Search Results

Search found 32007 results on 1281 pages for 'php openid'.

Page 551/1281 | < Previous Page | 547 548 549 550 551 552 553 554 555 556 557 558  | Next Page >

  • woocommerce show attribute description when selecting a variable

    - by user2916995
    I'm trying to figure out a way to display custom text based on the users selection of the variable product. The attribute is 'pricing' and the tag is deposit - which I've added a text description to when adding the attribute. So I'm trying to make this text appear when the user selects 'deposit' But the code I'm using in 'content-single-product.php' is displaying the text all the time no matter what variable is selected or not. <?php $my_taxonomy = 'pa_pricing'; $terms = wp_get_post_terms( $post->ID, $my_taxonomy ); echo term_description($terms[0]->term_id, $my_taxonomy); ?> I only want the text to be displayed after the user has selected pricing 'deposit' Can someone help me with this?

    Read the article

  • open_basedir restriction does not allow me to use rename() or write files in a dir.

    - by lukasoppermann
    Hey, I have a php file (currently at / ) and I want this file to change the content of a file, "test.js". This file is in the dir "/libs/js/test.js". While I can read the content, for example with fread or file_get_contents, I can not write in it with file_put_contents or any other function. I always get the Warning Warning: rename() [function.rename]: open_basedir restriction in effect. File(/libs/js/test.js) is not within the allowed path(s): (/var/www/web166/:/usr/bin/) in /var/www/web166/html/info.php on line 88 Does anyone have any idea what to do? Thanks in advance.

    Read the article

  • How can I store and access SQLite databases from a central location?

    - by Brian Ramsay
    I have installed SQLite on my UNIX system, and am planning on accessing it from PHP. However, the database is created in the directory I initialize it in, and if a script runs in a different directory a new database is created in the same directory. Is there an option for SQLite (or the PHP wrappers) to create the databases in one location, and have those databases accessible just by name outside of that directory? Ideally, I'd like to be able to do something like $db=new SQLiteDatabase("db.test"); in any directory and have it reference the same database, if that makes sense.

    Read the article

  • Getting Null value with JSON from MySQL, how to retrive data from MySQL to JSON correctly?

    - by sky
    I'm using following code but cannot return data from MySQL. This is the output: <script type="text/javascript"> var somethings= [null,null,null]; </script> It does have three post, but I couldn't get the title(message) output. EDIT: this is the code I'm using: <?php $session = mysql_connect('localhost','name','pass'); mysql_select_db('dbname', $session); $result= mysql_query('SELECT * FROM posts', $session); $somethings= array(); while ($row= mysql_fetch_assoc($result)) { $somethings[]= $row['something']; } ?> <script type="text/javascript"> var somethings= <?php echo json_encode($somethings); ?>; </script> This is the table: message Try iPhone post! Welcome to Yo~ :) ??!

    Read the article

  • "slash before every quote" problem

    - by Camran
    I have a php page which contains a form. Sometimes this page is submitted to itself (like when pics are uploaded). I wouldn't want users to have to fill in every field again and again, so I use this as a value of a text-input inside the form: value="<?php echo htmlentities(@$_POST['annonsera_headline'],ENT_COMPAT,'UTF-8');?>"> This works, except it adds a "\" sign before every double-quote... For instance writing 19" wheels gives after page is submitted to itself: 19\" wheels And if I don't even use htmlentities then everything after the quotes dissappears. What is the problem here?

    Read the article

  • Upload files, form within form

    - by Alexd2
    Hello everyone and thanks in advance. I have a problem and I have 2 form into one another, the domestic form is to perform a file upload. As I can do to make when sending in internal form not run the main form. <form name="x" method="post" action="xxx.php"> .... <form action="" method="post" enctype="multipart/form-data" target="xxx"> <input type="file" /> <input type="submit" /> </form> <iframe id="xxx" src="process.php"> </iframe> .... <input type="submit" name="pro" value="Register user"/ > </form> Doing this does not work, as this within another form. Any help or possible solution.

