Search Results

Search found 63877 results on 2556 pages for 'mysql error 1452'.

Page 539/2556 | < Previous Page | 535 536 537 538 539 540 541 542 543 544 545 546  | Next Page >

  • Sql script, create a database

    - by Blanca
    Hi! I have the next file: create_mysql.sql DROP DATABASE IF EXISTS playence_media; CREATE DATABASE playence_media; USE playence_media; GRANT ALL PRIVILEGES ON . TO 'media'@'localhost' IDENTIFIED BY 'media' WITH GRANT OPTION; But I don't know how to create this database. I would like to do it with my terminal, no other graphics interfaces. Thanks

    Read the article

  • (My)SQL performance: updating one field vs many unneccesary fields

    - by changokun
    i'm processing a form that has a lot of fields for a user who is editing an existing record. the user may have only changed one field, and i would typically do an update query that sets the values of all the fields, even though most of them don't change. i could do some sort of tracking to see which fields have actually changed, and only update the few that did. is there a performance difference between updating all fields in a record vs only the one that changed? are there other reasons to go with either method? the shotgun method is pretty easy...

    Read the article

  • Trouble making login page?

    - by Ken
    Okay, so I want to make a simple login page. I've created a register page successfully, but i can't get the login thing down. login.php: <?php session_start(); include("mainmenu.php"); $usrname = mysql_real_escape_string($_POST['usrname']); $password = md5($_POST['password']); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } mysql_select_db("users", $con) or die(mysql_error()); $login = "SELECT * FROM `users` WHERE (usrname = '$usrname' AND password = '$password')"; $result = mysql_query($login); if(mysql_num_rows($result) == 1 { $_SESSION = true; header('Location: indexlogin.php'); } else { echo = "Wrong username or password." ; } ?> indexlogin.php just echoes "Login successful." What am I doing wrong? Oh, and just FYI- my database is "users" and my table is "data".

    Read the article

  • please help me in this query

    - by testkhan
    I have three tables (user, friends, posts) and two users (user1 and user2). When user1 adds user2 as friend then user1 can see the posts of user2 just like on Facebook. But only the posts after the date when user1 added user2 as friend. My query is like this: $sql = mysql_query("SELECT * FROM posts p JOIN friends f ON p.currentuserid = f.friendid AND p.time >= f.friend_since OR p.currentuserid='user1id' WHERE f.myid='user1id' ORDER BY p.postid DESC LIMIT 20"); it is working all the way fine but with a little problem.....!! it displays user2, user3 (all the users as friends of user1) posts for single time but shows user1 posts multiple.......i.e user2. hi user1. userssfsfsfsfsdf user1. userssfsfsfsfsdf user3. dddddddd user1. sdfsdsdfsdsfsf user1. sdfsdsdfsdsfsf but i in database it is single entry/post why it is happening........!! How can I fix it?

    Read the article

  • How to add SQL elements to an array in PHP

    - by DanLeaningphp
    So this question is probably pretty basic. I am wanting to create an array from selected elements from a SQL table. I am currently using: $rcount = mysql_num_rows($result); for ($j = 0; $j <= $rcount; $j++) { $row = mysql_fetch_row($result); $patients = array($row[0] => $row[2]); } I would like this to return an array like this: $patients = (bob=>1, sam=>2, john=>3, etc...) Unfortunately, in its current form, this code is either copying nothing to the array or only copying the last element.

    Read the article

  • Solr; "rookie" question

    - by Camran
    I have a SolrPhpClient on my classifieds website, and whenever users wants to add/remove classified the index in Solr gets updated via Php code. So I wonder, does this mean that my Solr index is open for anybody to alter with? Same Q applies to the Solr Admin page. If I set a password for the admin page, does this mean that my classifieds website wont have access to updating/removing documents from the Solr index? Thanks

    Read the article

  • ora-00939 error in reporting services, SSRS

    - by san
    Hi, I have an SSRS report , Oracle is my backend and am using this following query for dataset of my second parameter. select distinct X from v_stf_sec_user_staffing_center usc where usc.center_group_id in ( select distinct center_group_id from V_T_STAFFING_CENTER_GROUP scg where INSTR(','||REPLACE(:PI_REGION_LIST,' ')||',', ','||scg.group_abbreviation||',') 0) and usc.nt_user_name=:PI_NT_USER_NAME Here PI_REGION_LIST is a multivalued parameter of string type. and PI_NT_USER_NAME is a default string valued parameter this query works fine when i try to execute in manulally in the Data tab , also in the Oracle tool. But when i run the report in SSRS and select more than 3 values for the parameter PI_REGION_LIST the report throws an error on this dataset, ora-00939 error,too many arguments for function. I am not able to figure out the error here. Please help me with an idea. Thanks in advance, Suni.

