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  • Starting ActiveMQ message listener in Tomcat?

    - by Nick Swarr
    I've created an ActiveMQ MessageListener and configured it using Spring. I'm hosting the listener in Tomcat. When I start up the web application (that features only the listener), should the listener automatically start? Or do I need additional configuration? Here's what I have. First, updated the web.xml to allow spring to configure itself on startup, <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/classes/spring/applicationContext.xml</param-value> </context-param> </web-app> Then I created the applicationContext.xml to configure the ActiveMQ listener, <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:amq="http://activemq.apache.org/schema/core" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <context:annotation-config /> <context:component-scan base-package="com.somepackage"/> <context:property-placeholder location="classpath:env.properties"/> <bean id="jmsFactory" class="org.apache.activemq.ActiveMQConnectionFactory"> <property name="brokerURL" value="tcp://localhost:61616" /> </bean> <bean id="documentListener" class="com.somepackage.SomeListener" /> <bean id="container" class="org.springframework.jms.listener.DefaultMessageListenerContainer"> <property name="connectionFactory" ref="cachingConnectionFactory"/> <property name="messageListener" ref="documentListener"/> <property name="destinationName" value="STOCKS.MSFT" /> </bean> <bean id="cachingConnectionFactory" class="org.springframework.jms.connection.CachingConnectionFactory"> <property name="targetConnectionFactory" ref="jmsFactory" /> <property name="sessionCacheSize" value="1" /> </bean> </beans> And that's it. Based on what I've seen around the web, I can't tell if that's all I need? Maybe I need some other configuration in Tomcat to kick off the listener?

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  • list of polymorphic objects

    - by LivingThing
    I have a particular scenario below. The code below should print 'say()' function of B and C class and print 'B says..' and 'C says...' but it doesn't .Any ideas.. I am learning polymorphism so also have commented few questions related to it on the lines of code below. class A { public: // A() {} virtual void say() { std::cout << "Said IT ! " << std::endl; } virtual ~A(); //why virtual destructor ? }; void methodCall() // does it matters if the inherited class from A is in this method { class B : public A{ public: // virtual ~B(); //significance of virtual destructor in 'child' class virtual void say () // does the overrided method also has to be have the keyword 'virtual' { cout << "B Sayssss.... " << endl; } }; class C : public A{ public: //virtual ~C(); virtual void say () { cout << "C Says " << endl; } }; list<A> listOfAs; list<A>::iterator it; # 1st scenario B bObj; C cObj; A *aB = &bObj; A *aC = &cObj; # 2nd scenario // A aA; // B *Ba = &aA; // C *Ca = &aA; // I am declaring the objects as in 1st scenario but how about 2nd scenario, is this suppose to work too? listOfAs.insert(it,*aB); listOfAs.insert(it,*aC); for (it=listOfAs.begin(); it!=listOfAs.end(); it++) { cout << *it.say() << endl; } } int main() { methodCall(); retrun 0; }

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  • Spring / Hibernate / JUnit - No Hibernate Session bound to Thread

    - by Marty Pitt
    Hi I'm trying to access the current hibernate session in a test case, and getting the following error: org.hibernate.HibernateException: No Hibernate Session bound to thread, and configuration does not allow creation of non-transactional one here at org.springframework.orm.hibernate3.SpringSessionContext.currentSession(SpringSessionContext.java:63) at org.hibernate.impl.SessionFactoryImpl.getCurrentSession(SessionFactoryImpl.java:574) I've clearly missed some sort of setup, but not sure what. Any help would be greatly appreciated. This is my first crack at Hibernate / Spring etc, and the learning curve is certainly steep! Regards Marty Code follows: The offending class: public class DbUnitUtil extends BaseDALTest { @Test public void exportDtd() throws Exception { Session session = sessionFactory.getCurrentSession(); session.beginTransaction(); Connection hsqldbConnection = session.connection(); IDatabaseConnection connection = new DatabaseConnection(hsqldbConnection); // write DTD file FlatDtdDataSet.write(connection.createDataSet(), new FileOutputStream("test.dtd")); } } Base class: @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations={"classpath:applicationContext.xml"}) public class BaseDALTest extends AbstractJUnit4SpringContextTests { public BaseDALTest() { super(); } @Resource protected SessionFactory sessionFactory; } applicationContext.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd"> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName"> <value>org.hsqldb.jdbcDriver</value> </property> <property name="url"> <value>jdbc:hsqldb:mem:sample</value> </property> <property name="username"> <value>sa</value> </property> <property name="password"> <value></value> </property> </bean> <bean id="sessionFactory" class="com.foo.spring.AutoAnnotationSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="entityPackages"> <list> <value>com.sample.model</value> </list> </property> <property name="schemaUpdate"> <value>true</value> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect </prop> <prop key="hibernate.show_sql">true</prop> </props> </property> </bean> </beans>

