Search Results

Search found 43671 results on 1747 pages for 'html form'.

Page 493/1747 | < Previous Page | 489 490 491 492 493 494 495 496 497 498 499 500  | Next Page >

  • .NET MVC Ajax Form - How do you hide it?

    - by Tommy
    Ok, everything is 'functionally' working with what I am attempting to accomplish and once again, I am sure this is something dumb, but I cannot figure out how to do this one thing. I have an edit form for an entity, lets say a car. This 'car' can have 0 - many passengers. So on my edit form, I have all the fields for the car, then a list view showing each passenger (partial). I also have a 'add new passenger' button that will render a new partial view that allows you to enter a passenger. This has a cancel link and an add button to submit an Ajax form. When you add a passenger, the passenger is automatically added to the list, but I need the enter passenger form to go away. I have tried using the onSuccess and onComplete functions to hide the div that the form is in, but both render just the partial view HTML elements (white screen, text) and not the partialView in the context of the entire page. Sources: 1) Main Edit View <script type="text/javascript"> Function hideForm(){ document.getElementById('newPassenger').style.display = 'none'; } </script> <h2>Edit</h2> <%-- The following line works around an ASP.NET compiler warning --%> <%= ""%> <%Html.RenderPartial("EditCar", Model)%> <h2>Passengers for this car</h2> <%=Ajax.ActionLink("Add New Passenger", "AddPassenger", New With {.ID = Model.carID}, New AjaxOptions With {.UpdateTargetId = "newPassenger", .InsertionMode = InsertionMode.Replace})%> <div id="newPassenger"></div> <div id="passengerList"> <%Html.RenderPartial("passengerList", Model.Passengers)%> </div> <div> <%= Html.ActionLink("Back to List", "Index") %> </div> 2) AddPassenger View. The cancel link below is an action that returns nothing, thus removing the information in the div. <% Using Ajax.BeginForm("AddPassengerToCar", New With {.id = ViewData("carID")}, New AjaxOptions With {.UpdateTargetId = "passengerList", .InsertionMode = InsertionMode.Replace})%> <%=Html.DropDownList("Passengers")%> <input type="submit" value="Add" /> <%=Ajax.ActionLink("Cancel", "CancelAddControl", _ New AjaxOptions With {.UpdateTargetId = "newPassenger", .InsertionMode = InsertionMode.Replace})%><% end using %>

    Read the article

  • Using respond_to ... format.json and jQuery Form Plugin by malsup

    - by Topher Fangio
    Hello all, I'm having a tad bit of trouble getting the jQuery Form Plugin to work properly with a file-upload field. When I use the plugin to submit the form without a file-upload field, the format.json portion of the respond_to do |format| block is called properly. However, by adding the file-upload field, it only executes the format.html portion which makes my javascript code think that an error has occurred. Has anyone run into this before or know a way to force the plugin to always use json? Alternatively, can I modify the url that the plugin uses to force Rails to render the json? Thanks very much for any help! Code below: # app/controllers/details_controller.rb def create @detail = Detail.new(params[:detail]) style = params[:detail_style].to_sym || :thumb data = { :id => '5', :url => 'test.rails' } respond_to do |format| if @detail.save flash[:notice] = 'Your image has been saved.' data = { :id => @detail.id, :url => @detail.data.url(style) } format.html { redirect_to :action => 'index' } format.json { render :json => "<textarea>#{data.to_json}</textarea>", :status => :created } else format.html { render :action => 'new' } format.json { render :json => @detail.errors, :status => :unprocessable_entity } end end end /* app/views/sidebar/_details.html.erb (excerpt) */ <% form_for(Detail.new, :html => { :multipart => true } ) do |f| %> <%= hidden_field_tag 'detail_style', 'thumb' %> <%= f.label :image, "Recent Images" %> <%= f.file_field :image%> <p> <%= f.submit "Upload" %> </p> <% end %> <script> $(document).ready(function() { var options = { dataType: 'json', success: function(json, statusText) { console.log("success: " + json); }, error: function(xhr, statusText, errorThrown) { console.log("error: " + xhr.responseText); } }; $('#new_detail').ajaxForm(options); });

    Read the article

  • How do I apply a servlet filter when serving an HTML page directly?

