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  • WCF Double Hop questions about Security and Binding.

    - by Ken Maglio
    Background information: .Net Website which calls a service (aka external service) facade on an app server in the DMZ. This external service then calls the internal service which is on our internal app server. From there that internal service calls a stored procedure (Linq to SQL Classes), and passes the serialized data back though to the external service, and from there back to the website. We've done this so any communication goes through an external layer (our external app server) and allows interoperability; we access our data just like our clients consuming our services. We've gotten to the point in our development where we have completed the system and it all works, the double hop acts as it should. However now we are working on securing the entire process. We are looking at using TransportWithMessageCredentials. We want to have WS2007HttpBinding for the external for interoperability, but then netTCPBinding for the bridge through the firewall for security and speed. Questions: If we choose WS2007HttpBinding as the external services binding, and netTCPBinding for the internal service is this possible? I know WS-* supports this as does netTCP, however do they play nice when passing credential information like user/pass? If we go to Kerberos, will this impact anything? We may want to do impersonation in the future. If you can when you answer post any reference links about why you're answering the way you are, that would be very helpful to us. Thanks!

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  • Cross-platform game development: ease of development vs security

    - by alcuadrado
    Hi, I'm a member and contributor of the Argentum Online (AO) community, the first MMORPG from Argentina, which is Free Software; which, although it's not 3D, it's really addictive and has some dozens of thousands of users. Really unluckily AO was developed in Visual Basic (yes, you can laugh) but the former community, so imagine, the code not only sucks, it has zero portability. I'm planning, with some friends to rewrite the client, and as a GNU/Linux frantic, want to do it cross-platform. Some other people is doing the same with the server in Java. So my biggest problem is that we would like to use a rapid development language (like Java, Ruby or Python) but the client would be pretty insecure. Ruby/Python version would have all it's code available, and the Java one would be easily decompilable (yes, we have some crackers in the community) We have consider the option to implement the security module in C/C++ as a dynamic library, but it can be replaced with a custom one, so it's not really secure. We are also considering the option of doing the core application in C++ and the GUI in Ruby/Python. But haven't analysed all it's implications yet. But we really don't want to code the entire game in C/C++ as it doesn't need that much performance (the game is played at 18fps on average) and we want to develop it as fast as possible. So what would you choose in my case? Thank you!

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  • silverlight security with WCF service, Forms Authentication and Custom Form Ticket

    - by user74825
    I have a silverlight application with login on the silverlight page. It uses Forms Authentication with WCF authentication service and customer Membership Provider. Something like : http://blogs.msdn.com/phaniraj/archive/2009/09/10/using-the-ado-net-data-services-silverlight-client-library-in-x-domain-and-out-of-browser-scenarios-ii-forms-authentication.aspx So, SL page login page calls the WCF service authentication service, it validates using DB - brings back username and password. Now, in each subsequent calls (in Global.asax in Authenticate_Request, I get HttpContext.User.IsAuthenticated and HttpContext.User.UserName). I have all this working properly. But, I just don't want the username, but more information surrounding the user, like UserId, UserAddress, UserAssociateCustomer etc. I tried couple of different approaches. 1) Use HttpContext.Cache as a dictionary to save the item and get it off based on httpcontext.user.name, problem is cache can be erased if there memory is being used heavily. 2) Tried CustomFormsAuth Ticket, when forms authentication writes a ticket, I intercept CreatingCookie method and write additional info in formauthentication ticket, so that I can read it in subsequent requests, I am having problems with this approach, I don't find the ticket in subsequent requests. I read about how we should use REsponse.Redirect, but where do I redirect user from WCF call. How do you guys implement the above scenario? Any best practices.? Any issues you see with going on HTTPS? All examples (or most of them) just explains simple forms authentication with "I am logged in message".. Any suggestions ?

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  • how to retrive pK using spring security

    - by aditya
    i implement this method of the UserDetailService interface, public UserDetails loadUserByUsername(final String username) throws UsernameNotFoundException, DataAccessException { final EmailCredential userDetails = persistentEmailCredential .getUniqueEmailCredential(username); if (userDetails == null) { throw new UsernameNotFoundException(username + "is not registered"); } final HashSet<GrantedAuthority> authorities = new HashSet<GrantedAuthority>(); authorities.add(new GrantedAuthorityImpl("ROLE_USER")); for (UserRole role:userDetails.getAccount().getRoles()) { authorities.add(new GrantedAuthorityImpl(role.getRole())); } return new User(userDetails.getEmailAddress(), userDetails .getPassword(), true, true, true, true, authorities); } in the security context i do some thing like this <!-- Login Info --> <form-login default-target-url='/dashboard.htm' login-page="/login.htm" authentication-failure-url="/login.htm?authfailed=true" always-use-default-target='false' /> <logout logout-success-url="/login.htm" invalidate-session="true" /> <remember-me user-service-ref="emailAccountService" key="fuellingsport" /> <session-management> <concurrency-control max-sessions="1" /> </session-management> </http> now i want to pop out the Pk of the logged in user, how can i show it in my jsp pages, any idea thanks in advance

