Search Results

Search found 19093 results on 764 pages for 'max path'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 5/764 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Path erased in Debian

    - by Lyon83
    I'm trying to deploy a rails app in Debian, using Apache/Passenger. I was trying to fox a problem with some GEMs and in the process I put executed this in console: export PATH=/var/lib/gems/1.8/bin/:${vendor/cache} Now my path environmental variable is gone, or at least its content. My server is running under Debian 6. Is there a way to recover my path info? Or at least can someone point me where to find the file where that variable i s stored? Some help please. This is a BIG problem for me. Thanks in advance!

    Read the article

  • Is there a way to display navmesh agent path in Unity?

    - by Antoine Guillien
    I'm currently making a prototype for a game I plan to develop. As far as I did, I managed to set up the navigation mesh and my navmeshagents. I would like to display the path they are following when setDestination() is fired. I did some researches but didn't find anything about it. EDIT 1 : So I instantiate an empty object with a LineRenderer and I have a line bewteen my agent and the destination. Still I've not all the points when the path has to avoid an obstacle. Furthermore, I wonder if the agent.path does reflect the real path that the agent take as I noticed that it actually follow a "smoothier" path. Here is the code so far : GameObject container = new GameObject(); container.transform.parent = agent.gameObject.transform; LineRenderer ligne = container.AddComponent<LineRenderer>(); ligne.SetColors(Color.white,Color.white); ligne.SetWidth(0.1f,0.1f); //Get def material ligne.gameObject.renderer.material.color = Color.white; ligne.gameObject.renderer.material.shader = Shader.Find("Sprites/Default"); ligne.gameObject.AddComponent<LineScript>(); ligne.SetVertexCount(agent.path.corners.Length+1); int i = 0; foreach(Vector3 v in p.corners) { ligne.SetPosition(i,v); //Debug.Log("position agent"+g.transform.position); //Debug.Log("position corner = "+v); i++; } ligne.SetPosition(p.corners.Length,agent.destination); ligne.gameObject.tag = "ligne"; So How can I get the real coordinates my agent is going to walk throught ?

    Read the article

  • Positioning an image inside an ImageView width max height and max width set

    - by andern
    I have an ImageView with max height and max width both set to 100. The figure below is clearly not a square, but you can use your imagination ;) Figure 1: +----------------------------------------------+ ¦ ImageView +--------------+ ¦ ¦ ¦ ¦ ¦ ¦ ¦ Actual image ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ +--------------+ ¦ +----------------------------------------------+ Anyway, If I try to set a BitMap to the ImageView that does not have a ratio of 1:1, the image is positioned like pictured in Figure 1. What I want is for the picture to be placed to the left inside the ImageView like pictured in Figure 2 below. Figure 2: +----------------------------------------------+ ¦--------------+ ¦ ¦ ¦ ¦ ¦ Actual image ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦--------------+ ¦ +----------------------------------------------+ You can see my ImageView in XML below. maxHeight, maxWidth and adjustViewBounds are set during runtime. <ImageView android:id="@+id/someImage" android:layout_alignParentLeft="true" android:layout_below="@+id/textName" android:layout_height="wrap_content" android:layout_width="wrap_content" android:paddingRight="4dp" /> This is in a RelativeLayout if it makes any difference.

    Read the article

  • Positioning an image inside an ImageView with max height and max width set

    - by andern
    I have an ImageView with max height and max width both set to 100. The figure below is clearly not a square, but you can use your imagination ;) Figure 1: +----------------------------------------------+ ¦ ImageView +--------------+ ¦ ¦ ¦ ¦ ¦ ¦ ¦ Actual image ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ +--------------+ ¦ +----------------------------------------------+ Anyway, If I try to set a BitMap to the ImageView that does not have a ratio of 1:1, the image is positioned like pictured in Figure 1. What I want is for the picture to be placed to the left inside the ImageView like pictured in Figure 2 below. Figure 2: +----------------------------------------------+ ¦--------------+ ¦ ¦ ¦ ¦ ¦ Actual image ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦ ¦--------------+ ¦ +----------------------------------------------+ You can see my ImageView in XML below. maxHeight, maxWidth and adjustViewBounds are set during runtime. <ImageView android:id="@+id/someImage" android:layout_alignParentLeft="true" android:layout_below="@+id/textName" android:layout_height="wrap_content" android:layout_width="wrap_content" android:paddingRight="4dp" /> This is in a RelativeLayout if it makes any difference.

