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  • Play 2.0 framework - POST parameters

    - by user1452715
    I'm trying to POST parameters to Action, and wrote in the routes: Home page GET / controllers.Application.index() POST /login/name:/password: controllers.Application.login(name, password) and I have an Action public static Result login(String name, String password) { return ok(name + " " + password); } my form is <form action="/login" method="post"> <input name="name" type="text" id="name"> <input name="password" type="password" id="password"> <input type="submit" value="Login"> </form> and it doesn't work For request 'POST /login' [Missing parameter: name] what am i doing wrong?

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  • alternative to lag SQL command

    - by mahen
    I have a table which has a table like this. Month-----Book_Type-----sold_in_Dollars Jan----------A------------ 100 Jan----------B------------ 120 Feb----------A------------ 50 Mar----------A------------ 60 Mar----------B------------ 30 and so on I have to calculate the expected sales for each month and book type based on the last 2 months sales. So for March and type A it would be (100+50)/2 = 75 For March and type B it is 120/1 since no data for Feb is there. I was trying to use the lag function but it wouldn't work since there is data missing in a few rows. Any ideas on this?

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  • How to get the class of an input inside a jQuery each loop?

    - by Paul Atkins
    Hi, I have function which appends inputs inside a list item when a link is clicked. I then loop through these inputs using an each loop using the code below. It is working correctly as shown, however instead of using field.name I want to use the class of the input as the array key but when i try to do this the class is shown as undefined. Here is the code I am currently using: var values = {}; $.each($('li :input').serializeArray(), function(i, field) { values[field.name] = field.value; }); Here is the code I have inside the list item once I have appended the hidden inputs using jQuery append: <li><input type="hidden" name="group" class="group" value="2"/><input type="hidden" name="condition" class="condition" value="isany"/><input type="hidden" name="value" class="value" value="1,2"/></li> I can get the name attribute fine but class is always undefined. Could anybody help with this?

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  • Filter Phrase Query

    - by alsuelo
    I try to filter a phrase to make a search in my website i've this query, this code working with one word but when i type wit more than one isn't working becuase the print is without spaces. $phrase = $this->getState($this->context.".filter_phrase"); printf("Original string: %s\n", $phrase); if(!empty($phrase)) { $escaped = $db->escape($phrase, true); printf("Escaped string: %s\n", $escaped); $quoted = $db->quote("%" . $escaped . "%" , false); $query->where ('a.title LIKE ' .$quoted); } Example i type king and the output is king , when i type the king the output is theking, i want to know if exist any way to conserve the blank spaces.

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  • Unable to open my project in C# .Net

    - by user210332
    Hello sir/madam, I'm unable to open my project in visual studio2008. It was developed in C# .net by my friend. When i try to open any open it is showing the error as: "Could not find type 'LibrarySystem.ctrlSeparator'. Please make sure that the assembly that contains this type is referenced. If this type is a part of your development project, make sure that the project has been successfully built. " Also "The variable 'ctrlSeparator1' is either undeclared or was never assigned. " Please anyone help me about how to rectify this problem. With regards and waiting for your answer

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  • Background-image is not displaying in Firefox

    - by goa
    Strange thing happens. Background-image is not displaying in Firefox under some versions of WindowsXP and Windows Vista, but displays in Firefox under Mac OSX. It also displays in IE. This is CSS: .cherry_banner { background: url("library/media/images/cherry_banner_top.png") no-repeat; width: 276px; display:block; min-height:100px; padding-top: 13px; color: #fdfdfd; margin-bottom:20px; } .cherry_banner a { color: #fdfdfd; } .cherry_banner a:hover { text-decoration:underline; } .cherry_banner li { list-style-type:none; } .cherry_banner h2 { font-size: 18px; margin-bottom: 10px; } .chb_text1 { background: url("library/media/images/cherry_banner_pixel.png") repeat-y; } .chb_text2 { background: url("library/media/images/cherry_banner_bottom.gif") bottom no-repeat; padding: 4px 14px 24px 25px; } And this is html: <div id="linkcat-8" class="cherry_banner tpt"><div class="chb_text1"><div class="chb_text2"> <h2>??? ?????????</h2> <ul class='xoxo blogroll'> <li><a href="http://inveda.ru/jyotish/naksatra-calendar/">???????? ?????????? ?????????????? ????????? ????????????? ??? ?? 2010?.</a></li> </ul> </div></div></div> You can see on http://www.inveda.ru - right column - red banner.

