Search Results

Search found 5323 results on 213 pages for 'associated sorting'.

Page 5/213 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Knockout.js - Filtering, Sorting, and Paging

    - by jtimperley
    Originally posted on: http://geekswithblogs.net/jtimperley/archive/2013/07/28/knockout.js---filtering-sorting-and-paging.aspxKnockout.js is fantastic! Maybe I missed it but it appears to be missing flexible filtering, sorting, and pagination of its grids. This is a summary of my attempt at creating this functionality which has been working out amazingly well for my purposes. Before you continue, this post is not intended to teach you the basics of Knockout. They have already created a fantastic tutorial for this purpose. You'd be wise to review this before you continue. http://learn.knockoutjs.com/ Please view the full source code and functional example on jsFiddle. Below you will find a brief explanation of some of the components. http://jsfiddle.net/JTimperley/pyCTN/13/ First we need to create a model to represent our records. This model is a simple container with defined and guaranteed members. function CustomerModel(data) { if (!data) { data = {}; } var self = this; self.id = data.id; self.name = data.name; self.status = data.status; } Next we need a model to represent the page as a whole with an array of the previously defined records. I have intentionally overlooked the filtering and sorting options for now. Note how the filtering, sorting, and pagination are chained together to accomplish all three goals. This strategy allows each of these pieces to be used selectively based on the page's needs. If you only need sorting, just sort, etc. function CustomerPageModel(data) { if (!data) { data = {}; } var self = this; self.customers = ExtractModels(self, data.customers, CustomerModel); var filters = […]; var sortOptions = […]; self.filter = new FilterModel(filters, self.customers); self.sorter = new SorterModel(sortOptions, self.filter.filteredRecords); self.pager = new PagerModel(self.sorter.orderedRecords); } The code currently supports text box and drop down filters. Text box filters require defining the current 'Value' and the 'RecordValue' function to retrieve the filterable value from the provided record. Drop downs allow defining all possible values, the current option, and the 'RecordValue' as before. Once defining these filters, they are automatically added to the screen and any changes to their values will automatically update the results, causing their sort and pagination to be re-evaluated. var filters = [ { Type: "text", Name: "Name", Value: ko.observable(""), RecordValue: function(record) { return record.name; } }, { Type: "select", Name: "Status", Options: [ GetOption("All", "All", null), GetOption("New", "New", true), GetOption("Recently Modified", "Recently Modified", false) ], CurrentOption: ko.observable(), RecordValue: function(record) { return record.status; } } ]; Sort options are more simplistic and are also automatically added to the screen. Simply provide each option's name and value for the sort drop down as well as function to allow defining how the records are compared. This mechanism can easily be adapted for using table headers as the sort triggers. That strategy hasn't crossed my functionality needs at this point. var sortOptions = [ { Name: "Name", Value: "Name", Sort: function(left, right) { return CompareCaseInsensitive(left.name, right.name); } } ]; Paging options are completely contained by the pager model. Because we will be chaining arrays between our filtering, sorting, and pagination models, the following utility method is used to prevent errors when handing an observable array to another observable array. function GetObservableArray(array) { if (typeof(array) == 'function') { return array; }   return ko.observableArray(array); }

    Read the article

  • Sorting a multidimensional array in objective-c

    - by Zen_silence
    Hello, I'm trying to sort a multidimensional array in objective-c i know that i can sort a single dimensional array using the line of code below: NSArray *sortedArray = [someArray sortedArrayUsingSelector:@selector(caseInsensitiveCompare:)]; I can't seem to figure out how to sort a 2D array like the one below: ( ("SOME_URL", "SOME_STORY_TITLE", "SOME_CATEGORY"), ("SOME_URL", "SOME_STORY_TITLE", "SOME_CATEGORY"), ("SOME_URL", "SOME_STORY_TITLE", "SOME_CATEGORY") ); If someone could provide me code that would sort the array by SOME_CATEGORY it would be of great help to me. Thanks, Zen_Silence

    Read the article

  • Getting Serial Port Information and Sorting the Results in C#

    - by Jim Fell
    I have some code that loads the serial ports into a combo-box: comboBoxComPort.Items.Add("Select COM port..."); foreach (string s in SerialPort.GetPortNames()) { comboBoxComPort.Items.Add(s); } comboBoxComPort.SelectedIndex = 0; Ideally, I would like to add the port descriptions to the list and sort the items in the list that are after index 0. Does anyone have any suggestions for doing this? Any thoughts you may have would be appreciated. Thanks.