    Read the article

  • Give the mount point of a path

    - by Charles Stewart
    The following, very non-robust shell code will give the mount point of $path: (for i in $(df|cut -c 63-99); do case $path in $i*) echo $i;; esac; done) | tail -n 1 Is there a better way to do this? Postscript This script is really awful, but has the redeeming quality that it Works On My Systems. Note that several mount points may be prefixes of $path. Examples On a Linux system: cas@txtproof:~$ path=/sys/block/hda1 cas@txtproof:~$ for i in $(df -a|cut -c 57-99); do case $path in $i*) echo $i;; esac; done| tail -1 /sys On a Mac osx system cas local$ path=/dev/fd/0 cas local$ for i in $(df -a|cut -c 63-99); do case $path in $i*) echo $i;; esac; done| tail -1 /dev Note the need to vary cut's parameters, because of the way df's output differs: indeed, awk is better. Answer It looks like munging tabular output is the only way within the shell, but df /dev/fd/impossible | tail -1 | awk '{ print $NF}' is a big improvement on what I had. Note two differences in semantics: firstly, df $path insists that $path names an existing file, the script I had above doesn't care; secondly, there are no worries about dereferncing symlinks. It's not difficult to write Python code to do the job.

    Read the article

  • A good file path builder library for C#?

    - by Igor Brejc
    System.IO.Path in .NET is notoriously clumsy to work with. In my various projects I keep encountering the same usage scenarios which require repetitive, verbose and thus error-prone code snippets that use Path.Combine, Path.GetFileName, Path.GetDirectoryName, String.Format, etc. Scenarios like: changing the extension for a given file name changing the directory path for a given file name building a file path using string formatting (like "Package{0}.zip") building a path without resorting to using hard-coded directory delimiters like \ (since they don't work on Linux on Mono) etc etc Before starting to write my own PathBuilder class or something similar: is there a good (and proven) open-source implementation of such a thing in C#?

    Read the article

  • Linux Exim set return-path header automaticly using from header

    - by solomongaby
    Hello, I use Exim on a Centos distribution and have some problems with the mail sending. In order to make all the email pass the spam filters the "Return-path" and "Sender" headers have to be attached to each email. What should I do in order to have "Return-path" and "Sender" headers added by Exim to be exactly the same as the "From" header created by my mail client ? Thanks

    Read the article

  • I need to create a volume/symbolic link from a UNC Path

    - by Sebas
    I have a workstation with Windows XP and I need to make a symbolic link or mount a UNC Path like a local Drive. I need the same behavior that produces M-Daemon tools when you mount an .iso File but with a remote directory. This is because I have a software client that perform several task but only with local drives and directorys. The remote UNC path is a NAS server, thats the why I need to perform all the tasks from a workstations. Thanks a lot!

    Read the article

  • Updating the $PATH for running an command through SSH with LDAP user account

    - by Guillaume Bodi
    Hi all, I am setting up a Mac OSX 1.6 server to host Git repositories. As such we need to push commits to the server through SSH. The server has only an admin account and uses a user list from a LDAP server. Now, since it is accessing the server through a non interactive shell, git operations are not able to complete since git executables are not in the default path. As the users are network users, they do not have a local home folder. So I cannot use a ~/.bashrc and the like solution. I browsed over several articles here and there but could not get it working in a nice and clean setup. Here are the infos on the methods I gathered so far: I could update the default PATH environment to include the git executables folder. However, I could not manage to do it successfully. Updating /etc/paths didn't change anything and since it's not an interactive shell, /etc/profile and /etc/bashrc are ignored. From the ssh manpage, I read that a BASH_ENV variable can be set to get an optional script to be executed. However I cannot figure how to set it system wide on the server. If it needs to be set up on the client machine, this is not an acceptable solution. If someone has some info on how it is supposed to be done, please, by all means! I can fix this problem by creating a .bashrc with PATH correction in the system root (since all network users would start here as they do not have home). But it just feels wrong. Additionally, if we do create a home folder for an user, then the git command would fail again. I can install a third party application to set up hooks on the login and then run a script creating a home directory with the necessary path corrections. This smells like a backyard tinkering and duct tape solution. I can install a small script on the server and ForceCommand the sshd to this script on login. This script will then look for a command to execute ($SSH_ORIGINAL_COMMAND) and trigger a login shell to run this command, or just trigger a regular login shell for an interactive session. The full details of this method can be found here: http://marc.info/?l=git&m=121378876831164 The last one is the best method I found so far. Any suggestions on how to deal with this properly?

