Search Results

Search found 23568 results on 943 pages for 'select'.

Page 507/943 | < Previous Page | 503 504 505 506 507 508 509 510 511 512 513 514  | Next Page >

  • Custom order in Oracle PL/SQL

    - by Jasim
    I have an oracle query in which and i want the result to be in custom order 'SENIOR DIRECTOR', 'DIRECTOR', 'MANAGER', 'EMPLOYEE' which is from the field GRADE_DESCRIPTON. I am using the below query. However I am not getting the desired result The order of the result im getting is 'SENIOR DIRECTOR','MANAGER', DIRECTOR,'EMPLOYEE' SELECT DISTINCT GRADE_DESCRIPTION, HIRING_FORECATS.* FROM GRADE_MASTER left join IRING_FORECATS ON (HIRING_FORECATS.GRADE = GRADE_MASTER.GRADE_DESCRIPTION and HIRING_FORECATS.LOCATION = 'HO' ) order by decode(GRADE_MASTER.GRADE_DESCRIPTION, 'SENIOR DIRECTOR', 'DIRECTOR', 'MANAGER', 'EMPLOYEE') Any Suggestions??

    Read the article

  • Function returning MYSQL_ROW

    - by Gabe
    I'm working on a system using lots of MySQL queries and I'm running into some memory problems I'm pretty sure have to do with me not handling pointers right... Basically, I've got something like this: MYSQL_ROW function1() { string query="SELECT * FROM table limit 1;"; MYSQL_ROW return_row; mysql_init(&connection); // "connection" is a global variable if (mysql_real_connect(&connection,HOST,USER,PASS,DB,0,NULL,0)){ if (mysql_query(&connection,query.c_str())) cout << "Error: " << mysql_error(&connection); else{ resp = mysql_store_result(&connection); //"resp" is also global if (resp) return_row = mysql_fetch_row(resp); mysql_free_result(resp); } mysql_close(&connection); }else{ cout << "connection failed\n"; if (mysql_errno(&connection)) cout << "Error: " << mysql_errno(&connection) << " " << mysql_error(&connection); } return return_row; } And function2(): MYSQL_ROW function2(MYSQL_ROW row) { string query = "select * from table2 where code = '" + string(row[2]) + "'"; MYSQL_ROW retorno; mysql_init(&connection); if (mysql_real_connect(&connection,HOST,USER,PASS,DB,0,NULL,0)){ if (mysql_query(&connection,query.c_str())) cout << "Error: " << mysql_error(&conexao); else{ // My "debugging" shows me at this point `row[2]` is already fubar resp = mysql_store_result(&connection); if (resp) return_row = mysql_fetch_row(resp); mysql_free_result(resp); } mysql_close(&connection); }else{ cout << "connection failed\n"; if (mysql_errno(&connection)) cout << "Error : " << mysql_errno(&connection) << " " << mysql_error(&connection); } return return_row; } And main() is an infinite loop basically like this: int main( int argc, char* args[] ){ MYSQL_ROW row = NULL; while (1) { row = function1(); if(row != NULL) function2(row); } } (variable and function names have been generalized to protect the innocent) But after the 3rd or 4th call to function2, that only uses row for reading, row starts losing its value coming to a segfault error... Anyone's got any ideas why? I'm not sure the amount of global variables in this code is any good, but I didn't design it and only got until tomorrow to fix and finish it, so workarounds are welcome! Thanks!

    Read the article

  • SQL Server Update Group by

    - by Gerardo Abdo
    I'm trying to execute this on MS-SQL but returns me an error just at the Group by line update #temp Set Dos=Count(1) From Temp_Table2010 s where Id=s.Total and s.total in (Select Id from #temp) group by s.Total Do anyone knows how can I solve this problem having good performance.

    Read the article

  • MySQL, Coldfusion, Selecting records that were timestamped in the last 24 hours.

