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• Update is not updating the whole string

  - by Malik

  Following is my SQL fiddle: http://sqlfiddle.com/#!2/f9bae/1 In which i am trying to check if the whole name is being verified by lookup table or not and if there is any error then it should get replaced by the correct value but the problem i am facing is that if any name contains more than one wrong values then query only update one part of that name and leave the rest unchanged , kindly let me know how can i modify my query for update so it'll update the whole name as per lookup table correct values. Thanks,

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• How to verify if two tables have exactly the same data?

  - by SiLent SoNG

  Basically we have one table (original table) and it is backed up into another table (backup table); thus the two tables have exactly the same schema. At the beginning both tables (original table and backup table) contains exactly the same set of data. After sometime for some reason I need to verify whether dataset in the original table has changed or not. In order to do this I have to compare the dataset in the original table against the backup table. Let's say the original table has the following schema: `create table LemmasMapping ( lemma1 int, lemma2 int, index ix_lemma1 using btree (lemma1), index ix_lemma2 using btree (lemma2) )` How could I achieve the dataset comparision? Update: the table does not have a primary key. It simply stores mappings between two ids.

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• Difficults on sql query

  - by João Madureira Pires

  I have the following tables: TableA (id, tableB_id, tableC_id) TableB (id, expirationDate) TableC (id, expirationDate) I want to retrieve all the results from TableA ordered by tableB.expirationDate and tableC.expirationDate. thanks

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• (database design):Which tables should be created for all kindes files (images, attached email files,

  - by meyosef

  Hi, I new in database design: I have question with my own few solution,what do you thinks?: Which tables should be created for all kinds files (images, attached email files,text files for store email body, etc..) that stored in my online store? *option 1:use seperate table for files types * files{ id files_types_id FK file_path file_extension } files_types{ id type_name (unique) } *option 2: use bool field for each file type * files{ id file_path file_extension is_image_main is_image_icon is_image_logo is_pdf_file is_text_file } **option 3: use 1 enum field 'file_type' for each file type ** files{ id file_path file_extension file_type (image_main,image_icon,image_logo,image_main,pdf,text) **enum** } Thanks you, Yosef

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• Create new table with Wordpress API

  - by Fire G

  I'm trying to create a new plugin to track popular posts based on views and I have everything done and ready to go, but I can't seem to create a new table using the Wordpress API (I can do it with standard PHP or with phpMyAdmin, but I want this plugin to be self-sufficient). I've tried several ways ($wpdb-query, $wpdb-get_results, dbDelta) but none of them will create the new table. function create_table(){ global $wpdb; $tablename = $wpdb->prefix.'popular_by_views'; $ppbv_table = $wpdb->get_results("SHOW TABLES LIKE '".$tablename."'" , ARRAY_N); if(is_null($ppbv_table)){ $create_table_sql = "CREATE TABLE '".$tablename."' ( 'id' BIGINT(50) NOT NULL AUTO_INCREMENT, 'url' VARCHAR(255) NOT NULL, 'views' BIGINT(50) NOT NULL, PRIMARY KEY ('id'), UNIQUE ('id') );"; $wpdb->show_errors(); $wpdb->flush(); if(is_null($wpdb->get_results("SHOW TABLES LIKE '".$tablename."'" , ARRAY_N))) echo 'crap, the SQL failed.'; } else echo 'table already exists, nothing left to do.';}

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• Prevent Users from Performing an Action Twice

  - by TheOnly92

  We have some problems with users performing a specific action twice, we have a mechanism to ensure that users can't do it but somehow it still happens. Here is how our current mechanism works: Client side: The button will be disabled after 1 click. Server side: We have a key hash in the URL which will be checked against the key stored in SESSIONS, once it matches, the key is deleted. Database side: Once the action is performed, there is a field to be flagged indicating the user has completed the action. However, with all these measures, still there are users able to perform the action twice, are there any more safer methods?

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• INSERT..ON DUPLICATE KEY UPDATE - but NOT using the duplicate key to compare.

  - by calumbrodie

  I am trying to solve a problem I have inherited with poor treatment of different data sources. I have a user table that contains BOTH good and evil users. create table `users`( `user_id` int(13) NOT NULL AUTO_INCREMENT , `email` varchar(255) , `name` varchar(255) , PRIMARY KEY (`user_id`) ); In this table the primary key is currently set to be user_id. I have another table ('users_evil') which contains ONLY the evil users (all the users from this table are included in the first table) - the user_id's on this table do NOT correspond to those in the first table. I want to have all my users in one table, and simply flag which are good and which are evil. What I want to do is alter the user table and add a column ('evil') which defaults to 0. I then want to dump the data from my 'users_evil') table and then run an INSERT..ON DUPLICATE KEY UPDATE with this data into the first table (setting 'evil'=1 where the emails match) The problem is that the 'PK' is set to the user_id and not the 'email'. Any suggestions, or even another strategy to successfully achive this. Can I run this statement but treat another column as PK only for the duration of the statement.