    Read the article

  • How do I create a symbolic link to a UNC Path in Windows XP

    - by Sebas
    I have a workstation with Windows XP and I need to make a symbolic link or mount a UNC Path like a local Drive. I need the same behavior that produces M-Daemon tools when you mount an .iso File but with a remote directory. This is because I have a software client that perform several task but only with local drives and directorys. The remote UNC path is a NAS server, thats the why I need to perform all the tasks from a workstations.

    Read the article

  • What should be in the path variable?

    - by Paperflyer
    Recently, I had some programming problem. Some files could not be found. I checked the PATH variable and guess what? It was empty except for Quicktime. I guess Quicktime somehow managed to delete my path. Great. So. What should be in there? (Win7 x64)

    Read the article

  • django select max field from mysql when column is varchar

    - by doza
    Hi, Using Django 1.1, I am trying to select the maximum value from a varchar column (in MySQL.) The data stored in the column looks like: 9001 9002 9017 9624 10104 11823 (In reality, the numbers are much bigger than this.) This worked until the numbers incremented above 10000: Feedback.objects.filter(est__pk=est_id).aggregate(sid=Max('sid')) Now, that same line would return 9624 instead of 11823. I'm able to run a query directly in the DB that gives me what I need, but I can't figure out the best way to do this in Django. The query would be: select max(sid+0) from Feedback; Any help would be much appreciated. Thanks!

    Read the article

  • SQL Max Group By Query Help

    - by Hcabnettek
    Hi All, I have a quick question. How do I select the two values I need in one query? Currently I'm doing this, which works fine, but it's obviously running two queries when one should do the trick. I tried MAX(columnA) and GROUP BY ColumnB, but that returns multiple row. I only want one row returned. DECLARE @biID bigint , @dtThreshold DateTime SELECT @biID = MAX(biID) FROM tbPricingCalculationCount WITH (NOLOCK) SELECT @dtThreshold = dtDateTime FROM tbPricingCalculationCount WITH (NOLOCK) WHERE biID = @biID I would like both those variables to be set correctly in one query. How can I do that? Thanks, ~ck

    Read the article

  • How to get MAX value of a version-number (varchar) column in T-SQL

    - by Ogre Psalm33
    I have a table defined like this: Column: Version Message Type: varchar(20) varchar(100) ---------------------------------- Row 1: 2.2.6 Message 1 Row 2: 2.2.7 Message 2 Row 3: 2.2.12 Message 3 Row 4: 2.3.9 Message 4 Row 5: 2.3.15 Message 5 I want to write a T-Sql query that will get message for the MAX version number, where the "Version" column represents a software version number. I.e., 2.2.12 is greater than 2.2.7, and 2.3.15 is greater than 2.3.9, etc. Unfortunately, I can't think of an easy way to do that without using CHARINDEX or some complicated other split-like logic. Running this query: SELECT MAX(Version) FROM my_table will yield the erroneous result: 2.3.9 When it should really be 2.3.15. Any bright ideas that don't get too complex?

    Read the article

  • Unable to get defined path in 'source' type on AIX node

    - by haris
    hi all, I am trying to create a set of users on my AIX node and trying to get their authorized_keys which are already hosted on my server with name like, 'myuser_id_dsa.pub'. Currently i am managing 2 nodes (1. SLES 2. AIX). I defined the 'source' file paths in 2 separate contexts in fileserver.conf; [AIX] path myfiles/users/ssh/ allow *.another.mydomain.com [SLES] path myfiles/users/keys/ssh/ allow *.mydomain.com but when I run puppet then it ended successfully on my SLES node but encountered failure on AIX; with following err; /* Could not describe /AIX/myuser_id_rsa.pub: Fileserver module 'AIX' not mounted*/ in my code i have defined the 'source' with $filserver variable as: case $operatingsystem { "AIX": { $fileserver = "AIX" } default: { $fileserver = "SLES" } } file { "${home}/${username}/.ssh/authorized_keys": source = "puppet:///$fileserver/${username}_is_dsa.pub", ... ... } why AIX is not able to get the source path from my fileserver.conf while SLES is running absolutely fine? and how can I do it? I have to run similar configuration across different servers so I can only deal it with case statement. looking forward for your help Thanks

