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  • thread destructors in C++0x vs boost

    - by Abruzzo Forte e Gentile
    Hi All These days I am reading the pdf Designing MT programs . It explains that the user MUST explicitly call detach() on an object of class std::thread in C++0x before that object gets out of scope. If you don't call it std::terminate() will be called and the application will die. I usually use boost::thread for threading in C++. Correct me if I am wrong but a boost::thread object detaches automatically when it get out of scope. Is seems to me that the boost approach follow a RAII principle and the std doesn't. Do you know if there is some particular reason for this? Kind Regards AFG

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  • PHP IF statement not taking variable into account!

    - by Jess
    I have a tabled view in a while loop, where a user can view information on books. For example, book ISBN, book name, read status... Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this: $readstatus = $_GET['readstatus']; if ($readstatus == 'complete') { echo '<tr class="completed">'; } else if ($readstatus != 'complete') { echo '<tr class="reading">'; } I'm obviously doing something wrong here, but all I need is the CSS class of the table row to change if the value of 'readstatus' = 'complete', if not, then output the default CSS table row color ('reading') Should I be putting $result as the variable or something? I have this coming just before my nested IF statement: $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); while($row = mysql_fetch_array($result)) { ?>

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  • Error comparing hash to hashed mysql password (output values are equal)

    - by Charlie
    Im trying to compare a hashed password value in a mysql database with the hashed value of an inputted password from a login form. However, when I compare the two values it says they aren't equal. I removed the salt to simply, and then tested what the outputs were and got the same values $password1 = $_POST['password']; $hash = hash('sha256', $password1); ...connect to database, etc... $query = "SELECT * FROM users WHERE username = '$username1'"; $result = mysql_query($query); $userData = mysql_fetch_array($result); if($hash != $userData['password']) //incorrect password { echo $hash."|".$userData['password']; die(); } ...other code... Sample output: 7816ee6a140526f02289471d87a7c4f9602d55c38303a0ba62dcd747a1f50361| 7816ee6a140526f02289471d87a7c4f9602d55c38303a0ba62dcd747a1f50361 Any thoughts?

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  • convert mysql code to codeigniter

    - by Jethro Tamares Doble
    How can i convert this code into an acceptable codeigniter code: mysql_select_db($database_connection_ched, $connection_ched); $query_Institutions = "SELECT * FROM tb_institutional_profile ORDER BY tb_institutional_profile.institution_name ASC"; $Institutions = mysql_query($query_Institutions, $connection_ched) or die(mysql_error()); $row_Institutions = mysql_fetch_assoc($Institutions); $totalRows_Institutions = mysql_num_rows($Institutions); <td width="192"><select name="institution_id"> <?php do { <option value="<?php echo $row_Institutions['institution_id']?>" ><?php echo $row_Institutions['institution_name']?></option> <?php } while ($row_Institutions = mysql_fetch_assoc($Institutions)); ?> </select></td>

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  • PHP MySQL Insert Data

    - by happyCoding25
    Hello, Im trying to insert data into a table in MySQL. I found/modified some code from w3Schools and still couldn't get it working. Heres what I have so far: <?php $rusername=$_POST['username']; $rname=$_POST['name']; $remail=$_POST['emailadr']; $rpassword=$_POST['pass']; $rconfirmpassword=$_POST['cpass']; if ($rpassword==$rconfirmpassword) { $con = mysql_connect("host","user","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mydbname ", $con); } mysql_query("INSERT INTO members (id, username, password) VALUES ('4', $rusername, $rpassword)"); ?> Did I mistype something? To my understanding "members" is the name of the table. If anyone knows whats wrong I appreciate the help. Thanks

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  • How do you display a PHPmyadmin table onto a web browser/web page?

    - by user1390754
    Just a simple question, i've been searching around and for some reason i cannot find an answer to this. after creating a database/table in Phpmyadmin using xampp, what command do i need to put into my webpage (PHP) to show the table I made? I know the first step involves connecting to the database and i think i've done that properly. This is the code i found from somewhere about connecting (w3 tutorials I believe) $con = mysql_connect("localhost","xxxxxx,""); if (!$con) { die('Could not connect: ' . mysql_error()); }

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  • Need help... how to add md5 to password field in php?

