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  • Algorithm to see if keywords exist inside a string

    - by rksprst
    Let's say I have a set of keywords in an array {"olympics", "sports tennis best", "tennis", "tennis rules"} I then have a large list (up to 50 at a time) of strings (or actually tweets), so they are a max of 140 characters. I want to look at each string and see what keywords are present there. In the case where a keyword is composed of multiple words like "sports tennis best", the words don't have to be together in the string, but all of them have to show up. I've having trouble figuring out an algorithm that does this efficiently. Do you guys have suggestions on a way to do this? Thanks! Edit: To explain a bit better each keyword has an id associated with it, so {1:"olympics", 2:"sports tennis best", 3:"tennis", 4:"tennis rules"} I want to go through the list of strings/tweets and see which group of keywords match. The output should be, this tweet belongs with keyword #4. (multiple matches may be made, so anything that matches keyword 2, would also match 3 -since they both contain tennis). When there are multiple words in the keyword, e.g. "sports tennis best" they don't have to appear together but have to all appear. e.g. this will correctly match: "i just played tennis, i love sports, its the best"... since this string contains "sports tennis best" it will match and be associated with the keywordID (which is 2 for this example).

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  • Finding character in String in Vector.

    - by SoulBeaver
    Judging from the title, I kinda did my program in a fairly complicated way. BUT! I might as well ask anyway xD This is a simple program I did in response to question 3-3 of Accelerated C++, which is an awesome book in my opinion. I created a vector: vector<string> countEm; That accepts all valid strings. Therefore, I have a vector that contains elements of strings. Next, I created a function int toLowerWords( vector<string> &vec ) { for( int loop = 0; loop < vec.size(); loop++ ) transform( vec[loop].begin(), vec[loop].end(), vec[loop].begin(), ::tolower ); that splits the input into all lowercase characters for easier counting. So far, so good. I created a third and final function to actually count the words, and that's where I'm stuck. int counter( vector<string> &vec ) { for( int loop = 0; loop < vec.size(); loop++ ) for( int secLoop = 0; secLoop < vec[loop].size(); secLoop++ ) { if( vec[loop][secLoop] == ' ' ) That just looks ridiculous. Using a two-dimensional array to call on the characters of the vector until I find a space. Ridiculous. I don't believe that this is an elegant or even viable solution. If it was a viable solution, I would then backtrack from the space and copy all characters I've found in a separate vector and count those. My question then is. How can I dissect a vector of strings into separate words so that I can actually count them? I thought about using strchr, but it didn't give me any epiphanies.

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  • Interpolating environment variables into a string in Ruby using String#scan

    - by robc
    I'm trying to interpolate environment variables into a string in Ruby and not having much luck. One of my requirements is to do something (log an error, prompt for input, whatever) if a placeholder is found in the initial string that has no matching environment variable. It looks like the block form of String#scan is what I need. Below is an irb session of my failed attempt. irb(main):014:0> raw_string = "need to replace %%FOO%% and %%BAR%% in here" => "need to replace %%FOO%% and %%BAR%% in here" irb(main):015:0> cooked_string << raw_string => "need to replace %%FOO%% and %%BAR%% in here" irb(main):016:0> raw_string.scan(/%%(.*?)%%/) do |var| irb(main):017:1* cooked_string.sub!("%%#{var}%%", ENV[var]) irb(main):018:1> done irb(main):019:1> end TypeError: cannot convert Array into String from (irb):17:in `[]' from (irb):17 from (irb):16:in `scan' from (irb):16 from :0 If I use ENV["FOO"] to manually interpolate one of those, it works fine. I'm banging my head against the desk. What am I doing wrong? Ruby is 1.8.1 on RHEL or 1.8.7 on Cygwin.

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  • Compare two String with MySQL

    - by Scorpi0
    Hi, I wan't to compare two strings in a SQL request so I can retrieve the best match, the aim is to propose to an operator the best zip code possible. For example, in France, we have Integer Zip code, so I made an easy request : SELECT * FROM myTable ORDER BY abs(zip_code - 75000) This request returns first the data closest of Paris. Unfortunatelly, United Kingdom have zip code like AB421RS, so my request can't do it. I see in SQL Server a function 'Difference' : http://www.java2s.com/Code/SQLServer/String-Functions/DIFFERENCEworkoutwhenonestringsoundssimilartoanotherstring.htm But I use MySQL.. Is there anyone who have a good idea to do the trick in one simple request ? PS : the Levenshtein Distance will not do it, as I really wan't to compare string like if they were number. ABCDEF have to be closer to AWXYZ than to ZBCDEF.