    - by Philippe Beaudoin
    First off, I'm using Google AppEngine and Guice, but I suspect my problem is not related to these. When the user connect to my (GWT) webapp, the URL is a direct html page. For example, in development mode, it is: http://127.0.0.1:8888/Puzzlebazar.html?gwt.codesvr=127.0.0.1:9997. Now, I setup my web.xml in the following way: <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> <display-name>PuzzleBazar</display-name> <!-- Default page to serve --> <welcome-file-list> <welcome-file>Puzzlebazar.html</welcome-file> </welcome-file-list> <filter> <filter-name>guiceFilter</filter-name> <filter-class>com.google.inject.servlet.GuiceFilter</filter-class> </filter> <filter-mapping> <filter-name>guiceFilter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <!-- This Guice listener hijacks all further filters and servlets. Extra filters and servlets have to be configured in your ServletModule#configureServlets() by calling serve(String).with(Class<? extends HttpServlet>) and filter(String).through(Class<? extends Filter) --> <listener> <listener-class>com.puzzlebazar.server.guice.MyGuiceServletContextListener </listener-class> </listener> </web-app> Since I'm using Guice, I have to configure extra filters in my ServletModule, where I do this: filter("*.html").through( SecurityCookieFilter.class ); But my SecurityCookieFilter.doFilter is never called. I tried things like "*.html*" or <url-pattern>*</url-pattern> but to no avail. Any idea how I should do this?

    Read the article

  • Why always fires OnFailure when return View() to Ajax Form ?

    - by Wahid Bitar
    I'm trying to make a log-in log-off with Ajax supported. I made some logic in my controller to sign the user in and then return simple partial containing welcome message and log-Off ActionLink my Action method looks like this : public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (Request.IsAjaxRequest()) { //HERE IS THE PROBLEM :( return View("LogedInForm"); } else { if (!String.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); if (Request.IsAjaxRequest()) { return Content("There were an error !"); } } } return View(model); } and I'm trying to return this simple partial : Welcome <b><%= Html.Encode(Model.UserName)%></b>! <%= Html.ActionLink("Log Off", "LogOff", "Account") %> and of-course the two partial are strongly-typed to LogOnModel. But if i returned View("PartialName") i always get OnFailure with status code 500. While if i returned Content("My Message") everything is going right. so please tell me why i always get this "StatusCode = 500" ??. where is the big mistake ??. By the way in my Site MasterPage i rendered partial to show long-on simple form this partial looks like this : <script type="text/javascript"> function ShowErrorMessage(ajaxContext) { var response = ajaxContext.get_response(); var statusCode = response.get_statusCode(); alert("Sorry, the request failed with status code " + statusCode); } function ShowSuccessMessage() { alert("Hey everything is OK!"); } </script> <div id="logedInDiv"> </div> <% using (Ajax.BeginForm("LogOn", "Account", new AjaxOptions { UpdateTargetId = "logedInDiv", InsertionMode = InsertionMode.Replace, OnSuccess = "ShowSuccessMessage", OnFailure = "ShowErrorMessage" })) { %> <%= Html.TextBoxFor(m => m.UserName)%> <%= Html.PasswordFor(m => m.Password)%> <%= Html.CheckBoxFor(m => m.RememberMe)%> <input type="submit" value="Log On" /> < <% } %>

    Read the article

  • Reading POST data from html form sent to serversocket.

    - by user32167
    i try to write simplest possible server app in Java, displaying html form with textarea input, which after submitting gives me possibility to parse xml typed in that textarea. For now i build simple serversocket based server like that: import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.net.ServerSocket; import java.net.Socket; public class WebServer { protected void start() { ServerSocket s; String gets = ""; System.out.println("Start on port 80"); try { // create the main server socket s = new ServerSocket(80); } catch (Exception e) { System.out.println("Error: " + e); return; } System.out.println("Waiting for connection"); for (;;) { try { // wait for a connection Socket remote = s.accept(); // remote is now the connected socket System.out.println("Connection, sending data."); BufferedReader in = new BufferedReader(new InputStreamReader( remote.getInputStream())); PrintWriter out = new PrintWriter(remote.getOutputStream()); String str = "."; while (!str.equals("")) { str = in.readLine(); if (str.contains("GET")){ gets = str; break; } } out.println("HTTP/1.0 200 OK"); out.println("Content-Type: text/html"); out.println(""); // Send the HTML page String method = "get"; out.print("<html><form method="+method+">"); out.print("<textarea name=we></textarea></br>"); out.print("<input type=text name=a><input type=submit></form></html>"); out.println(gets); out.flush(); remote.close(); } catch (Exception e) { System.out.println("Error: " + e); } } } public static void main(String args[]) { WebServer ws = new WebServer(); ws.start(); } } After form (textarea with xml and one additional text input) is submitted in 'gets' String-type variable I have Urlencoded values of my variables (also displayed on the screen, it looks like that: gets = GET /?we=%3Cnetwork+ip_addr%3D%2210.0.0.0%2F8%22+save_ip%3D%22true%22%3E%0D%0A%3Csubnet+interf_used%3D%22200%22+name%3D%22lan1%22+%2F%3E%0D%0A%3Csubnet+interf_used%3D%22254%22+name%3D%22lan2%22+%2F%3E%0D%0A%3C%2Fnetwork%3E&a=fooBar HTTP/1.1 What can i do to change GET to POST method (if i simply change it in form and than put " if (str.contains("POST")){" it gives me string like gets = POST / HTTP/1.1 with no variables. And after that, how i can use xml from my textarea field (called 'we')?

