Search Results

Search found 25852 results on 1035 pages for 'linq query syntax'.

Page 553/1035 | < Previous Page | 549 550 551 552 553 554 555 556 557 558 559 560  | Next Page >

  • Google App Engine update an object from servlet not working ?

    - by Frank
    I use the following code to update an object from servlet in Google App Engine : String Time_Stamp=Get_Date_Format(6),query="select from "+Contact_Info_Entry.class.getName()+" where Contact_Id == '"+Contact_Id+"' order by Contact_Id desc"; PersistenceManager pm=null; try { pm=PMF.get().getPersistenceManager(); // note that this returns a list, there could be multiple, DataStore does not ensure uniqueness for non-primary key fields List<Contact_Info_Entry> results=(List<Contact_Info_Entry>)pm.newQuery(query).execute(); Contact_Info_Entry A_Contact_Entry=results.get(0); A_Contact_Entry.Extra_10=Time_Stamp; pm.makePersistent(A_Contact_Entry); } catch (Exception e) { Send_Email(Email_From,Email_To,"Check_License_Servlet Error [ "+Time_Stamp+" ]",new Text(e.toString()+"\n"+Get_Stack_Trace(e)),null); } finally { pm.close(); } The value "[ 2010-05-13 Thu 15:58:31 ]" was in A_Contact_Entry.Extra_10, but it seems "pm.makePersistent(A_Contact_Entry);" was not executed. The object was not updated and there was no error message, why ? How to fix it ?

    Read the article

  • How can I have a Visual Studio Report(.rdlc) with account information and also a chart in the same r

    - by Paul Mendoza
    I'm working on a report in Visual Studio 2008 with their Report tooling and I'm not sure how to approach this conceptually. I have a report I want to generate. At the top of the report will be a bunch of information about a customer of our site (Name, Address, Phone). Then below will be a chart of the purchases that customer has each month. My problem is that I want the content at the top of the page to use a query that selects from my Users table in my database. But then I need another query that gets all of the purchases grouped by month. I've thought one way to approach this would be to place a subreport on the parent report that only contained the chart. The parent report would have the details of the account. Is this the correct approach?

    Read the article

  • Going from webforms, VS 2008, 3.5 framework to the "next level" based on my goals

    - by Caveatrob
    I've got a few choices to make as I develop some business websites that will run for the next two to three years. Currently I run ASP.NET 3.5 with Visual Studio 2008. I do my development rather crudely in WebForms because that's what I learned and am most productive with. I don't use Membership or any other frameworks in my projects. I use a simple class that maintains a few session keys for each user based on basic database tables for users and roles. (I have about 3,000 users). So far I've kept the data simple, using ADO.NET against SQL Server and a data access class (Circa 2000, I know) to build my sites. My questions are as follows: Under what conditions would I be better off moving to MVC? Under what conditions would I find LINQ and ORM a better way to go than standard ADO.NET? Would I benefit, in my current state of development, from going from Studio 2008 to Studio 2010?

    Read the article

  • How to learn more XMPP/Jabber command

    - by user359277
    Hi, I am using ejabberd as a chatting server now. And I am writing a client to chat and register new user. Right now, I know some of the protocol to register a new account, like sending the following command to register new user: <iq type="set"><query xmlns="jabber:iq:register"><username>wfwfewegwegwewefg</username><password>wfwefwefwefwef</password></query></iq> My question is: I want to learn more command/protocol to talk to the server. So where can I learn more? For example, How can I ask the server if the user name exists or not. How can I ask the server to unregister a user. What is the key word I should search for? Should I search for Jabber XMPP protocol or what? Thanks

    Read the article

  • Simple image displaying php error

    - by Rani dubey
    In a query say i have a image path that have multiple images stored as path=http://localhost/images/xyz.When i run the code: <?php //Retrieves data from MySQL mysql_connect("localhost", "root", "") or die ("Could not save image name Error: " . mysql_error()); mysql_select_db("dawat") or die("Could not select database"); $data = mysql_query("SELECT 'images_path' FROM images_tbl") or die(mysql_error()); //Puts it into an array $file_path = 'http://localhost/images/xyz'; while($row = mysql_fetch_assoc( $data )) {//Outputs the image and other data $src=$file_path.$row["images_path"]; echo "<img src=".$src."> <br>"; } ?> Everything is working fine,but only images are not showing.On place of images it is showing small thumnails.Please suggest what to do.... Sql query i used is: CREATE TABLE images_tbl( images_id INT NOT NULL AUTO_INCREMENT, images_path VARCHAR(200) NOT NULL, submission_date DATE, PRIMARY KEY (images_id) );