    Read the article

  • ASP.Net GridView Sorting

    - by Ali Shafai
    I have a grid view with AllowSorting set to true. I get an event onsorting when a sortable header is clicked on. the handler has a parameter "GridViewSortEventArgs e" which has a SortDirection property on it. regardless of how many times you click on the same heading, the SortDirection is always Ascending. I think I'm missing something, like a way to tell the grid "now you are sorted based on column one and in ascending order", so that next time the grid sees a click on the "column one" heading, it decides to go descending. any help appreciated. Cheers, Ali

    Read the article

  • sorting and paging with gridview asp.net

    - by dangerisgo
    I'm trying to get a gridview to sort and page manually with no success. The problem is that when a user clicks the column they want to sort, it sorts that page, but doesn't sort the datasource (dataview) behind the gridview. So when they progress to a different page, their sort is lost. Pretty much I'm looking for a sort that will actually sort the datasource behind the gridview. Here is what I have so far: protected void GridView_OnSort(object sender, GridViewSortEventArgs e) { String sortExpression = e.SortExpression; if (GridViewSortDirection == SortDirection.Ascending) { DataView myDataView = new DataView(mybll.GetItemsOrdered()); myDataView.Sort = sortExpression + " DESC"; GridView.DataSource = myDataView; GridView.DataBind(); } else { DataView myDataView = new DataView(mybll.GetItemsOrdered()); myDataView.Sort = sortExpression + " ASC"; GridView.DataSource = myDataView; GridView.DataBind(); } } Any help would be appreciated. Thanks.

    Read the article

  • Ignoring 'A' and 'The' when sorting with XSLT

    - by ChrisV
    I would like to have a list sorted ignoring any initial definite/indefinite articles 'the' and 'a'. For instance: The Comedy of Errors Hamlet A Midsummer Night's Dream Twelfth Night The Winter's Tale I think perhaps in XSLT 2.0 this could be achieved along the lines of: <xsl:template match="/"> <xsl:for-each select="play"/> <xsl:sort select="if (starts-with(title, 'A ')) then substring(title, 2) else if (starts-with(title, 'The ')) then substring(title, 4) else title"/> <p><xsl:value-of select="title"/></p> </xsl:for-each> </xsl:template> However, I want to use in-browser processing, so have to use XSLT 1.0. Is there any way to achieve this in XLST 1.0?

    Read the article

  • What Sorting Algorithm Is Used By LINQ "OrderBy"?

    - by Mystagogue
    Evidently LINQ's "OrderBy" had originally been specified as unstable, but by the time of Orca it was specified as stable. Not all documentation has been updated accordingly - consider these links: Jon Skeet on OrderBy stability Troy Magennis on OrderBy stability But if LINQ's OrderBy is now "stable," then it means it is not using a quicksort (which is inherently unstable) even though some documentation (e.g. Troy's book) says it is. So my question is: if not quicksort, then what is the actual algorithm LINQ's orderBy is using?

    Read the article

  • Drupal: Sorting a view programmatically

    - by Ace
    Hey there. I'm trying to take the results of a view - using the function views_get_view_result() - and sort the array in a way I couldn't do from within the Views interface. So far so good. I've got a $rows variable with all of the stuff I need. Now... How do I put it back? :) Before I needed this sort, I used views_embed_view(), but I can't do that anymore. Grateful for any help on this, feels like I'm so close to cracking it!

    Read the article

  • Sorting HTML table (with anchor tags and data in cells) in Python

    - by AJ
    I have a necessity to sort a given HTML table of the following structure, in Python. <table> <tr> <td><a href="#">ABCD</a></td> <td>A23BND</td> <td><a title="ABCD">345345</td> </tr> <tr> <td><a href="#">EFG</a></td> <td>Add4D</td> <td><a title="EFG">3432</td> </tr> <tr> <td><a href="#">HG</a></td> <td>GJJ778</td> <td><a title="HG">2341333</td> </tr> </table> I am doing something like this: container = tree.findall("tr") strOut = "" data = [] for elem in container: key = elem.findtext(colName) data.append((key, elem)) data.sort() The problem is that it sorts by the text inside the . I want to be able to sort by the anchor value and not href. What can I do to achieve that? Thanks a lot.

