Search Results

Search found 33692 results on 1348 pages for 'php bugs'.

Page 484/1348 | < Previous Page | 480 481 482 483 484 485 486 487 488 489 490 491  | Next Page >

  • Form Submitting Incorrect Information to MySQL Database

    - by ThatMacLad
    I've created a form that submits data to a MySQL database but the Date, Time, Year and Month fields constantly revert to the exact same date (1st January 1970) despite the fact that when I submit the information to the database the form displays the current date, time etc to me. I've already set it so that the time and date fields automatically display the current time and date. Could someone please help me with this. Form: <html> <head> <title>Blog | New Post</title> <link rel="stylesheet" href="css/newposts.css" type="text/css" /> </head> <body> <div class="new-form"> <div class="header"> <a href="edit.php"><img src="images/edit-home-button.png"></a> </div> <div class="form-bg"> <?php if (isset($_POST['submit'])) { $month = htmlspecialchars(strip_tags($_POST['month'])); $date = htmlspecialchars(strip_tags($_POST['date'])); $year = htmlspecialchars(strip_tags($_POST['year'])); $time = htmlspecialchars(strip_tags($_POST['time'])); $title = htmlspecialchars(strip_tags($_POST['title'])); $entry = $_POST['entry']; $timestamp = strtotime($month . " " . $date . " " . $year . " " . $time); $entry = nl2br($entry); if (!get_magic_quotes_gpc()) { $title = addslashes($title); $entry = addslashes($entry); } mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "INSERT INTO php_blog (timestamp,title,entry) VALUES ('$timestamp','$title','$entry')"; $result = mysql_query($sql) or print("Can't insert into table php_blog.<br />" . $sql . "<br />" . mysql_error()); if ($result != false) { print "<p class=\"success\">Your entry has successfully been entered into the blog. </p>"; } mysql_close(); } ?> <?php $current_month = date("F"); $current_date = date("d"); $current_year = date("Y"); $current_time = date("H:i"); ?> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_month; ?>" /> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_date; ?>" /> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_year; ?>" /> <input type="text" name="time" id="time" size="5"value="<?php echo $current_time; ?>" /> <input class="field2" type="text" id="title" value="Title Goes Here." name="title" size="40" /> <textarea class="textarea" cols="80" rows="20" name="entry" id="entry" class="field2"></textarea> <input class="field" type="submit" name="submit" id="submit" value="Submit"> </form> </div> </div> </div> <div class="bottom"></div> </body> </html>

    Read the article

  • Apache on Windows in production environment? Why not?

    - by tillda
    "Everyone" know that Apache is for Linux/Unix and on Windows IIS is the way to go. However, I'm not a pro at Linux and it would be an enormous relief for me to use just the same setup in the production environment that I use during development. I'm a solo developer and I'm trying to make things as simple as possible. I've already got rid of other issues like storage (-cloud) emails (-postmark). So, what are the real drawbacks that can happen when I just put Apache in Windows virtual private server from Rackspace and use it as the main production environment for a PHP project? Money for more VPS resources is not that big issue compared to the possibility of not having to learn a different OS. Super-heavy traffic is not expected. Also my PHP project can be quite optimized. There are some heavy scripts, but only for the inside (logged) users. All else can be served more or less statically.

    Read the article

  • MySQL Database Query - Codeigniter

    - by user2450349
    I am building an application with Codeigniter and need some help with a DB query. I have a table called users with the following fields: user_id, user_name, user_password, user_email, user_role, user_manager_id In my app, I pull all records from the user table using the following: function get_clients() { $this->db->select('*'); $this->db->where('user_role', 'client'); $this->db->order_by("user_name", "Asc"); $query = $this->db->get("users"); return $query->result_array(); } This works as expected, however when I display the results in the view, I also want to display a new column called Manager which will display the managers user_name field. The user_manager_id is the id of the user from the same table. Im guessing you can create an outer join on the same table but not sure. In the view, I am displaying the returned info as follows: <table class="table table-striped" id="zero-configuration"> <thead> <tr> <th>Name</th> <th>Email</th> <th>Manager</th> </tr> </thead> <tbody> <?php foreach($clients as $row) { ?> <tr> <td><?php echo $row['user_name']; ?> (<?php echo $row['user_username']; ?>)</td> <td><?php echo $row['user_email']; ?></td> <td><?php echo $row['???']; ?></td> </tr> <?php } ?> </tbody> </table> Any idea of how I can form the query and display the manager name is the view? Example: user_id user_name user_password user_email user_role user_manager_id 1 Ollie adjjk34jcd [email protected] client null 2 James djklsdfsdjk [email protected] client 1 When i query the database, i want to display results like this: Ollie [email protected] James [email protected] Ollie

    Read the article

  • CURL request incomplete, suspect timeout but not sure.