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  • Eclipse Maven web application - can not run on server anymore

    - by wuntee
    I have an maven eclipse webapp project that I was able to right click and 'Run on server' and it would deploy on tomcat. I recently did a 'maven - Update project conifgurations' and I now can NOT deploy and run the project as a webapp. Has anyone seen this before? The only output from tomcat is as follows - it doesnt even look like its trying to deploy the application. Apr 14, 2010 3:58:54 PM org.apache.catalina.core.AprLifecycleListener init INFO: The APR based Apache Tomcat Native library which allows optimal performance in production environments was not found on the java.library.path: .:/Library/Java/Extensions:/System/Library/Java/Extensions:/usr/lib/java Apr 14, 2010 3:58:54 PM org.apache.tomcat.util.digester.SetPropertiesRule begin WARNING: [SetPropertiesRule]{Server/Service/Engine/Host/Context} Setting property 'source' to 'org.eclipse.jst.j2ee.server:taac-web' did not find a matching property. Apr 14, 2010 3:58:54 PM org.apache.coyote.http11.Http11Protocol init INFO: Initializing Coyote HTTP/1.1 on http-8080 Apr 14, 2010 3:58:54 PM org.apache.catalina.startup.Catalina load INFO: Initialization processed in 402 ms Apr 14, 2010 3:58:54 PM org.apache.catalina.core.StandardService start INFO: Starting service Catalina Apr 14, 2010 3:58:54 PM org.apache.catalina.core.StandardEngine start INFO: Starting Servlet Engine: Apache Tomcat/6.0.24 Apr 14, 2010 3:58:54 PM org.apache.coyote.http11.Http11Protocol start INFO: Starting Coyote HTTP/1.1 on http-8080 Apr 14, 2010 3:58:54 PM org.apache.jk.common.ChannelSocket init INFO: JK: ajp13 listening on /0.0.0.0:8009 Apr 14, 2010 3:58:54 PM org.apache.jk.server.JkMain start INFO: Jk running ID=0 time=0/14 config=null Apr 14, 2010 3:58:54 PM org.apache.catalina.startup.Catalina start INFO: Server startup in 247 ms

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  • jQuery Tools alert works once (but only once)

    - by Jim Miller
    I'm trying to build a simple alert mechanism with jQuery Tools -- in response to a bit of Javascript code, pop up an overlay with a message and an OK button that, when clicked, makes the overlay go away. Trivial, or it should be. I've been slavishly following http://flowplayer.org/tools/demos/overlay/trigger.html, and have something that works fine the first time it's invoked, but only that time. If I repeat the JS action that should expose the overlay, it doesn't. My content/DIV: <div class='modal' id='the_alert'> <div id='modal_content' class='modal_content'> <h2>hi there</h2> this is the body <p> <button class='close'>OK</button> </p> </div> <div id='modal_background' class='modal_background'><img src='/images/overlay/f9f9f9-180.png' class='stretch' alt='' /></div> </div> and the Javascript: function showOverlayDialog() { $('#the_alert').overlay({ mask: {color: '#cccccc', loadSpeed: 200, opacity: 0.9}, closeOnClick: false, load: true }); } As I said: When showOverlayDialog() is invoked the first time, the overlay appears just like it should, and goes away when the "OK" button is clicked. But if I cause showOverlayDialog() to run again, without reloading the page, nothing happens. If I reload the page, then the pattern repeats -- the first invocation brings up the overlay, but the second one doesn't. I'm obviously missing something -- any advice out there? Thanks!

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  • What is the ambiguity in this piece of code?

    - by cambr
    #include <iostream> using namespace std; class A { public: void eat(){ cout<<"A";} }; class B: public A { public: void eat(){ cout<<"B";} }; class C: public A { public: void eat(){ cout<<"C";} }; class D: public B,C { public: void eat(){ cout<<"D";} }; int main(){ A *a = new D(); a->eat(); } I am not sure this is called diamond problem or not, but why doesn't this work? When I said, a->eat() (remember eat() is not virtual), there is only one possible eat() to call, that of A. Why then, do I get this error: 'A' is an ambiguous base of 'D'

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  • LINQ Query please help C#.Net.

    - by Paul Matthews
    I'm very new to LINQ and struggling to find the answers. I have a simple SQL query. Select ID, COUNT(ID) as Selections, OptionName, SUM(Units) as Units FROM tbl_Results GROUP BY ID, OptionName. The results I got were: '1' '4' 'Approved' '40' '2' '1' 'Rejected' '19' '3' '2' 'Not Decided' '12' Due to having to encrypt all my data in the database I'm unable to do sums. Therefore I have now brought back the data and decrypt it in the application layer. Results would be: '1' 'Approved' '10' '3' 'Not Deceided' '6' '2' 'Rejected' '19' '1' 'Approved' '15' '1' 'Approved' '5' '3' 'Not Deceided' '6' '1' 'Approved' '10' using a simple class I have called back the above results, and put them in a list class. public class results { public int ID {get;set;} public string OptionName {get;set;} public int Unit {get;set;} } I almost have the LINQ query to bring back the results like the SQL query at the top var q = from r in Results group p.Unit by p.ID int g select new {ID = g.Key, Selections = g.Count(), Units = g.Sum()}; How do I ensure my LINQ query also give me the Option Name? Also if I created a class called Statistics to hold my results how would I modify the LINQ query to give me list result set? public class results { public int ID {get;set;} public int NumberOfSelections { get; set; } public string OptionName {get;set;} public int UnitTotal {get;set;} }

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  • Django admin causes high load for one model...

    - by Joe
    In my Django admin, when I try to view/edit objects from one particular model class the memory usage and CPU rockets up and I have to restart the server. I can view the list of objects fine, but the problem comes when I click on one of the objects. Other models are fine. Working with the object in code (i.e. creating and displaying) is ok, the problem only arises when I try to view an object with the admin interface. The class isn't even particularly exotic: class Comment(models.Model): user = models.ForeignKey(User) thing = models.ForeignKey(Thing) date = models.DateTimeField(auto_now_add=True) content = models.TextField(blank=True, null=True) approved = models.BooleanField(default=True) class Meta: ordering = ['-date'] Any ideas? I'm stumped. The only reason I could think of might be that the thing is quite a large object (a few kb), but as I understand it, it wouldn't get loaded until it was needed (correct?).

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  • Problem with IE and Jquery qTip plugin

    - by user272899
    I am having problems with the Jquery qtip plugin. It works fine in Firefox (see here http://movieo.no-ip.org/ hover over the first image). But doesn't work in IE. This is the code: $('.moviebox').each(function() { $(this).qtip({ content: $(this).children('.info'), show: 'mouseover', hide: 'mouseout', style: { name: 'light' }, position: { corner: { target: 'rightbottom', tooltip: 'bottomleft' } } }); }); And the html <!--start moviebox--> <div class="moviebox"> <a href="#"> <img src="http://1.bp.blogspot.com/_mySxtRcQIag/S6deHcoChaI/AAAAAAAAObc/Z1Xg3aB_wkU/s200/rising_sun.jpg" /> </a> <!--start infobox--> <div class="info"> <span>Rising Sun (2006)</span> <div class="description"><strong>Description:</strong><br /> test test test test test test test test test test test test test test test test</div> <img src="http://1.bp.blogspot.com/_mySxtRcQIag/S6deHcoChaI/AAAAAAAAObc/Z1Xg3aB_wkU/s200/rising_sun.jpg" /> <div class="cast"><strong>Cast:</strong><br /> Sean connery</div> <div class="rating"><strong>Rating:</strong><br />5stars</div> </div> <!--end infobox--> </div> <!--end moviebox--> Why wouldn't that work in IE????? Beats me. Checkout movieo.no-ip.org for the whole source

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  • Why aren't google api clients built on top of Apache's Abdera project ?

    - by lisak
    Hey, Could anybody please explain that to me? As far as I can see, the developers of java's google api client library are reinventing the wheel. It's like writing a new JDK for a Java project. I'm aware of the fact that google data protocol is a little specific re atom publishing, but if one needs to use some of the fancy extensions and features that Apache Abdera project offers for this protocol, it is better not to use google api client library and implement the client from scratch with Abdera... And I'm sure that in a lot of cases its features such as Abdera's JCR adapter would become very handy for google docs, google translator toolkit and others. Now it's great that there is a google api client library to be used for google docs, but what am I going to do with the documents? I believe that in more than a half cases there is also a repository or database on the other side. And in that case, abdera is needed, not the simple google api clients that are only marshalling/unmarshalling the feeds... In fact, there is something to persist in all of the google APIs. It would make sense, if google decided to invest the effort into Abdera enhancement... This doesn't... Also for the question to be more specific: How are you developing google api clients, that need entry persistence (JCR for instance) ? What would be the best way to integrate a google api client library with Apache Abdera ?