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  • How to find the submit button in a specific form in jQuery

    - by leifg
    I try to get jQuery object of a submit button in a specific form (there are several forms on the same page). I managed to get the form element itself. It looks something like this: var curForm = curElement.parents("form"); The current Element has the context HTMLInputElement. The several techniques I tried to get the according submit element of the form: var curSubmit = curForm.find("input[type='submit']"); var curSubmit = $(curForm).find("input[type='submit']"); var curSubmit = curForm.find(":submit"); var curSubmit = $(curForm).find(":submit"); var curSubmit = $(curSubmit, "input[type='submit']"); the result is always the same (and very strange). The result that I get is the same element as "curElement". So how can I get the right submit button?

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  • Jquery - how i can get the video src value?

    - by 3gwebtrain
    i need to get the value of a video and need to change in to new value... for that i used this function: var video = $('#task2ResultVideo').get(0); console.log($(video).attr('poster')); // i am getting this $(video).attr('src',function(num,val){ console.log(num,val) // i am not getting this.. }) ? HTML: <video id="task2ResultVideo" autobuffer poster="img/task2-results-host-poster.jpg"> <source src="Video/webm/Task_2.4a_Host_treated.webm" type="video/webm" /> <source src="Video/ogv/Task_2.4a_Host_treated.theora.ogv" type="video/ogg" /> <source src="Video/MP4/Task_2.4a_Host_treated.mp4" type="video/mp4" /> </video>? But i am not able to get the values. what is wrong with my code? in case if i get the value how can i change the src? any suggestion please?

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  • Which code snipplets in PHP can create a input form, which creates a new set of data in my mysql dat