    - by girlygeek
    I am currently using CURL via a php script running as daily cron to export product data in csv format from a site's admin area. The normal way of exporting data will be to go to the Export page in a browser, and set the configuration, then click on "export data" button. But as the number of products I am exporting is very large, and it takes more than 5-10 mins to export the data, I've decided to use php's curl function to mimic this on a daily basis via cron. Previously, it is working fine, but recently as I increased the number of products in the store by 500+, the script fails to return the exported data. Testing it manually via clicking on the "export" button in a browser, does return the data correctly. Thus there is no "timeout" issue with running the export in a browser manually. I've tested and by removing/decreasing the number of products (thus the time needed), the php-curl script works fine again when run from cron. So I suspect that it has something to do with timeouts issue, specifically with the curl function in php. I've set both CURLOPT_TIMEOUT and CURLOPT_CONNECTTIMEOUT to '0' respectively to try. In the php-curl script, I've also set "set_time_limit(3000)". But still it does not work, and the request will timeout, with the script failing to return with a complete set of csv data. Any help in helping me resolve/understand this issue will be much appreciated!

    Read the article

  • Adding to database. No repeat on refresh

    - by kevstarlive
    I have this code: Episode.php <?$feedback = new feedback; $articles = $feedback->fetch_all(); if (isset($_POST['name'], $_POST['post'])) { $cast = $_GET['id']; $name = $_POST['name']; $email = $_POST['email']; $post = nl2br ($_POST['post']); $ipaddress = $_SERVER['REMOTE_ADDR']; if (empty($name) or empty($post)) { $error = 'All Fields Are Required!'; }else{ $query = $pdo->prepare('INSERT INTO comments (cast, name, email, post, ipaddress) VALUES(?, ?, ?, ?, ?)'); $query->bindValue(1, $cast); $query->bindValue(2, $name); $query->bindValue(3, $email); $query->bindValue(4, $post); $query->bindValue(5, $ipaddress); $query->execute(); } }?> <div align="center"> <strong>Give us your feedback?</strong><br /><br /> <?php if (isset($error)) { ?> <small style="color:#aa0000;"><?php echo $error; ?></small><br /><br /> <?php } ?> <form action="episode.php?id=<?php echo $data['cast_id']; ?>" method="post" autocomplete="off" enctype="multipart/form-data"> <input type="text" name="name" placeholder="Name" /> / <input type="text" name="email" placeholder="Email" /><small style="color:#aa0000;">*</small><br /><br /> <textarea rows="10" cols="50" name="post" placeholder="Comment"></textarea><br /><br /> <input type="submit" onclick="myFunction()" value="Add Comment" /> <br /><br /> <small style="color:#aa0000;">* <b>Email will not be displayed publicly</b></small><br /> </form> </div> Include.php class feedback { public function fetch_all(){ global $pdo; $query = $pdo->prepare("SELECT * FROM comments"); $query->bindValue(1, $cast); $query->execute(); return $query->fetchAll(); } } This code updates to the database as it is suppose to. But after submission it reloads the current page as mentioned in the form action. But when I refresh the page to see the comment being added it asks to re submit. If I hit submit then the comment adds again. How can I stop this from happening? Maybe I could hide the comment box and display a thank you message but that would not stop a repeat entry. Please help. Thank you. Kev

    Read the article

  • Redirection Still not working (updated on earlier question)

