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  • jquery ajax form success callback not being called

    - by Michael Merchant
    I'm trying to upload a file using "AJAX", process data in the file and then return some of that data to the UI so I can dynamically update the screen. I'm using the JQuery Ajax Form Plugin, jquery.form.js found at http://jquery.malsup.com/form/ for the javascript and using Django on the back end. The form is being submitted and the processing on the back end is going through without a problem, but when a response is received from the server, my Firefox browser prompts me to download/open a file of type "application/json". The file has the json content that I've been trying to send to the browser. I don't believe this is an issue with how I'm sending the json as I have a modularized json_wrapper() function that I'm using in multiple places in this same application. Here is what my form looks after Django templates are applied: <form method="POST" enctype="multipart/form-data" action="/test_suites/active/upload_results/805/"> <p> <label for="id_resultfile">Upload File:</label> <input type="file" id="id_resultfile" name="resultfile"> </p> </form> You won't see any submit buttons because I'm calling submit with a button else where and am using ajaxSubmit() from the jquery.form.js plugin. Here is the controlling javascript code: function upload_results($dialog_box){ $form = $dialog_box.find("form"); var options = { type: "POST", success: function(data){ alert("Hello!!"); }, dataType: "json", error: function(){ console.log("errors"); }, beforeSubmit: function(formData, jqForm, options){ console.log(formData, jqForm, options); }, } $form.submit(function(){ $(this).ajaxSubmit(options); return false; }); $form.ajaxSubmit(options); } As you can see, I've gotten desperate to see the success callback function work and simply have an alert message created on success. However, we never reach that call. Also, the error function is not called and the beforeSubmit function is executed. The file that I get back has the following contents: {"count": 18, "failed": 0, "completed": 18, "success": true, "trasaction_id": "SQEID0.231"} I use 'success' here to denote whether or not the server was able to run the post command adequately. If it failed the result would look something like: {"success": false, "message":"<error_message>"} Your time and help is greatly appreciated. I've spent a few days on this now and would love to move on.

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  • How do I identify where the POST data sent to a PHP script came from?

    - by Mike Turley
    I have a ton of data collection forms on my website, and I wrote a PHP script to handle all the data. All the forms have that one script as their action, and POST as the method. The handler emails a copy of the data to me, and I'd like for the emails I get to contain the URL of the form where they originated. Is there any way in PHP to get the url of the form which was submitted to the script? Or do I have to add an extra hidden field in every form with its URL?

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  • Symfony2 same form, different entities NOT related

