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• Convert Normalize table to Unormalize table

  - by M R Jafari

  I have tow tables, Table A has 3 columns as StudentID, Name, Course, ClassID and Table B has many columns as StudentID, Name, Other1, Other2, Other3 ... I want convert Table A to Table B. Please help me! Table A StudentID Name Course ClassID 85001 David Data Base 11 85001 David Data Structure 22 85002 Bob Math 33 85002 Bob Data Base 44 85002 Bob Data Structure 55 85002 Bob C# 66 85003 Sara C# 77 85003 Sara Data Base 88 85004 Mary Math 99 85005 Mary Math 100 … Table B SdentdID Name Other 1 Other 2 Other 3 Other 4 … 85001 David DBase,11 DS,22 85002 Bob Math,33 DB,44 DS,55 C#,66 85003 Sara C#,77 DBase,88 85004 Mary Math,99

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• mysql true row merge... not just a union

  - by panofish

  What is the mysql I need to achieve the result below given these 2 tables: table1: +----+-------+ | id | name | +----+-------+ | 1 | alan | | 2 | bob | | 3 | dave | +----+-------+ table2: +----+---------+ | id | state | +----+---------+ | 2 | MI | | 3 | WV | | 4 | FL | +----+---------+ I want to create a temporary view that looks like this desired result: +----+---------+---------+ | id | name | state | +----+---------+---------+ | 1 | alan | | | 2 | bob | MI | | 3 | dave | WV | | 4 | | FL | +----+---------+---------+ I tried a mysql union but the following result is not what I want. create view table3 as (select id,name,"" as state from table1) union (select id,"" as name,state from table2) table3 union result: +----+---------+---------+ | id | name | state | +----+---------+---------+ | 1 | alan | | | 2 | bob | | | 3 | dave | | | 2 | | MI | | 3 | | WV | | 4 | | FL | +----+---------+---------+ First suggestion results: SELECT * FROM table1 LEFT OUTER JOIN table2 USING (id) UNION SELECT * FROM table1 RIGHT OUTER JOIN table2 USING (id) +----+---------+---------+ | id | name | state | +----+---------+---------+ | 1 | alan | | | 2 | bob | MI | | 3 | dave | WV | | 2 | MI | bob | | 3 | WV | dave | | 4 | FL | | +----+---------+---------+

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• Rails How to get all the grandchildren of an ojbect.

  - by adam

  I have 3 models User has_many :quetions has_many :corrections end Question has_one :correction belongs_to :user end Correction belongs_to :user belongs_to :question So if user Bob asks a question then user Terry can check it and if its wrong offer a correction. Lets stay with bob and assume he as kindly corrected 5 other users, i.e and lets assume he has been lucky to get 3 corrections from other users. I want to be able to do something like this @bob.corrections_offered = 5 correction objects @bob.corrections_received = 3 correction objects the first one is easy as its really just @bob.corrections under the hood. But i dont know how to implement the latter one. Can anyone help?

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• links for 2011-03-11

  - by Bob Rhubart

  The Arup Nanda Blog: Good Engineering (tags: ping.fm) Spend Analytics on a Grand Scale (BI & Analytics Pulse) (tags: ping.fm) OSB and Coherence Integration (Mark Smith) (tags: ping.fm) Oracle Technology Network Architect Day: Denver (tags: ping.fm)

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• Using the public ssh key from local machine to access two remote users [closed]

  - by Nick

  I have an new Ubuntu (Hardy 8.04) server; it has two users, Alice and Bob. Alice is listed in sudoers. I appended my public ssh key (my local machine's public key local/Users/nick/.ssh/id_rsa.pub) to authorized_keys in remote_server/home/Alice/.ssh/authorized_keys, changed the permissions on Alice/.ssh/ to 700 and Alice/.ssh/authorized_keys to 600, and both the file and folder are owned my Alice. Then added I Alice to sshd_config (AllowUsers Alice). This works and I can login into Alice: ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 123.456.789.00 I then copied the authorized_keys file remote_server/home/Alice/.ssh/authorized_keys to remote_server/home/Bob/.shh/authorized_keys and changed the permissions and ownership and added Bob to AllowUsers in sshd_config (AllowUsers Alice Bob). Now when I try to login to Bob it will not authenticate the same public key. ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works?