    Read the article

  • Levenshtein: MySQL + PHP

    - by user317005
    $word = strtolower($_GET['term']); $lev = 0; $q = mysql_uqery("SELECT `term` FROM `words`"); while($r = mysql_fetch_assoc($q)) { $r['term'] = strtolower($r['term']); $lev = levenshtein($word, $r['term']); if($lev >= 0 && $lev < 5) { $word = $r['term']; } } how can I move all that into just one query? don't want to have to query through all terms and do the filtering in php.

    Read the article

  • Hibernate not using schema and catalog name in id generation with strategy increment

    - by Ben
    Hi, I am using the hibernate increment strategy to create my IDs on my entities. @GenericGenerator(name="increment-strategy", strategy="increment") @Id @GeneratedValue(generator="increment=strategy") @Column(name="HDR_ID", unique=true, nullable=false) public int getHdrId(){ return this.hdrId; } The entity has the following table annotation @Table(name = "PORDER.PUB.PO_HEADER", schema = "UVOSi", catalog = "VIRT_UVOS") Please note I have two datasources. When I try to insert an entity Hibernate creates the following SQL statement: select max(hdr_id) from PORDER.PUB.PO_HEADER which causes the following error: Group specified is ambiguous, resubmit the query by fully qualifying group name. When I create a query by hand with entityManager.createQuery() hibernate uses the fully qualified name select XXX from VIRT_UVOS.UVOSi.PORDER.PUB.PO_HEADER and that works fine. So how do I get Hibernate to use the fully qualified name in the Id autogeneration? Btw. I am using Hibernate 3.2 and Seam 2.2 running on JBoss 4.2.3 Regards Immo

    Read the article

  • Incremement Page Hit Count in Django

    - by Andrew C
    I have a table with an IntegerField (hit_count), and when a page is visited (ie. http://site/page/3) I want record id 3 'hit_count' column in the database to increment by 1. The query should be like: update table set hit_count = hit_count + 1 where id=3 Can I do this with the standard Django Model conventions? Or should I just write the query by hand? I'm starting a new project, so I am trying to avoid hacks. We'll see how long this lasts! Thanks!

    Read the article

  • NDepend v4 has just been released!

    - by Vincent Maverick Durano
    Few months ago I blogged about the release of NDepend v3 Continuous Integration and Reporting Capabilities here. Recently, the NDepend team has released v4 which comes with code rules based on C# LINQ queries (CQLinq), this make code ruling so much more powerful and flexible. There are couple of new rules available like: http://www.ndepend.com/DefaultRules/webframe?Q_UI_layer_shouldn't_use_directly_DB_types.html http://www.ndepend.com/DefaultRules/webframe?Q_Types_with_disposable_instance_fields_must_be_disposable.html http://www.ndepend.com/DefaultRules/webframe?Q_Avoid_the_Singleton_pattern.html http://www.ndepend.com/DefaultRules/webframe?Q_Avoid_making_complex_methods_even_more_complex_(Source_CC).html v4 also provides NDepend.API and a dozen of open-source code tool developed with NDepend.API (the Power Tools) http://www.ndepend.com/API/webframe.html

    Read the article

  • Google Social Graph API, working as intended?

    - by pns
    Hey, I'm experiencing some problems with Google's social graph API. It seems that for some parameters passed to 'otherme' nothing is returned. I'll use Robert Scoble's profiles as an example (as he's a guy sure to be everywhere on the web). If I query: http://socialgraph.apis.google.com/otherme?q=http://twitter.com/scobleizer&pretty=1 I get results, as expected. However, if I query: http://socialgraph.apis.google.com/otherme?q=http://delicious.com/scobleizer&pretty=1 Nothing is returned, even though 'http://delicious.com/scobleizer' is listed in the previous results... Any thoughts? Thanks

    Read the article

  • Simple script - execute command on selected file

    - by askmoo
    I want to make a script that will execute .jar file on selected file. Later I will add that script to right-click menu via the tool Nautilus Actions or just place it into nautilus-scripts folder. I have a problem creating script. When I am in a usual console screen and want to execute this jar file on any other file, I use this syntax myfile.jar ./someotherfile.xml and the jar file will write the output to the console screen. So I created a file script.sh, added lines in it #!/bin/bash /home/username/myfile.jar $1 But it does not output anything. I know I am doing something wrong. Please help. To sum, I need a script that will use selected file as a parameter, open the gnome-terminal, inside that terminal it will start JAR file and pass it the selected file. I am confident that this is a very simple procedure, but I am total newbie with shell scripting.

