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  • Flex 4 animation question

    - by Jerry
    Hello.. I am trying to do the move vertically animation on a button nested in the vertical layout. I am not sure if the Hgroup restricts the button moving vertically. Are there ways to go around it? Thanks for the helps. <s:states> <s:State name="default"/> <s:State name="addRecommend"/> <s:State name="seeOther"/> </s:states> AS: protected function add_clickHandler(event:MouseEvent):void { currentState="addRecommend"; addRecommendMove.play(); } <s:transitions> <s:Transition fromState="default" toState="addRecommend"> <s:Sequence id="addRecommendMove"> <s:Move yTo="50" target="{add}"/> // add button doesn't move at all </s:Sequence> </s:Transition> <s:Transition fromState="addRecommend" toState="seeOther"> <s:Sequence> <s:Move yBy="50" target="{seeOthers}"/> </s:Sequence> </s:Transition> </s:transitions> <s:layout> <s:VerticalLayout paddingTop="15" paddingRight="10" paddingLeft="7"/> </s:layout> <button id="add" click=add_clickHandler(event)/> <button id="seeOthers"/>

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  • problem in adding image to JFrame

    - by firestruq
    Hi, I'm having problems in adding a picture into JFrame, something is missing probebly or written wrong. here are the classes: main class: public class Tester { public static void main(String args[]) { BorderLayoutFrame borderLayoutFrame = new BorderLayoutFrame(); borderLayoutFrame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); borderLayoutFrame.setSize(600,600); borderLayoutFrame.setVisible(true); } } public class BorderLayoutFrame extends JFrame implements ActionListener { private JButton buttons[]; // array of buttons to hide portions private final String names[] = { "North", "South", "East", "West", "Center" }; private BorderLayout layout; // borderlayout object private PicPanel picture = new PicPanel(); // set up GUI and event handling public BorderLayoutFrame() { super( "Philosofic Problem" ); layout = new BorderLayout( 5, 5 ); // 5 pixel gaps setLayout( layout ); // set frame layout buttons = new JButton[ names.length ]; // set size of array // create JButtons and register listeners for them for ( int count = 0; count < names.length; count++ ) { buttons[ count ] = new JButton( names[ count ] ); buttons[ count ].addActionListener( this ); } add( buttons[ 0 ], BorderLayout.NORTH ); // add button to north add( buttons[ 1 ], BorderLayout.SOUTH ); // add button to south add( buttons[ 2 ], BorderLayout.EAST ); // add button to east add( buttons[ 3 ], BorderLayout.WEST ); // add button to west add( picture, BorderLayout.CENTER ); // add button to center } // handle button events public void actionPerformed( ActionEvent event ) { } } I'v tried to add the image into the center of layout. here is the image class: public class PicPanel extends JPanel { Image img; private int width = 0; private int height = 0; public PicPanel() { super(); img = Toolkit.getDefaultToolkit().getImage("table.jpg"); } public void paintComponent(Graphics g) { super.paintComponents(g); if ((width <= 0) || (height <= 0)) { width = img.getWidth(this); height = img.getHeight(this); } g.drawImage(img,0,0,width,height,this); } } Please your help, what is the problem? thanks BTW: i'm using eclipse, which directory the image suppose to be in?

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  • User control or custom control for this design?

    - by m0s
    If I want to create a button control like that, is it supposed to be a User Control or a Custom Control? I am not sure maybe something else? Ideally I want to be able style/animate the main button and the inner button separately; also obviously Ill need to process their events separately. These buttons will be created at run-time and Ill need to set the icons dynamically.

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  • Watir question regarding exist on a class for testing purposes.

    - by AJ
    I have a button on my page that changes depending on what radio button is clicked. The button has the same text on it with the same id, but different classes. How do I test if the two different buttons exist depending on the radio. <a id="submit" class="on" href="javascript:submit();">Submit</a> <a id="submit" class="off" href="javascript:submit();">Submit</a> How do i test if the second button appears instead of the first one. I used something like, browser.link(:text, 'Submit').exist? but this doesn't work cause it will return true no matter what. thanks

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  • wxHaskell on OS X

    - by Bill
    I want to use wxHaskell on OS X (Snow Leopard, MacBook Pro). I was able to install the library successfully and the script below: module Main where import Graphics.UI.WX main :: IO () main = start hello hello :: IO () hello = do f <- frame [text := "Hello!"] quit <- button f [text := "Quit", on command := close f] set f [layout := widget quit] does result in a window being displayed with a single button, as specified. However, nothing happens when I click the button - I don't even get the visual response of the button turning blue to indicate that it's been depressed (haha, no pun intended). I've heard that you have to run a package called "macosx-app" on wxHaskell binaries to get them to run, but I can't find this anywhere. It's not on my machine or (as far as I can tell) in the WX or wxHaskell distros. Anyone know what I need to do to get this to work?

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  • icon as an image

    - by Ken
    Hi All, is it possible to use icon file as a image for a button in visual basic? f.e. I have 3 buttons that need to have 3 icons when you click the button the icon of the button needs to be the icon of the form is this posible? btnIcon1 = my.resources.ICO1 btnIcon2 = my.resources.ICO2

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  • Using Javascript, How do I bring an already existing open window to the front on top of other window

    - by user268249
    The question was fairly descriptive but I'll describe it further. Basically, I have Window1, clicking a button link opens window2. Clicking a button in window2 opens window3, clicking a button in window3 should bring window2 back to the front of the screen on top of window2. I'm not sure how this is exactly done, however I have used and played around with focus(), opener and other various methods and I cannot seem to get it to work properly. Thanks for any help in advance!

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  • WPF Buttons Style

    - by Polaris
    I have WPF Form which has many buttons with the same code. Appearance of all buttons must be the same For example, code for one of these buttons <Button x:Name="btnAddRelative" Width="120" Click="btnAddRelative_Click" > <Button.Content> <StackPanel Orientation="Horizontal"> <Image Height="26" HorizontalAlignment="Left"> <Image.Source> <BitmapImage UriSource="images/add.png" /> </Image.Source> </Image> <TextBlock Text=" Add Relative" Height="20" VerticalAlignment="Center"/> </StackPanel> </Button.Content> </Button> How can I create one style and use it for all my buttons. All buttons has the same png image, only their text different. How can I do this. I tried to do this with Style object in Resource Section: <UserControl.Resources> <Style TargetType="Button" x:Key="AddStyle"> <Setter Property="Content"> <Setter.Value> <StackPanel Orientation="Horizontal"> <Image Height="26" HorizontalAlignment="Left"> <Image.Source> <BitmapImage UriSource="images/add.png" /> </Image.Source> </Image> <TextBlock Text=" " Height="20" VerticalAlignment="Center"/> </StackPanel> </Setter.Value> </Setter> </Style> </UserControl.Resources> But this code not work. Can any body know how can I do this?

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  • Need to have an aspx page with a Feature in SharePoint 2010

    - by camit90
    I have added a custom button to the server ribbon in SharePoint (I have used a feature with Farm scope, so that the button is visible throughout the various site collections). For the elements of the feature, I have added a CustomUIExtension through which I want to load an aspx page on the click of the button. <CommandUIHandler Command="Test_Button" CommandAction="javascript: function demoCallback(dialogResult, returnValue) { SP.UI.Notify.addNotification('Operation Successful!'); SP.UI.ModalDialog.RefreshPage(SP.UI.DialogResult.OK); } var options = { url: '/_layouts/CustomPage.aspx', tite: 'Custom Page', dialogReturnValueCallback: demoCallback }; SP.UI.ModalDialog.showModalDialog(options);" /> I have added the CustomPage.aspx and its corresponding code behind class to the 14 hive (inside 14/TEMPLATE/LAYOUTS). However when I install the feature and click the button, I get an error saying "Cannot load CustomPage". I understand that I haven't deployed the assembly, but shouldn't the aspx page be compiled Just In Time?

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  • problem with dropdown in jsp

    - by Deven
    hello friends i am having three drop downs and button in my web page naming 1st 2nd and 3rd in which the value of 2nd depends on 1st and value of 3rd depends on 2dn its done using ajax now when i click on the button it calls one function of ajax which takes value from database and then select value at 1st dropdown and then fire on change event using fireEvent() function which is used to set values in 2nd dropdown and then the function called at button now select value at 2nd dropdown and then fire on change event using fireEvent() function which is used to set values in 3rd dropdown The main problem is that when i click on button it set value in 1st dropdown but 2nd and 3rd dropdown shows blank values

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  • How to use JS to jump to a specific place in a page? Tried scrollIntoView, not working

