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  • Need Help With Simple Regex

    - by npinti
    I have strings of this type: text (more text) What I would like to do is to have a regular expression that extracts the "more text" segment of the string, so far I have been using this regular expression: "^.*\\((.*)\\)$" Which although it works on many cases, it seems to fail if I have something of the sort: text (more text (even more text)) What I get is: even more text) What I would like to get instead is: more text (even more text) (basically the content of the outermost pair of brackets.) Thanks

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  • Matlab regex if statement

    - by Dan
    I want to have matlab take user input but accept both cases of a letter. For example I have: function nothing = checkGC(gcfile) if exist(gcfile) reply = input('file exists, would you like to overwrite? [Y/N]: ', 's'); if (reply == [Yy]) display('You have chosen to overwrite!') else $ Do nothing end end The if statement obviously doesn't work, but basically I want to accept a lowercase or uppcase Y. Whats the best way to do this?

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  • Trying to create a RegEx for the following patterns

    - by Travis
    Here are the patterns: Red,Green (and so on...) Red (+5.00),Green (+6.00) (and so on...) Red (+5.00,+10.00),Green (+6.00,+20.00) (and so on...) Red (+5.00),Green (and so on...) Each attribute ("Red,"Green") can have 0, 1, or 2 modifiers (shown as "+5.00,+10.00", etc.). I need to capture each of the attributes and their modifiers as a single string (i.e. "Red (+5.00,+10.00)", "Green (+6.00,+20.00)". Help?

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  • Regex to replace 'li' with 'option' without losing class and id attributes

    - by Earthman Web
    I am looking for a solution using preg_replace or similar method to change: <li id="id1" class="authorlist" /> <li id="id2" class="authorlist" /> <li id="id3" class="authorlist" /> to <option id="id1" class="authorlist" /> <option id="id2" class="authorlist" /> <option id="id3" class="authorlist" /> I think I have the pattern correct, but not sure how to do the replacement part... Here is the (wordpress) php code: $string = wp_list_authors( $args ); //returns list as noted above $pattern = '<li ([^>]*)'; $replacement = '?????'; echo preg_replace($pattern, $replacement, $string); Suggestions, please?

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  • .Net regex: what is the word character \w?

    - by tanascius
    Simple question: What is the pattern for the word character \w in c#, .net? My first thought was that it matches [A-Za-z0-9_] and the documentation tells me: Character class Description Pattern Matches \w Matches any \w "I", "D", "A", "1", "3" word character. in "ID A1.3" which is not very helpful. And \w seems to match äöü, too. What else? Is there a better (exact) definition available?

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  • PHP regex to search across multiple lines

    - by Gaz
    I'm using preg_* in PHP to search for the pattern <!-- %{data=THIS GETS MATCHED}% --> and pull out the matched text. The pattern for this is: preg_match('#<!-- %{' . $knownString . '\s*=\s*(.*?)}% -->#', ...) What I would like it to do is search across multiple lines for the string. For example: <!-- %{data= THIS GETS MATCHED AND RETURNED }% --> How can I edit my current pattern to have this search ability?

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  • Poor performance / speed of regex with lookahead