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  • security deleting a mysql row with jQuery $.post

    - by FFish
    I want to delete a row in my database and found an example on how to do this with jQuery's $.post() Now I am wondering about security though.. Can someone send a POST request to my delete-row.php script from another website? JS function deleterow(id) { // alert(typeof(id)); // number if (confirm('Are you sure want to delete?')) { $.post('delete-row.php', {album_id:+id, ajax:'true'}, function() { $("#row_"+id).fadeOut("slow"); }); } } PHP: delete-row.php <?php require_once("../db.php"); mysql_connect(DB_SERVER, DB_USER, DB_PASSWORD) or die("could not connect to database " . mysql_error()); mysql_select_db(DB_NAME) or die("could not select database " . mysql_error()); if (isset($_POST['album_id'])) { $query = "DELETE FROM albums WHERE album_id = " . $_POST['album_id']; $result = mysql_query($query); if (!$result) die('Invalid query: ' . mysql_error()); echo "album deleted!"; } ?>

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  • Problem with Spring security's logout

    - by uther-lightbringer
    Hello, I've got a problem logging out in Spring framework. First when I want j_spring_security_logout to handle it for me i get 404 j_spring_security_logout not found: sample-security.xml: <http> <intercept-url pattern="/messageList.htm*" access="ROLE_USER,ROLE_GUEST" /> <intercept-url pattern="/messagePost.htm*" access="ROLE_USER" /> <intercept-url pattern="/messageDelete.htm*" access="ROLE_ADMIN" /> <form-login login-page="/login.jsp" default-target-url="/messageList.htm" authentication-failure-url="/login.jsp?error=true" /> <logout/> </http> Sample url link to logout in JSP page: <a href="<c:url value="/j_spring_security_logout" />">Logout</a> When i try to use a custom JSP page i.e. I use login form for this purpose then I get better result at least it gets to login page, but another problem is that you dont't get logged off as you can diretcly type url that should be guarded buy you get past it anyway. Slightly modified from previous listings: <http> <intercept-url pattern="/messageList.htm*" access="ROLE_USER,ROLE_GUEST" /> <intercept-url pattern="/messagePost.htm*" access="ROLE_USER" /> <intercept-url pattern="/messageDelete.htm*" access="ROLE_ADMIN" /> <form-login login-page="/login.jsp" default-target-url="/messageList.htm" authentication-failure-url="/login.jsp?error=true" /> <logout logout-success-url="/login.jsp" /> </http> <a href="<c:url value="/login.jsp" />">Logout</a> Thank you for help

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  • E-Commerce Security: Only Credit Card Fields Encrypted?!

    - by bizarreunprofessionalanddangerous
    I'd like your opinions on how a major bricks-and-mortar company is running the security for its shopping Web site. After a recent update, when you are logged into your shopping account, the session is now not secured. No 'https', no browser 'lock'. All the personal contact info, shopping history -- and if I'm not mistaken submit and change password -- are being sent unencrypted. There is a small frame around the credit card fields that is https. There's a little notice: "Our website is secure. Our website uses frames and because of this the secure icon will not appear in your browser" On top of this the most prominent login fields for the site are broken, and haven't gotten fixed for a week or longer (giving the distinct impression they have no clue what's going on and can't be trusted with anything). Now is it just me -- or is this simply incomprehensible for a billion dollar company, significant shopping site, in the year 2010. No lock. "We use frames" (maybe they forget "Best viewed in IE4"). Customers complaining, as you can see from their FAQ "explaining" why you aren't seeing https. I'm getting nowhere trying to convince customer service that they REALLY need to do something about this, and am about to head for the CEO. But I just want to make sure this is as BIZARRE and unprofessional and dangerous a situation as I think it is. (I'm trying to visualize what their Web technical team consists of. I'm getting A) some customer service reps who were given a 3 hour training course on Web site maintenance, B) a 14 year old boy in his bedroom masquerading as a major technical services company, C) a guy in a hut in a jungle with an e-commerce book from 1996.)

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  • What is the best prctice for using security in JAX-WS

    - by kislo_metal
    Here is scenario : I have some web services (JAX-WS) that need to be secured. Currently for authentication needs I providing addition SecurityWService that give authorized user some userid & sessionid that is need to be described in request to other services. It would be more better to use some java security. We have many of them but could not defined what is better to use. Q1 : It is understand that I should use SSL in transport layer, but what should I use for user authorization. Is there is better way to establishing session, validating user etc. ? Here is some key description : Most web services clents is php based. I am using jax-ws implementation as a Stateless session EJB. Deploying to glassfish v3. Q2: what is the best framework / technology for user authorization / authentication in case of using JSF 2.0 and ejb3.1 technologies ( Realms? WSIT? )? Thank You!

