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  • With a SELECT...WHERE id IN (...), order results by IN() ?

    - by Deca
    With a query such as: SELECT * FROM images WHERE id IN (12,9,15,3,1) is it possible to order the results by the contents of the IN clause? The result I'm looking for would be something like: [0] => Array ( [id] => 12 [file_name] => foo ) [1] => Array ( [id] => 9 [file_name] => bar ) [2] => Array ( [id] => 15 [file_name] => baz ) ...

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  • Invalid attempt to access a field before calling Read() INSERT

    - by Raphael Fernandes
    I'm trying to use this code to check if the system already exists a field with this value Dim adap As New MySqlDataAdapter Dim sqlquery = "SELECT * FROM client WHERE code ='"+ TxtCode.Text +"'" Dim comand As New MySqlCommand() comand.Connection = con comand.CommandText = sqlquery adap.SelectCommand = comand Dim data As MySqlDataReader data = comando2.ExecuteReader() leitor.Read() If (data(3).ToString) = code Then MsgBox("already exists", MsgBoxStyle.Information) TxtCode.ResetText() TxtCode.Focus() Else Console.WriteLine(insert("INSERT INTO client (name, tel, code) VALUES ('" & name & "', '" & tel & "')")) con.Close() End If

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  • mysql_affected_rows() always returns 1 even though no row was updated.

    - by happyhardik
    What I am trying to do is: (programmatically) Update status where id is something, if no rows where updated, give error: we cannot find the record with id something, otherwise give message success. Here I am using mysql_affected_rows() to know if a row was updated or not, but it always return 1, so the user gets a success message, even though there was no row updated. Can anyone tell me what could it be?

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  • I having a problem with the mysqli free() member function

    - by neo skosana
    Hi I have code where I connected to the database like so: $db = new mysqli("localhost", "user", "pass", "company"); Now when I query the database like so: //query calls to a stored procedure 'user_info' $result = $db->query("CALL user_info('$instruc', 'c_register', '$eml', '$pass', '')"); //I use the $result This query works well. Now when I try and free that result like so: $result->free(); or $result->close(); It seems like it doesn't do anything because $result is still set. When I try to run another query it gives me this error: Fatal error: Call to a member function fetch_array() on a non-object in... For me to run this other query I have to close the db conection and connect again, then it will work. I want to know if there is a way I could run the other query without having to disconnect and reconnect to the database. thanks in advance.

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  • Make SQL query more efficient

    - by Webnet
    I currently have this query which runs 2 of the exact same sub queries but pull different data. When I make the values comma separated it throws an SQL error saying the sub query can return only one value. Is there anything else I can do to avoid running multiple sub queries? SELECT product_id, ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc WHERE product_id = product_master.product_id) as listing_count, sku, type_id, ( SELECT AVG(ebay_archive_listing.current_price), AVG(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing WHERE id IN ( SELECT listing_id FROM ebay_archive_product_listing_assoc WHERE product_id = product_master.product_id ) AND ebay_archive_listing.start_time >= '.$startTimestamp.' AND ebay_archive_listing.start_time <= '.$endTimestamp.' AND ebay_archive_listing.current_price > 0 ) as average_bid_price, ( SELECT FROM ebay_archive_listing WHERE id IN ( SELECT listing_id FROM ebay_archive_product_listing_assoc WHERE product_id = product_master.product_id ) AND ebay_archive_listing.start_time >= '.$startTimestamp.' AND ebay_archive_listing.start_time <= '.$endTimestamp.' AND ebay_archive_listing.buy_it_now_price > 0 ) as average_buyout_price FROM product_master I'm aware of the syntax error... I'm selecting 2 seperate averages and am wondering if I can do it any simpler way.

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  • How To Get YEARWEEK() To See Sunday As The Start Of The Week?

    - by tan
    I'm trying to get the YEARWEEK function to see Sunday as the 1st day of the week. An example date is: Sunday 1st Mar 2009 Here is my sql SELECT YEARWEEK('2009-03-01') and the result is - 200909 Which is week 9. I believe it is telling me this is week 9 because it sees the sunday as the last day of the previous week. How would I get this function to see sunday as the 1st day of the week and therefore return as week 10?

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  • Pass database data to multiples views-Laravel

    - by user3696018
    I have a database with details of daily sales. To query a database, I have a form in a view with parameters that will query as date of admission, client and others. The result is shown in another view with the daily details of income, and below is a summary of the article do all entered. The summary I wish to transfer to another view, try to view :: composer but only transfer the empty query (I saw it with debug bar). Just appeared an empty view. How I can transfer data from the database without the latter view is empty? The second html view is totaly diferent , only the data is the same.

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  • What statistics app should I use for my website?