    - by user1381537
    I'm trying to write one form for submitting against MySQL DB, but I can't get it working, I've tried a lot of things (separate forms, create an ->add('foo', new foo()) to a field, and trying to parse plain SQL with a normal HTML form is my only solution, which is obviously not the best. This is my DB structure: As you can see I need to insert the comments textarea to ticketcomments among the user who wrote it, etc. On crmentity the description field. Then on ticketcf the fields that I need to submit from form, are this (because you wont know if I don't tell you because of the field names): tcf.cf594 AS Type, tcf.cf675 AS Suscription, tcf.cf770 AS ID_PRODUCT, tcf.cf746 AS NotificationDate, tcf.cf747 AS ResponseDate, tcf.cf748 AS ResolutionDate, And, of course, every table needs to have the same ticketid id for the submitted form, so we can retrieve it with one simple query. It will be easy to do with plain SQL instead of using DQL and Symfony2 forms, but is not a good way to do it. Also, here's my "Ticket list" query, if you need it to have it more clear... SELECT t.ticketNo AS Ticket, t.title AS Asunto, t.status AS Estado, t.updateLog AS LOG, t.hours AS Horas, t.solution AS Solucion, t.priority AS Prioridad, tcf.cf594 AS Tipo, tcf.cf675 AS Suscripcion, tcf.cf770 AS IDPROD, tcf.cf746 AS F_Noti, tcf.cf747 AS F_Resp, tcf.cf748 AS F_Reso, CONCAT (cd.firstname, cd.lastname) AS Contacto, crm.description AS Descripcion, crm.crmid AS id FROM WbsGoclientsBundle:VtigerTroubletickets t INNER JOIN WbsGoclientsBundle:VtigerTicketcf tcf WITH t.ticketid = tcf.ticketid INNER JOIN WbsGoclientsBundle:VtigerContactdetails cd WITH t.parentId = cd.contactid INNER JOIN WbsGoclientsBundle:VtigerCrmentity crm WITH t.ticketid = crm.crmid WHERE t.parentId IN ( SELECT cd1.contactid FROM WbsGoclientsBundle:VtigerContactdetails cd1 WHERE cd1.accountid = ( SELECT cd2.accountid FROM WbsGoclientsBundle:VtigerContactdetails cd2 WHERE cd2.contactid = :contactid)) AND t.status <> \'Closed\' And also "Ticket details" query (which is not in DQL format yet, only SQL) is so simple, it only retrieve the comments field and createdtime from ticketcomments appended to this query so we have all the fields... Thank you. This is a test form, using troubletickets and ticketcomments, it's returning errores because I can't set a comments field because troubletickets doesn't has it, but I need that field to be submitted to ticketcomments ... VtigerTicketcommentsType <?php namespace WbsGo\clientsBundle\Form\Type; use Symfony\Component\Form\AbstractType, Symfony\Component\Form\FormBuilderInterface; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class VtigerTicketcommentsType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('ticketid') ->add('comments') ->add('ownerid') ->add('ownertype') ->add('createdtype') ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'WbsGo\clientsBundle\Entity\VtigerTicketcomments' )); } public function getName() { return 'comments'; } } OpenTicketType.php <?php namespace WbsGo\clientsBundle\Form; use Symfony\Component\Form\AbstractType, Symfony\Component\Form\FormBuilderInterface ; use WbsGo\clientsBundle\Form\Type\VtigerTicketcommentsType; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class OpenTicketType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('title') ->add('priority') ->add('solution') ->add('comments', 'collection', array( 'type' => new VtigerTicketcommentsType() )) ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'WbsGo\clientsBundle\Entity\VtigerTroubletickets' )); } public function getName() { return 'ticket'; } } TicketController.php <?php namespace WbsGo\clientsBundle\Controller; use Symfony\Bundle\FrameworkBundle\Controller\Controller; use WbsGo\clientsBundle\Entity\VtigerTroubletickets; use WbsGo\clientsBundle\Entity\VtigerTicketcomments; use WbsGo\clientsBundle\Form\OpenTicketType; use Symfony\Component\HttpFoundation\Request; class TicketController extends Controller { public function indexAction() { $em = $this->getDoctrine()->getManager(); $tickets = $em ->getRepository('WbsGoclientsBundle:VtigerTroubletickets') ->findAllOpenByCustomerId($this->getUser()->getId()); $userdata = $this->getDoctrine()->getManager() ->getRepository('WbsGoclientsBundle:VtigerContactdetails') ->findContact($this->getUser()->getId()); return $this ->render('WbsGoclientsBundle:Ticket:index.html.twig', array('tickets' => $tickets, 'userdata' => $userdata)); } public function addAction() { $assets = $this->getDoctrine()->getManager() ->getRepository('WbsGoclientsBundle:VtigerAssets') ->findAssetByAccountId($this->getUser()->getId()); $assetlist = array(); foreach ($assets as $key => $v) { $assetlist[$key] = $key; } $form = $this->createForm(new OpenTicketType(), new VtigerTroubletickets()); return $this ->render('WbsGoclientsBundle:Ticket:add.html.twig', array('form' => $form->createView(), 'assets' => $assets,)); } } This is the error Symfony2 is returning Neither the property "comments" nor one of the methods "getComments()", "isComments()", "hasComments()", "_get()" or "_call()" exist and have public access in class "WbsGo\clientsBundle\Entity\VtigerTroubletickets". EDIT 2 This code is actually rendering my forms, but I need help in order to submit each XXXType form to its corresponding table. public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('descripcion') ->add('prioridad') ->add('solucion') ->add('comment', new VtigerTicketcommentsType() ) ->add('contacto') ->add('suscripcion') ->add('producto', 'entity', array( 'class' => 'WbsGo\clientsBundle\Entity\VtigerAssets', 'property' => 'assetname', 'empty_value' => '--SELECT--', 'query_builder' => function(\WbsGo\clientsBundle\Entity\VtigerAssetsRepository $repository) { //return $repository->findAssetByAccountId($this->customerId); return $repository->createQueryBuilder('a') ->select('a') ->where('a.account = (SELECT cd.accountid FROM WbsGoclientsBundle:VtigerContactdetails cd WHERE cd.contactid = ?1)') ->setParameter(1, $this->customerId); } ) ) ->add('hardware') ->add('backup') ->add('web') ->add('restore') ->add('customerId') ; } I also removed ->add('ticketid') from VtigerTicketcommentsType.php because it has relationship and is not needed. it's auto_incremental and must be generated once everything is submitted.