    Read the article

  • Unique Alpha numeric generator

    - by AAA
    Hi, I want to give our users in the database a unique alpha-numeric id. I am using the code below, will this always generate a unique id? Below is the updated version of the code: old php: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid(rand(),true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; New PHP: // Generate Guid function NewGuid() { $s = strtoupper(uniqid("something",true)); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Will the second (new php) code guarantee 100% uniqueness. Final code: PHP // Generate Guid function NewGuid() { $s = strtoupper(uniqid(rand(),true)); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; $alphabet = '123456789abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ'; function base_encode($num, $alphabet) { $base_count = strlen($alphabet); $encoded = ''; while ($num >= $base_count) { $div = $num/$base_count; $mod = ($num-($base_count*intval($div))); $encoded = $alphabet[$mod] . $encoded; $num = intval($div); } if ($num) $encoded = $alphabet[$num] . $encoded; return $encoded; } function base_decode($num, $alphabet) { $decoded = 0; $multi = 1; while (strlen($num) > 0) { $digit = $num[strlen($num)-1]; $decoded += $multi * strpos($alphabet, $digit); $multi = $multi * strlen($alphabet); $num = substr($num, 0, -1); } return $decoded; } echo base_encode($Guid, $alphabet); } So for more stronger uniqueness, i am using the $Guid as the key generator. That should be ok right?

    Read the article

  • cakephp pagination overide paginate() method

    - by islam
    iam using cakephp pagination and to paginate using custome query i override the paginate() method in my controller the problem is that every other action that use paginate() method not work any more how i can override this method without conflict with other that use this method from the same model

    Read the article

  • PHP4 No Error When Missing Method is Called

    - by INTPnerd
    I have come across an annoying problem while writing some PHP4 code. I renamed the method of a class but I forgot to rename it where it was being called from. The annoying part is it was hard to track down where the problem was because no error was triggered. The script simply aborted leaving the web page partially rendered. Is it normal for this not to trigger an error or is there something wacky going on here? If this is normal is there a way to force this kind of thing to cause an error?

    Read the article

  • PHP: table structure

    - by A3efan
    I'm developing a website that has some audio courses, each course can have multiple lessons. I want to display each course in its own table with its different lessons. This is my sql statement: Table: courses id, title Table: lessons id, cid (course id), title, date, file $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; Can someone help me with the PHP code? This is the I code I have written: mysql_select_db($database_config, $config); mysql_query("set names utf8"); $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; $result = mysql_query($sql) or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo "<p><span class='heading1'>" . $row['course'] . "</span> </p> "; echo "<p class='datum'>Posted onder <a href='*'>*</a>, latest update on " . strftime("%A %d %B %Y %H:%M", strtotime($row['date'])); } echo "</p>"; echo "<class id='text'>"; echo "<p>...</p>"; echo "<table border: none cellpadding='1' cellspacing='1'>"; echo "<tr>"; echo "<th>Nr.</th>"; echo "<th width='450'>Lesso</th>"; echo "<th>Date</th>"; echo "<th>Download</th>"; echo "</tr>"; echo "<tr>"; echo "<td>" . $row['nr'] . "</td>"; echo "<td>" . $row['title'] . "</td>"; echo "<td>" . strftime("%d/%m/%Y", strtotime($row['date'])) . "</td>"; echo "<td><a href='audio/" . rawurlencode($row['file']) . "'>MP3</a></td>"; echo "</tr>"; echo "</table>"; echo "<br>"; } ?>

    Read the article

  • SQL How to join multiplue columns with same name to one column

    - by Choi Shun Chi
    There is a super class account {User, TYPE} and subclasses saving{User, ID, balance,TYPE,interest,curency_TYPE} time{User,ID,balance,TYPE,interest,curency_TYPE,start_date,due_date,period} fore{User,ID,balance,interest,curency_TYPE} User and TYPE is the primary key of account and foreign key of three subclasses ID is primary key of three subclasses how to make a list of showing all IDs in one column?Also the same as balance and TYPE meet the problem I considered a.ID as saving, b.ID as time but it showing them separately

    Read the article

  • Rails: Generated tokens missing occasionally

    - by Vincent Chan
    We generate an unique token for each user and store it on database. Everything is working fine in the local environment. However, after we upload the codes to the production server on Engine Yard, things become weird. We tried to register an account right after the deploy. It is working fine and we can see the token in the db. But after that, when we register new accounts, we cannot see any tokens. We only have NULL in the db. Not sure what caused this problem because we can't re-produce this in the local machine. Thanks for your help.

