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  • Error message when trying to insert method into touchesBegan

    - by Rob
    I am trying to create a new method within my TapDetectingImageView file and it's giving me a warning that it cannot find the method even though I have it declared in the .h file. The specific three warnings all point to the @end line in the .m file when I build it and they say: "Incomplete implementation of class 'TapDetectingImageView' ; 'Method definition for '-functionA:' not found" ; "Method definition for '-functionB:' not found" What am I missing? Am I not allowed to do this in a protocol file like TapDetectingImageView? In my .h file is: @interface TapDetectingImageView : UIImageView <AVAudioPlayerDelegate> { id <TapDetectingImageViewDelegate> delegate; } @property (nonatomic, assign) id <TapDetectingImageViewDelegate> delegate; -(void) functionA:(NSString*)aVariable; -(void) functionB:(NSString*)aVariable; @end In my .m file is: -(void)functionA:(NSString*)aVariable { // do stuff in this function with aVariable } -(void)functionB:(NSString*)aVariable { // do stuff in this function with aVariable }

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  • insert VBS variable within a single-quoted WMI query

    - by jiaoziren
    Hi all, I am really frustrated by the snippet below: Dim objFSO, varSrc, varDest, varExt Set objFSO = CreateObject("Scripting.FileSystemObject") varSrc = WScript.Arguments(0) varDest = WScript.Arguments(1) varExt = WScript.Arguments(2) If objFSO.FolderExists(varSrc) Then WScript.Echo varSrc strComputer = "." Set objWMIService = GetObject("winmgmts:" _ & "{impersonationLevel=impersonate}!\\" & strComputer & "\root\cimv2") Set colMonitoredEvents = objWMIService.ExecNotificationQuery _ ("SELECT * FROM __InstanceCreationEvent WITHIN 10 WHERE " _ & "Targetinstance ISA 'CIM_DirectoryContainsFile' AND " _ & "TargetInstance.GroupComponent= " _ & "'Win32_Directory.Name=""c:\\\\kk ""'") Do Set objLatestEvent = colMonitoredEvents.NextEvent WScript.Echo objLatestEvent.TargetInstance.PartComponent Loop Else WScript.Echo "Bazinga" End If I tried to replace c:\\kk with varSrc however it seems impossible for WSH to recognize it in WMI query - not to mention it was within a single quote! I have tried chr(34) and it didn't work. Please help if possible. Much appreciated!

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  • asp.net mvc DataViewModel Problem no insert and edit