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• Objective-C classes, pointers to primitive types, etc.

  - by Toby Wilson

  I'll cut a really long story short and give an example of my problem. Given a class that has a pointer to a primitive type as a property: @interface ClassOne : NSObject { int* aNumber } @property int* aNumber; The class is instantiated, and aNumber is allocated and assigned a value, accordingly: ClassOne* bob = [[ClassOne alloc] init]; bob.aNumber = malloc(sizeof(int)); *bob.aNumber = 5; It is then passed, by reference, to assign the aNumber value of a seperate instance of this type of class, accordingly: ClassOne* fred = [[ClassOne alloc] init]; fred.aNumber = bob.aNumber; Fred's aNumber pointer is then freed, reallocated, and assigned a new value, for example 7. Now, the problem I'm having; Since Fred has been assigned the same pointer that Bob had, I would expect that Bob's aNumber will now have a value of 7. It doesn't, because for some reason it's pointer was freed, but not reassigned (it is still pointing to the same address it was first allocated which is now freed). Fred's pointer, however, has the allocated value 7 in a different memory location. Why is it behaving like this? What am I minsunderstanding? How can I make it work like C++ does?

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• Beginner python - stuck in a loop

  - by Jeremy

  I have two begininer programs, both using the 'while' function, one works correctly, and the other gets me stuck in a loop. The first program is this; num=54 bob = True print('The guess a number Game!') while bob == True: guess = int(input('What is your guess? ')) if guess==num: print('wow! You\'re awesome!') print('but don\'t worry, you still suck') bob = False elif guess>num: print('try a lower number') else: print('close, but too low') print('game over')`` and it gives the predictable output of; The guess a number Game! What is your guess? 12 close, but too low What is your guess? 56 try a lower number What is your guess? 54 wow! You're awesome! but don't worry, you still suck game over However, I also have this program, which doesn't work; #define vars a = int(input('Please insert a number: ')) b = int(input('Please insert a second number: ')) #try a function def func_tim(a,b): bob = True while bob == True: if a == b: print('nice and equal') bob = False elif b > a: print('b is picking on a!') else: print('a is picking on b!') #call a function func_tim(a,b) Which outputs; Please insert a number: 12 Please insert a second number: 14 b is picking on a! b is picking on a! b is picking on a! ...(repeat in a loop).... Can someone please let me know why these programs are different? Thank you!

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• Altruistic network connection bandwidth estimation

  - by datenwolf

  Assume two peers Alice and Bob connected over a IP network. Alice and Bob are exchanging packets of lossy compressed data which are generated and to be consumes in real time (think a VoIP or video chat application). The service is designed to cope with as little bandwidth available, but relies on low latencies. Alice and Bob would mark their connection with an apropriate QoS profile. Alice and Bob want use a variable bitrate compression and would like to consume all of the leftover bandwidth available for the connection between them, but would voluntarily reduce the consumed bitrate depending on the state of the network. However they'd like to retain a stable link, i.e. avoid interruptions in their decoded data stream caused by congestion and the delay until the bandwidth got adjusted. However it is perfectly possible for them to loose a few packets. TL;DR: Alice and Bob want to implement a VoIP protocol from scratch, and are curious about bandwidth and congestion control. What papers and resources do you suggest for Alice and Bob to read? Mainly in the area of bandwidth estimation and congestion control.

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• Copying content on webpages in safari. To HTML

  - by Carl Smith

  Hi, is there an easier way to copy and paste website content in html? Want to copy and look like this. Product Information: Length: S / M / L Material: Polyester and Elasthane Brand: Roxana Exclusive Style: Basque But when i paste it into my content box it looks like this- Product Information Length: S / M / L Material: Polyester and Elasthane Brand: Roxana Exclusive Style: Basque Then i need to edit it in the html editor to rearrange it. Is the some sort of app or plugin that i can get so i can turn the text of the page into html so it looks right straight away when i copy it into my content box? If that makes any sense? Thanks Carl Smith :-)

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• Gateway IP Returns to Zero

  - by Robert Smith

  When you set a static IP under Ubuntu 12.04.1, you must supply the desired machine IP and the gateway IP, all using the Network Manager. When I first entered them and rebooted, everything worked great. On the second boot, however, Firefox could find no Web page. Upon checking, I discovered that the gateway IP had returned to zero. Now, no matter how often I resupply it, it returns to zero immediately after NM "saves" it: that is, appears as zero when redisplayed. The only way I can get to the Internet is to restore DHCP operation. I need to use static IP for access to my home network. Would appreciate any suggestion. --Robert Smith

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• Ways to ensure unique instances of a class?