    Read the article

  • weird problem..the exact xml work in one host and not working in another...

    - by Ofear
    hi all! i search alot for this but can't find an aswer... I have made a working xml parser using php. till today i host my files on a free web host, and everything works just fine. today i got access to my college server and i host my files there. now for some reason.. i can't make the parser work as i was in the free host... look on those files please: working site: xml file: [http://ofear.onlinewebshop.net/asce/calendar.xml] working parser is this: [http://ofear.onlinewebshop.net/asce/calendar.php] (the lower table is the xml,it's hebrew) not working site: xml file: [http://apps.sce.ac.il/agoda/calendar.xml] not working parser is this: [http://apps.sce.ac.il/agoda/calendar.php] anyone have idea why it's not working.. those are the same files and they should work. maybe it a server problem? calendar.xml: <?xml version="1.0" encoding="UTF-8" ?> <events> <record> <event>??? ???? ????? ???? ???</event> <eventDate>30/12/2010</eventDate> <desc>?????? ?? ????</desc> </record> <record> <event>??? ???? ??????? - 2 : ???? ??? ???? ??????</event> <eventDate>22/12/2010</eventDate> <desc>????? ???? ??????? ?????? ??? ???? ??????? ?????? ????? ?????? ?? ??? ???? ??????? 2 ??????? ????? ???????? 22-23 ?????? 2010. ???? ????? ???? ????? "?????? ????"</desc> </record> <record> <event>????? ???? ?????? ?????? - ?? ????</event> <eventDate>5/12/2010</eventDate> <desc>??? ????? 17:30-20:45</desc> </record> </events> parser: <?php $doc = new DOMDocument(); $doc->load( 'calendar.xml' ); $events = $doc->getElementsByTagName( "record" ); foreach( $events as $record ) { $events = $record->getElementsByTagName( "event" ); $event = $events->item(0)->nodeValue; $eventDates= $record->getElementsByTagName( "eventDate" ); $eventDate= $eventDates->item(0)->nodeValue; $descs = $record->getElementsByTagName( "desc" ); $desc = $descs->item(0)->nodeValue; echo "<tr><td>$event</td><td>$eventDate</td><td>$desc</td></tr>"; } ?> after a little debugging i saw that it's stop here: $doc = new DOMDocument(); and it's not doing anything after that. i think that the line above is the cos

    Read the article

  • User's Post count from specific category [Wordpress]

    - by morningglory
    Hello, I want to show user's post count from specific category. Currently, I can only be able to query all posts. My code is like this <?php $userpost_count = $wpdb->get_var("SELECT COUNT(*) FROM $wpdb->posts WHERE post_status = 'publish' AND post_type ='post' AND post_author = '".$curauth->ID."'");?> <?php echo "<span>Total post: </b></span>".$userpost_count.""?> I know that, I need to join two table which is post table and term_relationships, but i don't know how to get it. Please kindly help me with that. Thank you.

    Read the article

  • session variable values are not being passed between pages

    - by ravi nankani
    hi, i am a little new to php and although i have managed to pass values of session variables before this piece of code is leaving me puzzled <form action="team_reg2.php" method="post" name="form1" class="cent" id="form1"> Team Registration "; print "member$i"; print "\n"; print "\n"; print "Please enter only id\n"; } ? now this will pass via post to team_reg2.php echo " please note your team id is 1 "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } else { $str="select * from $query where ("; for($i=1;$i<=$num;$i++) { $name='mem'.$i; $text="p_id='$_POST[$name]'"; if($i==1) $str=$str.$text; else $str=$str.' or '.$text; } $str=$str.')'; $query2=$str; echo "$str"; // echo "$query2"; $que=mysql_query($query2,$con) or die(mysql_error()); $num=mysql_num_rows($que); if($num!=0) { while($result=mysql_fetch_array($que)) { echo "$result[p_id] is already registered in team $result[t_id]"; } //include("reg_team.html"); } else if($num==0) { //echo $query; $query2="select max(t_id) from $query"; $que=mysql_query($query2,$con) or die(mysql_error()); //echo "$que"; $result=mysql_fetch_array($que); $max=$result['max(t_id)']; $max++; $num=$_SESSION['max_team']; for($i=1;$i<=$num;$i++) { $name='mem'.$i; if($_POST[$name]!="") { $query2="insert into $query values($max,'$_POST[$name]')"; $que=mysql_query($query2,$con); } } echo " please note your team id is $max "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } } ? i have done session_start(); at the beginning of the page itself. The problem is that echoing $_SESSION variables in second file is not printing anything. someone please explain me whats going on. thank you