    Read the article

  • Symlinks are inaccessible by their full path on OS X

    - by Computer Guru
    Hi, I have symlinks pointing to applications placed in /usr/local/bin which is in the path. However, I can't run these applications from other folders. Even more weird, I can't access them by the full path to the symlink. [mqudsi@iqudsi:Desktop/EasyBCD]$ echo $path (03-26 13:42) /opt/local/bin /opt/local/sbin /usr/local/bin /usr/local/sbin/ /usr/local/CrossPack-AVR/bin /usr/bin /bin /usr/sbin /sbin /usr/local/bin /usr/X11/bin [mqudsi@iqudsi:local/bin]$ ls -l /usr/local/bin (03-26 13:47) total 24280 -rwxr-xr-x 1 mqudsi wheel 18464 May 14 2009 ascii-xfr -rwxr-xr-x 1 mqudsi wheel 12567 Mar 25 04:50 brew -rwxr-xr-x 1 mqudsi wheel 17768 Dec 11 12:41 bsdiff -rwxr-xr-x 1 mqudsi wheel 43024 Mar 28 2009 dumpsexp -rwxr-xr-x 1 mqudsi wheel 280 Sep 10 2009 easy_install -rwxr-xr-x 1 mqudsi wheel 288 Sep 10 2009 easy_install-2.6 -rwxr-xr-x 1 mqudsi wheel 39696 Apr 5 2009 fuse_wait lrwxr-xr-x 1 mqudsi wheel 29 Mar 25 04:53 git -> ../Cellar/git/1.7.0.3/bin/git [mqudsi@iqudsi:local/bin]$ /usr/local/bin/git (03-26 13:47) zsh: no such file or directory: /usr/local/bin/git Clearly the link is there, but I'm not able to get it to it :S

    Read the article

  • Installing Ruby 1.9.3 OSX 10.7.4 breaks after altering PATH

    - by R V
    I was having trouble installing ruby 1.9.3-p194 from ruby 1.8.7 on my mac osx 10.7.4. I have was trying to fix my homebrew after running "brew doctor" and got the message of "/usr/bin occurs before /usr/local/bin This means that system-provided programs will be used instead of those provided by Homebrew. The following tools exist at both paths: c++-4.2 cpp-4.2 erb g++-4.2 gcc-4.2 gcov-4.2 gem i686-apple-darwin11-cpp-4.2.1 i686-apple-darwin11-g++-4.2.1 i686-apple-darwin11-gcc-4.2.1 irb rake rdoc ri ruby testrb" I fixed it by entering the following, which I found on another stackoverflow answer: export PATH="/usr/local/bin:/usr/local/sbin:~/bin$PATH" Lo and behold! when I typed that ruby updates to 1.9.3-p194. Ruby files seem to compile and run just fine. However, afterward, my navigation around terminal is messed up severely. For instance I can't do the command "open example_file.html" and have the file pop up in Chrome, instead I get the error: "-bash: open: command not found" Also, when I change directory, I get an error, inputting "$ cd desktop" yields the output, "-bash: dirname: command not found" but the directory does then changes... strange. When I exit out of a terminal window all this resets. I'm back to Ruby 1.8.7, have to use the PATH command again to update to 1.9.3, command line navigation gets broken again. Any guidance on how to remedy so I can use 1.9.3-p194 and also have normal terminal navigation would be greatly appreciated.

    Read the article

  • System.IO.Path or equivelent use with Unix paths

    - by pm_2
    Is it possible to either use the System.IO.Path class, or some similar object to format a unix style path, providing similar functionality to the PATH class? For example, I can do: Console.WriteLine(Path.Combine("c:\\", "windows")); Which shows: "C:\\windows" But is I try a similar thing with forward slashes (/) it just reverses them for me. Console.WriteLine(Path.Combine("/server", "mydir")); Which shows: "/server\\mydir"

    Read the article

  • SQL SERVER – Find Max Worker Count using DMV – 32 Bit and 64 Bit

    - by pinaldave
    During several recent training courses, I found it very interesting that Worker Thread is not quite known to everyone despite the fact that it is a very important feature. At some point in the discussion, one of the attendees mentioned that we can double the Worker Thread if we double the CPU (add the same number of CPU that we have on current system). The same discussion has triggered this quick article. Here is the DMV which can be used to find out Max Worker Count SELECT max_workers_count FROM sys.dm_os_sys_info Let us run the above query on my system and find the results. As my system is 32 bit and I have two CPU, the Max Worker Count is displayed as 512. To address the previous discussion, adding more CPU does not necessarily double the Worker Count. In fact, the logic behind this simple principle is as follows: For x86 (32-bit) upto 4 logical processors  max worker threads = 256 For x86 (32-bit) more than 4 logical processors  max worker threads = 256 + ((# Procs – 4) * 8) For x64 (64-bit) upto 4 logical processors  max worker threads = 512 For x64 (64-bit) more than 4 logical processors  max worker threads = 512+ ((# Procs – 4) * 8) In addition to this, you can configure the Max Worker Thread by using SSMS. Go to Server Node >> Right Click and Select Property >> Select Process and modify setting under Worker Threads. According to Book On Line, the default Worker Thread settings are appropriate for most of the systems. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL System Table, SQL Tips and Tricks, T SQL, Technology Tagged: SQL DMV

    Read the article

  • XElement.Load("~/App_Data/file.xml") Could not find a part of the path

    - by mahdiahmadirad
    hi everybody, I am new in LINQtoXML. I want to use XElement.Load("") Method. but the compiler can't find my file. can you help me to write correct path for my XML file? Note that: I defined a Class in App_Code and I want to use the XML file data in one of methods and my XML file Located in App_Data. settings = XElement.Load("App_Data/AppSettings.xml"); i cant Use Request.ApplicationPath and Page.MapPath() or Server.MapPath() to get the physical path for my file because i am not in a class Inherited form Page class. Brief error Message: *Could not find a part of the path 'C:\Program Files\Microsoft Visual Studio 9.0\Common7\IDE\App_Data\AppSettings.xml'*. you see the path compiled is fully different from my project path(G:\MyProjects\ASP.net Projects\VistaComputer\Website\App_Data\AppSettings.xml) Full error Message is here: System.IO.DirectoryNotFoundException was unhandled by user code Message="Could not find a part of the path 'C:\\Program Files\\Microsoft Visual Studio 9.0\\Common7\\IDE\\App_Data\\AppSettings.xml'." Source="mscorlib" StackTrace: at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize) at System.Xml.XmlDownloadManager.GetStream(Uri uri, ICredentials credentials) at System.Xml.XmlUrlResolver.GetEntity(Uri absoluteUri, String role, Type ofObjectToReturn) at System.Xml.XmlReader.Create(String inputUri, XmlReaderSettings settings, XmlParserContext inputContext) at System.Xml.XmlReader.Create(String inputUri, XmlReaderSettings settings) at System.Xml.Linq.XElement.Load(String uri, LoadOptions options) at System.Xml.Linq.XElement.Load(String uri) at ProductActions.Add(Int32 catId, String title, String price, String website, String shortDesc, String fullDesc, Boolean active, Boolean editorPick, String fileName, Stream image) in g:\MyProjects\ASP.net Projects\VistaComputer\Website\App_Code\ProductActions.cs:line 67 at CMS_Products_Operations.Button1_Click(Object sender, EventArgs e) in g:\MyProjects\ASP.net Projects\VistaComputer\Website\CMS\Products\Operations.aspx.cs:line 72 at System.Web.UI.WebControls.Button.OnClick(EventArgs e) at System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) at System.Web.UI.WebControls.Button.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) InnerException:

    Read the article

  • $PATH issues with OSX Lion

    - by Mikey
    I'm having some issues with running mysql from terminal: macmini:~ michael$ which mysql /Applications/XAMPP/xamppfiles/bin/mysql macmini:~ michael$ mysql -bash: /usr/local/mysql/bin/mysql: No such file or directory I had a previous installation at /usr/local/mysql/bin/mysql which no longer exists. My path variable is as follows: macmini:~ michael$ echo $PATH /usr/bin:/bin:/usr/sbin:/sbin:/Applications/XAMPP/xamppfiles/bin/:/usr/local/bin:/usr/X11/bin:/usr/local/MacGPG2/bin:/usr/texbin Dropping to root seems to function correctly: macmini:~ michael$ sudo bash Password: bash-3.2# mysql Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 66 Server version: 5.1.44 Source distribution Type 'help;' or '\h' for help. Type '\c' to clear the current input statement. mysql> I seem to have found the issue - but I'm not sure how to change or remove this alias macmini:~ michael$ type -a mysql mysql is aliased to `/usr/local/mysql/bin/mysql' mysql is /Applications/XAMPP/xamppfiles/bin/mysql mysql is /Applications/XAMPP/xamppfiles/bin/mysql

    Read the article

  • adding mongo to path

    - by Mike
    Bit of a noob question. I have downloaded MongoDb and installed it here /Users/mike/downloads/mongodb In order to start it, I then have to 'cd' into the 'bin' /Users/mike/downloads/mongodb/bin and run ./mongod (to start the database) and ./mongo (to start the mongo shell) The problem is that I can only work with python and ruby scripts using the mongo shell if I have those scripts stored in the same bin directory, and I don't think that's the ideal set up. Will exporting the path allow me to access mongo from outside the bin? For example, I would prefer to have my ruby scripts in /sites/ruby and be able to access mongo by starting ruby in /sites/ruby. If exporting to path is the solution, how do I do that. I'm using a mac

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >