jQuery events .load(), .ready(), .unload()
- by Eric
Hi folks,
Just a simple question, for the jquery event. Are the .load(), .ready() and .unload() run in order when the DOM is loaded? The answer seems yes when I see the jQuery Documentation.
<script type="text/javascript">
$(window).load(function () {
// run code
initializeCode();
});
$(document).ready(function() {
//run code that MUST be after initialize
});
$(window).unload(function() {
Cleanup();
});
</script>
However, the code inside the .ready() is execute before the initializeCode(); is execute, so I feel really strange. And now I have to place my code inside the .onload() method and just after the initializeCode(); line, which means to be inside the .ready() block.
Could someone explain me more about this, as I am new to jQuery.
Thank you so much.