    - by nobosh
    With Coldfuson & MySQL - How to update the query to check for new entries that have a timestamp that occurs in the last 24 hours? Query: <cfquery name="caller.sel_BlogEntries" datasource="#request.db#"> SELECT blogentry.dateAdded, person.personName FROM blogentry INNER JOIN person ON blogentry.personID = person.personID WHERE blogentry.deleted = 'N' ORDER BY blogentry.dateAdded DESC </cfquery> blogentry.dateAdded is a MySql TimeStamp Thanks

    Read the article

  • I want to display the missing (non-matching) records

    - by Eric
    Is there a way to program the following SQL query SELECT dbo.Assets_Master.Serial_Number, dbo.Assets_Master.Account_Ident, dbo.Assets_Master.Disposition_Ident FROM dbo.Assets_Master LEFT OUTER JOIN dbo.Assets ON dbo.Assets_Master.Serial_Number = dbo.Assets.Serial_Number WHERE (dbo.Assets.Serial_Number IS NULL) in c# .net code using dataviews or data relation or something else? I have a spreadsheet of about 4k rows and a data table that should have the same records but if not I want to display the missing (non-matching) records from the table. Thanks, Eric

    Read the article

  • WordPress SQL Query on Category/Terms

    - by mroggle
    Hi, i am modifying a plugin slightly to meet my needs, and need to change this query to return post ID's of just one category. I know it has something to do with INNER JOIN, but cant get the query right. Here is the original query $query = "SELECT ID as PID FROM $wpdb->posts"; $results = $wpdb->get_results($querydetails,ARRAY_A);

    Read the article

  • Tootip steals mouse click

    - by deerchao
    I'm writing a custom TreeView from ScrollableControl. I decided to show tooltips when mouse is hover nodes with text too long to display. I find out when tooltips are shown, user would not be able to click the node to select it, because (I think) he's clicking the tooltip window, not my control. Is there any easy solutions? As I can see System.Windows.Forms.TreeView don't have this problem. Thanks!

    Read the article

  • VB.NET Use With keyword on existing object?

    - by ropstah
    Is it somehow possible to use the 'With' keyword on an existing object? I would like to do the following using LINQ to objects and can't seem to find a way: From m as Product in Me _ Select m With {.Match = m.Name.IndexOf(query)} _ Where m.Name.IndexOf(query) > 0

    Read the article

  • passing a scalar query result to coalesce

    - by Fakrudeen
    How can I pass the result from a scalar [single row, single value] query to coalesce? I am trying to pick the priority as (the biggest priority so far in the table) + 1. [0 if it is the first row.] create trigger priority_SuperRuleSamples before insert on SuperRuleSamples FOR EACH ROW SET NEW.Priority=coalesce(NEW.Priority, coalesce( select Priority from SuperRuleSamples order by Priority desc limit 1, -1 )+1 )

    Read the article

  • SQL - How to display the students with the same age?

    - by Cristian
    the code I wrote only tells me how many students have the same age. I want their names too... SELECT YEAR(CURRENT DATE-DATEOFBIRTH) AS AGE, COUNT(*) AS HOWMANY FROM STUDENTS GROUP BY YEAR(CURRENT DATE-DATEOFBIRTH); this returns something like this: AGE HOWMANY --- ------- 21 3 30 5 Thank you. TABLE STUDENTS COLUMNS: StudentID (primary key), Name(varchar), Firstname(varchar), Dateofbirth(varchar) I was thinking of maybe using the code above and somewhere add the function concat that will put the stundents' names on the same row as in

    Read the article

  • Connecting form to database errors

    - by Russell Ehrnsberger
    Hello I am trying to connect a page to a MySQL database for newsletter signup. I have the database with 3 fields, id, name, email. The database is named newsletter and the table is named newsletter. Everything seems to be fine but I am getting this error Notice: Undefined index: Name in C:\wamp\www\insert.php on line 12 Notice: Undefined index: Name in C:\wamp\www\insert.php on line 13 Here is my form code. <form action="insert.php" method="post"> <input type="text" value="Name" name="Name" id="Name" class="txtfield" onblur="javascript:if(this.value==''){this.value=this.defaultValue;}" onfocus="javascript:if(this.value==this.defaultValue){this.value='';}" /> <input type="text" value="Enter Email Address" name="Email" id="Email" class="txtfield" onblur="javascript:if(this.value==''){this.value=this.defaultValue;}" onfocus="javascript:if(this.value==this.defaultValue){this.value='';}" /> <input type="submit" value="" class="button" /> </form> Here is my insert.php file. <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="newsletter"; // Database name $tbl_name="newsletter"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // Get values from form $name=$_POST['Name']; $email=$_POST['Email']; // Insert data into mysql $sql="INSERT INTO $tbl_name(name, email)VALUES('$name', '$email')"; $result=mysql_query($sql); // if successfully insert data into database, displays message "Successful". if($result){ echo "Successful"; echo "<BR>"; echo "<a href='index.html'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?>