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  • How to manually set an authenticated user in Spring Security / SpringMVC

    - by David Parks
    After a new user submits a 'New account' form, I want to manually log that user in so they don't have to login on the subsequent page. The normal form login page going through the spring security interceptor works just fine. In the new-account-form controller I am creating a UsernamePasswordAuthenticationToken and setting it in the SecurityContext manually: SecurityContextHolder.getContext().setAuthentication(authentication); On that same page I later check that the user is logged in with: SecurityContextHolder.getContext().getAuthentication().getAuthorities(); This returns the authorities I set earlier in the authentication. All is well. But when this same code is called on the very next page I load, the authentication token is just UserAnonymous. I'm not clear why it did not keep the authentication I set on the previous request. Any thoughts? Could it have to do with session ID's not being set up correctly? Is there something that is possibly overwriting my authentication somehow? Perhaps I just need another step to save the authentication? Or is there something I need to do to declare the authentication across the whole session rather than a single request somehow? Just looking for some thoughts that might help me see what's happening here.

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  • Struts 2 security

    - by Dewfy
    Does Struts 2 has complete solution for simple login task? I have simple declaration in struts.xml: <package namespace="/protected" name="manager" extends="struts-default" > <interceptors> <interceptor-stack name="secure"> <interceptor-ref name="roles"> <param name="allowedRoles">registered</param> </interceptor-ref> </interceptor-stack> </interceptors> <default-action-ref name="pindex"/> <action name="pindex" > <interceptor-ref name="completeStack"/> <interceptor-ref name="secure"/> <result>protected/index.html</result> </action> </package> Accessing to this resource shows only (Forbidden 403). So what should I do on the next step to: Add login page (standart Tomcat declaration on web.xml with <login-config> not works) ? Provide security round trip. Do I need write my own servlet or exists struts2 solutions? Thanks in advance!

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  • Protecting my apps security from deassembling

    - by sandis
    So I recently tested deassembling one of my android apps, and to my horror I discovered that the code was quite readable. Even worse, all my variable names where intact! I thought that those would be compressed to something unreadable at compile time. The app is triggered to expire after a certain time. However, now it was trivial for me to find my function named checkIfExpired() and find the variable "expired". Is there any good way of making it harder for a potential hacker messing with my app? Before someone states the obvious: Yes, it is security through obscurity. But obviously this is my only option since the user always will have access to all my code. This is the same for all apps. The details of my deactivation-thingy is unimportant, the point is that I dont want deassembler to understand some of the things I do. side questions: Why are the variable names not compressed? Could it be the case that my program would run faster if I stopped using really long variable names, as are my habit?

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  • UDP security and identifying incoming data.

    - by Charles
    I have been creating an application using UDP for transmitting and receiving information. The problem I am running into is security. Right now I am using the IP/socketid in determining what data belongs to whom. However, I have been reading about how people could simply spoof their IP, then just send data as a specific IP. So this seems to be the wrong way to do it (insecure). So how else am I suppose to identify what data belongs to what users? For instance you have 10 users connected, all have specific data. The server would need to match the user data to this data we received. The only way I can see to do this is to use some sort of client/server key system and encrypt the data. I am curious as to how other applications (or games, since that's what this application is) make sure their data is genuine. Also there is the fact that encryption takes much longer to process than unencrypted. Although I am not sure by how much it will affect performance. Any information would be appreciated. Thanks.

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  • Security of Flex for payment website

    - by Mario
    So, it's been about 3 years since I wrote and went live with my company's main internet facing website. Originally written in php, I've since just been making minor changes here and there to progress the site as we've needed to. I've wanted to rewrite it from the ground up in the last year or so and now, we want to add some major features so this is a perfect time. The website in question is as close to a banking website as you'd get (without being a bank; sorry for the obscurity, but the less info I can give out, the better). For the rewrite, I want to separate the presentation layer from the processing layer as much as I can. I want the end user to be stuck in a box and not be able to get out so to speak (this is all because of PCI complacency, being PEN tested every 3 months, etc...) So, being probed every 3 months has increasingly made me nervous. We haven't failed yet and there hasen't been a breach yet, but I want to make sure I continue to pass (as much as I can anyways) So, I'm considering rewriting the presentation layer in Adobe Flex and do all the processing in PHP (effectively IMO, separating presentation from processing) - I would do all my normal form validation in flex (as opposed to javascript or php) and do my reads and writes to the db via php. My questions are: I know Flash has something like 99% market penetration - do people find this to be true? Has anyone seen on their own sites being in flash that someone couldn't access it? Flash in general has come under alot of attacks about security and the like - i know this. I would use a swf encryptor - disable debugging (which i got snagged on once on a different application), continue to use https and any other means i can think of. At the end of the day, everyone knows if someone wants in to the data bad enough, their going to find a ways in; i just wanna make it as difficult for them as i can. Any thoughts are appreciated. -Mario

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  • How to strengthen Mysql database server Security?

