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  • how to use an mdf in App_Data with shared hosting

    - by name
    If I create a website that uses an mdf in App_Data with the connection string: Server=.\SQLExpress;AttachDbFilename=|DataDirectory|mydbfile.mdf;Database=dbname; Trusted_Connection=Yes; what do I need to do to run the site in a shared hosting environment? Do I need to copy the contents of my mdf to the main SQL Server engine of my host? Is there a way to use the non-SQLExpress engine of my host and still keep my mdf in my App_Data?

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  • sql to xml using linq - nested collections

    - by nelsonwebs
    I have a table of data that looks something like this. name, hour, price1, price2, price3, price4, price5 fred, 3, 12.5, 13.5, 14, 15, 16 dave, 6, 8, 12, 18, 20.2, 25 fred, 6, 10, 11, 14, 15, 19.7 This table needs to be output to an xml file that looks like this. <timeCost> <person name="fred"> <time hour="5"> <cost price="12.5" /> <cost price="13.5" /> <cost price="14" /> <cost price="15" /> <cost price="16" /> </time> <time hour="6"> <cost price="10" /> <cost price="11" /> <cost price="14" /> <cost price="15" /> <cost price="19.7" /> </time> </person> <person name="dave"> <time hour="6"> <cost price="8" /> <cost price="12" /> <cost price="18" /> <cost price="20.2" /> <cost price="25" /> </time> </person> </timeCost> I have a linq query to get the data from SQL something like this. // initialize data context var people = from p in dc.people orderby p.name, p.hour select p; However, I'm having trouble writing the xml out using linq (csharp). Specifically, the problem is I don't know how to deal with having multiple time nodes under each name node (nested loops/collections). How can this be done? This is a sql 08 ent db if it matters to anyone.

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  • using or in mysql and merging columns

    - by Pradyut Bhattacharya
    I can select using or with the sql statement select f.userid, f.friend_userid from friends f where userid = 1 or friend_userid = 1; now in the output i have to merge the two rows(userid and friend_userid) into one row such that only the rows without 1 are displayed I m using mysql.... Thanks Pradyut India

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  • Asp.net web site and web service hosting

    - by Razvi
    I have a web site and a web service and I would like to host them somewhere. I need to use it mostly for testing and so that a some friends who are developing some applications to use the service have access to it. Also the service is using a MS SQL 2008 database. Could you suggest any good free or cheap web hosting service for this. I would need about 1-2 months of hosting.

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  • Oracle Sql Developer vendor code 1317

    - by Zemian
    Hi, I am using Oracle Sql Developer to browse a MySQL database. When I browse table with Columns tab(shows table definitions), some of tables will display an Error Encountered dialog that says: Vendor code 1317. Does anyone know how I can resolve this? Thanks, /Z

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  • See images in SSMS?

    - by Vaccano
    I was browsing around and found this blog post: http://erikej.blogspot.com/2010/04/version-3-of-exportsqlce-now-available.html (It is for a great add in if you user SQL Server CE.) On that post I saw an screen shot of SSMS with images in the results. How is this done? I have images in my database (PNG files that are serialized via memory stream), but I just see numbers when I select the image column.

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  • Determine if an Index has been used as a hint

    - by Joe Bloggs
    In SQL Server, there is the option to use query hints. eg SELECT c.ContactID FROM Person.Contact c WITH (INDEX(AK_Contact_rowguid)) I am in the process of getting rid of unused indexes and was wondering how I could go about determining if an index was used as a query hint. Does anyone have suggestions on how I could do this? Cheers, Joe

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  • How may I create an horizontal view from a tree table

    - by Giuseppe Alfieri
    I want to create a view for each tree for each customer of this 3 table structured in this way: Fields: db_attrib.name, db_attrib.name, db_attrib.name until the last db_tree.id_child = 0 Values: db_attrib_values.value where db_attrib.id = db_attrib_value.id_attrib and so on for each child And so on for each db_tree.id This is the link to sql fiddle with the prepared structure: http://sqlfiddle.com/#!9/21516

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