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  • Can I reproduce Scala's behavior for == ?

    - by JPP
    In Programming in Scala, I can read that the == operator behaves as if it was defined like this: final def == (that: Any): Boolean = if (null eq this) {null eq that} else {this equals that} But there must actually be compiler magic to avoid null pointer exceptions, right? Is there any way for me to replicate this behavior with pure Scala; i.e., have an operator/method return one thing if the receiver is null and another one if it isn't? What I mean is an actual implementation of null eq this. I suppose I can write a "pimp" and then define the method on the wrapper class, but is there a more direct way to do this?

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  • find all occurrences of comparison with == in visual studio

    - by Emiswelt
    Hi there I made the mistake of using == for comparing IP addresses instead of using the equals() method of the IPAddress class in C#, which will result in the comparison of references instead of values. Since the solution I am currently working on is very large for a one-man project ( 100.000 lines of source code), I am very sure that I still have some of these wrong statements in my code. Is there any possibility to tell Visual Studio to find all occurrences of == operations on a specific class for me, so that I can find and clean up the bugged comparisons? with best regards, emi

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  • c# xml function to check whether a string is equal to a xml attribute, to add selected combobox item

    - by fuch
    i want to check the combobox.selecteditem.tostring() on combobox select in a given xml with several nodes, where each one has an attribute called "name" private void comboBox1_SelectedIndexChanged(object sender, EventArgs e) { try { textBox1.AppendText(nameAttributeCheck(comboBox1.SelectedItem.ToString())); } catch { } } private string nameAttributeCheck(string a) { XmlDocument doc = new XmlDocument(); doc.Load("armor.xml"); XmlElement root = doc.DocumentElement; XmlNodeList items = root.SelectNodes("/items"); String result = null; try { foreach (XmlNode item in items) { if (string.Equals(a, item.Attributes["name"].InnerText.ToString())) { result += item.Attributes["picture"].InnerText.ToString(); } } } catch { } return result; } each time i try it, nothing happens

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  • Help with string equality in Java

    - by annayena
    The following function accepts 2 strings, the 2nd (not 1st) possibly containing *'s (asterisks). An * is a replacement for a string (empty, 1 char or more), it can appear appear (only in s2) once, twice, more or not at all, it cannot be adjacent to another * (ab**c), no need to check that. public static boolean samePattern(String s1, String s2) It returns true if strings are of the same pattern. It must be recursive, not use any loops, static or global variables. Also it's prohibited to use the method equals in the String class. Can use local variables and method overloading. Can use only these methods: charAt(i), substring(i), substring(i, j), length(). Examples: 1: TheExamIsEasy; 2: "The*xamIs*y" ---> true 1: TheExamIsEasy; 2: "Th*mIsEasy*" ---> true 1: TheExamIsEasy; 2: "*" ---> true 1: TheExamIsEasy; 2: "TheExamIsEasy" ---> true 1: TheExamIsEasy; 2: "The*IsHard" ---> FALSE I am stucked on this question for many hours now! I need the solution in Java please kindly help me.

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  • MVC ActionLink omits action when action equals default route value

    - by rjygraham
    I have the following routes defined for my application: routes.MapRoute( "Referral", // Route name "{referralCode}", // URL with parameters new { controller = "Home", action = "Index" } // Parameter defaults ); routes.MapRoute( "Default", // Route name "{controller}/{action}", // URL with parameters new { controller = "Home", action = "Index" } // Parameter defaults ); And I'm trying to create an ActionLink to go on the Index action on my AdminController: @Html.ActionLink("admin", "Index", "Admin") However, when the view is executed the ActionLink renders as (Index action value is omitted): <a href="/Admin">admin</a> Normally this would be ok, but it's causing a collision with the "Referral" route. NOTE: If I instead use ActionLink to render a different action like "Default," the ActionLink renders correctly: <a href="/Admin/Default">admin</a> The fact that the "Default" action renders correctly leads me to believe the problem has to do with the default value specified for the route. Is there anyway to force ActionLink to render the "Index" action as well?