    - by i need help
    If we were to use server1 for all files (file server), server2 for mysql database (database server). In order for websites in server1 to access to the database in server2, isn't it needed to connect to to ip address of second (mysql server) ? In this case, is remote mysql connection. However, I seen from some people comment on the security issue. remote access to MySQL is not very secure. When your remote computer first connects to your MySQL database, the password is encrypted before being transmitted over the Internet. But after that, all data is passed as unencrypted "plain text". If someone was able to view your connection data (such as a "hacker" capturing data from an unencrypted WiFi connection you're using), that person would be able to view part or all of your database. So I just wondering ways to secure it? Allow remote mysql access from server1 by allowing the static ip adress allow remote access from server 1 by setting port allowed to connect to 3306 change 3306 to other port? Any advice?

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  • How can I cache a Subversion password on a server, without storing it in unencrypted form?

    - by Zilk
    My Subversion server only provides access via HTTPS; support for svn+ssh has been dropped because we wanted to avoid creating system users on that machine just for SVN access. Now I'm trying to provide a way for users to cache their passwords for a while, without leaving them stored on the filesystem in unencrypted form. This is no problem for Gnome or KDE users, because they can use gnome-keyring and kwallet, respectively. IIRC, TortoiseSVN has a similar caching mechanism, too. But what about users on a non-GUI system? Some context: in this case, we have a development/testing server where one project has been checked out into the Apache htdocs directory. Development for this project is almost complete, and only minor text/layout changes are performed directly on this server. Nevertheless, the changes should be checked into the repository. There's no kwallet and no gnome-keyring on this system, and the ssh-agent can't help because the repository is accessed via https instead of svn+ssh. As far as I know, that leaves them the choice of entering the password every time they talk to the SVN server, or storing it in an insecure way. Is there any way to get something like what gnome-keyring and kwallet provide in a non-GUI environment?

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  • Spring security problem, Error creating bean with name 'org.springframework.web.servlet.mvc.annotati

    - by benaissa
    Hello; I'm developping a web application with spring mvc, i started by developping the web application after i'm trying to add spring security; but i have this message, and i don't find a solution, thanks 16-04-2010 12:10:22:296 6062 ERROR org.springframework.web.servlet.DispatcherServlet - Context initialization failed org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping': Initialization of bean failed; nested exception is java.lang.NoClassDefFoundError: org/springframework/beans/factory/generic/GenericBeanFactoryAccessor at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:527) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:286) at org.springframework.web.servlet.DispatcherServlet.createDefaultStrategy(DispatcherServlet.java:770) at org.springframework.web.servlet.DispatcherServlet.getDefaultStrategies(DispatcherServlet.java:737) at org.springframework.web.servlet.DispatcherServlet.initHandlerMappings(DispatcherServlet.java:518) at org.springframework.web.servlet.DispatcherServlet.initStrategies(DispatcherServlet.java:410) at org.springframework.web.servlet.DispatcherServlet.onRefresh(DispatcherServlet.java:398) at org.springframework.web.servlet.FrameworkServlet.onApplicationEvent(FrameworkServlet.java:474) at org.springframework.context.event.GenericApplicationListenerAdapter.onApplicationEvent(GenericApplicationListenerAdapter.java:51) at org.springframework.context.event.SourceFilteringListener.onApplicationEventInternal(SourceFilteringListener.java:97) at org.springframework.context.event.SourceFilteringListener.onApplicationEvent(SourceFilteringListener.java:68) at org.springframework.context.event.SimpleApplicationEventMulticaster.multicastEvent(SimpleApplicationEventMulticaster.java:97) at org.springframework.context.support.AbstractApplicationContext.publishEvent(AbstractApplicationContext.java:301) at org.springframework.context.support.AbstractApplicationContext.finishRefresh(AbstractApplicationContext.java:888) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:426) at org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:402) at org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:316) at org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:282) at org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:126) at javax.servlet.GenericServlet.init(GenericServlet.java:212) at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1173) at org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:809) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:129) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:619) Caused by: java.lang.NoClassDefFoundError: org/springframework/beans/factory/generic/GenericBeanFactoryAccessor at org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping.determineUrlsForHandler(DefaultAnnotationHandlerMapping.java:113) at org.springframework.web.servlet.handler.AbstractDetectingUrlHandlerMapping.detectHandlers(AbstractDetectingUrlHandlerMapping.java:79) at org.springframework.web.servlet.handler.AbstractDetectingUrlHandlerMapping.initApplicationContext(AbstractDetectingUrlHandlerMapping.java:57) at org.springframework.context.support.ApplicationObjectSupport.initApplicationContext(ApplicationObjectSupport.java:119) at org.springframework.web.context.support.WebApplicationObjectSupport.initApplicationContext(WebApplicationObjectSupport.java:69) at org.springframework.context.support.ApplicationObjectSupport.setApplicationContext(ApplicationObjectSupport.java:73) at org.springframework.context.support.ApplicationContextAwareProcessor.invokeAwareInterfaces(ApplicationContextAwareProcessor.java:99) at org.springframework.context.support.ApplicationContextAwareProcessor.postProcessBeforeInitialization(ApplicationContextAwareProcessor.java:82) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyBeanPostProcessorsBeforeInitialization(AbstractAutowireCapableBeanFactory.java:394) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1405) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:519) ... 32 more Caused by: java.lang.ClassNotFoundException: org.springframework.beans.factory.generic.GenericBeanFactoryAccessor at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1516) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1361) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) ... 43 more

