Search Results

Search found 9098 results on 364 pages for 'django admin'.

Page 54/364 | < Previous Page | 50 51 52 53 54 55 56 57 58 59 60 61  | Next Page >

  • WordPress - Emergency Access Without Admin Accounts

    In some cases, when you need to do something in a WordPress website, but all you have is only access to WordPress database and FTP, and you cannot get the admin password from the database because it's decrypted. All changes you have to make via some low level MySQL queries, it's hard and easy mistaken. Joost de Valk has written a script for emergency access to WordPress dashboard by changing admin password or creating new user.

    Read the article

  • CUPS Authentication for Admin on localhost:631 interface

    - by Tony Kruse
    I have searched quite a bit, saw the one response that purported to have a solution to this but it did not work in my case. My Brother printer is not shown in CUPS so I go to Admin-Add Printer it gives me the User Name/Password popup with refuses to recognize my user name on the machine. This is a brand new install of 13.1. My Restrict Access to the admin pages section has: Order allow, deny Allow localhost

    Read the article

  • Can't access my Ubuntu admin account

    - by Kermilli
    It just shows a black screen with words in it for a fraction of a second and then gets back to users screen(where you choose your user). I tried to enter from another account and removed the password for the admin account , but it didn't work too , and then I couldn't access my admin privileged places with my old password ? What should I do ? I tried to change my password from recovery but no success.

    Read the article

  • Can't access my admin ubuntu account

    - by Kermilli
    It just shows a black screen with words in it for a fraction of a second and then gets back to users screen(where you choose your user). I tried to enter from another account and removed the password for the admin account , but it didn't work too , and then I couldn't access my admin privileged places with my old password ? What should I do ? I tried to change my password from recovery but no success.

    Read the article

  • How to run a restricted set of programs with Administrator privileges without giving up Admin acces (Win7 Pro)

    - by frLich
    I have a shared system, running Windows7 X64, restricted to a 'standard user' with no password. Not everyone who has access to the system has the administrator password. This works rather well, except for some applications - specially the unlock-applications for encrypted hard drives/USB flash drives. The specific ones either require Administrator access (eg. Seagate Blackarmor) or simply fail without it -- since these programs are sending raw commands to a device, this is to be expected. I would like to be able to add the hashes of these particular programs to a whitelist, and have them run as administrator without needing any prompts. Since these are by definition on removable media, I can't simply use a filename or even a path. One of the users who shares the system can be considered 'crafty', so anything which temporarily grants administrator rights to an user account is certain to cause problems. What i'd like to be able to do: 1) Create an admin account that can only run programs from a whitelist (or, failing that, from a directory) I can't find a good way to do this: As far as I can tell, SRP applies equally to ALL users? Even if I put a "Deny" token on all directories on the system, such that new directories would inherit it, it could still potentially run things from the mounted USB devices. I also don't know whether it's possible to create a new directory that DOESN'T inherit from the parent, that would lake the deny token, and provide admin access. 2) Find a lightweight service that will run these programs in its local context Windows7 seems to block cross-privilege level communication by default, and I haven't found such for windows 7. One example seems to be "sudo" (http://pages.cpsc.ucalgary.ca/~nfriess/sudo/) but because it uses a WLNOTIFY hook, it won't work under Vista nor Windows7 Non-Solutions: - RunAs: Requires administrator password! (but everyone calls it "sudo" anyway) - SuRun: From Google: "Surun uses its own Windows service that adds the user to the group of administrators during program start and removes him automatically from that group again"

    Read the article

  • Help with understanding generic relations in Django (and usage in Admin)

    - by saturdayplace
    I'm building a CMS for my company's website (I've looked at the existing Django solutions and want something that's much slimmer/simpler, and that handles our situation specifically.. Plus, I'd like to learn this stuff better). I'm having trouble wrapping my head around generic relations. I have a Page model, a SoftwareModule model, and some other models that define content on our website, each with their get_absolute_url() defined. I'd like for my users to be able to assign any Page instance a list of objects, of any type, including other page instances. This list will become that Page instance's sub-menu. I've tried the following: class Page(models.Model): body = models.TextField() links = generic.GenericRelation("LinkedItem") @models.permalink def get_absolute_url(self): # returns the right URL class LinkedItem(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') title = models.CharField(max_length=100) def __unicode__(self): return self.title class SoftwareModule(models.Model): name = models.CharField(max_length=100) description = models.TextField() def __unicode__(self): return self.name @models.permalink def get_absolute_url(self): # returns the right URL This gets me a generic relation with an API to do page_instance.links.all(). We're on our way. What I'm not sure how to pull off, is on the page instance's change form, how to create the relationship between that page, and any other extant object in the database. My desired end result: to render the following in a template: <ul> {% for link in page.links.all %} <li><a href='{{ link.content_object.get_absolute_url() }}'>{{ link.title }}</a></li> {% endfor%} </ul> Obviously, there's something I'm unaware of or mis-understanding, but I feel like I'm, treading into that area where I don't know what I don't know. What am I missing?