    Read the article

  • How can I handle multiple views of a data object? Which design pattern is acceptable?

    - by tranquil.byte
    I have a person object. class Person { private $name; ... } I need to be able to change how they are displayed on the front-end ( visitors have control ). They can choose list view, grid view, photo view for example. class PersonDisplay { public function displayList() { // Query database // Output html to display in list mode } public function displayPhoto() { // Query database // Output html to display in photo mode } } Is this an acceptable way to handle the presentation of the items on the front-end or is there a specific design pattern I should be researching to help me with this task? Does anyone have any suggestions or ideas where this could go wrong or if this could potentially make maintenance a nightmare? The Person object was just an example very similiar to what I am using.

    Read the article

  • PHP error can't figure it out something to do with SQL stuff I think

    - by MrEnder
    Ok the error is showing up somewhere in this here code if($error==false) { $query = pg_query("INSERT INTO chatterlogins(firstName, lastName, gender, password, ageMonth, ageDay, ageYear, email, createDate) VALUES('$firstNameSignup', '$lastNameSignup', '$genderSignup', md5('$passwordSignup'), $monthSignup, $daySignup, $yearSignup, '$emailSignup', now());"); $query = pg_query("INSERT INTO chatterprofileinfo(email, lastLogin) VALUES('$email', now())";); $_SESSION['$userNameSet'] = $email; header('Location: signup_step2.php'.$rdruri); } anyone see what I did wrong??? sorry for being so unspecific but ive been staring at it for 10 mins and I can't figure it out.

    Read the article

  • PHP/mySQL - using result from 'CONCAT' and 'AS' in 'LIKE' clause

    - by Phil Jackson
    Hi I have the following code; if( ! empty( $post['search-bar'] ) ) { $search_data = preg_replace("#\s\s#is", '', preg_replace("#[^\w\d\s+]#is", '', $post['search-bar'] ) ); $data_array = explode( " ", $search_data ); $data_array = "'%" . implode( "%' OR '%", $data_array ) . "%'"; $query = "SELECT CONCAT( PROFILE_PROFFESION, FIRST_NAME, LAST_NAME, DISPLAY_NAME) AS 'STRING' FROM `" . ACCOUNT_TABLE . "` WHERE STRING LIKE ( " . $data_array . " ) AND BUSINESS_POST_CODE LIKE '" . substr(P_BUSINESS_POST_CODE, 0, 4) . "%'"; $q = mysql_query( $query, $CON ) or die( "_error_" . mysql_error() ); if( mysql_num_rows( $q ) != 0 ) { die(); } } Problem is I want to use the temp col 'STRING' in the where clause but is returning 'unknown coloumn STRING Can any one point me in the right direction, regards Phil

    Read the article

  • mysql filtering result using left outer join

    - by user288178
    my query: SELECT content.*, activity_log.content_id FROM content LEFT JOIN activity_log ON content.id = activity_log.content_id AND sess_id = '$sess_id' WHERE activity_log.content_id IS NULL AND visibility = $visibility AND content.reported < ".REPORTED_LIMIT." AND content.file_ready = 1 LIMIT 1 The purpose of that query is to get 1 row from the content table that has not been viewed by the user (identified by session_id), but it still returns contents that have been viewed. What is wrong? ( I have checked the table making sure that the content_ids are there) Note: I think this is more efficient than using subqueries, thoughts?

    Read the article

  • Multiple memcached servers question.

    - by Andre
    hypothetically - if I have multiple memcached servers like this: //PHP $MEMCACHE_SERVERS = array( "10.1.1.1", //web1 "10.1.1.2", //web2 "10.1.1.3", //web3 ); $memcache = new Memcache(); foreach($MEMCACHE_SERVERS as $server){ $memcache->addServer ( $server ); } And then I set data like this: $huge_data_for_frong_page = 'some data blah blah blah'; $memcache->set("huge_data_for_frong_page", $huge_data_for_frong_page); And then I retrieve data like this: $huge_data_for_frong_page = $memcache->get("huge_data_for_frong_page"); When i would to retrieve this data from memcached servers - how would php memcached client know which server to query for this data? Or is memcached client going to query all memcached servers?