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  • How to display a hierarchical skill tree in php

    - by user3587554
    If I have skill data set up in a tree format (where earlier skills are prerequisites for later ones), how would I display it as a tree, using php? The parent would be on top and have 3 children. Each of these children can then have one more child so its parent would be directly above it. I'm having trouble figuring out how to add the root element in the middle of the top div, and the child of the children below each child of the root. I'm not looking for code, but an explanation of how to do it. My data in array form is this: Data: Array ( [1] => Array ( [id] => 1 [title] => Jutsu [description] => Skill that makes you awesomer at using ninjutsu [tiers] => 1 [prereq] => [image] => images/skills/jutsu.png [children] => Array ( [2] => Array ( [id] => 2 [title] => fireball [description] => Increase your damage with fire jutsu and weapons [tiers] => 5 [prereq] => 1 [image] => images/skills/fireball.png [children] => Array ( [5] => Array ( [id] => 5 [title] => pin point [description] => Increases jutsu accuracy [tiers] => 5 [prereq] => 2 [image] => images/skills/pinpoint.png ) ) ) [3] => Array ( [id] => 3 [title] => synergy [description] => Reduce the amount of chakra needed to use ninjutsu [tiers] => 1 [prereq] => 1 [image] => images/skills/synergy.png ) [4] => Array ( [id] => 4 [title] => ebb & flow [description] => Increase the damage of water jutsu, water weapons, and reduce the damage of jutsu and weapons that use water element [tiers] => 5 [prereq] => 1 [image] => images/skills/ebbandflow.png [children] => Array ( [6] => Array ( [id] => 6 [title] => IQ [description] => Decrease the time it takes to learn a jutsu [tiers] => 5 [prereq] => 4 [image] => images/skills/iq.png ) ) ) ) ) ) An example would be this demo image minus the hover stuff.

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  • PHP code works on Chrome, but not on Firefox or IE (send email via HTML form) [on hold]

    - by Cachirro
    My brother has this form: <form id="lista" action="lista2.php" method="post"> <input name="cf_name" type="text" size="50" hidden="yes" class="obscure"> <input name="cf_email" type="text" size="50" hidden="yes" class="obscure"> <textarea name="cf_message" cols="45" rows="10" hidden="yes" class="obscure"> </textarea> <input type="image" name="submit" value="Enviar Lista por Email" src="imagens/lista_email.png" width="40" height="40" onclick="this.form.elements['cf_message'].value = lista_mail;this.form.elements['cf_name'].value = prompt('Escreva o seu nome:', '');this.form.elements['cf_email'].value = prompt('Escreva o seu email:', '');"> <input name="submit2" type="submit" value="Enviar" hidden="yes" class="obscure"> </form> That calls this PHP file: <?php if ( isset($_POST['submit']) ) { // Dados de autenticacao SMTP $smtpinfo['host'] = 'localhost'; $smtpinfo['port'] = '25'; $smtpinfo['auth'] = true; $smtpinfo['username'] = 'xxx'; $smtpinfo['password'] = 'xxx'; // Dados recebidos do formulario $nome = $_POST['cf_name']; $email = $_POST['cf_email']; $mensagem = $_POST['cf_message']; // Inclusão de ficheiro PEAR. Certifique-se que o PEAR está activado no seu alojamento require_once "Mail.php"; // Corpo da mensagem $body = "Nome: ".$nome; $body.= "\n\n"; $body.= nl2br($mensagem); $headers = array ('From' => $email, 'To' => $smtpinfo["username"], 'Subject' => 'Encomenda Website'); $mail_object = Mail::factory('smtp', $smtpinfo); $mail = $mail_object->send($smtpinfo["username"], $headers, $body); if ( PEAR::isError($mail) ) { echo ("<p>" . $mail->getMessage() . "</p>"); } else { echo ('<b><font color="FFFF00">Mensagem enviada com sucesso.<br><br></b>Seu email: ' . $email . '<br><br></font>'); }} ?> This basically sends an email with some selected products, name and email. The problem is that it works perfectly on Chrome, but not on FF or IE. When the submit image is pressed, the URL changes to the PHP file, but it displays a blank page. After display errors activated: ini_set('display_errors',1); ini_set('display_startup_errors',1); error_reporting(-1) FF/IE display blank page and email isn't sent, Chrome sends the email and displays this: Strict Standards: Non-static method Mail::factory() should not be called statically in /var/www/vhosts/[site url]/httpdocs/lista2.php on line 33 Strict Standards: Non-static method PEAR::isError() should not be called statically, assuming $this from incompatible context in /usr/share/php/Mail/smtp.php , dont know if it helps So, what is causing the email to be sent on chrome and not on FF or IE? Thank you.