    Read the article

  • How do you select form elements in JQuery based upon an html table?

    - by Swoop
    I am working on some ASP.NET web forms which involves some dynamic generation, and I need to add some onClick helpers on the client side. I have a basic outline of something working, except for one huge problem. There are multiple HTML tables, each generated by a different ASP.NET web control. Each table can contain overlapping field names, which is causing a problem with my JQuery click event handlers. The click event handler is linking to unintended form fields in addition to the intended form field. I have provided a simplified sample version of the code below. This code is trying to set the value of textbox box1 when a particular radiobutton is selected in the table with id=thing1. Obviously, the jquery code will be triggered for the form fields in both tables. The tables are dynamically added to the webpage based upon different conditions. It is possible that no tables will be loaded, only 1 table, or both tables might load. In the future, other tables could be added. Each table comes from a different .net web control. Other than renaming the form fields to make sure they are unique across all user controls, is there a way to have JQuery act only on the intended form fields? In other words, could the table ID be incorporated into the JQuery code in a manner that does not become a nightmare to maintain later? <script> $(document).ready(function() { $("[id$=radio1_0]").click(function() { $("[id$=box1]").attr("value", ""); }); $("[id$=radio1_1]").click(function() { $("[id$=box1]").attr("value", "N/A"); }); </script> <table id="thing1"> <tr><td> <radiobuttonlist id="radio1"/> <listitem>yes</listitem> <listitem>no</listitem> </td></tr> <tr><td> <textbox id="box1"/> </td></tr> </table> <table id="thing2"> <tr><td> <radiobuttonlist id="radio1"/> <listitem>yes</listitem> <listitem>no</listitem> </td></tr> <tr><td> <textbox id="box1"/> </tr></td> </table>

    Read the article

  • Why the parent page get refreshed when I click the link to open thickbox-styled form?

    - by user333205
    Hi, all: I'm using Thickbox 3.1 to show signup form. The form content comes from jquery ajax post. The jquery lib is of version 1.4.2. I placed a "signup" link into a div area, which is a part of my other large pages, and the whole content of that div area is ajax+posted from my server. To make thickbox can work in my above arangement, I have modified the thickbox code a little like that: //add thickbox to href & area elements that have a class of .thickbox function tb_init(domChunk){ $(domChunk).live('click', function(){ var t = this.title || this.name || null; var a = this.href || this.alt; var g = this.rel || false; tb_show(t,a,g); this.blur(); return false; });} This modification is the only change against the original version. Beacause the "signup" link is placed in ajaxed content, so I Use live instead of binding the click event directly. When I tested on my pc, the thickbox works well. I can see the signup form quickly, without feeling the content of the parent page(here, is the other large pages) get refreshed. But after transmiting my site files into VHost, when I click the "signup" link, the signup form get presented very slowly. The large pages get refreshed evidently, because the borwser(ie6) are reloading images from server incessantly. These images are set as background images in CSS files. I think that's because the slow connection of network. But why the parent pages get refreshed? and why the browser reloads those images one more time? Havn't those images been placed in local computer's disk? Is there one way to stop that reloadding? Because the signup form can't get displayed sometimes due to slow connection of network. To verified the question, you can access http://www.juliantec.info/track-the-source.html and click the second link in left grey area, that is the "signup" link mentioned above. Thinks!

    Read the article

  • [java] reading POST data from html form sent to serversocket.

    - by user32167
    i try to write simplest possible server app in Java, displaying html form with textarea input, which after submitting gives me possibility to parse xml typed in thet textarea. For now i build simple serversocket based server like that: import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.PrintWriter; import java.net.ServerSocket; import java.net.Socket; public class WebServer { protected void start() { ServerSocket s; String gets = ""; System.out.println("Start on port 80"); try { // create the main server socket s = new ServerSocket(80); } catch (Exception e) { System.out.println("Error: " + e); return; } System.out.println("Waiting for connection"); for (;;) { try { // wait for a connection Socket remote = s.accept(); // remote is now the connected socket System.out.println("Connection, sending data."); BufferedReader in = new BufferedReader(new InputStreamReader( remote.getInputStream())); PrintWriter out = new PrintWriter(remote.getOutputStream()); String str = "."; while (!str.equals("")) { str = in.readLine(); if (str.contains("GET")){ gets = str; break; } } out.println("HTTP/1.0 200 OK"); out.println("Content-Type: text/html"); out.println(""); // Send the HTML page String method = "get"; out.print("<html><form method="+method+">"); out.print("<textarea name=we></textarea></br>"); out.print("<input type=text name=a><input type=submit></form></html>"); out.println(gets); out.flush(); remote.close(); } catch (Exception e) { System.out.println("Error: " + e); } } } public static void main(String args[]) { WebServer ws = new WebServer(); ws.start(); } } After form (textarea with xml and one additional text input) is submitted in 'gets' String-type variable I have Urlencoded values of my variables (also displayed on the screen, it looks like that: gets = GET /?we=%3Cnetwork+ip_addr%3D%2210.0.0.0%2F8%22+save_ip%3D%22true%22%3E%0D%0A%3Csubnet+interf_used%3D%22200%22+name%3D%22lan1%22+%2F%3E%0D%0A%3Csubnet+interf_used%3D%22254%22+name%3D%22lan2%22+%2F%3E%0D%0A%3C%2Fnetwork%3E&a=fooBar HTTP/1.1 What can i do to change GET to POST method (if i simply change it in form and than put " if (str.contains("GET")){" it gives me string like gets = POST / HTTP/1.1 with no variables. And after that, how i can use xml from my textarea field (called 'we')?

