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  • Java: how to have global values inside a class?

    - by HH
    I want less methods. I want a common global TestClass from which I could use any of its value inside the class. import java.util.*; import java.io.*; public class TestClass { TestClass(String hello){ String hallo = hello; String halloSecond = "Saluto!"; } public static void main(String[] args) { TestClass test = new TestClass("Tjena!"); System.out.println("I want "Tjena!": " + test.hallo); TestClass testSecond = new TestClass("1"); System.out.println("I want Saluto!:" + test.halloSecond); System.out.println("I want Saluto!:" + testSecond.halloSecond); // How can I get glob.vars like the "Saluto!"? } }

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  • Send and receive Array as GET/POST using querystring

    - by Vanwaril
    I've got the following code, but it doesn't seem to work: var post_req = { array: [ [ { param1: 'something', param2: 123 } ], [ ], [ ], [ { param2: 'something', param4: 1234, param1: 'hello' } ] ] }; var data_send = querystring.stringify(post_req); var request = client.request('POST', '/', headers); request.end(data_send); and if( req.method == 'POST' ) { req.addListener('data', function(chunk) { POST = querystring.parse(chunk); console.log(POST); } } I end up with 5 sub-arrays, corresponding to the 5 parameters in the objects but with extra '][' characters in their names: { array: [ { '][param1': 'something' } , { '][param2': '123' } , { '][param2': 'something' } , { '][param4': '1234' } , { '][param1': 'hello' } ] }

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  • Problem separating C++ code in header, inline functions and code.

    - by YuppieNetworking
    Hello all, I have the simplest code that I want to separate in three files: Header file: class and struct declarations. No implementations at all. Inline functions file: implementation of inline methods in header. Code file: normal C++ code for more complicated implementations. When I was about to implement an operator[] method, I couldn't manage to compile it. Here is a minimal example that shows the same problem: Header (myclass.h): #ifndef _MYCLASS_H_ #define _MYCLASS_H_ class MyClass { public: MyClass(const int n); virtual ~MyClass(); double& operator[](const int i); double operator[](const int i) const; void someBigMethod(); private: double* arr; }; #endif /* _MYCLASS_H_ */ Inline functions (myclass-inl.h): #include "myclass.h" inline double& MyClass::operator[](const int i) { return arr[i]; } inline double MyClass::operator[](const int i) const { return arr[i]; } Code (myclass.cpp): #include "myclass.h" #include "myclass-inl.h" #include <iostream> inline MyClass::MyClass(const int n) { arr = new double[n]; } inline MyClass::~MyClass() { delete[] arr; } void MyClass::someBigMethod() { std::cout << "Hello big method that is not inlined" << std::endl; } And finally, a main to test it all: #include "myclass.h" #include <iostream> using namespace std; int main(int argc, char *argv[]) { MyClass m(123); double x = m[1]; m[1] = 1234; cout << "m[1]=" << m[1] << endl; x = x + 1; return 0; } void nothing() { cout << "hello world" << endl; } When I compile it, it says: main.cpp:(.text+0x1b): undefined reference to 'MyClass::MyClass(int)' main.cpp:(.text+0x2f): undefined reference to 'MyClass::operator[](int)' main.cpp:(.text+0x49): undefined reference to 'MyClass::operator[](int)' main.cpp:(.text+0x65): undefined reference to 'MyClass::operator[](int)' However, when I move the main method to the MyClass.cpp file, it works. Could you guys help me spot the problem? Thank you.

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  • Python:How to override inner class methods if the inner class is defined as a property of the top cl

    - by Maddy
    I have a code snippet like this class A(object): class b: def print_hello(self): print "Hello world" b = property(b) And I want to override the inner class 'b'(please dont worry about the lowercase name) behaviour. Say, I want to add a new method or I want to change an existing method, like: class C(A): class b(A.b): def print_hello(self): print "Inner Class: Hello world" b = property(b) Now if I create C's object as c = C(), and call c.b I get TypeError: 'property' object is not callable error. How would I get pass this and call print_hello of the extended inner class? Disclaimer: I dont want to change the code for A class.