  - by Peanut

  I'm looking for different ways to ensure that each instance of a given class is a uniquely identifiable instance. For example, I have a Name class with the field name. Once I have a Name object with name initialised to John Smith I don't want to be able to instantiate a different Name object also with the name as John Smith, or if instantiation does take place I want a reference to the orginal object to be passed back rather than a new object. I'm aware that one way of doing this is to have a static factory that holds a Map of all the current Name objects and the factory checks that an object with John Smith as the name doesn't already exist before passing back a reference to a Name object. Another way I could think of off the top of my head is having a static Map in the Name class and when the constructor is called throwing an exception if the value passed in for name is already in use in another object, however I'm aware throwing exceptions in a constructor is generally a bad idea. Are there other ways of achieving this?

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• Installing ubuntuone

  - by bob

  Linux Mint 14 os I have tried to install ubuntu one onto the linux mint 14 through Synaptic package manager and software manager, both say its installed but when I go to find the programme its not there. installed as what Synaptic says........... ubuntuone client, ubuntuone client data, ubuntuone client gnome, ubuntuone control panel, what else is missing from this list please, it used to be so so easy to install but now, eeeek yours in advance Bob

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• Ubuntu 10.10 not recognizing external hard drive

  - by sr71

  Installed Ubuntu 10.10 on a hard drive by itself (no windows). All updates are up to date. Everything`works fine except when I plug in a 320 gig Toshiba external hard drive....it is not recognized. When I plug in an 8 gig flash drive it is recognized no problem. What do I mean by "not recognized"? I mean: how do you know it was not recognized. You can check the command "cat /proc/partitions" in a terminal with and without the hdd attached. If you see some difference, it's ok. If the difference is something like "sda1" (sd+letter+number) then you have partition on it, maybe it can't be handled in Ubuntu (no filesystem on it or so). If there is only "sda" in the difference for example (sd+letter, but no number after it) then the drive itself is detected, just no partition is created on it. Also you can check out the messages of the kernel, with the "dmesg" command in the terminal. If there is no disk/partition/anything in /proc/partitions, there can be an USB level problem, you can issue command "lsusb" as it was suggested before my answer. It's really matter of what do you mean about "not recognized". @Marco Ceppi @Oli @Pitto By "not recognized" I meant that when I plug in a 8 gig flash drive an icon immediately appears on the desktop imdicating that there is a flash drive plugged in and I can click on it and view the files on the flash drive. It also shows up on the "Nautilus" default file manager. When I plug in the 320 gig Toshiba external hard drive, I get no indication on the desktop or the file manager (thus "not recogized"). When I run the command "cat/proc/partitions/" I get an error message Could not open location 'file:///home/bob/cat/proc/partitions' with or without the external hard drive installed. With the "dmeg" command I get about 10 pages of info with no mention of disk/partition/anything in /proc/partitions. When I run "lsub" command I get the following: bob@bob-desktop:~$ lsusb Bus 005 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 004 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 003 Device 003: ID 04b3:3003 IBM Corp. Rapid Access III Keyboard Bus 003 Device 002: ID 04b3:3004 IBM Corp. Media Access Pro Keyboard Bus 003 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 002 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub bob@bob-desktop:~$

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• OpenSUSE Yast permissions for user

  - by pajton

  I have an OpenSUSE 11.4 box with Kde 4.6. I am currently working to create a sandbox environment for the user, let's call hime bob. Bob isn't allowed to do much in the system, but I'd like to let him configure certain things in yast. I have dektop shortcuts for particular yast modules, e.g. the shortcut executes xdg-su -c "/sbin/yast2 lan" to launch yast lan configuration. Now, I do not want Bob to have to enter password to launch this configuration (just please don't tell me it's insecure - I know this, in this particular setting it is going to be OK). I wanted to do this with setuid, but obiously setting it on *.desktop shortcut doesn't work. There is sudo approach, but I would have to allow Bob to use all yast modules. So, is there anything more fine-grained to set the permissions for exact yast modules? Thanks in advance!

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• Which server software and configuration to retrieve from multiple POP servers, routing by address to correct user

  - by rolinger

  I am setting up a small email server on a Debian machine, which needs to pick up mail from a variety of POP servers and figure out who to send it to from the address, but I'm not clear what software will do what I need, although it seems like a very simple question! For example, I have 2 users, Alice and Bob. Any email to [email protected] ([email protected] etc) should go to Alice, all other mail to domain.example.com should go to Bob. Any email to [email protected] should go to Bob, and [email protected] should go to Alice Anything to *@bobs.place.com should go to Bob And so on... The idea is to pull together a load of mail addresses that have built up over the years and present them all as a single mailbox for Bob and another one for Alice. I'm expecting something like Postfix + Dovecot + Amavis + Spamassassin + Squirrelmail to fit the bill, but I'm not sure where the above comes in, can Postfix deal with it as a set of defined regular expressions, or is it a job for Amavis, or something else entirely? Do I need fetchmail in this mix, or is its role now included in one of the other components above. I think of it as content-filtering, but everything I read about content-filtering is focussed on detecting spam rather than routing email.

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• Sendmail - preventing aliased users from receiving multiple copies of the same email

  - by MikeQ

  Is there any way to prevent a user from receiving multiple copies of the same email if an email is sent to both an alias for the user as well as the user themselves? For example, suppose bob.smith is a included in the alias list for developers (@company.com) If I send the email to both the user and an alias for the user: To: bob[email protected], [email protected] ... is there any way to prevent user Bob from receiving the same email two times? EDIT: I've observed that if Bob is a member of two different alias groups, and I send an email just to those two groups (not the user directly), sendmail correctly expands the groups and removes the duplicate. The behavior I want to fix occurs when you send directly to the user AND a group they belong to.

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• Windows 7, network shares, and authentication via local group instead of local user

  - by Donovan

  I have been doing some troubleshooting of my home network lately and have come to an odd conclusion that I was hoping to get some clarification on. I'm used to managing share permissions in a domain environment via groups instead of individual user accounts. I have a box at home running windows 7 ultimate and I decided to share some directories on that machine. I set it up to disallow guest access and require specifically granted permissions. (password moe?). Anyway, after a whole bunch of time i figured out that even though the shares I created were allowed via a local group i could not access them until i gave specific allowance to the intended user. I just didn't think i would have to do that. So here is the breakdown. Network is windows workgroup, not homegroup or nt domain PC_1 - win 7 ultimate - sharing in classic mode - user BOB - groups Admins PC_2 - win 7 starter - client - user BOB - groups admins PC_3 - win xp pro - client - user BOB - groups admins the share on PC_1 granted permission to only the local group administrators. local user BOB on PC_1 was a member of administrators. Both PC_2 and PC_3 could not browse the intended share on PC_1 because they were denied access. Also, no challenge was presented. They were simply denied. After adding BOB specifically to the intended share everything works just fine. Remember, its not an nt domain just a workgroup. But still, shouldn't i be able to manage share permissions via groups instead of individual user accounts? D.

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• What's the best / easiest way to combine two mailboxes on Exchange 2007?

  - by jmassey

  I've found this and this(2) (sorry, maximum hyperlink limit for new users is 1, apparently), but they both seem targeted toward much more complex cases than what I'm trying to do, and I just want to make sure I'm not missing some better approach. Here's the scenario: 'Alice' has retired. 'Bob' has taken over Alice's position. Bob was already with the organization in a different but related position, and so they already have their own Exchange account with mail, calendars, etc., that they need to keep. I need to get all of Alice's old mail, calendar entries, etc., merged into Bob's existing stuff. Ideally, I don't want to have all of Alice's stuff in a separate 'recovery' folder that Bob would have to switch back and forth between to look at older stuff; I want it all just merged into Bob's current Inbox / Calendar. I'm assuming (read: hoping) that there's a better way to do this than fiddling with permissions and exporting to and then importing from a .pst. Office version is 2007 for everybody that uses Exchange, if that helps. Exchange is version 8.1. What (preferably step-by-step - I'm new to Exchange) is the best way to do this? I can't imagine this is an uncommon scenario, but my google-fu has failed me; there seems to be nothing on this subject that isn't geared towards far more complex scenarios. (2): h t t p://technet.microsoft.com/en-us/library/bb201751%28EXCHG.80%29.aspx

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• pygame double buffering

  - by BaldDude

  I am trying to use double buffering in pygame. What I'm trying to do is display a red then green screen, and switch from one to the other. Unfortunately, all I have is a black screen. I looked through many sites, but have been unable to find a solution. Any help would be appreciated. import pygame, sys from pygame.locals import * RED = (255, 0, 0) GREEN = ( 0, 255, 0) bob = 1 pygame.init() #DISPLAYSURF = pygame.display.set_mode((500, 400), 0, 32) DISPLAYSURF = pygame.display.set_mode((1920, 1080), pygame.OPENGL | pygame.DOUBLEBUF | pygame.HWSURFACE | pygame.FULLSCREEN) glClear(GL_COLOR_BUFFER_BIT) glMatrixMode(GL_MODELVIEW) glLoadIdentity() running = True while running: if bob==1: #pygame.draw.rect(DISPLAYSURF, RED, (0, 0, 1920, 1080)) #pygame.display.flip() glBegin(GL_QUADS) glColor3f(1.0, 0.0, 0.0) glVertex2f(-1.0, 1.0) glVertex2f(-1.0, -1.0) glVertex2f(1.0, -1.0) glVertex2f(1.0, 1.0) glEnd() pygame.dis bob = 0 else: #pygame.draw.rect(DISPLAYSURF, GREEN, (0, 0, 1920, 1080)) #pygame.display.flip() glBegin(GL_QUADS) glColor3f(0.0, 1.0, 0.0) glVertex2f(-1.0, 1.0) glVertex2f(-1.0, -1.0) glVertex2f(1.0, -1.0) glVertex2f(1.0, 1.0) glEnd() pygame.dis bob = 1 for event in pygame.event.get(): if event.type == pygame.QUIT: running = False elif event.type == KEYDOWN: if event.key == K_ESCAPE: running = False pygame.quit() sys.exit() I'm using Python 2.7 and my code need to be os independent. Thanks for your help.

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• Are today's general purpose languages at the right level of abstarction ?

  - by KeesDijk

  Today Uncle Bob Martin, a genuine hero, showed this video In this video Bob Martin claims that our programming languages are at the right level for our problems at this time. One of the reasons I get from this video as that he Bob Martin sees us detail managers and our problems are at the detail level. This is the first time I have to disagree with Bob Martin and was wondering what the people at programmers think about this. First there is a difference between MDA and MDE MDA in itself hasn't worked and I blame way to much formalisation at a level you can't formalize these kind of problems. MDE and MDD are still trying to prove themselves and in my mind show great promise. e.g. look at MetaEdit The detail still needs to be management in my mind, but you do so in one place (framework or generators) instead of at multiple places. Right for our kind of problems ? I think depends on what problems you look at. Do the current programming languages keep up with the current demands on time to market ? Are they good at bridging the business IT communication gap ? So what do you think ?

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• Are today's general purpose languages at the right level of abstraction ?

  - by KeesDijk

  Today Uncle Bob Martin, a genuine hero, showed this video In this video Bob Martin claims that our programming languages are at the right level for our problems at this time. One of the reasons I get from this video as that Bob Martin sees us as detail managers and our problems are at the detail level. This is the first time I have to disagree with Bob Martin and was wondering what the people at programmers think about this. First there is a difference between MDA and MDE MDA in itself hasn't worked and I blame way to much formalisation at a level you can't formalize these kind of problems. MDE and MDD are still trying to prove themselves and in my mind show great promise. e.g. look at MetaEdit The detail still needs to be management in my mind, but you do so in one place (framework or generators) instead of at multiple places. Right for our kind of problems ? I think depends on what problems you look at. Do the current programming languages keep up with the current demands on time to market ? Are they good at bridging the business IT communication gap ? So what do you think ?