    Read the article

  • Is it possible to use multiple languages in .NET resource files?

    - by Gabe Brown
    We’ve got an interesting requirement that we’ll want to support multiple languages at runtime since we’re a service. If a user talks to us using Japanese or English, we’ll want to respond in the appropriate language. FxCop likes us to store our strings in resource files, but I was curious to know if there was an integrated way to select resource string at runtime without having to do it manually. Bottom Line: We need to be able to support multiple languages in a single binary. :)

    Read the article

  • filter duplicates in SQL join

    - by Will
    When using a SQL join, is it possible to keep only rows that have a single row for the left table? For example: select * from A, B where A.id = B.a_id; a1 b1 a2 b1 a2 b2 In this case, I want to remove all except the first row, where a single row from A matched exactly 1 row from B. I'm using MySQL.

    Read the article

  • Android number input with plus and minus sign.

    - by alaak
    Hi, I am developing in android and I would like an input field for numbers, where the user can select the correct number using the plus sign at the top and the minus sign at the bottom of the input field. I know this works for date picker. Is there some property or something similar to make this available for any integer number input field? Thanks

    Read the article

  • Yahoo Weather WebService

    - by Zakaria
    Hi, I'm trying to find a way to get some weather information with Yahoo Weather using Yahoo Query Language. As i'm living in France, in a city called Nice, the following query returns an error: select * from weather.forecast where location='Nice' And as I have the latitude and longitude coordinated, how can I give them to the YQL to return the weather info? Is this service worldwide or just for USA? Thank you, Regards.

    Read the article

  • Asynchronous IO in Java?

    - by thr
    What options for async io (socket-based) are there in java other then java.nio? Also does java.nio use threads in the backround (as I think .NET's async-socket-library does, maybe it's been changed) or is it "true" async io using a proper select call?

    Read the article

  • What am I encrypting wrong here?

    - by Katie Krueger
    So I have a wordplay project to do and I have to encrypt some characters. I am at the point where I am stuck, and when I run it and type 1 for encrypt it doesn't shift that many letters. It just prints the work over again. I am wondering what I could do to fix it where if I say "hello" it will print 1 character over and say "ifmmp" Thank you! import java.util.Scanner; public class WordPlayTester{ public static void main(String [] args){ String word, reverse=""; String original; int key= 0; String Menu= "1-Encrypt \n2-Decrypt \n3-Is Palindrome \n0-Quit \n-Select an option-"; Scanner in = new Scanner(System.in); System.out.println("-Type any word-"); word = in.nextLine(); System.out.println(Menu); int choice=in.nextInt(); if(choice==1) { System.out.println("Insert a Key number"); int select= in.nextInt(); for (int i=0; i < word.length(); i++) { char c = word.charAt(i); if (c >= 'A' && c <= 'Z') { c = (char)(c - 64); int n = c+1; n = n % 26; if (n < 0) { n = n + 26; } c = (char)(n + 65); } System.out.println(c); } } else if(choice==3) { int length = word.length(); for ( int i = length - 1 ; i >= 0 ; i-- ) reverse = reverse + word.charAt(i); if (word.equals(reverse)) System.out.println("Your word is a palindrome."); else System.out.println("Your word is not a palindrome."); } else if(choice==0) { System.exit(0); } else { System.out.println(Menu); } } }

    Read the article

< Previous Page | 503 504 505 506 507 508 509 510 511 512 513 514  | Next Page >