    - by Hugo Zaragoza
    I have been observing extremely slow execution times with expressions with several lookaheads. I suppose that this is due to underlying data structures, but it seems pretty extreme and I wonder if I do something wrong or if there are known work-arounds. The problem is determining if a set of words are present in a string, in any order. For example we want to find out if two terms "term1" AND "term2" are somewhere in a string. I do this with the expresion: (?=.*\bterm1\b)(?=.*\bterm2\b) But what I observe is that this is an order of magnitude slower than checking first just \bterm1\b and just then \bterm2\b This seems to indicate that I should use an array of patterns instead of a single pattern with lookaheads... is this right? it seems wrong... Here is an example test code and resulting times: public static void speedLookAhead() { Matcher m, m1, m2; boolean find; int its = 1000000; // create long non-matching string char[] str = new char[2000]; for (int i = 0; i < str.length; i++) { str[i] = 'x'; } String test = str.toString(); // First method: use one expression with lookaheads m = Pattern.compile("(?=.*\\bterm1\\b)(?=.*\\bterm2\\b)").matcher(test); long time = System.currentTimeMillis(); ; for (int i = 0; i < its; i++) { m.reset(test); find = m.find(); } time = System.currentTimeMillis() - time; System.out.println(time); // Second method: use two expressions and AND the results m1 = Pattern.compile("\\bterm1\\b").matcher(test); m2 = Pattern.compile("\\bterm2\\b").matcher(test); time = System.currentTimeMillis(); ; for (int i = 0; i < its; i++) { m1.reset(test); m2.reset(test); find = m1.find() && m2.find(); } time = System.currentTimeMillis() - time; System.out.println(time); } This outputs in my computer: 1754 150

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  • Regex to match javadoc style comments

    - by Anant
    I have files having content like /** * Some Content * @param .. * @author .. * */ function a_sample_function ( $args = '' ) { I need to extract the text Some Content @param .. @author .. given a function name a_sample_function ( the * can be removed by a gsub later I believe) I'm writing this in ruby.

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  • Using regex to add leading zeroes

    - by hgpc
    I would like to add a certain number of leading zeroes (say up to 3) to all numbers of a string. For example: Input: /2009/5/song 01 of 3 Output: /2009/0005/song 0001 of 0003 What's the best way to do this with regular expressions?

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  • How to write this regex in PHP?

    - by user198729
    $url = "http://google.com1215http://132.239.7.64:8082/jsp/wej29/en/Vm.jspHUAWEI"; preg_match('/http:\/\/.*?\.jsp/', $url, $match); I want to retrieve http://132.239.7.64:8082/jsp/wej29/en/Vm.jsp from $url,but the above returns more than I want: http://google.com1215http://132.239.7.64:8082/jsp/wej29/en/Vm.jsp How to do it properly?

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  • Help with regex pulling XML data from response body in PHP

    - by spdaly
    I am working on a project that pulls data from JMS queue using PHP and Zend Framework. The HTTP client response is below. All I need is the XML string. I came up with /(.*)<\/RequestDetails/gs which tests ok on http://gskinner.com/RegExr/ but the preg_match call is returning an empty matches array. I'm going to continue to hunt around for a pattern, but thought I would post here as well. Thanks to all who read, etc... Steve UPDATE: I can't get the code to paste correctly. Here's a link to a pastbin: http://pastebin.com/rQxzcfSg

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  • need a regex for matching repeating lines of symbols (example: ------------- or *****************)

    - by Haroldo
    I want to be able to remove linebreaks etc that people make by using recurring characters, for example: **************************************************** ---------------------------------------------------- ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ etc i'd like to not have to specify which characters it will match, maybe all that are NOT \w characters? also note they will not always start/end on a new line.. is this possible?

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  • Java - Regex problem

    - by Yatendra Goel
    I have list of urls of types: http://www.abc.com/pk/etc http://www.abc.com/pk/etc/ http://www.abc.com/pk/etc/etc where etc can be anything. So I want to search only those urls that contains www.abc.com/pk/etc or www.abc.com/pk/etc/

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  • Java - Regex problem

    - by Yatendra Goel
    I have a list of urls of type http://www.abc.com/pk/ca and http://www.abc.com/pk Now, I want to find out only those urls that ends with /pk or /pk/ and don't have anything in between .com and /pk

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  • Regex replace using a repetitive capture

    - by Zac
    I have a table like: A | 1 A | 2 B | 1 B | 2 B | 3 I'm trying to transform it to look like this: A { 1 | 2 } B { 1 | 2 | 3 } I've come up with this which will match correctly I just can't figure out how to get the repeated capture out. (A|B)|(\d)(\r\n\1|(\d))*