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  • How to protect UI components using OPSS Resource Permissions

    - by frank.nimphius
    v\:* {behavior:url(#default#VML);} o\:* {behavior:url(#default#VML);} w\:* {behavior:url(#default#VML);} .shape {behavior:url(#default#VML);} Normal 0 false false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} table.MsoTableGrid {mso-style-name:"Table Grid"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-priority:59; mso-style-unhide:no; border:solid black 1.0pt; mso-border-alt:solid black .5pt; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-border-insideh:.5pt solid black; mso-border-insidev:.5pt solid black; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Times New Roman","serif";} ADF security protects ADF bound pages, bounded task flows and ADF Business Components entities with framework specific JAAS permissions classes (RegionPermission, TaskFlowPermission and EntityPermission). If used in combination with the ADF security expression language and security checks performed in Java, this protection already provides you with fine grained access control that can also be used to secure UI components like buttons and input text field. For example, the EL shown below disables the user profile panel tabs for unauthenticated users: <af:panelTabbed id="pt1" position="above">   ...   <af:showDetailItem        text="User Profile" id="sdi2"                                       disabled="#{!securityContext.authenticated}">   </af:showDetailItem>   ... </af:panelTabbed> The next example disables a panel tab item if the authenticated user is not granted access to the bounded task flow exposed in a region on this tab: <af:panelTabbed id="pt1" position="above">   ...   <af:showDetailItem text="Employees Overview" id="sdi4"                        disabled="#{!securityContext.taskflowViewable         ['/WEB-INF/EmployeeUpdateFlow.xml#EmployeeUpdateFlow']}">   </af:showDetailItem>   ... </af:panelTabbed> Security expressions like shown above allow developers to check the user permission, authentication and role membership status before showing UI components. Similar, using Java, developers can use code like shown below to verify the user authentication status: ADFContext adfContext = ADFContext.getCurrent(); SecurityContext securityCtx = adfContext.getSecurityContext(); boolean userAuthenticated = securityCtx.isAuthenticated(); Note that the Java code lines use the same security context reference that is used with expression language. But is this all that there is? No ! The goal of ADF Security is to enable all ADF developers to build secure web application with JAAS (Java Authentication and Authorization Service). For this, more fine grained protection can be defined using the ResourcePermission, a generic JAAS permission class owned by the Oracle Platform Security Services (OPSS).  Using the ResourcePermission  class, developers can grant permission to functional parts of an application that are not protected by page or task flow security. For example, an application menu allows creating and canceling product shipments to customers. However, only a specific user group - or application role, which is the better way to use ADF Security - is allowed to cancel a shipment. To enforce this rule, a permission is needed that can be used declaratively on the UI to hide a menu entry and programmatically in Java to check the user permission before the action is performed. Note that multiple lines of defense are what you should implement in your application development. Don't just rely on UI protection through hidden or disabled command options. To create menu protection permission for an ADF Security enable application, you choose Application | Secure | Resource Grants from the Oracle JDeveloper menu. The opened editor shows a visual representation of the jazn-data.xml file that is used at design time to define security policies and user identities for testing. An option in the Resource Grants section is to create a new Resource Type. A list of pre-defined types exists for you to create policy definitions for. Many of these pre-defined types use the ResourcePermission class. To create a custom Resource Type, for example to protect application menu functions, you click the green plus icon next to the Resource Type select list. The Create Resource Type editor that opens allows you to add a name for the resource type, a display name that is shown when granting resource permissions and a description. The ResourcePermission class name is already set. In the menu protection sample, you add the following information: Name: MenuProtection Display Name: Menu Protection Description: Permission to grant menu item permissions OK the dialog to close the resource permission creation. To create a resource policy that can be used to check user permissions at runtime, click the green plus icon in the Resources section of the Resource Grants section. In the Create Resource dialog, provide a name for the menu option you want to protect. To protect the cancel shipment menu option, create a resource with the following settings Resource Type: Menu Protection Name: Cancel Shipment Display Name: Cancel Shipment Description: Grant allows user to cancel customer good shipment   A new resource Cancel Shipmentis added to the Resources panel. Initially the resource is not granted to any user, enterprise or application role. To grant the resource, click the green plus icon in the Granted To section, select the Add Application Role option and choose one or more application roles in the opened dialog. Finally, you click the process action to define the policy. Note that permission can have multiple actions that you can grant individually to users and roles. The cancel shipment permission for example could have another action "view" defined to determine which user should see that this option exist and which users don't. To use the cancel shipment permission, select the disabled property on a command item, like af:commandMenuItem and click the arrow icon on the right. From the context menu, choose the Expression Builder entry. Expand the ADF Bindings | securityContext node and click the userGrantedResource option. Hint: You can expand the Description panel below the EL selection panel to see an example of how the grant should look like. The EL that is created needs to be manually edited to show as #{!securityContext.userGrantedResource[               'resourceName=Cancel Shipment;resourceType=MenuProtection;action=process']} OK the dialog so the permission checking EL is added as a value to the disabled property. Running the application and expanding the Shipment menu shows the Cancel Shipments menu item disabled for all users that don't have the custom menu protection resource permission granted. Note: Following the steps listed above, you create a JAAS permission and declaratively configure it for function security in an ADF application. Do you need to understand JAAS for this? No!  This is one of the benefits that you gain from using the ADF development framework. To implement multi lines of defense for your application, the action performed when clicking the enabled "Cancel Shipments" option should also check if the authenticated user is allowed to use process it. For this, code as shown below can be used in a managed bean public void onCancelShipment(ActionEvent actionEvent) {       SecurityContext securityCtx =       ADFContext.getCurrent().getSecurityContext();   //create instance of ResourcePermission(String type, String name,   //String action)   ResourcePermission resourcePermission =     new ResourcePermission("MenuProtection","Cancel Shipment",                            "process");        boolean userHasPermission =          securityCtx.hasPermission(resourcePermission);   if (userHasPermission){       //execute privileged logic here   } } Note: To learn more abput ADF Security, visit http://download.oracle.com/docs/cd/E17904_01/web.1111/b31974/adding_security.htm#BGBGJEAHNote: A monthly summary of OTN Harvest blog postings can be downloaded from ADF Code Corner. The monthly summary is a PDF document that contains supporting screen shots for some of the postings: http://www.oracle.com/technetwork/developer-tools/adf/learnmore/index-101235.html