    - by NoviceCoding
    So earlier I asked this question: JQuery Login Redirect. Code Included The php file is sending the following: $return['error'] = false; $return['msg'] = 'You have successfully logged in!!'; I've tried all the suggestions, quoting the error on php and ajax end, 2 equals instead of 3, I've also tried DNE true which should be the same as an else statement: $(document).ready(function(){ $('#submit').click(function() { $('#waiting').show(500); $('#empty').show(500); $('#reg').hide(0); $('#message').hide(0); $.ajax({ type : 'POST', url : 'logina.php', dataType : 'json', data: { type : $('#typeof').val(), login : $('#login').val(), pass : $('#pass').val(), }, success : function(data){ $('#waiting').hide(500); $('#empty').show(500); $('#message').removeClass().addClass((data.error === true) ? 'error' : 'success') .text(data.msg).show(500) if(data.error != true) window.location.replace("http://blahblah.com/usercp.php"); if (data.error === true) $('#reg').show(500); $('#empty').hide() }, error : function(XMLHttpRequest, textStatus, errorThrown) { $('#waiting').hide(500); $('#message').removeClass().addClass('error') .text("There was an Error. Please try again.").show(500); $('#reg').show(500); $('#empty').hide(); Recaptcha.reload(); } }); return false; }); And it still wont work. Any ideas on how to make a redirection work if login is successful and error returns false? Also while I am asking, can I put a .delay(3000) 3s at the end of window.location.replace("http://blahblah.com/usercp.php")?

    Read the article

  • Virtualhost subdomain Internal Server Error

    - by Andrew
    I am trying to set up user generated sub domains for my PHP application. When I go to sub.domain.com and if I upload an index.html file it works fine, however if I use index.php it gives me a "Internal Server Error 500" message I have done the steps below to get subdomains working STEP 1: Edited my DNZ zone file and appended *.domain.com. IN A 91.111.111.111 STEP 2: Appended to httpd.conf the following: <VirtualHost 91.111.111.111:80> ServerName domain.com ServerAlias *.domain.com DocumentRoot /home/domain/public_html/sub <Directory "/home/domain/public_html/sub"> Options -Indexes Options FollowSymLinks AllowOverride All </Directory> </VirtualHost> Step 3: Tested by uploading an index.html file to the document directory in step 2, and works fine. Tried with an index.php gives a internal server error and then I looked into Apache error log and shows error for a redirect loop more than 10 times Update: getting this error: No user or group set - set suPHP_UserGroup Any ideas why I can not use any .php file in the directory?

    Read the article

  • variable $base_path is not working

    - by Nidhi Prasad
    I am trying to get the value of base_path variable in PHP (on lamp server) . I have kept the code insider beta_test directory inside www directly. i.e, base path function should return " /beta_test/ " . But it is returning just single slash ( "/" ) . The code that I tried is <script type="text/javascript" src="<?php print base_path(); ?>sites/all/themes/people10/slider/call.js"></script> Expected output is <script type="text/javascript" src="/beta_test/sites/all/themes/people10/slider/call.js"></script> But its giving <script type="text/javascript" src="/sites/all/themes/people10/slider/call.js"></script> I am using php version 5.3.3.Can anyone please help me in getting this issue solved? I am newbie to php and drupal .

    Read the article

  • Is there a script that can dynamically list the contents of a folder?

    - by user294756
    I am redesigning my company's intranet site in Wordpress and one of the things they need is an archive of company memos. There are over 300 memos saved in one location and I'm wondering if there is a jQuery script that I can run that will read the contents of a local (network) folder and auto-generate a list of the contents of that folder dynamically (and generate those names as a hyperlink to that file, but if I can list the files, I can get include the hyperlink tag myself). I can always manually create the list of hyperlinks (would take a couple days to do so) but if I can generate it dynamically, whenever a new memo is added, the script will automatically include it making the site much easier to maintain. Is this at all possible? I know that this can probably be done in PHP, but the page I need to do this on is not a php page, it is one of the subpages that is created in wordpress that does not have a php file extension and can't run php code (that I know of) Thanks in advance for any and all assistance.

    Read the article

  • convert mysql code to codeigniter

    - by Jethro Tamares Doble
    How can i convert this code into an acceptable codeigniter code: mysql_select_db($database_connection_ched, $connection_ched); $query_Institutions = "SELECT * FROM tb_institutional_profile ORDER BY tb_institutional_profile.institution_name ASC"; $Institutions = mysql_query($query_Institutions, $connection_ched) or die(mysql_error()); $row_Institutions = mysql_fetch_assoc($Institutions); $totalRows_Institutions = mysql_num_rows($Institutions); <td width="192"><select name="institution_id"> <?php do { <option value="<?php echo $row_Institutions['institution_id']?>" ><?php echo $row_Institutions['institution_name']?></option> <?php } while ($row_Institutions = mysql_fetch_assoc($Institutions)); ?> </select></td>

    Read the article

  • Is there any real advantage to use zend ce server over just referencing (include) the zend framework library?