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• Selecting first records of a type in a given period

  - by Emanuil Rusev

  I have a database table that stores user comments: comments(id, user_id, created_at) I want to get from it the number of users that have commented for the first time in the past week. Here's what I have so far: SELECT COUNT(DISTINCT `user_id`) FROM `comments` WHERE `created_at` BETWEEN DATE_SUB(NOW(), INTERVAL 7 DAY) AND NOW() This would give the number of users that have commented, but it would not take into consideration whether these comments are first for these users.

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• Get category count for a category where only the child categories have products

  - by Matthew

  I'm having problems getting a count for a category collection that will include products in any of that categories children. However I don't want just a full count I want to filter that count by a product collection (so only include products in the count that appear in the product collection)... Any suggestions? Code to get a filtered product collection (filtered by a multiselect attribute) /** @var $attribute Mage_Eav_Model_Entity_Attribute */ $valuesCollection = Mage::getResourceModel('eav/entity_attribute_option_collection') ->setAttributeFilter($attribute->getId()) ->addFieldToFilter('value', array ('like' => $make)) ->addFieldToSelect('option_id') ->setStoreFilter(0, false); $set = array(); foreach($valuesCollection as $option){ $set[] = $option->getData('option_id'); } $_productCollection = Mage::getResourceModel('catalog/product_collection') ->addAttributeToFilter('sparex_makemodel', array('in' => $set ) ) ->addAttributeToSelect('*'); I'm getting the child categories for a given category like thus.. $childCats = Mage::getModel('catalog/category')->load(2)->getChildrenCategories(); Now none of these categories have products assigned to them, however their children (or children of children) do. I want to produce a count for these categories that includes the child categories but only where the products are in my filtered collection.

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• Get a unique data in a SQL query

  - by Jensen

  Hi, I've a database who contain some datas in that form: icon(name, size, tag) (myicon.png, 16, 'twitter') (myicon.png, 32, 'twitter') (myicon.png, 128, 'twitter') (myicon.png, 256, 'twitter') (anothericon.png, 32, 'facebook') (anothericon.png, 128, 'facebook') (anothericon.png, 256, 'facebook') So as you see it, the name field is not uniq I can have multiple icons with the same name and they are separated with the size field. Now in PHP I have a query that get ONE icon set, for example : $dbQueryIcons = mysql_query("SELECT * FROM pl_icon WHERE tag LIKE '%".$SEARCH_QUERY."%' GROUP BY name ORDER BY id DESC LIMIT ".$firstEntry.", ".$CONFIG['icon_per_page']."") or die(mysql_error()); With this example if $tag contain 'twitter' it will show ONLY the first SQL data entry with the tag 'twitter', so it will be : (myicon.png, 16, 'twitter') This is what I want, but I would prefer the '128' size by default. Is this possible to tell SQL to send me only the 128 size when existing and if not another size ? In an another question someone give me a solution with the GROUP BY but in this case that don't run because we have a GROUP BY name. And if I delete the GROUP BY, it show me all size of the same icons. Thanks !

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• Referral System PHP

  - by Liam

  I have a membership based website and im planning on implementing a referral system. My website is credit based, the idea is that if User X refers User Y, then User X gets 100 bonus credits. Has anybody built a referral system before and if so what obstacles should I bear in mind? I've had a snoop round SO tonight but couldn't find any suitable answers. My theory is to give each user a random string which is generated and stored in the DB when they sign up, The user will then be presented with a URL incl. that string which when they pass to somebody (User Z), User Z is then sent to a page, the page then uses the GET method to gather the Random string and update the DB Row they currently occupy, does this sound feasible or could it easily be breached? Thanks

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• Find the closest locations to a given address

  - by xtine

  I have built an application in CakePHP that lists businesses. There are about 2000 entries, and the latitude and longitude coordinates for each business is in the DB. I now am trying to tackle the search function. There will be an input box where the user can put a street address, city, or zipcode, and then I would like it to return the 11 closest businesses as found from the database. How would I go about doing this?

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• SQL query, select from 2 tables random

  - by klaus

  Hello all i have a problem that i just CANT get to work like i what it.. i want to show news and reviews (2 tables) and i want to have random output and not the same output here is my query i really hope some one can explain me what i do wrong SELECT anmeldelser.billed_sti , anmeldelser.overskrift , anmeldelser.indhold , anmeldelser.id , anmeldelser.godkendt FROM anmeldelser LIMIT 0,6 UNION ALL SELECT nyheder.id , nyheder.billed_sti , nyheder.overskrift , nyheder.indhold , nyheder.godkendt FROM nyheder ORDER BY rand() LIMIT 0,6

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• Is a clear and replace more efficient than a loop checking all records?

  - by Matt

  I have a C# List, that is filled from a database.. So far its only 1400 records, but I expect it to grow a LOT.. Routinely I do a check for new data on the entire list.. What I'm trying to figure out is this, is it faster to simply clear the List and reload all the data from the table, or would checking each record be faster.. Intuition tells me that the dump and load method would be faster, but I thought I should check first...

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• How to exclude result from 2 different table and show the result?

  - by Lucy Amalia Lusiana

  I have 2 tables: T1 (Total User) T2 (User_id_that_have_done_something_for_today) the mysql_query result from T1 are (Total User) ----- ID ----- | 1 | | 2 | | 3 | | 4 | | 5 | | 6 | | 7 | | 8 | the mysql_query from T2 are (logged) ----- user_id_log ----- | 1 | | 3 | | 4 | | 7 | How to compare T1 and T2 And only show the user that not approved? The end result that i wanted is (result) ----- ID ----- | 2 | | 5 | | 6 | | 8 | I spent 2 days to make this work but i cannot do it I have try LEFT JOIN and NOT IT but the result is not what i wanted Please help me, thank you

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• Store LAST_INSERT_ID() in a transaction

  - by Oden

  Hi, I use codeigniter's database abstarction, and im doing a transaction with it. My problem is, that i have several inserts into several tables, but i need the insert id from the first insert query. Is there any way to store the last insert id for more than one following insert?

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• Insert names into table if not already existing

  - by John

  I am trying to build an application that allows users to submit names to be added to a db table (runningList). Before the name is added tho, I would like to check firstname and lastname against another table (controlList). It must exist in (controlList) or reply name not valid. If the name is valid I would like to then check firstname and lastname against (runningList) it make sure it isnt already there. If it isnt there, then insert firstname & lastname. If it is there, reply name already used. Below is code that worked before I tried to add the test against the controlList, I somehow broke it altogether while trying to add the extra step. if (mysql_num_rows(mysql_query('SELECT * FROM runninglist WHERE firstname=\'' .$firstname . '\' AND lastname=\'' . $lastname . '\' LIMIT 1')) == 0) { $sql="INSERT INTO runninglist (firstname, lastname) VALUES ('$_POST[firstname]','$_POST[lastname]')"; } else { echo "This name has been used."; } Any direction would be appreciated. Thanx John

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• Does the MySQLdb module support prepared statements ?

  - by planetp

  Does MySQLdb support server-side prepared statements? I can't figure this out from its manual.

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• How do I make all the finders on the model ignorecase?

  - by Glex

  I have a model with several attributes, among them title and artist. The case of title and artist should be ignored in all the Active Record finders. Basically, if title or artist are present in the :conditions (or dynamically i.e. find_all_by_artist), then the WHERE artist = :artist should become WHERE UPPER(artist) = UPPER(:artist) or something along these lines. Is there a way of doing it with Rails?

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• C# Application process hangs after some time

  - by Chris

  Hi, I implemented a simple C# application which inserts about 350000 records into the database. This used to work well and the process took approximately 20 minutes. I created a progress bar which lets you know approximately the progress of the records insertion. When the progress bar reaches about 75% it stops progressing. I have to manually terminate the program as the process doesn't seem to complete. If I use less data (like 10000), the progress bar finishes and the process is completed. However when I try to insert all the records, this won't happen any more. Note that if I wait longer to terminate the program manually, more records would have been inserted. For example, if I terminate the program after 15 minutes, 200000 records are inserted, whereas if I terminate the program after 20 minutes, 250000 records are inserted. This program is using a single thread. In face I can't do anything else until the process is complete. Does this have anything to do with threading or processes? Any feedback will be greatly appreciated. Thanks.

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• How do I set ORDER BY params using prepared PDO statement?