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  • Emailing smtp with Python error

    - by jakecar
    I can't figure out why this isn't working. I'm trying to send an email from my school email address with this code I got online. The same code works for sending from my GMail address. Does anyone know what this error means? The error occurs after waiting for about one and a half minutes. import smtplib FROMADDR = "FROM_EMAIL" LOGIN = "USERNAME" PASSWORD = "PASSWORD" TOADDRS = ["TO_EMAIL"] SUBJECT = "Test" msg = ("From: %s\r\nTo: %s\r\nSubject: %s\r\n\r\n" % (FROMADDR, ", ".join(TOADDRS), SUBJECT) ) msg += "some text\r\n" server = smtplib.SMTP('OUTGOING_SMTP', 587) server.set_debuglevel(1) server.ehlo() server.starttls() server.login(LOGIN, PASSWORD) server.sendmail(FROMADDR, TOADDRS, msg) server.quit() And here's the error I get: Traceback (most recent call last): File "emailer.py", line 13, in server = smtplib.SMTP('OUTGOING_SMTP', 587) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 239, in init (code, msg) = self.connect(host, port) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 295, in connect self.sock = self._get_socket(host, port, self.timeout) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/smtplib.py", line 273, in _get_socket return socket.create_connection((port, host), timeout) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/socket.py", line 514, in create_connection raise error, msg socket.error: [Errno 60] Operation timed out

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  • How to find specific/local files via CMake

    - by Andreas Romeyke
    Hello, I have a problem with a locally installed library. In my project there is the xmlrpc++0.7-library: myproject/ +-- xmlrpc++0.7/ +-- src/ I want that CMake fallbacks using the local xmlrpc++0.7 directory if not found otherwise. Two problems, the first one, find_path() or find_library() does not work with local dir. I used a workaround testing if variables processed by find_xxx() are empty or not. If empty I set them manually. The cmake generates the Makefile without errors now. But if I want to compile the project via make, the c++ compiler returns "error: XmlRpc.h: file not found". The file XmlRpc.h lies in myproject/xmlrpc++0.7/src and if I compile all them manually it works fine. Here is my CMakeLists.txt. I am very happy if anyone could me point to the right solution to use cmake under conditions described above. --- CMakeLists.txt --- project(webservice_tesseract) cmake_minimum_required(VERSION 2.6) set(CMAKE_INCLUDE_CURRENT_DIR ON) # find tesseract find_path(TESSERACT_INCLUDE_DIR tesseract/tesseractmain.h /opt/local/include /usr/local/include /usr/include ) find_library(TESSERACT_LIBRARY_DIR NAMES tesseract_main PATHS /opt/local/lib/ /usr/local/lib/ /usr/lib ) message(STATUS "looked for tesseract library.") message(STATUS "Include file detected: [${TESSERACT_INCLUDE_DIR}].") message(STATUS "Lib file detected: [${TESSERACT_LIBRARY_DIR}].") add_library(tesseract STATIC IMPORTED) set_property(TARGET tesseract PROPERTY IMPORTED_LOCATION ${TESSERACT_LIBRARY_DIR}/libtesseractmain.a ) #find xmlrpc++ message(STATUS "cmake home dir: [${CMAKE_HOME_DIRECTORY}].") set(LOCAL_XMLRPCPLUSPLUS ${CMAKE_HOME_DIRECTORY}/xmlrpc0.7++/) message(STATUS "xmlrpc++ local dir: [${LOCAL_XMLRPCPLUSPLUS}].") find_path(XMLRPCPLUSPLUS_INCLUDE_DIR XmlRpcServer.h ${LOCAL_XMLRPCPLUSPLUS}src /opt/local/include /usr/local/include /usr/include ) find_library(XMLRPCPLUSPLUS_LIBRARY_DIR NAMES XmlRpc PATHS ${LOCAL_XMLRPCPLUSPLUS} /opt/local/lib/ /usr/local/lib/ /usr/lib/ ) # next lines are an ugly workaround because cmake find_xxx() does not find local stuff if (XMLRPCPLUSPLUS_INCLUDE_DIR) else (XMLRPCPLUSPLUS_INCLUDE_DIR) set(XMLRPCPLUSPLUS_INCLUDE_DIR ${LOCAL_XMLRPCPLUSPLUS}src) endif (XMLRPCPLUSPLUS_INCLUDE_DIR) if (XMLRPCPLUSPLUS_LIBRARY_DIR) else (XMLRPCPLUSPLUS_LIBRARY_DIR) set(XMLRPCPLUSPLUS_LIBRARY_DIR ${LOCAL_XMLRPCPLUSPLUS}) endif (XMLRPCPLUSPLUS_LIBRARY_DIR) message(STATUS "looked for xmlrpc++ library.") message(STATUS "Include file detected: [${XMLRPCPLUSPLUS_INCLUDE_DIR}].") message(STATUS "Lib file detected: [${XMLRPCPLUSPLUS_LIBRARY_DIR}].") add_library(xmlrpc STATIC IMPORTED) set_property(TARGET xmlrpc PROPERTY IMPORTED_LOCATION ${XMLRPCPLUSPLUS_LIBRARY_DIR}/libXmlRpc.a ) #### link together include_directories(${XMLRPCPLUSPLUS_INCLUDE_DIR} ${TESSERACT_INCLUDE_DIR}) link_directories(${XMLRPCPLUSPLUS_LIBRARY_DIR} ${TESSERACT_LIBRARY_DIR}) add_library(simpleocr STATIC simple_ocr.cpp) add_executable(webservice_tesseract webservice.cpp) target_link_libraries(webservice_tesseract xmlrpc tesseract simpleocr)