    Read the article

  • Export XML with only one MySQL request ?

    - by mere-teresa
    I want to export in XML format some data from 7 tables (MySQL database), and then I want to import in another database. And I have a update or insert rule for data. I already have a SQL query retrieving all data, with JOINs on my 7 tables. But...when I try to put data in XML format, I reach a limit. My PHP loop can catch each row, but I would like to benefit from hierachical structure of the XML, and all I have are rows with the same data repeated. It is better to query once and to construct the XML tree in PHP or to query each time I want access to a lower level ?

    Read the article

  • Is there any way to use imagegrabwindow() with Firefox or Chrome?

    - by patternsofchaos
    I'm trying to generate website thumbnails programatically in PHP. To do this, I'm using imagegrabwindow() with a COM object: $browser = new COM("InternetExplorer.Application"); $handle = $browser->HWND; $browser->Visible = true; $browser->Navigate($pre.$URL); while ($browser->Busy) { com_message_pump(4000); } $img = imagegrabwindow($handle); What I'm wondering is if there is any way to do the same thing with Firefox or Chrome? Can I invoke either of them with PHP COM?

    Read the article

  • Won't connect to the database

    - by user1657958
    I'm confused...I'm using the same code in a different document and in there it's not a problem to get a connection to the database. But in the new document it's just not working...(password, username, database name...all is checked and correct) :-/ <?php define ("DB_HOST", "db1234567.db.hello.com"); // set database host define ("DB_USER", "db1234567"); // set database user define ("DB_PASS","password123"); // set database password define ("DB_NAME","db1234567"); // set database name $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die("Couldn't make connection."); $db = mysql_select_db(DB_NAME, $link) or die("Couldn't select database"); ?> In the browser I get this: "Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'db1234567'@'123.123.12.12 (using password: YES) in /homepages/12/1234567/test/test.php on line 8 Couldn't make connection." Would be cool if someone could help me :) I'm not seeing any error... Thx!

    Read the article

  • Need help with regular expressions - URL redirection

    - by paperless
    Hello everyone. I'm trying to redirect an easy to remember url to a php file but I'm having some trouble with the regex. Here's what I have at the moment: RewriteRule ^tcb/([a-zA-Z0-9]{1,})/([a-zA-Z0-9]{1,})/([a-zA-Z0-9]{1,}) /tcb/lerbd.php?autocarro=$1&tipo=$2&dsd=$3 It is working but only if I supply all 3 arguments. I want the last two arguments to be optional so it either works with only the first or all three. I'm hoping you can help me with this. Thank you very much.

    Read the article

  • Simple question about javascript history.go

    - by Camran
    I have a classifieds website. In every classified, there is a back link which simply takes the browser back one step. This is because when users search classifieds, and click on one to view it, they can easily go back with a link also (instead of only the browser back button). Here is the problem, if the classified is entered directly into the adress bar of a browser, or if somebody bookmarked a classified, then this back-link would take them someplace else... Is there any way of making sure that the previous page is a certain page (index.php in my case)? This way I would only display the back link if the previous page was index.php... Thanks

    Read the article

  • Placing .htaccess file in var/www folder messes my website up...