    Read the article

  • SYSDATE - 1 error on pl/sql function

    - by ayo
    Hi curtisk/all, I have an issue: when i issue this function below ti gives me the following error: select 'EXECUTE DBMS_LOGMNR.ADD_LOGFILE(LOGFILENAME =>'''||name||'''||,OPTIONS=>DBMS_LOGMNR.NEW);' from v\$archived_log where name is not null; select 'EXECUTE DBMS_LOGMNR.ADD_LOGFILE(LOGFILENAME =>'''||name||'''||,OPTIONS=>DBMS_LOGMNR.ADDFILE);' from v\$archived_log where name is not null; EXECUTE DBMS_LOGMNR.START_LOGMNR( STARTTIME => SYSDATE - 1, ENDTIME => SYSDATE, OPTIONS => DBMS_LOGMNR.DICT_FROM_ONLINE_CATALOG + DBMS_LOGMNR.CONTINUOUS_MINE + DBMS_LOGMNR.COMMITTED_DATA_ONLY + DBMS_LOGMNR.PRINT_PRETTY_SQL); Error: * ERROR at line 1: ORA-01291: missing logfile ORA-06512: at "SYS.DBMS_LOGMNR", line 58 ORA-06512: at line 1 But i have added all the archived logs for several days before and my sysdate is at today. Kindly help out on this issue. thanks. Reagrds Ayo

    Read the article

  • In SQL, in what situation do we want to Index a field in a table, or 2 fields in a table at the same

    - by Jian Lin
    In SQL, it is obvious that whenever we want to do a search on millions of record, say CustomerID in a Transactios table, then we want to add an index for CustomerID. Is another situation we want to add an index to a field when we need to do inner join or outer join using that field as a criteria? Such as Inner join on t1.custumerID = t2.customerID. Then if we don't have an index on customerID on both tables, we are looking at O(n^2) because we need to loop through the 2 tables sequentially. If we have index on customerID on both tables, then it becomes O( (log n) ^ 2 ) and it is much faster. Any other situation where we want to add an index to a field in a table? What about adding index for 2 fields combined in a table. That is, one index, for 2 fields together?

    Read the article

  • Managing Foreign Keys

    - by jwzk
    So I have a database with a few tables. The first table contains the user ID, first name and last name. The second table contains the user ID, interest ID, and interest rating. There is another table that has all of the interest ID's. For every interest ID (even when new ones are added), I need to make sure that each user has an entry for that interest ID (even if its blank, or has defaults). Will foreign keys help with this scenario? or will I need to use PHP to update each and every record when I add a new key?

    Read the article

  • checking if records exists in DB, in single step or 2 steps?

    - by Sinan
    Suppose you want to get a record from database which returns a large data and requires multiple joins. So my question would be is it better to use a single query to check if data exists and get the result if it exists. Or do a more simple query to check if data exists then id record exists, query once again to get the result knowing that it exists. Example: 3 tables a, b and ab(junction table) select * from from a, b, ab where condition and condition and condition and condition etc... or select id from a, b ab where condition then if exists do the query above. So I don't know if there is any reason to do the second. Any ideas how this affects DB performance or does it matter at all?

    Read the article

  • Lost with hibernate - OneToMany resulting in the one being pulled back many times..

    - by Andy
    I have this DB design: CREATE TABLE report ( ID MEDIUMINT PRIMARY KEY NOT NULL AUTO_INCREMENT, user MEDIUMINT NOT NULL, created TIMESTAMP NOT NULL, state INT NOT NULL, FOREIGN KEY (user) REFERENCES user(ID) ON UPDATE CASCADE ON DELETE CASCADE ); CREATE TABLE reportProperties ( ID MEDIUMINT NOT NULL, k VARCHAR(128) NOT NULL, v TEXT NOT NULL, PRIMARY KEY( ID, k ), FOREIGN KEY (ID) REFERENCES report(ID) ON UPDATE CASCADE ON DELETE CASCADE ); and this Hibernate Markup: @Table(name="report") @Entity(name="ReportEntity") public class ReportEntity extends Report{ @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name="ID") private Integer ID; @Column(name="user") private Integer user; @Column(name="created") private Timestamp created; @Column(name="state") private Integer state = ReportState.RUNNING.getLevel(); @OneToMany(mappedBy="pk.ID", fetch=FetchType.EAGER) @JoinColumns( @JoinColumn(name="ID", referencedColumnName="ID") ) @MapKey(name="pk.key") private Map<String, ReportPropertyEntity> reportProperties = new HashMap<String, ReportPropertyEntity>(); } and @Table(name="reportProperties") @Entity(name="ReportPropertyEntity") public class ReportPropertyEntity extends ReportProperty{ @Embeddable public static class ReportPropertyEntityPk implements Serializable{ /** * long#serialVersionUID */ private static final long serialVersionUID = 2545373078182672152L; @Column(name="ID") protected int ID; @Column(name="k") protected String key; } @EmbeddedId protected ReportPropertyEntityPk pk = new ReportPropertyEntityPk(); @Column(name="v") protected String value; } And i have inserted on Report and 4 Properties for that report. Now when i execute this: this.findByCriteria( Order.asc("created"), Restrictions.eq("user", user.getObject(UserField.ID)) ) ); I get back the report 4 times, instead of just the once with a Map with the 4 properties in. I'm not great at Hibernate to be honest, prefer straight SQL but I must learn, but i can't see what it is that is wrong.....? Any suggestions?

    Read the article

  • DEADLOCK_WRAP error when using Berkeley Db in python (bsddb)

    - by JiminyCricket
    I am using a berkdb to store a huge list of key-value pairs but for some reason when i try to access some of the data later i get this error: try: key = 'scrape011201-590652' contenttext = contentdict[key] except: print the error <type 'exceptions.KeyError'> 'scrape011201-590652' in contenttext = contentdict[key]\n', ' File "/usr/lib64/python2.5/bsddb/__init__.py", line 223, in __getitem__\n return _DeadlockWrap(lambda: self.db[key]) # self.db[key]\n', 'File "/usr/lib64/python2.5/bsddb/dbutils.py", line 62, in DeadlockWrap\n return function(*_args, **_kwargs)\n', ' File "/usr/lib64/python2.5/bsddb/__init__.py", line 223, in <lambda>\n return _DeadlockWrap(lambda: self.db[key]) # self.db[key]\n'] I am not sure what DeadlockWrap is but there isnt any other program or process accessing the berkdb or writing to it (as far as i know,) so not sure how we could get a deadlock, if its referring to that. Is it possible that I am trying to access the data to rapidly? I have this function call in a loop, so something like for i in hugelist: #try to get a value from the berkdb #do something with it I am running this with multiple datasets and this error only occurs with one of them, the largest one, not the others.

    Read the article

  • Dynamically removing records when certain columns = 0; data cleansing

    - by cdburgess
    I have a simple card table: CREATE TABLE `users_individual_cards` ( `id` int(11) NOT NULL AUTO_INCREMENT, `user_id` char(36) NOT NULL, `individual_card_id` int(11) NOT NULL, `own` int(10) unsigned NOT NULL, `want` int(10) unsigned NOT NULL, `trade` int(10) unsigned NOT NULL, PRIMARY KEY (`id`), UNIQUE KEY `user_id` (`user_id`,`individual_card_id`), KEY `user_id_2` (`user_id`), KEY `individual_card_id` (`individual_card_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1; I have ajax to add and remove the records based on OWN, WANT, and TRADE. However, if the user removes all of the OWN, WANT, and TRADE cards, they go to zero but it will leave the record in the database. I would prefer to have the record removed. Is checking after each "update" to see if all the columns = 0 the only way to do this? Or can I set a conditional trigger with something like: //psuedo sql AFTER update IF (OWN = 0, WANT = 0, TRADE = 0) DELETE What is the best way to do this? Can you help with the syntax?

    Read the article

  • tiny mce sql error when adding links

    - by Anders Kitson
    I am using tiny mce with a script I built for uploading some content to a blog like system. Whenever I add a link via tiny mce I get this error. The field type in mysql for $content which is the one carrying the link is longblob if that helps. here is the link error first and then my code You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'google test" href="http://www.google.ca" target="_blank"google est laborum' at line 4 /* GRAB FORM DATA */ $title = $_POST['title']; $date = $_POST['date']; $content = $_POST['content']; $imageName1 = $_FILES["file"]["name"]; $date = date("Y-m-d"); $sql = "INSERT INTO blog (title,date,content,image)VALUES( \"$title\", \"$date\", \"$content\", \"$imageName1\" )"; $results = mysql_query($sql)or die(mysql_error());

    Read the article

  • Erubis block helper throwing error with concat

    - by DEfusion
    I have a couple of block helpers, here's a simple example of what I'm doing: def wrap_foo foo, &block data = capture(&block) content = " <div class=\"foo\" id=\"#{foo}\"> #{data} </div>" concat( content ) end I'm just trying out erubis and it's giving me the following error: You have a nil object when you didn't expect it! You might have expected an instance of Array. The error occurred while evaluating nil.<< Removing the call to concat removes the error but ends up with my wrapper not being rendered Using: Rails 2.3.5 Erubis 2.6.5 And tried this gem that helps Erubis (though 2.6.4) and Rails 2.3 play better together

    Read the article

< Previous Page | 535 536 537 538 539 540 541 542 543 544 545 546  | Next Page >