    Read the article

  • Javascript with Django?

    - by Rosarch
    I know this has been asked before, but I'm having a hard time setting up JS on my Django web app, even though I'm reading the documentation. I'm running the Django dev server. My file structure looks like this: mysite/ __init__.py MySiteDB manage.py settings.py urls.py myapp/ __init__.py admin.py models.py test.py views.py templates/ index.html Where do I want to put the Javascript and CSS? I've tried it in a bunch of places, including myapp/, templates/ and mysite/, but none seem to work. From index.html: <head> <title>Degree Planner</title> <script type="text/javascript" src="/scripts/JQuery.js"></script> <script type="text/javascript" src="/media/scripts/sprintf.js"></script> <script type="text/javascript" src="/media/scripts/clientside.js"></script> </head> From urls.py: (r'^admin/', include(admin.site.urls)), (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'media'}) (r'^.*', 'mysite.myapp.views.index'), I suspect that the serve() line is the cause of errors like: TypeError at /admin/auth/ 'tuple' object is not callable Just to round off the rampant flailing, I changed these settings in settings.py: MEDIA_ROOT = '/media/' MEDIA_URL = 'http://127.0.0.1:8000/media'

    Read the article

  • Django does not load internal .css files

    - by Rubén Jiménez
    I have created a Django project in local which runs without any kind of problem. But, after an annoying and difficult Cherokee + uWSGI installation on Amazon AWS, my project does not show Django .css internal files. http://f.cl.ly/items/2Q2W3I3R0X1n2X3v0q2P/django_error.jpg <-- /Admin/ looks like The image is a screen of my /admin/, which should have a different style, but .css files are not loaded. [pid: 23206|app: 0|req: 19/19] 83.49.10.217 () {56 vars in 1121 bytes} [Sun Apr 15 05:50:24 2012] GET /static/admin/css/base.css = generated 2896 bytes in 6 msecs (HTTP/1.1 404) 1 headers in 51 bytes (1 switches on core 0) [pid: 23206|app: 0|req: 20/20] 83.49.10.217 () {56 vars in 1125 bytes} [Sun Apr 15 05:50:24 2012] GET /static/admin/css/login.css = generated 2899 bytes in 5 msecs (HTTP/1.1 404) 1 headers in 51 bytes (1 switches on core 0) This is a log from Cherokee. I don't understand why it is looking for the .css files in that path. Cherokee should be searching the files in Django original directory so i didn't change .css files in my project. Any advice? Thanks a lot.

    Read the article

  • Can't get python.manage.py syncdb to work

    - by Diego
    I just created my first django app, initialized variables DATABASE_ENGINE and DATABASE_NAME in settings.py, but now when I run python manage.py syncdb, I get the following error Can somebody help? Does this have to do with having two python versions installed? I'm a django/python noob, please help. thanks!! my-computer:~/Django-1.1.1 mycomp$ python manage.py syncdb /Library/Frameworks/Python.framework/Versions/2.6/Resources/Python.app/Contents/MacOS/Python: can't open file 'manage.py': [Errno 2] No such file or directory my-computer:~/Django-1.1.1 mycomp$ export PATH=/Users/mycomp/bin:$PATH

    Read the article

  • How to serve static files for multiple Django projects via nginx to same domain

