString(); String text2 = new Integer(top).toString(); g.drawText(text + " " + text2,120-left,120-top); }

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  • ASP.NET MVC Dropdownlist retain the selected value in the browser after post

    - by MLabib
    I build a drop down list in my aspx page as following <%= Html.DropDownList("SelectedRole", new SelectList((IEnumerable)Model.roles, "RoleId", "RoleName", Model.SelectedRole), "")%> it works fine for first Get and the first default value is selected; then I select item from the drop down list and submit the form. the controller bind the values correctly, public ActionResult About([Bind] Roles r) { //r.SelectedRole = the selected value in the page. //Roles r = new Roles(); r.roles = new List<Role>(); r.roles.Add(new Role(1, "one")); r.roles.Add(new Role(2, "two")); r.roles.Add(new Role(3, "three")); r.roles.Add(new Role(4, "four")); r.SelectedRole = null; return View(r) } Then I nullify the selected item and return my view, but still the previous selected Item is selected (although I did nullify it) Any Idea if I am doing something wrong or it is a bug in MVC? I am using ASP.NET MVC 1 Thanks

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  • Am I encrypting my passwords correctly in ASP.NET

    - by Nick
    I have a security class: public class security { private static string createSalt(int size) { //Generate a random cryptographic number RNGCryptoServiceProvider rng = new RNGCryptoServiceProvider(); byte[] b = new byte[size]; rng.GetBytes(b); //Convert to Base64 return Convert.ToBase64String(b); } /// <summary> /// Generate a hashed password for comparison or create a new one /// </summary> /// <param name="pwd">Users password</param> /// <returns></returns> public static string createPasswordHash(string pwd) { string salt = "(removed)"; string saltAndPwd = string.Concat(pwd, salt); string hashedPwd = FormsAuthentication.HashPasswordForStoringInConfigFile( saltAndPwd, "sha1"); return hashedPwd; } } This works fine, but I am wondering if it is sufficient enough. Also, is this next block of code better? Overkill? static byte[] encrInitVector = new byte[] { 0x12, 0x34, 0x56, 0x78, 0x90, 0xAB, 0xCD, 0xEF }; static string encrKey = "(removed)"; public static string EncryptString(string s) { byte[] key; try { key = Encoding.UTF8.GetBytes(encrKey.Substring(0, 8)); DESCryptoServiceProvider des = new DESCryptoServiceProvider(); byte[] inputByteArray = Encoding.UTF8.GetBytes(s); MemoryStream ms = new MemoryStream(); CryptoStream cs = new CryptoStream(ms, des.CreateEncryptor(key, encrInitVector), CryptoStreamMode.Write); cs.Write(inputByteArray, 0, inputByteArray.Length); cs.FlushFinalBlock(); return Convert.ToBase64String(ms.ToArray()); } catch (Exception e) { throw e; }

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  • GridView to excel after create send mail c#

    - by Diego Bran
    I want to send a .xlsx , first I created (It has html code in it) then I used a SMTP server to send it , it does attach the file but when I tried to open it " It says that the file is corrupted etc" any help? Here is my code try { System.IO.StringWriter sw = new System.IO.StringWriter(); System.Web.UI.HtmlTextWriter htw = new System.Web.UI.HtmlTextWriter(sw); // Render grid view control. gvStock.RenderControl(htw); // Write the rendered content to a file. string renderedGridView = sw.ToString(); File.WriteAllText(@"C:\test\ExportedFile.xls", renderedGridView); // File.WriteAllText(@"C:\test\ExportedFile.xls", p1); } catch (Exception e) { Response.Write(e.Message); } try { MailMessage mail = new MailMessage(); SmtpClient SmtpServer = new SmtpClient("server"); mail.From = new MailAddress("[email protected]"); mail.To.Add("[email protected]"); mail.Subject = "Test Mail - 1"; mail.Body = "mail with attachment"; Attachment data = new Attachment("C:/test/ExportedFile.xls"); mail.Attachments.Add(data); SmtpServer.Port = 25; SmtpServer.Credentials = new System.Net.NetworkCredential("user", "pass"); // SmtpServer.EnableSsl = true; SmtpServer.UseDefaultCredentials = false; SmtpServer.Send(mail); } catch( Exception e) { Response.Write(e.Message); }

