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  • Query that ignore the spaces.

    - by xRobot
    What's the best way to run a query so that spaces in the fields are ignored? For example the following queries.... SELECT * FROM mytable WHERE username = "JohnBobJones" SELECT * FROM mytable WHERE username = "John Bob Jones" . would find the following entries: John Bob Jones JohnBob Jones JohnBobJones . I am using php or python but I think this doesn't matter.

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  • Proxy Authentication Error while calling FedEx webservice

    - by Abdel Olakara
    Hi all, I am trying to call the FedEx tracking webservice. Currently I am running the sample application provided by FedEx itself (Added my test account number and other details). When I run the application, I get the following error: The remote server returned an error: (407) Proxy Authentication Required. I am inside a proxy at my organization and I tried provided the proxy server details to the webservice client using the WebProxy class as: trackService.Proxy = WebProxy.GetDefaultProxy(); and also by providing the proxy server details as: trackService.Proxy = new WebProxy("IP",8080); But I still keep getting the same error!! Could somebody help me how to resolve this problem? Thanks in advance, Regards, Abdel Olakara

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  • Update multiple rows with known keys without inserting new rows if nonexistent keys are found

    - by Kirzilla
    Hello, Let's imagine that we have table items... table: items item_id INT PRIMARY AUTO_INCREMENT title VARCHAR(255) views INT Let's imagine that it is filled with something like (1, item-1, 10), (2, item-2, 10), (3, item-3, 15) I want to make multi update view for this items from data taken from this array [item_id] = [views] '1' => '50', '2' => '60', '3' => '70', '5' => '10' IMPORTANT! Please note that we have item_id=5 in array, but we don't have item_id=5 in database. I can use INSERT ... ON DUPLICATE KEY UPDATE, but this way image_id=5 will be inserted into talbe items. How to avoid inserting new key? I just want item_id=5 be skipped because it is not in table. Of course, before execution I can select existing keys from items table; then compare with keys in array; delete nonexistent keys and perform INSERT ... ON DUPLICATE KEY UPDATE. But maybe there is some more elegant solutions? Thank you.

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  • Can't find my.cnf file so I can enable InnoDB - is there another way?

    - by Jared
    Hey all, I am trying to Magento running on a share server, and am having difficulty. When I look at the engines in PHPmyAdmin, I get InnoDB DISABLED. So I look in /etc/, and there is no my.cnf file. There is a ftpquota and a .boxtrapper file, but nothing else. I know I can probably create a new one, but this is a server that hosts a lot of sites. I'm afraid I will mess someone up. So is there a way to maybe create a my.cnf file that only enable InnoDB and doesn't effect anything else? Or is there another way to enable it?

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  • Failing to install activerecord-jdbcmysql-adapter gem

