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  • shopify_app syntax error

    - by Pete171
    Edit: Debugging has got me further. Question clarified. We have installed Ruby, RubyGems and Rails and have forked the shopify_app project. We have created a new rails applications and added three items to the Gemfile: execjs, therubyracer and shopify_app. Running rails s in order to start our rails application returns this trace: root@ubuntu:/usr/local/pete-shopify/cart# rails s Faraday: you may want to install system_timer for reliable timeouts /var/lib/gems/1.8/gems/shopify_app-4.1.0/lib/shopify_app.rb:15:in `require': /var/lib /gems/1.8/gems/shopify_app-4.1.0/lib/shopify_app/login_protection.rb:5: syntax error, unexpected ':', expecting kEND (SyntaxError) ...rce::UnauthorizedAccess, with: :close_session ^ from /var/lib/gems/1.8/gems/shopify_app-4.1.0/lib/shopify_app.rb:15 from /var/lib/gems/1.8/gems/bundler-1.2.1/lib/bundler/runtime.rb:68:in `require' from /var/lib/gems/1.8/gems/bundler-1.2.1/lib/bundler/runtime.rb:68:in `require' from /var/lib/gems/1.8/gems/bundler-1.2.1/lib/bundler/runtime.rb:66:in `each' from /var/lib/gems/1.8/gems/bundler-1.2.1/lib/bundler/runtime.rb:66:in `require' from /var/lib/gems/1.8/gems/bundler-1.2.1/lib/bundler/runtime.rb:55:in `each' from /var/lib/gems/1.8/gems/bundler-1.2.1/lib/bundler/runtime.rb:55:in `require' from /var/lib/gems/1.8/gems/bundler-1.2.1/lib/bundler.rb:128:in `require' from /usr/local/pete-shopify/cart/config/application.rb:7 from /var/lib/gems/1.8/gems/railties-3.2.8/lib/rails/commands.rb:53:in `require' from /var/lib/gems/1.8/gems/railties-3.2.8/lib/rails/commands.rb:53 from /var/lib/gems/1.8/gems/railties-3.2.8/lib/rails/commands.rb:50:in `tap' from /var/lib/gems/1.8/gems/railties-3.2.8/lib/rails/commands.rb:50 from script/rails:6:in `require' from script/rails:6 I haven't modified any files since forking from Github. Lines 1 - 6 of login_protection.rb are as follows: module ShopifyApp::LoginProtection extend ActiveSupport::Concern included do rescue from ActiveResource::UnauthorizedAccess, with: :close_session end I've looked into this and it seems that the error is caused by a new-style hash syntax between Ruby 1.8 and 1.9; key : value instead of key => value. Running ruby -v from the command line returns ruby 1.9.3p0 (2011-10-30 revision 33570) [x86_64-linux]. This would seem to be OK... but I did some debugging, and inside the file /var/lib/gems/1.8/gems/shopify_app-4.1.0/lib/shopify_app.rb (at the top) by putting this: puts RUBY_VERSION exit It printed 1.8.7. **Why are ruby -v and RUBY_VERSION giving me different results? And am I correct in assuming this is the cause of my problems? Note: To upgrade Ruby I installed the later version with apt-get and then switched to it by using update-alternatives --config ruby and selecting option 2 like this: root@ubuntu:/usr/local/pete-shopify/cart# update-alternatives --config ruby There are 2 choices for the alternative ruby (providing /usr/bin/ruby). Selection Path Priority Status ------------------------------------------------------------ 0 /usr/bin/ruby1.8 50 auto mode 1 /usr/bin/ruby1.8 50 manual mode * 2 /usr/bin/ruby1.9.1 10 manual mode Also note: We're PHP/Python developers so this is all new to us! Summary: 1 - Am I right in determining the cause of the syntax error? 2 - Why does RUBY_VERSION and ruby -v give me different results?

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  • Multiple views and source list in a Core Data app

    - by Ellie P.
    I'm working on my first major Cocoa app for an undergraduate research project. The application is document-based and uses Core Data. One of the entities is an abstract entity, Page. Page is parent of several types of pages: ie PageWithHeaderAndFooter, PageWithTwoColumns, BasicPage etc. Page has attributes, such as title and author, that all pages have in common. Each specific type of page has a certain number of layout blocks (PageWithHeaderAndFooter has three: header, footer, body. BasicPage has one: body. etc.) Additionally, all Page subclasses define layout-specific implementations of certain methods. The other relevant entity is Style, which defines the visual look of a Page. (Think of Pages as HTML and Style as CSS.) I would like my app to have an iTunes/Mail-like source list with sections. (One section would be Pages, the other would be Styles.) I have a pretty good idea how to do the sectioned source list (this was a great help). However, after hours of headbanging and fruitless googling, here's what I can't figure out: Pages and Styles listed in the source list, and when you select one of them, all of the relevant fields for that object appear at the right (mostly NSTextViews, pop up menus, etc). I laid that out and did all of the bindings in Interface Builder. The problem is, if my source list contains different types of pages, how do I get a different view to display at the right depending on the type of page selected? For example, if a BasicPage is selected, I want just what you see above: the general page stuff and one NSTextView that corresponds to the one field body of BasicPage. But if I select a PageWithHeaderAndFooter, I want to display the general page stuff plus three NSTextViews (one for header, body, and footer.) If I have a Style selected, I want to display various pop up menus, color wells, etc. For the pages at least, we're only talking about one or more NSTextViews, each of which corresponds to a String attribute of the respective entity. How would you do this? Thank you for your help!

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  • How efficient is Python substring extraction?

    - by Cameron
    I've got the entire contents of a text file (at least a few KB) in string myStr. Will the following code create a copy of the string (less the first character) in memory? myStr = myStr[1:] I'm hoping it just refers to a different location in the same internal buffer. If not, is there a more efficient way to do this? Thanks! Note: I'm using Python 2.5.

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  • Checking jQuery AJAX Request Status

    - by mTuran
    Hi, i do 2 different ajax request via jQuery and i have to check the other one is active or not. How can i do that ? one of example from my ajax requests: active_project_categories_ajax = $.ajax( { url: "/ajax/get_skill_list", dataType: 'json', ...... }); i need something like that: active_project_categories_ajax.status()

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  • Is it possible to override the behavior of a merge module.

    - by Kragen
    Supposing I have a merge module that installs a file "MyFile.txt" to a certain location, and that I wish to use that merge module, however I want to supply a different copy of "MyFile.txt" from the one supplied with the merge module. Is it possible to do this? (And for bonus points how can I do this using Wix)

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  • Using ruby's OptionParser to parse sub-commands

    - by rampion
    I'd like to be able to use ruby's OptionParser to parse sub-commands of the form COMMAND [GLOBAL FLAGS] [SUB-COMMAND [SUB-COMMAND FLAGS]] like: git branch -a gem list foo I know I could switch to a different option parser library (like Trollop), but I'm interested in learning how to do this from within OptionParser, since I'd like to learn the library better. Any tips?

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  • one high-end server with one Application Server or multiple Application Servers?

    - by elgcom
    If I have a high-end server, for example with 1T memory and 8x4core CPU... will it bring more performance if I run multiple App Server (on different JVM) rather than just one App Server? On App Server I will run some services (EAR whith message driven beans) which exchange message with each other. btw, has java 64bit now no memory limitation any more? http://java.sun.com/products/hotspot/whitepaper.html#64

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  • C# Loading a xml file from the current directory?

    - by Jonathan Dyle
    Hi all, I use the line below in my C# winform app, this works great but occasionally if the program is being run from the command line I get an error that the config.xml file cannot be found. This is because the 'working directory' is different (I think), I need to say "load config.xml from current directory", how would I do this? docXML.Load("config.xml"); Thanks Jonathan

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  • Real time complex raster image morphing in Flash CS4

    - by cosmorocket
    Is there a way to load an image from some url or a local folder and then make some complex morphing to it in real time? For example, I have a vector animated pseudo 3D paper in my project that, for example, is being flipped different ways. Then I want to place some image inside that paper box and want to morph that image accordingly to the box form changes or at least make it look more realistically, not exactly the same as the paper box. Thanks.

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  • Scala Array constructor?

    - by Lukasz Lew
    scala> val a = Array [Double] (10) a: Array[Double] = Array(10.0) scala> val a = new Array [Double] (10) a: Array[Double] = Array(0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0) Why these two expressions have different semantics?

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  • JBoss: Authentication caches wrong login credentials

    - by aliaslan
    I am using JBoss AS 4.2.3 JBossSeam 2.1 My Problem is that I can login/logout with different users as long as I do not enter a wrong password for one user. If this happens it is not possible to authenticate any user. Authentication always fails. If I delete the browser cookies everything works fine. I have tried to set DefaultCacheTimeout and DefaultCacheResolution to 0 but without luck. Why does JBoss cache wrong credentials?

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  • abstract test case using python unittest

    - by gruszczy
    Is it possible to create an abstract TestCase, that will have some test_* methods, but this TestCase won't be called and those methods will only be used in subclasses? I think I am going to have one abstract TestCase in my test suite and it will be subclassed for a few different implementation of a single interface. This is why all test methods are the some, only one, internal method changes. How can I do it in elegant way?

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  • Adding Previous/Next Functionality to jQuery Map Highlight Plugin

    - by Keith
    As you can see in my jsFiddle example, I have a diagram that uses jQuery Map Highlight plugin to allow users to click to different parts of the diagram and see the corresponding text to the left. Right now, the only way to interact with the diagram is by clicking on it. I'd like to give users the ability to hit previous and next buttons to control it as well. I'm just not sure how to go about it. Any help would be appreciated: http://jsfiddle.net/keith/jkLH7/1/

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  • What language is used in Google Desktop gadgets?

    - by Claudiu
    The language Google Desktop gadgets use resembles JavaScript, but it's different in subtle ways. For example, I saw this line in a gadget: options(HISTORY_OPTIONS_NAME) = items_.join("|"); which looks like it's assigning to a function call. That's just not OK in JavaScript... what language is this? And what exactly is that line doing?

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  • wpf: usercontrol vs. customcontrol performance issue

    - by viky
    Which one is better from performance view user control or custom control? Right now I am using user control and In a specific scenario, I am creating around 200(approx.) different instances of this control but it is bit slow while loading and I need to wait atlest 20-30 second to complete the operation. What should I do to increase the performance?

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  • Is there a utility that can monitor open windows/ in .net winforms?

    - by Jules
    This is a general question, but I'll explain my specific need at the moment: I want to find the framework class that enables one to choose an image at design-time. I can find the editor that is used at run-time - its the Drawing.Design.ImageEditor. At design time, however, a different editor pops up which allows one to choose an image from resources. I'm guessing I could run some kind of program, then open up the image editor, from the property grid, and see what new windows/classes have been created? Thanks

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  • how to implement more functionality in webpage

    - by trans
    Dear All, I have a website in front page i m displaying 5 records ,for different options,i want that when user licks more he should be able to view next records.i would i keep track as whicg list has already been shown to user,since i m using an arraylist,can i ipmlement it through that.

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  • how to achieve xxx.blogspot.com URL pattern ??

    - by abc
    Consider the case of blogspot.com the domain is the one blogspot.com only but suppose i register in it with xxx then i will have xxx.blogspot.com like wise here it won't be the subdomain (i can smell) , but its some thing different ... how to achieve this ?? in j2ee web application..

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  • Am I Leaking ADO.NET Connections?

    - by HardCode
    Here is an example of my code in a DAL. All calls to the database's Stored Procedures are structured this way, and there is no in-line SQL. Friend Shared Function Save(ByVal s As MyClass) As Boolean Dim cn As SqlClient.SqlConnection = Dal.Connections.MyAppConnection Dim cmd As New SqlClient.SqlCommand Try cmd.Connection = cn cmd.CommandType = CommandType.StoredProcedure cmd.CommandText = "proc_save_my_class" cmd.Parameters.AddWithValue("@param1", s.Foo) cmd.Parameters.AddWithValue("@param2", s.Bar) Return True Finally Dal.Utility.CleanupAdoObjects(cmd, cn) End Try End Function Here is the Connection factory (if I am using the correct term): Friend Shared Function MyAppConnection() As SqlClient.SqlConnection Dim cn As New SqlClient.SqlConnection(ConfigurationManager.ConnectionStrings("MyConnectionString").ToString) cn.Open() If cn.State <> ConnectionState.Open Then ' CriticalException is a custom object inheriting from Exception. Throw New CriticalException("Could not connect to the database.") Else Return cn End If End Function Here is the Dal.Utility.CleaupAdoObjects() function: Friend Shared Sub CleanupAdoObjects(ByVal cmd As SqlCommand, ByVal cn As SqlConnection) If cmd IsNot Nothing Then cmd.Dispose() If cn IsNot Nothing AndAlso cn.State <> ConnectionState.Closed Then cn.Close() End Sub I am getting a lot of "Timeout expired. The timeout period elapsed prior to completion of the operation or the server is not responding." error messages reported by the users. The application's DAL opens a connection, reads or saves data, and closes it. No connections are ever left open - intentionally! There is nothing obvious on the Windows 2000 Server hosting the SQL Server 2000 that would indicate a problem. Nothing in the Event Logs and nothing in the SQL Server logs. The timeouts happen randomly - I cannot reproduce. It happens early in the day with only 1 to 5 users in the system. It also happens with around 50 users in the system. The most connections to SQL Server via Performance Monitor, for all databases, has been about 74. The timeouts happen in code that both saves to, and reads from, the database in different parts of the application. The stack trace does not point to one or two offending DAL functions. It's happened in many different places. Does my ADO.NET code appear to be able to leak connections? I've goolged around a bit, and I've read that if the connection pool fills up, this can happen. However, I'm not explicitly setting any connection pooling. I've even tried to increase the Connection Timeout in the connection string, but timeouts happen long before the 300 second (5 minute) value: <add name="MyConnectionString" connectionString="Data Source=MyServer;Initial Catalog=MyDatabase;Integrated Security=SSPI;Connection Timeout=300;"/> I'm at a total loss already as to what is causing these Timeout issues. Any ideas are appreciated.

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  • Best way to detect IronPython

    - by Adal
    I need to write a module which will be used from both CPython and IronPython. What's the best way to detect IronPython, since I need a slightly different behaviour in that case? I noticed that sys.platform is "win32" on CPython, but "cli" on IronPython. Is there another preferred/standard way of detecting it?

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  • Is there a way in PHP to keep a file open and process each line and subsequent lines?

    - by Chris Denman
    I want to write a php script that keeps the apache_log file open and "listen" to the log and deal with each log entry as it happens. I'm thinking that I need to open a file, get the number of lines, then do this again in a loop - and when the size is different, read the new lines and process them. Am I barking up the wrong tree, or is there a silly easy solution that I have missed? Chris

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