    - by Camran
    I have my own server (with root access). I need statistics of users who visit my website etc etc... I have looked at an app called Webalyzer... Is this a good choice? I run apache2 on a Ubuntu 9 system... If you know of any good statistics apps for servers please let me know. And a follow-up question: All statistics are saved in log-files right? So how large would these log-files become then? Possibility to split them would be good, dont know if this is possible with Webalyzer though...

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  • datesub question

    - by Ahmet vardar
    Hi, is it possible to use date_sub like this ? $dt = date("Y-m-d h:i:s"); $query = "INSERT INTO `table` (`date`) VALUES ('DATE_SUB('$dt', INTERVAL 15 DAY)')"; $result = MYSQL_QUERY($query); Thanks

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  • What does the below query explain?

    - by Parth
    What does the below query explain? SELECT * FROM `jos_menu` WHERE (id = 69 OR id = 72) I know its very silly question, but sometimes easy things creates mess in my skulls interpreter.. Pls help EDIT Its giving me record for both IDs, why is it doing so? It should five me the record for either 69 or 72....

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  • "=null" and select statement!

    - by user329820
    Hi I have asked this question before in this forum and they told me that it will retun an empty result set,I want to know that if I set the column with null values it will retun an empty result set?also the ANSI_NULLS is OFF ,thanks SELECT 'A' FROM T WHERE A = NULL;

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  • Doing sum's if certain conditions are true

    - by Gugu
    I am trying to build a query that does a sum if a certain parameter is set. For example: SELECT SUM(IF(<condition>,field,field)) AS total_value ...which is working correctly. But i have more than one condition in IF(), like: SELECT SUM(IF(<condition> <condition>,field,field)) AS total_value ..which is not working, could you have any idea what should be the right query for this.

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  • sql query help join (i think)

    - by milan
    I am having trouble figuring our how I can get results only when products.published, product_types.published, and product_cats.published = 1 but my query isn't working. Please help: SELECT `products`.`title`, `products`.`menu_id`, `products`.`short_description`, `products`.`datasheet_icon`, `products`.`datasheet`, `products`.`ordering`, `products`.`product_type_id`, CASE WHEN CHAR_LENGTH(`products`.`alias`) THEN CONCAT_WS(':', `products`.`id`, `products`.`alias`) ELSE `products`.`id` END AS slug FROM `products`, `product_cats`, `product_types` WHERE `products`.published=1 AND `product_cats`.published=1 AND `product_types`.published=1 AND `products`.`product_cat_id`='42' AND `product_types`.`id` IN (1,40,48,49,50) GROUP BY `products`.`id` ORDER BY `product_types`.`ordering`, `products`.`ordering`

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  • sql clarification

    - by JPro
    Can anyone please clarify what this query will return ? SELECT TestCase FROM MyTable WHERE Verdict = 'PASS' AND StartTime > DATE_SUB(NOW(), INTERVAL 2 MONTH)

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  • How to pass a variable to a IN clause?

    - by Thanu
    Lets say I have a SP that has a SELECT statements as follows, SELECT product_id, product_price FROM product WHERE product_type IN ('AA','BB','CC'); But data goes to that IN clause must be through a single variable that contains the string of values. Something link below SELECT product_id, product_price FROM product WHERE product_type IN (input_variables); But its not working that way. Any idea how to do this?

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  • Correcting an UPDATE statement (and making it more secure!)

    - by Jess
    I'm trying to a single value in my DB...When I run it through the console, it works correctly (as I'm replacing the variables with numbers and text).. However, My query is not running correctly. It's just prompting a syntax error Here is what I have: "UPDATE books SET readstatus='".$readstatus."' WHERE book_id=".$book_id; This won't work, I also tried doing something like this as I'm told this makes it a bit more secure? : "UPDATE books SET readstatus='{$readstatus}', WHERE read_id='{read_id}'"; This does not prompt any errors, but no change is happeneing to the value in the DB, I'm guessing the syntax is incorrect.

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  • Is UTF-8 enough for all common languages?

    - by jack
    I just wanted to develop a translation app in a Django projects which enables registered users with certain permissions to translate every single message it appears in latest version. My question is, what character set should I use for database tables in this translation app? Looks like some european language characters cannot be stored in UTF-8?

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  • CONCAT_WS rows in JOIN

    - by Alex Kiselev
    i have tables profiles (id, name, deleted) categories (id, name, deleted) profiles_categories (id, profile_id, category_id, , deleted) I have wrong query SELECT p.id, p.name CONCAT_WS(', ', c.name) AS keywords_categories FROM profiles p LEFT JOIN profiles_categories pc ON p.id = pc.profile_id LEFT JOIN categories c ON pc.id = c.id WHERE p.deleted = FALSE So, i want have result with all profiles with concan categories.name. Thanks

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