    Read the article

  • question about sorting

    - by skydoor
    Bubble sort is O(n) at best, O(n^2) at worst, and its memory usage is O(1) . Merge sort is always O(n log n), but its memory usage is O(n). Which algorithm we would use to implement a function that takes an array of integers and returns the max integer in the collection, assuming that the length of the array is less than 1000. What if the array length is greater than 1000?

    Read the article

  • Sorting NSSets of a core data entity - Objective-c

    - by ncohen
    Hi everyone, I would like to sort the data of a core data NSSet (I know we can do it only with arrays but let me explain...). I have an entity user who has a relationship to-many with the entity recipe. A recipe has the attributes name and id. I would like to get the data such that: Code: NSArray *id = [[user.recipes valueForKey:@"identity"] allObjects]; NSArray *name = [[user.recipes valueForKey:@"name"] allObjects]; if I take the object at index 1 in both arrays, they correspond to the same recipe... Thanks

    Read the article

  • WPF 4, ListView and ListCollectionView custom sorting

    - by JustABill
    I'm trying to use a custom sort with a ListView, as described in this blog entry. I'm doing ListCollectionView view = (ListCollectionView)CollectionViewSource.GetDefaultView(TheList.ItemsSource); as recommended there and in several other places, but for some reason I'm getting "Unable to cast object of type 'MS.Internal.Data.EnumerableCollectionView' to type 'System.Windows.Data.ListCollectionView'." (TheList is of type ListView). What could be causing this?

    Read the article

  • Sorting ArrayList - IndexOutOfBoundsException -Java

    - by FILIaS
    I'm trying to sort an ArrayList with strings(PlayersNames) and imageIcons(PlayersIcons) based on the values i store in an other arrayList with integers(results). As you can see i get an indexOutOfBoundsException but i cant understand why. Maybe the earling of the morning makes me not to see plain things. ArrayList<String> PlayersNames=new ArrayList<String>; ArrayList<ImageIcon> PlayersIcons=new ArrayList<ImageIcons>; public void sortPlayers(ArrayList<Integer> results){ String tmp; ImageIcon tmp2; for (int i=0; i<PlayersNames.size(); i++) { for (int j=PlayersNames.size(); j>i; j--) { if (results.get(i) < results.get(i+1) ) { //IndexOutOfBoundsException! tmp=PlayersNames.get(i+1); PlayersNames.set(i+1,PlayersNames.get(i)); PlayersNames.set(i,tmp); tmp2=PlayersIcons.get(i+1); PlayersIcons.set(i+1,PlayersIcons.get(i)); PlayersIcons.set(i,tmp2); } } } }

    Read the article

  • Sorting an array of Doubles with NaN in it

    - by Agent Worm
    This is more of a 'Can you explain this' type of question than it is anything else. I came across a problem at work where we were using NaN values in a table, but when the table was sorted, it came out in a very strange, strange manner. I figured NaN was mucking up something so I wrote up a test application to see if this is true. This is what I did. static void Main(string[] args) { double[] someArray = { 4.0, 2.0, double.NaN, 1.0, 5.0, 3.0, double.NaN, 10.0, 9.0, 8.0 }; foreach (double db in someArray) { Console.WriteLine(db); } Array.Sort(someArray); Console.WriteLine("\n\n"); foreach (double db in someArray) { Console.WriteLine(db); } Console.ReadLine(); } Which gave the result: Before: 4,2,NaN,1,5,3,NaN,10,9,8 After: 1,4,NaN,2,3,5,8,9,10,NaN So yes, the NaN some how made the sorted array to be sorted in a strange way. To quote Fry; "Why is those things?"

    Read the article

  • C# Sorting Question

    - by betamoo
    I wonder what is the best C# data structure I should use to sort efficiently? Is it List or Array or what? And why the standard array [] does not implement sort method in it? Thanks

    Read the article

  • Specific complex array sorting

    - by TheDeadMedic
    Okay, a before; Array ( 'home' => array('order' => 1), 'about' => array(), 'folio' => array('order' => 2), 'folio/web' => array('order' => 2), 'folio/print' => array('order' => 1) 'contact' => array('order' => 2) ) And a desired after; Array ( 'home' => array('order' => 1), 'contact' => array('order' => 2), 'folio' => array('order' => 2), 'folio/print' => array('order' => 1), 'folio/web' => array('order' => 2), 'about' => array() ) I know, horrific (don't ask!) See how the slash in the key indicates children, and how the order is nested accordingly? And items without orders are simply shifted to the bottom. But also how multiple 'same level' items with the same order are merely sorted by key?