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  • Apply function to one element of a list in Python

    - by user189637
    I'm looking for a concise and functional style way to apply a function to one element of a tuple and return the new tuple, in Python. For example, for the following input: inp = ("hello", "my", "friend") I would like to be able to get the following output: out = ("hello", "MY", "friend") I came up with two solutions which I'm not satisfied with. One uses a higher-order function. def apply_at(arr, func, i): return arr[0:i] + [func(arr[i])] + arr[i+1:] apply_at(inp, lambda x: x.upper(), 1) One uses list comprehensions (this one assumes the length of the tuple is known). [(a,b.upper(),c) for a,b,c in [inp]][0] Is there a better way? Thanks!

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  • ASP Classic Named Parameter in Paramaterized Query: Must declare the scalar variable

    - by My Alter Ego
    I'm trying to write a parameterized query in ASP Classic, and it's starting to feel like i'm beating my head against a wall. I'm getting the following error: Must declare the scalar variable "@something". I would swear that is what the hello line does, but maybe i'm missing something... <% OPTION EXPLICIT %> <!-- #include file="../common/adovbs.inc" --> <% Response.Buffer=false dim conn,connectionString,cmd,sql,rs,parm connectionString = "Provider=SQLOLEDB.1;Integrated Security=SSPI;Data Source=.\sqlexpress;Initial Catalog=stuff" set conn = server.CreateObject("adodb.connection") conn.Open(connectionString) set cmd = server.CreateObject("adodb.command") set cmd.ActiveConnection = conn cmd.CommandType = adCmdText cmd.CommandText = "select @something" cmd.NamedParameters = true cmd.Prepared = true set parm = cmd.CreateParameter("@something",advarchar,adParamInput,255,"Hello") call cmd.Parameters.append(parm) set rs = cmd.Execute if not rs.eof then Response.Write rs(0) end if %>

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  • string manipulations in C

    - by Vivek27
    Following are some basic questions that I have with respect to strings in C. If string literals are stored in read-only data segment and cannot be changed after initialisation, then what is the difference between the following two initialisations. char *string = "Hello world"; const char *string = "Hello world"; When we dynamically allocate memory for strings, I see the following allocation is capable enough to hold a string of arbitary length.Though this allocation work, I undersand/beleive that it is always good practice to allocate the actual size of actual string rather than the size of data type.Please guide on proper usage of dynamic allocation for strings. char *string = (char *)malloc(sizeof(char));

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  • Why doesn't C# allow for global inferred types i.e. using var?

    - by BritishDeveloper
    I know it can't be done since using var can only be done for local variables. I'm just wondering if anyone has a theory why the C# team thought this should be so. e.g. what would be wrong with this: public class SomeClass { var someString = "hello"; //not cool public SomeClass() { var someOtherString = "hello"; //cool } } If someString is initialised then it is obviously a string just like someOtherString. Why is there one rule for local variables and another for globals?

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  • Using Python simplejson for transmitting JSON to another server results in unicode encoding problems

    - by Mark
    Hi there, I'm encoding a string with Python's simplejson library with special characters: hello testing spécißl characters plusses: +++++ special chars :œ?´®†¥¨ˆøp“ß?ƒ©??°¬O˜çv?˜µ== However, when I encode it and transmit it to the other machine (using POST), it turns out like this: {'message': ['{"body": "hello testing sp\\u00e9ci\\u00dfl characters\\n\\nplusses: \\n\\nspecial chars :\\u0153\\u2211\\u00b4\\u00ae\\u2020\\u00a5\\u00a8\\u02c6\\u00f8\\u03c0\\u201c\\u00df\\u2202\\u0192\\u00a9\\u02d9\\u2206\\u02da\\u00ac\\u03a9\\u2248\\u00e7\\u221a\\u222b\\u02dc\\u00b5\\u2264\\u2265"}']} The + signs are completely stripped and the rest are in this unicode(?) format. My code for this is: data = {'body': data_string} data_encoded = json.dumps(data) Any ideas? Thanks! Edit: I've tried using json.dumps(data, ensure_ascii=False) but it results in a UnicodeError ordinal not in range error.