    - by thanley
    I am trying to setup my nginx conf so that I can serve the relevant files for my multiple Django projects. Ultimately I want each app to be available at www.example.com/app1, www.example.com/app2 etc. They all serve static files from a 'static-files' directory located in their respective project root. The project structure: Home Ubuntu Web www.example.com ref logs app app1 app1 static bower_components templatetags app1_project templates static-files app2 app2 static templates templatetags app2_project static-files app3 tests templates static-files static app3_project app3 venv When I use the conf below, there are no problems for serving the static-files for the app that I designate in the /static/ location. I can also access the different apps found at their locations. However, I cannot figure out how to serve all of the static files for all the apps at the same time. I have looked into using the 'try_files' command for the static location, but cannot figure out how to see if it is working or not. Nginx Conf - Only serving static files for one app: server { listen 80; server_name example.com; server_name www.example.com; access_log /home/ubuntu/web/www.example.com/logs/access.log; error_log /home/ubuntu/web/www.example.com/logs/error.log; root /home/ubuntu/web/www.example.com/; location /static/ { alias /home/ubuntu/web/www.example.com/app/app1/static-files/; } location /media/ { alias /home/ubuntu/web/www.example.com/media/; } location /app1/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app1; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app1.sock; } location /app2/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app2; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app2.sock; } location /app3/ { include uwsgi_params; uwsgi_param SCRIPT_NAME /app3; uwsgi_modifier1 30; uwsgi_pass unix:///home/ubuntu/web/www.example.com/app3.sock; } # what to serve if upstream is not available or crashes error_page 400 /static/400.html; error_page 403 /static/403.html; error_page 404 /static/404.html; error_page 500 502 503 504 /static/500.html; # Compression gzip on; gzip_http_version 1.0; gzip_comp_level 5; gzip_proxied any; gzip_min_length 1100; gzip_buffers 16 8k; gzip_types text/plain text/css application/x-javascript text/xml application/xml application/xml+rss text/javascript; # Some version of IE 6 don't handle compression well on some mime-types, # so just disable for them gzip_disable "MSIE [1-6].(?!.*SV1)"; # Set a vary header so downstream proxies don't send cached gzipped # content to IE6 gzip_vary on; } Essentially I want to have something like (I know this won't work) location /static/ { alias /home/ubuntu/web/www.example.com/app/app1/static-files/; alias /home/ubuntu/web/www.example.com/app/app2/static-files/; alias /home/ubuntu/web/www.example.com/app/app3/static-files/; } or (where it can serve the static files based on the uri) location /static/ { try_files $uri $uri/ =404; } So basically, if I use try_files like above, is the problem in my project directory structure? Or am I totally off base on this and I need to put each app in a subdomain instead of going this route? Thanks for any suggestions TLDR: I want to go to: www.example.com/APP_NAME_HERE And have nginx serve the static location: /home/ubuntu/web/www.example.com/app/APP_NAME_HERE/static-files/;

    Read the article

  • Looking for a good example usage of get_or _create in Django views and raising a Form error

    - by Rik Wade
    I am looking for a good example of how to achieve the following: I would like to use get_or_create to check whether an object already exists in my database. If it does not, then it will be created. If it does exist, then I will not create the new object, but need to raise a form error to inform the user that they need to enter different data (for example, a different username). The view contains: p, created = Person.objects.get_or_create( email = registration_form.cleaned_data['email'], defaults = { 'creationDate': datetime.datetime.now(), 'dateOfBirth': datetime.date(1970,1,1) }) So 'p' will contain the existing Person if it exists, or the new Person if not. I would like to act on the boolean value in 'created' in order to skip over saving the Person and re-display the registration_form and raise an appropriate form validation error. The alternative I'm considering is doing a check in a custom Form validation method to see whether a Person exists with the data in the provided 'email' field, and just raising a validation error.

    Read the article

  • Django QuerySet API: How do I join iexact and icontains?

    - by Zeynel
    Hello, I have this join: lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name) This is the site If you try Last Name: Abbas and First Name: Amr it tells you that amr abbas has 1 schoolmates. But if you try First name only it says that there are no lawyers in the database called amr (obviously there is). If I change (last__iexact=last_name) to (last__icontains=last_name) then leaving Last Name blank works fine and amr is found. But with last__icontains=last_name if you search for "collin" you also get "collins" and "collingwood" which is not what I want. Do you know how I can use iexact and also have it ignored if it is blank? Thanks This is the view function: def search_form(request): if request.method == 'POST': search_form = SearchForm(request.POST) if search_form.is_valid(): last_name = search_form.cleaned_data['last_name'] first_name = search_form.cleaned_data['first_name'] lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name) if len(lawyers)==0: form = SearchForm() return render_to_response('not_in_database.html', {'last': last_name, 'first': first_name, 'form': form}) if len(lawyers)>1: form = SearchForm(initial={'last_name': last_name}) return render_to_response('more_than_1_match.html', {'lawyers': lawyers, 'last': last_name, 'first': first_name, 'form': form}) q_school = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('school', flat=True) q_year = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('year_graduated', flat=True) lawyers1 = Lawyer.objects.filter(school__iexact=q_school[0]).filter(year_graduated__icontains=q_year[0]).exclude(last__icontains=last_name) form = SearchForm() return render_to_response('search_results.html', {'lawyers': lawyers1, 'last': last_name, 'first': first_name, 'form': form}) else: form = SearchForm() return render_to_response('search_form.html', {'form': form, })

    Read the article

  • Is there a Django template tag that lets me set a context variable?

    - by hekevintran
    I want to be able to set variables in a template to string values. I wrote a tag, but it doesn't seem to change the context. The intended use is: {% define my_var as "a string" %} class DefineNode(Node): def __init__(self, value, variable_name, nodelist): self.value = value self.variable_name = variable_name self.nodelist = nodelist def __repr__(self): return "<DefineNode>" def render(self, context): context[self.variable_name] = self.value return '' @register.tag def define(parser, token): bits = list(token.split_contents()) if len(bits) != 4: raise TemplateSyntaxError("%r expected format is 'value as variable'" % bits[0]) if bits[1][0] in ('"', "'") and bits[1][-1] == bits[1][0]: value = bits[1][1:-1] nodelist = parser.parse(('enddefine',)) parser.delete_first_token() return DefineNode(value, bits[3], nodelist) I

    Read the article

  • Display a boolean model field in a django form as a radio button rather than the default Checkbox.

    - by Lakshman Prasad
    This is how I went about, to display a Boolean model field in the form as Radio buttons Yes and No. choices = ( (1,'Yes'), (0,'No'), ) class EmailEditForm(forms.ModelForm): #Display radio buttons instead of checkboxes to_send_form = forms.ChoiceField(choices=choices,widget=forms.RadioSelect) class Meta: model = EmailParticipant fields = ('to_send_email','to_send_form') def clean(self): """ A workaround as the cleaned_data seems to contain u'1' and u'0'. There may be a better way. """ self.cleaned_data['to_send_form'] = int(self.cleaned_data['to_send_form']) return self.cleaned_data As you can see in the code above, I need a clean method that converts input string to an integer, which may be unnecessary. Is there a better and/or djangoic way to do this. If so, how? And no, using BooleanField seems to cause a lot more problems. Using that seemed obvious to me; but it isn't. Why is it so.

    Read the article

  • Django: How can I delete a formset entry if one of it's data is blank?

    - by mkret
    Hi, I have the following scenario: I have a form with data that does not need translation and a formset with a textfield that should be translated into an undefined amount of languages. Both parts are bound to a model. Each translated text is kept in a model with a foreign key that binds it to the untranslatable data. Something like: class Person(models.Model): name = models.CharField(max_length=60) birth_date = models.DateField() class PersonBio(models.Model): person = models.ForeignKey(Person) locale = models.CharField(max_length=10) bio = models.TextField() Each form in the formset has 2 fields: A textfield (with the translated text) A locale field (with the language into which the text was translated) I've got it working with no problems until I tryed to change it's normal behaviour. I wanted to eliminate the need for the DELETE field by deleting an instance of the translated text if the textfield was left blank. I've googled quite a lot now and read the whole documentation for forms, formsets and model validation but had no luck. To be honest, I couldn't even think of a solution. Where should I implement this? On a Form clean() method? On the view? Somewhere in the Fieldset? Fieldset's save() method, maybe? I'll keep trying to find a way to do that, but any help/tip/clue is appreciated. Thanks in advance.

    Read the article

  • Sorting and indexing into a list in a Django template?

    - by slypete
    How can you perform complex sorting on an object before passing it to the template? For example, here is my view: @login_required def overview(request): physicians = PhysicianGroup.objects.get(pk=physician_group).physicians for physician in physicians.all(): physician.service_patients.order_by('bed__room__unit', 'bed__room__order', 'bed__order') return render_to_response('hospitalists/overview.html', RequestContext(request, {'physicians': physicians,})) The physicians object is not ordered correctly in the template. Why not? Additionally, how do you index into a list inside the template? For example, (this doesn't work): {% for note_type in note_types %} <div><h3>{{ note_type }}</h3> {% for notes in note_sets.index(parent.forloop.counter0) %} #only want to display the notes of this note_type! {% for note in notes %} <p>{{ note }}</p> {% endfor %} {% endfor %} </div> {% endfor %}

    Read the article

  • Can I filter a django model with a python list?