    Read the article

  • Sorting objects in Python

    - by Curious2learn
    I want to sort objects using by one of their attributes. As of now, I am doing it in the following way USpeople.sort(key=lambda person: person.utility[chosenCar],reverse=True) This works fine, but I have read that using operator.attrgetter() might be a faster way to achieve this sort. First, is this correct? Assuming that it is correct, how do I use operator.attrgetter() to achieve this sort? I tried, keyFunc=operator.attrgetter('utility[chosenCar]') USpeople.sort(key=keyFunc,reverse=True) However, I get an error saying that there is no attribute 'utility[chosenCar]'. The problem is that the attribute by which I want to sort is in a dictionary. For example, the utility attribute is in the following form: utility={chosenCar:25000,anotherCar:24000,yetAnotherCar:24500} I want to sort by the utility of the chosenCar using operator.attrgetter(). How could I do this? Thanks in advance.

    Read the article

  • sorting hashes inside an array on values

    - by srk
    @aoh =( { 3 => 15, 4 => 8, 5 => 9, }, { 3 => 11, 4 => 25, 5 => 6, }, { 3 => 5, 4 => 18, 5 => 5, }, { 0 => 16, 1 => 11, 2 => 7, }, { 0 => 21, 1 => 13, 2 => 31, }, { 0 => 11, 1 => 14, 2 => 31, }, ); I want the hashes in each array index sorted in reverse order based on values.. @sorted = sort { ........... please fill this..........} @aoh; expected output @aoh =( { 4 => 8, 5 => 9, 3 => 15, }, { 5 => 6, 3 => 11, 4 => 25, }, { 5 => 5, 3 => 5, 4 => 18, }, { 2 => 7, 1 => 11, 0 => 16, }, { 1 => 13, 0 => 21, 2 => 31, }, { 0 => 11, 1 => 14, 2 => 31, }, ); Please help.. Thanks in advance.. Stating my request again: I only want the hashes in each array index to be sorted by values.. i dont want the array to be sorted..

    Read the article

  • Sorting nested hash in ruby

    - by Rabbott
    Provided the following ruby hash: { cat: { 1: 2, 2: 10, 3: 11, 4: 1 }, wings: { 1: 3, 2: 5, 3: 7, 4: 7 }, grimace: { 1: 4, 2: 5, 3: 5, 4: 1 }, stubborn: { 1: 5, 2: 3, 3: 7, 4: 5 } } How can I sort the hash by the sum of 'leaf' excluding "4", for instance the value to compare for "cat" would be (2 + 10 + 11) = 23, the value for "wings" would be (3 + 5 + 7) = 15 so if I was comparing just those two they would be in the correct order, highest sum on top. It is safe to assume that it will ALWAYS be {1: value, 2: value, 3: value, 4: value} as those are keys for constants I have defined. It is also safe to assume that I will only ever want to exclude the key "4", and always use the keys "1", "2", and "3"

    Read the article

  • perl array of hashes sorting

    - by srk
    use strict; my @arr; $arr[0][0]{5} = 16; $arr[0][1]{6} = 11; $arr[0][2]{7} = 25; $arr[0][3]{8} = 31; $arr[0][4]{9} = 16; $arr[0][5]{10} = 17; sort the array based on hash values so this should change to $arr[0][0]{6} = 11; $arr[0][1]{9} = 16; $arr[0][2]{5} = 16; $arr[0][3]{10} = 17; $arr[0][4]{7} = 25; $arr[0][5]{8} = 31; first sort on values in the hash.. when the values are same reverse sort based on keys... Please tell me how to do this.. Thank you

    Read the article

  • sorting using recursion

    - by user310587
    I have the following function to sort an array with even numbers in the front and odd numbers in the back. Is there a way to get it done without using any loops? //front is 0, back =array.length-1; arrangeArray (front, back); public static void arrangeArray (int front, int back) { if (front != back || front<back) { while (numbers [front]%2 == 0) front++; while (numbers[back]%2!=0) back--; if (front < back) { int oddnum = numbers [front]; numbers[front]= numbers[back]; numbers[back]=oddnum; arrangeArray (front+1, back-1); } } }

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >