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• How do I query through a many-to-many relationship using NHibernate Criteria and Lambda Extensions?

  - by Brian Kendig

  In my database I have a Person table and an Event table (parties, meetings, &c.). This many-to-many relationship is represented through an Invitation table. Each Person can have many Invitations. Each Event can also have many Invitations. If I want a list of Events to which a Person is invited, I can use this HQL query: IQuery query = Session.CreateQuery("SELECT i.Event from Invitation i where i.Person = :p"); query.SetParameter("p", person); return query.List<Person>(); How would I write this query with NHibernate criteria and Lambda Extensions?

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• NHibernate - define where condition

  - by t.kehl

  Hi. In my application the user can defines search-conditions. He can choose a column, set an operator (equals, like, greater than, less or equal than, etc.) and give in the value. After the user clicks on a button and the application should do a search on the database with the condition. I use NHibernate and ask me now, what is the efficientest way to do this with NHibernate. Should I create a query with it like (Column=Name, Operator=Like, Value=%John%) var a = session.CreateCriteria<Customer>(); a.Add(Restrictions.Like("Name", "%John%")); return a.List<Customer>(); Or should I do this with HQL: var q = session.CreateQuery("from Customer where " + where); return q.List<Customer >(); Or is there a more bether solution? Thanks for your help. Best Regards, Thomas

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• Select an entity according to a list of associated entities

  - by Maverickch

  I have the following database schema : Two tables, books and tags, with n-m relationship. Books - Tags We can have for example the book 1, with tags {A,B,C}, and book 2, with tags {A}. I would like to select the books according to a list of tags. For example : selected tags list : {A,B} - book 1 My idea was to use the MINUS SQL function, to subtract book tags list to the selected tags list, and return the book if the list was empty. Unfortunately, this SQL function is not supported by HQL. Any idea about that ?

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• Hibernate - join un related objects

  - by CuriousMind

  I have a requirement, wherein I have to join two unrelated objects using Hibernate HQL. Here is the sample POJO class class Product{ int product_id; String name; String description; } and Class Item{ int item_id; String name; String description; int quantity; int product_id; //Note that there is no composed product object. } Now I want to perform a query like select * from Product p left outer join Item i on p.product_id = i.item_id I want a multidimensional array as an output of this query so that I can have separate instances of Product and Item, instead of one composed in another. Is there any way to do this in Hibernate?

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• Table per subclass inheritance relationship: How to query against the Parent class without loading a

  - by Arthur Ronald F D Garcia

  Suppose a Table per subclass inheritance relationship which can be described bellow (From wikibooks.org - see here) Notice Parent class is not abstract @Entity @Inheritance(strategy=InheritanceType.JOINED) public class Project { @Id private long id; // Other properties } @Entity @Table(name="LARGEPROJECT") public class LargeProject extends Project { private BigDecimal budget; } @Entity @Table(name="SMALLPROJECT") public class SmallProject extends Project { } I have a scenario where i just need to retrieve the Parent class. Because of performance issues, What should i do to run a HQL query in order to retrieve the Parent class and just the Parent class without loading any subclass ???

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• Getting changes in one column of an historical table

  - by Javi

  Hello, I have a table which stores historical data. It's mapped to an Entity with the following fields (I use JPA with Hibernate implementation): @Entity @Table(name="items_historical") public class ItemHistory{ private Integer id; private Date date; @Enumerated(EnumType.ORDINAL) private StatusEnum status @ManyToOne(optional=false) private User user; @ManyToOne(optional=false) private Item item; } public enum StatusEnum { OK, BAD,...//my status } In every row I store historical data of another table. I need to get the list of the changes on "status" column: the status, the date and the previous status on a specified item (It would be good as well getting the status and date when status was changed). I don't know if this is possible by using HQL. Thanks.

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• ClassCastException in iterating list returned by Query using Hibernate Query Language

  - by Tushar Paliwal

  I'm beginner in hibernate.I'm trying a simplest example using HQL but it generates exception at line 25 ClassCastException when i try to iterate list.When i try to cast the object returned by next() methode of iterator it generates the same problem.I could not identify the problem.Kindly give me solution of the problem. Employee.java package one; import javax.persistence.Entity; import javax.persistence.Id; @Entity public class Employee { @Id private Long id; private String name; public Long getId() { return id; } public void setId(Long id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } public Employee(Long id, String name) { super(); this.id = id; this.name = name; } public Employee() { } } Main2.java package one; import java.util.Iterator; import java.util.List; import org.hibernate.Query; import org.hibernate.Session; import org.hibernate.SessionFactory; import org.hibernate.Transaction; import org.hibernate.cfg.Configuration; public class Main2 { public static void main(String[] args) { SessionFactory sf=new Configuration().configure().buildSessionFactory(); Session s1=sf.openSession(); Query q=s1.createQuery("from Employee "); Transaction tx=s1.beginTransaction(); List l=q.list(); Iterator itr=l.iterator(); while(itr.hasNext()) { Object obj[]=(Object[])itr.next();//Line 25 for(Object temp:obj) { System.out.println(temp); } } tx.commit(); s1.close(); sf.close(); } }

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• How to query across many-to-many association in NHibernate?

  - by Splash

  I have two entities, Post and Tag. The Post entity has a collection of Tags which represents a many-to-many join between the two (that is, each post can have any number of tags and each tag can be associated with any number of posts). I am trying to retrieve all Posts which have a given tag. However, I seem to be unable to get this query right. I essentially want something which means the same as the following pseudo-HQL: from Posts p where p.Tags contains (from Tags t where t.Name = :tagName) order by p.DateTime The only thing I've found which even approaches this is a post by Ayende. However, his approach requires the entity on the other side (in my case, Tag) to have a collection showing the other end of the many-to-many. I don't have this and don't really wish to have it. I find it hard to believe this can't be done. What am I missing? My entities & mappings look like this (simplified): public class Post { public virtual int Id { get; set; } public virtual string Title { get; set; } private IList<Tag> tags = new List<Tag>(); public virtual IEnumerable<Tag> Tags { get { return tags; } } public virtual void AddTag(Tag tag) { this.tags.Add(tag); } } public class PostMap : ClassMap<Post> { public PostMap() { Id(x => x.Id).GeneratedBy.HiLo("99"); Map(x => x.Title); HasManyToMany(x => x.Tags); } } // ---- public class Tag { public virtual int Id { get; set; } public virtual string Name { get; set; } } public class TagMap : ClassMap<Tag> { public TagMap () { Id(x => x.Id).GeneratedBy.HiLo("99"); Map(x => x.Name).Unique(); } }

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• Problem with NHibernate

  - by Bernard Larouche

  I am trying to get a list of Products that share the Category. NHibernate returns no product which is wrong. Here is my Criteria API method : public IList<Product> GetProductForCategory(string name) { return _session.CreateCriteria(typeof(Product)) .CreateCriteria("Categories") .Add(Restrictions.Eq("Name", name)) .List<Product>(); } Here is my HQL method : public IList<Product> GetProductForCategory(string name) { return _session.CreateQuery("select from Product p, p.Categories.elements c where c.Name = :name").SetString("name",name).List<Product>(); } Both methods return no product when they should return 2 products. Here is the Mapping for the Product class : <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" assembly="CBL.CoderForTraders.DomainModel" namespace="CBL.CoderForTraders.DomainModel"> <class name="Product" table="Products" > <id name="_persistenceId" column="ProductId" type="Guid" access="field" unsaved-value="00000000-0000-0000-0000-000000000000"> <generator class="assigned" /> </id> <version name="_persistenceVersion" column="RowVersion" access="field" type="int" unsaved-value="0" /> <property name="Name" column="ProductName" type="String" not-null="true"/> <property name="Price" column="BasePrice" type="Decimal" not-null="true" /> <property name="IsTaxable" column="IsTaxable" type="Boolean" not-null="true" /> <property name="DefaultImage" column="DefaultImageFile" type="String"/> <bag name="Descriptors" table="ProductDescriptors"> <key column="ProductId" foreign-key="FK_Product_Descriptors"/> <one-to-many class="Descriptor"/> </bag> <bag name="Categories" table="Categories_Products" > <key column="ProductId" foreign-key="FK_Products_Categories"/> <many-to-many class="Category" column="CategoryId"></many-to-many> </bag> <bag name="Orders" generic="true" table="OrderProduct" > <key column="ProductId" foreign-key="FK_Products_Orders"/> <many-to-many column="OrderId" class="Order" /> </bag> </class> </hibernate-mapping> And finally the mapping for the Category class : <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" assembly="CBL.CoderForTraders.DomainModel" namespace="CBL.CoderForTraders.DomainModel" default-access="field.camelcase-underscore" default-lazy="true"> <class name="Category" table="Categories" > <id name="_persistenceId" column="CategoryId" type="Guid" access="field" unsaved-value="00000000-0000-0000-0000-000000000000"> <generator class="assigned" /> </id> <version name="_persistenceVersion" column="RowVersion" access="field" type="int" unsaved-value="0" /> <property name="Name" column="Name" type="String" not-null="true"/> <property name="IsDefault" column="IsDefault" type="Boolean" not-null="true" /> <property name="Description" column="Description" type="String" not-null="true" /> <many-to-one name="Parent" column="ParentID"></many-to-one> <bag name="SubCategories" inverse="true"> <key column="ParentID" foreign-key="FK_Category_ParentCategory" /> <one-to-many class="Category"/> </bag> <bag name="Products" table="Categories_Products"> <key column="CategoryId" foreign-key="FK_Categories_Products" /> <many-to-many column="ProductId" class="Product"></many-to-many> </bag> </class> </hibernate-mapping> Can you see what could be the problem ?