    - by EmmyS
    I have a PHP form for discussions. Each message has its own response button, which is dynamically generated. I'm using javascript in the button to make a response form visible at the bottom of the page, but I can't for the life of me get the page to jump down to the form once it's visible. This is a problem for pages that have a lot of discussions on it, as some users may not know to scroll down and will just think the button didn't work. Here's what I have now for my button code: <a href="#" onClick="changeVisibility(3,'responseForm')"><img src="images/reply.jpg" border=0 /></a> The changeVisibility function looks like this: function changeVisibility(parentID, elementID) { document.getElementById(elementID).style.visibility="visible"; document.forms[0].parent_id.value=parentID; var el = document.getElementById(elementID); el.scrollIntoView(true); } In my form, I have a div whose id is set to responseForm. When clicking the button, the div does become visible, but the scrollIntoView is not working - I have to manually scroll down to see it. Any ideas?

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  • How can I ignore an http request without clearing the browser?

    - by Timid Developer
    To prevent duplicate requests (i.e. pressing F5 right after clicking a command button), I've setup my page base class to ignore the request if it's detected as a duplicate. When I say 'ignore' I mean Response.End() Now I thought I've seen this work before, where there's an issue, I just Response.End() and the users page just does nothing. I don't know the exact circumstance in which this worked, but I'm unable to repeat it now. Now when I call Response.End(), I just get an empty browser. More specifically, I get this html. <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META http-equiv=Content-Type content="text/html; charset=utf-8"></HEAD> <BODY></BODY></HTML> I setup the following test app to confirm the problem is not elsewhere in my app. Here it is: Add the following to an aspx form <asp:Label ID="lbl" Text="0" runat="server" /><br /> <asp:Button ID="btnAdd1" Text="Add 1" runat="server" /><br /> <asp:Button ID="btnAdd2" Text="Add 2" runat="server" /><br /> <asp:Button ID="btnAdd3" Text="Add 3" runat="server" /><br /> And here's the code behind file using System; namespace TestDupRequestCancellation { public partial class _Default : System.Web.UI.Page { protected void Page_Init(object sender, EventArgs e) { btnAdd1.Click += btnAdd1_Click; btnAdd2.Click += btnAdd2_Click; btnAdd3.Click += btnAdd3_Click; } protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) CurrentValue = 0; else if (Int32.Parse(lbl.Text) != CurrentValue) Response.End(); } protected void Page_PreRender(object sender, EventArgs e) { lbl.Text = CurrentValue.ToString(); } protected int CurrentValue { get { return Int32.Parse(Session["CurrentValue"].ToString()); } set { Session["CurrentValue"] = value.ToString(); } } void btnAdd3_Click(object sender, EventArgs e) { CurrentValue += 3; } void btnAdd2_Click(object sender, EventArgs e) { CurrentValue += 2; } void btnAdd1_Click(object sender, EventArgs e) { CurrentValue += 1; } } } When you load the page, clicking any button does what is expected, but if you press F5 at any time after pressing one of the buttons, it will detect it as a duplicate request and call Response.End() which promptly ends the task. Which leaves the user with an empty browser. Is there anyway to leave the user with the page as it was, so they can just click a button? Also; please note that this code is the simplest code I could come up with to demonstrate my problem. It's not meant to demonstrate how to check for dup requests.

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  • How to Access value of dynamically created control?

    - by sharad
    i have asp.net web application in which i need to create form dynamically depend upon table which user selected.however,i created form dynamically with it's control like text box,drop downlist etc. but not able to access those controls at particular button click event. My form scenario is like this: i have dropdownlist in which i display list of tables,button control say display( on click event which i redirect page with some addition in querystring so that at page init it dynamically genrate controls) and another button control which used to access this controls value say Submit and store in database. This is my code: At Display button Click event: Response.Redirect("dynamic_main.aspx?mode=edit&tablename=" + CMBTableList.SelectedItem.ToString()); This is code For page.Init level if (Request.QueryString["mode"] != null) { if (Request.QueryString["mode"].ToString() == "edit") { Session["tablename"] = Request.QueryString["tablename"].ToString(); // if (Session["tablename"].ToString() == CMBTableList.SelectedItem.ToString()) //{ createcontrol(Session["tablename"].ToString()); // } } } i have used createcontrol() which genrate controls Code For Submit Button: string[] contid=controlid.Value.Split(','); MasterPage ctl00 = FindControl("ctl00") as MasterPage; ContentPlaceHolder cplacehld = ctl00.FindControl("ContentPlaceHolder2") as ContentPlaceHolder; Panel panel1 = cplacehld.FindControl("plnall") as Panel; Table tabl1 = panel1.FindControl("id1") as Table; foreach (string sin in contid) { string splitcvalu = sin.Split('_')[0].ToString(); ControlsAccess contaccess = new ControlsAccess(); if (splitcvalu.ToString() == "txt") { TextBox txt = (TextBox)tabl1.FindControl(sin.ToString()); //TextBox txt = cplacehld.FindControl(sin.ToString()) as TextBox; val = txt.ID; } else { DropDownList DDL = cplacehld.FindControl(sin.ToString()) as DropDownList; } } Here i am no able to access this textbox or drop downlist.i am getting id of particular control from hidden field controlid in which i have stored it during genrating controls. i have used findcontrol() it works in case of finding masterpage,contentplaceholder,table etc. but in case of textbox or other control it doesnt work it shows it returns null. Anyone can help me. Thanks