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  • How best to convert CakePHP date picker form data to a PHP DateTime object?

    - by Daren Thomas
    I'm doing this in app/views/mymodel/add.ctp: <?php echo $form->input('Mymodel.mydatefield'); ?> And then, in app/controllers/mymodel_controller.php: function add() { # ... (if we have some submitted data) $datestring = $this->data['Mymodel']['mydatefield']['year'] . '-' . $this->data['Mymodel']['mydatefield']['month'] . '-' . $this->data['Mymodel']['mydatefield']['day']; $mydatefield = DateTime::createFromFormat('Y-m-d', $datestring); } There absolutly has to be a better way to do this - I just haven't found the CakePHP way yet... What I would like to do is: function add() { # ... (if we have some submitted data) $mydatefield = $this->data['Mymodel']['mydatefiled']; # obviously doesn't work }

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  • Nginx + PHP - No input file specified for 1 server block. Other server block works fine

    - by F21
    I am running Ubuntu Desktop 12.04 with nginx 1.2.6. PHP is PHP-FPM 5.4.9. This is the relevant part of my nginx.conf: http { include mime.types; default_type application/octet-stream; sendfile on; keepalive_timeout 65; server { server_name testapp.com; root /www/app/www/; index index.php index.html index.htm; location ~ \.php$ { fastcgi_intercept_errors on; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; include fastcgi_params; } } server { listen 80 default_server; root /www index index.html index.php; location ~ \.php$ { fastcgi_intercept_errors on; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; include fastcgi_params; } } } Relevant bits from php-fpm.conf: ; Chroot to this directory at the start. This value must be defined as an ; absolute path. When this value is not set, chroot is not used. ; Note: you can prefix with '$prefix' to chroot to the pool prefix or one ; of its subdirectories. If the pool prefix is not set, the global prefix ; will be used instead. ; Note: chrooting is a great security feature and should be used whenever ; possible. However, all PHP paths will be relative to the chroot ; (error_log, sessions.save_path, ...). ; Default Value: not set ;chroot = ; Chdir to this directory at the start. ; Note: relative path can be used. ; Default Value: current directory or / when chroot chdir = /www In my hosts file, I redirect 2 domains: testapp.com and test.com to 127.0.0.1. My web files are all stored in /www. From the above settings, if I visit test.com/phpinfo.php and test.com/app/www, everything works as expected and I get output from PHP. However, if I visit testapp.com, I get the dreaded No input file specified. error. So, at this point, I pull out the log files and have a look: 2012/12/19 16:00:53 [error] 12183#0: *17 FastCGI sent in stderr: "Unable to open primary script: /www/app/www/index.php (No such file or directory)" while reading response header from upstream, client: 127.0.0.1, server: testapp.com, request: "GET / HTTP/1.1", upstream: "fastcgi://127.0.0.1:9000", host: "testapp.com" This baffles me because I have checked again and again and /www/app/www/index.php definitely exists! This is also validated by the fact that test.com/app/www/index.php works which means the file exists and the permissions are correct. Why is this happening and what are the root causes of things breaking for just the testapp.com v-host? Just an update to my investigation: I have commented out chroot and chdir in php-fpm.conf to narrow down the problem If I remove the location ~ \.php$ block for testapp.com, then nginx will send me a bin file which contains the PHP code. This means that on nginx's side, things are fine. The problem is that something must be mangling the file paths when passing it to PHP-FPM. Having said that, it is quite strange that the default_server v-host works fine because its root is /www, where as things just won't work for the testapp.com v-host because the root is /www/app/www.