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  • Select rows from table1 and all the children from table2 into an object

    - by Patrick
    I want to pull data from table "Province_Notifiers" and also fetch all corresponding items from table "Province_Notifier_Datas". The table "Province_Notifier" has a guid to identify it (PK), table "Province_Notifier_Datas" has a column called BelongsToProvinceID witch is a foreign key to the "Province_Notifier" tables guid. I tried something like this: var records = from data in ctx.Province_Notifiers where DateTime.Now >= data.SendTime && data.Sent == false join data2 in ctx.Province_Notifier_Datas on data.Province_ID equals data2.BelongsToProvince_ID select new Province_Notifier { Email = data.Email, Province_ID = data.Province_ID, ProvinceName = data.ProvinceName, Sent = data.Sent, UserName = data.UserName, User_ID = data.User_ID, Province_Notifier_Datas = (new List<Province_Notifier_Data>().AddRange(data2)) }; This line is not working and i am trying to figure out how topull the data from table2 into that Province_Notifier_Datas variable. Province_Notifier_Datas = (new List<Province_Notifier_Data>().AddRange(data2)) I can add a record easily by adding the second table row into the Province_Notifier_Datas but i can't fetch it back. Province_Notifier dbNotifier = new Province_Notifier(); // set some values for dbNotifier dbNotifier.Province_Notifier_Datas.Add( new Province_Notifier_Data { BelongsToProvince_ID = userInput.Value.ProvinceId, EventText = GenerateNotificationDetail(notifierDetail) }); This works and inserts the data correctly into both tables. Edit: These error messages is thrown: Cannot convert from 'Province_Notifier_Data' to 'System.Collections.Generic.IEnumerable' If i look in Visual Studio, the variable "Province_Notifier_Datas" is of type System.Data.Linq.EntitySet The best overloaded method match for 'System.Collections.Generic.List.AddRange(System.Collections.Generic.IEnumerable)' has some invalid arguments Edit: var records = from data in ctx.Province_Notifiers where DateTime.Now >= data.SendTime && data.Sent == false join data2 in ctx.Province_Notifier_Datas on data.Province_ID equals data2.BelongsToProvince_ID into data2list select new Province_Notifier { Email = data.Email, Province_ID = data.Province_ID, ProvinceName = data.ProvinceName, Sent = data.Sent, UserName = data.UserName, User_ID = data.User_ID, Province_Notifier_Datas = new EntitySet<Province_Notifier_Data>().AddRange(data2List) }; Error 3 The name 'data2List' does not exist in the current context.

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  • Consume a JSON webservice and process data in Android

    - by user1783391
    I am trying to consume a the webservice below http://62.253.195.179/disaster/webservices/login.php?message=[{"email":"[email protected]","password":"welcome"}] This returns a JSON array [{"companyuserId":"2","name":"ben stein","superiorname":"Leon","departmentId":"26","departmentname":"Development","companyId":"23","UDID":"12345","isActive":"1","devicetoken":"12345","email":"[email protected]","phone":"5456465465654","userrole":"1","chngpwdStatus":"1"}] My code is below try{ String weblink = URLEncoder.encode("http://62.253.195.179/disaster/webservices/login.php?message=[{\"email\":\"[email protected]\",\"password\":\"welcome\"}]"); HttpParams httpParameters = new BasicHttpParams(); int timeoutConnection = 7500; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 7500; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); HttpClient client = new DefaultHttpClient(httpParameters); HttpGet request = new HttpGet(); URI link = new URI(weblink); request.setURI(link); HttpResponse response = client.execute(request); BufferedReader rd = new BufferedReader(new InputStreamReader( response.getEntity().getContent())); result = rd.readLine(); JSONObject myData = new JSONObject(result); JSONArray jArray = myData.getJSONArray(""); JSONObject steps = jArray.getJSONObject(0); String name = steps.getString("name"); } catch (JSONException e) { e.printStackTrace(); } But its not working and I am not 100% sure this is the best way to do it. 11-10 10:49:55.489: E/AndroidRuntime(392): java.lang.IllegalStateException: Target host must not be null, or set in parameters.

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  • Flash CS4 Actionscript 3.0 --- Make my script loop!