    - by Rhubarb
    Say I have a model object 'Person' defined, which has a field called 'Name'. And I have a list of people: l = ['Bob','Dave','Jane'] I would like to return a list of all Person records where the first name is not in the list of names defined in l. What is the most pythonic way of doing this?

    Read the article

  • How do I memoize expensive calculations on Django model objects?

    - by David Eyk
    I have several TextField columns on my UserProfile object which contain JSON objects. I've also defined a setter/getter property for each column which encapsulates the logic for serializing and deserializing the JSON into python datastructures. The nature of this data ensures that it will be accessed many times by view and template logic within a single Request. To save on deserialization costs, I would like to memoize the python datastructures on read, invalidating on direct write to the property or save signal from the model object. Where/How do I store the memo? I'm nervous about using instance variables, as I don't understand the magic behind how any particular UserProfile is instantiated by a query. Is __init__ safe to use, or do I need to check the existence of the memo attribute via hasattr() at each read? Here's an example of my current implementation: class UserProfile(Model): text_json = models.TextField(default=text_defaults) @property def text(self): if not hasattr(self, "text_memo"): self.text_memo = None self.text_memo = self.text_memo or simplejson.loads(self.text_json) return self.text_memo @text.setter def text(self, value=None): self.text_memo = None self.text_json = simplejson.dumps(value)

    Read the article

  • How do I modify the HttpResponse object in django ?

    - by Rohit
    I need the html returned using render_to_response to be escaped. I am unable to find any suitable documentation. Can someone point in some direction ? the code is : return render_to_response(template_name, {return render_to_response(template_name, { 'form': form, redirect_field_name: redirect_to, 'site': current_site, 'site_name': current_site.name, }, context_instance=RequestContext(request)) Here I need the response html text to be escaped. I way I know is reading template file in string and escaping it with re.escape() and then rendering it. whats a cleaner and simpler way to do that ??

    Read the article

  • Django: How to iterate over formsets and access cleaned data?

    - by Mark
    What if I want to do something with my formset other than immediately saving it? How can I do this? for form in vehicles_formset.forms: listing.id = None listing.vehicle_year = form.cleaned_data['year'] listing.vehicle_make = form.cleaned_data['make'] listing.vehicle_model = form.cleaned_data['model'] listing.vin = form.cleaned_data['vin'] listing.vehicle_runs = form.cleaned_data['runs'] listing.vehicle_convertible = form.cleaned_data['convertible'] listing.vehicle_modified = form.cleaned_data['modified'] listing.save() (Thus creating multiple listings) Apparently cleaned_data does not exist. There's a bunch of stuff in the data dict like form-0-year but it's pretty useless to me like that.

    Read the article

  • How to preprocess a Django model field value before return?

    - by Satoru.Logic
    Hi, all. I have a Note model class like this: class Note(models.Model): author = models.ForeignKey(User, related_name='notes') content = NoteContentField(max_length=256) NoteContentField is a custom sub-class of CharField that override the to_python method in purpose of doing some twitter-text-conversion processing. class NoteContentField(models.CharField): __metaclass__ = models.SubfieldBase def to_python(self, value): value = super(NoteContentField, self).to_python(value) from ..utils import linkify return mark_safe(linkify(value)) However, this doesn't work. When I save a Note object like this: note = Note(author=request.use, content=form.cleaned_data['content']) The conversed value is saved into the database, which is not what I wanna see. Would you please tell me what's wrong with this? Thanks in advance.

    Read the article

  • How elevate and get admin rights on-demand in a .NET application?

    - by sashaeve
    I have an .NET application which is run with default rights as the current user, then at some point I need to perform an action which requires admin rights. How can I get admin rights on-demand in a .NET application? Requiring that the application is run with admin rights from the beginning is not appropriate as it may be that such action may not be called.

    Read the article

< Previous Page | 50 51 52 53 54 55 56 57 58 59 60 61  | Next Page >