    Read the article

  • How to use python and beautfulsoup to print timestamp/last updated time (from HTML:) for each row ?

    - by cesalo
    How to use python and beautfulsoup to print timestamp/last updated time (from HTML:) for each row ? thanks a lot ! A) 1) can i add the print a)date/time and b)last updated time after row ? a) date/time - display the time when execute the python code b) last updated time from HTML: HTML structure: td x 1 including two tables each table have few "tr" and within "tr" have few "td" data inside HTML: <td> <table width="100%" border="4" cellspacing="0" bordercolor="white" align="center"> <tbody> <tr> <td colspan="2" class="verd_black11">Last Updated: 18/08/2014 10:19</td> </tr> <tr> <td colspan="3" class="verd_black11">All data delayed at least 15 minutes</td> </tr> </tbody> </table> <table width="100%" border="4" cellspacing="0" bordercolor="white" align="center"> <tbody id="tbody"> <tr id="tr0" class="tableHdrB1" align="center"> <td align="centre">C Aug-14 - 15000</td> <td align="right"> - </td> <td align="right">5</td> <td align="right">9,904</td> </tr> </tbody> </table> </td> Code: import urllib2 from bs4 import BeautifulSoup contenturl = "HTML:" soup = BeautifulSoup(urllib2.urlopen(contenturl).read()) table = soup.find('tbody', attrs={'id': 'tbody'}) rows = table.findAll('tr') for tr in rows: cols = tr.findAll('td') for td in cols: t = td.find(text=True) if t: text = t + ';' print text, print Output from above code C Aug-14 - 15000 ; - ; 5 ; 9,904 Expected output: C Aug-14 - 15000 ; - ; 5 ; 9,904 ; 18/08/2014 ; 13:48:00 ; 18/08/2014 ; 10:19 (execute python code) (last updated time)