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  • How to format output using MATLAB's num2str

    - by Doresoom
    I'm trying to ouput an array of numbers as a string in MATLAB. I know this is easily done using num2str, but I wanted commas followed by a space to separate the numbers, not tabs. The array elements will at most have resolution to the tenths place, but most of them will be integers. Is there a way to format output so that unnecessary trailing zeros are left off? Here's what I've managed to put together: data=[2,3,5.5,4]; datastring=num2str(data,'%.1f, '); datastring=['[',datastring(1:end-1),']'] which gives the output: [2.0, 3.0, 5.5, 4.0] rather than: [2, 3, 5.5, 4] Any suggestions? EDIT: I just realized that I can use strrep to fix this by calling datastring=strrep(datastring,'.0','') but that seems even more kludgey than what I've been doing.

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  • How Do I Pull Info from String

    - by Russ Bradberry
    I am trying to pull dynamics from a load that I run using bash. I have gotten to a point where I get the string I want, now from this I want to pull certain information that can vary. The string that gets returned is as follows: Records: 2910 Deleted: 0 Skipped: 0 Warnings: 0 Each of the number can and will vary in length, but the overall structure will remain the same. What I want to do is be able to get these numbers and load them into some bash variables ie: RECORDS=?? DELETED=?? SKIPPED=?? WARNING=?? In regex I would do it like this: Records: (\d*?) Deleted: (\d*?) Skipped (\d*?) Warnings (\d*?) and use the 4 groups in my variables.

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  • Javascript string syntax to write SQL

    - by sebastien leblanc
    I am writing an SQL query as a Javascript string like that: SQLdetail = 'SELECT [Avis SAP], Avis.[Ordre SAP], [Date Appel], [Heur Appel], Client_List![Code Client], [Numero Passerelle], [Designation Appel], Ordre![Metier], Ordre!Repercussion, Ordre!Objet, Ordre![Profil Panne], Ordre!Cause, Ordre![Sommaire Correctif], Ordre![Statut]' SQLdetail += ' FROM (Avis' SQLdetail += ' LEFT JOIN Client_List ON Avis.[Numero Client] = Client_List.[Numero Client])' SQLdetail += ' LEFT JOIN Ordre ON Avis.[Ordre SAP] = Ordre.[Ordre SAP] WHERE Avis.[Date Appel] BETWEEN #' & DateOne & '# AND #' & DateTwo & '#;' alert('SQLdetail:' + SQLdetail) and the last SQLdetail += somehow returns "0". Am I missing something in the syntax that just turns the whole string to a 0?

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  • [Java] Cut <br/>-Tags from String end

    - by Robert M.
    Hello everybody, I am currently developing a Web-Application using Java EE where I'm using a Rich-Javascript-Editor (http://www.primefaces.org/showcase/ui/editor.jsf). As the user can easily add too many linebreaks that will be convertet to linebreak-tags, I need to remove all these Tags from the end of a String. Is there an elegant way of using Regex to accomplish this? An example String would be: "This is a test <b>bold</b><br/><br/>" Where obviously the last two tags have to be removed. Thank you in advance for any help Best Regards, Robert

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  • String Format for DateTime in C#