    - by Phil Sturgeon
    I am trying to follow the basic "Create a blog in 20 minutes" Rails screencast but have hit a stumbling block already. When I try to rake db:migrate I get errors about the gem activerecord-jdbcmysql-adapter not being installed. When I try to install it, I am told it doesn't exist. If I try to simply gem install mysql I get all sorts of madness appearing. I am running this on Mac OS X 10.6.2 and my installation was all done through gem. My basic setup works (Hello world!). Here is the error log: $ rake db:migrate (in /Users/xxxx/Sites/blog) rake aborted! Please install the jdbcmysql adapter: gem install activerecord-jdbcmysql-adapter (no such file to load -- active_record/connection_adapters/jdbcmysql_adapter) (See full trace by running task with --trace) $ sudo gem install activerecord-jdbcmysql-adapter ERROR: could not find gem activerecord-jdbcmysql-adapter locally or in a repository $ sudo gem install mysql Password: Building native extensions. This could take a while... ERROR: Error installing mysql: ERROR: Failed to build gem native extension. /opt/local/bin/ruby extconf.rb checking for mysql_query() in -lmysqlclient... no checking for main() in -lm... yes checking for mysql_query() in -lmysqlclient... no checking for main() in -lz... yes checking for mysql_query() in -lmysqlclient... no checking for main() in -lsocket... no checking for mysql_query() in -lmysqlclient... no checking for main() in -lnsl... no checking for mysql_query() in -lmysqlclient... no checking for main() in -lmygcc... no checking for mysql_query() in -lmysqlclient... no * extconf.rb failed * Could not create Makefile due to some reason, probably lack of necessary libraries and/or headers. Check the mkmf.log file for more details. You may need configuration options. Provided configuration options: --with-opt-dir --without-opt-dir --with-opt-include --without-opt-include=${opt-dir}/include --with-opt-lib --without-opt-lib=${opt-dir}/lib --with-make-prog --without-make-prog --srcdir=. --curdir --ruby=/opt/local/bin/ruby --with-mysql-config --without-mysql-config --with-mysql-dir --without-mysql-dir --with-mysql-include --without-mysql-include=${mysql-dir}/include --with-mysql-lib --without-mysql-lib=${mysql-dir}/lib --with-mysqlclientlib --without-mysqlclientlib --with-mlib --without-mlib --with-mysqlclientlib --without-mysqlclientlib --with-zlib --without-zlib --with-mysqlclientlib --without-mysqlclientlib --with-socketlib --without-socketlib --with-mysqlclientlib --without-mysqlclientlib --with-nsllib --without-nsllib --with-mysqlclientlib --without-mysqlclientlib --with-mygcclib --without-mygcclib --with-mysqlclientlib --without-mysqlclientlib Gem files will remain installed in /opt/local/lib/ruby/gems/1.8/gems/mysql-2.8.1 for inspection. Results logged to /opt/local/lib/ruby/gems/1.8/gems/mysql-2.8.1/ext/mysql_api/gem_make.out

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  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

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  • SQL Server 2008 DBNETLIB error

    - by Joseph
    Hi all Our ASp.net applications getting error as below" [DBNETLIB][ConnectionOpen (Connect()).]SQL Server does not exist or access denied " But i can connect with Enterprise manager management studio and Query analaizer with out any issue. It was running these applications with out any issue long time. last one week we are getting this error.If we restart the server .it works then it will come again after 3to 4 hours. We are running on Windows 2003 server. I was seraching and didnt find a solution yet. If anybody knows anything for this error, please post the details to resolve. Thank you in Advance Joseph

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  • Error Domain=SKErrorDomain Code=3 UserInfo=0x2a5a00 "Cannot connect to iTunes Store"

    - by SKk
    I am trying to implement InApp purchase in my application. I have implemented it as per Apple's programming guide and it(code) was working fine until I created new application, appid, provisioning profile and in-app products @ another developer account. Now, it gives me following error. Error Domain=SKErrorDomain Code=3 UserInfo=0x2a5a00 "Cannot connect to iTunes Store" Same code works fine if I use previous developer account's appid, pro-certificate and product ids. This is very strange issue, I double checked product id names and other things still facing same error. Any clue..?

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  • Database design for very large amount of data

    - by Hossein
    Hi, I am working on a project, involving large amount of data from the delicious website.The data available is at files are "Date,UserId,Url,Tags" (for each bookmark). I normalized my database to a 3NF, and because of the nature of the queries that we wanted to use In combination I came down to 6 tables....The design looks fine, however, now a large amount of data is in the database, most of the queries needs to "join" at least 2 tables together to get the answer, sometimes 3 or 4. At first, we didn't have any performance issues, because for testing matters we haven't had added too much data in the database. No that we have a lot of data, simply joining extremely large tables does take a lot of time and for our project which has to be real-time is a disaster.I was wondering how big companies solve these issues.Looks like normalizing tables just adds complexity, but how does the big company handle large amounts of data in their databases, don't they do the normalization? thanks

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  • Comparing fields of one table to other fields of another table

    - by chupinette
    Hello! I have a function called add_item which actually inserts values in a field item_name of temporary table called temp having fields temp_id and item_name. I have another table calleed item which consists of fields item_id, item_name, price. I have another table called quotation which consists of fields q_id, item_id,item_name,price. Now I cant figure out how do i compare the item_name from temp to the field item_name from item. And then, insert the values of item in quoatation table. Can anyone guide me please?

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  • HTTP 404 Error manifests itself as EndPointNotFoundException on a WCF client

    - by dudia
    How can I make my client treat 404 Error correctly? Right now it catches a general exception... My WCF Server uses WebOperationContext.Current.OutgoingResponse.SetStatusAsNotFound(); To return a 404 Error code however my WCF client interperts it as an EndPointNotFoundException There was no endpoint listening at http://myUrl that could accept the message. This is often caused by an incorrect address or SOAP action. See InnerException, if present, for more details. The inner exception is WebException "The remote server returned an error: (404) Not Found.

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  • UTF-8 character encoding battles json_encode()

    - by Dave Jarvis
    Quest I am looking to fetch rows that have accented characters. The encoding for the column (NAME) is latin1_swedish_ci. The Code The following query returns Abord â Plouffe using phpMyAdmin: SELECT C.NAME FROM CITY C WHERE C.REGION_ID=10 AND C.NAME_LOWERCASE LIKE '%abor%' ORDER BY C.NAME LIMIT 30 The following displays expected values (function is called db_fetch_all( $result )): while( $row = mysql_fetch_assoc( $result ) ) { foreach( $row as $value ) { echo $value . " "; $value = utf8_encode( $value ); echo $value . " "; } $r[] = $row; } The displayed values: 5482 5482 Abord â Plouffe Abord â Plouffe The array is then encoded using json_encode: $rows = db_fetch_all( $result ); echo json_encode( $rows ); Problem The web browser receives the following value: {"ID":"5482","NAME":null} Instead of: {"ID":"5482","NAME":"Abord â Plouffe"} (Or the encoded equivalent.) Question The documentation states that json_encode() works on UTF-8. I can see the values being encoded from LATIN1 to UTF-8. After the call to json_encode(), however, the value becomes null. How do I make json_encode() encode the UTF-8 values properly? One possible solution is to use the Zend Framework, but I'd rather not if it can be avoided.

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  • Python MySQLdb placeholders syntax

    - by ensnare
    I'd like to use placeholders as seen in this example: cursor.execute (""" UPDATE animal SET name = %s WHERE name = %s """, ("snake", "turtle")) Except I'd like to have the query be its own variable as I need to insert a query into multiple databases, as in: query = """UPDATE animal SET name = %s WHERE name = %s """, ("snake", "turtle")) cursor.execute(query) cursor2.execute(query) cursor3.execute(query) What would be the proper syntax for doing something like this?

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  • MIDL2003 Error in VC6 project

    - by graham.reeds
    While bug fixing I tracked a problem to an old vc6 compiled dll that hasn't been touched in nearly 3 years. After checking out the most recent source I am getting the following error when trying to compile. Processing C:\PROGRAM FILES\MICROSOFT SDK\INCLUDE\msxml.idl msxml.idl .\ocidl.idl(1524) : error MIDL2003 : redefinition : IErrorLog .\ocidl.idl(1541) : error MIDL2003 : redefinition : IPropertyBag Google gives lots of suggestions regarding Visual Studio 2002 - 2003 errors but I can't find anything that relates to Visual Studio 6 or can be applied to my problem. I did find this page but following it's advice didn't fix my problem. Does anyone have any suggestions on how to fix this? (I am presuming that it did work once.) Other items of interest: I have the February 2003 Platform SDK installed, and looking at the add/remove program page I have Micrsoft XML Parser and SDK, MSXML 4.0 SP2 and MSXML 6.0 Parser too.

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  • XCode and SVN Error: 200019

    - by Boiler Bill
    So, I haven't been in an XCode project on this machine since last summer, and now when I try to access the repo through SCM Configuration in preferences I get the following error: Error: 200019 (Incompatible library version) Description: Mismatched RA version for 'http': found 1.6.2, expected 1.6.5 I know at some point I updated my subversion client through MacPorts and is probably the cause of the problem. So I located all the svn programs on my path and replaced them with symlinks to the /opt/local/bin/svn client thinking that would do it (note that /usr/bin/svn --version yielded the same error message as XCode. Somehow XCode (3.2.1) is still pointing to some older 1.6.2 files. Can someone point me in the right direction on getting XCode svn integration cleaned up?

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  • Good example usage of get_or _create in Django views and raising a Form error

    - by Rik Wade
    I would like to use get_or_create to check whether an object already exists in my database. If it does not, then it will be created. If it does exist, then I will not create the new object, but need to raise a form error to inform the user that they need to enter different data (for example, a different username). The view contains: p, created = Person.objects.get_or_create( email = registration_form.cleaned_data['email'], defaults = { 'creationDate': datetime.datetime.now(), 'dateOfBirth': datetime.date(1970,1,1) }) So 'p' will contain the existing Person if it exists, or the new Person if not. I would like to act on the boolean value in 'created' in order to skip over saving the Person and re-display the registration_form and raise an appropriate form validation error. The alternative I'm considering is doing a check in a custom Form validation method to see whether a Person exists with the data in the provided 'email' field, and just raising a validation error.

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  • A rails migration that specifies the distance between two months..?

    - by Trip
    I would like to make two drop downs. a start time, and an end time. Specifically, I only need months. I would like to, for example, choose January, and then March, and then have the database read that it is the these two months plus February. Is there any out of the box migration that could work? I'm guessing.. script/generate migration AddMonthsToClass beginDate:datetime #through endDate:datetime I apologize ahead of time if my question sounds retarded! Sorry! :D

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  • What is wrong with this WHERE clause?

    - by Victor
    Is there a reason why this query doesn't work? The following query will work if I just exclude the WHERE clause. I need to know what is wrong with it. I know the given values of $key exists in the table, so why doesn't this work? $q = "SELECT * WHERE t1.project=$key FROM project_technologies AS t1 JOIN languages AS t2 ON t1.language = t2.key"; Table's have the following fields: project_technologies - key - project - language languages - key - name

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  • Visual Studio 2008 debug does not stop on error

    - by Diana
    I have a simple Windows App written in Visual Studio 2008 (.NET 3.0, C#). Without making any change to the project, solution or Visual Studion (from what I can remember), something weird is happening: when I debug (or run) my application, when it hits an error, Visual Studio does not show me any messagebox with the error, and does not stop execution. It "looks" like nothing happended... the code after the error is not executed, but everything else continues to behave like nothing had happened. Any ideeas about what might be wrong? I don't think it's a big deal, but I can't seem to find it. Thanks!

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  • Relational database queestion with php.

    - by Oliver Bayes-Shelton
    Hi, Not really a coding question more a little help with my idea of a Relational database. If I have 3 tables in a SQL database. In my php script I basically query the companies which are in industry "a" and then insert a row into a seperate table with their details such as companyId , companyName etc is that a type of Relational database ? I have explained it in a simple way so we don't get confused what I am trying to say.

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  • Active Merchant Paypal Recurring Pem Error Neither Pub Nor Priv Key

    - by Andy
    Hi, I am trying to use ActiveMerchant to make a Paypal Recurring transaction call. I used the patch here: http://blog.vuzit.com/2008/08/01/paypal-website-payments-pro-us-with-recurring-billing-and-activemerchant/ and I'm stuck on this here: ActiveMerchant::Billing::PaypalGateway.pem_file = File.read('paypal_cert.pem') I am fairly sure the pem file is correctly downloaded from paypal. The error I receive is: /Library/Ruby/Gems/1.8/gems/activemerchant-1.5.1/lib/active_merchant/lib/connection.rb:129:in initialize': Neither PUB key nor PRIV key:: nested asn1 error (OpenSSL::PKey::RSAError) from /Library/Ruby/Gems/1.8/gems/activemerchant-1.5.1/lib/active_merchant/lib/connection.rb:129:innew' from calling the commit method from line 49 of paypal_pro_recurring. I simply have 2 files - paypal_pro_recurring.rb from the tutorial and paypalTest.rb which I wrote and simply requires all files and calls the function. I hope the error isn't something stupid like I must require from an environment file or something. Thanks all!