    Read the article

  • MVC 2 Entity Framework View Model Insert

    - by cannibalcorpse
    This is driving me crazy. Hopefully my question makes sense... I'm using MVC 2 and Entity Framework 1 and am trying to insert a new record with two navigation properties. I have a SQL table, Categories, that has a lookup table CategoryTypes and another self-referencing lookup CategoryParent. EF makes two nav properties on my Category model, one called Parent and another called CategoryType, both instances of their respective models. On my view that creates the new Category, I have two dropdowns, one for the CategoryType and another for the ParentCategory. When I try and insert the new Category WITHOUT the ParentCategory, which allows nulls, everything is fine. As soon as I add the ParentCategory, the insert fails, and oddly (or so I think) complains about the CategoryType in the form of this error: 0 related 'CategoryTypes' were found. 1 'CategoryTypes' is expected. When I step through, I can verifiy that both ID properties coming in on the action method parameter are correct. I can also verify that when I go to the db to get the CategoryType and ParentCategory with the ID's, the records are being pulled fine. Yet it fails on SaveChanges(). All that I can see is that my CategoryParent dropdownlistfor in my view, is somehow causing the insert to bomb. Please see my comments in my httpPost Create action method. My view model looks like this: public class EditModel { public Category MainCategory { get; set; } public IEnumerable<CategoryType> CategoryTypesList { get; set; } public IEnumerable<Category> ParentCategoriesList { get; set; } } My Create action methods look like this: // GET: /Categories/Create public ActionResult Create() { return View(new EditModel() { CategoryTypesList = _db.CategoryTypeSet.ToList(), ParentCategoriesList = _db.CategorySet.ToList() }); } // POST: /Categories/Create [HttpPost] public ActionResult Create(Category mainCategory) { if (!ModelState.IsValid) return View(new EditModel() { MainCategory = mainCategory, CategoryTypesList = _db.CategoryTypeSet.ToList(), ParentCategoriesList = _db.CategorySet.ToList() }); mainCategory.CategoryType = _db.CategoryTypeSet.First(ct => ct.Id == mainCategory.CategoryType.Id); // This db call DOES get the correct Category, but fails on _db.SaveChanges(). // Oddly the error is related to CategoryTypes and not Category. // Entities in 'DbEntities.CategorySet' participate in the 'FK_Categories_CategoryTypes' relationship. // 0 related 'CategoryTypes' were found. 1 'CategoryTypes' is expected. //mainCategory.Parent = _db.CategorySet.First(c => c.Id == mainCategory.Parent.Id); // If I just use the literal ID of the same Category, // AND comment out the CategoryParent dropdownlistfor in the view, all is fine. mainCategory.Parent = _db.CategorySet.First(c => c.Id == 2); _db.AddToCategorySet(mainCategory); _db.SaveChanges(); return RedirectToAction("Index"); } Here is my Create form on the view : <% using (Html.BeginForm()) {%> <%= Html.ValidationSummary(true) %> <fieldset> <legend>Fields</legend> <div> <%= Html.LabelFor(model => model.MainCategory.Parent.Id) %> <%= Html.DropDownListFor(model => model.MainCategory.Parent.Id, new SelectList(Model.ParentCategoriesList, "Id", "Name")) %> <%= Html.ValidationMessageFor(model => model.MainCategory.Parent.Id) %> </div> <div> <%= Html.LabelFor(model => model.MainCategory.CategoryType.Id) %> <%= Html.DropDownListFor(model => model.MainCategory.CategoryType.Id, new SelectList(Model.CategoryTypesList, "Id", "Name"))%> <%= Html.ValidationMessageFor(model => model.MainCategory.CategoryType.Id)%> </div> <div> <%= Html.LabelFor(model => model.MainCategory.Name) %> <%= Html.TextBoxFor(model => model.MainCategory.Name)%> <%= Html.ValidationMessageFor(model => model.MainCategory.Name)%> </div> <div> <%= Html.LabelFor(model => model.MainCategory.Description)%> <%= Html.TextAreaFor(model => model.MainCategory.Description)%> <%= Html.ValidationMessageFor(model => model.MainCategory.Description)%> </div> <div> <%= Html.LabelFor(model => model.MainCategory.SeoName)%> <%= Html.TextBoxFor(model => model.MainCategory.SeoName, new { @class = "large" })%> <%= Html.ValidationMessageFor(model => model.MainCategory.SeoName)%> </div> <div> <%= Html.LabelFor(model => model.MainCategory.HasHomepage)%> <%= Html.CheckBoxFor(model => model.MainCategory.HasHomepage)%> <%= Html.ValidationMessageFor(model => model.MainCategory.HasHomepage)%> </div> <p><input type="submit" value="Create" /></p> </fieldset> <% } %> Maybe I've just been staying up too late playing with MVC 2? :) Please let me know if I'm not being clear enough.

    Read the article

  • How do I use jquery validate remote validation on a field that depends on another field in the form?

    - by Kevin J
    I have a form in which I am using remote validation to check if an email address already exists in the database. However, the catch is that on this form, the user can select between several different "groups", and each group has its own distinct set of email addresses (thus the same email can exist once in each group). The group selection is a dropdown on the form, and the email address is an input field with remote validation. I have a couple issues. First, I have set up my remote rule like this: remote: { url: 'remote_script.php', data: { group_id: $('select.group_id').val() } } However, this seems to statically set the group_id parameter to whatever the first value in the select is. Meaning, if I change the select, then trigger the remote validation again, the group_id parameter does not change First, how can I make this parameter dynamic, depending on the value of a select in the form? Secondly, how do I manually trigger the remote validation on the email address field? When the group_id select is changed, I want to re-trigger the remote validation on the email address field (without changing the value of the field). I tried using $(selector).validate().element('.email_addr') But this appears to only trigger the standard validation (required, email), and not the remote call.

    Read the article

  • Weird response for controller.request.format.html? in Rails

    - by Tony
    In my main controller, I have this: class MainController < ApplicationController before_filter do |controller| logger.info "controller.request.format.html? = #{controller.request.format.html?}" logger.info "controller.request.format.fbml? = #{controller.request.format.fbml?}" controller.send :login_required if controller.request.format.html? controller.send :facebook_auth_required if controller.request.format.fbml? end As expected, I get "true" for the ...fbml? line if a request comes from Facebook (my facebooker gem automatically sets the format). However, I get "5" for the ...html? line if the request comes from Facebook. Why would a method with a ? ever return a "5"? Isn't that against Rails conventions? Also, I think "5" is considered true so this might mess up my filters. Still looking into that... Any ideas?

    Read the article

  • Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server.

