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  • How to Get Your Website on Top of Google

    Have you ever searched for something then just clicked the very first thing that came to the top? Well even if you haven't plenty of other people out there do this. So if they search for your site's category then you better be the one at the top of the list. If not first then let's try to make it on the first page at least.

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  • Get to the Top of Google With Blogging

    There are many websites out there all trying to get noticed by the search engines which will in turn help them to be found by users. Every website wants more traffic coming into it whether it is providing information or selling products.

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  • Microsoft marches on Android and Linux

    <b>Cyber Cynic:</b> "Microsoft has never proven, or even attempted to prove, any of these claims. That hasn't, however, stopped Microsoft from using the threat of Linux patent lawsuit to force companies like Amazon into paying them off."

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  • Google Chrome Extensions For SEO

    With more than 12% of internet users now using Chrome, it has obviously become the browser of choice for many power users. As a result, a number of extremely useful plug-ins have been created for Chrome, including many which are highly relevant to SEO professionals. What follows is a sampling of the most useful.

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  • Difference between a Deprecated and an Legacy API?

    - by Vaibhav Bajpai
    I was studying the legacy API's in the Java's Collection Framework and I learnt that classes such as Vector and HashTable have been superseded by ArrayList and HashMap. However still they are NOT deprecated, and deemed as legacy when essentially, deprecation is applied to software features that are superseded and should be avoided, so, I am not sure when is a API deemed legacy and when it is deprecated.

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  • J2ME development and native API

    - by Attilah
    Is it possible to write a mobile application with J2ME and whenever we want to implement a functionality not offered by J2ME call native mobile API ? (kind of like what is done with .NET, whenever you need something not provided, you just call the Win32 API from the .NET platform).

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  • How can data not stored in a DB be accessed from any activity in Android?

    - by jul
    hi, I'm passing data to a ListView to display some restaurant names. Now when clicking on an item I'd like to start another activity to display more restaurant data. I'm not sure about how to do it. Shall I pass all the restaurant data in a bundle through the intent object? Or shall I just pass the restaurant id and get the data in the other activity? In that case, how can I access my restaurantList from the other activity? In any case, how can I get data from the restaurant I clicked on (the view only contains the name)? Any help, pointers welcome! Thanks Jul ListView lv= (ListView)findViewById(R.id.listview); lv.setAdapter( new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1,restaurantList.getRestaurantNames())); lv.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View view, int position, long id) { Intent i = new Intent(Atable.this, RestaurantEdit.class); Bundle b = new Bundle(); //b.putInt("id", ? ); startActivityForResult(i, ACTIVITY_EDIT); } }); RestaurantList.java package org.digitalfarm.atable; import java.util.ArrayList; import java.util.List; public class RestaurantList { private List<Restaurant> restaurants = new ArrayList<Restaurant>(); public List<Restaurant> getRestaurants() { return this.restaurants; } public void setRestaurants(List<Restaurant> restaurants) { this.restaurants = restaurants; } public List<String> getRestaurantNames() { List<String> restaurantNames = new ArrayList<String>(); for (int i=0; i<this.restaurants.size(); i++) { restaurantNames.add(this.restaurants.get(i).getName()); } return restaurantNames; } } Restaurant.java package org.digitalfarm.atable; public class Restaurant { private int id; private String name; private float latitude; private float longitude; public int getId() { return this.id; } public void setId(int id) { this.id = id; } public String getName() { return this.name; } public void setName(String name) { this.name = name; } public float getLatitude() { return this.latitude; } public void setLatitude(float latitude) { this.latitude = latitude; } public float getLongitude() { return this.longitude; } public void setLongitude(float longitude) { this.longitude = longitude; } }

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  • Windows API Error 2 when installing MikTex (Win7)

    - by GreenAsJade
    I am trying to install MikTex 2.9.3927 on Windows 7 x64. Very early in the installation process, I get a MikTex setup wizard error saying: "Windows API Error 2: The system cannot find the file specified Details: C:...\somefile.tpm" The file that results in the error seems to be different every time I try. I have tried many different installation paths, with many different setup options. The same error occurs if I download the ~138MB "Basic MiKTeX 2.9" Installer or if I use the Net Installer to download the entire setup (~1GB). Note that this is a duplicate question - the other copy of this question is closed to users of under 10 rep. I have asked it so that I can provide an updated answer...

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  • Android: Stopping method to be called twice if already running.

    - by user285831
    I'm trying to prevent my application to call the same method twice in the event of a double-click, or if the user presses different buttons quickly, almost at the same time. I have clickable Views, acting as buttons, that call the same method but passing different parameters. This is the call: startTheSearch(context, getState(), what, where); Inside this method I'm creating a new Thread, because it queries a web server for the result: new Thread(new Runnable() { public void run() { progDiag = ProgressDialog.show(ctx, null, "Searching", true); getServerXML(context, what, where, searchIsCustom, mOffset); handler.sendEmptyMessage(0); } }).start(); The problem is that upon two quick clicks, the method is fired twice, two threads are created, and consequently two new activities are created. That makes my app crash. When the methods are done, and we have the result from the server, we call the handler: private Handler handler = new Handler() { @Override public void handleMessage(Message msg) { super.handleMessage(msg); try { Intent i = new Intent(Golf.this, Result.class); Bundle b = new Bundle(); b.putString("what", mWhat); b.putString("where", mWhere); b.putInt("offset", mOffset); b.putBoolean("searchIsCustom", searchIsCustom); i.putExtras(b); startActivityForResult(i, Activity.RESULT_OK); progDiag.dismiss(); } catch (Exception e) { Alerts.generalDialogAlert("Error", "settings", ctx); } } }; I tried to have a global boolean variable called "blocked" initially set to false, creating a condition like: if(!blocked){ blocked = true; new Thread(new Runnable() { public void run() { But this only seems to work on slower phones like the G1, I tried on Nexus and before it set blocked = true, the second request has was granted. So is there any way I can block the method being called if it's already running, or if the thread has started so it wont create a new one? Please, I really need to fix this. I've been developing on Android for almost 2 months now, but I'm yet to tackle that bug. Thanks in advance.

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  • How can I get sessions to work if I'm using Google App Engine + Django 1.1?

    - by user341642
    Is there a way for me to get sessions working? I know Django has built in session management, and GAE has some tools for it if you're using their watered down version of Django 0.96, but is there a way to get sessions to work if you're trying to use GAE w/ Django 1.1 (i.e. use_library() call). I assume using a db-backed session doesn't work, and a file system backed one won't work b/c we don't have access to the filesystem if we deploy to the Google production servers. This kinda worked (as in didn't crap out) when I used SessionMiddleware backed by a local-memory backed cache and a non-persistent cache (i.e. setting SESSION_ENGINE to django.contrib.sessions.backends.cache). But the session never seems to persist in this case, no matter how I set the timeouts. A new session key is generated on every page reload. Maybe this is b/c the GAE assumes complete statelessness with each request and blows away my local cache? Apologies in advance, I'm pretty new to Python. Any suggestions would be greatly appreciated.

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  • question on src folders in eclipse

    - by Jeff Colapietro
    So, I've been doing android application tutorials and everytime I create a package, for example the helloAndroid tutorial is com.example.android. When it saves this to src it creates a folder for com, another for example and one last one for android. So it gives me the error "class com.example.android does not exist" because its broken into different folders. If anyone can help me out please email me at: [email protected] Thank you very much.

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  • understanding an API

    - by adusum
    I know that there are many API's like json,Facebook,twitter etc for developing related applications on iphone....but how to understand an API?This might be scilly question but I want to know how? what would you suggest for for a beginner?

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