    - by smiyazaki
    I am using the Google Maps API with parts in javascript and others in PHP. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> Google Maps AJAX + mySQL/PHP Example // var iconBlue = new GIcon(); iconBlue.image = 'icon.png'; iconBlue.shadow = ''; iconBlue.iconSize = new GSize(19, 19); iconBlue.shadowSize = new GSize(22, 20); iconBlue.iconAnchor = new GPoint(6, 20); iconBlue.infoWindowAnchor = new GPoint(5, 1); var iconRed = new GIcon(); iconRed.image = 'icon.png'; iconRed.shadow = ''; iconRed.iconSize = new GSize(19, 19); iconRed.shadowSize = new GSize(22, 20); iconRed.iconAnchor = new GPoint(6, 20); iconRed.infoWindowAnchor = new GPoint(5, 1); var customIcons = []; customIcons["restaurant"] = iconBlue; customIcons["bar"] = iconRed; function load() { if (GBrowserIsCompatible()) { var map = new GMap2(document.getElementById("map")); map.setMapType(G_SATELLITE_MAP); map.addControl(new GSmallMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng(47.614495, -122.341861), 13); // Change this depending on the name of your PHP file GDownloadUrl("phpsqlajax_genxml.php", function(data) { var xml = GXml.parse(data); var markers = xml.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { var name = markers[i].getAttribute("name"); var address = markers[i].getAttribute("address"); var type = markers[i].getAttribute("type"); var point = new GLatLng(parseFloat(markers[i].getAttribute("lat")), parseFloat(markers[i].getAttribute("lng"))); var marker = createMarker(point, name, address, type); map.addOverlay(marker); } }); } } function createMarker(point, name, address, type) { var marker = new GMarker(point, customIcons[type]); var html = "<b>" + name + "</b> <br/>" + address; GEvent.addListener(marker, 'click', function() { marker.openInfoWindowHtml(html); }); return marker; } //]]> (I suppose the php will be called by "GDownloadUrl("phpsqlajax_genxml.php", function(data) { ..." in the javascript part of the sourcecode of phpsqlajax_map.htm) Now I need another php file and the code snipplets for it, which creates an input form where I can add some new locations to the google map. Following code is used to create the xml file here: http://detektors.de/maptest/phpsqlajax_genxml.php The next step would be, trying to make an plugin for wordpress that I could easily post a blog entry with a new location on the same map, which displays already some other locations stored in the mysql database. thanks! <?php require("phpsqlajax_dbinfo.php"); function parseToXML($htmlStr) { $xmlStr=str_replace('<','<',$htmlStr); $xmlStr=str_replace('','>',$xmlStr); $xmlStr=str_replace('"','"',$xmlStr); $xmlStr=str_replace("'",''',$xmlStr); $xmlStr=str_replace("&",'&',$xmlStr); return $xmlStr; } // Opens a connection to a MySQL server $connection=mysql_connect ($host, $username, $password); if (!$connection) { die('Not connected : ' . mysql_error()); } // Set the active MySQL database $db_selected = mysql_select_db($database, $connection); if (!$db_selected) { die ('Can\'t use db : ' . mysql_error()); } // Select all the rows in the markers table $query = "SELECT * FROM markers WHERE 1"; $result = mysql_query($query); if (!$result) { die('Invalid query: ' . mysql_error()); } header("Content-type: text/xml"); // Start XML file, echo parent node echo ''; // Iterate through the rows, printing XML nodes for each while ($row = @mysql_fetch_assoc($result)){ // ADD TO XML DOCUMENT NODE echo ''; } // End XML file echo ''; ?

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  • What's wrong with my If-statement to check uploaded file? (PHP)

    - by ggfan
    I am trying to test if the uploaded file is the image type I want. If it isn't a gif,jpeg, png, it should echo "Problem". But when I execute this code, it always says there's a problem. What's wrong with my if statement? $uploadfile_type=$_FILES['userfile']['type']; if ( ($uploadfile_type !='image/gif') || ($uploadfile_type !='image/jpeg') || ($uploadfile_type !='image/png')) { echo 'Problem: file is not a gif or jpeg or png!'; exit; } This code works when I am only checking one type of image. Ex: if($uploadfile_type !='image/gif') -- this statement would work but when I add a OR it doesn't.

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  • How can I figure out where all these extra sqlite3 selects are being generated in my rails app?

    - by radixhound
    I'm trying to figure out where a whole pile of extra queries are being generated by my rails app. I need some ideas on how to tackle it. Or, if someone can give me some hints, I'd be grateful. I get these: SQL (1.0ms) SELECT name FROM sqlite_master WHERE type = 'table' AND NOT name = 'sqlite_sequence' SQL (0.8ms) SELECT name FROM sqlite_master WHERE type = 'table' AND NOT name = 'sqlite_sequence' SQL (0.8ms) SELECT name FROM sqlite_master WHERE type = 'table' AND NOT name = 'sqlite_sequence' repeated over and over on every request to the DB (as much as 70 times for a single request) I tried installing a plugin that traced the source of the queries, but it really didn't help at all. I'm using the hobofields gem, dunno if that is what's doing it but I'm somewhat wedded to it at the moment Any tips on hunting down the source of these extra queries?