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  • Redirect PHP-Shell-Script output

    - by Corelgott
    Hi Folks, i have got a php-script foo.php #!/usr/bin/php -c /etc/php5/cli/php.ini -q <?php echo 'hello'; // & do some stuff ?> I call this script not wrapped by a sh-script but using it directly in a cron job. To get rid of it's output i normally would just create a sh-file which calls /usr/bin/php -c /etc/php5/cli/php.ini -q foo.php > /dev/null 2 > /dev/null now i'd like to do this in the interpreter-declaration of the php file it self... so i am looking for the syntax for: #!/usr/bin/php -args [file's content] > /redirect 2 > /redirect i have kind of a hard time googleing for it... so if anybody could point me into the right direction i would really appreciate it! Thx in advance Corelgott

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  • Executing php with crontab

    - by Stefan Konno
    Hi everyone. I'm trying to run a php-script on a scheduled basis. So I'd thought crontab was a good idea. The server I'm using is on Linux which I'm not that familiar with. So the problem I'm having is, I don't know how make the script executable from php. I need to reference the script, or put it into a folder that can run php from the command line. So I don't know what path to give my crontab, for example: 5 * * * * var/www/some/path/script.php I found some vague information about this php executable being found in /usr/bin/php But I can't find any php file in there, maybe I don't have it installed? My php5 and apache installation is in: /etc/php5 So my question becomes, is there anyway to execute a php-script with crontab in any other folder, or do I just lack the php executable in usr/bin/php?

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  • Zend Framework: isValid() clears values from disabled form fields!

    - by Andrew
    When you submit a form, disabled form fields are not submitted in the request. So if your form has a disabled form field, it makes working with Zend_Form::isValid() a little frustrating. $form->populate($originalData); $form->my_text_field->disabled = 'disabled'; if (!$form->isValid($_POST)) { //form is not valid //since my_text_field is disabled, it doesn't get submitted in the request //isValid() will clear the disabled field value, so now we have to re-populate the field $form->my_text_field->value($originalData['my_text_field']); $this->view->form = $form; return; } // if the form is valid, and we call $form->getValues() to save the data, our disabled field value has been cleared! Without having to re-populate the form, and create duplicate lines of code, what is the best way to approach this problem?

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  • Opinions sought on the best way to organise classes in PHP

    - by jax
    I am pretty much set on using the Java package naming convention of com.website.app.whatever but am unsure about the best way of doing this in PHP. Option 1: Create a directory structure com/ mysite/ myapp/ encryption/ PublicKeyGenerator.class.php Cipher.class.php Xml/ XmlHelper.class.php XmlResponse.class.php Now this is how Java does it, it uses the folders to organize the heirarchy. This is however a little clumsy in PHP because there is no native support for it and when you move things around you break all includes. Option 2 Name classes using a periods for the package, therefore sames are just like in Java but can all be in the same directory making __autoload a breeze. classes/ com.mysite.myapp.encription.PublicKeyGenerator.class.php com.mysite.myapp.encription.Cipher.class.php com.mysite.myapp.xml.XmlHelper.class.php com.mysite.myapp.xml.XmlResponse.class.php The only real disadvantage here is that all the classes are in a single folder which might be confusing for large projects. Opinions sought, which is the best or are there other even better options?