    Read the article

  • Oracle - correlated subquery problems

    - by FrustratedWithFormsDesigner
    I have this query: select acc_num from (select distinct ac_outer.acc_num, ac_outer.owner from ac_tab ac_outer where (ac_outer.owner = '1234567') and ac_outer.owner = (select sq.owner from (select a1.owner from ac_tab a1 where a1.acc_num = ac_outer.acc_num order by a1.a_date desc, a1.b_date desc, a1.c_date desc) sq where rownum = 1) order by dbms_random.value()) subq order by acc_num; The idea is to get all acc_nums (not a primary key) from ac_tab, that have an owner of 1234567. Since an acc_num in ac_tab could have changed owners over time, I am trying to use the inner correlated subqueries to ensure that an acc_num is returned ONLY if it's most recent owner is 12345678. Naturally, it doesn't work (or I wouldn't be posting here ;) ) Oracle gives me an error: ORA-000904 ac_outer.acc_num is an invalid identifier. I thought that ac_outer should be visible to the correlated subqueries, but for some reason it's not. Is there a way to fix the query, or do I have to resort to PL/SQL to solve this? (Oracle verison is 10g)

    Read the article

  • Virtual hosting

    - by H3llGhost
    Hello, I want to use domains like xxx.abc.domain.tld. The xxx is my folder to access. I tried it with the rewrite rules, but I can't get it working, because I don't know how to get the part xxx from the SERVER_NAME into my RewriteRule. This was my try: UseCanonicalName Off # include the IP address in the logs so they may be split LogFormat "%A %h %l %u %t \"%r\" %s %b" vcommon CustomLog /var/log/apache2/vaccess.log vcommon RewriteEngine On # a ServerName derived from a Host: header may be any case at all RewriteMap lowercase int:tolower ## deal with normal documents first: # do the magic RewriteCond ${lowercase:%{SERVER_NAME}} ^.+\.abc\.domain\.tld$ RewriteRule ^(.*)$ /var/www/abc.domain.tld/[xxx-part]/$1 [L] Perhaps there is a better solution. In generally I want to create a dynamic login system with mod_auth_mysql and for each xxx is a seperate user database. I would prefer the domain/address syntax abc.domain.tld/xxx, but I don't know how to realize it. Thanks for any advices.

    Read the article

  • How to dynamically order many-to-many relationship in JPA or HQl?

    - by Indrek
    I have a mapping like this: @ManyToMany(cascade = CascadeType.PERSIST) @JoinTable( name="product_product_catalog", joinColumns={@JoinColumn(name="product_catalog", referencedColumnName="product_catalog")}, inverseJoinColumns={@JoinColumn(name="product", referencedColumnName="product")}) public List<Product> products = new ArrayList<Product>(); I can fetch the products for the catalog nicely, but I can't (dynamically) order the products. How could I order them? I probably have to write a many-to-many HQL query with the order-by clause? I though of passing the orderBy field name string to the query, or is there a better solution? Tables are: products, product_catalog, product_product_catalog (associative table) P.S. Using Play! Framework JPASupport for my entities.

    Read the article

  • MVC 2 in 2 Minutes!

    - by Steve Michelotti
    In a couple of recent Code Camps, I’ve given my presentation: Top 10 Ways MVC 2 Will Boost Your Productivity. In the presentation, I cover all major new features introduced in MVC 2 with a focus on productivity enhancements. To drive the point home, I conclude with a final demo where I build a couple of screens from scratch highlighting many (but not all) of the features previously covered in the talk. A couple of weeks ago, I was asked to make it available online so here it is. In 2 minutes the demo builds a couple screens from scratch that provide a goal setting tracker for a user. MVC 2 features included in the video are: Template Helpers / Editor Templates Server-side/Client-side Validation Model Metadata for View Model HTML Encoding Syntax Dependency Injection Abstract Controllers Custom T4 Templates Custom MVC Visual Studio 2010 Code Snippets The complete code samples and slide deck can be downloaded here: Top 10 Ways MVC 2 Will Boost Your Productivity. Enjoy! (Right-click and Zoom to view in full screen)   Click here for Direct link to video