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  • Determine if FieldInfo is compiler generated backingfield

    - by Steffen
    The title pretty much says it all, how do I know if I'm getting a compiler generated backingfield for a {get; set;} property ? I'm running this code to get my FieldInfos: Class MyType { private int foo; public int bar {get; private set; } } Type type = TypeOf(MyType); foreach (FieldInfo fi in type.GetFields(BindingFlags.Instance | BindingFlags.Public | BindingFlags.DeclaredOnly | BindingFlags.NonPublic)) { // Gets both foo and bar, however bar is called <bar>k__backingfield. } so the question is, can I somehow detect that the FieldInfo is a backingfield, without relying on checking its name ? (Which is pretty undocumented, and could be broken in next version of the framework)

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  • crash happens when NSMutableArray is returned?

    - by senthilmuthu
    Hi, I have coded like that(that function will be called again and again), but the returned object gives "BAD ACCESS", the NSLog prints correct string, but toReturn sometimes(i called again and again) gives crashes..any help to alter this code - (NSMutableArray *)getAll:(NSString *)type { NSLog(@"Type: %@", type); NSMutableArray *toReturn = [[NSMutableArray alloc] initWithCapacity:0] ; rs = [db executeQuery:Query1]; while ([rs next]) { [toReturn addObject:[rs stringForColumn:@"Name"]]; NSLog(@"name: %@", [rs stringForColumn:@"Name"]); } [rs close]; return toReturn; }

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  • Usage of CRTP in a call chain

    - by fhw72
    In my widget library I'd like to implement some kind of call chain to initialize a user supplied VIEW class which might(!) be derived from another class which adds some additional functionality like this: #include <iostream> template<typename VIEW> struct App { VIEW view; void init() {view.initialize(); } }; template<typename DERIVED> struct SpecializedView { void initialize() { std::cout << "SpecializedView" << std::endl; static_cast<DERIVED*>(this)->initialize(); } }; struct UserView : SpecializedView<UserView> { void initialize() {std::cout << "UserView" << std::endl; } }; int _tmain(int argc, _TCHAR* argv[]) { // Cannot be altered to: App<SpecializedView<UserView> > app; App<UserView> app; app.init(); return 0; } Is it possible to achieve some kind of call chain (if the user supplied VIEW class is derived from "SpecializedView") such that the output will be: console output: SpecializedView UserView Of course it would be easy to instantiate variable app with the type derived from but this code is hidden in the library and should not be alterable. In other words: The library code should only get the user derived type as parameter.

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  • C++ difference of keywords 'typename' and 'class' in templates

    - by Mat
    For templates I have seen both declarations: template < typename T > And: template < class T > What's the difference? And what exactly do those keywords mean in the following example (taken from the German Wikipedia article about templates)? template < template < typename, typename > class Container, typename Type > class Example { Container< Type, std::allocator < Type > > baz; };

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  • Why do you sometimes need to write <typename T> instead of just <T> ?

    - by StackedCrooked
    I was reading the Wikipedia article on SFINAE and encountered following code sample: struct Test { typedef int Type; }; template < typename T > void f( typename T::Type ) {} // definition #1 template < typename T > void f( T ) {} // definition #2 void foo() { f< Test > ( 10 ); //call #1 f< int > ( 10 ); //call #2 without error thanks to SFINAE } Now I've actually written code like this before, and somehow intuitively I knew that I needed to type "typename T" instead of just "T". However, it would be nice to know the actual logic behind it. Anyone care to explain?

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  • JavaScript to enable "submit" button (doesn't work)

    - by Halst
    I need the button "submit" to be disabled unless JavaScript is on. I tried: 1. <input onLoad="this.disabled=false" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> 2. <input onLoad="this.removeAttribute("disabled");" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> 3. <input onLoad="document.getElementById("post-comment").removeAttribute("disabled");" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> Doesn't work. I'm new to JavaScript, but can't find answer on the net.

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  • Radio Button wont work in internet explorer but works fine in firefox

    - by Mo
    Hi i have HTML code like so: <div id="action_content" class="layout"> <input type="hidden" id="action_editing" value=""/> <div id="action_types"> <input type="radio" checked name="action_type" value="EmailActionDescription" onclick="toggle_action(this);"/><label>Email</label> <input type="radio" name="action_type" value="TicketActionDescription" onclick="toggle_action(this);"/><label>Ticket</label> </div> it works fine in firefox but dosent work in internet explorer. any ideas what it could be? the buttons basically display one of 2 options, a ticket or e mail, when clicking on the ticket it just dosent show. if you require any further information please let me know. thanks

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  • $_FILES empty on image upload

    - by zvir
    i need help, i'm programing some kind of catalogue and i have a page where clients can upload their logo or images. every page i make is included in index.php and my url looks like something like this www.url.com/index.php?s=upload where "upload" is name of upload.php file. when i create form on that upload.php file and submit it, $_FILES array is empty. echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php\" />\n"; echo "<input type=\"file\" name=\"image\">\n"; echo "<input type=\"hidden\" name=\"s\" value=\"upload\">\n"; echo "<input type=\"submit\" name=\"submit\" value=\"Spremi\">\n"; echo "</form>\n"; i tried everything and nothing works. $_POST items are returned but $_FILES are empty...

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  • How to convet DataTable to List on runtype with out existin class property [closed]

    - by shamim
    Work on VS2010 C#,Have one DataTable ,want to convert this DataTable to List Suppose: Table dt; On run time want to create similar field from a datatable and fill fields in List.There is no existing class for list properties. ListName=TableName List property name=Table column name List Property type=Table column type List items=Table rows Note: Recently work on EF.To fullfill my project requirement, need to give flexibility to use to input and execute ESQL at runtime .I don’t want to put this execute result on datatable or List ,want to put this result on list. List has no existing class and property,don’t want to convert DataTable on list Type:DataRow If have any query please ask,Thanks in advanced.

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  • GIT not functionnal on Mac OS X Lion?

    - by user1187727
    I am trying to use GIT to manage my computing projects. But all commands using GIT do not respond on my terminal. For example if I try git --version followed by entry keyboard typing, a blank line appear and wait until ever. If I type again the entry key on my keyboard the command line is again available but nothing appear. It's the same for all git function that I type. Do you have any solution or explanation for this ?

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  • How to add visible menu item from php code (drupal)

    - by uta
    I have a content type with important "created" date field. And I have a menu link (in primary links) which is link to page that shows list of all nodes of my content type. (http://example.com/mycontenttype) I want to have menu links (visible in primary links) to each year when nodes of my content type are displayed (http://example.com/mycontenttype/2010). And I want to add these menu links from mymodule_nodeapi function, when the node is creating and only if it has a "created" date of new year. I know that I can create a pathes in mymodule_menu function, but it doesn't create a visible menu item. (Maybe I can somehow set parent_link_id or something else to do it?)

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  • JavaScript not working with Chrome & Xampp!

    - by Anonymous
    Hi, I've been trying for a couple hours now to figure out why JavaScript wouldn't work. The code works, but here it is anyway. <script type="text/javascript"> function change(text) { document.f1.ta.value="Hi!"; } </script> <form name="f1"> <input type="textarea" id="ta"/> <input type="button" action='change("Hi!")'/> </form> When I click the button, it does nothing. When I write "document.f1.ta.value="Hi!";" in the Chrome's inspector console, it works. I am using XAMPP (for Windows) 1.7.3 Windows 7 Ultimate.

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  • JQuery validation based on class?

    - by Mark Kadlec
    I have a form that will have dynamically created elements, one of those will be of date type. There can also be many fields of this type on my form, all which must be validated. I am using a strongly typed view in Asp MVC, so the name will change based on various factors. What I would like to do is validate based on a class name instead, since that will be constant for that type of field. Ie: <%= Html.TextBox("questionAnswers[" + index + "].AnswerValue", qa.AnswerValue, new { @class = "DateTypeClass" })%> So then I would need JQuery validation based on the classname DateTypeClass versus the Name. Any ideas?

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