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  • Creating a mySQL query using PHP form dropdowns - If user ignores dropdown, do not filter by that pa

    - by user303043
    Hello, I am creating a simple MySQL query that will be built from the user selecting options from 2 dropdowns. The issue I am having is that I would like each drop down to default that if they do not actually choose an option, do not filter by that dropdown parameter. So, if they come in, and simply hit submit without choosing from a dropdown they should see everything. If they come in and pick from only one of the dropdowns, the query will basically ignore filtering by the other dropdown. I tried making <OPTION VALUE='any'>Choose but my query didn't know what to do with the 'any' and just shows no results. Here is my code. Thank you very much for whatever help you can provide. FORM <form method="POST" action="<?php echo $_SERVER['REQUEST_URI']; ?>"> <select name="GameType"> <OPTION VALUE='any'>Choose Game Type <option value="Game1">Option 1</option> <option value="Game2">Option 2</option> <option value="Game3">Option 3</option> </select> <select name="Instructor"> <OPTION VALUE='any'>Choose Instructor <option VALUE="InstructorA">Instructor A</option> <option value="InstructorB">Instructor B</option> <option value="InstructorC">Instructor C</option> </select> <input type='submit' value='Search Videos'> </form> MYSQL <?PHP connection stuff $db_handle = mysql_connect($server, $user_name, $password); $db_found = mysql_select_db($database, $db_handle); if ($db_found) { $SQL = "SELECT * FROM Videos WHERE GameType=\"{$_POST['GameType']}\" AND Instructor=\"{$_POST['Instructor']}\""; $result = mysql_query($SQL); while ($db_field = mysql_fetch_assoc($result)) { echo $db_field['ShortDescription'] . ", "; echo $db_field['LongDescription'] . ", "; echo $db_field['GameType'] . ", "; echo $db_field['NumberOfPlayers'] . ", "; echo $db_field['Instructor'] . ", "; echo $db_field['Stakes'] . ", "; echo $db_field['UserPermissionLevel'] . ", "; echo $db_field['DateCreated'] . "<BR>"; } mysql_close($db_handle); } else { print "Database NOT Found "; mysql_close($db_handle); } ?>

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  • PHP class referencing confusion across multiple files

    - by DssTrainer
    I have an index.php file that has 3 includes <?php require_once('mod.php'); $mod = new Mod(); require_once('start.php'); require_once('tools.php'); ....some code.... ?> I need to be able to reference the $mod object inside the start.php and tools.php. How do I pass that object to be referenced by those 2 other require files? Basically the mod.php is a class that has an array list generated in its __construct(). I want to use that array list data inside the startup.php and tools.php file but not sure how to pass in the existing one without calling "new" inside both of those files separately which doesn't do what I need since it resets everything. Thanks!

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  • How to remove "index.php?" from HTACCESS [duplicate]

    - by Francis Goris
    This question already has an answer here: Reference: mod_rewrite, URL rewriting and “pretty links” explained 2 answers I have url like this: www.site.com/index.php?/genero/aventura/av/ But I would like this to be my new url: site.com/genero/aventura/av/ I used the following code: <IfModule mod_rewrite.c>RewriteEngine On RewriteCond %{HTTP_HOST} !^www.site.com/$ [NC] RewriteRule ^index.php\?/(.*)$ site.com/$1 [R=301,L] </IfModule> but only returns me: site.com/index.php?/genero/aventura/av/ This is my latest & full version: RewriteEngine on #RewriteCond $1 !^(index\.php|ver_capitulo\.html|google3436eb8eea8b8d6e\.html|BingSiteAuth\.xml |portadas|public|mp3|css|favicon\.ico|js|plantilla|i|swf|plugins|player\.swf|robots\.txt) RewriteCond $1 !^(index\.php|public|css|js|i|feed|portadas|robots\.txt|BingSiteAuth\.xml|plugins|i|mp3|favicon\.ico|pluginslist\.xml|google3436eb8eea8b8d6e\.html) RewriteRule ^(.*)$ /index.php?/$1 [L] #DirectoryIndex index.php #RewriteCond %{THE_REQUEST} http://www.page.com/index\.php [NC] #RewriteRule ^(.*?)index\.php$ http://page.com/$1 [L,R=301,NC,NE] #DirectoryIndex index.php #RewriteEngine On Thanks for reading.

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  • PHP: Simulate a <form> tag with POST data and also redirecting the user...

    - by tarnfeld
    Hi, I have been scouring the internet for a way to do this with no luck :( Basically, it's easy to make a form in HTML with a submit button and some data, and send it to a URL. With this you send the POST data and also the user is taken to the page. I know you can send POST data using cURL and get a response back in PHP but how do I take the user there, I need to simulate exactly what a tag does in php. Some sample code or links would be great! Thanks in advanced...

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  • PHP - Get value of imput box, without a form?