    - by Marcos Roriz
    Hi, I'm new to PHP frameworks, and currently I'm trying Zend Framework (ZF). I'm old fashioned when it comes to installing software, I like to install apache/mysql/php all separetely since I find easier and it gives me more control of it. It seems that the "encouraged" way to develop with Zend Framework is using the Zend (CE) Server. I personally don't like this idea of a app install everything else (PHP/Apache and so on). From what I've seen if I include Zend Framework Library in php.ini path I'm ready to go. So is there any real advantage to use the Full Zend (CE) Server??

    Read the article

  • Using curl to submit/retrieve a forms results

    - by Jason
    I need help in trying to use curl to post data to a page and retrieve the results after the form has been submitted. I created a simple form: <form name="test" method="post" action="form.php"> <input type="text" name="name" size="40" />e <input type="text" name="comment" size="140" /> <input type="submit" name="submit" value="submit" /> </form> In addition, I have php code to handle this form in the same page. All it does is echo back the form values. The curl that I have been using is this: $h = curl_init(); curl_setopt($h, CURLOPT_URL, "path/to/form.php"); curl_setopt($h, CURLOPT_POST, true); curl_setopt($h, CURLOPT_POSTFIELDS, array( 'name' = 'yes', 'comment' = 'no' )); curl_setopt($h, CURLOPT_HEADER, false); curl_setopt($h, CURLOPT_RETURNTRANSFER, 1); $result = curl_exec($h); When I launch the page with the curl code in it, I get the form.php page contents but it doesn't not show the variables that PHP should have echo'd when the form is submitted. would appreciate any help with this. Thanks.

    Read the article

  • someone help me please

    - by Ronnie Chester Lynwood
    hey i want to make a thing but i need some help. ive got an index.php with codes. and i added "file" parameter to index.php. so i mean if "index.php?file=/folder/folder/picture.png" is set, go to file. if "file=" not set do not do anything. I get "file" parameter with $_REQUEST thingy. please help thanks..

    Read the article

  • Upgrading Fedora to Current Version - Dependent Applications Concerns

    - by nicorellius
    Is it possible to upgrade to Fedora 11 and still keep the server functional (it's running Fedora Core release 6 now, with MySQL 5.0, PHP 5.1 and Apache 2.2)? I have a Customer Relationship Management system on there and it is required on a daily basis. I am trying to figure out if I should upgrade (and whether that will cause huge problems) or if I should start over with a new OS (like Ubuntu) and install the CRM fresh, with updated version of MySQL, PHP, Apache, etc. I ask because I am not really the sysadmin, but have but put in charge of this server.

    Read the article

  • Jquery and CSS switching - is this possible?

    - by Joe
    I build a css file using PHP which allows me to easily customize the color of many elements. Is it possible for me to "rebuild" the stylesheet and apply it to the page in the DOM using Jquery? eg. <?php if (isset($_POST['mycolor'])){ $myColor = $_POST['mycolor']; } else { $myColor = "blue"; } ?> <style type='text/css'> .style1{ color:<?php $myColor;?>; } </style> Now on my page I have a link you can click called "change color to red" and when you click "red" it does a $.post to my php script, which rebuilds the css including .style1 - and allows the page to change the stylesheet. I haven't tested this but would it even work? If I echo'ed out the new stylesheet after the post into the dom... would it even apply to the page?

    Read the article

  • Where to start when setting up a gambling website [closed]

    - by molleman
    I don't know if this is the correct place or this question by I couldn't find anywhere else. I am looking into building a gambling website, I have good HTML CSS and JavaScript skills but I do not know enough of the server side to actually build a backend for a gambling website. Firstly where would you start , what language , I work With Wordpress , so I understand php a little but not a lot . Would php be a good place to start . If so what framework would be able to scale if the number of users on the website increased . clearly I would like a backend where you could view 1. Users 2. Transactions 3. input games which you can bet on And so on.. Also users should be able to see all there associated information If anyone could help that would be great.