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  • WCF security via message headers

    - by exalted
    I'm trying to implement "some sort of" server-client & zero-config security for some WCF service. The best (as well as easiest to me) solution that I found on www is the one described at http://www.dotnetjack.com/post/Automate-passing-valuable-information-in-WCF-headers.aspx (client-side) and http://www.dotnetjack.com/post/Processing-custom-WCF-header-values-at-server-side.aspx (corrisponding server-side). Below is my implementation for RequestAuth (descibed in the first link above): using System; using System.Diagnostics; using System.ServiceModel; using System.ServiceModel.Configuration; using System.ServiceModel.Dispatcher; using System.ServiceModel.Description; using System.ServiceModel.Channels; namespace AuthLibrary { /// <summary> /// Ref: http://www.dotnetjack.com/post/Automate-passing-valuable-information-in-WCF-headers.aspx /// </summary> public class RequestAuth : BehaviorExtensionElement, IClientMessageInspector, IEndpointBehavior { [DebuggerBrowsable(DebuggerBrowsableState.Never)] private string headerName = "AuthKey"; [DebuggerBrowsable(DebuggerBrowsableState.Never)] private string headerNamespace = "http://some.url"; public override Type BehaviorType { get { return typeof(RequestAuth); } } protected override object CreateBehavior() { return new RequestAuth(); } #region IClientMessageInspector Members // Keeping in mind that I am SENDING something to the server, // I only need to implement the BeforeSendRequest method public void AfterReceiveReply(ref System.ServiceModel.Channels.Message reply, object correlationState) { throw new NotImplementedException(); } public object BeforeSendRequest(ref System.ServiceModel.Channels.Message request, System.ServiceModel.IClientChannel channel) { MessageHeader<string> header = new MessageHeader<string>(); header.Actor = "Anyone"; header.Content = "TopSecretKey"; //Creating an untyped header to add to the WCF context MessageHeader unTypedHeader = header.GetUntypedHeader(headerName, headerNamespace); //Add the header to the current request request.Headers.Add(unTypedHeader); return null; } #endregion #region IEndpointBehavior Members public void AddBindingParameters(ServiceEndpoint endpoint, System.ServiceModel.Channels.BindingParameterCollection bindingParameters) { throw new NotImplementedException(); } public void ApplyClientBehavior(ServiceEndpoint endpoint, ClientRuntime clientRuntime) { clientRuntime.MessageInspectors.Add(this); } public void ApplyDispatchBehavior(ServiceEndpoint endpoint, EndpointDispatcher endpointDispatcher) { throw new NotImplementedException(); } public void Validate(ServiceEndpoint endpoint) { throw new NotImplementedException(); } #endregion } } So first I put this code in my client WinForms application, but then I had problems signing it, because I had to sign also all third-party references eventhough http://msdn.microsoft.com/en-us/library/h4fa028b(v=VS.80).aspx at section "What Should Not Be Strong-Named" states: In general, you should avoid strong-naming application EXE assemblies. A strongly named application or component cannot reference a weak-named component, so strong-naming an EXE prevents the EXE from referencing weak-named DLLs that are deployed with the application. For this reason, the Visual Studio project system does not strong-name application EXEs. Instead, it strong-names the Application manifest, which internally points to the weak-named application EXE. I expected VS to avoid this problem, but I had no luck there, it complained about all the unsigned references, so I created a separate "WCF Service Library" project inside my solution containing only code above and signed that one. At this point entire solution compiled just okay. And here's my problem: When I fired up "WCF Service Configuration Editor" I was able to add new behavior element extension (say "AuthExtension"), but then when I tried to add that extension to my end point behavior it gives me: Exception has been thrown by the target of an invocation. So I'm stuck here. Any ideas?

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  • Is Flash a secure content delivery technology for password protected digital content?

    - by Merkel Fastia
    We are working on a project that would be a competitor to Yudu for online publishing and what we are debating is whether to use Flash for content security protection as Yudu does. See for example "The Testicle Cookbok" for which a limited (3-frame) preview is available before a password is requested by the Flash application running in the browser. Do you see any problems with this approach or could you recommend an alternative technology for password proected digital content?

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  • How to create column of type password in gridview?

    - by Preeti
    Hi, I am creating an application in which user selects files and provides credentials to open that file. For that i have created three columns in a gridview. User enters password in password column. I want to display '*' in place of characters like we can create a textbox of password type. I have tried this code on 'GridView_CellClick' event : if (GridView.Columns[e.ColumnIndex].HeaderText == "Password") { txtPassword[e.RowIndex] = new TextBox(); txtPassword[e.RowIndex].Name = "txtPassword"+e.RowIndex; txtPassword[e.RowIndex].PasswordChar = '*'; txtPassword[e.RowIndex].Visible = true; txtPassword[e.RowIndex].TextChanged += new if (GridView.CurrentCell.Value == null) txtPassword[e.RowIndex].Text = ""; else txtPassword[e.RowIndex].Text = GridView.CurrentCell.Value.ToString(); txtPassword[e.RowIndex].Location = GridView.GetCellDisplayRectangle(e.ColumnIndex, e.RowIndex + 1, false).Location; txtPassword[e.RowIndex].Size = GridView.GetCellDisplayRectangle(e.ColumnIndex, e.RowIndex + 1, false).Size; txtPassword[e.RowIndex].Visible = true; txtPassword[e.RowIndex].Focus(); } But in above solution characters are displayed. How can i solve this problem???

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  • What's the difference between the input type "text" and "password" in an html form?

    - by Domingo
    Hi everybody, this question might seem stupid, but here's the situation: I'm trying to create an auto login page for my mail using jquery's post request, but it's not working, it works with all other pages except with webmail. So, trying to figure out what was wrong, I recreated the login form, here's the code: <form id="form1" name="form1" method="post" action="https://login.hostmonster.com/"> <label>User <input type="text" name="login" id="user" /> </label> <label>Pass <input name="password" type="password" id="pass" /> </label> <input name="doLogin" type="submit" id="doLogin" value="Login"> </form> The strange thing is when you change the input type of pass to text, the form doesn't work! I can't figure out why. Anyway, if you can tell me what's the real difference between the input type text and password (and not what it says everywhere on the net that the only difference is that when you type stars appear instead of characters) I would appreciate it. Also, do you think this is affecting my jquery's post? Here's the code for it: $j.post('https://login.hostmonster.com/', { login: '[email protected]', password: 'xxx' }, function(data, text){ if (text=='success') { alert('Success '+data); } else { alert('Failed'); } }); Thanks a lot! Regards, D