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  • Qt - reloading widget contents

    - by bullettime
    I'm trying to modify the fridge magnets example by adding a button that will reload the widget where the draggable labels are drawn, reflecting any changes made to the text file it reads. I defined another class that would contain the button and the DragWidget object, so there would be an instance of this class instead of DragWidget in main(): class wrapWidget: public QWidget { public: wrapWidget(); }; wrapWidget::wrapWidget() { QGridLayout *gridlayout = new QGridLayout(); DragWidget *w = new DragWidget(); QPushButton *b = new QPushButton("refresh"); gridlayout ->addWidget(w,0,0); gridlayout ->addWidget(b,1,0); setLayout(gridlayout ); connect(b,SIGNAL(clicked()),w,SLOT(draw())); } The call to connect is where I'm trying to do the refresh thing. In the original fridge magnets example, all the label drawing code was inside the constructor of the DragWidget class. I moved that code to a public method that I named 'draw()', and called this method from the constructor instead. Here's DragWidget definition and implementation: #include <QWidget> QT_BEGIN_NAMESPACE class QDragEnterEvent; class QDropEvent; QT_END_NAMESPACE class DragWidget : public QWidget { public: DragWidget(QWidget *parent = 0); public slots: void draw(); protected: void dragEnterEvent(QDragEnterEvent *event); void dragMoveEvent(QDragMoveEvent *event); void dropEvent(QDropEvent *event); void mousePressEvent(QMouseEvent *event); void paintEvent(QPaintEvent *event); }; DragWidget::DragWidget(QWidget *parent) : QWidget(parent) { draw(); QPalette newPalette = palette(); newPalette.setColor(QPalette::Window, Qt::white); setPalette(newPalette); setMinimumSize(400, 100);//qMax(200, y)); setWindowTitle(tr("Fridge Magnets")); setAcceptDrops(true); } void DragWidget::draw(){ QFile dictionaryFile(":/dictionary/words.txt"); dictionaryFile.open(QFile::ReadOnly); QTextStream inputStream(&dictionaryFile); int x = 5; int y = 5; while (!inputStream.atEnd()) { QString word; inputStream >> word; if (!word.isEmpty()) { DragLabel *wordLabel = new DragLabel(word, this); wordLabel->move(x, y); wordLabel->show(); wordLabel->setAttribute(Qt::WA_DeleteOnClose); x += wordLabel->width() + 2; if (x >= 245) { x = 5; y += wordLabel->height() + 2; } } } } I thought that maybe calling draw() as a slot would be enough to reload the labels, but it didn't work. Putting the draw() call inside the widget's overriden paintEvent() instead of the constructor didn't work out as well, the program would end up in an infinite loop. What I did was obviously not the right way of doing it, so what should I be doing instead?

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  • filterSecurityInterceptor and metadatasource implementation spring-security

    - by Mike
    Hi! I created a class that implements the FilterInvocationSecurityMetadataSource interface. I implemented it like this: public List<ConfigAttribute> getAttributes(Object object) { FilterInvocation fi = (FilterInvocation) object; Object principal = SecurityContextHolder.getContext().getAuthentication().getPrincipal(); Long companyId = ((ExtenededUser) principal).getCompany().getId(); String url = fi.getRequestUrl(); // String httpMethod = fi.getRequest().getMethod(); List<ConfigAttribute> attributes = new ArrayList<ConfigAttribute>(); FilterSecurityService service = (FilterSecurityService) SpringBeanFinder.findBean("filterSecurityService"); Collection<Role> roles = service.getRoles(companyId); for (Role role : roles) { for (View view : role.getViews()) { if (view.getUrl().equalsIgnoreCase(url)) attributes.add(new SecurityConfig(role.getName() + "_" + role.getCompany().getName())); } } return attributes; } when I debug my application I see it reaches this class, it only reaches getAllConfigAttributes method, that is empty as I said, and return null. after that it prints this warning: Could not validate configuration attributes as the SecurityMetadataSource did not return any attributes from getAllConfigAttributes(). My aplicationContext- security is like this: <beans:bean id="filterChainProxy" class="org.springframework.security.web.FilterChainProxy"> <filter-chain-map path-type="ant"> <filter-chain filters="sif,filterSecurityInterceptor" pattern="/**" /> </filter-chain-map> </beans:bean> <beans:bean id="filterSecurityInterceptor" class="org.springframework.security.web.access.intercept.FilterSecurityInterceptor"> <beans:property name="authenticationManager" ref="authenticationManager" /> <beans:property name="accessDecisionManager" ref="accessDecisionManager" /> <beans:property name="securityMetadataSource" ref="filterSecurityMetadataSource" /> </beans:bean> <beans:bean id="filterSecurityMetadataSource" class="com.mycompany.filter.FilterSecurityMetadataSource"> </beans:bean> what could be the problem?