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• Help with SVN+SSH permissions with CentOS/WHM setup

  - by Furiam

  Hi Folks, I'll try my best to explain how I'm trying to set up this system. Imagine a production server running WHM with various sites. We'll call these sites... site1, site2, site2 Now, with the WHM setup, each site has a user/group defined for them, we'll keep these users/groups called site1,site2 for simplicity reasons. Now, updating these sites is accomplished using SVN, and through the use of a post commit script to auto update these sites (With .svn blocked through the apache configuration). There are two regular maintainers of these sites, we'll call them Joe and Bob. Joe and Bob both have commandline access to the server through thier respective limited accounts. So I've done the easy bit, managed to get SVN working with these "maintainers" so that when an SVN commit occurs, the changes are checked out and go live perfectly. Here's the cavet, and ultimately my problem. User permissions. Through my testing of this setup, I've only managed to get it working by giving what is being updated permissions of 777, so that Joe and Bob can both read and write access to webfront directories for each of the sites. So, an example of how it's set up now: Joe and Bob both belong to a group called "Dev". I have the master /svn folders set up for both read and write access to this group, and it works great. Post commit triggers, updates the site, and then sets 777 on each file within the webfront. I then changed this to try and factor in group permission updates, instead of straight 777. Each folder in /home/site1/public_html intially gets given a chmod of 664, and each folder 775 Which looks a little something like this drwxrwxr-x . drwxrwxr-x .. drwxrwxr-x site1 site1 my_test_folder -rw-rw-r-- site1 site1 my_test_file So site1 is sthe owner and group owner of those files and folders. So I then added site1 to Joe and Bobs secondary groups so that the SVN update will correctly allow access to these files. Herein lies the problem now. When I wish to add a file or folder to /home/site1, say Bobs_file, it then looks like this drwxrwxr-x . drwxrwxr-x .. drwxr-xr-x Bob dev bobs_folder drwxrwxr-x site1 site1 my_test_folder -rw-rw-r-- Bob dev bobs_file -rw-rw-r-- site1 site1 my_test_file How can I get it so that with the set of user permissions Bob has available, to change the owner and group owner of that file to reflect "site1" "site1". As Bob belongs to Dev I can set the permissions correctly with CHMOd, but It appears CHGRP is throwing back operation errors. Now this was long winded enough to give an overview of exactly what I'm trying to accomplish, just incase I'm going about this arse-over-tit and there's a far easier solution. Here's my goals 2 people to update multiple user accounts specified given the structure of WHM Trying to maintain master user/group permissions of file and folders to the original user account, and not the account of the updatee. I like the security of SVN+SSH over just SVN. Don't want to run all this over root. I hope this made sense, and thanks in advance :)

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• OTN ArchBeat Top 10 for September 2012