    - by Ross
    Here is my script... all I want to do is have it continuously loop! import fl.transitions.Tween; import fl.transitions.easing.*; yourwebsite_mc.visible=false; var uptodateFadeTween=new Tween(uptodate_mc,"alpha",Strong.easeOut,0,1,3,true); var uptodateRotateTween=new Tween(uptodate_mc,"rotation",Strong.easeOut,360,0,3,true); var uptodateXTween:Tween=new Tween(uptodate_mc,"x",Strong.easeOut,-250,200,3,true); var uptodateDone:Timer=new Timer(3000,1); uptodateDone.addEventListener(TimerEvent.TIMER, timerDoneF); uptodateDone.start(); function timerDoneF(e:TimerEvent):void { var uptodateYTween:Tween=new Tween(uptodate_mc,"y",Strong.easeOut,129,-150,3,true); } var uptodateFlyUp:Timer=new Timer(3500,1); uptodateFlyUp.addEventListener(TimerEvent.TIMER, timerDoneG); uptodateFlyUp.start(); function timerDoneG(e:TimerEvent):void { yourwebsite_mc.visible=true; var yourwebsiteXTween:Tween=new Tween(yourwebsite_mc,"x",Strong.easeOut,-200,450,1.5,true); }

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  • How to set gravity (or margins) of ImageView using code?

    - by mastojun
    Hi. I want to add ImageView to FrameLayout with Gravity or margins. but FramLayout and ImageView has no method about that(Actually, I can't found that). Reason that selects Framelayout is to put ImageView on ImageView. Help me plz. It is emergency for me to find solution. thx. Bellow is my code which help understanding my question. FrameLayout imageFrame = new FrameLayout(mContext); imageFrame.setLayoutParams(new GridView.LayoutParams(158, 158)); ImageView frame = new ImageView(mContext); frame = new ImageView(mContext); frame.setLayoutParams(new LayoutParams(158, 158)); frame.setScaleType(ImageView.ScaleType.CENTER_CROP); frame.setImageResource(R.drawable.image_frame_n); ImageView image = new ImageView(mContext); image.setLayoutParams(new LayoutParams(148, 148)); image.setScaleType(ImageView.ScaleType.CENTER_CROP); image.setImageResource(mThumbIds[position]); // image is needed to have a margin or gravity to be positioned at center imageFrame.addView(image); imageFrame.addView(frame);

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  • Barcode not generated in C# web forms?

    - by Sinsil Mathew
    I am trying for create a barcode in my web form.for that i download font IDAutomationHC39M and install in my system,then i run my wesite in localhost but barcode cannot be generated.This is my code protected void Button1_Click1(object sender, EventArgs e) { string barCode = TextBox1.Text; System.Web.UI.WebControls.Image imgBarCode = new System.Web.UI.WebControls.Image(); using (Bitmap bitMap = new Bitmap(barCode.Length * 40, 80)) { using (Graphics graphics = Graphics.FromImage(bitMap)) { Font oFont = new Font("IDAutomationHC39M", 16); PointF point = new PointF(2f, 2f); SolidBrush blackBrush = new SolidBrush(Color.Black); SolidBrush whiteBrush = new SolidBrush(Color.White); graphics.FillRectangle(whiteBrush, 0, 0, bitMap.Width, bitMap.Height); graphics.DrawString("*" + barCode + "*", oFont, blackBrush, point); } using (MemoryStream ms = new MemoryStream()) { bitMap.Save(ms, System.Drawing.Imaging.ImageFormat.Png); byte[] byteImage = ms.ToArray(); Convert.ToBase64String(byteImage); imgBarCode.ImageUrl = "data:image/png;base64," + Convert.ToBase64String(byteImage); } plBarCode.Controls.Add(imgBarCode); } And the result is appear like that code

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  • How do I return a variable in javascript?

    - by bmckim
    I am working with the google maps API and whenever I return the variable to the initialize function from the codeLatLng function it claims undefined. If I print the variable from the codeLatLng it shows up fine. var geocoder; function initialize() { geocoder = new google.maps.Geocoder(); var latlng = new google.maps.LatLng(40.730885,-73.997383); var addr = codeLatLng(); document.write(addr); } function codeLatLng() { var latlng = new google.maps.LatLng(40.730885,-73.997383); if (geocoder) { geocoder.geocode({'latLng': latlng}, function(results, status) { if (status == google.maps.GeocoderStatus.OK) { if (results[1]) { return results[1].formatted_address; } else { alert("No results found"); } } else { alert("Geocoder failed due to: " + status); } }); } } prints out undefined If I do: var geocoder; function initialize() { geocoder = new google.maps.Geocoder(); var latlng = new google.maps.LatLng(40.730885,-73.997383); codeLatLng(); } function codeLatLng() { var latlng = new google.maps.LatLng(40.730885,-73.997383); if (geocoder) { geocoder.geocode({'latLng': latlng}, function(results, status) { if (status == google.maps.GeocoderStatus.OK) { if (results[1]) { document.write(results[1].formatted_address); } else { alert("No results found"); } } else { alert("Geocoder failed due to: " + status); } }); } } prints out New York, NY 10012, USA

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  • NUnit, CollectionAssert.AreEquivalent(...,...), C# Question

    - by K-Bell
    I new to NUnit and looking for an explination as to why this test fails? I get the following exception when running the test. NUnit.Framework.AssertionException: Expected: equivalent to < <....ExampleClass, <....ExampleClass But was: < <....ExampleClass, <....ExampleClass using NUnit.Framework; using System.Collections.ObjectModel; public class ExampleClass { public ExampleClass() { Price = 0m; } public string Description { get; set; } public string SKU { get; set; } public decimal Price { get; set; } public int Qty { get; set; } } [TestFixture] public class ExampleClassTests { [Test] public void ExampleTest() { var collection1 = new Collection<ExampleClass> { new ExampleClass {Qty = 1, SKU = "971114FT031M"}, new ExampleClass {Qty = 1, SKU = "971114FT249LV"} }; var collection2 = new Collection<ExampleClass> { new ExampleClass {Qty = 1, SKU = "971114FT031M"}, new ExampleClass {Qty = 1, SKU = "971114FT249LV"} }; CollectionAssert.AreEquivalent(collection1, collection2); } }

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  • public class ImageHandler : IHttpHandler

    - by Ken
    cmd.Parameters.AddWithValue("@id", new system.Guid (imageid)); What using System reference would this require? Here is the handler: using System; using System.Collections.Specialized; using System.Web; using System.Web.Configuration; using System.Web.Security; using System.Globalization; using System.Configuration; using System.Data.SqlClient; using System.Data; using System.IO; using System.Web.Profile; using System.Drawing; public class ImageHandler : IHttpHandler { public void ProcessRequest(HttpContext context) { string imageid; if (context.Request.QueryString["id"] != null) imageid = (context.Request.QueryString["id"]); else throw new ArgumentException("No parameter specified"); context.Response.ContentType = "image/jpeg"; Stream strm = ShowProfileImage(imageid.ToString()); byte[] buffer = new byte[8192]; int byteSeq = strm.Read(buffer, 0, 8192); while (byteSeq > 0) { context.Response.OutputStream.Write(buffer, 0, byteSeq); byteSeq = strm.Read(buffer, 0, 8192); } //context.Response.BinaryWrite(buffer); } public Stream ShowProfileImage(String imageid) { string conn = ConfigurationManager.ConnectionStrings["MyConnectionString1"].ConnectionString; SqlConnection connection = new SqlConnection(conn); string sql = "SELECT image FROM Profile WHERE UserId = @id"; SqlCommand cmd = new SqlCommand(sql, connection); cmd.CommandType = CommandType.Text; cmd.Parameters.AddWithValue("@id", new system.Guid (imageid));//Failing Here!!!! connection.Open(); object img = cmd.ExecuteScalar(); try { return new MemoryStream((byte[])img); } catch { return null; } finally { connection.Close(); } } public bool IsReusable { get { return false; } } }

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  • C# image drawing colours are incorrect

    - by Jon Tackabury
    I have a source bitmap that is 1x1 and I am trying to take that image and draw it to a new bitmap. The source bitmap is all red, but for some reason the new bitmap ends up with a gradient (see image). Using the code below, shouldn't the new bitmap be completely red? Where is it getting the white/alpha from? private void DrawImage() { Bitmap bmpSOURCE = new Bitmap(1, 1, PixelFormat.Format32bppArgb); using (Graphics g = Graphics.FromImage(bmpSOURCE)) { g.Clear(Color.Red); } Bitmap bmpTest = new Bitmap(300, 100, PixelFormat.Format32bppArgb); using (Graphics g = Graphics.FromImage(bmpTest)) { g.CompositingMode = CompositingMode.SourceCopy; g.CompositingQuality = CompositingQuality.AssumeLinear; g.InterpolationMode = InterpolationMode.HighQualityBicubic; g.PageUnit = GraphicsUnit.Pixel; g.PixelOffsetMode = PixelOffsetMode.None; g.SmoothingMode = SmoothingMode.None; Rectangle rectDest = new Rectangle(0, 0, bmpTest.Width, bmpTest.Height); Rectangle rectSource = new Rectangle(0, 0, 1, 1); g.DrawImage(bmpSOURCE, rectDest, rectSource, GraphicsUnit.Pixel); } pictureBox1.Image = bmpTest; }

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  • WPF bound object update notification

    - by Carlo
    I have a TreeView with a few objects bound to it, let's say something like this: public class House { public List<Room> Rooms { get; set; } public List<Person> People { get; set; } public House() { this.Rooms = new List<Room>(); this.People = new List<Person>(); } public void BuildRoom(string name) { this.Rooms.Add(new Room() { Name = name }); } public void DestroyRoom(string name) { this.Rooms.Remove(new Room() { Name = name }); } public void PersonEnter(string name) { this.People.Add(new Person() { Name = name }); } public void PersonLeave(string name) { this.People.Remove(new Person() { Name = name }); } } public class Room { public string Name { get; set; } } public class Person { public string Name { get; set; } } The TreeView is watching over the House object, whenever a room is built / destroyed or a person enters / leaves, my tree view updates itself to show the new state of the house (I omitted some implementation details for simplicity). What I want is to know the exact moment when this update finishes, so I can do something right there, the thing is that I created an indicator of the selected item, and when something moves, I need to update said indicator's position, that's the reason I need it exactly when the tree view updates. Let me know if you know a solution to this. Also, the code is not perfect (DestroyRoom and PersonLeave), but you get the idea. Thanks!

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  • Pointers and Addresses in C

    - by Mohit
    #include "stdio.h" main() { int i=3,*x; float j=1.5,*y; char k='c',*z; x=&i; y=&j; z=&k; printf("\nAddress of x= %u",x); printf("\nAddress of y= %u",y); printf("\nAddress of z= %u",z); x++; y++;y++;y++;y++; z++; printf("\nNew Address of x= %u",x); printf("\nNew Address of y= %u",y); printf("\nNew Address of z= %u",z); printf("\nNew Value of i= %d",i); printf("\nNew Value of j= %f",j); printf("\nNew Value of k= %c\n",k); } Output: Address of x= 3219901868 Address of y= 3219901860 Address of z= 3219901875 New Address of x= 3219901872 New Address of y= 3219901876 New Address of z= 3219901876 New Value of i= 3 New Value of j= 1.500000 New Value of k= c The new address of variable y and z are same. How can two variables have same address and et have different values? Note: I used gcc compiler on Ubuntu 9.04

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  • Rails : can't write unknown attribute `url'

    - by user2954789
    I am new to ruby on rails,and I am learning by creating a blog. I am not able to save to my blogs table and I get this error "can't write unknown attribute url" Blogs migration :db/migrate/ class CreateBlogs < ActiveRecord::Migration --def change --- create_table :blogs do |t| ---- t.string :title ---- t.text :description ---- t.string :slug ---- t.timestamps --- end --end end Blogs Model :/app/models/blogs.rb class Blogs < ActiveRecord::Base --acts_as_url :title --def to_param ---url --end --validates :title, presence:true end Blogs Controller : /app/controllers/blogs_controller.rb class BlogsController < ApplicationController before_action :require_login --def new --- @blogs = Blogs.new --end --def show ---@blogs = Blogs.find(params[:id]) --end --def create ---@blogs = Blogs.new(blogs_params) --if @blogs.save ---flash[:success] = "Your Blog has been created." ---redirect_to home_path --else ---render 'new' --end -end --def blogs_params ---params.require(:blogs).permit(:title,:description) --end private --def require_login ---unless signed_in? ----flash[:error] = "You must be logged in to create a new Blog" ----redirect_to signin_path ---end --end end Blogs Form:/app/views/blogs/new.html.erb Blockquote <%= form_for @blogs, url: blogs_path do |f| %><br/> <%= render 'shared/error_messages_blogs' %><br/> <%= f.label :title %><br/> <%= f.text_field :title %><br/> <%= f.label :description %><br/> <%= f.text_area :description %><br/> <%= f.submit "Submit Blog", class: "btn btn-large btn-primary" %><br/> <% end %><br/> and I have also added "resources :blogs" to my routes.rb file. I get this error in controller at if @blogs.save

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  • How to sort data in a table data structure in Java?

    - by rgksugan
    I need to sort data based on the third column of the table data structure. I tried based on the answers for the following question. But my sorting does not work. Please help me in this. Here goes my code. Object[] data = new Object[y]; rst.beforeFirst(); while (rst.next()) { int p_id = Integer.parseInt(rst.getString(1)); String sw2 = "select sum(quantity) from tbl_order_detail where product_id=" + p_id; rst1 = stmt1.executeQuery(sw2); rst1.next(); String sw3 = "select max(order_date) from tbl_order where tbl_order.`Order_ID` in (select tbl_order_detail.`Order_ID` from tbl_order_detail where product_id=" + p_id + ")"; rst2 = stmt2.executeQuery(sw3); rst2.next(); data[i] = new Object[]{new String(rst.getString(2)), new String(rst.getString(3)), new Integer(rst1.getString(1)), new String(rst2.getString(1))}; i++; } ColumnComparator cc = new ColumnComparator(2); Arrays.sort(data, cc); if (i == 0) { table.addCell(""); table.addCell(""); table.addCell(""); table.addCell(""); } else { for (int j = 0; j < y; j++) { Object[] theRow = (Object[]) data[j]; table.addCell((String) theRow[0]); table.addCell((String) theRow[1]); table.addCell((String) theRow[2]); table.addCell((String) theRow[3]); }

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  • What is the best way to store static data in C# that will never changes

    - by Luke101
    I have a class that stores data in asp.net c# application that never changes. I really don't want to put this data in the database - I would like it to stay in the application. Here is my way to store data in the application: public class PostVoteTypeFunctions { private List<PostVoteType> postVotes = new List<PostVoteType>(); public PostVoteTypeFunctions() { PostVoteType upvote = new PostVoteType(); upvote.ID = 0; upvote.Name = "UpVote"; upvote.PointValue = PostVotePointValue.UpVote; postVotes.Add(upvote); PostVoteType downvote = new PostVoteType(); downvote.ID = 1; downvote.Name = "DownVote"; downvote.PointValue = PostVotePointValue.DownVote; postVotes.Add(downvote); PostVoteType selectanswer = new PostVoteType(); selectanswer.ID = 2; selectanswer.Name = "SelectAnswer"; selectanswer.PointValue = PostVotePointValue.SelectAnswer; postVotes.Add(selectanswer); PostVoteType favorite = new PostVoteType(); favorite.ID = 3; favorite.Name = "Favorite"; favorite.PointValue = PostVotePointValue.Favorite; postVotes.Add(favorite); PostVoteType offensive = new PostVoteType(); offensive.ID = 4; offensive.Name = "Offensive"; offensive.PointValue = PostVotePointValue.Offensive; postVotes.Add(offensive); PostVoteType spam = new PostVoteType(); spam.ID = 0; spam.Name = "Spam"; spam.PointValue = PostVotePointValue.Spam; postVotes.Add(spam); } } When the constructor is called the code above is ran. I have some functions that can query the data above too. But is this the best way to store information in asp.net? if not what would you recommend?

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  • Issue with the Entity Manager and phpunit in Symfony 2