    Read the article

  • Separating MySQL SELECT statement based on data in a column

    - by NightMICU
    Hi everyone, I need to retrieve data (vehicle details, in this case) from a MySQL table tabled and then loop through the results to generate separate lists for each category of vehicle. Is there a simple way to do this without having to have a SELECT statement for each type of vehicle? If I were just doing this for one category, I would use the following: <?php $sql = "SELECT * FROM apparatus WHERE vehicleType = 'Support'; $getSQL = mysql_query($sql); ?> <ul> <?php while ($vehicleData = mysql_fetch_assoc($getSQL)) {?> <li><?php echo $vehicleData['name'];?></li> <?php } ?> </ul> ..etc. Need to do this for four different types of vehicles. Thanks!

    Read the article

  • ajax echo returns javascript code!

    - by StevanSteve
    Hi, i have an ajax call. Php page (A) called by ajax requires some other php page (B). Page "B" is php file looking something like this <html> <head> javascript code </head> <body> PHP Code </body> Inside of "head" tags is javascript code. Now, Page "A" includes page "B", but instead of expected result, it echoes pure javascript code from included page "B"! How to prevent that?

    Read the article

  • Problems using "at" with Apache

    - by Alex Padgett
    I'm trying to use a PHP script to create at jobs, but when it comes time to execute the jobs, nothing seems to be happening. I've tried to output any errors to log files, but have had no luck. It seems obvious that it's a permissions issue, because when I set apache to run as my personal user, everything works fine. However, when I exec wget directly from PHP, everything works fine so it seems that apache has the correct permissions to use it. The problem appears to be when using at in conjunction with apache. So I need to find a way to make this work with apache running as its own user. Here is the command I'm using: echo "wget -qO- http://example.com/" | at now + 1 minute 2>&1 Any ideas? EDIT: Apache can create the at jobs, it just seems that when they execute nothing is happening.

    Read the article

  • WURFL's New API Question

    - by silent
    Hi all, I have a simple stupid question. Here's the problem, for years, my company has been using the old WURFL PHP API. Now, with the release of the new WURFL PHP API that promises a better performance, we want to use it. What I want to ask is, how do I update the cache? Can I use the old *update_cache.php*?

    Read the article

  • facebook access_token problem

    - by user559711
    Hi, I just wrote a little application(4 page php), everything work fine, however, I have a question that, do I need to create a new instance of facebook (just like $facebook = new facebook.....) in every new php page, or just pass a access token or session? If only pass the access token, how can I use the function $faceook-api('something'); to acheive the data? Because I'm a beginner of php, I have no idea how access token work, please help, thanks a lot! Regards, YK

    Read the article

  • Explanation of NSMutableURLRequest : setHTTPMethod

    - by kkmoslehpour
    I am new to objective c programming. I am currently trying to insert data into mysql database. I have read a couple links on this and could not find the exact answer I am looking for. Here is what I am trying to do: I have my app that user inputs a name in a text field and once the press the add button, it makes a connection to my php file and my php file does the rest of the work (using POST method) and adds the name to the mysql dataase. I have seen a lot of people use NSMutableURLRequest : setHTTPMethod :POST`` in their code (in my case my php file does that and I don't haveNSMutableURLRequest` included in my code and it works perfectly fine.) My questions are: Are there any benefits of including NSMutableURLRequest in your code when you can just call your php code to take care of the POST for you? What does NSMutableURLRequest exactly do and which way is more efficient?

    Read the article

  • How does Apache process several requests at a time?

    - by Vicenç Gascó
    In a short question: If 10 requests hit Apache, does it process them one by one, so when R3 finishes, then it starts to run R4, or does it fire 10 processes/threads/whatever and are resolved simultaneously? Now some background: I have a PHP script that takes up to two minutes to do some processes. My question is: while a client is waiting for this 2 minutes, all the other clients requests are being processed? Or also waiting for this one to end? By the way, if there are simultaneous request, how can I handle them? Let's say put a limit on them. Or a limit on resources consumed. For instance I want the server to use its 80% performance on serving the webapp, and just a 20% for those long operations ... because I have no hurry to end them. Doesn't know if it cares but is all in PHP. Thanks in advance!!

    Read the article

< Previous Page | 480 481 482 483 484 485 486 487 488 489 490 491  | Next Page >