  - by Bob Rhubart

  The results are in... Listed below are the Top 10 most popular items shared via the OTN ArchBeat Facebook Page for the month of September 2012. The Real Architects of Los Angeles - OTN Architect Day - Oct 25 No gossip. No drama. No hair pulling. Just a full day of technical sessions and peer interaction focused on using Oracle technologies in today's cloud and SOA architectures. The event is free, but seating is limited, so register now. Thursday October 25, 2012. 8:00 a.m. – 5:00 p.m. Sofitel Los Angeles, 8555 Beverly Boulevard, Los Angeles, CA 90048. Oracle Fusion Middleware Security: Attaching OWSM policies to JRF-based web services clients "OWSM (Oracle Web Services Manager) is Oracle's recommended method for securing SOAP web services," says Oracle Fusion Middleware A-Team member Andre Correa. "It provides agents that encapsulate the necessary logic to interact with the underlying software stack on both service and client sides. Such agents have their behavior driven by policies. OWSM ships with a bunch of policies that are adequate to most common real world scenarios." His detailed post shows how to make it happen. Oracle 11gR2 RAC on Software Defined Network (SDN) (OpenvSwitch, Floodlight, Beacon) | Gilbert Stan "The SDN [software defined network] idea is to separate the control plane and the data plane in networking and to virtualize networking the same way we have virtualized servers," explains Gil Standen. "This is an idea whose time has come because VMs and vmotion have created all kinds of problems with how to tell networking equipment that a VM has moved and to preserve connectivity to VPN end points, preserve IP, etc." H/T to Oracle ACE Director Tim Hall for the recommendation. Process Oracle OER Events using a simple Web Service | Bob Webster Bob Webster's post "provides an example of a simple web service that processes Oracle Enterprise Repository (OER) Events. The service receives events from OER and utilizes the OER REX API to implement simple OER automations for selected event types." Understanding Oracle BI 11g Security vs Legacy Oracle BI 10g | Christian Screen "After conducting a large amount of Oracle BI 10g to Oracle BI 11g upgrades and after writing the Oracle BI 11g book,"says Oracle ACE Christian Screen, "I still continually get asked one of the most basic questions regarding security in Oracle BI 11g; How does it compare to Oracle BI 10g? The trail of questions typically goes on to what are the differences? And, how do we leverage our current Oracle BI 10g security table schema in Oracle BI 11g?" OIM-OAM-OAAM integration using TAP – Request Flow you must understand!! | Atul Kumar Atul Kumar's post addresses "key points and request flow that you must understand" when integrating three Oracle Identity Management product Oracle Identity Management, Oracle Access Management, and Oracle Adaptive Access Manager. Adding a runtime LOV for a taskflow parameter in WebCenter | Yannick Ongena Oracle ACE Yannick Ongena illustrates how to customize the parameters tab for a taskflow in WebCenter. Tips on Migrating from AquaLogic .NET Accelerator to WebCenter WSRP Producer for .NET | Scott Nelson "It has been a very winding path and this blog entry is intended to share both the lessons learned and relevant approaches that led to those learnings," says Scott Nelson. "Like most journeys of discovery, it was not a direct path, and there are notes to let you know when it is practical to skip a section if you are in a hurry to get from here to there." 15 Lessons from 15 Years as a Software Architect | Ingo Rammer In this presentation from the GOTO Conference in Copenhagen, Ingo Rammer shares 15 tips regarding people, complexity and technology that he learned doing software architecture for 15 years. WebCenter Content (WCC) Trace Sections | ECM Architect ECM Architect Kevin Smith shares a detailed technical post covering WebCenter Content (WCC) Trace Sections. Thought for the Day "Eventually everything connects - people, ideas, objects. The quality of the connections is the key to quality per se." — Charles Eames (June 17, 1907 – August 21, 1978) Source: SoftwareQuotes.com

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• What is the effect of this order_by clause?

  - by bread

  I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

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• Tricky SQL query involving consecutive values

  - by Gabriel

  I need to perform a relatively easy to explain but (given my somewhat limited skills) hard to write SQL query. Assume we have a table similar to this one: exam_no | name | surname | result | date ---------+------+---------+--------+------------ 1 | John | Doe | PASS | 2012-01-01 1 | Ryan | Smith | FAIL | 2012-01-02 <-- 1 | Ann | Evans | PASS | 2012-01-03 1 | Mary | Lee | FAIL | 2012-01-04 ... | ... | ... | ... | ... 2 | John | Doe | FAIL | 2012-02-01 <-- 2 | Ryan | Smith | FAIL | 2012-02-02 2 | Ann | Evans | FAIL | 2012-02-03 2 | Mary | Lee | PASS | 2012-02-04 ... | ... | ... | ... | ... 3 | John | Doe | FAIL | 2012-03-01 3 | Ryan | Smith | FAIL | 2012-03-02 3 | Ann | Evans | PASS | 2012-03-03 3 | Mary | Lee | FAIL | 2012-03-04 <-- Note that exam_no and date aren't necessarily related as one might expect from the kind of example I chose. Now, the query that I need to do is as follows: From the latest exam (exam_no = 3) find all the students that have failed (John Doe, Ryan Smith and Mary Lee). For each of these students find the date of the first of the batch of consecutively failing exams. Another way to put it would be: for each of these students find the date of the first failing exam that comes after their last passing exam. (Look at the arrows in the table). The resulting table should be something like this: name | surname | date_since_failing ------+---------+-------------------- John | Doe | 2012-02-01 Ryan | Smith | 2012-01-02 Mary | Lee | 2012-01-04 Ann | Evans | 2012-02-03 How can I perform such a query? Thank you for your time.

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