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  • Scala method where type of second parameter equals part of generic type from first parameter

    - by ifischer
    I want to create a specific generic method in Scala. It takes two parameters. The first is of the type of a generic Java Interface (it's from the JPA criteria query). It currently looks like this: def genericFind(attribute:SingularAttribute[Person, _], value:Object) { ... } // The Java Interface which is the type of the first parameter in my find-method: public interface SingularAttribute<X, T> extends Attribute<X, T>, Bindable<T> Now i want to achieve the following: value is currently of type java.lang.Object. But I want to make it more specific. Value has to be the of the same type as the placeholder "_" from the first parameter (and so represents the "T" in the Java interface). Is that somehow possible, and how? BTW Sorry for the stupid question title (any suggestions?)

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  • Find if id of a link equals id of parent container

    - by Robert Lawson
    Hi guys needing a bit of help. I am creating a one page personal site. Each section has a menu in it to jump to another section, however i want to have a class added to menu for the current section: i.e. if you are in about the about link would have a class 'current'. This is how it looks. <section id="about"> <nav> <li><a href="#" id ="about">About</a></li> <li><a href="#" id ="contact">About</a></li> <li><a href="#" id ="blog">About</a></li> </nav> New to jquery so i am struggling to find out how to do this. Any help will be greatly appreciated. Thanks

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  • Problem with a NSString that equals to (null)

    - by Guy Dor
    Hi, I have an UIViewController named MainViewController I have another UIViewController named LeftSharingViewController; I would like to get and use the NSString from MainViewController in my LeftSharingViewController I have a problem, I always get (null) instead of the NSString wanted value. Here's my code and how does the NSString get it's value MainViewController: - (void)webViewDidFinishLoad:(UIWebView *)webView { leftWebViewString = [NSString stringWithString:leftWebView.request.URL.absoluteString]; } LeftSharingViewController.h: #import <UIKit/UIKit.h> #import "MainViewController.h" #import <MessageUI/MessageUI.h> #import <MessageUI/MFMailComposeViewController.h> @class MainViewController; @interface LeftSharingViewController : UIViewController <MFMailComposeViewControllerDelegate> { MainViewController *mainViewController; NSString *leftWebViewUrl; } @property (nonatomic, retain) MainViewController *mainViewController; @property (nonatomic, retain) NSString *leftWebViewUrl; @end LeftSharingViewController.m: #import "LeftSharingViewController.h" #import "MainViewController.h" @implementation LeftSharingViewController @synthesize mainViewController; @synthesize leftWebViewUrl; - (void)viewWillAppear:(BOOL)animated { self.leftWebViewUrl = self.mainViewController.leftWebViewString; } #pragma mark - #pragma mark Compose Mail -(void)displayComposerSheet { MFMailComposeViewController *mailPicker = [[MFMailComposeViewController alloc] init]; mailPicker.mailComposeDelegate = self; [mailPicker setSubject:@"Check Out This Website!"]; [mailPicker setMessageBody:[NSString stringWithFormat:@"Take a look at this site:%@", leftWebViewUrl] isHTML:YES]; mailPicker.modalPresentationStyle = UIModalPresentationFormSheet; [self presentModalViewController:mailPicker animated:YES]; [mailPicker release]; } Thanks!

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  • PHP variable equals true no matter what the value, even 0

    - by kaigoh
    This is the var_dump: object(stdClass)#27 (8) { ["SETTING_ID"]=> string(2) "25" ["SETTING_SOURCE"]=> string(2) "XV" ["SETTING_FLEET"]=> string(3) "313" ["SETTING_EXAM"]=> string(1) "A" ["SETTING_HIDE"]=> string(1) "0" ["SETTING_THRESHOLD"]=> string(1) "0" ["SETTING_COUNT"]=> string(8) "POSITIVE" ["SETTING_USAGE"]=> string(7) "MILEAGE" } The variable I am testing is SETTING_HIDE. This is being pulled from MySQL using the Code igniter framework. I don't know if it is just me being thick after a rather long day at work or what, but no matter what value the variable holds, any if statement made against it returns true, even when typecast as a boolean or a direct string comparison, ie. == "0" or == "1". Anyone with a fresh pair of eyes care to make me feel silly!?! :) Just to clarify: Have tried the following: if($examSetting->SETTING_HIDE == "1") { $showOnABC = "checked=\"checked\""; } if((bool)$examSetting->SETTING_HIDE) { $showOnABC = "checked=\"checked\""; } if($examSetting->SETTING_COUNT == "POSITIVE") further on in my code works perfectly.