    - by Hiru
    When a form with a run at server is added there will be two forms with runat server and another error occurs. Can some one give me an idea. Thankx in advance. The details of the error are as follows. Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Web.HttpException: Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server. Source Error: An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below. Stack Trace: [HttpException (0x80004005): Control 'ctl00_TextBox1' of type 'TextBox' must be placed inside a form tag with runat=server.] System.Web.UI.Page.VerifyRenderingInServerForm(Control control) +2052287 System.Web.UI.WebControls.TextBox.AddAttributesToRender(HtmlTextWriter writer) +49 System.Web.UI.WebControls.WebControl.RenderBeginTag(HtmlTextWriter writer) +17 System.Web.UI.WebControls.TextBox.Render(HtmlTextWriter writer) +17 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +25 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +121 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +22 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +199 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +20 System.Web.UI.Control.Render(HtmlTextWriter writer) +7 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +25 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +121 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +22 System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +199 System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +20 System.Web.UI.Page.Render(HtmlTextWriter writer) +26 System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +25 System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +121 System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +22 System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) +2558 Version Information: Microsoft .NET Framework Version:2.0.50727.1873; ASP.NET Version:2.0.50727.1433

    Read the article

  • CSS style to create an HTML with an image on left and input text boxes on right that fills all space

    - by dafi
    I need to create an HTML page (a JqueryUI dialog but this isn't the problem) containing an image on left (size is fixed to 75x75) and on right some input text boxes, input boxes must resize to all remaining space. You can see an example at http://img683.imageshack.us/img683/5412/19483174.jpg The problem is that when I resize the dialog controls move under image as shown at http://img510.imageshack.us/img510/4817/44749696.jpg How can I resolve this problem in all browser and if possible using only CSS? Below I show my HTML code and the CSS I'm using HTML code <div id="dialog-form" title="Modify Post"> <form action=""> <fieldset> <img id="dialog-modify-thumb" src="http://dummyimage.com/75x75/000/fff" alt="" width="75" height="75"/> <div id="dialog-modify-controls"> <label for="dialog-modify-caption">Caption</label> <input type="text" name="dialog-modify-caption" id="dialog-modify-caption"/> <br/> <label for="dialog-modify-tags">Tags</label> <input type="text" name="dialog-modify-tags" id="dialog-modify-tags"/> <br/> <label for="dialog-modify-publish-date">Publish Date</label> <input type="text" name="dialog-modify-publish-date" id="dialog-modify-publish-date"/> </div> </fieldset> </form> </div> The CSS #dialog-modify-thumb { margin-right: 3px; border: 1px solid; display: block; float:left; } #dialog-form input[type='text'] { width: 100%; } #dialog-modify-controls { float: right; width:100%; }

    Read the article

  • [C#][XNA 3.1] How can I host two different XNA windows inside one Windows Form?

    - by secutos
    I am making a Map Editor for a 2D tile-based game. I would like to host two XNA controls inside the Windows Form - the first to render the map; the second to render the tileset. I used the code here to make the XNA control host inside the Windows Form. This all works very well - as long as there is only one XNA control inside the Windows Form. But I need two - one for the map; the second for the tileset. How can I run two XNA controls inside the Windows Form? While googling, I came across the terms "swap chain" and "multiple viewports", but I can't understand them and would appreciate support. Just as a side note, I know the XNA control example was designed so that even if you ran 100 XNA controls, they would all share the same GraphicsDevice - essentially, all 100 XNA controls would share the same screen. I tried modifying the code to instantiate a new GraphicsDevice for each XNA control, but the rest of the code doesn't work. The code is a bit long to post, so I won't post it unless someone needs it to be able to help me. Thanks in advance.

    Read the article

  • KeyUp processed for wrong control

    - by Mikael
    I have made a simple test application for the issue, two winforms each containing a button. The button on the first form opens the other form when clicked. It also subscribes to keyup events. The second form has its button set as "AcceptButton" and in the Clicked event we sleep for 1s and then set DialogResult to true (the sleep is to simulate some processing done) When enter is used to close this second form the KeyUp event of the button on the first form is triggered, even though the key was released well before the second had passed so the second form was still shown and focused. If any key other then enter is pressed in the second form the event is not triggered for the button on the first form. First form: public Form1() { InitializeComponent(); buttonForm2.KeyUp += new KeyEventHandler(cntKeyUp); } void cntKeyUp(object sender, KeyEventArgs e) { MessageBox.Show(e.KeyCode.ToString()); } private void buttonForm2_Click(object sender, EventArgs e) { using (Form2 f = new Form2()) { f.ShowDialog(); } } Second form: private void button1_Click(object sender, EventArgs e) { Thread.Sleep(1000); this.DialogResult = DialogResult.OK; } Does anyone know why the event is triggered for the button on the non active form and what can be done to stop this from happening?

    Read the article

  • How do I insert an input's value into a separate form?