    Read the article

  • How to get the Time Difference in C# .net

    - by Aamir Hasan
    A DateTime instance stores both date and time information. The DateTime class can be found in the System namespace.In order to retrieve the current system time, we can use the static property Now of the DateTime class.In this Example i have shown, how to calculate the difference between two DateTime objects using C# syntax. DateTime startTime; DateTime endTime;            startTime = Convert.ToDateTime("12:12 AM");            endTime = Convert.ToDateTime("1:12 AM");            var timeDifference = new TimeSpan(endTime.Ticks - startTime.Ticks);Response.Write("Time difference in hours is " + timeDifference.Hours);Link:http://msdn.microsoft.com/en-us/library/8kb3ddd4.aspx

    Read the article

  • Non-mathematical Project Euler (or similar)?

    - by Juha Untinen
    I checked the post (Where can I find programming puzzles and challenges?) where there's a lot of programming challenges and such, but after checking several of them, they all seem to be about algorithms and mathematics. Is there a similar site for purely logic/functionality-based challenges? For example: - Retrieve data using a web service - Generate output X from a CSV file - Protect this code against SQL injection - Make this code more secure - What is wrong with this code (where the error is in logic, not syntax) - Make this loop more efficient Does a challenge site like that exist? Especially one that provides hints and/or correct solutions. That would be a very helpful learning site.

    Read the article

  • Retrieving Top 10 rows ans sum all others in row 11

    - by Mario
    Hello all, I have the following query that retrieve the number of users per country; SELECT C.CountryID AS CountryID, C.CountryName AS Country, Count(FirstName) AS Origin FROM Users AS U INNER JOIN Country AS C ON C.CountryID = U.CountryOfOrgin GROUP BY CASE C.CountryName, C.CountryID What I need is a way to get the top 10 and then sum all other users in a single row. I know how to get the top 10 but I`m stuck on getting the remaining in a single row. Is there a simple way to do it? For example if the above query returns 17 records the top ten are displayed and a sum of the users from the 7 remaining country should appear on row 11. On that row 11 the countryid would be 0 and countryname Others Thanks for your help!

    Read the article

  • Excel - referenced values via OleDB from .Net client

    - by ho
    I'm trying to read an Excel file (.xls, I think Excel 2003 compatible) via OleDB, but it fails to get the values for referenced fields. This is my current test code (please note, this is just part of the class): Private m_conn As OleDbConnection Public Sub New(ByVal fileName As String) Dim connString As String = String.Format("Provider=Microsoft.Jet.OLEDB.4.0;Data Source={0};Extended Properties=Excel 8.0;", fileName) m_conn = New OleDbConnection(connString) m_conn.Open() End Sub Public Sub GetSheet(ByVal sheet As String) Dim query As String = String.Format("SELECT * FROM [{0}]", sheet) Using cmd As OleDbCommand = m_conn.CreateCommand() cmd.CommandText = query Dim ds As New DataSet() Dim a As New OleDbDataAdapter(cmd) Using rdr As OleDbDataReader = cmd.ExecuteReader() While rdr.Read() Debug.WriteLine(rdr.Item(0).ToString()) End While End Using End Using End Sub But if the value is a reference (something like =+'MySheetName'!K37), I just get a DBNull from the call to rdr.Item(0). I can get around this by automating Excel instead, but would prefer not to have to use Excel automation so wondering if anyone knows how to do it.

    Read the article

  • How sql server evaluates the multiple different joins?

    - by ziang
    Hi, i have a general question about how sql server evaluates the joins.The query is SELECT * FROM TableA INNER JOIN TableB ON TableB.id = TableA.id LEFT JOIN TABLEC ON TABLEC.id = TABLEB.id Q1: What tables is the left join based on? I know it will based on the TABLEC but what is the other one? Is it the result of the first inner join or the TABLEB specified in the left join condition? Q2: Is "LEFT JOIN TABLEC ON TABLEC.id = TABLEB.id" equivalent to "LEFT JOIN TABLEC ON TABLEB.id = TABLEC.id" Q3: Is the query equivalent to the following one? (with TABLEB.id replaced by TABLEA.id?) SELECT * FROM TableA INNER JOIN TableB ON TableB.id = TableA.id LEFT JOIN TABLEC ON TABLEC.id = TABLEA.id Thank you!

    Read the article

< Previous Page | 549 550 551 552 553 554 555 556 557 558 559 560  | Next Page >