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  • Validating XML with multiple XSDs in Java

    - by Arian
    Hello! I want to parse an XML file with Java and validate it in the same step against an XSD schema. An XML file may contain content of several schemas, like this: <outer xmlns="my.outer.namespace" xmlns:x="my.third.namespace"> <foo>hello</foo> <inner xmlns="my.inner.namespace"> <bar x:id="bar">world</bar> </inner> </outer> Given a namespace the corresponding xsd file can be provided, but the used namespaces are unknown before parsing. If a schema defines default values for attributes, I also want to know that somehow. I was able to validate a file if the schemas are known, I was able to parse a file without validation and I implemented a LSResourceResolver. However, I can't get all of it working together. How do I have to set up my (SAX) parser?

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  • Netbeans C++ not finding standard libraries (Macintosh)

    - by Grue
    Hello everyone! I am trying to use Netbeans 6.7 (on a Mac) to create C++ applications. I started out with the standard "Hello World," just to test if everything was working correctly. First try std and could not be found. So I tried reinstalling the developer tools on my Mac OS X disk. After that Netbeans updated its c++ compiler info, but still cannot find std or . Odder than this XCode seems to be working with C++ perfectly fine. Any help fixing this would be greatly appreciated.

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  • Why do I get a "warning: no newline at end of file" ?

    - by user198729
    The file is a helloworld.cpp: #include <iostream> using namespace std; int main() { if(true) cout << "!!!Hello World!!!" << endl; // prints !!!Hello World!!! return 0; } But when I build it,get a warning: g++ -Wall -O2 -c -o hw.o hw.cpp hw.cpp:8:2: warning: no newline at end of file g++ -o myprog hw.o If I add a newline at the end,the warning will go. Why is that newline at end of file recommended in a cpp source file?

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  • PHP/MySQL Database Issues

    - by queryne
    PHP/MySQL newbie question. I have a database I've imported into my local phpmyadmin. However it seems I can't access it from my a php application. The connection string seems right and when I try to authenticate user credentials to access database information, no problems. However authenticate everyone and knows when I put in fake credentials. Still it won't pull any other information from the database. For instance, once a users login they should see something like, "Hello username", that kind of thing. At this point I see "Hello" without the username. Any ideas what i might be missing?

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  • C++ conditional compilation

    - by Shaown
    I have the following code snippet #ifdef DO_LOG #define log(p) record(p) #else #define log(p) #endif void record(char *data){ ..... ..... } Now if I call log("hello world") in my code and DO_LOG isn't defined, will the line be compiled, in other words will it eat up the memory for the string "hello world"? P.S. There are a lot of record calls in the program and it is memory sensitive, so is there any other way to conditionally compile so that it only depends on the #define DO_LOG? Thanks in advance.

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  • How can I create or assign a method to temp (WindowAdapter)?

    - by Doug Hauf
    I want to create an instance of the WindowAdapter and put my method for windowClosing in it and then sent the temp into the f.addWindowListener(temp) can this be done. Java will not let me create an instance of WindowAdapter like below. WindowAdapter temp = new WindowAdapter(); <-- Does not compile How could this be done? Code: public static void main(String args[]) { setLookFeel(); JFrame f = new JFrame("Hello World Printer..."); WindowAdapter temp; f.addWindowListener(new WindowAdapter() { public void windowClosing(WindowEvent e) { System.exit(0); } }); JButton printButton = new JButton("Print Hello World"); printButton.addActionListener(new HelloWorldPrinter()); f.add("Center", printButton); f.pack(); f.setVisible(true); }

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