    - by ryan
    I'm making a tool for my university that allows students to create a list of classes by doing the following: Searching by course title for their course via an autocomplete input field. Adding that course to a separate form that upon being submitted creates a course list. I am trying to link the autocomplete and the course list form with an 'add to course list' button that inserts a hidden input field into the course list form which can subsequently be submitted by a 'create course list' button. My question is this: How do I take the value of the autocomplete input and insert it into the course list form without using AJAX? So far I have something like the following: <%= text_field_with_auto_complete :course, :title, :size => 40 %> <%= link_to_function "Add to Course List" do |page| page.insert_html :top, :course_list, hidden_field(:courses, :course, {:value => "$('course_title').value"}) %> <% form_for(@course_list) do |f|%> <div id="course_list">Insert selected courses here.</div> <% end %>

    Read the article

  • asp.net mvc: What is the correct way to return html from controller to refresh select list?

    - by Mark Redman
    Hi, I am new to ASP.NET MVC, particularly ajax operations. I have a form with a jquery dialog for adding items to a drop-down list. This posts to the controller action. If nothing (ie void method) is returned from the Controller Action the page returns having updated the database, but obviously there no chnage to the form. What would be the best practice in updating the drop down list with the added id/value and selecting the item. I think my options are: 1) Construct and return the html manually that makes up the new <select> tag [this would be easy enough and work, but seems like I am missing something] 2) Use some kind of "helper" to construct the new html [This seems to make sense] 3) Only return the id/value and add this to the list and select the item [This seems like an overkill considering the item needs to be placed in the correct order etc] 4) Use some kind of Partial View [Does this mean creating additional forms within ascx controls? not sure how this would effect submitting the main form its on? Also unless this is reusable by passing in parameters(not sure how thats done) maybe 2 is the option?] UPDATE: Having looked around a bit, it seems that generating html withing the controller is not a good idea. I have seen other posts that render partialviews to strings which I guess is what I need and separates concerns (since the html bits are in the ascx). Any comments on whether that is good practice.

    Read the article

  • CSS: how to set the width of form control so they all have the same width?

    - by Alessandro Vernet
    Consider the following example: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/> <style type="text/css"> div { width: 15em } input, textarea, select { width: 100%; -moz-box-sizing: border-box; -webkit-box-sizing: border-box; box-sizing: border-box } </style> </head> <body> <form> <div> <input value="Input"> </div> <div> <textarea>Text area</textarea> </div> <div> <select> <option>One</option> <option>Two</option> <option>Three</option> </select> </div> </form> </body> </html> On browser that support the border-box box sizing, this is rendered as I want: On IE 6/7, however, this is rendered as: How can I get the same rendering in IE 6/7 that I get in other browsers, without resorting to setting sizes in pixels?

    Read the article

  • CakePHP 1.26: Bug in 'Security' component?

    - by Steve
    Okay, for those of you who may have read this earlier, I've done a little research and completely revamped my question. I've been having a problem where my form requests get blackholed by the Security component, although everything works fine when the Security component is disabled. I've traced it down to a single line in a form: <?php echo $form->create('Audition');?> <fieldset> <legend><?php __('Edit Audition');?></legend> <?php echo $form->input('ensemble'); echo $form->input('position'); echo $form->input('aud_date'); // The following line works fine... echo $form->input('owner'); // ...but the following line blackholes when Security included // and the form is submitted: // echo $form->input('owner', array('disabled'=>'disabled'); ?> </fieldset> <?php echo $form->end('Submit');?> (I've commented out the offending line for clarity) I think I'm following the rules by using the form helper; as far as I can tell, this is a bug in the Security component, but I'm too much of a CakePHP n00b to know for sure. I'd love to get some feedback, and if it's a real bug, I'll submit it to the CakePHP team. I'd also love to know if I'm just being dumb and missing something obvious here.

    Read the article

  • How to render an HTML attribute from a Razor view.

    - by ProfK
    I would like to use the same partial view for create, edit, and details views, to avoid duplicating the fieldset structure for an entity. Then, depending on which view renders the partial view, I would like to add a class of "read-only" to a div surrounding my fieldset and handle making the actual input fields read-only on the client, using css or jQuery, or whatever. How can I specify from my Razor view that I need this class added to the "item-details" div? <div class="item-details"> <fieldset> <legend>Product Details</legend> @Html.HiddenFor(model => model.DetailItem.ProductId) <div class="editor-label"> @Html.LabelFor(model => model.DetailItem.Name) </div> <div class="editor-field"> @Html.EditorFor(model => model.DetailItem.Name) @Html.ValidationMessageFor(model => model.DetailItem.Name) </div> <p> <input type="submit" value="Save" /> </p> </fieldset> </div>