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  • Objective C, Linking Error with extern variable..

    - by LCYSoft
    I have a very simple java code like this. I don't have any idea how to do this in Objective C. Especially, the static part which calls the getLocalAddress() method and assign it into the static string variable. I know how to set a static variable and a static method in Objective but I dont know how to implement that static { } part in java. Thanks in advance... public class Address { public static String localIpAddress; static { localIpAddress = getLocalIpAddress(); } public Address() { } static String getLocalIpAddress() { //do something to get local ip address } } I added this in my .h file #import <Foundation/Foundation.h> extern NSString *localIpAddress; @class WifiAddrss; @interface Address : NSObject { } @end And my .m file looks like #import "Address.h" #import "WifiAddress.h" @implementation Address +(void)initialize{ if(self == [Address class]){ localIpAddress = [self getLocalIpAddress]; } } +(NSString *)getLocalIpAddress{ return address here } -(id)init{ self = [super init]; if (self == nil){ NSLog(@"init error"); } return self; } @end And Now I am getting a linking error and it complains about "extern NSString *localIpAddress" part. If I change the extern to static, it works fine. But what I wanted to do is that I want make the scope of "localIpAddress" variable as grobal. Since if I put "static" in front of a variable in Objective-C then the variable is only visible in the class. But this time, I want to make that as a grobal variable. So my question is how to make "localIpAddress" variable as a grobal variable which is initialized once when the first time Address class is created.. Thanks in advance...

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  • Adding a generic image field onto a ModelForm in django

    - by Prairiedogg
    I have two models, Room and Image. Image is a generic model that can tack onto any other model. I want to give users a form to upload an image when they post information about a room. I've written code that works, but I'm afraid I've done it the hard way, and specifically in a way that violates DRY. Was hoping someone who's a little more familiar with django forms could point out where I've gone wrong. Update: I've tried to clarify why I chose this design in comments to the current answers. To summarize: I didn't simply put an ImageField on the Room model because I wanted more than one image associated with the Room model. I chose a generic Image model because I wanted to add images to several different models. The alternatives I considered were were multiple foreign keys on a single Image class, which seemed messy, or multiple Image classes, which I thought would clutter my schema. I didn't make this clear in my first post, so sorry about that. Seeing as none of the answers so far has addressed how to make this a little more DRY I did come up with my own solution which was to add the upload path as a class attribute on the image model and reference that every time it's needed. # Models class Image(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') image = models.ImageField(_('Image'), height_field='', width_field='', upload_to='uploads/images', max_length=200) class Room(models.Model): name = models.CharField(max_length=50) image_set = generic.GenericRelation('Image') # The form class AddRoomForm(forms.ModelForm): image_1 = forms.ImageField() class Meta: model = Room # The view def handle_uploaded_file(f): # DRY violation, I've already specified the upload path in the image model upload_suffix = join('uploads/images', f.name) upload_path = join(settings.MEDIA_ROOT, upload_suffix) destination = open(upload_path, 'wb+') for chunk in f.chunks(): destination.write(chunk) destination.close() return upload_suffix def add_room(request, apartment_id, form_class=AddRoomForm, template='apartments/add_room.html'): apartment = Apartment.objects.get(id=apartment_id) if request.method == 'POST': form = form_class(request.POST, request.FILES) if form.is_valid(): room = form.save() image_1 = form.cleaned_data['image_1'] # Instead of writing a special function to handle the image, # shouldn't I just be able to pass it straight into Image.objects.create # ...but it doesn't seem to work for some reason, wrong syntax perhaps? upload_path = handle_uploaded_file(image_1) image = Image.objects.create(content_object=room, image=upload_path) return HttpResponseRedirect(room.get_absolute_url()) else: form = form_class() context = {'form': form, } return direct_to_template(request, template, extra_context=context)

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  • Why Spark viewengine renders unnecessary (or unexpected) quotes?

    - by Arnis L.
    If i add pageBaseType="Spark.Web.Mvc.SparkView" in my web.config (necessary to fix intellisense), somehow it does not render links (probably not only) correctly anymore. This is how it's supposed to look like (and does, if page base type is not specified)= This is how it looks when base type is specified= Chrome source viewer shows identical page source code for both cases= <body> <div class="content"> <div class="navigation"> <a href="/Employee/List">Employees</a> <a href="/Product/List">Products</a> <a href="/Store/List">Stores</a> <div class="navigation_title"> Navigation</div> </div> <div class="main"> <div class="content"> <h2>Employees</h2>Nothing found... &lt;a href=&quot;/Employee/Create&quot;&gt;Create&lt;/a&gt; </div> </div> </div> </body> Developer tools does not= So - why my link gets htmlencoded (if that's what happens)? If it's default behavior, then how to render raw html? Using latest Spark version, rebuilt with Asp.Net Mvc2 RC assemblies.

