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  • Stopping long-running requests in Pylons

    - by Jack
    I'm working on an application using Pylons and I was wondering if there was a way to make sure it doesn't spend way too much time handling one request. That is, I would like to find a way to put a timer on each request such that when too much time elapses, the request just stops (and possibly returns some kind of error). The application is supposed to allow users to run some complex calculations but I would like to make sure that if a calculation starts taking too much time, we stop it to allow other calculations to take place.

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  • How can I retrieve all the returned variables from a function?

    - by user1447941
    import random def some_function(): example = random.randint(0, 1) if example == 1: other_example = 2 else: return False return example, other_example With this example, there is a chance that either one or two variables will be returned. Usually, for one variable I'd use var = some_function() while for two, var, var2 = some_function(). How can I tell how many variables are being returned by the function?

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  • problem with list return type??

    - by kaushik
    my list has value such as m=[['na','1','2']['ka','31','45']['ra','3','5'] d=0 r=2 t=m[d][r] print t # this is givin number i.e 2 Now when I use this value u=[] u=m[t] I am getting an err msg saying type error list does take str values... i want to use like this how can i convert that t into a integer?? please suggest.. thanks..

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  • Conditional CellRenderCombo in pyGTK TreeView

    - by Präriewolf
    I have a two column TreeView attached to a ListStore. Both columns are CellRenderCombo combo boxes. When the user selects an entry in the first box, I need to dynamically load a set of options in the second. For example, the behavior I want is: On row 0, the user selects "Alphabet" in the first column box. The second column box is populated with the letters "A-Z". On row 1, the user selects "Numbers" in the first column box. The second column box is populated with the numbers "0-9". On row 2, the user selects "Alphabet" in the first column box. The second column box is populated with the letters "A-Z". etc. Does anyone know how to do this, or seen any open source pygtk or gtk projects that have similar behavior which I can analyze?

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  • Efficient retrieval of lists over WebServices

    - by Chris
    I have a WCF WebService that uses LINQ and EF to connect to an SQL database. I have an ASP.NET MVC front end that collects its data from the webservice. It currently has functions such as List<Customer> GetCustomers(); As the number of customers increases massively the amount of data being passed increases also reducing efficiency. What is the best way to "page data" across WebServices etc. My current idea is to implement a crude paging system such as List<Customer> GetCustomers(int start, int length); This, however, means I would have to replicate such code for all functions returning List types. It is unfortunate that I cannot use LINQ as it would be much nicer. Does anyone have any advice or ideas of patterns to implement that would be "as nice as possible" Thanks

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  • how am I supposed to call the function?

    - by user1816768
    I wrote a program which tells you knight's movement (chess). For example if I wanted to know all possible moves, I'd input: possibilites("F4") and I'd get ['D3', 'D5', 'E2', 'E6', 'G2', 'G6', 'H3', 'H5'] as a result, ok I did that, next, I had to write a function in which you input two fields and if those fields are legal, you'd get True and if they're not you'd get False(I had to use the previous function). For example: legal("F4","D3") >>>True code: def legal(field1,field2): c=possibilities(field1) if field1 and field2 in a: return True return False I'm having a problem with the following function which I have to write: I have to put in path of the knight and my function has to tell me if it's legal path, I'm obliged to use the previous function. for example: >>> legal_way(["F3", "E1", "G2", "H4", "F5"]) True >>> legal_way(["F3", "E1", "G3", "H5"]) False >>> legal_way(["B4"]) True I know I have to loop through the list and put first and second item on it in legal(field1,field2) and if it's false, everything is false, but if it's true I have to continue to the end, and this has to work also if I have only one field. I'm stuck, what to do? def legal_way(way): a=len(way) for i in range(0,a-2): if a==1: return true else if legal(way[i],way[i+1]: return True return False and I get True or index out of range

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  • CCRC unable to check in and check out issue.

    - by Rational Admin
    Hi; One of the team with Clearcase already set up is facing issues in checking and checking out files. They don't have issue in adding a new file to source control. The team has been complaining that they are unable to do so due to domain problem. Seems like Clearcase server is in a domain and the users are logging to the server from a different domain. I haven't yet had a look at the environment. Do you have any idea or would be able to give me heads up on the cause of this issue. Have you ever faced this issue in the past?

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  • Indexing over the results returned by selenium

    - by Guy
    Hi I try to index over results returned by an xpath. For example: xpath = '//a[@id="someID"]' can return a few results. I want to get a list of them. I thought that doing: numOfResults = sel.get_xpath_count(xpath) l = [] for i in range(1,numOfResults+1): l.append(sel.get_text('(%s)[%d]'%(xpath, i))) would work because doing something similar with firefox's Xpath checker works: (//a[@id='someID'])[2] returns the 2nd result. Ideas why the behavior would be different and how to do such a thing with selenium Thanks

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  • How to get attributes from parent?

    - by bribon
    Hi all, Let's say we have these classes: class Foo(object): _bar = "" def __init__(self): self.bar = "hello" def getBar(self): return self._bar def setBar(self, bar): self._bar = bar def getAttributes(self): for attr in self.__dict__: print attr bar = property(getBar, setBar) class Child(Foo): def __init__(self): super(Child, self).__init__() self.a = "" self.b = "" if I do something like: child = Child() child.getAttributes() I get all the attributes from parent and child. How could I get the attributes only from the parent? Thanks in advance!

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  • sip.conf configuration file - add new line to each record

    - by Flukey
    I have a sip configuration file which looks like this: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no For each record I need to add another line (vmxten for each record) for example the above becomes: [1664] username=1664 mailbox=1664@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1664 [1679] username=1679 mailbox=1679@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1679 [1700] username=1700 mailbox=1700@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1700 [1701] username=1701 mailbox=1701@8360 host=192.168.254.3 type=friend subscribemwi=no vmexten=1701 What would you say would be the quickest way to do this? there are hundreds of records in the file, therefore modifying all of the records by hand would take a long time. Would you use Regex? Would you use sed? I'm interested to know how you would approach the problem. Thanks

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  • Using SQLAlchemy, how can I return a count with multiple columns

    - by Andy
    I am attempting to run a query like this: SELECT comment_type_id, name, count(comment_type_id) FROM comments, commenttypes WHERE comment_type_id=commenttypes.id GROUP BY comment_type_id Without the join between comments and commenttypes for the name column, I can do this using: session.query(Comment.comment_type_id,func.count(Comment.comment_type_id)).group_by(Comment.comment_type_id).all() However, if I try to do something like this, I get incorrect results: session.query(Comment.comment_type_id, Comment.comment_type, func.count(Comment.comment_type_id)).group_by(Comment.comment_type_id).all() I have two problems with the results: (1, False, 82920) (2, False, 588) (3, False, 4278) (4, False, 104370) Problems: The False is not correct The counts are wrong My expected results are: (1, 'Comment Type 1', 13820) (2, 'Comment Type 2', 98) (3, 'Comment Type 2', 713) (4, 'Comment Type 2', 17395) How can I adjust my command to pull the correct name value and the correct count?

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  • How to pickle and unpickle objects with self-references and from a class with slots?

    - by EOL
    Is it possible to pickle an object from a class with slots, when this object references itself through one of its attributes? Here is a simple example: import weakref import pickle class my_class(object): __slots__ = ('an_int', 'ref_to_self', '__weakref__') def __init__(self): self.an_int = 42 self.ref_to_self = weakref.WeakKeyDictionary({self: 1}) # __getstate__ and __setstate__ not defined: how should this be done? if __name__ == '__main__': obj = my_class() # How to make the following work? obj_pickled = pickle.dumps(obj) obj_unpickled = pickle.loads(obj_pickled) # Self-references should be kept: print "OK?", obj_unpickled == obj_unpickled.ref_to_self.keys()[0]

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  • How to save to two tables using one SQLAlchemy model

    - by Oatman
    I have an SQLAlchemy ORM class, linked to MySQL, which works great at saving the data I need down to the underlying table. However, I would like to also save the identical data to a second archive table. Here's some psudocode to try and explain what I mean my_data = Data() #An ORM Class my_data.name = "foo" #This saves just to the 'data' table session.add(my_data) #This will save it to the identical 'backup_data' table my_data_archive = my_data my_data_archive.__tablename__ = 'backup_data' session.add(my_data_archive) #And commits them both session.commit() Just a heads up, I am not interested in mapping a class to a JOIN, as in: http://www.sqlalchemy.org/docs/05/mappers.html#mapping-a-class-against-multiple-tables

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  • Filtering SQLAlchemy query on attribute_mapped_collection field of relationship

    - by bsa
    I have two classes, Tag and Hardware, defined with a simple parent-child relationship (see the full definition at the end). Now I want to filter a query on Tag using the version field in Hardware through an attribute_mapped_collection, eg: def get_tags(order_code=None, hardware_filters=None): session = Session() query = session.query(Tag) if order_code: query = query.filter(Tag.order_code == order_code) if hardware_filters: for k, v in hardware_filters.iteritems(): query = query.filter(getattr(Tag.hardware, k).version == v) return query.all() But I get: AttributeError: Neither 'InstrumentedAttribute' object nor 'Comparator' object associated with Tag.hardware has an attribute 'baseband The same thing happens if I strip it back by hard-coding the attribute, eg: query.filter(Tag.hardware.baseband.version == v) I can do it this way: query = query.filter(Tag.hardware.any(artefact=k, version=v)) But why can't I filter directly through the attribute? Class definitions class Tag(Base): __tablename__ = 'tag' tag_id = Column(Integer, primary_key=True) order_code = Column(String, nullable=False) version = Column(String, nullable=False) status = Column(String, nullable=False) comments = Column(String) hardware = relationship( "Hardware", backref="tag", collection_class=attribute_mapped_collection('artefact'), ) __table_args__ = ( UniqueConstraint('order_code', 'version'), ) class Hardware(Base): __tablename__ = 'hardware' hardware_id = Column(Integer, primary_key=True) tag_id = Column(String, ForeignKey('tag.tag_id')) product_id = Column(String, nullable=True) artefact = Column(String, nullable=False) version = Column(String, nullable=False)

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  • GTK+: How do I process RadioMenuItem choice without marking it chosen? And vise versa

    - by eugene.shatsky
    In my program, I've got a menu with a group of RadioMenuItem entries. Choosing one of them should trigger a function which can either succeed or fail. If it fails, this RadioMenuItem shouldn't be marked chosen (the previous one should persist). Besides, sometimes I want to set marked item without running the choice processing function. Here is my current code: # Update seat menu list def update_seat_menu(self, seats, selected_seat=None): seat_menu = self.builder.get_object('seat_menu') # Delete seat menu items for menu_item in seat_menu: # TODO: is it a good way? does remove() delete obsolete menu_item from memory? if menu_item.__class__.__name__ == 'RadioMenuItem': seat_menu.remove(menu_item) # Fill menu with new items group = [] for seat in seats: menu_item = Gtk.RadioMenuItem.new_with_label(group, str(seat[0])) group = menu_item.get_group() seat_menu.append(menu_item) if str(seat[0]) == selected_seat: menu_item.activate() menu_item.connect("activate", self.choose_seat, str(seat[0])) menu_item.show() # Process item choice def choose_seat(self, entry, seat_name): # Looks like this is called when item is deselected, too; must check if active if entry.get_active(): # This can either succeed or fail self.logind.AttachDevice(seat_name, '/sys'+self.device_syspath, True) Chosen RadioMenuItem gets marked irrespective of the choose_seat() execution result; and the only way to set marked item without triggering choose_seat() is to re-run update_seat_menu() with selected_seat argument, which is an overkill. I tried to connect choose_seat() with 'button-release-event' instead of 'activate' and call entry.activate() in choose_seat() if AttachDevice() succeeds, but this resulted in whole X desktop lockup until AttachDevice() timed out, and chosen item still got marked.

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  • index error:list out of range

    - by kaushik
    from string import Template from string import Formatter import pickle f=open("C:/begpython/text2.txt",'r') p='C:/begpython/text2.txt' f1=open("C:/begpython/text3.txt",'w') m=[] i=0 k='a' while k is not '': k=f.readline() mi=k.split(' ') m=m+[mi] i=i+1 print m[1] f1.write(str(m[3])) f1.write(str(m[4])) x=[] j=0 while j<i: k=j-1 l=j+1 if j==0 or j==i: j=j+1 else: xj=[] xj=xj+[j] xj=xj+[m[j][2]] xj=xj+[m[k][2]] xj=xj+[m[l][2]] xj=xj+[p] x=x+[xj] j=j+1 f1.write(','.join(x)) f.close() f1.close() It say line 33,xj=xj+m[l][2] has index error,list out of range please help thanks in advance

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