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• Big Data – Data Mining with Hive – What is Hive? – What is HiveQL (HQL)? – Day 15 of 21

  - by Pinal Dave

  In yesterday’s blog post we learned the importance of the operational database in Big Data Story. In this article we will understand what is Hive and HQL in Big Data Story. Yahoo started working on PIG (we will understand that in the next blog post) for their application deployment on Hadoop. The goal of Yahoo to manage their unstructured data. Similarly Facebook started deploying their warehouse solutions on Hadoop which has resulted in HIVE. The reason for going with HIVE is because the traditional warehousing solutions are getting very expensive. What is HIVE? Hive is a datawarehouseing infrastructure for Hadoop. The primary responsibility is to provide data summarization, query and analysis. It  supports analysis of large datasets stored in Hadoop’s HDFS as well as on the Amazon S3 filesystem. The best part of HIVE is that it supports SQL-Like access to structured data which is known as HiveQL (or HQL) as well as big data analysis with the help of MapReduce. Hive is not built to get a quick response to queries but it it is built for data mining applications. Data mining applications can take from several minutes to several hours to analysis the data and HIVE is primarily used there. HIVE Organization The data are organized in three different formats in HIVE. Tables: They are very similar to RDBMS tables and contains rows and tables. Hive is just layered over the Hadoop File System (HDFS), hence tables are directly mapped to directories of the filesystems. It also supports tables stored in other native file systems. Partitions: Hive tables can have more than one partition. They are mapped to subdirectories and file systems as well. Buckets: In Hive data may be divided into buckets. Buckets are stored as files in partition in the underlying file system. Hive also has metastore which stores all the metadata. It is a relational database containing various information related to Hive Schema (column types, owners, key-value data, statistics etc.). We can use MySQL database over here. What is HiveSQL (HQL)? Hive query language provides the basic SQL like operations. Here are few of the tasks which HQL can do easily. Create and manage tables and partitions Support various Relational, Arithmetic and Logical Operators Evaluate functions Download the contents of a table to a local directory or result of queries to HDFS directory Here is the example of the HQL Query: SELECT upper(name), salesprice FROM sales; SELECT category, count(1) FROM products GROUP BY category; When you look at the above query, you can see they are very similar to SQL like queries. Tomorrow In tomorrow’s blog post we will discuss about very important components of the Big Data Ecosystem – Pig. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Big Data, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL

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• NHibernate Query across multiple tables

  - by Dai Bok

  I am using NHibernate, and am trying to figure out how to write a query, that searchs all the names of my entities, and lists the results. As a simple example, I have the following objects; public class Cat { public string name {get; set;} } public class Dog { public string name {get; set;} } public class Owner { public string firstname {get; set;} public string lastname {get; set;} } Eventaully I want to create a query , say for example, which and returns all the pet owners with an name containing "ted", OR pets with a name containing "ted". Here is an example of the SQL I want to execute: SELECT TOP 10 d.*, c.*, o.* FROM owners AS o INNER JOIN dogs AS d ON o.id = d.ownerId INNER JOIN cats AS c ON o.id = c.ownerId WHERE o.lastname like '%ted%' OR o.firstname like '%ted%' OR c.name like '%ted%' OR d.name like '%ted%' When I do it using Criteria like this: var criteria = session.CreateCriteria<Owner>() .Add( Restrictions.Disjunction() .Add(Restrictions.Like("FirstName", keyword, MatchMode.Anywhere)) .Add(Restrictions.Like("LastName", keyword, MatchMode.Anywhere)) ) .CreateCriteria("Dog").Add(Restrictions.Like("Name", keyword, MatchMode.Anywhere)) .CreateCriteria("Cat").Add(Restrictions.Like("Name", keyword, MatchMode.Anywhere)); return criteria.List<Owner>(); The following query is generated: SELECT TOP 10 d.*, c.*, o.* FROM owners AS o INNER JOIN dogs AS d ON o.id = d.ownerId INNER JOIN cats AS c ON o.id = c.ownerId WHERE o.lastname like '%ted%' OR o.firstname like '%ted%' AND d.name like '%ted%' AND c.name like '%ted%' How can I adjust my query so that the .CreateCriteria("Dog") and .CreateCriteria("Cat") generate an OR instead of the AND? thanks for your help.

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• Nhibernate: distinct results in second level Collection

  - by Miguel Marques

  I have an object model like this: class EntityA { ... IList<EntityB> BList; ... } class EntityB { ... IList<EntityC> CList; } I have to fetch all the colelctions (Blist in EntityA and CList in EntityB), because if they all will be needed to make some operations, if i don't eager load them i will have the select n+1 problem. So the query was this: select a from EntityA a left join fetch a.BList b left join fetch b.CList c The fist problem i faced with this query, was the return of duplicates from the DB, i had EntityA duplicates, because of the left join fetch with BList. A quick read through the hibernate documentation and there were some solutions, first i tried the distinct keyword that supposelly wouldn't replicate the SQL distinct keyword except in some cases, maybe this was one of those cases because i had a SQL error saying that i cannot select distict text columns (column [Observations] in EntityA table). So i used one of the other solutions: query.SetResultTransformer(new DistinctRootEntityResultTransformer()); This worked fine. But the result of the operations were still not passing the tests. I checked further and i found out that now there were duplicates of EntityB, because of the left join fetch with CList. The question is, how can i use the distinct in a second level collection? I searched and i only find solutions for the root entity's direct child collection, but never for the second level child collections... Thank you for your time

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• How to implement paging in NHibernate with a left join query

  - by Gabe Moothart

  I have an NHibernate query that looks like this: var query = Session.CreateQuery(@" select o from Order o left join o.Products p where (o.CompanyId = :companyId) AND (p.Status = :processing) order by o.UpdatedOn desc") .SetParameter("companyId", companyId) .SetParameter("processing", Status.Processing) .SetResultTransformer(Transformers.DistinctRootEntity); var data = query.List<Order>(); I want to implement paging for this query, so I only return x rows instead of the entire result set. I know about SetMaxResults() and SetFirstResult(), but because of the left join and DistinctRootEntity, that could return less than x Orders. I tried "select distinct o" as well, but the sql that is generated for that (using the sqlserver 2008 dialect) seems to ignore the distinct for pages after the first one (I think this is the problem). What is the best way to accomplish this?

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• Hibernate Query Language Problem

  - by Sarang

  Well, I have implemented a distinct query in hibernate. It returns me result. But, while casting the fields are getting interchanged. So, it generates casting error. What should be the solution? As an example, I do have database, "ProjectAssignment" that has three fields, aid, pid & userName. I want all distinct userName data from this table. I have applied query : select distinct userName, aid, pid from ProjectAssignment Whereas the ProjectAssignment.java file has the fields in sequence aid, pid & userName. Now, here the userName is first field in output. So, Casting is not getting possible. Also, query : select aid, pid, distinct userName from ProjectAssignment is not working. What is the proper query for the same ? Or what else the solution ? The code is as below : System Utilization Service Bean Method where I have to retrieve data : public List<ProjectAssignment> getProjectAssignments() { projectAssignments = ProjectAssignmentHelper.getAllResources(); //Here comes the error return projectAssignments; } ProjectAssignmentHelper from where I fetch Data : package com.hibernate; import java.util.List; import org.hibernate.Query; import org.hibernate.Session; public class ProjectAssignmentHelper { public static List<ProjectAssignment> getAllResources() { List<ProjectAssignment> projectMasters; Session session = HibernateUtil.getSessionFactory().openSession(); Query query = session.createQuery("select distinct aid, pid, userName from ProjectAssignment"); projectMasters = (List<ProjectAssignment>) query.list(); session.close(); return projectMasters; } } Hibernate Data Bean : package com.hibernate; public class ProjectAssignment implements java.io.Serializable { private short aid; private String pid; private String userName; public ProjectAssignment() { } public ProjectAssignment(short aid) { this.aid = aid; } public ProjectAssignment(short aid, String pid, String userName) { this.aid = aid; this.pid = pid; this.userName = userName; } public short getAid() { return this.aid; } public void setAid(short aid) { this.aid = aid; } public String getPid() { return this.pid; } public void setPid(String pid) { this.pid = pid; } public String getUserName() { return this.userName; } public void setUserName(String userName) { this.userName = userName; } } Error : For input string: "userName" java.lang.NumberFormatException: For input string: "userName" at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48) at java.lang.Integer.parseInt(Integer.java:447) at java.lang.Integer.parseInt(Integer.java:497) at javax.el.ArrayELResolver.toInteger(ArrayELResolver.java:375) at javax.el.ArrayELResolver.getValue(ArrayELResolver.java:195) at javax.el.CompositeELResolver.getValue(CompositeELResolver.java:175) at com.sun.faces.el.FacesCompositeELResolver.getValue(FacesCompositeELResolver.java:72) at com.sun.el.parser.AstValue.getValue(AstValue.java:116) at com.sun.el.parser.AstValue.getValue(AstValue.java:163) at com.sun.el.ValueExpressionImpl.getValue(ValueExpressionImpl.java:219) at com.sun.faces.facelets.el.TagValueExpression.getValue(TagValueExpression.java:102) at javax.faces.component.ComponentStateHelper.eval(ComponentStateHelper.java:190) at javax.faces.component.ComponentStateHelper.eval(ComponentStateHelper.java:178) at javax.faces.component.UICommand.getValue(UICommand.java:218) at org.primefaces.component.commandlink.CommandLinkRenderer.encodeMarkup(CommandLinkRenderer.java:113) at org.primefaces.component.commandlink.CommandLinkRenderer.encodeEnd(CommandLinkRenderer.java:54) at javax.faces.component.UIComponentBase.encodeEnd(UIComponentBase.java:878) at org.primefaces.renderkit.CoreRenderer.renderChild(CoreRenderer.java:70) at org.primefaces.renderkit.CoreRenderer.renderChildren(CoreRenderer.java:54) at org.primefaces.component.datatable.DataTableRenderer.encodeTable(DataTableRenderer.java:525) at org.primefaces.component.datatable.DataTableRenderer.encodeMarkup(DataTableRenderer.java:407) at org.primefaces.component.datatable.DataTableRenderer.encodeEnd(DataTableRenderer.java:193) at javax.faces.component.UIComponentBase.encodeEnd(UIComponentBase.java:878) at org.primefaces.renderkit.CoreRenderer.renderChild(CoreRenderer.java:70) at org.primefaces.renderkit.CoreRenderer.renderChildren(CoreRenderer.java:54) at org.primefaces.component.tabview.TabViewRenderer.encodeContents(TabViewRenderer.java:198) at org.primefaces.component.tabview.TabViewRenderer.encodeMarkup(TabViewRenderer.java:130) at org.primefaces.component.tabview.TabViewRenderer.encodeEnd(TabViewRenderer.java:48) at javax.faces.component.UIComponentBase.encodeEnd(UIComponentBase.java:878) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1620) at javax.faces.render.Renderer.encodeChildren(Renderer.java:168) at javax.faces.component.UIComponentBase.encodeChildren(UIComponentBase.java:848) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1613) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1616) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1616) at com.sun.faces.application.view.FaceletViewHandlingStrategy.renderView(FaceletViewHandlingStrategy.java:380) at com.sun.faces.application.view.MultiViewHandler.renderView(MultiViewHandler.java:126) at com.sun.faces.lifecycle.RenderResponsePhase.execute(RenderResponsePhase.java:127) at com.sun.faces.lifecycle.Phase.doPhase(Phase.java:101) at com.sun.faces.lifecycle.LifecycleImpl.render(LifecycleImpl.java:139) at javax.faces.webapp.FacesServlet.service(FacesServlet.java:313) at org.apache.catalina.core.StandardWrapper.service(StandardWrapper.java:1523) at org.apache.catalina.core.ApplicationDispatcher.doInvoke(ApplicationDispatcher.java:802) at org.apache.catalina.core.ApplicationDispatcher.invoke(ApplicationDispatcher.java:664) at org.apache.catalina.core.ApplicationDispatcher.processRequest(ApplicationDispatcher.java:497) at org.apache.catalina.core.ApplicationDispatcher.doDispatch(ApplicationDispatcher.java:468) at org.apache.catalina.core.ApplicationDispatcher.dispatch(ApplicationDispatcher.java:364) at org.apache.catalina.core.ApplicationDispatcher.forward(ApplicationDispatcher.java:314) at org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:783) at org.apache.jsp.welcome_jsp._jspService(welcome_jsp.java from :59) at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:109) at javax.servlet.http.HttpServlet.service(HttpServlet.java:847) at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:406) at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:483) at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:373) at javax.servlet.http.HttpServlet.service(HttpServlet.java:847) at org.apache.catalina.core.StandardWrapper.service(StandardWrapper.java:1523) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:279) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:188) at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:641) at com.sun.enterprise.web.WebPipeline.invoke(WebPipeline.java:97) at com.sun.enterprise.web.PESessionLockingStandardPipeline.invoke(PESessionLockingStandardPipeline.java:85) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:185) at org.apache.catalina.connector.CoyoteAdapter.doService(CoyoteAdapter.java:332) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:233) at com.sun.enterprise.v3.services.impl.ContainerMapper.service(ContainerMapper.java:165) at com.sun.grizzly.http.ProcessorTask.invokeAdapter(ProcessorTask.java:791) at com.sun.grizzly.http.ProcessorTask.doProcess(ProcessorTask.java:693) at com.sun.grizzly.http.ProcessorTask.process(ProcessorTask.java:954) at com.sun.grizzly.http.DefaultProtocolFilter.execute(DefaultProtocolFilter.java:170) at com.sun.grizzly.DefaultProtocolChain.executeProtocolFilter(DefaultProtocolChain.java:135) at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:102) at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:88) at com.sun.grizzly.http.HttpProtocolChain.execute(HttpProtocolChain.java:76) at com.sun.grizzly.ProtocolChainContextTask.doCall(ProtocolChainContextTask.java:53) at com.sun.grizzly.SelectionKeyContextTask.call(SelectionKeyContextTask.java:57) at com.sun.grizzly.ContextTask.run(ContextTask.java:69) at com.sun.grizzly.util.AbstractThreadPool$Worker.doWork(AbstractThreadPool.java:330) at com.sun.grizzly.util.AbstractThreadPool$Worker.run(AbstractThreadPool.java:309) at java.lang.Thread.run(Thread.java:619)

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• Working with Hibernate Queries

  - by jschoen

  I am new to hibernate queries, and trying to get a grasp on how everything works. I am using Hibernate 3 with Netbeans 6.5. I have a basic project set up and have been playing around with how to do everything. I started with essentially a search query. Where the user can enter values into one or more fields. The table would be Person with the columns first_name, middle_name, last_name for the sake of the example. The first way I found was to have a method that took firstName, middleName, and lastName as parameters: Session session = HibernateUtil.getSessionFactory().getCurrentSession(); Transaction tx = session.beginTransaction(); String query = "from Person where (first_name = :firstName or :firstName is null) "+ "and (middle_name = :middleName or :middleName is null) " "and (last_name = :lastname or :lastName is null)"; Query q = session.createQuery(query); q.setString("firstName", firstName); q.setString("middleName", middleName); q.setString("lastName", lastName); List<Person> results = (List<Person>) q.list(); This did not sit well with me, since it seemed like I should not have to write that much, and well, that I was doing it wrong. So I kept digging and found another way: Session session = HibernateUtil.getSessionFactory().getCurrentSession(); Transaction tx = session.beginTransaction(); Criteria crit = session.createCriteria(Person.class); if (firstName != null) { crit.add(Expression.ge("firstName", firstName); } if (middleName != null) { crit.add(Expression.ge("middleName", middleName); } if (lastName != null) { crit.add(Expression.ge("lastName", lastName); } List<Person> results = (List<Person>) crit.list(); So what I am trying to figure out is which way is the preferred way for this type of query? Criteria or Query? Why? I am guessing that Criteria is the preferred way and you should only use Query when you need to write it by hand for performance type reasons. Am I close?

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• [Hibernate Mapping] relationship set between table and mapping table to use joins.

  - by Matthew De'Loughry

  Hi guys, I have two table a "Module" table and a "StaffModule" I'm wanting to display a list of modules by which staff are present on the staffmodule mapping table. I've tried from Module join Staffmodule sm with ID = sm.MID with no luck, I get the following error Path Expected for join! however I thought I had the correct join too allow this but obviously not can any one help StaffModule HBM <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated Apr 26, 2010 9:50:23 AM by Hibernate Tools 3.2.1.GA --> <hibernate-mapping> <class name="Hibernate.Staffmodule" schema="WALK" table="STAFFMODULE"> <composite-id class="Hibernate.StaffmoduleId" name="id"> <key-many-to-one name="mid" class="Hibernate.Module"> <column name="MID"/> </key-many-to-one> <key-property name="staffid" type="int"> <column name="STAFFID"/> </key-property> </composite-id> </class> </hibernate-mapping> and Module.HBM <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated Apr 26, 2010 9:50:23 AM by Hibernate Tools 3.2.1.GA --> <hibernate-mapping> <class name="Hibernate.Module" schema="WALK" table="MODULE"> <id name="id" type="int"> <column name="ID"/> <generator class="assigned"/> </id> <property name="modulename" type="string"> <column length="50" name="MODULENAME"/> </property> <property name="teacherid" type="int"> <column name="TEACHERID" not-null="true"/> </property> </class> hope thats enough information! and thanks in advance.

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• How to eager fetch a child collection while joining child collection entities to an association

  - by ShaneC

  Assuming the following fictional layout Dealership has many Cars has a Manufacturer I want to write a query that says get me a Dealership with a Name of X and also get the Cars collection but use a join against the manufacturer when you do so. I think this would require usage of ICriteria. I'm thinking something like this.. var dealershipQuery = Session.CreateCriteria< Dealership>("d") .Add(Restrictions.InsenstiveLike("d.Name", "Foo")) .CreateAlias("d.Cars", "c") .SetFetchMode("d.Cars", FetchMode.Select) .SetFetchMode("c.Manufacturer", FetchMode.Join) .UniqueResult< Dealership>(); But the resulting query looks nothing like I would have expected. I'm starting to think a DetachedCriteria may be required somewhere but I'm not sure. Thoughts?

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• Load data from CSV to mySQL database Java+hibernate+spring

  - by mona

  I am trying to load a CSV file in to mySQL database using Java+Hibernate+Spring. I am using the following query in the DAO to help me load in to the database: entityManager.createQuery("LOAD DATA INFILE :fileName INTO TABLE test").setParameter("fileName", "C:\\samples\\test\\abcd.csv").executeUpdate(); I got some idea to use this from http://dev.mysql.com/doc/refman/5.1/en/load-data.html and how to import a csv file into a mysql from an hibernate+spring application? But I am getting the error: java.lang.IllegalArgumentException: node to traverse cannot be null! Please help! Thanks

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• Beautify Integer values for comparing as strings

  - by Zahra

  Hi. For some reason I need to enter my integer values to database as string, then I want to run a query on them and compare those integers as strings. Is there any way to beautify integer numbers (between 1 and 1 US billion as an example) so I can compare them as strings? Thanks in advance.

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• Selecting one object from a one-to-many relationship in Hibernate

  - by Nick Thomson

  I have two tables: Job job_id, <other data> Job_Link job_link_id, job_id, start_timestamp, end_timestamp, <other data> There may be multiple records in Job_Link specifying the same job_id with the start_timestamp and end_timestamps to indicate when those records are considered "current", it is guaranteed that start_timestamp and end_timestamp will not overlap. We have entities for both the Job and Job_Link tables and defining a one-to-many relationship to load all the job_links wouldn't be a problem. However we'd like to avoid that and have a single job_link item in the Job entity that will contain only the "current" Job_Link object. Is there any way to achive that?

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• How to map a property for HQL usage only (in Hibernate)?

  - by ManBugra

  i have a table like this one: id | name | score mapped to a POJO via XML with Hibernate. The score column i only need in oder by - clauses in HQL. The value for the score column is calculated by an algorithm and updated every 24 hours via SQL batch process (JDBC). So i dont wanna pollute my POJO with properties i dont need at runtime. For a single column that may be not a problem, but i have several different score columns. Is there a way to map a property for HQL use only? For example like this: <property name="score" type="double" ignore="true"/> so that i still can do this: from Pojo p order by p.score but my POJO implementation can look like this: public class Pojo { private long id; private String name; // ... } No Setter for score provided or property added to implementation. using the latest Hibernate version for Java.

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• ClassNotFoundException (HqlToken) when running in WebLogic

  - by dave

  I have a .war file for an application that normally runs fine in Jetty. I'm trying to port the application to run in WebLogic, but at startup I'm getting these exceptions: ERROR:Foo - Error in named query: findBar org.hibernate.QueryException: ClassNotFoundException: org.hibernate.hql.ast.HqlToken [from Bar] at org.hibernate.hql.ast.HqlLexer.panic(HqlLexer.java:80) at antlr.CharScanner.setTokenObjectClass(CharScanner.java:340) at org.hibernate.hql.ast.HqlLexer.setTokenObjectClass(HqlLexer.java:54) at antlr.CharScanner.<init>(CharScanner.java:51) at antlr.CharScanner.<init>(CharScanner.java:60) at org.hibernate.hql.antlr.HqlBaseLexer.<init>(HqlBaseLexer.java:56) at org.hibernate.hql.antlr.HqlBaseLexer.<init>(HqlBaseLexer.java:53) at org.hibernate.hql.antlr.HqlBaseLexer.<init>(HqlBaseLexer.java:50) ... What's the best way to fix this? I'm using Hibernate 3.3.1.GA and WebLogic 10.3.2.0.

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• How to perform a non-polymorphic HQL query in Hibernate?

  - by Eli Acherkan

  Hi all, I'm using Hibernate 3.1.1, and in particular, I'm using HQL queries. According to the documentation, Hibernate's queries are polymorphic: A query like: from Cat as cat returns instances not only of Cat, but also of subclasses like DomesticCat. How can I query for instances of Cat, but not of any of its subclasses? I'd like to be able to do it without having to explicitly mention each subclass. I'm aware of the following options, and don't find them satisfactory: Manually filtering the instances after the query, OR: Manually adding a WHERE clause on the discriminator column. It would make sense for Hibernate to allow the user to decide whether a query should be polymorphic or not, but I can't find such an option. Thanks in advance!

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• Can I write this query using the criteria API or am I stuck with HQL?

  - by Yannis

  hi all. I have the following query which I would like to write using the criteria api of NH. select status, count(1) from (select distinct Status, post_id from post_statistics) tbl group by status each post_id can exist multiple times in post_statistics e.g. id post_id status 1 1 open 1 1 edit 1 1 open 1 2 open so the query should return the following results: status count open 2 edit 1 thx in advance.

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• how to find difference between two timestamp using hibernate query language

  - by Shekhar

  Hello I am trying to write an hql query which gives me the number of hours between two timestamp. So, far i am unable to do this. I have used hql hour function but that does not work if the timestamp corresponds to different date. Please provide any input. My hql query is select count(*) from com.xxx.Request as request where request.id = :id and hour(current_timestamp - request.lastEventDate) :delay Thanks Shekhar

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