  - by Marlorn

  I'm having problems using params in the ORDER BY section of my SQL. It doesn't issue any warnings, but prints out nothing. $order = 'columnName'; $direction = 'ASC'; $stmt = $db->prepare("SELECT field from table WHERE column = :my_param ORDER BY :order :direction"); $stmt->bindParam(':my_param', $is_live, PDO::PARAM_STR); $stmt->bindParam(':order', $order, PDO::PARAM_STR); $stmt->bindParam(':direction', $direction, PDO::PARAM_STR); $stmt->execute(); The :my_param works, but not :order or :direction. Is it not being internally escaped correctly? Am I stuck inserting it directly in the SQL? Like so: $order = 'columnName'; $direction = 'ASC'; $stmt = $db->prepare("SELECT * from table WHERE is_live = :is_live ORDER BY $order $direction"); Is there a PDO::PARAM_COLUMN_NAME constant or some equivalent? Thanks!

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• Hibernate/Spring: getHibernateTemplate().save(...) Freezes/Hangs

  - by ashes999

  I'm using Hibernate and Spring with the DAO pattern (all Hibernate dependencies in a *DAO.java class). I have nine unit tests (JUnit) which create some business objects, save them, and perform operations on them; the objects are in a hash (so I'm reusing the same objects all the time). My JUnit setup method calls my DAO.deleteAllObjects() method which calls getSession().createSQLQuery("DELETE FROM <tablename>").executeUpdate() for my business object table (just one). One of my unit tests (#8/9) freezes. I presumed it was a database deadlock, because the Hibernate log file shows my delete statement last. However, debugging showed that it's simply HibernateTemplate.save(someObject) that's freezing. (Eclipse shows that it's freezing on HibernateTemplate.save(Object), line 694.) Also interesting to note is that running this test by itself (not in the suite of 9 tests) doesn't cause any problems. How on earth do I troubleshoot and fix this? Also, I'm using @Entity annotations, if that matters. Edit: I removed reuse of my business objects (use unique objects in every method) -- didn't make a difference (still freezes). Edit: This started trickling into other tests, too (can't run more than one test class without getting something freezing) Transaction configuration: <bean id="txManager" class="org.springframework.jdbc.datasource.DataSourceTransactionManager"> <property name="dataSource" ref="dataSource" /> </bean> <tx:advice id="txAdvice" transaction-manager="txManager"> <!-- the transactional semantics... --> <tx:attributes> <!-- all methods starting with 'get' are read-only --> <tx:method name="get*" read-only="true" /> <tx:method name="find*" read-only="true" /> <!-- other methods use the default transaction settings (see below) --> <tx:method name="*" /> </tx:attributes> </tx:advice> <!-- my bean which is exhibiting the hanging behavior --> <aop:config> <aop:pointcut id="beanNameHere" expression="execution(* com.blah.blah.IMyDAO.*(..))" /> <aop:advisor advice-ref="txAdvice" pointcut-ref="beanNameHere" /> </aop:config>

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• Select one column from a row in hibernate

  - by ComfortablyNumb

  I am trying to do a simple query to get a unique result back in hibernate here is my code. public String getName(Integer id) { Session session = getSessionFactory().openSession(); String name = (String)session.createSQLQuery("SELECT name FROM users WHERE user_id = :userId").setParameter("userId", id).uniqueResult(); return name; } The name that is being returned is stored as HTML text that includes html syntacx language. I think this is what is causing the problem but it doesnt make sense I just want to return it as a string. It is only happening on this one field name, I can get every other field in the row but this one it gives me the error. I am getting an exception. The exception I am getting is No Dialect mapping for JDBC type: -1; nested exception is org.hibernate.HibernateException How do you query for a specific column on a row in hibernate?

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• sql query without subquery

  - by user1285737

  I need to rewrite this query and I'm not allowed to use a subquery. I need to select the name and color of the parts that are heavier than the wheel. SELECT name, color FROM parts WHERE weight > (SELECT weight FROM parts WHERE name="wheel"); This is the table: PARTS ID NAME COLOR WEIGHT 1 wheel black 100 2 tire black 50 3 gear red 20 Thanks in advance

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• php search database for row

  - by Brenden Morley

  Okay I got code the code to pull data based on a users account number well here is what im using (And yes I know it isnt safe now that is the reason for my post) <?php include('config.php'); $user_info = fetch_user_info($_GET['AccountNumber']); ?> <html> <body> <div> <?php if ($user_info === false){ $Output = 'http://www.MyDomain.Com/'; echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL='.$Output.'">'; }else{ ?> <center> <title><?php echo $user_info['FirstName'], ' ', $user_info['LastName'], ' - ', $user_info['City'], ', ', $user_info['State']; ?> - Name of site</title> So basically what this code is allowing me to do is have a file called Profile.php And when a user visits this this page it will return the data Like this http://MyDomain.com/Profile.php?AccountNumber=50b9c965b7c3b How can I do this securely cause right now its using a get method really unsafe to retive the account number from the url bar.

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