    Read the article

  • I am confused about how to use @SessionAttributes

    - by yusaku
    I am trying to understand architecture of Spring MVC. However, I am completely confused by behavior of @SessionAttributes. Please look at SampleController below , it is handling post method by SuperForm class. In fact, just field of SuperForm class is only binding as I expected. However, After I put @SessionAttributes in Controller, handling method is binding as SubAForm. Can anybody explain me what happened in this binding. ------------------------------------------------------- @Controller @SessionAttributes("form") @RequestMapping(value = "/sample") public class SampleController { @RequestMapping(method = RequestMethod.GET) public String getCreateForm(Model model) { model.addAttribute("form", new SubAForm()); return "sample/input"; } @RequestMapping(method = RequestMethod.POST) public String register(@ModelAttribute("form") SuperForm form, Model model) { return "sample/input"; } } ------------------------------------------------------- public class SuperForm { private Long superId; public Long getSuperId() { return superId; } public void setSuperId(Long superId) { this.superId = superId; } } ------------------------------------------------------- public class SubAForm extends SuperForm { private Long subAId; public Long getSubAId() { return subAId; } public void setSubAId(Long subAId) { this.subAId = subAId; } } ------------------------------------------------------- <form:form modelAttribute="form" method="post"> <fieldset> <legend>SUPER FIELD</legend> <p> SUPER ID:<form:input path="superId" /> </p> </fieldset> <fieldset> <legend>SUB A FIELD</legend> <p> SUB A ID:<form:input path="subAId" /> </p> </fieldset> <p> <input type="submit" value="register" /> </p> </form:form>

    Read the article

  • I expect to see in the browswer "http://path/some_page.html" but instead it identifies with "http:/

    - by indiehacker
    I am developing with app engine SDK. I have a feeling this is much too basic a question so apologies ahead of time... A simple submit button doesnt work instead of just showing an alert box as expected it continues on afterwards and redirects me to the latest http-request, and I think this is because I dont understand how to tell the browser to recognize the proper URLs. Why does my browser say I am at the most recent http-request http://localhost:8080/putProjectInDB rather than the somepage.html that was actually served to the browser that I am currently looking at? How can I get the browser to recognize and show in its url spot the normal expected http://somepage.html ? Just in case, here are details of the specific problem which you might be able to ignore for answering the question: This hasnt been mattered for me until I just wanted to put into my .html a simple button that changes some stuff of the page without needing the server. The below code after displaying the alert box redirects me to the last server request http://localhost:8080/putProjectInDB instead of just staying in the same html page. in header: function MyFormCommands() { alert('Some Text'); } in body: <form onSubmit="MyFormCommands()" ><input type=submit ></form >

    Read the article

  • How to use javascript to get information from the content of another page (same domain)?

    - by hlovdal
    Let's say I have a web page (/index.html) that contains the following <li> <div>item1</div> <a href="/details/item1.html">details</a> </li> and I would like to have some javascript on /index.html to load that /details/item1.html page and extract some information from that page. The page /details/item1.html might contain things like <div id="some_id"> <a href="/images/item1_picture.png">picture</a> <a href="/images/item1_map.png">map</a> </div> My task is to write a greasemonkey script, so changing anything serverside is not an option. To summarize, javascript is running on /index.html and I would like to have the javascript code to add some information on /index.html extracted from both /index.html and /details/item1.html. My question is how to fetch information from /details/item1.html. I currently have written code to extract the link (e.g. /details/item1.html) and pass this on to a method that should extract the wanted information (at first just .innerHTML from the some_id div is ok, I can process futher later). The following is my current attempt, but it does not work. Any suggestions? function get_information(link) { var obj = document.createElement('object'); obj.data = link; document.getElementsByTagName('body')[0].appendChild(obj) var some_id = document.getElementById('some_id'); if (! some_id) { alert("some_id == NULL"); return ""; } return some_id.innerHTML; }

    Read the article

  • WindowsFormsApplicationBase SplashScreen makes login form ignore keypresses until I click on it - how to debug?

    - by Tom Bushell
    My WinForms app has a simple modal login form, invoked at startup via ShowDialog(). When I run from inside Visual Studio, everything works fine. I can just type in my User ID, hit the Enter key, and get logged in. But when I run a release build directly, everything looks normal (the login form is active, there's a blinking cursor in the User ID MaskedEditBox), but all keypresses are ignored until I click somewhere on the login form. Very annoying if you are used to doing everything from the keyboard. I've tried to trace through the event handlers, and to set the focus directly with code, to no avail. Any suggestions how to debug this (outside of Visual Studio), or failing that - a possible workaround? Edit Here's the calling code, in my Main Form: private void OfeMainForm_Shown(object sender, EventArgs e) { OperatorLogon(); } private void OperatorLogon() { // Modal dialogs should be in a "using" block for proper disposal using (var logonForm = new C21CfrLogOnForm()) { var dr = logonForm.ShowDialog(this); if (dr == DialogResult.OK) SaveOperatorId(logonForm.OperatorId); else Application.Exit(); } } Edit 2 Didn't think this was relevant, but I'm using Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase for it's splash screen and SingleInstanceController support. I just commented out the splash screen code, and the problem has disappeared. So that's opened up a whole new line of inquiry... Edit 3 Changed title to reflect better understanding of the problem

    Read the article

< Previous Page | 489 490 491 492 493 494 495 496 497 498 499 500  | Next Page >