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  • Using one sqlconnection/sqlcommand through 2 DB-bound methods

    - by dotnetdev
    I have a class with a method which gets data from a database through a SELECT stored proc. This method uses a SqlDbReader by returning ExecuteReader() on a SqlCommand. The connection and everything is made in this method, with fields (such as connection string) set as class level fields. I now need to populate an array based on the results of this query (so the columns of each row will go into the array with its own index). However, this query will not select all of the data from one table which is involved. I can write the queries to get what I need, but how can I use one connection throughout the class? If I instantiate the connection object and call Open() in the constructor, I get an exception @ runtime. I'm hoping for something like this: // At class level: sqlconn.Open(); // sqlcommand set up Method() { // Fire stored proc // Insert results in a collection } Method2() { // Pass same collection in (use same one), // Add new row columns into same collection } How can I do this with strict performance in mind? Thanks

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  • C# Login Dialog Implementation

    - by arc1880
    I have implemented a LoginAccess class that prompts the user to enter their active directory username and password. Then I save the login data as an encrypted file. Every subsequent start of the application, the LoginAccess class will read the encrypted file and check against the active directory to see if the login information is still valid. If it is not, then it will prompt the user again. I have made it so that the reading of the encrypted file and displaying of the login dialog is done on a separate thread. A delegate is fired when the login process is complete. The issue that I'm having is that I have a class that is used in multiple places. This class contains the call to the LoginAccess object. Every time I instantiate a new object there are multiple calls to the LoginAccess object and I get multiple dialogs appearing when it tries to prompt for a username and password. Any suggestions on how to have only one dialog appear would be greatly appreciated.

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  • What are the basics of dealing with user input events in Android?

    - by user279112
    Hello. I thought I had understood this question, but something is quite wrong here. When the user (me, so far) tries to press keys, nothing really happens, and I am having a lot of trouble understanding what it is that I've missed. Consider this before I present some code to help clarify my problem: I am using Android's Lunar Lander example to make my first "real" Android program. In that example, of course, there exist a class LunarView, and class nested therein LunarThread. In my code the equivalents of these classes are Graphics and GraphicsThread, respectively. Also I can make sprite animations in 2D just fine on Android. I have a Player class, and let's say GraphicsThread has a Player member referred to as "player". This class has four coordinates - x1, y1, x2, and y2 - and they define a rectangle in which the sprite is to be drawn. I've worked it out so that I can handle that perfectly. Whenever the doDraw(Canvas canvas) method is invoked, it'll just look at the values of those coordinates and draw the sprite accordingly. Now let's say - and this isn't really what I'm trying to do with the program - I'm trying to make the program where all it does is display the Player sprite at one location of the screen UNTIL the FIRST time the user presses the Dpad's left button. Then the location will be changed to another set position on the screen, and the sprite will be drawn at that position for the rest of the program invariably. Also note that the GraphicsThread member in Graphics is called "thread", and that the SurfaceHolder member in GraphicsThread is called "mSurfaceHolder". So consider this method in class Graphics: @Override public boolean onKeyDown(int keyCode, KeyEvent msg) { return thread.keyDownHandler(keyCode, msg); } Also please consider this method in class GraphicsThread: boolean keyDownHandler(int keyCode, KeyEvent msg) { synchronized (mSurfaceHolder) { if (keyCode == KeyEvent.KEYCODE_DPAD_LEFT) { player.x1 = 100; player.y1 = 100; player.x2 = 120; player.y2 = 150; } } return true; } Now then assuming that player's coordinates start off as (200, 200, 220, 250), why won't he do anything different when I press Dpad: Left? Thanks!

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  • Passing Activity to non-activity object properly

    - by rayman
    In my app ive got a non-activity object which it's role is being a manager class. many times i need to pass "source activity" to methods as parameter to that manager class in order to make some operations on that activity. for exaple let's assume we have MyActivity which gotta do some toast. so i have this manager class called MyManager, and i have this method in it raiseToast(Activity sourceActivity) { Toast.makeText(sourceActivity, demo, Toast.LENGTH_LONG).show(); } and from Myactivity class we calling that method this way: MyManager manager=new MyManager(); manager.raitetoast(MyActivity.this); it works fine. what I'm asking here, is this a proper way to pass an Activity as parameter to a non-activity object? I'm having a memory leaks on real device(not the emulator), I wonder if this could also causing any reason for that? Thanks Idan.