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  • How to get element order number

    - by martin-masiar
    Hello everyone, how can i get order number of some element by javascript/jquery? <ul> <li>Anton</li> <li class="abc">Victor</li> <li class="abc">Simon</li> <li>Adam</li> <li>Peter</li> <li class="abc">Tom</li> </ul> There is 3xli with abc class. Now I need to get order(sequence) number of Simon li. Thanks in advance

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  • Can't operator == be applied to generic types in C#?

    - by Hosam Aly
    According to the documentation of the == operator in MSDN, For predefined value types, the equality operator (==) returns true if the values of its operands are equal, false otherwise. For reference types other than string, == returns true if its two operands refer to the same object. For the string type, == compares the values of the strings. User-defined value types can overload the == operator (see operator). So can user-defined reference types, although by default == behaves as described above for both predefined and user-defined reference types. So why does this code snippet fail to compile? void Compare<T>(T x, T y) { return x == y; } I get the error Operator '==' cannot be applied to operands of type 'T' and 'T'. I wonder why, since as far as I understand the == operator is predefined for all types? Edit: Thanks everybody. I didn't notice at first that the statement was about reference types only. I also thought that bit-by-bit comparison is provided for all value types, which I now know is not correct. But, in case I'm using a reference type, would the the == operator use the predefined reference comparison, or would it use the overloaded version of the operator if a type defined one? Edit 2: Through trial and error, we learned that the == operator will use the predefined reference comparison when using an unrestricted generic type. Actually, the compiler will use the best method it can find for the restricted type argument, but will look no further. For example, the code below will always print true, even when Test.test<B>(new B(), new B()) is called: class A { public static bool operator==(A x, A y) { return true; } } class B : A { public static bool operator==(B x, B y) { return false; } } class Test { void test<T>(T a, T b) where T : A { Console.WriteLine(a == b); } }

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  • C# - How to override GetHashCode with Lists in object

    - by Christian
    Hi, I am trying to create a "KeySet" to modify UIElement behaviour. The idea is to create a special function if, eg. the user clicks on an element while holding a. Or ctrl+a. My approach so far, first lets create a container for all possible modifiers. If I would simply allow a single key, it would be no problem. I could use a simple Dictionary, with Dictionary<Keys, Action> _specialActionList If the dictionary is empty, use the default action. If there are entries, check what action to use depending on current pressed keys And if I wasn't greedy, that would be it... Now of course, I want more. I want to allow multiple keys or modifiers. So I created a wrapper class, wich can be used as Key to my dictionary. There is an obvious problem when using a more complex class. Currently two different instances would create two different key, and thereby he would never find my function (see code to understand, really obvious) Now I checked this post: http://stackoverflow.com/questions/638761/c-gethashcode-override-of-object-containing-generic-array which helped a little. But my question is, is my basic design for the class ok. Should I use a hashset to store the modifier and normal keyboardkeys (instead of Lists). And If so, how would the GetHashCode function look like? I know, its a lot of code to write (boring hash functions), some tips would be sufficient to get me started. Will post tryouts here... And here comes the code so far, the Test obviously fails... public class KeyModifierSet { private readonly List<Key> _keys = new List<Key>(); private readonly List<ModifierKeys> _modifierKeys = new List<ModifierKeys>(); private static readonly Dictionary<KeyModifierSet, Action> _testDict = new Dictionary<KeyModifierSet, Action>(); public static void Test() { _testDict.Add(new KeyModifierSet(Key.A), () => Debug.WriteLine("nothing")); if (!_testDict.ContainsKey(new KeyModifierSet(Key.A))) throw new Exception("Not done yet, help :-)"); } public KeyModifierSet(IEnumerable<Key> keys, IEnumerable<ModifierKeys> modifierKeys) { foreach (var key in keys) _keys.Add(key); foreach (var key in modifierKeys) _modifierKeys.Add(key); } public KeyModifierSet(Key key, ModifierKeys modifierKey) { _keys.Add(key); _modifierKeys.Add(modifierKey); } public KeyModifierSet(Key key) { _keys.Add(key); } }

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  • Problem with operator ==

    - by CPPDev
    I am facing some problem with use of operator == in the following c++ program. #include < iostream> using namespace std; class A { public: A(char *b) { a = b; } A(A &c) { a = c.a; } bool operator ==(A &other) { return strcmp(a, other.a); } private: char *a; }; int main() { A obj("test"); A obj1("test1"); if(obj1 == A("test1")) { cout<<"This is true"<<endl; } } What's wrong with if(obj1 == A("test1")) line ?? Any help is appreciated.