    - by SAMIR BHOGAYTA
    String Format for DateTime [C#] This example shows how to format DateTime using String.Format method. All formatting can be done also using DateTime.ToString method. Custom DateTime Formatting There are following custom format specifiers y (year), M (month), d (day), h (hour 12), H (hour 24), m (minute), s (second), f (second fraction), F (second fraction, trailing zeroes are trimmed), t (P.M or A.M) and z (time zone). Following examples demonstrate how are the format specifiers rewritten to the output. [C#] // create date time 2008-03-09 16:05:07.123 DateTime dt = new DateTime(2008, 3, 9, 16, 5, 7, 123); String.Format("{0:y yy yyy yyyy}", dt); // "8 08 008 2008" year String.Format("{0:M MM MMM MMMM}", dt); // "3 03 Mar March" month String.Format("{0:d dd ddd dddd}", dt); // "9 09 Sun Sunday" day String.Format("{0:h hh H HH}", dt); // "4 04 16 16" hour 12/24 String.Format("{0:m mm}", dt); // "5 05" minute String.Format("{0:s ss}", dt); // "7 07" second String.Format("{0:f ff fff ffff}", dt); // "1 12 123 1230" sec.fraction String.Format("{0:F FF FFF FFFF}", dt); // "1 12 123 123" without zeroes String.Format("{0:t tt}", dt); // "P PM" A.M. or P.M. String.Format("{0:z zz zzz}", dt); // "-6 -06 -06:00" time zone You can use also date separator / (slash) and time sepatator : (colon). These characters will be rewritten to characters defined in the current DateTimeForma­tInfo.DateSepa­rator and DateTimeForma­tInfo.TimeSepa­rator. [C#] // date separator in german culture is "." (so "/" changes to ".") String.Format("{0:d/M/yyyy HH:mm:ss}", dt); // "9/3/2008 16:05:07" - english (en-US) String.Format("{0:d/M/yyyy HH:mm:ss}", dt); // "9.3.2008 16:05:07" - german (de-DE) Here are some examples of custom date and time formatting: [C#] // month/day numbers without/with leading zeroes String.Format("{0:M/d/yyyy}", dt); // "3/9/2008" String.Format("{0:MM/dd/yyyy}", dt); // "03/09/2008" // day/month names String.Format("{0:ddd, MMM d, yyyy}", dt); // "Sun, Mar 9, 2008" String.Format("{0:dddd, MMMM d, yyyy}", dt); // "Sunday, March 9, 2008" // two/four digit year String.Format("{0:MM/dd/yy}", dt); // "03/09/08" String.Format("{0:MM/dd/yyyy}", dt); // "03/09/2008" Standard DateTime Formatting In DateTimeForma­tInfo there are defined standard patterns for the current culture. For example property ShortTimePattern is string that contains value h:mm tt for en-US culture and value HH:mm for de-DE culture. Following table shows patterns defined in DateTimeForma­tInfo and their values for en-US culture. First column contains format specifiers for the String.Format method. Specifier DateTimeFormatInfo property Pattern value (for en-US culture) t ShortTimePattern h:mm tt d ShortDatePattern M/d/yyyy T LongTimePattern h:mm:ss tt D LongDatePattern dddd, MMMM dd, yyyy f (combination of D and t) dddd, MMMM dd, yyyy h:mm tt F FullDateTimePattern dddd, MMMM dd, yyyy h:mm:ss tt g (combination of d and t) M/d/yyyy h:mm tt G (combination of d and T) M/d/yyyy h:mm:ss tt m, M MonthDayPattern MMMM dd y, Y YearMonthPattern MMMM, yyyy r, R RFC1123Pattern ddd, dd MMM yyyy HH':'mm':'ss 'GMT' (*) s SortableDateTi­mePattern yyyy'-'MM'-'dd'T'HH':'mm':'ss (*) u UniversalSorta­bleDateTimePat­tern yyyy'-'MM'-'dd HH':'mm':'ss'Z' (*) (*) = culture independent Following examples show usage of standard format specifiers in String.Format method and the resulting output. [C#] String.Format("{0:t}", dt); // "4:05 PM" ShortTime String.Format("{0:d}", dt); // "3/9/2008" ShortDate String.Format("{0:T}", dt); // "4:05:07 PM" LongTime String.Format("{0:D}", dt); // "Sunday, March 09, 2008" LongDate String.Format("{0:f}", dt); // "Sunday, March 09, 2008 4:05 PM" LongDate+ShortTime String.Format("{0:F}", dt); // "Sunday, March 09, 2008 4:05:07 PM" FullDateTime String.Format("{0:g}", dt); // "3/9/2008 4:05 PM" ShortDate+ShortTime String.Format("{0:G}", dt); // "3/9/2008 4:05:07 PM" ShortDate+LongTime String.Format("{0:m}", dt); // "March 09" MonthDay String.Format("{0:y}", dt); // "March, 2008" YearMonth String.Format("{0:r}", dt); // "Sun, 09 Mar 2008 16:05:07 GMT" RFC1123 String.Format("{0:s}", dt); // "2008-03-09T16:05:07" SortableDateTime String.Format("{0:u}", dt); // "2008-03-09 16:05:07Z" UniversalSortableDateTime

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  • Marshalling the value of a char* ANSI string DLL API parameter into a C# string

    - by Brian Biales
    For those who do not mix .NET C# code with legacy DLL's that use char* pointers on a regular basis, the process to convert the strings one way or the other is non-obvious. This is not a comprehensive article on the topic at all, but rather an example of something that took me some time to go find, maybe it will save someone else the time. I am utilizing a third party too that uses a call back function to inform my application of its progress.  This callback includes a pointer that under some circumstances is a pointer to an ANSI character string.  I just need to marshal it into a C# string variable.  Seems pretty simple, yes?  Well, it is, (as are most things, once you know how to do them). The parameter of my callback function is of type IntPtr, which implies it is an integer representation of a pointer.  If I know the pointer is pointing to a simple ANSI string, here is a simple static method to copy it to a C# string: private static string GetStringFromCharStar(IntPtr ptr) {     return System.Runtime.InteropServices.Marshal.PtrToStringAnsi(ptr); } The System.Runtime.InteropServices is where to look any time you are mixing legacy unmanaged code with your .NET application.