    - by Dodi300
    Hello. Does anyone know how I can get the value of an imput box, without having a form? I want a sumbit button, but instead of submiting a form, I want it to change data in a MySQL database. Something like this maybe? $img1="WHAT DO I PUT HERE?" $idx=1 $sql="INSERT INTO games SET img1='$img1' WHERE id=$idx"; $result=mysql_query($sql); Could I use that code on a "onclick" event? The imput box is named "img1". Thanks for the help!

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  • Career advice: stay with PHP or start a new career in something else ( .Net?)

    - by Christian P
    I'm planning on moving to NY in 6-12 months tops, so I'm forced to find a new job. When I'm planing to start my life in another city it's also probably a good time to think about career changes. I've found a lot of different opinions about PHP vs .Net vs Java and this is not topic here. I don't want to start a new fight about which language is better. Knowing programming language is not the most important thing for being a software developer. To be a really good developer you need to know OOP, design patterns, testing... and language is just a tool to make things happen. So back to my question. I have mixed experience in IT - 1 year as an IT support guy (Windows administration and support), around 2 years of experience in embedded programming (VB.Net 2005) and for the last 2 years I'm working with PHP/MySQL. I have worked with Magento web shop, assisted in some projects in Symfony, modified few Drupal sites. My main concerns are following: Do I continue to improve my skills in PHP e.g. to start learning some major PHP framework like Zend, Symfony maybe get some PHP certification. Or do I start learning .NET or Java. I'm more familiar to .NET so I'll probably choose it if choice falls between .NET and Java ( or you could convince me to choose Java :). Career-wise, I don't know what is the best choice. Learning new framework and language is more time consuming then improving my existing skills in PHP. But with .NET you have a lot of possibilities (Windows 7 Phone development, Silverlight, WPF) and possibly bigger chances to find better jobs. PHP jobs are less payed then .NET, at least, according to my researches (correct me if I'm wrong). But if I start now with .NET I'm just a beginner and my salary will be low. I need at least 2+ years of experience in some language to even try to find some job that is paying higher than $50-60k in NY. My main goal in next 2-3 years is to try to find a job in a $60-80k category. Don't get me wrong, I'm not just chasing money, but money is an important factor when you're trying to start a family. I'm 27 years old and I feel that there isn't a lot of room for wrong decisions regarding my career, so any advice will be very welcome. Update Thank you all for spending time to help me with my problem. All of the answers and comments have been very helpful. I have decided to stick with PHP but also to learn C# and Silverlight 4. We'll see where the life will take me.

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  • Is DreamWeaver a good tool to write PHP code? [closed]

    - by Akito
    I have started learning PHP. I have Windows XP installed. I use DreamWeaver to write PHP code and XAMP to run it. I love using DreamWeaver as I can handle, HTML, CSS, PHP, JavaScript using DreamWeaver. While learning online, I have seen many other configurations like using Eclipse and other tools. I wanted to ask if using Dreamweaver to write PHP code a good practice or it can be made better using any other code writing tool?

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  • Is having sensitive data in a PHP script secure? [closed]

    - by tkbx
    Possible Duplicate: What attributes of PHP make it insecure? I've heard that PHP is somewhat secure because Apache won't allow the download of raw PHP. Is this reliable, though? For example, if you wanted to password protect something, but didn't want to create a database, would something like $pass = "123454321"; be safe? Bottom line, is it safe to assume that nobody has access to the actual .php file?

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  • PHP-FPM bind issues

    - by Leo
    I have a setup of a mac server running Nginx 1.2.3, PHP-FPM 5.3.10 on OSX Lion. It works fine with Nginx on port 8080 ( using port fordwaring on from 80 ) and PHP-FPM listening on 9000. Both are running as /System/LaunchDaemons. My issue is that the system log is full of these errors ( every ten seconds ) which despite the fact the system works I don't like. Sep 10 19:59:05 mac-server php-fpm[974]: [10-Sep-2012 19:59:05] ERROR: unable to bind listening socket for address '127.0.0.1:9000': Address already in use (48) Sep 10 19:59:05 mac-server php-fpm[974]: [10-Sep-2012 19:59:05] ERROR: FPM initialization failed Sep 10 19:59:05 mac-server com.apple.launchd[1] (php-fpm): Throttling respawn: Will start in 10 seconds I have pretty much an out of the box php-fpm config. Could someone please point me to what configuration variables may be causing this problem. There are not any errorneous LaunchAgent/LaunchDaemons floating around either?