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  • Regex "or" Expression

    - by David
    This is probably a really basic question, but I can't find any answers. I need to match a string by either one or more spaces OR an equals sign. When I split this string: 9 x 13 = (8.9 x 13.4) (89 x 134) with ( +) I get: part 0: 9 x 13 = (8.9 x 13.4) part 1: (89 x 134) When I split it with (=) I get: part 0: 9 x 13 part 1: (8.9 x 13.4) (89 x 134) How can split by BOTH? Something like: (=)OR( +) Edit: This does not work(=)|( +) Test it here: http://myregexp.com/ under "split".

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  • Regex in javascript for enum datatype of mysql

    - by himadri
    Hello, I am working with php and mysql. I have one dropdown box where I am asking datatype of mysql field. Now, I want to put javascript validation for it. I am confused with the enum datatype. I am using regular expression /^[']{1}[^',^\\]+[']{1}$/. This is for one single value of enum values. It is working fine but issue is when I put single quote or backslash with backslash, it is valid but this regular expression shows it as invalid. For eg, 'a'b' is invalid but 'a\'b' is valid.

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  • Passing values into regex match function

    - by Tim
    In python (it's a Django filter), I'm doing this: lReturn = re.sub(r'\[usecase:([ \w]+)]', r'EXTEND WITH <a href="/usecase/%s/\1/">\1</a>' % pCurrentProjectName, lReturn) I'd like to use a function instead of a string (so I can check that the usercase is a valid name), so it would change to this: def _match_function(matchobj): lMatch = matchobj.group(1) return "EXTEND WITH <a href='/usecase/%s/%s/'>%s</a>" % (pCurrentProjectName, lMatch, lMatch) lReturn = re.sub(r'\[usecase:([ \w]+)]', _match_function, lReturn) How do I get pCurrentProjectName into the _match_function() function?

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  • Regex - Trim character at the end of a string

    - by Torez
    I am trying to remove a trailing - (dash) at the end of the string. Here is my code: <?php $str = 'SAVE $45! - Wed. Beach Co-ed 6s (Jul-Aug)'; echo ereg_replace('([^a-z0-9]+)','-',strtolower($str)); ?> produces this: save-45-wed-beach-co-ed-6s-jul-aug- How can I remove a specific trailing character only if its there, in this case the dash? Thanks in advance.

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  • Regex: Match words in sentence PHP

    - by Granit Luzhnica
    Hi, I have an array with words like $arr = arra("go", "walk", ...) I would like to replace these words with links f they are matched in sentences. But it should be only if they match exactly (for example "walk" should match "Walk" or "walk!" but not also "walking") And the replacement should be a simple link like: < a href='#walk' walk< /a Anybody Any idea?

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  • Converting paragraph tags with RegEx

    - by Joel
    I need to replace all <p> tags with <br /> tags within a string. The problem is that the <p> tag can have attributes in it , such as <p align="center"> so I want to delete all occurrences of an opening tag of a paragraph, no matter what attributes are in it, and replace them with <br />. I am using PHP and had no success getting to the right expression with the preg_replace function. Any help would be appreciated! Joel

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  • Java regex skipping matches

    - by Mihail Burduja
    I have some text; I want to extract pairs of words that are not separated by punctuation. Thi is the code: //n-grams Pattern p = Pattern.compile("[a-z]+"); if (n == 2) { p = Pattern.compile("[a-z]+ [a-z]+"); } if (n == 3) { p = Pattern.compile("[a-z]+ [a-z]+ [a-z]+"); } Matcher m = p.matcher(text.toLowerCase()); ArrayList<String> result = new ArrayList<String>(); while (m.find()) { String temporary = m.group(); System.out.println(temporary); result.add(temporary); } The problem is that it skips some matches. For example "My name is James", for n = 3, must match "my name is" and "name is james", but instead it matches just the first. Is there a way to solve this?

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