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  • What to pass to UserType, BlobType.setPreparedStatement session parameter

    - by dlots
    http://blog.xebia.com/2009/11/09/understanding-and-writing-hibernate-user-types/ I am attempting to defined a customer serialization UserType that mimics, the XStreamUserType referenced and provided here: http://code.google.com/p/aphillips/source/browse/commons-hibernate-usertype/trunk/src/main/java/com/qrmedia/commons/persistence/hibernate/usertype/XStreamableUserType.java My serializer outputs a bytearray that should presumably written to a Blob. I was going to do: public class CustomSerUserType extends DirtyCheckableUserType { protected SerA ser=F.g(SerA.class); public Class<Object> returnedClass() { return Object.class; } public int[] sqlTypes() { return new int[] {Types.BLOB}; } public Object nullSafeGet(ResultSet resultSet,String[] names,Object owner) throws HibernateException,SQLException { if() } public void nullSafeSet(PreparedStatement preparedStatement,Object value,int index) throws HibernateException,SQLException { BlobType.nullSafeSet(preparedStatement,ser.ser(value),index); } } Unfortunetly, the BlobType.nullSafeSet method requires the session. So how does one define a UserType that gets access to a servlet requests session? EDIT: There is a discussion of the issue here and it doesn't appear there is a solution: Best way to implement a Hibernate UserType after deprecations?

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  • How can I get jquery to toggle-fade a flashcard div open and closed on click?

    - by Edward Tanguay
    What do I have to change to the code below in order for the user to click on a flashcard header to open and close the flashcard answer? I couldn't get toggle() to work with fadein/fadeout the version below doesn't respond to the click code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <script type="text/javascript" src="http://www.google.com/jsapi"></script> <script type="text/javascript"> google.load("jquery", "1.4.1"); google.setOnLoadCallback(function() { $("div > div.question").click(function() { if($(this).next().is(":hidden") { $(this).next().fadeIn("slow"); } else { $(this).next().fadeOut("slow"); } }); }); </script> <style> div.flashcard { margin: 0 10px 10px 0; } div.flashcard div.question { background-color:#ddd; width: 400px; padding: 5px; cursor: hand; cursor: pointer; } div.flashcard div.answer { background-color:#eee; width: 400px; padding: 5px; display: none; } </style> </head> <body> <div id="1" class="flashcard"> <div class="question">Who was Wagner?</div> <div class="answer">German composer, conductor, theatre director and essayist, primarily known for his operas (or "music dramas", as they were later called). Unlike most other opera composers, Wagner wrote both the music and libretto for every one of his works.</div> </div> <div id="2" class="flashcard"> <div class="question">Who was Thalberg?</div> <div class="answer">a composer and one of the most distinguished virtuoso pianists of the 19th century.</div> </div> </body> </html>

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  • Cocoa App with Python extension which use Scipy -> ImportError: No module named scipy

    - by Snej
    Hi: I have installed Scipy (via macports) for Python on my Mac and it runs fine when running Python scripts. But now I'm using Scipy (via PyObjc) for calculations embedded in a Cocoa App frontend. The following error occurs: ImportError: No module named scipy I am using the "Python.framework" in XCode. Does anybody know why Scipy module is not found? I even added it manually to the module search path via sys.path.append("/opt/local/var/macports/software/py26-scipy/0.7.1_0+gcc43/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/") EDIT: I found the problem myself. The path should be without "/scipy" at the end. But now I got an architecture problem: ImportError: dlopen(/opt/local/var/macports/software/py26-scipy/0.7.1_0+gcc43/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/fftpack/_fftpack.so, 2): no suitable image found. Did find: /opt/local/var/macports/software/py26-scipy/0.7.1_0+gcc43/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/fftpack/_fftpack.so: mach-o, but wrong architecture EDIT 2: I checked the architectures: Yes, sure it is an architecture problem. But when I run: file /opt/local/var/macports/software/py26-scipy/0.7.1_0+gcc43/opt/local/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/scipy/fftpack/_fftpack.so I get a result Mach-O 64-bit bundle x86_64. And the Mac OS 10.6 PYTHON is: Mach-O universal binary with 3 architectures /usr/bin/python (for architecture x86_64): Mach-O 64-bit executable x86_64 /usr/bin/python (for architecture i386): Mach-O executable i386 /usr/bin/python (for architecture ppc7400): Mach-O executable ppc I build the XCode project as x86_64.

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  • How do I flag only one of the formsets in django admin?

    - by azuer88
    I have these (simplified) models: class Question(models.Model): question = models.CharField(max_length=60) class Choices(models.Model): question = models.ForeignKey(Question) text = models.CharField(max_length=60) is_correct = models.BooleanField(default=False) I've made Choices as an inline of Question (in admin). Is there a way to make sure that only one Choice will have is_correct = True? Ideally, is_correct will be displayed as a radio button when it is displayed in the admin formset (TabularInline). my admin.py has: from django.contrib import admin class OptionInline(admin.TabularInline): model = Option extra = 5 max_num = 5 class QuestionAdmin(admin.ModelAdmin): inlines = [OptionInline, ] admin.site.register(QType) admin.site.register(Question, QuestionAdmin)

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