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  • PHP FastCGI HTTP Error 500 on Windows 7

    - by CJM
    I've just installed PHP (5.3.1) and MySQL (5.1.44) on my development machine. Then I used the Web Platform Installer to install a copy of Joomla and Drupal. However, when I tried to browse either site application, I get a HTTP Error 500: Module FastCgiModule Notification ExecuteRequestHandler Handler PHP_via_FastCGI Error Code 0x00000000 Requested URL http://localhost:808/drupal/index.php Physical Path D:\Projects\drupal\index.php Logon Method Anonymous Logon User Anonymous PHPInfo.php reports that FastCGI is configured (not sure if that is significant). Sure the fact that PHPInfo.php reports anything is perhaps an indication that PHP itself is working...? I'm struggling to know where to look for a solution... Each application appears to be configure similarly to my other [ASP/ASP.NET] applications.

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  • PHP ZendOptimizer on Red Hat Enterprise Linux

    - by Jacob Kristensen
    I would like to install FlashMoto and the requirements are not unreasonable: PHP 5.2.1 or higher, Zend Optimizer 3.3 or higher. However my RHEL 5.4 provides me with PHP 5.1.6. So I tried the remi repository http://rpms.famillecollet.com/ but it gave me PHP 5.3.1 and Zend Optimizer from zend.com does not support anything higher than 5.2.x. I also tried the dag repo but it does not have PHP in any version. I also tried some RPMs that Oracle provides on their homepage but they don't provide php-mbstring that I also need. Does anyone know how to get PHP 5.2.1 installed on a RHEL 5.4? Then I can probably fix install the Zend thing. Thanks in advance.

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  • How to restart php-cgi automatically with spawn-fcgi

    - by mrm8
    I'm running nginx with php as fcgi. It's working just fine, however, php-cgi keeps on exit()ing after serving 500 requests. I tried increasing that value (PHP_FCGI_MAX_REQUESTS), and that worked, but that seems to be a workaround. Then I set it to 0, and it didn't exit() yet. But I think there's a reason why php-cgi should be restarted. At the moment, I'm running php-cgi with spawn-fcgi: when the php process exits, spawn-fcgi exits, too. Now, is there a way to automatically restart php (without dirty hacks like while [ 1 ]; do spawn-fcgi; done etc)?

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  • PHP FastCGI HTTP Error 500 on Windows 7

    - by CJM
    I've just installed PHP (5.3.1) and MySQL (5.1.44) on my development machine. Then I used the Web Platform Installer to install a copy of Joomla and Drupal. However, when I tried to browse either site application, I get a HTTP Error 500: Module FastCgiModule Notification ExecuteRequestHandler Handler PHP_via_FastCGI Error Code 0x00000000 Requested URL http://localhost:808/drupal/index.php Physical Path D:\Projects\drupal\index.php Logon Method Anonymous Logon User Anonymous PHPInfo.php reports that FastCGI is configured (not sure if that is significant). Sure the fact that PHPInfo.php reports anything is perhaps an indication that PHP itself is working...? I'm struggling to know where to look for a solution... Each application appears to be configure similarly to my other [ASP/ASP.NET] applications.

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  • .php files see Apache environment variables, .html files don't

    - by dotancohen
    Consider this environment: $ cat .htaccess AddType application/x-httpd-php .php .html SetEnv Foo Bar $ cat test.php <?php echo "Hello: "; echo $_SERVER['Foo']; echo $_ENV['Foo']; echo getenv('Foo'); ?> $ cat test.html <?php echo "Hello: "; echo $_SERVER['Foo']; echo $_ENV['Foo']; echo getenv('Foo'); ?> This is the output of test.php: Hello BarBarBar This is the output of test.html: Hello Why might that be? How might I fix it? Here is phpinfo.php: http://pastebin.com/rgq7up61 Here is phpinfo.html: http://pastebin.com/VUKFNZ36 If anyone knows where I can host a real webpage instead of just the HTML for one, please let me know and I'll move the content to there. Thanks.

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