    - by rgazelot
    I have an issue with my Entity Manager in phpunit. This is my test : public function testValidChangeEmail() { $client = self::createAuthClient('user','password'); $crawler = $client->request('GET', '/user/edit/30'); $crawler = $client->submit($crawler->selectButton('submit')->form(array( 'form[email]' => '[email protected]', ))); /* * With this em, this work perfectly * $em = $client->getContainer()->get('doctrine.orm.entity_manager'); */ $user = self::$em->getRepository('MyBundle:User')->findUser('[email protected]'); die(var_dump($user->getEmail())); } and this is my WebTestCase which extends original WebTestCase : class WebTestCase extends BaseWebTestCase { static protected $container; static protected $em; static protected function createClient(array $options = array(), array $server = array()) { $client = parent::createClient($options, $server); self::$em = $client->getContainer()->get('doctrine.orm.entity_manager'); self::$container = $client->getContainer(); return $client; } protected function createAuthClient($user, $pass) { return self::createClient(array(), array( 'PHP_AUTH_USER' => $user, 'PHP_AUTH_PW' => $pass, )); } As you can see, I replace the self::$em when I created my client. My issue : In my test, the die() give me the old email and not the new email ([email protected]) which has registered in the test. However in my database, I have the [email protected] correctly saved. When I retrieve my user in the database, I use sefl::$em. If I use the $em in comments, I retrieve the right new email. I don't understand why in my WebTestCase, I can access to the new Entity Manager...

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  • Write to PDF using PHP from android device

    - by Brent Mitchell
    I am trying to write to a pdf file on php server. I have sent variables to the server, create the pdf document, then have my phone download the document to view on device. The variables seem not to write on the php file. I have my code below public void postData() { try { Calculate calc = new Calculate(); HttpClient mClient = new DefaultHttpClient(); StringBuilder sb=new StringBuilder("myurl.com/pdf.php"); HttpPost mpost = new HttpPost(sb.toString()); String value = "1234"; List nameValuepairs = new ArrayList(1); nameValuepairs.add(new BasicNameValuePair("id",value)); mpost.setEntity(new UrlEncodedFormEntity(nameValuepairs)); } catch (UnsupportedEncodingException e) { Log.w(" error ", e.toString()); } catch (Exception e) { Log.w(" error ", e.toString()); } } And my php code to write the variable "value" onto the pdf document: //code to reverse the string if($_POST[] != null) { $reversed = strrev($_POST["value"]); $this->SetFont('Arial','u',50); $this->Text(52,68,$reversed); } I am just trying to write the variable in a random spot, but the variable the if statement is always null and I do not know why. Thanks. Sorry if it is a little sloppy.

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  • how to get email id from google api response

    - by user1726508
    i am able to get user information from Google API response using oath2 . But i do't know how to get those responses individually . Response i am getting from Google Api: * Access token: ya29.AHES6ZQ3QxKxnfAzpZasdfd23423NuxJs29gMa39MXV551yMmyM5IgA { "id": "112361893525676437860", "name": "Ansuman Singh", "given_name": "Ansuman", "family_name": "Singh", "link": "https://plus.google.com/112361893525676437860", "gender": "male", "birthday": "0000-03-18", "locale": "en" } Original Token: ya29.AHES6ZQ3QxKxnfAzpZu0lYHYu8sdfsdafdgMa39MXV551yMmyM5IgA New Token: ya29.AHES6ZQ3QxKxnfdsfsdaYHYu8TNuxJs29gMa39MXV551yMmyM5IgA But i want only "id" & "name" indiviually to save in my Database table. How can i do this? I got those above response/output By using the below code. public static void main(String[] args) throws IOException { ------------------------- ------------------------- ------------------------- String accessToken = authResponse.accessToken; GoogleAccessProtectedResource access = new GoogleAccessProtectedResource(accessToken, TRANSPORT, JSON_FACTORY, CLIENT_ID, CLIENT_SECRET, authResponse.refreshToken); HttpRequestFactory rf = TRANSPORT.createRequestFactory(access); System.out.println("Access token: " + authResponse.accessToken); String url = "https://www.googleapis.com/oauth2/v1/userinfo?alt=json&access_token=" + authResponse.accessToken; final StringBuffer r = new StringBuffer(); final URL u = new URL(url); final URLConnection uc = u.openConnection(); final int end = 1000; InputStreamReader isr = null; BufferedReader br = null; isr = new InputStreamReader(uc.getInputStream()); br = new BufferedReader(isr); final int chk = 0; while ((url = br.readLine()) != null) { if ((chk >= 0) && ((chk < end))) { r.append(url).append('\n'); } } System.out.print(""); System.out.println(); System.out.print(" "+ r ); //this is printing at once but i want them individually access.refreshToken(); System.out.println("Original Token: " + accessToken + " New Token: " + access.getAccessToken()); }

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