    - by jones
    Hi mates, i looking some help and nice attention here.. i bought some php script many years ago and now no suport anymore... i just want to add md5 to password field.. here my form: <?php $SQL = "SELECT * from USERS WHERE USERNAME = '$_SESSION[username]'"; $result = @mysql_query( $SQL ); $row = @mysql_fetch_array( $result ); include 'menu.php'; ?> <FORM METHOD="post" ACTION="?page=query_client"> <INPUT TYPE="hidden" NAME="controller" VALUE="USERS~update~account_details&up=1~<?php echo $row[ID]; ?>"> <TABLE CLASS="basictable"> <TR> <TD CLASS="tdmenu" WIDTH="40%">Username</TD> <TD CLASS="tdmenu" WIDTH="60%"> <b><?php echo $row[USERNAME]; ?></b> </TD> </TR> <TR> <TD CLASS="tdmenu" WIDTH="40%">Password *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="PASSWORD" NAME="PASSWORD" SIZE="40" VALUE="<?php echo $row[PASSWORD]; ?>"> </TD> </TR> <TR> <TD CLASS="tdmenu" WIDTH="40%">Email Address *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="text" NAME="EMAIL" SIZE="40" VALUE="<?php echo $row[EMAIL]; ?>"> </TD> </TR> <TR> <TD CLASS="tdmenu" WIDTH="40%">Full Name *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="text" NAME="FULLNAME" SIZE="40" VALUE="<?php echo $row[FULLNAME]; ?>"> </TD> <TR> <TD CLASS="tdmenu" WIDTH="40%">Address *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="text" NAME="ADDRESS1" SIZE="40" VALUE="<?php echo $row[ADDRESS1]; ?>"> </TD> </TR> <BR> <TABLE CLASS="basictable"> <TR> <TD CLASS="tdhead2" > <DIV ALIGN="CENTER"><B> <INPUT TYPE="submit" NAME="Submit" VALUE="Submit"> </B></DIV> </TD> </TR> </TABLE> </FORM> and the it self as query_client.php inside look like: <?PHP @session_start(); $controller = $_POST['controller']; $pieces = explode("~", $controller); $table = $pieces[0]; $qt = $pieces[1]; $return = $pieces[2]; $id = $pieces[3]; $hack = $pieces[4]; if ($qt == insert) $qt = 'INSERT INTO'; if ($qt == update) { $qt = 'UPDATE'; $end = "WHERE ID = '$id'"; } $pre = array_keys( $_POST ); mysql_query ("CREATE TABLE IF NOT EXISTS `$table` (`ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY ( `id` ) )"); $count = count($pre); $count = $count - 2; $sql = "$qt $table SET"; for ($i=0; $i < $count; $i++) { $x=$i+1; $y = $_POST[$pre[$x]]; $d = $y; mysql_query ("ALTER TABLE `$table` ADD `$pre[$x]` TEXT NOT NULL"); $sql .= " `$pre[$x]` = '$d',"; } $sql .= " ID = '$id' $end"; $query = mysql_query($sql) or die("$sql_error" . mysql_error()); if (empty($hack)) { } else { $pieces = explode("/", $hack); $h0 = $pieces[0]; $h1 = $pieces[1]; $h2 = $pieces[2]; $h3 = $pieces[3]; $h4 = $pieces[4]; $h5 = $pieces[5]; mysql_query ("ALTER TABLE `$table` $h0 $h1 $h2 $h3 $h4 $h5"); $query = mysql_query($sql) or die("$sql_error" . mysql_error()); } if (isset($_GET[inc])) include "$_GET[inc].php"; ?> so please help me how to add md5 in PASSWORD field? thanks in advance..

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  • Problem while redirecting user after registration

    - by Eternal Learner
    I am creating a simple website . My situation is like this. After registering an user, I want to redirect the user after say 3 seconds to a main page(if the registration succeeds) . The code I have now is as below $query = "INSERT INTO Privileges VALUES('$user','$password1','$role')"; $result = mysql_query($query, $dbcon) or die('Registration Failed: ' . mysql_error()); print 'Thanks for Registering , You will be redirected shortly'; ob_start(); echo "Test"; header("Location: http://www.php.net"); ob_flush() I get the error message Warning: Cannot modify header information - headers already sent by (output started at/home/srinivasa/public_html/ThanksForRegistering.php:27) in /home/srinivasa /public_html/ThanksForRegistering.php on line 35. What do I need to do now ?

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  • Get the names of IDs from different table

    - by user896692
    I have an array with a lot of data from a database. In the array, there are two fields called teameinsid and teamzweiid. The query is a very simple one : $spiel = mysql_query("select teameinsid, teamzweiid from begegnung", $connection) or die("Keine passende Begegnung"); What I need is to search in the database for the names of these IDs. The names are in a different table. What I have now is the following: while($tmp = mysql_fetch_array($spiel)){ $teins = $tmp['teameinsid']; $tzwei = $tmp['teamzweiid']; } So I know the two IDs, but I don't know where to save the names. If I try: $name = mysql_query("select name from team where teameinsid = $teins", $con) it gets overwritten every time. How can I manage this?

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  • How do I call Informix stored procedures from Perl?

    - by superjtc
    How do I call informix stored procedures from Perl? I use DBD::ODBC to connect to informix database, but I don't know how to call procedures. my code like this: my $dbh=DBI->connect("dbi:".DBDRIVE.":".DBNAME,DBUSER,DBPASS,{RaiseError=>0,PrintError=>0,AutoCommit=>1}) ||die $DBI::errstr; $dbh->do("execute procedure sp_test('2010-05-01 00:00:00')") || warn "failed\n"; $dbh->disconnect(); when I run it, it didn't get error. But I get nothing when I check the database. the store procedure works fine if I run it in database directly. Anyone can help me out?

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  • [Perl] Append a text File inside a Zip

    - by aleroot
    i have zip file inside a Text file (file.txt inside a file.zip) and i would have to append to this file another text file file.txt outside the zip file. How Can i do ? Is there a solution ? I've tried to add Append =1 parameters to IO::Compress::Zip but the file inside the zip been overwritten .. use IO::Compress::Zip qw(zip $ZipError) ; $filenameToZip = 'file.txt'; zip $filenameToZip => "file.zip",Append => 1 or die "zip failed: $ZipError\n"; Need i to decompress the zip, append/merge the two TXT file's and compress the file Again ? Or Is There a better Solution ?

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  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • php/mySQL error: mysql_num_rows(): supplied argument is not a valid MySQL result

    - by Michael Robinson
    I'm trying to INSERT INTO a mySQL database and I'm getting this error on: if (mysql_num_rows($login) == 1){ Here is the php, The php does add the user to the database. I can't figure it out. <? session_start(); require("config.php"); $u = $_GET['username']; $pw = $_GET['password']; $pwh = $_GET['passwordhint']; $em = $_GET['email']; $zc = $_GET['zipcode']; $check = "INSERT INTO family (loginName, email, password, passwordhint, location) VALUES ('$u', '$pw', '$pwh', '$em', '$zc')"; $login = mysql_query($check, $link) or die(mysql_error()); if (mysql_num_rows($login) == 1) { $row = mysql_fetch_assoc($login); echo 'Yes';exit; } else { echo 'No';exit; } mysql_close($link); ?> Thanks,

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  • Cannot insert into SQLite database through php PDO

    - by user323941
    Pls help see what is wrong.... (I test the db connection is fine) <?php $user_name=$_POST['user_name']; $password=$_POST['password']; $dbh=new PDO('sqlite:./db/user.db') or die("fail to connect db"); try{ $stmt = $dbh->prepare("INSERT INTO user_info VALUES (?, ?)"); $stmt->bindParam(1, $a); $stmt->bindParam(2, $b); $a=$user_name; $b=$password; $stmt->execute(); } catch(PDOException $e) {echo $e->getMessage();} ?>

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  • php var_dump returning blank array

    - by Oroku
    I'm following this tutorial on youtube: https://www.youtube.com/watch?v=VSF5p00uorc Around 4:28 - I get the following array when I load the sql.php page as in the tutorial: array(8) { [1]=> NULL [2]=> NULL [3]=> NULL [4]=> NULL [5]=> NULL [6]=> NULL [7]=> NULL [8]=> NULL } I do have 8 ids all with values in my data table. This is my code: <?php $con = mysqli_connect("localhost","root","","test2") or die('error'); $query = "select * from data"; $result = mysqli_query($con,$query); while($row = mysqli_fetch_array($result)) { $id = $row['id']; $feed = $row['feed']; $data[$id] = $feed; } var_dump($data); ?>

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  • MySQL Database || Tables Issue

    - by user1780103
    I'm trying to write up a script where the user is able to purchase an amount of points for dollars. I want the transaction to be inserted into MySQL. I keep facing a: "Column count doesn't match value count at row 1" error. And I have no idea what I'm doing wrong. I have written up this: mysql_query("INSERT INTO paypal_donations VALUES (NULL, ".$account_id.", ".$char_id.", ".$price.", ".$dp.", NOW(), NOW(), 'Started', 0, 0, '', '');") or die(mysql_error()); But I don't know what to execute in MySQL, since I've never worked with it before. Could anyone write up a quick script that I can insert into MySQL for it to work.

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  • php/mysql question, retrieving information

    - by chance
    Hey SO, I have a question, pretty new at PHP and MySql but was curious is it possible to display only the most recent column to a table, from a database? I know it is possible to display a list of all information, or if you have just one column of information in your table to display that using the Here is my code for my basic script (just loads 1 column of information) I would like it to only print out the recent column i added to the table $con = mysql_connect ("localhost","username","password"); if (!$con) { die ('Could not connect:' . mysql_error()0; } mysql_select_db("db_name", $con); $result = mysql_query(Select column FROM table"); while($row = mysql_fetch_array($result)) { echo $row['column']; } mysql_close($con); * keep in mind, im not looking for someone to shoot me my code with it completed, though it would be handy, however just giving me the options of what I have to do, or what the script is called would be plentiful enough for my research, thanks!

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  • How can I check if a value is in a list in Perl?

    - by ablimit
    I have a file in which every line is an integer which represents an id. What I want to do is just check whether some specific ids are in this list. But the code didn't work. It never tells me it exists even if 123 is a line in that file. I don't know why? Help appreciated. open (FILE, "list.txt") or die ("unable to open !"); my @data=<FILE>; my %lookup =map {chop($_) => undef} @data; my $element= '123'; if (exists $lookup{$element}) { print "Exists"; } Thanks in advance.

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  • Confused on the basics of AJAX

    - by Doug
    So right now, I'm just using a basic form to check a password. I want it to check the password and basically remain on page.html so I can use JavaScript to alert incorrect password or something. I'm not really sure how to do that. It seems it would bring me to check.php. I'm not too sure on the whole process, any help appreciated! Thanks! Page.html <form action="check.php" method="post"> <input type="password" name="password" /> <input type="submit" value="Submit" /> </form> check.php <?php $password = $_POST['password']; if ( $password != "testing" ) { die(); } ?>

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  • How do stop form posting to mysql if database contains a specific ID?

    - by user342391
    I have a form that I am using to post data to mysql. Before submitting the form I want to check the database and see if there are any fields in the column 'customerid' that equal 'userid' and if so not to post the form. Basically, I am trying to limit my users from posting more than once. Users will be able to login to my system and make ONE post. They will be able to delete and modify their post but are only limited to one post. How would I do this??? Code so far: <?php include '../login/dbc.php'; page_protect(); $userid = $_SESSION['user_id']; $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[userid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • Pushin each_line into array not working

    - by zettt
    Hi, I've got a weird issue with Ruby. I want to read data from a file and put the data then into an array. The weird thing is, it's working in another script which does basically, the same thing. quoteArray = [] quoteFile = File.new("quotes.txt", "r") or die "Unable to open file..." quoteFile.each_line { |line| quoteArray.push line } puts quoteArray[0] All I get out of this is an array with one element where the whole text file is in. What's wrong? Is it my machine? The text file? Any ideas? Thanks in advance

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  • PHP setcookie warning

    - by Ranking
    Hello guys, I have a problem with 'setcookie' in PHP and I can't solve it. so I receive this error "Warning: Cannot modify header information - headers already sent by (output started at C:\Program Files\VertrigoServ\www\vote.php:14) in C:\Program Files\VertrigoServ\www\vote.php on line 86" and here is the file.. line 86 is setcookie ($cookie_name, 1, time()+86400, '/', '', 0); is there any other way to do this ?? <html> <head> <title>Ranking</title> <link href="style.css" rel="stylesheet" type="text/css"> </head> <body bgcolor="#EEF0FF"> <div align="center"> <br/> <div align="center"><div id="header"></div></div> <br/> <table width="800" border="0" align="center" cellpadding="5" cellspacing="0" class="mid-table"> <tr><td height="5"> <center> <table border="0" cellpadding="0" cellspacing="0" align="center" style="padding-top:5px;"> <tr> <td align="center" valign="top"><img src="images/ads/top_banner.png"></td> </tr> </table> </center> </td></tr> <tr><td height="5"></td></tr> </table> <br/> <?php include "conf.php"; $id = $_GET['id']; if (!isset($_POST['submitted'])) { if (isset($_GET['id']) && is_numeric($_GET['id'])) { $id = mysql_real_escape_string($_GET['id']); $query = mysql_query("SELECT SQL_CACHE id, name FROM s_servers WHERE id = $id"); $row = mysql_fetch_assoc($query); ?> <form action="" method="POST"> <table width="800" height="106" border="0" align="center" cellpadding="3" cellspacing="0" class="mid-table"> <tr><td><div align="center"> <p>Code: <input type="text" name="kod" class="port" /><img src="img.php" id="captcha2" alt="" /><a href="javascript:void(0);" onclick="document.getElementById('captcha2').src = document.getElementById('captcha2').src + '?' + (new Date()).getMilliseconds()">Refresh</a></p><br /> <p><input type="submit" class="vote-button" name="vote" value="Vote for <?php echo $row['name']; ?>" /></p> <input type="hidden" name="submitted" value="TRUE" /> <input type="hidden" name="id" value="<?php echo $row['id']; ?>" /> </div></td></tr> <tr><td align="center" valign="top"><img src="images/ads/top_banner.png"></td></tr> </table> </form> <?php } else { echo '<font color="red">You must select a valid server to vote for it!</font>'; } } else { $kod=$_POST['kod']; if($kod!=$_COOKIE[imgcodepage]) { echo "The code does not match"; } else { $id = mysql_real_escape_string($_POST['id']); $query = "SELECT SQL_CACHE id, votes FROM s_servers WHERE id = $id"; $result = mysql_query($query) OR die(mysql_error()); $row = mysql_fetch_array($result, MYSQL_ASSOC); $votes = $row['votes']; $id = $row['id']; $cookie_name = 'vote_'.$id; $ip = $_SERVER['REMOTE_ADDR']; $ltime = mysql_fetch_assoc(mysql_query("SELECT SQL_CACHE `time` FROM `s_votes` WHERE `sid`='$id' AND `ip`='$ip'")); $ltime = $ltime['time'] + 86400; $time = time(); if (isset($_COOKIE['vote_'.$id]) OR $ltime > $time) { echo 'You have already voted in last 24 hours! Your vote is not recorded.'; } else { $votes++; $query = "UPDATE s_servers SET votes = $votes WHERE id = $id"; $time = time(); $query2 = mysql_query("INSERT INTO `s_votes` (`ip`, `time`, `sid`) VALUES ('$ip', '$time', '$id')"); $result = mysql_query($query) OR die(mysql_error()); setcookie ($cookie_name, 1, time()+86400, '/', '', 0); } } } ?> <p><a href="index.php">[Click here if you don't want to vote]</a></p><br/> <p><a href="index.php">Ranking.net</a> &copy; 2010-2011<br> </p> </div> </body> </html> Thanks a lot!

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  • Duplication in mysql/php

    - by user1334095
    I have a problem in the code.i have two tables 'sms' and 'bd_paid_bribe'.sms table has a column 'Message' and bd_paid_bribe table has a column 'c_addi_info'.when i execute the code first time all the values of Message column are inserted into c_addi_info column.when i enter a record for the second time instead of inserting the new record, all the records of Message column are inserted into bd_paid_bribe column.can u modify the code and provide a solution to avoid duplication and to insert only the newly added record. <?php $con=mysql_connect('localhost','root',''); if(!$con) { die("couldn't connect"); } mysql_select_db("ipab2",$con); $rs2=mysql_query(" select max(sms_index) from tab3"); do { $rs=mysql_query("insert into tab3(sms_index)select max(sms_index) from sms"); $rs3=mysql_query("SELECT max(sms_index) FROM sms"); $rs1=mysql_query("insert into bd_paid_bribe(c_addi_info) select Message from sms "); }while($rs2>$rs3); ?>

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  • Perl - Choose interface to connect through

    - by Dieterve
    I have 2 interfaces on my server, eth0 and eth0:0. Those are 2 different external ips and obviously 2 different reverse domains. When i open a IO::Socket::INET Perl uses the eth0 interface by default. I would like to use the second interface (eth0:0) because this has a different ip and i dont want to use my main ip/domain. I have absolutely no idea how to select which interface to connect through. Code i use to open a socket: my $sock = new IO::Socket::INET(PeerAddr => $server, PeerPort => $serverPort, Proto => 'tcp') or die "Can't connect to server: $!";

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