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  • Two '==' equality operators in same 'if' condition are not working as intended.

    - by Manav MN
    I am trying to establish equality of three equal variables, but the following code is not printing the obvious true answer which it should print. Can someone explain, how the compiler is parsing the given if condition internally? #include<stdio.h> int main() { int i = 123, j = 123, k = 123; if ( i == j == k) printf("Equal\n"); else printf("NOT Equal\n"); return 0; } Output: manav@workstation:~$ gcc -Wall -pedantic calc.c calc.c: In function ‘main’: calc.c:5: warning: suggest parentheses around comparison in operand of ‘==’ manav@workstation:~$ ./a.out NOT Equal manav@workstation:~$ EDIT: Going by the answers given below, is the following statement okay to check above equality? if ( (i==j) == (j==k))

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  • Why does virtual assignment behave differently than other virtual functions of the same signature?

    - by David Rodríguez - dribeas
    While playing with implementing a virtual assignment operator I have ended with a funny behavior. It is not a compiler glitch, since g++ 4.1, 4.3 and VS 2005 share the same behavior. Basically, the virtual operator= behaves differently than any other virtual function with respect to the code that is actually being executed. struct Base { virtual Base& f( Base const & ) { std::cout << "Base::f(Base const &)" << std::endl; return *this; } virtual Base& operator=( Base const & ) { std::cout << "Base::operator=(Base const &)" << std::endl; return *this; } }; struct Derived : public Base { virtual Base& f( Base const & ) { std::cout << "Derived::f(Base const &)" << std::endl; return *this; } virtual Base& operator=( Base const & ) { std::cout << "Derived::operator=( Base const & )" << std::endl; return *this; } }; int main() { Derived a, b; a.f( b ); // [0] outputs: Derived::f(Base const &) (expected result) a = b; // [1] outputs: Base::operator=(Base const &) Base & ba = a; Base & bb = b; ba = bb; // [2] outputs: Derived::operator=(Base const &) Derived & da = a; Derived & db = b; da = db; // [3] outputs: Base::operator=(Base const &) ba = da; // [4] outputs: Derived::operator=(Base const &) da = ba; // [5] outputs: Derived::operator=(Base const &) } The effect is that the virtual operator= has a different behavior than any other virtual function with the same signature ([0] compared to [1]), by calling the Base version of the operator when called through real Derived objects ([1]) or Derived references ([3]) while it does perform as a regular virtual function when called through Base references ([2]), or when either the lvalue or rvalue are Base references and the other a Derived reference ([4],[5]). Is there any sensible explanation to this odd behavior?

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  • equality on the sender of an event

    - by Berryl
    I have an interface for a UI widget, two of which are attributes of a presenter. public IMatrixWidget NonProjectActivityMatrix { set { // validate the incoming value and set the field _nonProjectActivityMatrix = value; .... // configure & load non-project activities } public IMatrixWidget ProjectActivityMatrix { set { // validate the incoming value and set the field _projectActivityMatrix = value; .... // configure & load project activities } The widget has an event that both presenter objects subscribe to, and so there is an event handler in the presenter like so: public void OnActivityEntry(object sender, EntryChangedEventArgs e) { // calculate newTotal here .... if (ReferenceEquals(sender, _nonProjectActivityMatrix)) { _nonProjectActivityMatrix.UpdateTotalHours(feedback.ActivityTotal); } else if (ReferenceEquals(sender, _projectActivityMatrix)) { _projectActivityMatrix.UpdateTotalHours(feedback.ActivityTotal); } else { // ERROR - we should never be here } } The problem is that the ReferenceEquals on the sender fails, even though it is the implemented widget that is the sender - the same implemented widget that was set to the presenter attribute! Can anyone spot what the problem / fix is? Cheers, Berryl I didn't know you could edit nicely. Cool. Here is the event raising code: void OnGridViewNumericUpDownEditingControl_ValueChanged(object sender, EventArgs e) { // omitted to save sapce if (EntryChanged == null) return; var args = new EntryChangedEventArgs(activityID, dayID, Convert.ToDouble(amount)); EntryChanged(this, args); } Here is the debugger dump of the presenter attribute, sans namespace info: ?_nonProjectActivityMatrix {WinPresentation.Widgets.MatrixWidgetDgv} [WinPresentation.Widgets.MatrixWidgetDgv]: {WinPresentation.Widgets.MatrixWidgetDgv} Here is the debugger dump of the sender: ?sender {WinPresentation.Widgets.MatrixWidgetDgv} base {Core.GUI.Widgets.Lookup.MatrixWidgetBase<Core.GUI.Widgets.Lookup.DynamicDisplayDto>}: {WinPresentation.Widgets.MatrixWidgetDgv} _configuration: {Domain.Presentation.Timesheet.Matrix.WeeklyMatrixConfiguration} _wrappedWidget: {Win.Widgets.DataGridViewDynamicLookupWidget} AllowUserToAddRows: true ColumnCount: 11 Count: 4 EntryChanged: {Method = {Void OnActivityEntry(System.Object, Smack.ConstructionAdmin.Domain.Presentation.Timesheet.Matrix.EntryChangedEventArgs)}} SelectedCell: {DataGridViewNumericUpDownCell { ColumnIndex=3, RowIndex=3 }} SelectedCellValue: "0.00" SelectedColumn: {DataGridViewNumericUpDownColumn { Name=MONDAY, Index=3 }} SelectedItem: {'AdministrativeActivity: 130-04', , AdministrativeTime, 0.00, 0.00, 0.00, 0.00, 0.00, 0.00, 0.00, 0.00} Berryl