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  • Using HTML entities in XML Literals (Avner Aharoni)

    One of the common use-cases of XML literals is creating HTML. However, HTML entities cannot be used in XML literals since LINQ to XML directly supports only the Data type definitions (DTD) defined in the XML 1.0 spec. You can read more about it here. The workaround is to use the Unicode representation of the entity, although its not as readable as the HTML entities, the output is the same. Here are two examples of HTML entities from the XHTML spec :   Entity...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Using HTML entities in XML Literals (Avner Aharoni)

    One of the common use-cases of XML literals is creating HTML. However, HTML entities cannot be used in XML literals since LINQ to XML directly supports only the Data type definitions (DTD) defined in the XML 1.0 spec. You can read more about it here. The workaround is to use the Unicode representation of the entity, although its not as readable as the HTML entities, the output is the same. Here are two examples of HTML entities from the XHTML spec :   Entity...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • search and display string from group of string php

    - by zahir hussain
    hi i want to know how to search and display string from group of string like google display the word which we search... the following example from google search word is google books result Search and preview millions of books from libraries and publishers worldwide using Google Book Search. Discover a new favorite or unearth an old classic. i would like to do this type of one... thanks and advance

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  • How to find string in a string

    - by owca
    I somehow need to find the longest string in other string, so if string1 will be "Alibaba" and string2 will be "ba" , the longest string will be "baba". I have the lengths of strings, but what next ? char* fun(char* a, char& b) { int length1=0; int length2=0; int longer; int shorter; char end='\0'; while(a[i] != tmp) { i++; length1++; } int i=0; while(b[i] != tmp) { i++; length++; } if(dlug1 > dlug2){ longer = length1; shorter = length2; } else{ longer = length2; shorter = length1; } //logics here } int main() { char name1[] = "Alibaba"; char name2[] = "ba"; char &oname = *name2; cout << fun(name1, oname) << endl; system("PAUSE"); return 0; }

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  • string maniupulations, oops, how do I replace parts of a string

    - by Joe Gibson
    I am very new to python. Could someone explain how I can manipulate a string like this? This function receives three inputs: complete_fmla: has a string with digits and symbols but has no hyphens ('-') nor spaces. partial_fmla: has a combination of hyphens and possibly some digits or symbols, where the digits and symbols that are in it (other than hyphens) are in the same position as in the complete_formula. symbol: one character The output that should be returned is: If the symbol is not in the complete formula, or if the symbol is already in the partial formula, the function should return the same formula as the input partial_formula. If the symbol is in the complete_formula and not in the partial formula, the function should return the partial_formula with the symbol substituting the hyphens in the positions where the symbol is, in all the occurrences of symbol in the complete_formula. For example: generate_next_fmla (‘abcdeeaa’, ‘- - - - - - - - ’, ‘d’) should return ‘- - - d - - - -’ generate_next_fmla (‘abcdeeaa’, ‘- - - d - - - - ’, ‘e’) should return ‘- - - d e e - -’ generate_next_fmla (‘abcdeeaa’, ‘- - - d e e - - ’, ‘a’) should return ‘a - - d e e a a’ Basically, I'm working with the definition: def generate_next_fmla (complete_fmla, partial_fmla, symbol): Do I turn them into lists? and then append? Also, should I find out the index number for the symbol in the complete_fmla so that I know where to append it in the string with hyphens??

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  • Recursive String Function (Java)

    - by Jake Brooks
    Hi, I am trying to design a function that essentially does as follows: String s = "BLAH"; store the following to an array: blah lah bah blh bla bl ba bh ah al So basically what I did there was subtract each letter from it one at a time. Then subtract a combination of two letters at a time, until there's 2 characters remaining. Store each of these generations in an array. Hopefully this makes sense, Jake

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  • Problems removing a " from a string

    - by Graeme
    Hi, I have a string that ends with a " (quotation mark) that I want to get rid of. However, because XCode usually requires you to enter the text you wish to remove using stringByReplacingOccurrencesOfString in @"texttoremove" format, you can't use the quotation marks in the space as it thinks you are closing the text. Any ideas on how I can do it? Thanks.

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  • Filter string in C

    - by Paul Tarjan
    How can I filter a string in c? I want to remove anything that isn't [a-z0-9_]. int main(int argc, char ** argv) { char* name = argv[1]; // remove anything that isn't [a-z0-9_] printf("%s", name); }

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