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  • How to reset the postgres super user password on mac os x

    - by Andrew Barinov
    I installed postgres on my mac running 10.6.8 and I would like to reset the password for the postgres user (I believe this is the super user password) and then restart it. All the directions I found do not work because I think my user name is not recognized by pg as having authority to change the password. (I am on the admin account of my mac) Here is what I tried: Larson-2:~ larson$ psql -U postgres Password for user postgres: psql (9.0.4, server 9.1.2) WARNING: psql version 9.0, server version 9.1. Some psql features might not work. Type "help" for help. postgres=# ALTER USER postgres with password 'mypassword' postgres-# \q and for restart I did: Larson-2:~ larson$ su postgres -c 'pg_ctl -D /opt/local/var/db/postgresql84/defaultdb/ restart > Which didn't work, as the password remained the same as it was before. Can someone provide directions for doing this and for making sure it's recognized by PG? Update I went ahead and edited the pg_hba.conf file located in /Library/PostgreSQL/9.1/data and set the settings as follows: # TYPE DATABASE USER ADDRESS METHOD # "local" is for Unix domain socket connections only local all all trust # IPv4 local connections: host all all 127.0.0.1/32 trust # IPv6 local connections: host all all ::1/128 trust However, like before, the password stayed the same after I changed it. I am not sure what further steps I can take from here.

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  • ssh - "Connection closed by xxx.xxx.xxx.xxx" - using password

    - by Michael B
    I attempted to create an new user account that I wish to use to log in using ssh. I did this (in CentOs): /usr/sbin/adduser -d /home/testaccount -s /bin/bash user passwd testaccount This is the error I receive when trying to log in via ssh: ~/.ssh$ ssh -v [email protected] OpenSSH_5.1p1 Debian-5ubuntu1, OpenSSL 0.9.8g 19 Oct 2007 debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug1: Connecting to xxx.xxx.xxx [xxx.xxx.xxx.xxx] port 22. debug1: Connection established. debug1: identity file /home/user/.ssh/identity type -1 debug1: identity file /home/user/.ssh/id_rsa type 1 debug1: Checking blacklist file /usr/share/ssh/blacklist.RSA-2048 debug1: Checking blacklist file /etc/ssh/blacklist.RSA-2048 debug1: identity file /home/user/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_4.3 debug1: match: OpenSSH_4.3 pat OpenSSH_4* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.1p1 Debian-5ubuntu1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-cbc hmac-md5 none debug1: kex: client->server aes128-cbc hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'xxx.xxx.xxx.xxx' is known and matches the RSA host key. debug1: Found key in /home/user/.ssh/known_hosts:8 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Next authentication method: gssapi-with-mic debug1: Unspecified GSS failure. Minor code may provide more information No credentials cache found debug1: Unspecified GSS failure. Minor code may provide more information No credentials cache found debug1: Unspecified GSS failure. Minor code may provide more information debug1: Next authentication method: publickey debug1: Offering public key: /home/user/.ssh/id_rsa debug1: Authentications that can continue: publickey,gssapi-with-mic,password debug1: Trying private key: /home/user/.ssh/identity debug1: Trying private key: /home/user/.ssh/id_dsa debug1: Next authentication method: password testaccount@xxx's password: Connection closed by xxx.xxx.xxx.xxx The "connection closed" message appeared immediately after entering the password (if I enter the wrong password it waits and then prompts for another password) I am able to log in from the same computer using other accounts that had been setup previously. When logged into the remote machine I am able to do 'su testaccount' Thanks for your time.

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  • ProtectedData.Unprotect() after Impersonate()

    - by Andrey
    The following code doesn't work: IntPtr token = Win32Dll.LogonUser(“user1”, “mydomain”, “password1”); WindowsIdentity id = new WindowsIdentity(token); WindowsImpersonationContext ic = id.Impersonate(); byte[] unprotectedBytes = ProtectedData.Unprotect(passwordBytes, null, DataProtectionScope.CurrentUser); password = Encoding.Unicode.GetString(unprotectedBytes); ic.Undo(); The password is not decrypted. MSDN said "If you use this method during impersonation, you may receive the following error: "Key not valid for use in specified state." This error can be prevented by loading the profile of the user you want to impersonate, before calling the method." I would be very grateful for the help!

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  • How to deecode your ODI encoded password in SDK

    - by tina.wang
    Someone asked me he want to use SDK to create ODI repository, but latest 11g API in SDK use plain password parameter. But he don't want to use plain text for security reason. So he want to transfer an encoded password, then decode it inside his code. He ask me whether there is a way.  After some investigating, I find com.sunopsis.dwg.DwgObject class has a static method snpsDecypher(String), it can satisfy his requirement. But seems this method is deprecated, I am trying to find the new replaced method. 

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