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  • Operator== in derived class never gets called.

    - by Robin Welch
    Can someone please put me out of my misery with this? I'm trying to figure out why a derived operator== never gets called in a loop. To simplify the example, here's my Base and Derived class: class Base { // ... snipped bool operator==( const Base& other ) const { return name_ == other.name_; } }; class Derived : public Base { // ... snipped bool operator==( const Derived& other ) const { return ( static_cast<const Base&>( *this ) == static_cast<const Base&>( other ) ? age_ == other.age_ : false ); }; Now when I instantiate and compare like this ... Derived p1("Sarah", 42); Derived p2("Sarah", 42); bool z = ( p1 == p2 ); ... all is fine. Here the operator== from Derived gets called, but when I loop over a list, comparing items in a list of pointers to Base objects ... list<Base*> coll; coll.push_back( new Base("fred") ); coll.push_back( new Derived("sarah", 42) ); // ... snipped // Get two items from the list. Base& obj1 = **itr; Base& obj2 = **itr2; cout << obj1.asString() << " " << ( ( obj1 == obj2 ) ? "==" : "!=" ) << " " << obj2.asString() << endl; Here asString() (which is virtual and not shown here for brevity) works fine, but obj1 == obj2 always calls the Base operator== even if the two objects are Derived. I know I'm going to kick myself when I find out what's wrong, but if someone could let me down gently it would be much appreciated.

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  • Swig C++ Lua Pass class by reference

    - by Jeremy
    I don't know why I'm having a hard time with this. All I want to do is this: class foo { public: foo(){} ~foo(){} float a,b; }; class foo2 { public: foo2(){} foo2(const foo &f){*this = f;} ~foo2(){} void operator=(const foo& f){ x = f.a; y = f.b; } float x,y; }; /* Usage(cpp): foo f; foo2 f2(f); //or using the = operator f2 = f; */ The problem I'm having is that, after swigging this code, I can't figure out how to make the lua script play nice. /* Usage(lua) f = example.foo() f2 = example.foo2(f) --error */ The error I get is "Wrong arguments for overloaded function 'new_Foo2'": Possible c/c++ prototypes are: foo2() foo2(foo const &) The same thing happens if I try and use do f2 = f. As I understand it everything is stored as a pointer so I did try adding an additional constructor that took a pointer to foo but to no avail.

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  • Retain, alloc, properties ... Topic to make your Obj-c life easier !

    - by gotye
    Hey everyone, The more I code, the more I get lost ... so I decided to create a topic entirely dedicated to the memory management for me (and others) not to waste hours understanding obj-c basics ... I'll update it as new questions are asked ! Okay below is some examples : // myArray is property (retain) myArray = otherArray; //myArray isn't a property myArray = otherArray; //myArray is a property (retain) myArray = [[NSArray alloc] init]; //myArray isn't a property myArray = [[NSArray alloc] init]; Could you explain to me what happens in every cases ? And especially the number 3 ;) Thanks for the time. Gotye.

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