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  • notications pop up in user side

    - by user2931015
    i try to show notification as a pop up. like when admin login and through his account he send notification to user i add this html in admin form like this.. <asp:Button ID="notic" runat="server" Text="Send" onclick="Button1_Click" /> <br /> <input class="add_message" type="text" value="type your message" name="add_message"></input> <input type="button" value="add message" onclick="sNotify.addToQueue($('.add_message').attr('value'))"/> Then when admin click on button then notification send to users account like when any user login then he/she able to see pop ups in user form I call this java script in page load like this .. ClientScript.RegisterStartupScript(GetType(), "Javascript", "javascript:sNotify.addToQueue($('.add_message').attr('value'))();", true); it works like when i login as a admin and click on button then notification in his own page .. but i want to show this notifications in user form. so how to solve it?

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  • Pass Value between MDI Child in WinForm using C#

    - by abhilashca
    I have an MDI Parent, containing a MenuStrip. When I click on one of the Menu, two Child Forms are displayed simultaneoulsy. I have a TextBox and a Send Button on one of my ChildForm. When I type-in something in that TextBox and Click the Send Button, I need to show that value in the TextBox of my Second Child Form. What I had done is, I wrote a Public Function in the Second Child Form and tried to invoke it by creating an object of Second Form, on the Send Button click event. When I put break points, in that Public Function, I find that the control is flowing through that Public function on cliking the Send button. But the passed value is not displayed. And, I know that is not the standard way to do that. Any sample script for help? Thanks.

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  • Magento: Customer Comment on order page required field

    - by Shamim Ahmed
    I am using whiteOrderComment module for customer comment on order review page. but in this section text-area field required option not working. I did little bit change on /checkout-onepage-review-button.phtml like this <script type="text/javascript"> function validate(){ if(document.getElementById("whiteOrderComment").value == ""){ alert('Required'); }else{ review.save(); } </script> <button type="submit" title="<?php echo $this->__('Place Order') ?>" class="button btn-checkout" onclick="validate();"><span><span><?php echo $this->__('Place Order') ?></span></span></button> but in this page javascript not working. can you please give any better idea, how can i make this text-area field required. thanks

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  • Is there an easy way to stream a m3u in iPhone?

    - by marty
    I can have a UIWebView with the .m3u file opened, which will go to the webview with a play button displayed, and that automatically goes to the quicktime player and starts playing the stream. But when I press the done button, it goes back to the UIWebView with a little play button in the middle, and from there you can go back to the previous screen (it was selected from a tableview). So I just want it to automatically load the quicktime player in the view. How can I do that?

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  • How can I prevent a page to jump to top position after failed validation?

    - by Slauma
    I have a simple aspx page with a few TextBoxes and a submit button. Some fields are required and below the button is a ValidationSummary. The complete form is larger than screen height so one has to scroll down to reach the submit button. If I don't fill all required fields and click on submit validation fails as expected and the validation summary displays some info messages below the button. Validation happens on the client and no postback occurs. So this all works as wished. But disturbing is that the page moves ("jumps") to top position when I click on the submit button. To see the validation summary one has to move down the page again. I've tried to set the ShowSummary property to false (which doesn't make much sense): The validation still works (no postback) but in this case the page does not move to top position. So the problem seems to depend on rendering the validation texts. Is there a way to prevent this page jump? Thank you in advance!

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  • iphone instance / class method issue

    - by user290031
    Hey All, Okay, so I have a viewController method that has some elements created with interface builder and some I coded myself. I created a view in the IB...lets call it viewOne. I created a loop that creates buttons (through code) and places them on a separate view (viewTwo). This is done in a class method. However, I want the view I made to be opened everytime one of the buttons is clicked. So I did: [button addTarget:self action:@selector(woogoo:) forControlEvents:UIControlEventTouchUpInside]; The woogoo class does the following: +(void) woogoo:(id)sender { //back button [self.view addSubview:viewOne] } However, the program crashes when a button is clicked. I did try making woogoo an instance method but it also crashes in this case too. All I want to do is show viewOne when a button is clicked. Any ideas what I can do?

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  • How to find a label in a asp repeater

    - by citrus
    Structure of my asp: repeater repeater updatePanel label1 (rating) button (updates rating) some_picture (thing being rated) /update panel /repeater Imagine the output of the above repeater containing 100 rows. (1 label, and 1 button on each row). Goal: when I click the button, I want the appropriate label to be updated. I dont know how to do this. I can reference a label via: Label myLabel2Update = (Label)Repeater1.Controls[0].Controls[0].FindControl("Label1"); But ofcourse, it will be the same label each time (not necessarily the label that needs to be updated). I need to update the label that is on the same row as the button. Any guidance would be appreciated.

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  • How to figure out which key was pressed on a BlackBerry

    - by Skrud
    What I want: To know when the user has pressed the button that has the number '2' on it, for example. I don't care whether "Alt" or "Shift" has been pressed. The user has pressed a button, and I want to evaluate whether this button has '2' printed on it. Naturally, if I switch devices this key will change. On a Bold 9700/9500 this is the 'E' key. On a Pearl, this is the 'T'/'Y' key. I've managed to get this working in what appears to be a roundabout way, by looking up the keycode of the '2' character with the ALT button enabled and using Keypad.key() to get the actual button: // figure out which key the '2' is on: final int BUTTON_2_KEY = Keypad.key(KeypadUtil.getKeyCode('2', KeypadListener.STATUS_ALT, KeypadUtil.MODE_EN_LOCALE)); protected boolean keyDown(int keycode, int time) { int key = Keypad.key(keycode); if ( key == BUTTON_2_KEY ) { // do something return true; } return super.keyDown(keycode,time); } I can't help but wonder if there is a better way to do this. I've looked at the constants defined in KeypadListener and Keypad but I can't find any constants mapped to the actual buttons on the device. Would any more experienced BlackBerry devs care to lend a helping hand? Thanks!

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  • Extjs 4.1 How to call controller action method from form

    - by Omar Faruq
    Extjs 4.1 How to call controller action method from form which is already use in a button action but i want this method reuse from a form field but do not how i can do? // here is my controller code init: function() { this.control({ 'itemsgrid': { removeitem: this.removeUser }, 'salewindow button[action=resetAll]': { click: this.resertform }, 'salewindow button[action=saveOrder]' : { click : this.onsaveOrder }, 'salewindow button[action=PDF]' : { click : this. pdfreport } }); }, resertform : function(button){ var store = Ext.data.StoreManager.get('Items'); store.destroy(); var vatstore = Ext.data.StoreManager.get('Vats'); vatstore.reload(); var rebatestore = Ext.data.StoreManager.get('Rebates'); rebatestore.reload(); Ext.getCmp('calculation-form').getForm().reset(); Ext.getCmp('itemform2').getForm().reset(); Ext.getCmp('itemsgrid').subtotalquantity(p=0); store.reload(); var co=store.getCount(); console.log(co); Ext.getCmp('customerID').setValue('0'); var a = Ext.getCmp('customerID').getValue(); Ext.getCmp('itemform2').customerinfo(a); } //and here is my from field listener { xtype : 'textfield', name : 'BranchId', fieldLabel : 'Branch Id', allowNegative : false, id : 'branchid', value : '1', onBlur: function(){ restoreItem();// i want call this method from here whis is stay in controller } }

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  • Font-awesome, input type 'submit'

    - by denis.peplin
    It seems no class for input type 'submit' in font-awesome. Is it possible to use some class from font-awesome for button input? I've added icons to all buttons (which actually links with class 'btn' from twitter-bootstrap) in my applications, but can't add icons on 'input type submit'. Or, how to use this code: input#image-button{ background: #ccc url('icon.png') no-repeat top left; padding-left: 16px; height: 16px; } html: <input type="submit" id="image-button">Text</input> (which I took from HTML: How to make a submit button with text + image in it?) with font-awesome?

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  • Give Markup support for Custom server control with public PlaceHolders properties

    - by ravinsp
    I have a custom server control with two public PlaceHolder properties exposed to outside. I can use this control in a page like this: <cc1:MyControl ID="MyControl1" runat="server"> <TitleTemplate> Title text and anything else </TitleTemplate> <ContentTemplate> <asp:TextBox ID="TextBox1" runat="server"></asp:TextBox> <asp:Button ID="Button1" runat="server" Text="Button" /> </ContentTemplate> </cc1:MyControl> TitleTemplate and ContentTemplate are properties of type asp.net PlaceHolder class. Everything works fine. The control gets any content given to these custom properties and produces a custom HTML output around them. If I want a Button1_Click event handler, I can attach the event handler in Page_Load like the following code. And it works. protected void Page_Load(object sender, EventArgs e) { Button1.Click += new EventHandler(Button1_Click); } void Button1_Click(object sender, EventArgs e) { TextBox1.Text = "Button1 clicked"; } But if try to attach the click event handler in aspx markup I get an error when running the application "Compiler Error Message: CS0117: 'ASP.default_aspx' does not contain a definition for 'Button1_Click' <asp:Button ID="Button1" runat="server" Text="Button" OnClick="Button1_Click" /> AutoEventWireup is set to "true" in the page markup. This happens only for child controls inside my custom control. I can programatically access child control correctly. Only problem is with event handler assignment from Markup. When I select the child Button in markup, the properties window only detects it as a < BUTTON. Not System.Web.UI.Controls.Button. It also doesn't display the "Events" tab. How can I give markup support for this scenario? Here's code for MyControl class if needed. And remember, I'm not using any ITemplate types for this. The custom properties I provide are of type "PlaceHolder". [ToolboxData("<{0}:MyControl runat=server>" + "<TitleTemplate></TitleTemplate>" + "<ContentTemplate></ContentTemplate>" + "</{0}:MyControl>")] public class MyControl : WebControl { PlaceHolder contentTemplate, titleTemplate; public MyControl() { contentTemplate = new PlaceHolder(); titleTemplate = new PlaceHolder(); Controls.Add(contentTemplate); Controls.Add(titleTemplate); } [Browsable(true)] [TemplateContainer(typeof(PlaceHolder))] [PersistenceMode(PersistenceMode.InnerProperty)] public PlaceHolder TitleTemplate { get { return titleTemplate; } } [Browsable(true)] [TemplateContainer(typeof(PlaceHolder))] [PersistenceMode(PersistenceMode.InnerProperty)] public PlaceHolder ContentTemplate { get { return contentTemplate; } } protected override void RenderContents(HtmlTextWriter output) { output.Write("<div>"); output.Write("<div class=\"title\">"); titleTemplate.RenderControl(output); output.Write("</div>"); output.Write("<div class=\"content\">"); contentTemplate.RenderControl(output); output.Write("</div>"); output.Write("</div>"); } }

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  • JavaScript cookie value can't be retrieved in Django

    - by Boris Rusev
    I am trying to build a web site in both English and Bulgarian using the Django framework. My idea is the user should click on a button, the page will reload and the language will be changed. This is how I am trying to do it: In my html I hava a the button tag <button id='btn' onclick="changeLanguage();" type="button"> ... </button> An excerpt from cookies.js: function changeLanguage() { if (getCookie('language') == 'EN') { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'BG'); } else { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'EN'); } } function setCookie(sName, sValue, oExpires, sPath, sDomain, bSecure) { var sCookie = sName + "=" + encodeURIComponent(sValue); if (oExpires) { sCookie += "; expires=" + oExpires.toGMTString(); } if (sPath) { sCookie += "; path=" + sPath; } if (sDomain) { sCookie += "; domain=" + sDomain; } if (bSecure) { sCookie += "; secure"; } document.cookie = sCookie; } And in my views.py file this is the situation @base def index(request): if request.session['language'] == 'EN': return """<b>%s</b>""" % "Home" else request.session['language'] == 'BG': return """<b>%s</b>""" % "??????" So I know that my JS changes the value of the language cookie but I think Django doesn't get that. On the other hand when I set and get the cookie in my Python code again the cookie is set. My question is whether there is a way to make JS and Django work together - JavaScript sets the cookie value and Python only reads it when asked and takes adequate actions? Thank you.

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