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  • Linq to SQL and SQL Server Compact Error: "There was an error parsing the query."

    - by Jeremy
    I created a SQL server compact database (MyDatabase.sdf), and populated it with some data. I then ran SQLMetal.exe and generated a linq to sql class (MyDatabase.mdf) Now I'm trying to select all records from a table with a relatively straightforward select, and I get the error: "There was an error parsing the query. [ Token line number = 3,Token line offset = 67,Token in error = MAX]" Here is my select code: public IEnumerable ListItems() { MyDatabase db_m = new MyDatabase("c:\mydatabase.sdf"); return this.db_m.TestTable.Select(test = new Item() { .... } } I've read that Linq to SQL works with Sql Compact, is there some other configuration I need to do?

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  • mutating, trigger/function may not see it- error during execution of trigger

    - by mahesh soni
    CREATE OR REPLACE TRIGGER UPDATE_TEST_280510 AFTER insert on TEST_TRNCOMPVISIT declare V_TRNCOMPNO NUMBER(10); CURSOR C1 IS SELECT B.COMPNO FROM TEST_TRNCOMPVISIT A, TEST_TRNCOMPMST B, TEST_MEMMAST C WHERE A.COMPNO=B.COMPNO AND B.TRNMEMID=C.MEMID AND C.MEMOS=1000; begin open c1; fetch c1 into V_TRNCOMPNO; UPDATE TEST_TRNCOMPMST SET COMPSTATUS='P', remark='comp is pending due to O/S1000' WHERE COMPNO=V_TRNCOMPNO AND COMPSTATUS='C'; CLOSE C1; end; I have made this trigger and while insert the row in table- TEST_TRNCOMPVISIT it gives following error- The following error has occurred: ORA-04091: table TEST.TEST_TRNCOMPVISIT is mutating, trigger/function may not see it ORA-06512: at "TEST.UPDATE_TEST_280510", line 4 ORA-06512: at "TEST.UPDATE_TEST_280510", line 10 ORA-04088: error during execution of trigger 'TEST.UPDATE_TEST_280510' Kindly suggest over this. MaheshA.....

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  • MS Dynamics CRM 4.0 - onChange event error

    - by Brett
    Hi I have an onChange event that keeps bringing up the error below whenever I preview it. 'Object doesnt support this property or method' I have the onChange event associated with a picklist and when a specific option is selected another field is unhidden. The code is below: onLoad: //If How did you hear about us is set to event show the Source Event lookup crmForm.SourceEvent = function SourceEvent() { if (crmForm.all.gcs_howdidyouhearaboutus.DataValue == 5) { crmForm.all.gcs_sourceeventid_c.style.display = '' ; crmForm.all.gcs_sourceeventid_d.style.display = '' ; } else { crmForm.all.gcs_sourceeventid_c.style.display = 'none' ; crmForm.all.gcs_sourceeventid_d.style.display = 'none' ; } } crmForm.SourceEvent() ; onChange crmForm.SourceEvent() ; Would be great if someone could let me know why this error is showing up? Also, this has happened on a few onChange events on the form preview but once published onto the live system it does not error. Any ideas? Thank you Brett

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  • Database design in blogging systems

    - by Peter
    As a learning exercise I'm trying to put myself a blogging system. The goal is to code something that will let me create multiple blogs, like blogger.com or wordpress.com, but much simplified. I would like to ask you, what do you think is best database design for this type of script. Is it better to have one big table, containing posts from all blogs of all users (like friendfeed) or would it be better to create separate table for each blog's posts? Big thanks in advance for your help, Peter.

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