    - by mazhar
    using the code DataViewModel with one form for create and edit with partial view , in the code below In the create*I am not able to enter the values to the database*,In the edit Mode I am not able to display the value as well in the textboxes for edit public class OrganizationGroupFormViewModel { // Properties public OrganizationGroup OrganizationGroup { get; private set; } public OrganizationGroupFormViewModel(OrganizationGroup organizationGroup) { OrganizationGroup = organizationGroup; } } public class OrganizationGroupsController : Controller { // // GET: /OrganizationGroups/ OrganizationGroupsRepository OrganizationGroupRepository = new OrganizationGroupsRepository(); OrganizationUsersDataContext _db = new OrganizationUsersDataContext(); public ActionResult Create() { try { OrganizationGroup OrgGroup = new OrganizationGroup() { int_CreatedBy=1, dtm_CreatedDate=DateTime.Now }; return View(new OrganizationGroupFormViewModel(OrgGroup)); } catch { return View(); } } [HttpPost] public ActionResult Create(OrganizationGroup OrgGroup) { if (ModelState.IsValid) { OrgGroup.int_CreatedBy = 1; OrgGroup.dtm_CreatedDate = DateTime.Now; OrganizationGroupRepository.Add(OrgGroup); OrganizationGroupRepository.Save(); return RedirectToAction("Details", new { id = OrganizationGroupRepository.int_OrganizationGroupId }); } return View(new OrganizationGroupFormViewModel(OrgGroup)); } // // GET: /OrganizationGroups/Edit/5 public ActionResult Edit(int id) { try { var OrgGroup = _db.OrganizationGroups.First(m => m.int_OrganizationGroupId == id); if (ModelState.IsValid) { OrgGroup.int_ModifiedBy = 1; OrgGroup.dtm_ModifiedDate = DateTime.Now; } return View(new OrganizationGroupFormViewModel(OrgGroup)); } catch { return View(); } } // // POST: /OrganizationGroups/Edit/5 [HttpPost] public ActionResult Edit(int id, FormCollection collection) { try { var OrgGroup = _db.OrganizationGroups.First(m => m.int_OrganizationGroupId == id); if (ModelState.IsValid) { OrgGroup.int_ModifiedBy = 1; OrgGroup.dtm_ModifiedDate = DateTime.Now; TryUpdateModel(OrgGroup); OrganizationGroupRepository.Save(); } return RedirectToAction("Details", new { id = OrgGroup.int_OrganizationGroupId }); } catch { return View(); } } Create View; <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<Egovst.Controllers.OrganizationGroupFormViewModel>" %> Create Organization Group <h2>Create</h2> <%= Html.ValidationSummary(true) %> <div> <% Html.RenderPartial("OrganizationGroup"); %> </div> Organization Group User Control <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<Egovst.Controllers.OrganizationGroupFormViewModel>" %> <% using (Html.BeginForm()) {%> <%= Html.ValidationSummary(true) %> <fieldset> <legend>Fields</legend> <div class="editor-label"> Organization Group Name: </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.OrganizationGroup.vcr_OrganizationGroupName)%> <%= Html.ValidationMessageFor(model => model.OrganizationGroup.vcr_OrganizationGroupName)%> </div> <div class="editor-label"> Organization Group Description: </div> <div class="editor-field"> <%= Html.TextAreaFor(model => model.OrganizationGroup.vcr_OrganizationGroupDesc)%> <%= Html.ValidationMessageFor(model => model.OrganizationGroup.vcr_OrganizationGroupDesc)%> </div> <p> <input type="submit" value="Save" /> </p> </fieldset> <% } %>

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  • Update query for Access Database for certain Parameters

    - by nitinkhanna
    Hi, I am using MS Access as a database and using c#, .net for updating some records in it. But it is giving error saying "No value given for one or more required parameters." There are 5 colums in Table and I want to update only 2, for that I have written the query like "update User_DTL set user_role_id = '" + _UserRole + "', auth_id ='" + _authId + "'" + " WHERE Id = '" + _Id + "' "; where _UserRole, _authId, _Id are strings. What may be the error. Do I need to give every parameter in update statement or there is some other way. Thanks

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  • I get NaN when I try to insert some HTML into a DIV element with jQuery

    - by Ankur
    I am tring to display a text box when a element of class numObj is clicked. For some reason I get NaNNaNaNaNNaNNaNaNaN where I expect to the see the result of the searchForm variable in the code below. I know that NaN stands for Not a Number. What I don't understand is why is Javascript expecting a number? I can't understand why it cares. $(".numObj").live('click',function(){ var preId = $(this).attr('preId'); var arrayPos = $(this).attr('numArrayPos'); alert(preId +" "+arrayPos); var searchForm = "<table border='0' cellspacing='0' cellpadding='4' id='add-tag2'>"+ +"<tr class='normal'><td bgcolor='#EEEEEE' valign='bottom' nowrap='nowrap'><span class='normal-small'>"+ +"<input name='predicate-name2' type='text' class='normal' id='predicate-name2' size='4' />"+ +"</span></td>"+ +"<td bgcolor='#EEEEEE' valign='bottom' nowrap='nowrap'><span class='normal-small'>&lt;=</span></td>"+ +"<td bgcolor='#EEEEEE' valign='bottom' nowrap='nowrap'>x</td>"+ +"<td valign='bottom' bgcolor='#EEEEEE'>&lt;=</td>"+ +"<td valign='bottom' bgcolor='#EEEEEE'><span class='normal-small'>"+ +"<input type='text' name='object-object2' id='object-object2' class='normal' size='4' />"+ +"</span></td>"+ +"</tr>"+ +"</table>"; $(".numObj").filter("[preId='"+preId+"']").filter("[numArrayPos='"+arrayPos+"']").html(searchForm); }); The generated code that has the numObj class looks something like this <td><div class="numObj" preid="73" numarraypos="5"><span class="normal">585.0</span></div></td>

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • Insert Image on Excel using Open XML

    - by Pankaj
    Hello All I am using this toolkit to write Excel.Every thing is fine with this, but i am not getting how can i inset image and also put style on some rows on my excel http://excelpackage.codeplex.com/wikipage?title=Creating%20an%20Excel%20spreadsheet%20from%20scratch&referringTitle=Home i am using c#

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  • Mysql_insert_id with Doctrine

    - by Industrial
    Hi! I have a couple of tables (mySQL) that i would like to update with the help of Doctrine. The products table id is auto-incrementing, and here's a brief description on what I would like to do: $prod = new Products(); $prod->type = '0'; $categ = new CategoriesToProducts(); $categ->cat = '111'; $categ->product = $prod->id; $conn = Doctrine_Manager::connection(); $conn->flush(); How can I do this while using flush? Using a regular save is an alternative, but there will be multiple transactions while doing such. I have tried to find a Mysql_insert_id version for doctrine, but without any luck. Thanks!

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  • Export MySQL Data as Insert Statements

    - by gav
    Hi All, I'm working in Ubuntu with MySql and I also have Query Browser and Administrator installed, I'm not afraid of the command line either if it helps. I want simply to be able to run a query and see a result set but then convert that result set into a series of commands that could be used to create the same rows in a table of an identical schema. I hope the question makes sense, it's quite a simple problem and one that must have been solved but I can't for the life of me work out where this kind of conversion is made available. Thanks in advance, Gav

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  • Get the identity value from an insert via a .net dataset update call

    - by DeveloperMCT
    Here is some sample code that inserts a record into a db table: Dim ds As DataSet = New DataSet() da.Fill(ds, "Shippers") Dim RowDatos As DataRow RowDatos = ds.Tables("Shippers").NewRow RowDatos.Item("CompanyName") = "Serpost Peru" RowDatos.Item("Phone") = "(511) 555-5555" ds.Tables("Shippers").Rows.Add(RowDatos) Dim custCB As SqlCommandBuilder = New SqlCommandBuilder(da) da.Update(ds, "Shippers") It inserts a row in the Shippers Table, the ShippersID is a Indentity value. My question is how can i retrieve the Identity value generated when the new row is inserted in the Shippers table. I have done several web searches and the sources I've seen on the net don't answer it speccifically or go on to talk about stored procedures. Any help would be appreciated. Thanks!

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  • Mod_Rewrite: Insert "/" between variables and values in URL

    - by Abs
    Hello all, I am attempting clean useful URLs using mod_rewrite. I am sure this is a common question but I am not so hot with mod_rewrite: I have this URL: http://mysite.com/user.php?user=fatcatmat&sort=popularv I want to be able to rewrite it like this: http://mysite.com/user/user/fatcatmat/sort/popularv (Is there a way to remove duplicates in a URL?) I think I have managed to do the removal of the PHP extension. RewriteRule ^(.*)\$ $1.php [nc] Is the above correct? For the separate pages, I would have something like this. RewriteRule ^/?user(/)?$ user.php Main Question: Its a bit tedious to do all the above but is there a MEGA rewrite rule that will just place "/" in between variables and their values and remove the .php extension from all pages? Thank you for any help.

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  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

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  • how to insert page view of a node in another page in drupal

    - by sprugman
    I have a list of node ids and I want to display the 'page' view of each one. For various reasons, I don't want to do this with views, and don't think I should need a module. Just an API call to theme('node'). Something like: $nids = array(3,4,5); foreach ($nids as $nid) { $node = node_load($nid); $result .= theme('node', $node); } but I'm not getting back the full page view of the node. I added this to my node-[type].tpl.php file: if ($page) print "PAGE MODE "; else print "NOT PAGE "; if ($teaser) print "TEASER MODE "; else print "NOT TEASER "; and got: NOT PAGE NOT TEASER I seem to be in some kind of limbo. I suspect there's an argument that I add to the theme function, but the terms are all so general (theme, teaser, page, node), I'm having trouble with my google-fu.

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  • Unable to Hide Update Button in GridView Editing

    - by nitinkhanna
    Hi, I am using commandfield edit button to edit the row of the gridview. But unable to perform the basics. This gridview is in update panel. When I press Edit button it shows UPDATE and CANCEL button but when I press UPDATE button it updates the DB but UPDATE button doesn't go back to EDIT one. While Cancel is working as it should. Like on pressing CANCEL it goes back to EDIT button, What I am doing worng. Thanks.

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  • Insert Registration Data in MySQL using PHP

    - by J M 4
    I may not be asking this in the best way possible but i will try my hardest. Thank you ahead of time for your help: I am creating an enrollment website which allows an individual OR manager to enroll for medical testing services for professional athletes. I will NOT be using the site as a query DB which anybody can view information stored within the database. The information is instead simply stored, and passed along in a CSV format to our network provider so they can use as needed after the fact. There are two possible scenarios: Scenario 1 - Individual Enrollment If an individual athlete chooses to enroll him/herself, they enter their personal information, submit their payment information (credit/bank account) for processing, and their information is stored in an online database as Athlete1. Scenario 2 - Manager Enrollment If a manager chooses to enroll several athletes he manages/ promotes for, he enters his personal information, then enters the personal information for each athlete he wishes to pay for (name, address, ssn, dob, etc), then submits payment information for ALL athletes he is enrolling. This number can range from 1 single athlete, up to 20 athletes per single enrollment (he can return and complete a follow up enrollment for additional athletes). Initially, I was building the database to house ALL information regardless of enrollment type in a single table which housed over 400 columns (think 20 athletes with over 10 fields per athlete such as name, dob, ssn, etc). Now that I think about it more, I believe create multiple tables (manager(s), athlete(s)) may be a better idea here but still not quite sure how to go about it for the following very important reasons: Issue 1 If I list the manager as the parent table, I am afraid the individual enrolling athlete will not show up in the primary table and will not be included in the overall registration file which needs to be sent on to the network providers. Issue 2 All athletes being enrolled by a manager are being stored in SESSION as F1FirstName, F2FirstName where F1 and F2 relate to the id of the fighter. I am not sure technically speaking how to store multiple pieces of information within the same table under separate rows using PHP. For example, all athleteswill have a first name. The very basic theory of what i am trying to do is: If number_of_athletes 1, store F1FirstName in row 1, column 1 of Table "Athletes"; store F1LastName in row 1, column 2 of Table "Athletes"; store F2FirstName in row 2, column 1 of Table "Athletes"; store F2LastName in row 2, column 2 of table "Athletes"; Does this make sense? I know this question is very long and probably difficult so i appreciate the guidance.

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  • Parse files in directory/insert in database

    - by jakesankey
    Hey there, Here is my dillema... I have a directory full of .txt comma delimited files arranged as shown below. What I want to do is to import each of these into a SQL or SQLite database, appending each one below the last. (1 table)... I am open to C# or VB scripting and just not sure how to accomplish this. I want to only extract and import the data starting BELOW the 'Feat. Type,Feat. Name, etc' line. These are stored in a \mynetwork\directory\stats folder on my network drive. Ideally I will be able to add functionality that will make the software/script know not to re-add the file to the database once it has already done so as well. Any guidance or tips is appreciated! $$ SAMPLE= $$ FIXTURE=- $$ OPERATOR=- $$ INSPECTION PROCESS=CMM #4 $$ PROCESS OPERATION=- $$ PROCESS SEQUENCE=- $$ TRIAL=- Feat. Type,Feat. Name,Value,Actual,Nominal,Dev.,Tol-,Tol+,Out of Tol.,Comment Point,_FF_PLN_A_1,X,-17.445,-17.445,0.000,-999.000,999.000,, Point,_FF_PLN_A_1,Y,-195.502,-195.502,0.000,-999.000,999.000,, Point,_FF_PLN_A_1,Z,32.867,33.500,-0.633,-0.800,0.800,, Point,_FF_PLN_A_2,X,-73.908,-73.908,0.000,-999.000,999.000,, Point,_FF_PLN_A_2,Y,-157.957,-157.957,0.000,-999.000,999.000,, Point,_FF_PLN_A_2,Z,32.792,33.500,-0.708,-0.800,0.800,, Point,_FF_PLN_A_3,X,-100.180,-100.180,0.000,-999.000,999.000,, Point,_FF_PLN_A_3,Y,-142.797,-142.797,0.000,-999.000,999.000,, Point,_FF_PLN_A_3,Z,32.768,33.500,-0.732,-0.800,0.800,, Point,_FF_PLN_A_4,X,-160.945,-160.945,0.000,-999.000,999.000,, Point,_FF_PLN_A_4,Y,-112.705,-112.705,0.000,-999.000,999.000,, Point,_FF_PLN_A_4,Z,32.719,33.500,-0.781,-0.800,0.800,, Point,_FF_PLN_A_5,X,-158.096,-158.096,0.000,-999.000,999.000,, Point,_FF_PLN_A_5,Y,-73.821,-73.821,0.000,-999.000,999.000,, Point,_FF_PLN_A_5,Z,32.756,33.500,-0.744,-0.800,0.800,, Point,_FF_PLN_A_6,X,-195.670,-195.670,0.000,-999.000,999.000,, Point,_FF_PLN_A_6,Y,-17.375,-17.375,0.000,-999.000,999.000,, Point,_FF_PLN_A_6,Z,32.767,33.500,-0.733,-0.800,0.800,, Point,_FF_PLN_A_7,X,-173.759,-173.759,0.000,-999.000,999.000,, Point,_FF_PLN_A_7,Y,14.876,14.876,0.000,-999.000,999.000,,

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  • greasemonkey insert javascript

    - by Kaartz
    I have a bookmarklet, clicking the bookmarklet includes a PHP script (evaluated as a JavaScript file) to the page few table values and select values passed as GET parameters. The PHP script writes the page data to the MySQL database, and outputs a success message that is treated as JavaScript code and executed by the browser. Is there any possibility to do this using greasemonkey and call this function when a existing button is clicked on the web page. I wrote the above bookmarklet inspired by this tutorial. http://tutorialzine.com/2010/04/simple-bookmarking-app-php-javascript-mysql/ This is the bookmarklet code: (function () { var jsScript = document.createElement('script'); jsScript.setAttribute('type', 'text/javascript'); jsScript.setAttribute('src', '/bookmark.php?url=' + encodeURIComponent(location.href) + '&title=' + encodeURIComponent(document.title)); document.getElementsByTagName('head')[0].appendChild(jsScript); })(); Please help me.

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  • SQL to insert latest version of a group of items

    - by Garett
    I’m trying to determine a good way to handle the scenario below. I have the following two database tables, along with sample data. Table1 contains distributions that are grouped per project. A project can have one or more distributions. A distribution can have one of more accounts. An account has a percentage allocated to it. The distributions can be modified by adding or removing account, as well as changing percentages. Table2 tracks distributions, assigning a version number to each distribution. I need to be able to copy new distributions from Table1 to Table2, but only under two conditions: 1. the entire distribution does not already exist 2. the distribution has been modified (accounts added/removed or percentages changed). Note: When copying a distribution from Table1 to Table2 I need to compare all accounts and percentages within the distribution to determine if it already exists. When inserting the new distribution then I need to increment the VersionID (max(VersionID) + 1). So, in the example provided the distribution (12345, 1) has been modified, adding account number 7, as well as changing percentages allocated. The entire distribution should be copied to the second table, incrementing the VersionID to 3 in the process. The database in question is SQL Server 2005. Table1 ------ ProjectID AccountDistributionID AccountID Percent 12345 1 1 25.0 12345 1 2 25.0 12345 1 7 50.0 56789 2 3 25.0 56789 2 4 25.0 56789 2 5 25.0 56789 2 6 25.0 Table2 ------ ID VersionID Project ID AccountDistributionID AccountID Percent 1 1 12345 1 1 50.0 2 1 12345 1 2 50.0 3 2 56789 2 3 25.0 4 2 56789 2 4 25.0 5 2 56789 2 5 25.0 6 2 56789 2 6 25.0

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