    - by Camran
    I am playing with mod_rewrite now, and have successfully enabled it. However, I need to put a htaccess file inside var/www/ in order to achieve what I want, which is to rename Urls simply... When I place it my website becomes very strange and nothing basically works... Is there any code I need to put into the htaccess file in order for things to act normally? Here is the htaccess file I have so far: Options +FollowSymLinks Options +Indexes RewriteEngine On RewriteCond %{REQUEST_URI} !^/ad\.php RewriteRule ^(.*)$ ad.php?ad_id=$1 [L] My DocumentRoot is also set to var/www/ and my entire website root is there... (index.html etc etc)... What am I missing about the htaccess? If you need more input let me know...

    Read the article

  • Create a picture with GD containing other images

    - by Jensen
    Hi, I would like to create a picture in PHP with GD composed by different other pictures. For example I have 6 pictures (or more) and I would like to create ONE picture who contain these different pictures. The Difficulty is that my final picture must have a fixed width and height (304x179), so if the different pictures are too big they must be cut. This is an example from IconFinder : This picture is composed by 6 images, but the 3rd bird (green) is cutted, and the 4, 5 and 6 are cutted in the bottom. This is what I want, can you give me some help to write this code in PHP ? Thanks

    Read the article

  • Warning: session_start(): Cannot send session cache limiter - headers already sent

    - by shyam
    I am receiving this warning in a page while I try starting the session. <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head> <title>Video</title> </head> -this is the part of the code. There are no characters (not even space) before the first line. This page is reached after logging in from another page, through redirection. Any help? (PHP version is 5.2)

    Read the article

  • Add a custom class name to Wordpress body tag?

    - by Scott B
    I'd like to place a directive in my theme's functions.php file which appends a classname to the wordpress body tag. Is there a built-in API method for this? For example, my body tag code is... <body <?php if(function_exists("body_class") && !is_404()){body_class();} else echo 'class="page default"'?>> And it results in the following being written to the body tag (depending on the context in which the page is presented (page, post, logged-in, etc) <body class="home blog logged-in"> Depending on the child theme I'm using at the time, I want it to be... <body class="home blog logged-in mychildthemename">

    Read the article

  • How to access constant defined in child class from parent class functions?

    - by kavoir.com
    I saw this example from php.net: <?php class MyClass { const MY_CONST = "yonder"; public function __construct() { $c = get_class( $this ); echo $c::MY_CONST; } } class ChildClass extends MyClass { const MY_CONST = "bar"; } $x = new ChildClass(); // prints 'bar' $y = new MyClass(); // prints 'yonder' ?> But $c::MY_CONST is only recognized in version 5.3.0 or later. The class I'm writing may be distributed a lot. Basically, I have defined a constant in ChildClass and one of the functions in MyClass (father class) needs to use the constant. Any idea?

    Read the article

  • How do stop form posting to mysql if database contains a specific ID?

    - by user342391
    I have a form that I am using to post data to mysql. Before submitting the form I want to check the database and see if there are any fields in the column 'customerid' that equal 'userid' and if so not to post the form. Basically, I am trying to limit my users from posting more than once. Users will be able to login to my system and make ONE post. They will be able to delete and modify their post but are only limited to one post. How would I do this??? Code so far: <?php include '../login/dbc.php'; page_protect(); $userid = $_SESSION['user_id']; $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[userid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

    Read the article

  • How to know if the website being scraped has changed?

    - by Lost_in_code
    I'm using PHP to scrape a website and collect some data. It's all done without using regex. I'm using php's explode() method to find particular HTML tags instead. It is possible that if the structure of the website changes (CSS, HTML), then wrong data may be collected by the scraper. So the question is - how do I know if the HTML structure has changed? How to identify this before storing any data to my database to avoid wrong data being stored.

    Read the article

  • Uploading files wont work on production server

    - by Camran
    I have a php script which uploads images to a temporary folder on the server. This works on my local computer with the local (virtual) server. (wampserver). However, on the production server (linux) I cant get it working. Everything is loading as it should, except for that the file doesn't show up on the server. My Q is, is there anything I should think about when moving to a production server with uploading images or files? I have set permissions on the folder where the images are supposed to go to 777 and also the php-code which uploads them to 777. Thanks

    Read the article

< Previous Page | 547 548 549 550 551 552 553 554 555 556 557 558  | Next Page >